Guess the Bigger Number Mathematics for Computer Science MIT 6.042J/18.062J Team 1: • Write different integers between 0 and 7 on two pieces of paper • Show to Team 2 face down Introduction to Random Variables Team 2: • Expose one paper and look at number • Either stick or switch to other number Team 2 wins if gets larger number Albert R Meyer, May 3, 2010 lec 13M.1 Strategy for Team 2 switch if threshold Z where Z is a random integer, 0 Z 6. May 3, 2010 May 3, 2010 lec 13M.4 Analysis of Team 2 Strategy Case M: low Z < high Team 2 wins in this case, so Pr{Team 2 wins | M} = 1 and Pr{M} = Albert R Meyer, May 3, 2010 Case L: Z < low Team 2 will switch, so wins iff low card gets exposed Team 2 will stick, so wins iff high card gets exposed Pr{Team 2 wins | H} = May 3, 2010 lec 13M.5 Analysis of Team 2 Strategy Case H: high Z Albert R Meyer, lec 13M.2 Analysis of Team 2 Strategy • pick a paper to expose giving each paper equal probability. • if exposed number is “small” then switch, otherwise stick. That is Albert R Meyer, Albert R Meyer, Pr{Team 2 wins | L} = lec 13M.6 Albert R Meyer, May 3, 2010 lec 13M.7 1 Analysis of Team 2 Strategy So 1/7 of time, sure win. Rest of time, win 1/2, so Pr{Team 2 wins} = Albert R Meyer, May 3, 2010 Does not matter what Team 1 does! lec 13M.8 …& Team 1 can play so Pr{Team 2 wins} whatever Team 2 does May 3, 2010 lec 13M.10 Random Variables May 3, 2010 May 3, 2010 lec 13M.9 Informally: an RV is a number produced by a random process: •threshold variable Z •number of larger card •number of smaller card •number of exposed card Albert R Meyer, May 3, 2010 lec 13M.11 Intro to Random Variables Informally: an RV is a number produced by a random process: •#hours to next system crash •#faulty chips in production run •avg # faulty chips in many runs •#heads in n coin flips Albert R Meyer, Albert R Meyer, Random Variables Team 1 Strategy Albert R Meyer, Analysis of Team 2 Strategy lec 13M.12 Example: Flip three fair coins C ::= # heads (Count) Albert R Meyer, May 3, 2010 lec 13M.13 2 What is a Random Variable? Intro to Random Variables Specify events using values of variables •[C = 1] is event “exactly 1 head” Pr{C = 1} = 3/8 •Pr{C 1} = 7/8 •Pr{C·M > 0} = Pr{M>0 and C>0} = Pr{all heads} = 1/8 Albert R Meyer, May 3, 2010 Formally, R:S Sample space Albert R Meyer, lec 13M.14 Independent Variables lec 13M.15 alternate version: Pr{R = a AND S = b} = Pr{R = a} · Pr{S = b} [R = a], [S = b] are independent events for all a, b May 3, 2010 May 3, 2010 Independent Variables random variables R,S are independent iff Albert R Meyer, (usually) Albert R Meyer, lec 13M.16 May 3, 2010 lec 13M.18 Binomial Random Variable Binomial Random Variable Bn,p::= # heads in n independent flips. Coin may be biased. So 2 parameters n ::= # flips, p ::= Pr{head}. C is binomial for 3 flips: C is B3,1/2 Bn,p::= # heads in n independent flips. Coin may be biased. So 2 parameters n ::= # flips, p ::= Pr{head}. C is binomial for 3 flips: C is B3,1/2 for n=5, p=2/3 Pr{HHTTH} = Pr{H}Pr{H}Pr{T}Pr{T}Pr{H} (by independence) for n=5, p=2/3 Pr{HHTTH} = Albert R Meyer, May 3, 2010 lec 13M.26 2 3 2 3 3 2 13 Albert R Meyer, 3 2 1 31 3 May 3, 2010 2 3 lec 13M.27 3 Binomial Random Variable Binomial Random Variable Bn,p::= # heads in n independent flips. Coin may be biased. So 2 parameters n ::= # flips, p ::= Pr{head}. Bn,p::= # heads in n independent flips. Coin may be biased. So 2 parameters n ::= # flips, p ::= Pr{head}. Pr{each sequence w/i H’s, n-i T’s} = Pr{get i H’s, n-i T’s} = ( p 1p i Albert R Meyer, n pi 1 p i ) ( ni May 3, 2010 Albert R Meyer, lec 13M.29 Binomial Random Variable B n,p = i ( Albert R Meyer, so ) ni May 3, 2010 lec 13M.30 The Probability Density Function of random variable R, }= n pi 1 p i May 3, 2010 Density & Distribution Bn,p::= # heads in n independent flips. Coin may be biased. So 2 parameters n ::= # flips, p ::= Pr{head}. Pr{ ) ni lec 13M.31 Uniform Distribution PDFR(a) ::= Pr{R = a} n ni PDFB i = pi 1 p n,p i () Albert R Meyer, ( ) May 3, 2010 lec 13M.32 Team Problems R is uniform iff PDFR is constant. R ::= outcome of fair die roll. Pr{R=1} = Pr{R=2} = ··· = Pr{R=6} = 1/6 S ::= 4-digit lottery number Pr{S = 0000} = Pr{S = 0001} = ··· = Pr{S = 9999} = 1/10000 Albert R Meyer, May 3, 2010 lec 13M.34 Problems 24 Albert R Meyer, May 3, 2010 lec 13M.40 4 MIT OpenCourseWare http://ocw.mit.edu 6.042J / 18.062J Mathematics for Computer Science Spring 2010 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.