10.37 Chemical and Biological Reaction Engineering, Spring 2007 Prof. K. Dane Wittrup Lecture 7: Batch Reactors This lecture covers batch reactor equations, reactor sizing for constant volume and variable volume processes. Batch Reactors Run at non-steady state conditions Which to choose? Batch vs. CSTR? Batch CSTR Figure 1. Schematics of a batch reactor and a CSTR. Small Amount of Material (small quantities) (does not tie up equipment continuously) Flexibility + - Expensive Reactants + - If product does not flow, Materials Handling (e.g. Polymers) + - Do not have to shut down and clean, less down time - + Captial costs? For size of reactor, for given conversion + (concentration stays higher longer) Operability & Control (T, P, p4) e.g. Exothermic reaction - - + (Manipulate only one setpoint, steady state. You can control additional variables. Such as flow rates.) Material Balance 0 In – Out + Product = Accumulation 0 Cite as: K. Dane Wittrup, course materials for 10.37 Chemical and Biological Reaction Engineering, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. rA V = dN A dt Constant V, dC A dt rA = In terms of conversion, Integrating, C Ao dX A = rA dt X A dX dC A A or t = C Ao ∫ 0 C Ao r r A A t=∫ CA 1st Order Reaction A ⎯k⎯ →B − rA = kC A = kC Ao (1− x A ) t = C Ao ∫ xA 0 dx A − kC Ao (1 − x A ) → ⎯⎯ t= 1 ⎛ 1 ⎞ ln ⎜ ⎟ k ⎝ 1− x A ⎠ xA = 1 − e −kt t90.0% = 90% conversion (order of 1 ⎛ 1 ⎞ 2.3 ln ⎜ ⎟= k ⎝ 1 − 0.9 ⎠ k 1 ) k 2nd Order Reaction A + A ⎯k⎯ →B −rA = kC A2 = kC Ao 2 (1− X A )2 XA dX A 1 = t = C Ao ∫ 2 2 0 −kC Ao −kC Ao (1 − X A ) t= If XA 1 kC Ao 1− X A XA = ∫ XA 0 dX A (1− X A ) 2 kC Aot 1+ kC Aot kfirst order = ksecond order C Ao , which is faster? 1st order 2nd order 1 0.63 0.50 2 0.86 0.67 3 0.95 0.75 }x A For a given Damkohler number, 1st order is faster. The second order reaction has greater concentration dependence. Exponential approach (1st order) is faster. 10.37 Chemical and Biological Reaction Engineering, Spring 2007 Prof. K. Dane Wittrup Lecture # Page 2 of 5 Cite as: K. Dane Wittrup, course materials for 10.37 Chemical and Biological Reaction Engineering, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. Batch Cycle Time t Charge rxn Discharge Clean Downtime, td How long should t be? How high should X A be? Economic calculation: Compare economics of further conversion to a different use of equipment Chemical consideration: Will product degrade? Assume product stable. Product produced in one cycle = X AC Ao V Pr(Rate of Production) = X AC Ao V t + td What value of t will maximize Pr? If there is a maximum of Pr vs. t, Assume td = constant. (toptimum + td ) 0= d Pr =0 dt d Pr = C Ao V dt dX A − XA dt (toptimum + td ) 2 (toptimum + td ) dX A − XA = 0 dt Now specify kinetics. There may be no optimum. X A = 1 − e− kt dX A = ke− kt dt − ktoptimum − kt (toptimum + td )ke − (1− e optimum ) = 0 1st order Can numerically solve for toptimum . 10.37 Chemical and Biological Reaction Engineering, Spring 2007 Prof. K. Dane Wittrup Lecture # Page 3 of 5 Cite as: K. Dane Wittrup, course materials for 10.37 Chemical and Biological Reaction Engineering, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. Semi-batch Reactor or Figure 2. Schematics of two types of fed-batch reactors. 1) Why? • To remove “poisonous” product • Make room in reactor (expansion of product) • If a reactant has a negative order effect on rate, add in small quantities • Selectivity A + B → Desired (control) A + A → Byproduct Start with B, slowly feed A. slow feed of A Figure 3. A fed-batch reactor with a slow feed of one reactant. B • • • To shift equilibrium, strip off product To control evolution of heat In biological cases Fed-batch - Feed in carbon source slowly to avoid overflow metabolism - (glucose) - O2 sparingly soluble, must feed. 2) Balances B A Balance Figure 4. Fed-batch reactor with a feed of B. A In – Out + Product = Accumulation rA V(t ) = d (rA V) dt 10.37 Chemical and Biological Reaction Engineering, Spring 2007 Prof. K. Dane Wittrup Lecture # Page 4 of 5 Cite as: K. Dane Wittrup, course materials for 10.37 Chemical and Biological Reaction Engineering, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. dC A dV + CA dt dt Liquid V = V0 + v0t rA V(t ) = V flow dilution v dC A = rA − 0 C A dt V0 B Balance v v dCB = rB + 0 CBo − 0 CB dt V0 V0 N Addition Dilution 10.37 Chemical and Biological Reaction Engineering, Spring 2007 Prof. K. Dane Wittrup Lecture # Page 5 of 5 Cite as: K. Dane Wittrup, course materials for 10.37 Chemical and Biological Reaction Engineering, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY].