MIT OpenCourseWare http://ocw.mit.edu 5.80 Small-Molecule Spectroscopy and Dynamics Fall 2008 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms. 5.80 Lecture #14 Fall, 2008 Page 1 of 7 pages Lecture #14: Definition of Angular Momenta and |A α MA〉. ROT Evaluation of H We want to be able to set up effective Hamiltonian models for rotation-vibration-electronic structure of diatomic molecules with non-zero electronic angular momenta. are The important terms in H ROT = B(R)R 2 H SO = H ∑ a (r )̂ ·sˆ i i i i electrons ROT and H SO — HUND’S CASE A * a convenient basis set for evaluating matrix elements of H ,A , and A ,A ± and A 2 operators and |A α M 〉 basis functions * A z ± Z A * Heff and van Vleck Corrections to Heff * Limiting cases where Heff is approximately diagonal and energy levels are expressed in terms of a pattern-forming rotational quantum number like J(J + 1), N(N + 1), R(R + 1). (Example in next lecture for 2∏ and 2∑+ states.) * effects of accidental degeneracies — perturbations. Angular Momenta R L S J N J a nuclear rotation e– orbital angular momentum e– spin +L + S R total angular momentum +L angular momentum. exclusive of spin J − S = R + S total electron angular momentum = L See H. Lefebvre-Brion/R. W. Field, pages 72-81. All angular momenta can be defined by their commutation rules. 5.80 Lecture #14 Fall, 2008 Page 2 of 7 pages ⎡⎣A ,A ⎤⎦ = +i ε A k ∑ ijk i j k εijk +1 for x, y, z in cyclic order –1 for non-cyclic 0 repeated coordinator , S , R , Above is a “normal” Commutation Rule which is applicable for all SPACE components of J , L , J a and all body components of L , S (but not J , R , N ). N involve rotation of body 2, A , A from Trivial matter to derive properties of eigenbasis |A α MA〉 under operation by A i ± commutation rule. 2 A AαM A = 2 A(A + 1) AαM A z AαM = α AαM A A A Z AαM = M AαM A A A A ± X ± iA Y (up for upper case) A ± ≡ A x ± iA y and A ≡ A ± AαM = [ A(A +1) − α(α ±1)]1/2 Aα ±1M A A A ± “raises” α A + “lowers” α A – 1/2 A AαM A = [ A(A +1) − M A (M A ±1)] AαM A ±1 + “raises” Μ A Α 5.80 Lecture #14 Fall, 2008 Page 3 of 7 pages This is all you need to know for rotation of diatomic molecules EXCEPT i, A j ⎤⎦ = −i ε A Anomalous commutation rule ⎡⎣A ∑ ijk k applies only to BODY components of J , R , N . k The only difference is ± AαM = + [ A(A + 1) − α(α 1)]1/2 A α 1 M A A A acts as a “lowering” operator rather than as raising operator. A + do to |A α M 〉 basis functions. Now, suppose we want to evaluate what other angular momenta than A A by similar commutation rules. We classify these other operators as vectors or scalars with respect to A (some other operator The Wigner-Eckart Theorem will eventually tell us how to evaluate the effect of B ) on |A α M 〉. classified by its commutation rule with respect to A A i ⎤⎦ = ⎡⎣S , A ± ⎤⎦ = 0 all i, I and S |A α M 〉 = s |A α M 〉. A scalar is defined as ⎡⎣S , A A A A ) is defined as A normal vector (with respect to A ,V j ⎤ = +i ⎡⎣ A i ⎦ ∑ ε ijk Vk k It happens that ,S ⎤ = ⎡ L ⎡⎣ L i j ⎦ ⎣ I ,S J ⎤⎦ = 0 , S operate on different coordinates and are L scalar operators with respect to each other and all angular momenta obey normal vector operator commutation rules with respect to J for space fixed components. J generates rotations in lab frame ⎤ = i ε A ⎡⎣ J I , A ∑ IJK K J ⎦ k for body and all angular momenta obey anomalous vector operator commutation rules with respect to R fixed components. generates rotations in body frame. R ,A ⎤ = –i ε A ⎡⎣ R ∑ ijk k i j ⎦ k +L + S . See this in example. j ⎤⎦ = ⎡⎣J i ,S j ⎤⎦ = 0 because J = R This has convenient effect that ⎡⎣J i , L 5.80 Lecture #14 Fall, 2008 Page 4 of 7 pages ⎡⎣J i , L j ⎤⎦ = ⎡⎣R i, L j ⎤⎦+ ⎡⎣L i, L j ⎤⎦+ ⎡⎣S i , L j ⎤⎦ E.g. –iεijkLk +iεijkLk =0 which means that J acts as a scalar operator with respect to |n L Λ S ∑〉 so we can factor ψ into electronic ⊗ vibration ⊗ rotation factors! So we can write a convenient basis set. Case (a) fully “uncoupled” basis set in body configuration or index |v〉 |nLΛ〉|S∑〉 |ΩJM〉 electronic rotation very convenient for body fixed matrix elements vibration 2 in this case(a) basis set. Now we can work out matrix elements of B(R) R v B(R) v ≡ Bv to cancel the 2 from all angular momentum matrix elements 2 (Note 〈v|B(R)|v′〉 = Bvv′ ≠ 0) We will see these again when we use J = 0 potential energy curve to derive centrifugal distortion effects. = J – L – S R R Evidently z ≡ 0 So R 5.80 Lecture #14 Fall, 2008 Page 5 of 7 pages 2 2 2 x − S x ) + ( J y − L y − S y ) R = R ·R = R x + R y = ( J x − L 2 2 = ( J 2x + J 2y ) + ( L2x + L2y ) + (S2x + S2y ) –2(JxLx + JyLy) No need to be careful of order of operators because body components of and S commute with each other and L with those of J . –2(JxSx + JySy) +2(LxSx + LySy) Now for some convenient simplifications. A 2x + A 2y = A 2 − A 2z 2 ( A x Bx + A y By ) = ( A + B− + A − B+ ) confirm for yourself 2 = ( J 2 − J 2 ) + ( L2 − L2 ) + (S2 − S2 ) Thus R z z z plus off-diagonal terms below. L–uncoupling term S–uncoupling term Rotation-electronic term –(J+L– + J–L+) –(J+S– + J–S+) +(L+S– + L–S+) diagonal part selection rules ∆Ω = ∆Λ = ±1 ∆Ω = ∆Σ = ±1 ∆Λ = –∆Σ = ±1 (∆Ω = 0) So we are almost ready to set up Heff. However L is not a well defined quantity. Non-Lecture: Stark effect in atoms ∆ = ±1 +↔ – ∆ ML = ∆ λ = 0 Electric field (axially symmetric) of atom B mixes L’s in atom A 5.80 Lecture #14 Fall, 2008 Page 6 of 7 pages typically 105 cm–1 for 1e– at 1Å ψ A = ∑ a nL nLA M LA nL a nL n′ L′ nL H ~ o E nL − E on ′L′ typically 104 cm–1 for different nL states of atom * LA destroyed * M LA preserved * L2 and L± matrix elements not explicitly defined (become perturbation parameter) * L2 and L± and Lz selection rules on Λ are preserved! * ( L2 − L2z ) ≡ L2⊥ treated as a constant * + v′, n′ Λ −1 S ∑ ≡ B β or β perturbation parameter. v, n Λ S ∑ BL vv′ v′v ROT = B(R)R 2 Matrix elements of H 1. Diagonal part (in v, n, Λ, S, ∑, J, Ω, M) B(R)⎣⎡( J 2 − J 2z ) + (L2⊥ ) + (S2 − S2z )⎤⎦ Bv ⎡⎣J(J + 1) − Ω 2 + L2⊥ + S(S +1) − ∑2 ⎤⎦ include BvL2⊥ in Te + G(v) 2. Within a 2S+1Λ multiplet state. The splitting of Ω-components within an S ≠ 0 state is SO and is usually small relative to splittings due to H between different nΛ states. HSO gives “fine structure”. o Spin-uncoupling term — will destroy ∑, Ω provided that E Ωo − E Ω±1 is small. 5.80 Lecture #14 Fall, 2008 Page 7 of 7 pages −B(R)[ J + S− + J − S+ ] − ( BV / 2 ) ∑ ±1 Ω ± 1 J S H ROT ∑ΩJS = −Bv [ J(J + 1) − (Ω ± 1)Ω ] 1/2 [S(S + 1) − (∑ ±1)∑ ]1/2 notice Ω′Ω, ∑′∑ ROT will always overwhelm Above matrix element is ≈ proportional to J, so at high J H o ∑ and Ω are destroyed, thus spin “uncouples from body frame”. ∆ E Ω,Ω±1 3. Between two electronic states ∆S = 0, ∆∑ = 0, ∆Λ = ∆Ω = ±1 “L-Uncoupling” (even though L is already destroyed) destroys Λ and Ω. − + J − L + ] − ( B(R) 2 )[ J + L − ⎡⎣ vΛ ±1 B(R) vΛ − + J − L + ) n Λ S ∑ J Ω 2 ⎤⎦ n′ Λ ± 1 S ∑ J Ω ± 1 ( J + L −BvΛ±1vΛ [ J(J + 1) − (Ω ± 1)Ω ] 1/2 4. n′Λ ± 1 L ± nΛ β ( n′Λ′, nΛ ) −BvΛ±1vΛ β ( n′Λ′, nΛ ) ≡ β an unknown perturbation parameter to be determined directly from spectrum Between two electronic states ∆Ω = 0 ∆Λ = –∆∑ = ±1 +β[S(S + 1) – ∑(∑ ± 1)]1/2 same β as above in #3 for L-uncoupling