Lecture 12 Crystal Vibrations From aclassical standpoint: The vibrationalmodes of the atoms are considered sound waves From a modern standpoint: The vibrational modes of the atoms are considered phonons The speed with which a longitudinal wave propagationthrough a medium of elastic material(for example solid) of density π given by: π£0 =ππ = ( Βπ ½ ) π …… 1 Where Βπ is adiabatic elastic bulk modulus, or stiffness coefficient. 4-1Vibrations of crystals with monatomic basis Consider a one-dimensional (linear) lattice with a period (π) and with identical atoms of mass m, vibrating around each lattice point(see Fig.26).Each atom is indexed by an integer (π), and its displacement from its equilibrium position is denoted (π’). The atoms are taken to oscillate in the same direction as the lattice. We want to find the angular frequency(w) of an elastic wave in terms of wavevector (k). In this one-dimension case we will take into account only the interaction between nearest neighbors. The force acted on the nth atom: πΉ n=π[π’n+1+π’n-1-2π’n] In a homogeneous solid the transmission of a plane wave in the x-direction can be represented by the displacement equation: π’=π΄exp[i(ππ₯ − π€π‘)],andπ’n=π΄exp[i(πππ-π€π‘)] where π₯ = ππ π2π’π ππ‘ 2 =-π€2 π΄ exp[i(πππ-π€π‘)] , π’n=-π€2π’π ∴ Fn=-mπ€2π’π -mπ€2π’π = C [π’n+1+ π’n-1-2π’n] π π’π+1 π π’π π€2= [2- - π’π−1 π’π ] π π π π π€2= [2-π πππ - π −πππ ]= 2 [1- πππ ππ] or π ππ π 2 = 4 sin2 ( ) π ππ π π πΎ=±π( )½ πππ ( π )=±πm πππ ( ππ ) where π ……………. 2 wm =±2( )½ π This relation is called the phonon dispersion relationbetween w and k for allowed longitudinal wave in a linear monatomic chain, and is plotted in Fig. 27. Note: the plus and minus signs in Eq. 2 denote waves traveling either to the right or to the left. The motion in any point is periodic in time. k Fig. 27 2ndBrillouin zone2nd Brillouin zone k in the case of propertiesππ βͺ 1(i.e. in the long wavelength limit ), π ππ ( ππ 2 )becomes ( ππ 2 ) and Eq. ( 2 ) becomes: π€ β π£0 π π π£0 = π( )½ …. 3 for ππ βͺ 1(non-dispetion) π π£0 :is the rapid spread of acoustic wave in a medium of elastic material, and It is approximately fixed amount π In the case of propertiesπ = ± (i.e. in the short π wavelength limit, asπ increases, the slope of π€ decreases and becomes flat at the zone boundaries π π=± ). π We have π = 2π π ,thenπ = 2π , andwm =2 π£0 π phase and group velocities are in general given by: π€ ππβ = ππ€ ππ = ππ π = 2 π ( π ½ ) π = π£0 πππ ( ππ 2 π ππ ( ππ 2 ) = π£0 [ ππ ) 2 ππ 2 sin β‘ ( ] ) Note:in the case of ππ βͺ 1 (or π β« π) the atoms moving in one direction and the same phase and this explains the fact thatπ€ = 0 when π = π. Problems π 1- Use Eq.π£0 = π( )½ to find the relation π between π and young model’s Y.? The answer (π = ππ). 2- in the case of properties ππ βͺ 1, show that ππ =π£0 , ππβ =π£0 and ππ =ππβ π 3- In the case of properties π = ± , show that π ππ =0 and 2π£0 ππβ = π