TRANSIENT SIGNALS IN COMPUTERS Ideal World: • Only 1’s and 0’s • Instantaneous links Reality: • • • • Voltages exhibit propagation delay, decay, reflections Spurious transients can superimpose to flip bits erroneously RFI generated and picked up by wires can flip bits Ground loops matter vs. good risky L12-1 TEM LINE THEVENIN EQUIVALENT Example: Given Vs(t): z z v(z,t) = v + (t - ) + v - (t + ) c c 1 z z i(z,t) = [v + (t - ) - v - (t + ) Zo c c Rs + Vs - i(t, z=0) + v(t, z=0) - Zo Assume v- = 0 (no other sources) Then v(t, z=0) = Zo i(t, z=0) yields equivalent circuit Solution at terminals: v+(t, z=0) = Vs(t) Zo (voltage divider equation) Zo + R s Solution for all t,z: Zo v + (t,z) = Vs (t − z ) c Z o + R s (forward propagating wave only) L12-2 TEM LINE THEVENIN EQUIVALENT Voltages at an Open Circuit: v+(t – z/c) i(t,D) = Yo[v+(t,D) – v-(t,D)] = 0 (open circuit) ⇒ v-(t,D) = v+(t,D) ⇒ v(t,D) = v+(t,D) + v-(t,D) = 2v+(t,D) + v(t,D) - Thevenin Equivalent for TEM source: vopen circuit(t) = 2v+(t) = VTh(t) z D 0 + VTh(t) = 2v+(t) - + Zo v(t,D) - Example—Resistive Load: Zo At z = D: v-(t) = vL(t) – v+(t) + + R But: v(t) = 2v+(t) VTh = 2v+(t) vL(t) R + Zo R − Zo = v+(t) Γ Thus: v-(t) = v+(t) D R + Zo Rn − 1 Define: Γ = “reflection coefficient” = v-/v+ at load = R + 1 R z n (= 0 if R = Z0, = -1 if R = 0, and = +1 if R = ∞) L12-3 CAPACITIVELY TERMINATED TEM LINE Example: Capacitive Load 1 Zo u(t) + Zo,c - C VTh = 2v+(t,D) + D VTh = u(t - ) - Zo vL(t) + C z v+(t,D) 0.5 t 0 0 z D c vL(t), τ = ZoC sec t =D/c v-(t,D) vL = v- + v+ at the load ⇒ v-(t,D) = vL(t,D) – v+(t,D) v(t,z) 0.5 z z i(z,t) = Yo [v + (t - ) - v - (t + )] c c 0 t = 0+, short-circuit response t → ∞, open-circuit response 1/2Zo D z i(t,z) 0 D z L12-4 DIODE-TERMINATED TEM LINE Example -- Logic Circuit: Zo + i - ideal diode 0 0.5 1 1 vs(t) 0.5 τ v(z,t) vTh(t) 3 v+(t,D) 2 0 D/c sec vL(t) 4 Zo,c Vs(t) D Zo D + v Th = Vs (t - ) c - physical diode v Let vs(t) = 1-volt ramped step v(t) + vL(t) 0.5v + - - 0 v+(t – z/c) + vL(t) 0.5 V + - 6 v(z,t) 0.5 t z τ 0.25 5 v-(t,z) D z vL(t) = v+(t,D) + v-(t,D) L12-5 INITIAL CONDITIONS Example – charged TEM line: t = 0 Charged to V, t<0 + Zo,c Γ = +1 - v(z,t) = v+(z – ct) + v-(z + ct) 1 i(z,t) = [v+(z – ct) - v-(z + ct)] Zo z D Initial voltage and currents: 1 v+(z,t) = [v(z,t) + Zo i(z,t)] 2 v-(z,t) = 1 [v(z,t) - Zo i(z,t)] 2 v(z, t<0) ⇒ V vi(t < 0) = 0 v+ Γ= +1 at ends 0 D z Subsequent voltages and currents: v(z, 0 < t < D/c) V v+ Γ = -1 vv- Γ = +1 z 0 v+ D V Γ = -1 0 v(z, D/c < t < 2D/c) vv+ Γ = +1 z D v- Lossless system, rattles forever L12-6 INITIAL CONDITIONS Arbitrary initial conditions: v,i v,i v- v(t=0) i(t=0) 0 D v+ z 0 v+ z v- D Arbitrary circuits: Put switches anywhere + Zo,c z D L12-7 LIGHTNING STRIKE EXAMPLE Lightning strikes the midpoint What happens? + - Zo,c z D Figure by MIT OpenCourseWare. L12-8 LIGHTNING STRIKE EXAMPLE Revenge? + - Zo,c z D Figure by MIT OpenCourseWare. L12-9 LIGHTNING STRIKE EXAMPLE One possibility: Temporary short through ionized channel + - Zo,c D z v(z,to) Γ = -1 v+ 0 v- v+ v+ z v- v2cto L12-10 LOSSY TRANSMISSION LINES Equivalent Circuit: i(z) RΔz LΔz v(t,z) CΔz RΔz LΔz GΔz CΔz GΔz L [Hy m-1], C [F m-1], R[Ω m-1], G[S m-1] Δz Equations for Δz → 0 : dV(z) = −(R + jωL) I (z) dz d I (z) = −(G + jωC)V(z) dz V(z) = V+e-jk’z – k”z I(z) = Yo V+e-jk’z – k”z d2 V(z) dz 2 = (R + jωL)(G + jωC)V(z) ⇒ V(z) = V e− jkz + V e+ jkz + − k = −(R + jωL)(G + jωC) = k '− jk " decay for forward wave: Yo = (G + jωC) /(R + jωL) Propagation e-jkz : decay rate (e-k”z) and phase velocity (vp) = f(ω) (Exception: “distortionless line” for which R/L = G/C) L12-11 MIT OpenCourseWare http://ocw.mit.edu 6.013 Electromagnetics and Applications Spring 2009 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.