Systems of Particles 1 2.003J/1.053J Dynamics and Control I, Spring 2007 Professor Thomas Peacock 2/20/2007 Lecture 4 Systems of Particles: Angular Momentum and Work Energy Principle Systems of Particles Angular Momentum (continued) τ ext B = d H + vB × P dt B τ ext B : Total External Torque H B : Total Angular Momentum P : Total Linear Momentum From now on, τ ext B = τ B. If τ B = 0 and v B = 0 or if B is the center of mass or if v B � v C then H B = constant (Conservation of Angular Momentum). d You may be familiar with τ B = dt H B (only valid if v B = 0 or v B � P ). Angular momentum H B of a collection of particles about point B is given by: HB = N � hBi i=1 � where hBi = r i × mi v i . If (H B ) is the sum of the angular momenta of the individual particles about point B, Cite as: Thomas Peacock and Nicolas Hadjiconstantinou, course materials for 2.003J/1.053J Dynamics and Control I, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. Systems of Particles 2 Figure 1: Angular momentum about B for a system of particles. Each particle � has mass mi positions ri with respect to the origin and ri with respect to B. � The center of mass C has positions rc with respect to B and ρi with respect to each point mass mi . Figure by MIT OCW. HB = n � = n � n � � r i × mi v i = i=1 = i=1 n � � i=1 � (r c + ρi ) × mi vi � (r c × mi v i ) + i=1 = � r i × mi r˙ i � rc × M vc + n � ρi × m i v i i=1 n � ρi × mi v i i=1 where we have used Therefore, we write: � mi v i = M v c � H B = H C + rc × P Notice that v B does not appear in this equation. The angular momentum about B is the angular momentum about the center of mass (C) plus the moment of the system linear momentum (M v C = P ) about B. We will use these equations for rigid bodies. With rigid bodies will need to use moments of inertia. Cite as: Thomas Peacock and Nicolas Hadjiconstantinou, course materials for 2.003J/1.053J Dynamics and Control I, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. Systems of Particles 3 Work Energy Principle W12 = n � � i=1 r2i F i · dr i = r1i n � � t2 t1 i=1 d p · v dt = dt i i � t2 t1 � � n � d 1 mi (v i · v i ) dt dt 2 i=1 = T2 − T 1 where: T = n � 1 2 i=1 W12 = = n � (W12 )i = i=1 n � r 2i � i=1 �n � r2i �ni=1 �rr1i2i i=1 r 1i mi (v i · v i ) n � � i=1 r2i F int · dr i + i r 1i Fi · dr i r1i n � � i=1 r2i F ext · dr i i r1i int F int · dr i = W12 i ext · dr i = W12 F ext i int W12 = n � � t2 n � � t2 i=1 = i=1 = � t2 � t2 t1 int = W12 F iint · v i dt t1 t1 n � fij · v i dt j=1 j�=1 n � n � (f ij · v i + f ji · v j )dt i=1 j>1 t1 n � � f ij · (v i − v j )dt i=1 j>1 This is non-zero in general. Cite as: Thomas Peacock and Nicolas Hadjiconstantinou, course materials for 2.003J/1.053J Dynamics and Control I, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. Systems of Particles 4 Figure 2: Relative velocity probably has a component in the direction of f ij . The figure shows two random points with randomly chosen velocities. Unless the difference between the velocities of the two points is zero or perpendicular to the direction of force f ij , f ij · (v i − v j ) will not be zero; there would be some component in the direction of f ij . Figure by MIT OCW. No reason that difference between velocities should not have a component in the direction of f ij . If particles are parts of a rigid body system, then there is no relative motion in the direction of f ij (e.g.) Figure 3: Two point masses connected by a rod. This is an example of a rigid body where due to the rod, there is no relative motion of the two point masses at each end when the rigid body moves. Figure by MIT OCW. d |r − r j |2 = 0 dt i � � d (r i − r j ) · (r i − r j ) = 0 dt 2(r i − r j ) · (v i − v j ) = 0 Internal forces f ij are along the direction (r i − r j ). f ij · (v i − v j ) = 0. Therefore, for a rigid body system we have proved: Cite as: Thomas Peacock and Nicolas Hadjiconstantinou, course materials for 2.003J/1.053J Dynamics and Control I, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. Examples 5 f ij · (v i − v j ) = 0 int Therefore, W12 must be 0 (or if you show that internal forces do no work). Thus, ext W12 = T2 − T 1 More generally: ext int W12 + W12 = T2 − T 1 If all external forces are potential forces or the ones who are external do no work int and W12 = 0, ext W12 = W12 = V1ext − V2ext � V = potential work where V ext = ni=1 Viext . Viext is the external force poten­ tial of particle i. T1 + V1ext = T2 + V2ext Examples Example 1 How does l affect the motion? How does θ affect the motion? No rotations involved. Probably will not need angular momentum. Kinematics Describe the motion (kinematics) without forces Knowing the location of A is equivalent to knowing the location of the center of mass of M. v C = vA M m r A = xı̂ r B = xı̂ + sês = xı̂ + s cos θı̂ + s sin θĵ ṙ A = ẋı̂ ṙ B = ẋı̂ + ṡ cos θı̂ + ṡ sin θĵ r̈A = ẍı̂ r̈B = ẍı̂ + s̈ cos θı̂ + s̈ sin θĵ Note: Generalized coordinates. ı̂ and ês are not ⊥. Important to define coordinates. Cite as: Thomas Peacock and Nicolas Hadjiconstantinou, course materials for 2.003J/1.053J Dynamics and Control I, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. Examples 6 Figure 4: Block on frictionless surface that moves on frictionless road. The mass (m) can slide down the incline in a frictionless manner. Mass (M ) is free to move horizontally without friction. If mass (m) is released from rest at the l position, find the velocity of mass (M ) at the moment (m) reaches the bottom of the incline. Figure by MIT OCW. Figure 5: Diagram of kinematics of block on ramp. Need two sets of coordinates. M only moves in the x-direction. m only moves in the ês direction. Figure by MIT OCW. Cite as: Thomas Peacock and Nicolas Hadjiconstantinou, course materials for 2.003J/1.053J Dynamics and Control I, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY].