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Lecture 10 8.324

Relativistic Quantum Field Theory II Fall 2010

8.324

Relativistic Quantum Field Theory II

MIT OpenCourseWare Lecture Notes

Hong Liu, Fall 2010

Lecture 10

2.4: UNSTABLE PARTICLES AND RESONANCES

We recall from previous lectures that the Feynman propagator for a general interacting theory is given by

G

F

( p

2

) = Γ( s =

− p

2

+ iϵ ) , (1) where

Γ( s ) =

∑ j iZ j s

− m 2 j

+

ˆ

4 m

2

1 dµ

2

σ ( µ

2

) i s

µ 2

, and the spectral density function is given by

(2)

ρ ( µ

2

) =

1

Im ( iG

F

π

( p

2

= Z j

δ ( µ

2

) p 2 =

µ 2

)

− m

2 j

) + σ ( µ

2

) .

j

For µ 2 > 4 m 2

1

, we have that ρ ( µ 2 ) = σ ( µ 2 ) =

1

2 π

Disc( Γ( s )

| s = µ 2

) .

The reason for this is that we cannot have

Im(s) m

2

1 m

2

2

4m

2

1

Re(s) m

2

1 m

2

2

4m

1

2

μ

2

Figure 1: Plots of the function Γ( s ) on the complex plane and the spectral density function ρ ( µ 2 ).

m

2 j

> 4 m

2

1 for any particle j which interacts with the others.

We can imagine changing the parameters of the theory, so that the pole moves beyond the branch point and sits on the branch cut.

We will consider what happens in this case.

Consider the Lagrangian

L

=

1

2

( ∂ϕ )

2 −

1

2

( ∂χ )

2

+

1 m

2

2 ϕ ϕ

2

+

1 m

2

2

χ

χ

2

+

1 g

2 ϕ ϕ

3

+

· · ·

, and examine the Feynman propagator G ϕ

F

( p 2 ) .

Suppose that 2 m

χ

> m ϕ

> m

χ

.

Then, perturbatively, iG ϕ

F

( p

2

) = p 2 + m 2 ϕ

1

Π ( ϕ ) ( p 2 )

− iϵ

.

(3)

(4)

The three-point vertex rule is given by ϕ

= ig, (5)

χ ϕ and hence, to lowest order,

Π

( ϕ )

( p

2

) = , (6)

1

Lecture 10 8.324

Relativistic Quantum Field Theory II Fall 2010 and we see that Π

( ϕ )

( p

2

) becomes imaginary if

− p

2

> 4 m

2

χ

.

Naively, the pole just sits on the branch cut.

But, as we will show, the pole, in fact, moves to the other sheet of the complex plane.

Physically, the particle becomes unstable since it can decay ϕ −→ 2 χ , where the imaginary part of the pole is proportional to the decay rate.

In the

Hilbert space of physical states, no states correspond to a single ϕ -particle.

It becomes a resonance.

Im(s)

Im(s)

2 m

φ

2

4m

χ

Re(s)

4m

2

χ

Γ

2 m

φ

Re(s)

(Second sheet unstable resonance)

Γ m

2

φ

4m

2

χ

μ

2

4m

2

χ m

2

φ

μ

2

Figure 2: Formation of an unstable resonance for m ϕ

> 2 m

χ

.

From the last lecture, after subtracting divergences using counter-terms,

Π

( ϕ )

( p

2

) =

= ϕ

α

ˆ

2

0

1 dx D log D

− a

′ p

2 − b

′ m

2 ϕ

, (7) where α

≡ g

2

(4 π ) 3

, D = m 2

χ

+ x (1

− x ) p 2 , and a

′ and physical field conditions: and b

′ are finite real constants, determined by the physical mass

Π( p

2

=

− m

2

) = 0 , d Π dp 2

( p

2

=

− m

2

) = 0 .

But, for m 2 ϕ

> 4 m 2

χ

, log D is complex at p 2 = − m 2 ϕ

, and there is no way to satisfy these two conditions for real a

′ and b

.

Therefore, G

( ϕ )

F

( p

2

) cannot have a pole on the real axis.

Physically, ϕ cannot be a physical single-particle state in

H

.

What can be done to resolve this is to modify the physical mass and physical field conditions to:

(

Re

( d Π

Π( p dp 2

( p

2

2

=

− m

=

− m

2

2

)

)

)

)

= 0 ,

= 0 .

which gives suitable real solutions for a

′ and b

.

We then have

Π( p

2

) =

α

ˆ

2

0

1

D dx D log

| |

α

12

( p

2

+ m

2 ϕ

) (8)

2

Lecture 10 8.324

Relativistic Quantum Field Theory II Fall 2010 with D

0

= D ( p

2

=

− m

2 ϕ

) = m

2

χ

− x (1

− x ) m

2 ϕ

.

Let us define m ϕ

˜ ≡

Im Π( p

2

) p 2 =

− m

2 ϕ

.

Then, near p

2

=

− m

2 ϕ

, we have iG

F

( p

2

) = p 2

1

+ m 2 ϕ

Π( p 2 )

− iϵ

1

= p 2 + m 2 ϕ

− im ϕ

.

Thus, there is a pole at p 2 =

− m 2 ϕ

+ im ϕ

Γ .

In terms of the complex function Γ( s ) , there is a pole at s = m

2 ϕ

− im ϕ

˜

, (9) and so, around the ϕ -mass, the spectral density function takes the form

ρ ( µ

2

)

µ 2 ≈ m

2 ϕ

=

1

Im ( iG

π

F

( p

2

)) =

1 m ϕ

π ( µ 2

− m 2 ϕ

) 2 + m 2 ϕ

Γ 2

+

· · ·

.

Now we proceed to calculate

˜

Im ( Π( p

2

) p 2 = − m 2 ϕ

) =

α

ˆ

1

2

0 dx Im ( D

0 log

D

D

0

0

) , where D

0

= m

2

χ

− x (1

− x ) m

2 ϕ

− iϵ .

Now, D

0

< 0 for the range

1

2

1

2

1

4 m 2

χ m 2 ϕ

< x <

1 1

+

2 2

1

4 m 2

χ

, m 2 ϕ and in this region, log

|

D

0

D

0

|

=

− iπ.

Therefore, letting β =

1

− 4 m 2

χ m 2 ϕ

, we have

Im (Π(

− m

2 ϕ

)) =

απ

2

ˆ

=

πα

12 m

2 ϕ

β

3

,

1

(1+ β )

2 dx ( m

2

χ

1

2

(1 − β )

− x (1

− x ) m

2 ϕ

) and hence,

˜

πα m

12 ϕ

β

3

.

In the problem set, we will see that when m ϕ

> 2 m

χ

, we have ϕ → 2 χ

=

πα

12 m ϕ

(1

4 m 2

χ m 2 ϕ

)

3

2

, and so

˜ ϕ → 2 χ

.

We now consider a couple of additional points.

(10)

(11)

(12)

(13)

(14)

Remarks:

1.

Consider the function log z .

The function increases by 2 π as we wrap around the origin each time.

This introduces a discontinuity if we try to plot the function on one sheet of the complex plane.

Instead, we have to plot the function on multiple sheets, introducing a branch cut, for example on the first sheet at Im (log(

− x + iϵ )) = iπ , Im (log(

− x

− iϵ )) =

− iπ.

Similarly, with Γ( s ), there is a branch cut at x = 4 m 2

χ

.

When we calculated

G

F

( p

2

) =

1

(15) p 2 + m 2 ϕ

− im ϕ we treated it as an analytic function across the real axis.

In other words, we have done the analytic continuation below the cut, and so, the pole lies on the second sheet.

3

Lecture 10 8.324

Relativistic Quantum Field Theory II

Im(s) log(s)

Re(s)

Fall 2010

Figure 3: The branch cut in log( s ) and the additional sheets needed to plot the function smoothly.

Im(s)

Γ(s)

2.

3.

4m

1

2

Re(s)

Figure 4: The branch cut in Γ( s ) with the second sheet on which the pole lies.

One can show that, as a consequence of the optical theorem,

Im (Π( p

2

)) =

=

2

, (16) where the propagators are put on shell, replaced by 2 πδ ( p 2

1 problem set.

+ m 2

χ

)Θ( p 0

1

).

This will be discussed in the

Considering the propagation of an unstable particle, for t > 0,

ˆ

G

F

( t, ⃗ ) =

⟨ ϕ ( t, p ) ϕ (0 , ⃗ )

= dw e

2 π

− iωt p 2

1

+ m 2 − im Γ

, with p

2 with ω

=

ω

2

+ ⃗

2

.

Hence,

G

F

( t, ⃗ ) = e

− i ω

2

− im � t

ω 2 p

− im Γ

⃗ 2 + m 2 .

Now, for the case that Γ ≪ ω

2 m

, this reduces to

1

G

F

( t, ⃗ ) =

2 ω e

− iω t

− m �

2 ω

⃗ t

1

=

2 ω e

− iω t

− t

2 τ ( p )

(17)

(18) where we have defined the lifetime τ ( ⃗ )

≡ dilation, where Γ

1

ω p m

Γ

− 1

= √ 1

1 − v 2

Γ

− 1

, which we recognise as the effect of time is the lifetime of the particle in its rest frame.

4

MIT OpenCourseWare http://ocw.mit.edu

8.324 Relativistic Quantum Field Theory II

Fall 2010

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