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CAMBRIDGE INTERNATIONAL MATHEMATICS
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UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
0607/05
For Examination from 2010
Paper 5 (Core)
SPECIMEN MARK SCHEME
1 hour
MAXIMUM MARK: 24
This document consists of 4 printed pages.
© UCLES 2007
[Turn over
2
TYPES OF MARK
•
•
•
•
•
•
•
•
M marks are given for a correct method.
A marks are given for an accurate answer following a correct method.
B marks are given for a correct statement or step.
D marks are given for clear and appropriately accurate drawing.
P marks are given for accurate plotting of points.
E marks are given for correctly explaining or establishing a given result.
C marks are given for clear communication (Papers 5 and 6 only).
R marks are given for appropriate reasoning (Papers 5 and 6 only).
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ft
oe
soi
www
ABBREVIATIONS
© UCLES 2007
Follow through
Or equivalent
Seen or implied
Without wrong working
0607/05/SM/10
3
1
2
(a)
3
4
7
+
=
24 24 24
AR1
(b)
2
3
5
+
=
12 12 12
AR1
(a)
(i)
1 1 2 1 3 1
+ = + = =
3 6 6 6 6 2
(ii)
1 1
3
1
4 1
+
=
+
=
=
4 12 12 12 12 3
(iii)
1 1
4
1
5
1
+
=
+
=
=
5 20 20 20 20 4
(b)
(c)
3
(b)
© UCLES 2007
reasons
are
1 1 1
= +
5 6 30
1 1 1
= +
6 7 42
1 1 1
= +
7 8 56
B2
1
1
1
=
+
99 100 9900
B1
(B1 or two correct)
2×
(i)
(ii)
(c)
&
R2
1
1 1 
=2  + 
3
 4 12 
2 2 2 1 1
= +
So = +
3 4 12 2 6
(a)
(both accuracy
required)
2
=2
5
R2
1
1 1  1
+
 +  =
 6 30  3 15
M1A1
2
1
1
1 1 
=2  +  =
+
7
4
28
 8 56 
M1A1
25
25
1  25
 1
= 25 
+
+
=
99
9900
 100 9900  100
1
1
+
=
4
396
0607/05/SM/10
M1
A1
[Turn over
4
4
1
1
5
3
8
4
+
=
+
=
=
6 10
30
30
30 15
(a)
(b)
(i)
(ii)
(c)
(d)
(e)
(f)
C2
x = 3 and y = 9 (or vice versa) in which
9+3
= 3 giving
case k =
4
4
1
1
=
+
OR
27
9
27
x = 1 and y = 27 (or vice versa) in
1 + 27
which case k =
= 7 giving
4
4
1
1
=
+
27
7 189
B2
x = 3 and y = 11 (or vice versa) in
11 + 3
which case k =
= 2 giving
7
7
1
1
=
+
33
6
22
B2
Take x = 1 and y = 15 (or vice versa) in
1 + 15
which case k =
= 4 giving
4
4
1
1
=
+
15
4
60
B2
Taking x = 1 and y = 20 gives k = 7
3
1
1
and
=
+
20
7 140
Taking x = 2 and y = 10 gives k = 4
3
1
1
and
=
+
20
8
40
Taking x = 4 and y = 5 gives k = 3 and
3
1
1
=
+
20 12
15
1
1
1
1
1
+
=
+
+
using the
2
2
2
3
6
pattern in part 2.
1=
1
as in question 2 (b)
6
1
1
1
1
+
+
+
gives 1 =
2
3
7
42
Breaking down
B1
B1
B1
B1
B1
1
1
1
1
+
+
+
2
4
6 12
1
1
1
1
+
+
+
1=
2
3 10
15
1
1
1
1
+
+
+
1=
2
4
5
20
Accept also 1 =
For clear communication and reasoning throughout the paper award C2
Total: 30 marks scaled down to 24.
© UCLES 2007
0607/05/SM/10