ENTROPY AND THE 2nd LAW 1 2 2 1 T bath dS ≥ 0 dS1 ≥ dQ1 / Tbath 8.044 L10B1 S as a State Function Note: adiabatic (≡ d /Q = 0) ⇒ constant S if the change is quasistatic. This is the origin of the sub­ script S on the adiabatic compressibility. 1 ∂V κT ≡ − V ∂P T 1 ∂V κS ≡ − V ∂P S 8.044 L10B2 Example A Hydrostatic System dS = ∂S ∂S dT + dV ∂V T ∂T V 1 P = dU + dV T T = by expansion from dU = T dS − P dV 1 ∂U 1 dT + T T ∂T V ∂U + P dV ∂V T by expansion of U But the cross derivatives of S must be equal. 8.044 L10B3 ∂ 1 ∂U 1 ∂ 2U = ∂V T ∂T V T T ∂V ∂T ∂ 1 ∂T T ∂U +P ∂V T 1 =− 2 T V 1 ∂P ∂U 1 ∂ 2U +P + + ∂V T T ∂V ∂T T ∂T V Equating these two expressions gives ∂U ∂P +P =T ∂V T ∂T V ∂U ∂P =T −P ∂V T ∂T V New Information! Does not contain S! 8.044 L10B4 CONSEQUENCES a) γ � � �� � � ∂U ∂U d /Q = dU + P dV = dT + + P dV T ' ∂T V. V ' ∂V V. CV T ∂P ∂T � � ∂P d /Q ≡ CP = CV + T dT P ∂T V � V � ∂V ' ∂T V. P αV � � � � 1 ∂V 1 ∂V Use α ≡ and κT ≡ − . V ∂T P V ∂P T 8.044 L10B5 ∂P −1 = ∂T ∂V ∂T V ∂V ∂P P = (−1) ∂V ∂T T 2V α T α CP − CV = T αV = κT κT ∂V ∂P T P α = κT T α2 V → γ−1= κT CV For an ideal gas P V = N kT ⇒ α = 1/T and κT = 1/P . Thus V /T = Nk CP − CV = 1/P This holds for polyatomic as well as monatomic gases. 8.044 L10B6 CONSEQUENCES b) Ideal Gas: CV N kT P = V ∂U Nk =T −P =P −P =0 ∂V T V ∂U ∂U dU = dT + dV = CV dT ∂T ∂Vv- T v- V CV U = � T 0 0 CV (T ', V ) dT ' + constant (∂U/∂V )T = 0 for all T ⇒ CV is not f (V ); CV = CV (T ). 8.044 L10B7 CONSEQUENCES c) Ideal Gas: S � � � � ∂S ∂S dS = dT + dV ∂T V ∂V T � � ∂S d /Q ≡ CV = T dT V ∂T V d /Q = T dS dU P dU = T dS − P dV ⇒ dS = + dV T T � � � � ∂S 1 ∂U P = + . ∂V T T - ∂V1L T T -1L 0 N k/V 8.044 L10B8 Nk CV (T ) dS = dT + dV T V CV (T ') V ' dT + N k ln( ) + S(T0, V0) S(T, V ) = ' T0 T V0 T For a monatomic gas CV = (3/2)N k. T V S(T, V ) − S(T0, V0) = (3/2)N k ln( ) + N k ln( ) T0 V0 = V N k ln T V0 T0 3/2 8.044 L10B9 V isentropic (adiabatic) ⇒ T 3/2 V 2/3T V 5/3P are constant 8.044 L10B10 Maxwell Relations dE(S, V ) = ∂E ∂E dS + dV ∂S V ∂V S = T dS − P dV expansion 1st and 2nd laws ∂T ∂P ⇒ =− ∂V S ∂S V 8.044 L10B11 dE(S, L) = T dS + FdL ⇒ dE(S, M ) = T dS + HdM ⇒ ∂T ∂F = ∂L S ∂S L ∂T ∂H = ∂M S ∂S M Observe: d(T S) = T dS + SdT d(P V ) = P dV + V dP 8.044 L10B12 Helmholtz Free Energy F ≡ E − TS dF = −SdT − P dV Enthalpy ⇒ ∂S ∂P = ∂T V ∂V T H ≡ E + PV dH = T dS + V dP ⇒ ∂T ∂V = ∂P S ∂S P 8.044 L10B13 Gibbs Free Energy G ≡ E + PV − TS dG = −SdT + V dP ⇒ ∂S ∂V − = ∂T P ∂P T E, F , H and G are called ”thermodynamic potentials”. 8.044 L10B14 The Magic Square Mnemonic x E -V F dE = T dS + Xdx S H -T P G ∂S ∂V (−1) = (−1)(−1) �� � ∂T ∂P T P (+1) X 8.044 L10B15 MIT OpenCourseWare http://ocw.mit.edu 8.044 Statistical Physics I Spring 2013 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.