10.569 Synthesis of Polymers Prof. Paula Hammond Tromsdorff Effect, Instantaneous P

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10.569 Synthesis of Polymers

Prof. Paula Hammond

Lecture 13: Thermodynamics of Free Radical Polymerizatioins, Ceiling T’s,

Tromsdorff Effect, Instantaneous P n

Thermodynamics (Continued)

Δ H o − T Δ S o = Δ G o = − RT ln K eq

Δ G = Δ G o + RT ln K eq

in general but at equilibrium:

Δ G = 0 = Δ G o + RT ln K eq so Δ H o − T c

Δ S o = − RT c ln

M

1

[ ] c

at equilibrium where [M] c

= ceiling monomer con’c

Solve for T c

:

T c

=

Δ H o

Δ S o + R ln[ M ] c

[ ] c

=

[ ] eq

[ ] o s

Equilibrium

S.S. in mol/L (standard state in mol/L)

[ ] o s

⇒ bulk concentration of monomer or 1 mol/L (depending on

We will use 1 mol/L

Susceptible polymers for “unzipping”

Carbonyl: CH

2

=O

CH

3

—CH=O

CCl

3

—CH=O

Cyclics:

O

THF

Other carbonyls

O O

O

O O trioxane unzips via

H

C

2

O n as well

Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 materials, MIT

OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date.

Monomer [M] c

@ 25 o C (mol/L)

Vinyl acetate

H

1x10 -9

O

O

H

3

C

Methyl metacrylate (MMA)

CH

3

T c

(pure monomer) (

∼ 400 o C or higher

1x10 -3 220 o C o C)

O

H

3

CO

α -methyl styrene

2.2 61 o C

Polydispersity Index (PDI) for Free Radical Polymerization

ν =

R p

R t

= k k p t

[ ]

[ ]

= (for thermally diss. initiator) = k p

[ ]

(

2 k d fk t

) 1

2 p n

= 2 a ν

Statistical Approach p = probability of growth of polymer chain

= “propagation probability” p = k M k p

[ ]

[ ]

+ 2 k t

[

M ⋅

]

=

R p

R

+ R t p

(

+ R tr

)

if needed (for chain transfer)

1-p = probability of chain termination

1 − p = k p

2 k t

[ ]

[ ]

+ 2 k t

X i

= number fraction of radicals having reached degree of polymerization = i

X i

= p (i-1) (1-p)

for chain end

10.569, Synthesis of Polymers, Fall 2006

Prof. Paula Hammond

Lecture 13

Page 2 of 5

Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 materials, MIT

OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date.

p n

=

∑ iXi i = 1

Xi

=

∑ iXi =

(

1 − p

) ∑ ip i = 1

∞ i = 1

( i − 1

)

1.0

⇒ p n

=

1

1 − p here p ≠ π as in step growth p n

= now

1 −

1 p

=

R p

+ R t

R t

→ 1.0 (i.e. R p

>> R t

) p =

R

R p p

+ R t

⇒ p n

→ ν

⇒ p n

R p

R t p w

=

∑ iWi =

∑ i

2

Xi iXi

=

∑ p i

2 n

Xi

apply series defn weight fraction

⇒ p w

=

1 + p

1 − p

PDI: z = 1+p } disproportionation as p → 1.0 z → 2.0

This all assumes termination by disproportionation

If we assume coupling, account for ∼ X ⋅ + ⋅ Y ∼

⇒ p n

=

2

1 − p p w

=

2 + p

1 − p as 1.0 z → 3/2 z = p w p n

=

2 + p

2

10.569, Synthesis of Polymers, Fall 2006

Prof. Paula Hammond

Lecture 13

Page 3 of 5

Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 materials, MIT

OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date.

Instantaneous vs. Integrated Rate Expressions

R p

= k p

⎜ fk d

⎝ k t

1

2 [ ] 1

2

[ ]

= − d

[ ] dt

instantaneous expression

Express things in terms of π (monomer conversion)

π =

[ ] o

[ ] o

[ ]

= 1 −

[ ] o d π dt

= −

M

1

[ ] o dt d π dt

= k p ⎜

⎛ fk d k t

1

2

[ ] 1

2

[

1 − π

] integrate assuming a constant [I] = [I] o

π ( )

= 1 − exp

⎢ k p

⎝ fk k t d

1

2 [ ] o t

⎥ so applies to batch polymer [M] ↓ but [I] constant ⇒ e.g. early stages of polymer

If [I] is not held constant: d dt

= − k d

[ ] [ ] o exp

(

− k t

) d π dt

= k

⎛ p

⎝ fk k t d

1

2 [ ] 1

2 exp

− k t

2

(

1 − π

)

Integrate from t=0 to t:

π t

= 1 − exp

⎜⎜

2 k k d p

⎠⎝

⎛ fk

⎜⎜ k t d

1

2

⎟⎟

[ ] 1

2

⎢ exp ⎜

⎣ ⎝ k d

2 t

⎞ −

1 ⎥

⎦⎪

global → conv at that time

10.569, Synthesis of Polymers, Fall 2006

Prof. Paula Hammond

Lecture 13

Page 4 of 5

Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 materials, MIT

OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date.

[M], [I] ↓ ⇒ R p

Max conversion is batch situation: t

So that all of I is consumed

π max

= 1 − exp

⎨−

⎜⎜

2 k k d p

⎟⎟

⎠⎝ fk d k t

1

2

1

2 o

⎭ e.g. Polystyrene, 1 wt% AIBN

⇒ π max

= 96.7% p n

= f ( t ) p n becomes fxn of time p n

( )

=

R p

R i t

( )

( )

[M]

[I]

Time avg value: p n

( )

= tot mol of monomer polym tot mol of "dead" chains (formed)

= o

π o

(

1 − exp

(

− k d t

))

10.569, Synthesis of Polymers, Fall 2006

Prof. Paula Hammond

Lecture 13

Page 5 of 5

Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 materials, MIT

OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date.

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