Part II Problems and Solutions
Problem 1: [Second order ODEs via Laplace transform] Find the unit impulse response
of the following operators by means of the Laplace transform.
(a) 3D2 + 6D + 6I.
(b) D4 − I.
Solution: (a) w(t) has Laplace transform W (s) =
1
,
s2 +1
3s2
1
1
1
=
. L(sin t) =
+ 6s + 6
3 ( s + 1)2 + 1
so by s-shift w(t) = 13 u(t)e−t sin t.
1
. The roots of s4 − 1 are ±1 and ±i, so we can write
−1
1
a
b
c
d
=
+
+
+
. Cover-up gives easily a = b = 14 ,
4
s−1 s+1 s−i s+i
s −1
c = 4i , d = − 4i . So
�
�
w(t) = u(t) 14 et + e−t + ieit − ie−it = u(t) 12 (sinh(t) − sin(t))
(where sinh(t) = 12 (et + e−t ), the hyperbolic sine function)
(b) W (s) =
s4
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