an100922w: HW 6
NAME:
DATE:
YrV
PERIOD:
800
7m
oo 600
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8{t 300
ut
200
100
0
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51015
1) A student whose normal weight is 500 newtons stands on a scale in an elevator and records the scale
reading as a function of time. The data arc shown in the graph above. At time t : 0, the elevator is at
displacement x: 0 with velocity v: 0. Assume that the positive directions for displacement, velocity, and
acceleration are upward.
a. On the diagram below, draw and label all of the forces on the student att:8 seconds.
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I
b.
Calculate the acceleration a of the elevator for each 5-second interval.
i. Indicate your results by completing the following table.
Time Interval (s) 0-5
5-10
10-15
t5-20
o
a (mjs2)
ii. Plot the acceleration
(\a
as a
IL
0
-+
function of time on the following graph.
J
E
€o
cl
iD
$
<-5
,20
I
Time (s)
c.
Determine the velocity v of the elevator at the end of each 5-second interval.
i. Indicate your results by completing the following table.
Time
(s)
0-5
10- 15
?t)
0
v (ml s)
r5-20
{)
ii. Plot the velocity as a function of time on the following graph.
ll,q
6
|"^ Tirp (s)
)'l
t)
6
t)
Deterrnine the displacement x of the elevator above the starting point at the end of each 5-second
interval.
i. Indicate your results by completing the following table.
Time (s)
0-5
s-10
l0-1 5
15-20
x(m)
b
ii. Plot the displacement
ell
J.00
as a function of time on the following graph.
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2- The vertical p*ieitisn of an elevator as a firnf,tinn nf tirne is shcurn a.bove.
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