w w ap eP m e tr .X w om .c s er Cambridge International Examinations Cambridge International General Certificate of Secondary Education MATHEMATICS 0580/02 For Examination from 2015 Paper 2 (Extended) SPECIMEN MARK SCHEME 1 hour 30 minutes MAXIMUM MARK: 70 The syllabus is approved for use in England, Wales and Northern Ireland as a Cambridge International Level 1/Level 2 Certificate. This document consists of 4 printed pages. © UCLES 2012 [Turn over 2 Types of mark M marks are given for a correct method. A marks are given for an accurate answer following a correct method. B marks are given for a correct statement or step. D marks are given for a clear and appropriately accurate drawing. P marks are given for accurate plotting of points. E marks are given for correctly explaining or establishing a given result. SC marks are given for special cases that are worthy of some credit. Abbreviations cao correct answer only cso correct solution only dep dependent ft follow through after error isw ignore subsequent working oe or equivalent SC Special Case www without wrong working art anything rounding to soi seen or implied Qu. Answers 1 7.5(0) cao 2 Mark Part Marks 258.75 4.6 2 M1 for 3 × 1027 2 M1 for 6 ÷ (2 × 10–27) 3 cos38 sin38 sin158 cos158 2 M1 correct decimals seen 0.7(88..) 0.6(15..) 0.3(74..) –0.9(271..) 4 41 333 5 (a) 7853 to 7855 or 7850 or 7860 www (b) 0.7853 to 0.7855 or 0.785 or 0.786 3 2 1ft 6 135 cao 3 7 (a) (y =) 80 1 (b) (z =) 40 1 (c) (t =) 10 1ft © UCLES 2012 0580/02/SM/15 123 oe fraction 999 or M1 for 1000[x] = 123.123… oe B2 for M1 for π × 502 Their (a) ÷ 10 000 evaluated M1 for 720 or (6 – 2) × 180 oe seen in working and M1 for equation 180 + 4x = their 720 or M1 for (360 − 180) ÷ 4 (= 45) oe seen in working and M1 dep for 180 − their 45 Follow through 90 − their y or 50 − their z 3 8 y= − 1 x +10 oe 2 3 M2 for − 1 x + 10 2 or M1 for gradient identified as − 1 2 or intercept as 10 (not on diagram) e.g. y = mx + 10 or 1 y= − x+c 2 9 10 11 12 (a) Correct perpendicular bisector with arcs 2 (b) 60° 1 4 B1 0.8, 0.6 or 0.55 then M1 0.45 × their 0.6 M1 0.2 × their 0.55 or M2 1 – (0.45 × 0.4 + 0.55 × their 0.8) 8 5 (a) 20 13 2 B1 two or three entries correct 1 1 − 12 oe (b) 2 − 2 1 2 3 − 1 1 a c B1 (k ) B1 2 b d − 4 2 (a) Negative 1 Ignore embellishments (b) Correct point 1 (c) (i) 1 0.38 or 19 50 Accurate ruled line (ii) English mark 13 B1 correct line B1 correct construction arcs (a) 1 1 a + b oe 2 2 1ft 2 Follow through their (c)(i) M1 unsimplified or any correct route e.g a + 1 1 (b) –1 a + 1 b oe 2 2 2 1 (b – a) or OA + AC 2 M1 unsimplified or any correct route e.g. CD = 1 14 (a) 2.84 2 M1 correct substitution of g and ℓ seen 3 M1 each correct move but third move marked on answer line (a) 156 4 M1 intention to find area under graph B2 completely correct area statement or B1 two areas found correctly (or one trapezium area) (b) 12 1ft (b) 15 1 1 AB or b – a + (b – a) 2 2 © UCLES 2012 4π 2 l oe T2 0580/02/SM/15 Their (a)/13 [Turn over 4 16 (a) 500, 405, 364–365, 295 (…) 2 B2 (b) 5 points plotted within correct square 1 P1 ft from table 1 C1 1 B1 ft from their curve or line reading at 350 g correct curve drawn within 1 mm of points plotted (c) (i) 3.3–3.4 17 (ii) Never oe 1 1 2 2 B1 f(–2) seen 2 M1 x –1 = y3 or 3√(y – 1) (c) 1 2 3 M2 (x – 1)(x – 2) = 0 or M1 (x + a)(x + b) = 0 where ab = 2 or a + b = –3 If 0 scored give M1 for x2 – 3x + 2 = 0 (a) 4324 cao 2 M1 (b) (i) 2 B1 either correct (a) (b) 3√(x – 1) or 18 (c) © UCLES 2012 3 x −1 4, 9 (ii) (n + 1)2 or n2 + 2n + 1 1 2 n(n+ 1)(2n + 1) oe 3 2 0580/02/SM/15 1 × 23 × 24 × 47 or better 6 M1 recognising Vn = 4Tn