5.72 Problem set #4 (spring 2012) Cao I. Harmonic Oscillator 1) For a harmonic oscillator, show that πΆ(π‘) = 〈π₯(π‘)π₯(0)〉 satisfies πΆΜ + π02 πΆ = 0. 2) Solve for πΆ(π‘) and its Fourier transform πΆΜ (π) = ∫ πΆ(π‘)π πππ‘ ππ‘. 3) The forced oscillator obeys the equation of motion ππ₯Μ + ππ02 π₯ = π(π)π −πππ‘ . Derive the expression for π(π) from the above equation. 4) Write the formula for πΎ(π‘). π½π Μ 5) Verify πΎ(π‘) = −π½πΆ(π‘) [i.e. π ′′ = πΆΜ (π)]. 2 6) *Verify the Kramers-Kronig relations. II. The relaxation of rotational motions can be described by the rotational diffusion equation ππ ππ‘ = π·π ∇2 π, where ∇2 is the angular part of the Laplacian operator 1 π π 1 π2 ∇ = sin π + 2 . sin π ππ ππ sin π ππ 2 1) Show that the average orientation π’(π‘) = 〈cos π(π‘)〉 satisfies π’Μ (π‘) = −2π·π π’(π‘). 2) Show that the orientational correlation function is given by 1 πΆ(π‘) = 〈cos π(π‘) cos π(0)〉 = π −2π·π π‘ . 3 3) Write down πΎ(π‘), π′, and π′′. 4) Calculate the response to a monochromatic force πΉ(π‘) = πΉ0 cos π0 π‘, which couples to the system according to π» ′ = −πΉ(π‘) cos π(π‘). 5) Calculate the average absorption rate. (Ref: McQuarrie, p. 398, prob. 17-19) 2 III. Repeat the steps in Problem I for a damped oscillator described by ππ₯Μ + ππΎπ₯Μ + ππ02 π₯ = π(π‘) + πΉ(π‘), where π(π‘) is the random force and πΉ(π‘) is the external driving force. 1) Show the position correlation function satisfies ππΆΜ + ππΎπΆΜ + ππ02 πΆ = 0 with the initial condition πΆ(0) = (π½ππ02 )−1 . 2) Derive explicit expressions for πΆ(π‘) and its Fourier transform πΆΜ (π). 3) Show that under the external force the average position π₯Μ satisfies πΉ(π‘) π₯ΜΜ + πΎπ₯ΜΜ + π02 π₯Μ = . π 4) Solve π(π) from the above equation. 5) Derive πΎ(π‘) using the expression for π(π) found above. 1 6) Verify πΎ(π‘) = −π½πΆΜ (π‘). IV. *Derivation of quantum response theory (Ref: McQuarrie, Berne, Kubo, Reichl). 1 1) Define the quantum Liouville operator as βπ΄ = [π», π΄]. Show that π΄Μ(π‘) = β πβ(π‘)π΄(π‘) and πΜ = −πβπ, where π is the density matrix and π΄(π‘) is a Heisenberg operator. 2) Given π» = π»0 − π΄πΉ(π‘), use perturbation theory to show where πΎ(π‘ − π‘ ′) π 〈π΄(π‘)〉 = ′ π‘ −∞ = 〈[π΄(π‘), π΄(π‘ )]〉. β πΎ(π‘ − π‘ ′ )πΉ(π‘ ′ )ππ‘′ , 3) Show that the classical limit of the quantum commutator is: where { , } is the Poisson bracket. 4) Show that the classical limit of πΎ(π‘) is −π½πΆΜ (π‘). 1 πβ [π΄, π΅] = {π΄, π΅}, V. Spectroscopic measurements are expressed as polarization responses. We calculate the response function of a linear harmonic oscillator as an example. 1) The linear response function is defined as π π π (π‘) = β¨0|[πΌ(π‘), πΌ(0)]|0β© = [β¨0|πΌ(π‘)πΌ(0)|0β© − β¨0|πΌ(0)πΌ(π‘)|0β©], β β where the transition dipole is assumed to be linear in coordinate πΌ(π‘) = πΌ0 π₯(π‘). Show π (π‘) = sin ππ‘ ππ Useful expressions: π₯(π‘) = β 2ππ πΌ02 . ππ −πππ‘ + π† π πππ‘ , 0 ππ† 0 = 1, 0 π† π 0 = 0. 2) Show that the same result can be obtained classically by replacing the quantum commutation with the Poisson bracket, 1 ππΌ(π‘) ππΌ(0) ππΌ(π‘) ππΌ(0) [πΌ(π‘), πΌ(0)] → {πΌ(π‘), πΌ(0)} = − πβ ππ₯(0) ππ(0) ππ(0) ππ₯(0) Useful expression: π₯(π‘) = π₯(0) cos ππ‘ + π(0) ππ sin ππ‘ 3) The non-linear response function is defined as π 2 π (π‘1 , π‘2 ) = 0 [πΌ(π‘1 + π‘2 ), πΌ(π‘1 )], πΌ(0) 0 , β If πΌ = πΌ0 π₯, show π (π‘1 , π‘2 ) = 0 from the balance of π and π† operators. 4) *To obtain non-vanishing non-linear response for the harmonic oscillator, we introduce a non-linear coordinate dependence, πΌ = πΌ0 π₯ + πΌ ′ π₯ 2 + β― Show that the leading order term in πΌ′ is proportional to πΌ02 πΌ′. 2 MIT OpenCourseWare http://ocw.mit.edu 5.72 Statistical Mechanics Spring 2012 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.