PHGN200: All Sections Recitation 1 January 23, 2007 y R q ` θ x ` −q Figure 1: For the above electric dipole, p = 2`q. 1. Dipole in a 2-D world because the 3-D world is too damn hard! (a) Find the electric field anywhere in the xy-plane (see Fig. 1). Ans: i h xı̂ı̂ı̂+(y+`)̂̂ xı̂ı̂ı̂+(y−`)̂̂ q ~ − 2 E = 4πo 2 2 3/2 2 3/2 [x +(y−`) ] [x +(y+`) ] (b) Evaluate the electric field found in part (a) on a circle with radius R (see Fig. 1). Ans: h i R cos θı̂ı̂ı̂+(R sin θ−`)̂̂ R cos θı̂ı̂ı̂+(R sin θ+`)̂̂ q ~ E = 4πo − 2 2 2 3/2 2 3/2 [R −2`R sin θ+` ] [R +2`R sin θ+` ] (c) Find an approximate expression for the x-component of the electric field on the circle if `/R 1 (see Fig. 1). Hint: Expand the denominator in Taylor series, (1 + )n = 1 + n + · · · , if || < 1. You can drop any terms containing square or higher powers 2 of R` because if R` is small, then R` is super-small. Ans: Ex = 4π3po R3 sin(θ) cos(θ), where p = 2`q (d) Find the total charge enclosed by the circle. Find the unit-normal to the circle. Ans: qenclosed = 0, n̂ = cos θı̂ı̂ + sin θ̂̂ PHGN200: All Sections Recitation 1 January 23, 2007 2. Hard integrals made easy! (a) Set-up an integral expression for the electric field at a field point, (xo , 0), due to a ring of charge with linear charge density λ = λo sin θ, where λo is a positive constant (see Fig. 2). y R θ (xo, 0) x Figure 2: The circle has a linear charge density given by λ = λo sin θ, where λo is a positive constant constant. Ans: hR R 2π 2π λ(xo −R cos θ) R ~ ı̂ E = 4πo 0 dθ − 3/2 0 (R2 +x2o −2xo R cos θ) where λ = λo sin θ λR sin θ 3/2 dθ (R2 +x2o −2xo R cos θ) i ̂ (b) Using only a symmetry argument, find the direction of the electric field. Ans: in the negative y direction. 3. Given a curve y = f (x) where x1 ≤ x ≤ x2 in the xy−plane, find the electric field at some field point, (a, b). Assume that the curve has a linear charge density given by λ = g(x). Ans: q q R x2 R x2 λ(a−x) λ(b−f (x)) 2 1 1 ~ = E 1 + [f 0 (x)] dx ı̂ı̂+ 4πo x1 1 + [f 0 (x)]2 dx ̂ 2 2 3/2 4πo x1 (a−x)2 +(b−f (x))2 3/2 [ ] [(a−x) +(b−f (x)) ] Page 2