University of Babylon College of Engineering Department of Civil Engineering Lectures of Highway Engineering Forth Stage 01- Cross-Section Elements 02- Earthworks & Mass-Haul Diagram 03- Asphaltic Materials 04- Aggregate 05- Asphalt Paving Mixture 06- Drainage 07- Evaluation of Strength for Subgrade 08- Thickness Design of Flexible Pavement 09- Rigid Pavement 10- The Effect of type and amount of Filler on Asphalt Paving Mix Prof. Ali Alwash Asst. Lect. Harith Ajam Oct-2010 Oct-2010 Lectures of Highway Engineering – Forth Stage References: 1. Yoder; E. J. and M. W. Witczak, “Principles of Pavement Design”, A Wiley- Interscience Publication, John Wiley & Sons Inc., U.S.A., 1975. 2. Yaug H. Huang, “Pavement Analysis and Design”, Prentic Hall Inc., U.S.A., 1993. 3. Paul Croney and David Croney, “The Design and Performance of Road Pavements”, McGraw Hill, U.S.A., 1998. 4. “AASHTO Guide for Design of Pavement Structures 1993”, AASHTO, American Association of State Highway and Transportation Officials, U.S.A., 1993. 5. “A Policy on Geometric Design of Highways and Streets 2001”, AASHTO, American Association of State Highway and Transportation Officials, U.S.A., 2001. 6. Oglesby Clarkson H., “Highway Engineering”, John Wiley & Sons Inc., U.S.A., 1975. 00-2 References Nov-2009 Lectures of Highway Engineering – Forth Stage 01- Cross-Section Elements 1. Surface Type: - Asphalt concrete (flexible pavement). - Plan, simply reinforced & continuously reinforced concrete (rigid pavement). - Surface treatment Æ for shoulders. Choice depending on ()اﺧﺘﻴﺎر ﻧﻮع اﻟﺴﻄﺢ ﻳﻌﺘﻤﺪ ﻋﻠﻲ: a. Applied stresses ()اﻻﺟﻬﺎدات اﻟﻤﺴﻠﻄﺔ. b. Environmental conditions ()اﻟﻈﺮوف اﻟﻤﻨﺎﺧﻴﺔ اﻟﻤﺤﻴﻄﺔ. c. Available materials ()اﻟﻤﻮاد اﻟﻤﺘﻮﻓﺮة. d. Common practice ()اﻟﺨﺒﺮة اﻟﺸﺎﺋﻌﺔ. e. Cost ()اﻟﻜﻠﻔﺔ. 2. Cross Slop: 0.01 – 0.03 "high type surface" 0.08 "low type surface" Æ shoulders 3. Lane Width: - Standard = 3.65m - In practice = 3.75 m - +0.25m (at shoulders) & +0.5m (at median if barrier curb is found). Where +0.25m & 0.50m marginal strips. 4. Shoulder: - Surface treatment Width = 2.5 - 3.0m Cross-slop = 5 - 8% = 0.05 - 0.08 01-1 Cross-Section Elements Nov-2009 Lectures of Highway Engineering – Forth Stage 5. Curbs: - Barrier (for pedestrian) ()ﻻ ﻳﻤﻜﻦ اﺟﺘﻴﺎزﻩ ﺑﺎﻟﻤﺮآﺒﺎت - Mountable ()ﻳﻤﻜﻦ اﺟﺘﻴﺎزﻩ ﺑﺎﻟﻤﺮآﺒﺎت - Curb & Gutter ()أﻧﻮاع ﻣﻦ اﻷرﺻﻔﺔ ﺗﺤﻮي ﻧﻈﺎم ﺗﺼﺮﻳﻒ 6. Guard rail (by sheet and column): Used at hazardous points: - at high fill > 3.0m - steep grades ()اﻧﺤﺪار ﺷﺪﻳﺪ - sharp curvature ()اﻧﺤﻨﺎء ﺷﺪﻳﺪ - sudden change in alignment - restricted sight (foggy )ﻣﻨﺎﻃﻖ اﻟﺮؤﻳﺔ اﻟﻤﻘﻴﺪة( )ﺿﺒﺎﺑﻲ - near rivers and lakes < 10 - 15m 7. Median: For: - Separating opposite flow - Future expansion W (m) 1.2 12 O (m) 30 9 01-2 Cross-Section Elements Nov-2009 Lectures of Highway Engineering – Forth Stage 8. Side walk ()ﻃﺮﻳﻖ اﻟﻤﺸﺎة: 9. Side slop: a. Cut slop: - For normal soil (clay, silt, sand), & h ≤ 6.0m: H:V = 2:1, … ..., 4:1 (favorable 4:1 )اﻟﻤﻔﻀﻠﺔ - For normal soil, & h > 6.0m: (has to be design according to slop stability theory) - For rocky soil: Hard (H:V) = 1:10 … 1:5 Medium (H:V) = 1:4 … 1:3 Sift (H:V) = 1:2 with steps b. Fill slop: ،أول ﺳ ﺘﺔ أﻣﺘ ﺎر ﺑﺎﻟﻤﻴ ﻞ اﻟﻤﺒ ﻴﻦ ﺑﺎﻟﺸ ﻜﻞ (1:1) ( ﺑﺎﻟﻤﻴﻞh) واﻟﻤﺘﺒﻘﻲ 01-3 Cross-Section Elements Nov-2009 Lectures of Highway Engineering – Forth Stage ﻓ ﻲ ﺣﺎﻟ ﺔ وﺟ ﻮد ﻣﺴ ﻄﺢ ﻣ ﺎﺋﻲ ﺑﺠﺎﻧ ﺐ اﻟﻄﺮﻳ ﻖ ﺗﻜ ﻮن اﻟﺘﻔﺎﺻﻴﻞ آﻤﺎ ﻓﻲ اﻟﺸﻜﻞ 10. Vertical clearance: For roads = min. 5.20m For railway = min. 6.50m For walkway = min. 2.50m For main rivers = min. 6.50m For other rivers = min. 3.50m For high tension lines = min. 8.8 -10m 11. Right of way ( ≥ )ﻣﺤﺮﻣﺎت اﻟﻄﺮﻳﻖ80m Freeway ≈ 200m Highway ≈ 100m Used for: future expansion ()اﻟﺘﻮﺳﻊ, safety ()اﻷﻣﺎن, maintenance ()اﻟﺼﻴﺎﻧﺔ. 01-4 Cross-Section Elements Nov-2009 Lectures of Highway Engineering – Forth Stage 02-Earthworks & Mass-Haul Diagram Mass-haul diagram: Continuous curve showing the relationship between the accumulated algebraic sums of corrected earthwork volume and distance for the purpose of minimizing the cost of excavating hauling & damping the materials (Soil). - Rising Æ Cut - Falling Æ Fill - Steep slop Æ High cut or fill - Zero slop Æ Change from cut to fill or vice versa. - Zero value Æ Balance between cut and fill Haul ( = )اﻟﻨﻘﻞVolume (m3) * Distance (sta.) Haul distance: The distance of moving the masses of soil from one place to another, in the process of earthwork. 02-1 Earthworks & Mass-Haul Diagram Nov-2009 Lectures of Highway Engineering – Forth Stage Free haul distance (F. H. D.): The distance within which there is a fixed price for excavating, hauling, and damping the materials regardless of the distance moved. Free haul ch arg e = I.D m3 Over haul distance (O. H. D.): The distance beyond (F. H. D.) for which there is an additional price for each (m3.sta.) Over haul ch arg e = max . O. H. D. = I.D m3.sta. Borrow ch arg e O. H. ch arg e Limit of economical haul distance (L. E. H. D.): The distance beyond which it is more economical to waste and borrow rather than to pay for the cost of over hauling. L. E. H. D. = F. H. D. + max. O. H. D. A-B = F. H. D. C-D = F. H. V. E-F = L. E. H. D. G-H = O. H. V. E-K = West (W) F-P = Borrow (B) وآﻤﺜﺎل ﺗﺮﺳﻢ اﻟﻌﻼﻗﺔ ﺑﻴﻦ اﻟﻤﺴﺎﻓﺔ )ﺑﺎﻟﻤﺤﻄﺎت( ﻣ ﻊ اﻟﺤﺠ ﻮم اﻟﻤﺼ ﺤﺤﺔ اﻟﻤﺠﻤﻌ ﺔ ﻟﻘ ﻴﻢ ﻣﻌﻴﻨ ﺔ ﺑﻤﻘﻴ ﺎس رﺳ ﻢ ﻣﻌ ﻴﻦ ﻟﻠﺤﺼ ﻮل ( وﺣﺴ ﺐ ﻣﻘﻴ ﺎس اﻟﺮﺳ ﻢ ﺗﺮﺳ ﻢ وﺗﻘ ﺎس3Sta.) ( هﻲ ﻣﺴﺎﻓﺔ اﻟﻨﻘﻞ اﻟﺤﺮ وﻣﻘﺪارهﺎ ﻟﻠﻤﺜﺎل ﺣ ﻮاﻟﻲA-B) ،ﻋﻠﻰ ﻣﺨﻄﻂ ﻧﻘﻞ اﻟﻜﺘﻞ وﻣﻨﻬﺎ ﺛ ﻢ ﻧﺮﺳ ﻢ اﻟﺤ ﺪ اﻻﻗﺘﺼ ﺎدي ﻟﻤﺴ ﺎﻓﺔ.(F. H. V.) ( وه ﻲ ﺣﺠ ﻢ اﻷﺗﺮﺑ ﺔ اﻟﻤﻨﻘﻮﻟ ﺔ ﺑﺼ ﻮرة ﺣ ﺮةA-B) اﻟﻤﺴﺎﻓﺔ ﻣﻦ ﻗﻤﺔ اﻟﻤﻨﺤﻨﻲ ﻟﻠﺨ ﻂ أﻣ ﺎ،( هﻲ ﺣﺠﻢ اﻟﺘﺮﺑﺔ اﻟﻤﻨﻘﻮﻟ ﺔ ﺑﺼ ﻮرة ﻣﻀ ﺎﻓﺔ ﺑﺼ ﻮرة ﻣﻨﺎﺳ ﺒﺔG-H) ( وﺣﺴﺐ ﻣﻘﻴﺎس اﻟﺮﺳﻢ ﻓﺘﻜﻮن اﻟﻤﺴﺎﻓﺔL. F. H. D.) اﻟﻨﻘﻞ .( اﻟﻔﺎﺋﺾ واﻟﻤﺴﺘﻌﺎرW, B) ( ﻓﻬﻲE-F) اﻟﺒﺎﻗﻲ ﺗﺤﺖ 02-2 Earthworks & Mass-Haul Diagram Nov-2009 Lectures of Highway Engineering – Forth Stage Correction: M M * Sandy, Silty clay ﺗﺤﻤﻴﻞ Shrinkage: 5 – 15 % ≈ 10% Loose V0 M ﺣﺪل V1 V2 V0 < V2 < V1 M M * Lime stone, Sand stone ﺗﺤﻤﻴﻞ Bulking: 25 – 35 % ≈ 30% V0 Loose M ﺣﺪل V1 V2 V2 < V1 V2 > V0 Ex.: Sta. End Area (m2) Cut Fill 4.0 2.6 0+00 2+00 2 4+00 1.0 6+00 7 9+00 0 Cut + (m3) (-) Shrinkage 10% (m3) Corrected Cut + (m3) Fill – (m3) Balance Vol. (m3) (Cut-Fill) 0.5*(4+2)*200 =600 600*0.1 =60 600-60 =540 0.5*(2.6+0)*200 =260 +280 0.5*(2+1)*200 =300 300*0.1 =30 300-30 =270 0.5*(0+3)*200 =300 -30 0.5*(1+7)*200 =800 800*0.1 =80 800-80 =720 0.5*(3+2)*200 =500 +220 0.5*(7+0)*300 =1050 1050*0.1 =105 1050-105 =945 0.5*(2+8)*300 =1500 -555 0 Accu. Vol. (m3) 0 +280 3 +250 2 +470 8 -85 M-H. Diagram Corrected accumulated volume (m3) 500 400 300 200 100 0 0 100 200 300 400 500 600 700 800 900 1000 -100 Distance (Sta.) 02-3 Earthworks & Mass-Haul Diagram Nov-2009 Lectures of Highway Engineering – Forth Stage 03-Asphaltic Materials Axel Load M. S. = (Marshall Stability) C.B.R. = (California bearing reaction) Flexible Pavement Layers: M. S. ≥ 8 kN ≈ 10 kN M. S. ≥ 7 kN Wearing (Surface) course Level (Binder) course (Asphaltic concrete) (Asphaltic concrete) M. S. ≥ 5 kN C. B. R. ≥ 80% C. B. R. ≥ 35% C. B. R. ≥ 5% ≈ 10% Base course - Asphaltic concrete - Crushed stone - Subbase course Compacted subgrade (Concrete) (Stabilized mater) (asphalt, concrete, lime) (Sand-gravel) C. B. R. < 5% ≈ 4% Natural subgrade Asphaltic Concrete: - Asphalt cement - Coarse aggregate (crushed gravel) [1" – No.4 (No.10)] - Fine aggregate (sand) [No.4 (No.10) – No.200] - Mineral filler (cement or lime) [≤ No.200] - Additives Bituminous materials: Mixture of hydrocarbons (C, H), liquid or semisolid in consistency, soluble in CS2 & CCl4 - Tar: produced by destructive distillation of coal (chemical change), cannot found in nature, more susceptible to temp. & more toxis. - Asphalt: produced by fractional distillation of petroleum (physical change), natural (lakes, rocks) or manufactured, less susceptible to temp. & less toxic. Dura refinery: Atmosphere Tower Vacuum Tower Medium distillation Steam Deasphaltive unit Steam (deasphaltive oil) Propane C3H8 o 370 C Red need oil ≈ 40% Blending (a) and (b) ()ﺑﻌﺾ ﺣﺎﻻت اﻟﻤﺰج to produce asphalt cement: Vacuum (a) residue ≈ 18% Heavy distillation Base (b) Asphalt ≈ 13% Blend 1 (a) + 1 (b) Æ AC (40-50) 1.8 (a) + 1 (b) Æ AC (60-70) 03-1 اﻟﻨﻔﻂ اﻟﺨﺎم ﺑﻌﺪ اﻟﺘﻘﻄﻴﺮ Crude oil 100% [315oC] Light distillation Asphaltic Materials Gasoline Kerosene Diesel Oil Lube Oil Asphalt + Paraffin Nov-2009 Lectures of Highway Engineering – Forth Stage Manufactured Asphalt Asphalt Cement Liquid (Cut-back) Asphalt Emulsified Asphalt A) Asphalt Cement: a. Penetration grade: 40-50 اﻧﺘﺎج ﻗﻠﻴﻞ50-60 60-70 85-100 120-150 200-300 Less durable ()ﻗﻠﻴﻞ اﻟﺪﻳﻤﻮﻣﺔ Less flexible ()ﻟﺪوﻧﺔ ﻗﻠﻴﻠﺔ (Thermal Cracking) More temperature susceptible (permanent deformation) (Rutting) b. Viscosity grade: Absolute viscosity (Dynamic): By Poise ( dyne * sec . ) cm 2 ⎡ dγ (shear strain ) ⎤ rate of shear strain ⎜⎝ sec . ⎟⎠ ⎛ dyne ⎞ τ(shear stress ) ⎜ = η(Abs.Vis. (Poise) ).⎢ ⎥ ←⎯ ⎯ ⎯ ⎯ ⎯⎯⎯ 2 ⎟ ⎝ cm ⎠ ⎣ dt ( time (sec .)) ⎦ ⎛ 1 ⎞ ﻗﻠﻴﻞ اﻻﻧﺘﺎج ﻣﻬﻢ Viscosity grade AC-40 AC-20 AC-10 AC-5 AC-2.5 o Abs. Vis. @60 C = 40*100=4000 poise 2000 poise 1000 poise 500 poise 250 poise Penetration grade > 20 > 40 > 70 > 120 > 200 Asphalt cement requirements (AC-20 [40-70]): 1. Basis of grading (Consistency) ()اﻟﻘﻮام - Abs. Viscosity @60oC = (1600 – 2400) poise (Gs = 1.01 – 1.05) 2. Temperature susceptibility ()ﺣﺴﺎﺳﻴﺘﻬﺎ ﻟﻠﺤﺮارة: - Penetration ()ﻓﺤﺺ اﻟﻐﺮز: (ST. condition – min. 40 (40-70) 1/10mm Penetration after thin film oven test, retained pen. > 55% & (mass loss < 0.75%) - Kinematics viscosity @135oC Æ Min. (210) Centistokes (Stokes = 100 Centistokes) (Stoke = Poise/Density) 03-2 Asphaltic Materials Nov-2009 Lectures of Highway Engineering – Forth Stage 3. Oxidative hardening ()اﻟﺘﺼﻠﺐ ﺑﺴﺒﺐ اﻻآﺴﺪة: - Abs. viscosity @60oC after thin film oven test Æ Min. (10000) Poise 4. Homogeneity ()اﻟﺘﺠﺎﻧﺲ: - Ductility after thin film oven test Æ Min. (20cm) Ductility before thin film oven test Æ (≥ 100cm) @25oC (5cm/min.) - Solubility in Trichloro-Ethelin Æ Min. (99%) 5. Safety: - Flash point Æ Min. (232oC) - Softening point Æ (52 – 60oC) Chemical components (AC): - Aliphatic hydro carbons (Chain) H H H H | | | | H − C − C − C − C − H | | | | Light molecular weight H H H H H | - Aromatic hydro carbons (Rings) C Heavy molecular weight H − / C \\ C − H || | H − C C \\ / − H C | H Chemical Components: :وﺟﺪ أن ﺗﺮآﻴﺐ ﻋﻴﻨﺔ ﻣﻦ اﻻﺳﻔﻠﺖ هﻮ [C89 H104 S3 N2 O2] :وﺗﺨﺘﻠﻒ أﻧﻮاع اﻻﺳﻔﻠﺖ ﻓﻲ ﻧﺴﺐ هﺬﻩ اﻟﻌﻨﺎﺻﺮ وﺗﺘﺮاوح ﺿﻤﻦ اﻟﺤﺪود اﻵﺗﻴﺔ C = 70 – 85 %, H = 7 – 12 %, O = 0 – 5 %, N=0–1% S=1–7% 03-3 Asphaltic Materials Nov-2009 Lectures of Highway Engineering – Forth Stage Fractional Components of AC Asphaltene 1 Asphaltene 2 Nitrogen bases Maltenes Role Bonding agent ()اﻟﻘﻮام Peptizing agent ( ﻳﺴﺎﻋﺪ ﻋﻠﻰ اﻧ ﺪﻣﺎج اﻻﺳ ﻔﻠﺘﻴﻦ ﺑ ﺎﻻﺟﺰاء )اﻻﺧﺮى 3 First acidaffines Solvent ()ﻣﻮاد ﻣﺬﻳﺒﺔ ﺗﺴﺎﻋﺪ ﻋﻠﻰ اﺣﺘﻮاء اﻟﻤﻮاد اﻻﺧﺮى 4 Second acidaffines Solvent ()ﻣﻮاد ﻣﺬﻳﺒﺔ ﺗﺴﺎﻋﺪ ﻋﻠﻰ اﺣﺘﻮاء اﻟﻤﻮاد اﻻﺧﺮى 5 Paraffin Gelling agent ()ﻋﺎﻣﻞ ﻣﺨﺜﺮ (Durability) Reactivity to O2 Low High High Low Very low B) Liquid (cut-back) Asphalt: Asphalt cement + solvent (for temporary liquefaction) a. Rapid Curing (R.C): AC (85-100) + Gasoline RC-70 (ً)اﻻآﺜﺮ ﺷﻴﻮﻋﺎ RC-250 RC-800 RC-3000 ﻟﻠﻤﻨﺎﻃﻖ اﻟﺤﺎرةKinamatic Vis. @60oC = 70-2*70 centestok ﻟﻠﻤﻨﺎﻃﻖ اﻟﺒﺎردة Used as Tack Coat: Thin film of asphalt applied (immediately before paving) between 2-paved layers (0.2-0.5 litter/m2) b. Medium Curing (M.C): AC (120-150) + Kerosene MC-30 MC-70 (ً )اﻻآﺜﺮ ﺷﻴﻮﻋﺎTight Surface ()ﻣﺴﺎﺣﺎت ﺻﻐﻴﺮة MC-270 (ً )اﻻآﺜﺮ ﺷﻴﻮﻋﺎOpen Surface ()ﻣﺴﺎﺣﺎت آﺒﻴﺮة MC-800 MC-3000 Used as Prime Coat: Film of asphalt applied (before 24hr of paving) between unpaved & paved layers (1.0-0.5 litter/m2) c. Slow Curing (S.C): AC (200-300) + Oils SC-70 SC-250 SC-800 SC-3000 For stabilizing earth works ()ﻟﺘﺜﺒﻴﺖ اﻷﻋﻤﺎل اﻟﺘﺮاﺑﻴﺔ 03-4 Asphaltic Materials Nov-2009 Lectures of Highway Engineering – Forth Stage C) Emulsified Asphalt: Dispersing of asphalt particles in water in presence of emulsifying agent AC (non-polar) + Water (polar H+OH-) + surface active agent (emulsifier) اﻟﻤ ﺎدة اﻟﻤﺴ ﺎﻋﺪة ﺗﻤ ﻨﺢ ذرات اﻹﺳ ﻔﻠﺖ ﻗﻄﺒﻴ ﺔ ﻟﺘﻜ ﻮن ﻣﺴ ﺘﺤﻠﺒﺔ ﻓ ﻲ، اﻟﻤﺎء ﻣ ﺎدة ﻣﺘﺄﻳﻨ ﺔ،* اﻹﺳﻔﻠﺖ ﻣﺎدة ﻏﻴﺮ ﻣﺘﺄﻳﻨﺔ اﻟﻤﺎء * ﺑﻌﺾ اﻟﻤﻮاد اﻟﻤﺴﺎﻋﺪة ﺗﻀﻴﻒ ﺷﺤﻨﺎت ﻣﻮﺟﺒﺔ أو ﺳﺎﻟﺒﺔ أآﺒﺮ ﻣﻦ اﻟﺜﺎﻧﻴ ﺔ واﻟﺘ ﻲ ﺗﺴ ﻤﺢ ﻓ ﻲ اﻟﺤﺼ ﻮل ﻋﻠ ﻰ ﺑﻌ ﺾ اﻟﺨﻮاص ﻟﻠﻤﺎدة اﻟﻤﺴﺘﺤﻠﺒﺔ For: 1. Possibility of mixing with aggregate at normal temperature. 2. Water is safer and cheaper. :ﺗﺴﺘﻌﻤﻞ اﻟﻤﺴﺘﺤﻠﺒﺎت ﻋﻨﺪ اﻟﻤﺰج ﻣﻊ اﻟﺮآﺎم ﻷﻧﻬﺎ ﺗﻮﻓﺮ اﻣﺘﺰاج اﻹﺳﻔﻠﺖ ﺑﺴﻄﺢ اﻟﺮآﺎم.1 إزاﻟﺔ اﻟﻤﺎء اﻟﻤﻮﺟﻮد ﻓﻲ ﻓﺠﻮات اﻟﺮآﺎم.2 * ﻳﺤﺘﻮي ﺳﻄﺢ اﻟﺮآﺎم ﻋﻠﻰ ﺷﺤﻨﺎت ﻗﻄﺒﻴﺔ ﻣﻌﻴﻨﺔ ﻟﺬﻟﻚ اﺧﺘﻴﺎر ﻧﻮع اﻟﻌﺎﻣﻞ اﻟﻤﺴ ﺎﻋﺪ ﻳﺴ ﺎﻋﺪ ﻋﻠ ﻰ إﻳﺠ ﺎد ﺗ ﺮاﺑﻂ ﺑ ﻴﻦ : آﻤﺎ ﻓﻲ اﻟﻤﺨﻄﻂ أدﻧﺎﻩ،اﻹﺳﻔﻠﺖ وﺣﺒﻴﺒﺎت اﻟﺮآﺎم ﺑﺼﻮرة أﻓﻀﻞ Emulsifying Type Anionic Emu. Asp. agent (Quality) Cationic Emu. Asp. Quantity With lime stone (+) With Quartz & Silica (-) Rapid setting As (tack coat) Medium setting As (prime coat with coarse agg.) Slow setting As (prime coat with fine agg.) Anionic Emu. Asp. RS-1 & RS-2 MS-1, MS-2 MS-h SS-1 & SS-1h Cationic Emu. Asp. CRS-1 & CRS-2 * & CMS-2 & CMS-2h CSS-1 & SCC-1h (-) ﻓﻲ ﺑﺪاﻳﺔ اﻟﺮﻣﺰ ﻣﻌﻨﺎﻩ أن اﻟﺸﺤﻨﺔ ﺳﺎﻟﺒﺔC * Setting: coalesance (separation) of asphalt from water Note: (2) more viscose than (1) ()أآﺜﺮ ﻟﺰوﺟﺔ (2h) harder asphalt (residue) ( )اﻟﻤﺘﺒﻘﻲ ﺑﻌﺪ ﺗﺒﺨﺮ اﻟﻤﺎءthan (2) (1h) harder asphalt (residue) than (1) 03-5 Asphaltic Materials Nov-2009 Lectures of Highway Engineering – Forth Stage Important properties of Asphalt: 1. Hardening with time (Oxidation, Volatilization of light components) زﻳﺎدة اﻟﺼﻼﺑﺔ ﺑﻤﺮور اﻟﺰﻣﻦ ﺑﺴﺒﺐ اﻟﺘﺄآﺴﺪ وﺗﺒﺨﺮ اﻟﻤﻮاد اﻟﻤﺬﻳﺒﺔ اﻟﺨﻔﻴﻔﺔ 2. Thermoplastic materials (Consistency varies with temperature) (η) ﻣﺎدة ﻣﺮﻧﺔ ﺑﺎﻟﺤﺮارة )اﻟﻠﺪوﻧﺔ ﺗﺘﻐﻴﺮ ﺑﺘﻐﻴﺮ اﻟﺤﺮارة( وﻣﻘﻴﺎس اﻟﻠﺪوﻧﺔ هﻲ اﻟﻠﺰوﺟﺔ Log η (Abs. Viscosity) Log T (Temp.) (Abs. Temp.) 3. Rheological materials (Stress-Strain behavior is time depending) وﻟﺪراﺳﺔ وﺗﻤﺜﻴﻞ ﺗﺼﺮف اﻟﻤﻮاد اﻻﺳﻔﻠﺘﻴﺔ اﻟﺘﻲ هﻲ وﺳﻂ ﺑﻴﻦ اﻟﻤﻮاد،هﻨﺎك ﻋﻼﻗﺔ ﺑﻴﻦ اﻻﺟﻬﺎد واﻻﻧﻔﻌﺎل ﻣﻊ اﻟﺰﻣﻦ : وآﻤﺎ ﻳﺄﺗﻲ.اﻟﻠﺪﻧﺔ واﻟﻤﻮاد اﻟﻠﺰﺟﺔ ﻳﺠﺐ دراﺳﺔ ﺗﺼﺮﻓﺎت اﻟﻤﻮاد اﻟﺒﻼﺳﺘﻴﻜﻴﺔ واﻟﻠﺰﺟﺔ Elastic materials: - Stress-strain in time independent. - No permanent deformation (all recoverable after unloading). - Instantaneous deformation while loading. - Follow Hook's low. τ (shear stress) = G (shear modulus) * γ (shear strain) - "Spring" may represent such behavior. τ = constant γ ﺑﻘﺎء اﻟﺘﺸﻮﻩ ﺑﺒﻘﺎء اﻟﺤﻤﻞ (Spring) ﻋﻨﺪ ﺗﺴﻠﻴﻂ اﻟﺤﻤﻞ ﻋﻠﻰ ﺣﺪوث ﺗﺸﻮﻩ ﺁﻧﻲ tu t Unload time 03-6 Asphaltic Materials Nov-2009 Lectures of Highway Engineering – Forth Stage Viscous materials: - Stress-Strain is time dependent. - No immediate deformation. - No recovery of deformation (all deformation are permanents). - Follows Newton's law. τ (shear stress) = η(abs. vis.) - dγ (rate of shear strain) dt Dash-pot may represent such behavior. τ = constant γ ﺑﻌﺪ رﻓﻊ اﻟﺤﻤﻞ ﻋﻨﺪ اﻟﺘﺤﻤﻴﻞ ()ﺗﺸﻮﻩ ﺗﺪرﻳﺠﻲ τ η ﺛﻘﻮب Asphalt t tu Unload time But Asphalt may be viscoelastic material. :وﻟﻠﺘﻌﺒﻴﺮ ﻋﻦ هﺬﻩ اﻟﺤﺎﻟﺔ هﻨﺎك ﻣﺠﻤﻮﻋﺔ ﻣﻦ اﻟﻤﻮدﻳﻼت اﻟﺮﻳﺎﺿﻴﺔ By Maxwell model: τ=η dγ ← γ 2 dt ← tu γ1 τ * tu γ2 = η γtotal = γ1 + γ2 γ total τ τ = + * t ← Anytime G η γ γ1 = γ2 γ2 τ η τ G γ2 = γ1 τ * tu η tu 03-7 t Asphaltic Materials Nov-2009 Lectures of Highway Engineering – Forth Stage By Kelvin or Voight model: γ= γ γ= τ *F G F≤1 When t = ∞ τ G τ G − t⎞ τ⎛ γ = ⎜1 − e η ⎟ ⎟ G ⎜⎝ ⎠ G tu F = 1− e γ= τ G t G − *t η No instantaneous deformation No permanent deformation But related elasticity By Burger (4-element) model [of asphaltic material]: γ1 η2 γ2 γ elastic G1 G2 inelastic γ1 = γ3 τ η3 γ2 γ3 η3 viscous τ G1 γ2 γ3 = γ1 τ * tu η3 tu t For loading curve: G − 2t ⎞ τ τ ⎛⎜ τ γ= + 1 − e η2 ⎟ + * t ⎟ η3 G1 G 2 ⎜⎝ ⎠ :ﻣﻼﺣﻈﺔ ﻟﻄﺒﻘﺎت اﻟﺘﺒﻠﻴﻂ اﻟﻤﺮﻧﺔ ﻳﻜﻮن ﻓﻴﻬﺎ ﻗﺴﻢ ﻣﻦ اﻟﺘﺸﻮﻩ وﻗﺘﻲ ﻳﺮﺟﻊ ﺑﺴﺮﻋﺔ وﻗﺴﻢ ﺁﺧﺮ ﻳﺮﺟﻊ ﺑﻤﺮور اﻟﺰﻣﻦ واﻟﻘﺴﻢ اﻟﺜﺎﻟ ﺚ ﺻ ﻐﻴﺮ )اﻟﻘﺴﻢ اﻟﺜﺎﻟﺚ ﻳﺤ ﺪث ﻏﺎﻟﺒ ًﺎ ﻓ ﻲ ﺟﺎﻧ ﺐ اﻟﻤﻤ ﺮ اﻟﺨ ﺎرﺟﻲ ﻟﻠﻄﺮﻳ ﻖ ﺣﻴ ﺚ اﻷﺣﻤ ﺎل اﻟﻤﺮورﻳ ﺔ اﻟﺒﻄﻴﺌ ﺔ.أو ﻗﻠﻴﻞ اﻟﺤﺪوث ﻳﻜﻮن ﻓﻴﻬﺎ داﺋﻤﻲ ((Parking) وآﺬﻟﻚ ﻳﺤﺪث ﻓﻲ ﻣﻨﺎﻃﻖ اﻟﻮﻗﻮف،واﻟﺜﻘﻴﻠﺔ وﻋﺪم آﻔﺎءة اﻟﺘﺒﻠﻴﻂ 03-8 Asphaltic Materials Nov-2009 Lectures of Highway Engineering – Forth Stage 04-Aggregate: Natural Igneous (Granite) Sedimentary (sand, gravel, sandstone, and limestone) Metamorphic (Marble) Industrial product Slag ()ﻣﺨﻠﻔﺎت أﻓﺮان اﻟﺤﺪﻳﺪ Clinker ()ﻣﺨﻠﻔﺎت أﻓﺮان اﻟﻔﺤﻢ Main desirable properties of aggregate: 1) Inter particle friction (Mechanism of load transfer): : وﻳﻤﻜﻦ اﻟﺴﻴﻄﺮة ﻋﻠﻴﻪ ﻣﻦ ﺧﻼل،(ﻣﻴﻜﺎﻧﻴﻜﻴﺔ اﻧﺘﻘﺎل اﻷﺣﻤﺎل )اﻻﺣﺘﻜﺎك اﻟﺪاﺧﻠﻲ a. Surface texture (rough or smooth): Resistance to displacement b. Particle shape (angularity) ( اﻟﺘﺰوّيround, fractured, & cubical) :ﻳﻘﻴﻢ ﻋﻦ ﻃﺮﻳﻖ Angularity No. (0-10%) = % voids in round (≈33%) - % voids in any shape ( آﻠﻤﺎ آﺎن اﻟﺮآﺎم أﻓﻀﻞ10%) وآﻠﻤﺎ اﻗﺘﺮﺑﺖ اﻟﻘﻴﻤﺔ ﻣﻦ c. Gradation ( اﻟﺘﻮزﻳﻊ اﻟﺤﺒﻴﺒﻲdense, gap, & open graded) :ﻳﻘﻴﻢ ﻋﻦ ﻃﺮﻳﻖ P ⎡d⎤ =⎢ ⎥ By Fuller (dense gradation) = 100 ⎣ D ⎦ 1 2 Where: D = diameter of max. size particle Æ (passing 100%); inch d = size of opening for any sieve, inch P = percent passing of that sieve. :وﺗﺴﺘﻌﻤﻞ اﻟﻤﻨﺎﺧﻞ ﻓﻲ إﻳﺠﺎد ﺣﺠﻢ اﻟﺤﺒﻴﺒﺎت اﻟﻤﻄﻠﻮب وهﻲ آﻤﺎ ﻳﻠﻲ 2", 1.5", 1", 3/4", 1/2", 3/8", No.4, …. . ﻣﻌﻨﺎهﺎ ﺗﻮﺟﺪ أرﺑﻌﺔ ﺛﻘﻮب ﻓﻲ اﻷﻧﺞ اﻟﻤﺮﺑﻊ اﻟﻮاﺣﺪNo.4 : ﻓﻨﺴﺘﺨﺮج ﺑﻘﻴﺔ اﻟﻨﺴﺐ ﻣﻦ اﻟﻘﺎﻧﻮن أﻋﻼﻩ وآﻨﺎ ﻳﺄﺗﻲ،1" إذا آﺎن اﻟﻤﻄﻠﻮب ﺗﺼﻤﻴﻢ ﺧﻠﻄﺔ ﺗﺤﻮي ﻋﻠﻰ رآﺎم أآﺒﺮ ﻗﻄﺮ ﻓﻴﻪ:ﻣﺜﺎل 04-1 Aggregate Nov-2009 Lectures of Highway Engineering – Forth Stage 1" 1/2" Æ Æ 100% 3/8" Æ ⎡ 3 "⎤ P=⎢ 8 ⎥ ⎢ 1" ⎥ ⎣ ⎦ 0.5 ⎡ 1 "⎤ P = ⎢ 2 ⎥ *100 = 70% ⎢ 1" ⎥ ⎣ ⎦ 0.5 *100 = 61% .اﻟﺦ ﻣﻦ اﻟﻤﻨﺎﺧﻞ... 2) Durability ()اﻟﺪﻳﻤﻮﻣﺔ: The resistance to: a. Crashing ()اﻟﻄﺤﻦ أو اﻟﺴﺤﻖ: Crashing Value = 40 Tons wt. of mat. pas sin g No.7 Original wt. ≤ 12% (≈ 8%) (1/2" – 3/8") وﻣﺘﺒﻘﻲ1/2" رآﺎم ﻣﺎر ﻣﻦ ﻣﻨﺨﻞ 3/8" ﻋﻠﻰ اﻟﻤﻨﺨﻞ b. Degradation ()اﻟﺘﻜﺴﺮ ﺑﺴﺒﺐ اﻟﺘﺄﺛﻴﺮ اﻟﻤﻴﻜﺎﻧﻴﻜﻲ: % of wear by L. A. Operation, ()ﻃﺮﻳﻘﺔ ﻟﻮس أﻧﺠﻠﺲ 2.5kg (3/4"-1/2") + 2.5kg (1/2"-3/8") & Spheres (500 revolution) Degradation = wt. of mat. pas sin g No.12 ≤ 30% Original wt. c. Disintegration ()اﻟﺘﻜﺴﺮ ﺑﺴﺒﺐ اﻟﺘﺄﺛﻴﺮ اﻟﻜﻴﻤﻴﺎﺋﻲ: 670 gm 330 gm 300 gm 1300 gm (3/4" – 1/2") (1/2" – 3/8") (3/8" – No.4) * Soundness for 16-18 hours & drying Cycle By Na2SO4 ()آﺒﺮﻳﺘﺎت اﻟﺼﻮدﻳﻮم ≤ 12% By MgSO4 ()آﺒﺮﻳﺘﺎت اﻟﻤﻐﻨﻴﺴﻴﻮم ≤ 18 % 3) Wet ability ()ﻗﺎﺑﻠﻴ ﺔ اﻟﺘﺮﻃﻴ ﺐ: adhesion with asphalt, or resistance to stripping of asphalt film from aggregate in the presence of water. a. Mechanical interlock: ()اﻟﺘﺄﺛﻴﺮ اﻟﻤﻴﻜﺎﻧﻴﻜﻲ - Rough surface texture. ()ﺳﻄﺢ ﺧﺸﻦ - Porous aggregate. ( ﻟﻀﻤﺎن ﺗﺪاﺧﻞ اﻹﺳﻔﻠﺖ وﻋﺪم اﻧﻔﺼﺎﻟﻪ ﺑﺎﻟﻤﺎء،)ﻣﺴﺎﻣﻴﺔ ﺳﻄﺤﻴﺔ ﻋﺎﻟﻴﺔ وﻟﻜﻦ ﻏﻴﺮ ﻣﺆﺛﺮة ﻋﻠﻰ اﻟﻘﻮة - No surface coating. ()إزاﻟﺔ اﻷﺗﺮﺑﺔ اﻟﻤﺤﻴﻄﺔ ﺑﺎﻟﺮآﺎم 04-2 Aggregate Nov-2009 Lectures of Highway Engineering – Forth Stage b. Chemical reactivity: ()اﻟﺘﺄﺛﻴﺮ اﻟﻜﻴﻤﻴﺎﺋﻲ Basic minerals (of aggregate) (اﻟﻤﻮاد اﻷوﻟﻴﺔ )اﻟﺮآﺎم + Acidic portion (of asphalt) Æ Compound not soluble in water (ﻣﻮاد ﺣﺎﻣﻀﻴﺔ )ﻓﻲ اﻹﺳﻔﻠﺖ ﻣﺮآﺐ ﻏﻴﺮ ذاﺋﺐ ﻓﻲ اﻟﻤﺎء c. Interfacial tension: ()اﻟﺸﺪ اﻟﺴﻄﺤﻲ ﺑﺴﺒﺐ اﻟﺸﺤﻨﺎت - Hydrophobic aggregate (water-hating) ()ﻏﻴﺮ ﻣﺄﻟﻮف ﻟﻠﻤﺎء - Hydrophilic aggregate (water-loving) ()ﻳﺄﻟﻒ اﻟﻤﺎء . أﻏﻠﺐ اﻟﺮآﺎم اﻟﻌﺮاﻗﻲ ﻣﻦ اﻟﻨﻮع اﻟﺜﺎﻧﻲ )أﻟﻴﻒ ﻟﻠﻤﺎء( ﻟﺬﻟﻚ ﻳﺠﺐ ﻣﺮاﻋﺎة ذﻟﻚ.واﻟﻤﻔﻀﻞ ﻣﻨﻬﺎ ﻏﻴﺮ اﻟﻤﺄﻟﻮف ﻟﻠﻤﺎء Aggregate combination (blending) & separation to meet Job Mix requirement: أو ﻓﺼ ﻞ ﻟﺘ ﺪرﺟﺎت اﻟﺮآ ﺎم/ ﻟ ﺬﻟﻚ ﻧﺤﺘ ﺎج إﻟ ﻰ ﻋﻤﻠﻴ ﺔ دﻣ ﺞ و،اﻟﺮآ ﺎم اﻟﻄﺒﻴﻌ ﻲ ﻏﺎﻟﺒ ًﺎ ﻻ ﻳﻜ ﻮن ﺿ ﻤﻦ اﻟﻤﻮاﺻ ﻔﺎت اﻟﺨﺎﺻ ﺔ ﺑﺎﻟﺘ ﺪرج :ﻟﻠﺤﺼﻮل ﻋﻠﻰ ﺗﺪرج ﻣﻘﺎرب ﻟﻤﻌﺎدﻟﺔ اﻟﺨﻠﻂ 1. Discarding the over size. ()إﺑﻌﺎد اﻟﺤﺠﻮم اﻷآﺒﺮ ﻣﻦ اﻟﺤﺠﻢ اﻷﻗﺼﻰ ﻟﻠﺮآﺎم 2. Separating into two or more portions on selected proper sieve. ()ﻓﺼﻞ اﻟﺮآﺎم إﻟﻰ ﺟﺰﺋﻴﻦ أو أآﺜﺮ ﻓﻲ ﻣﻨﻄﻘﺔ اﻟﺨﻠﻞ 3. Recombining using proper percentage for recombination with specification requirement (mid-specification limits). ()إﻋﺎدة دﻣﺞ اﻷﺟﺰاء ﺑﻨﺴﺐ ﻣﺌﻮﻳﺔ ﻣﻨﺎﺳﺒﺔ ﻟﺘﺘﻼﺋﻢ وﻣﻮاﺻﻔﺎت اﻟﺘﺪرج( )ﻣﻨﺘﺼﻒ اﻟﻤﻮاﺻﻔﺔ 4. Addition of fine materials (& Filler) if necessary. ()إﺿﺎﻓﺔ رآﺎم ﻧﺎﻋﻢ )ﻣﻮاد ﻣﺎﻟﺌﺔ( ﻋﻨﺪ اﻟﺤﺎﺟﺔ 04-3 Aggregate Nov-2009 Lectures of Highway Engineering – Forth Stage Ex.: Specifications 100 100 95 – 65 60 – 40 40 – 24 30 – 20 20 – 10 10 – 5 5–3 (% passing) Natural grading 100 90 80 60 40 30 20 10 5 Sieve size "1 "3/4 "1/2 "3/8 No.4 No.10 No.40 No.80 No.200 Sol.: ﻃﺮﻳﻘﺔ اﻟﺤﻞ: .1إزاﻟﺔ اﻟﺤﺠﻢ ﻓﻮق اﻟﺤﺠ ﻢ اﻷﻗﺼ ﻰ ) :(Discard Oversizeﻧﻼﺣ ﻆ أن اﻟﺤﺠ ﻢ اﻷﻗﺼ ﻰ ﻟﻠﺮآ ﺎم ﺿ ﻤﻦ اﻟﻤﻮاﺻ ﻔﺎت )" (3/4ﻟ ﺬﻟﻚ ﻳﺠﺐ إزاﻟﺔ اﻟﺤﺠﻮم ﺑﻴﻦ )" (1"-3/4أي ﺟﻌﻞ اﻟﻤﺎر ﻣﻦ اﻟﻤﻨﺨﻞ )" (100%) (3/4وﺗﺼﺤﻴﺢ ﺗﺪرج ﺑﺎﻗﻲ اﻟﻤﻨﺎﺧﻞ. .2ﺑﻌﺪ اﻟﻤﺮﺣﻠﺔ اﻷوﻟﻰ ﻧﺤﺪد ﺑﺪاﻳ ﺔ اﻟﺨﻠ ﻞ ﻓ ﻲ أي ﻣ ﻦ اﻟﻤﻨﺎﺧ ﻞ ،وﻧﻼﺣ ﻆ أن ﻣﻨﻄﻘ ﺔ اﻟﺨﻠ ﻞ ﻣ ﻊ اﻟﻤﻮاﺻ ﻔﺎت ه ﻲ ﻋﻨ ﺪ اﻟﻤﻨﺨ ﻞ )"(3/8 وآﻤﻴ ﺔ اﻟﻤ ﺎر ) (67وه ﻲ ﻣﺘﺠ ﺎوزة ﻟﻠﻤﻮاﺻ ﻔﺔ ) ،(40-60ﻟ ﺬﻟﻚ ﻳ ﺘﻢ ﻓﺼ ﻞ اﻟﻤﻘ ﺎدﻳﺮ ﻋﻨ ﺪ اﻟﻤﻨﺨ ﻞ )" (3/8واﻟ ﺬي ﻓﻴ ﻪ اﻟﺨﻠ ﻞ إﻟ ﻰ ﻣﺠﻤﻮﻋﺘﻴﻦ ﺛﻢ ﻳﺘﻢ اﻟﻤﺰج ﺑﻨﺴﺐ ﺑﻤﺤﺎوﻟﺔ وﺧﻄﺄ ﻟﻠﻮﺻﻮل ﻟﻠﻨﺴﺐ اﻟﻤﻨﺎﺳﺒﺔ ﻟﺘﺼﺤﻴﺢ اﻟﺘﺪرج. )(8 )(C 50% A + 50% B 100 100 83 50 33 26 16 8 4.5 )(7 )(B Portion passing "3/8 100 100 67 0 0 0 0 0 0 )(6 Percent retained )(5)-(4 0–0 0–0 11 – 33 33 – 100 )(5 )(A )Step (2 Portion Passing "3/8 100 (100/67)*45=67 (100/67)*34=51 (100/67)*22=33 (100/67)*11=16 (100/67)*6=9 )(4 )Step (1 Portion passing "3/4 )(3 Specifications )(2 )(% passing Natural grading )(1 Sieve size 100 100 (100/90)*80=89 (100/90)*60=67 (100/90)*40=45 (100/90)*30=34 (100/90)*20=22 (100/90)*10=11 (100/90)*5=6 100 100 95 – 65 60 – 40 40 – 24 30 – 20 20 – 10 10 – 5 5–3 100 90 80 60 40 30 20 10 5 "1 "3/4 "1/2 "3/8 No.4 No.10 No.40 No.80 No.200 ﻼ أي ان اﻟﺮآ ﺎم ﻻ ﻳﺤ ﻮﻳﻌﻠﻰ ﻣ ﻮاد ﻧﺎﻋﻤ ﺔ ﻣ ﻦ اﻟﺒﺪاﻳ ﺔ وﻻ ﻳﻤﻜ ﻦ ﺗﺼ ﺤﻴﺤﻪ ﺑﺈﻋ ﺎدة اﻟﺘﻮزﻳ ﻊ ﺑ ﻞ إذا آﺎﻧﺖ ﻧﺴ ﺒﺔ اﻟﻤ ﺎﻟﺊ ) (1)= (4.5ﻣ ﺜ ً ﺑﺈﺿﺎﻓﺔ ).(filler )(5 97% C + 3% D 100 100 83.5 51.5 35 22.25 18.5 10.75 4 Aggregate )(4 )(D Filler 100 100 100 100 100 100 100 100 100 )(3 )(C )(2 Specifications )(1 Sieve size 100 100 83 50 33 26 16 8 1 100 100 95 – 65 60 – 40 40 – 24 30 – 20 20 – 10 10 – 5 5–3 "1 "3/4 "1/2 "3/8 No.4 No.10 No.40 No.80 No.200 04-4 Nov-2009 Lectures of Highway Engineering – Forth Stage Ex.: Sieve 1" 1/2" No.4 No.10 No.40 No.80 No.200 Stock (A) Passing 100 63 19 8 5 3 2 Stock (B) Passing Stock (C) Passing 100 92 55 36 3 Specification 100 70 – 85 40 – 55 30 – 42 20 – 30 12 – 22 5 – 10 100 97 88 Sol.: :ﻃﺮﻳﻘﺔ اﻟﺤﻞ (No.200) وﻏﺎﻟﺒ ًﺎ ﻧﺒ ﺪأ ﺑﺎﻟﻨﺨ ﻞ،ﺗﻜﻮن ﻃﺮﻳﻘﺔ اﻟﺤﻞ ﺑﻄﺮﻳﻘﺔ اﻟﻤﺤﺎوﻟﺔ واﻟﺨﻄﺄ ﺑﻔﺮض ﻧﺴ ﺐ ﻣ ﺰج وﻣﻘﺎرﻧﺘﻬ ﺎ ﻣ ﻊ ﻣﻨﺘﺼ ﻒ اﻟﻤﻮاﺻ ﻔﺔ (No.200) ( ﻧﺴ ﺒﺔ اﻟﻤ ﺎر ﻣ ﻦ اﻟﻤﻨﺨ ﻞC) أي ﺑﻤ ﺎ أن ﻟﻠﻜﻮﻣ ﺔ،(Passing) وﻧﻔﺮض ﻟﻪ ﻧﺴﺒﺔ ﺻﻐﻴﺮة ﻟﻠﻜﻮﻣ ﺔ ذا اﻟﻤﺤﺘ ﻮى اﻟﻌ ﺎﻟﻲ ﻣ ﻦ (A, B) ( ﻓﻴﺠﺐ إﻋﻄﺎءهﺎ ﻧﺴﺒﺔ ﻗﻠﻴﻠﺔ وإﻋﻄﺎء ﻧﺴﺐ أآﺒﺮ ﻟﻠﻜﻮﻣﺘﻴﻦ5-10) ( واﻟﻤﻮاﺻﻔﺔ88) ﻳﺴﺎوي Sieve 1" 1/2" No.4 No.10 No.40 No.80 No.200 ﻧﺴﺐ اﻟﻤﺰج Stock (A) Passing 100 63 19 8 5 3 2 65% Stock (B) Passing 100 92 55 36 3 30% Stock (C) Passing Specification 100 70 – 85 40 – 55 30 – 42 20 – 30 12 – 22 5 – 10 100 97 88 5% 04-5 Mid Specification 100 77.5 47.5 36 25 17 7.5 Passing % Aggregate 100 76 47 38 25 18 7 Nov-2009 Lectures of Highway Engineering – Forth Stage 05-Asphalt Paving Mixture: :ﻳﺠﺐ أن ﺗﺘﻮﻓﺮ ﻋﺪد ﻣﻦ اﻟﺨﻮاص اﻟﺘﻲ ﺗﺤﺪد آﻔﺎءة اﻷﺳﻔﻠﺖ Function: - Smooth riding quality surface. ()ﻧﻌﻮﻣﺔ ﺳﻄﺤﻴﺔ ﻟﻀﻤﺎن ﻧﻮﻋﻴﺔ ﺳﻴﺮ ﻣﻨﺎﺳﺒﺔ - Safety. ()اﻷﻣﺎن - Load carrying median. ()ﻳﻤﻜﻦ ﺗﺤﻤﻞ اﻷﺣﻤﺎل اﻟﻤﺮورﻳﺔ اﻟﻤﺴﻠﻄﺔ اﻟﻤﺘﻮﻗﻌﺔ Note: • Batch plant: percentage depend on weight. Continuous plant: percentage depend on volume. • Hot mix: after heating aggregate & asphalt. Cold mix: mixing at normal temperature (emulsified asphalt). • Dense mix: % air voids ≤ 10%. Open mix: % air voids > 10%. Desirable properties: 1) Stability ()اﻟﺜﺒﺎت: resistance to permanent deformation. ()ﻣﻘﺎوﻣﺔ اﻟﺨﻠﻴﻂ ﻟﻠﺘﺸﻮﻩ اﻟﺪاﺋﻤﻲ Affected by: • Frictional resistance ()اﻟﻤﻘﺎوﻣ ﺔ اﻟﻨﺎﺗﺠ ﺔ ﻣ ﻦ اﻻﺣﺘﻜ ﺎك: rough surface texture (of aggregate), optimum asphalt content, & dense gradation with compaction. ( ﺗﺪرج آﺜﻴﻒ ﻣﻊ اﻟﺮص، ﻧﺴﺒﺔ اﻻﺳﻔﻠﺖ اﻟﻤﺜﻠﻰ،)ﺧﺸﻮﻧﺔ اﻟﺮآﺎم • Cohesion ()اﻟﺘﻤﺎﺳ ﻚ: reology of asphalt, adhesion with aggregate, & surface area of aggregate (filler 3-8%). ()آﻠﻤﺎ ﻧﺰداد ﻣﺴﺎﺣﺔ اﻟﺮآﺎم ﻳﺰداد اﻟﺘﻼﺻﻖ ﺑﻴﻨﻪ وﺑﻴﻦ اﻷﺳﻔﻠﺖ ﻟﺬﻟﻚ ﻧﺴﺒﺔ اﻟﻤﺎﻟﺊ ﻣﻬﻤﺔ ﻓﻲ زﻳﺎدة اﻟﺜﺒﺎت • Inertia of pavement: speed of vehicles, concentration of load, & axle load. ( واﻟﺤﻤﻞ اﻟﻤﺤﻮري، ﺗﺮآﻴﺰ اﻷﺣﻤﺎل،)ﺳﺮع اﻟﻤﺮآﺒﺎت 2) Durability ()اﻟﺪﻳﻤﻮﻣ ﺔ: resistance to weathering (air, water, & oil) & abrasive action of traffic. ( وﻣﻘﺎﻣ ﺔStripping اﻟﻤ ﺎء واﻟﻤ ﻮاد اﻟﻨﻔﻄﻴ ﺔ ﺗﺴ ﺒﺐ ﻓﺼ ﻞ اﻟﻤ ﻮاد،Oxidation )ﻣﻘﺎوﻣ ﺔ اﻟﺘﺠﻮﻳ ﺔ أواﻟﺘﻌﺮﻳ ﺔ )اﻟﻬ ﻮاء ﻳﺴ ﺒﺐ اﻟﺘﺄآﺴ ﺪ (اﻟﺘﺄﺛﻴﺮ اﻻﺗﻼﻓﻲ ﻟﻠﺴﻴﺮ 05-1 Asphalt Paving Mixture Nov-2009 Lectures of Highway Engineering – Forth Stage Affected by: • % of asphalt ()ﻧﺴﺒﺔ اﻻﺳﻔﻠﺖ • Gradation (dense or open) ()اﻟﺘﺪرج • Degree of compaction ()درﺟﺔ اﻟﺤﺪل 3) Flexibility ()اﻟﻤﺮوﻧﺔ: (fatigue resistance) ability to bend repeatedly without fracture. ( ﻗﺎﺑﻠﻴﺔ اﻟﺘﻤﺪد ﻟﻤﺮات ﻣﺘﻌﺪدة ﺑﺪون ﺣﺪوث ﺗﻜﺴﺮ،)ﻣﻘﺎوﻣﺔ اﻟﻜﻠﻞ 4) Skid resistance ()ﻣﻘﺎوﻣﺔ اﻟﺘﺰﺣﻠﻖ: ability to provide safe coefficient of friction. ()أﻣﻜﺎﻧﻴﺔ ﺗﻮﻓﻴﺮ ﻣﻌﺎﻣﻞ اﺣﺘﻜﺎك ﺁﻣﻦ Affected by: • % of asphalt. ()ﻧﺴﺒﺔ اﻻﺳﻔﻠﺖ • Gradation. ()اﻟﺘﺪرج 5) Imperviousness ()ﻋﺪم اﻟﻨﻔﺎذﻳﺔ: ()اﻻﻧﻐﻼﻗﻴﺔ أو ﻋﺪم وﺟﻮد ﻣﺴﺎﻣﺎت 6) Workability ()ﻗﺎﺑﻠﻴ ﺔ اﻟﺘﺸ ﻐﻴﻞ: ability to provide smooth shaping of the finished pavement. Affected by: • Balanced portion of materials ()أﺟﺰاء ﻣﺘﻨﺎﺳﺒﺔ ﻣﻦ اﻟﻤﻮاد • Efficient equipments. Job Mix formula: 1. Selection of aggregate quality & gradation with in specification limits. ()اﺧﺘﻴﺎر اﻟﺮآﺎم ﻣﻦ اﻟﻨﺎﺣﻴﺔ اﻟﻨﻮﻋﻴﺔ واﻟﺘﺪرج ﺿﻤﻦ اﻟﻤﻮاﺻﻔﺎت اﻟﻘﻴﺎﺳﻴﺔ 2. Selection of asphalt cement grade. (( وﻳﻜﻮن ﻟﻴﻦ ﻟﻀﻤﺎن ﻗﺎﺑﻠﻴﺔ اﻟﺘﺸﻐﻴﻞ واﻟﻤﻄﺎوﻋﺔ وﺻﻠﺐ ﻟﻤﻨﻊ اﻟﺘﺸﻮﻩ اﻟﺪاﺋﻤﻲ )اﻟﺜﺒﻮﺗﻴﺔ،)اﺧﺘﻴﺎر ﻧﻮﻋﻴﺔ اﻻﺳﻔﻠﺖ 3. Selection of optimum asphalt cement. ( ﺗﻜﻮن آﻤﻴﺔ آﺎﻓﻴﺔ ﻟﻀﻤﺎن اﻟﺪﻳﻤﻮﻣﺔ واﻟﻤﻄﺎوﻋﺔ وﻻ ﺗﺆﺛﺮ ﻋﻠﻰ اﻟﺜﺒﻮﺗﻴﺔ واﻻﺣﺘﻜﺎك اﻟﺪاﺧﻠﻲ،)اﺧﺘﻴﺎر ﻧﺴﺒﺔ اﻻﺳﻔﻠﺖ اﻟﻤﺜﻠﻰ 05-2 Asphalt Paving Mixture Nov-2009 Lectures of Highway Engineering – Forth Stage Mix Design Methods: 1. Marshall method 2. Hveem method 3. Immersion – compression 4. Indirect tensile strength 5. Creep method Marshall Method: (Max. size of aggregate 1") Stability: maximum load resistance of standard specimen (4" dia. & 2.5" height) when tested in the direction of diameter, at 60oC at the rate of 2"/min. (Stability ≥ 800 kg) (60oC) ( ﻋﻨ ﺪ ﺗﺴ ﻠﻴﻄﻪ ﺑﺎﺗﺠ ﺎﻩ اﻟﻘﻄ ﺮ وﺑﺪرﺟ ﺔ ﺣ ﺮارة4"x2.5") وهﻲ ﻣﻘﺎوﻣﺔ أآﺒﺮ ﺣﻤﻞ ﻣﺴﻠﻂ ﻋﻠﻰ ﻧﻤﻮذج ﻗﻴﺎﺳﻲ:ﺛﺒﺎﺗﻴﺔ ﻣﺎرﺷﺎل (2"/min.) وﺑﻤﻌﺪل ﺗﺤﻤﻴﻞ ﻣﻠ ﺊ اﻟﻘﺎﻟ ﺐ ﺑ ﺎﻟﻤﺰﻳﺞ اﻟﺴ ﺎﺧﻦ ﺑﺪرﺟ ﺔ ﺣ ﺮارة اﻟﻤ ﺰج:ﻣﻠﺨ ﺺ ﻃﺮﻳﻘ ﺔ اﻟﻌﻤ ﻞ ﻟﻠﺘﺠﺮﺑ ﺔ ( ﺛﻢ ﺗﺘﻢ ﻋﻤﻠﻴﺔ اﻟﺮص وذﻟﻚ ﺑﻤﻄﺮﻗﺔ100-105oC) ( ﺛﻢ ﺗﺮآﻬﺎ ﻟﺘﺒﺮد ﻟﺪرﺟﺔ160oC) Dial gage (1) Stability Dial gage (2) Flexibility 4" : ﻗﻴﺎﺳﻴﺔ ﺑﻤﻌﺪل 75 blow/end (tire pressure = 200psi) or 50 blow/end (tire pressure =100psi) ﺛ ﻢ ﺗﻔﺤ ﺺ،( ﻟﻀ ﻤﺎن زوال اﻟﺘﺸ ﻮهﺎت اﻟﻮﻗﺘﻴ ﺔ ﺑﺴ ﺒﺐ اﻟ ﺮص24hr) ﺛ ﻢ ﺗﺘ ﺮك ﻟﻤ ﺪة .ﺑﺠﻬﺎز ﻣﺎرﺷﺎل ﺑﺪرﺟﺔ ﺣﺮارة اﻟﻔﺤﺺ Flexibility (Flow): the deformation (strain) corresponding to the max. load resistance of the standard specimen. (2 – 4 mm) Durability: density – voids analysis. % of air voids (3 – 5)% or (3 - 7)% in total mix. 05-3 Asphalt Paving Mixture Nov-2009 Lectures of Highway Engineering – Forth Stage Density (gm/m3) ﺛﺒﻮﺗﻴ ﺔ،ﺗﺮﺳﻢ اﻟﻌﻼﻗﺔ ﺑﻴﻦ ﻧﺴﺒﺔ اﻻﺳﻔﻠﺖ ﻓﻲ اﻟﻤﺰﻳﺞ ﻣﻊ اﻟﻌﻮاﻣﻞ )اﻟﻜﺜﺎﻓﺔ .( وﻧﺴﺒﺔ اﻟﻔﺠﻮات اﻟﻤﻤﻠﻮءة ﺑﺎﻻﺳﻔﻠﺖ، ﻧﺴﺒﺔ اﻟﻔﺠﻮات، اﻟﻤﺮوﻧﺔ،ﻣﺎرﺷﺎل 2 ﺛﻢ ﻳﺘﻢ اﺧﺘﻴﺎر اﻟﻨﺴﺒﺔ اﻟﻤﺜﻠﻰ ﻣﻦ اﻻﺳ ﻔﻠﺖ ﺑﺤﻴ ﺚ ﺗﺤﻘ ﻖ ﻗ ﻴﻢ ﻟﻬ ﺬﻩ اﻟﻌﻮاﻣ ﻞ Stability (kg) وذﻟ ﻚ ﺑﺈﻳﺠ ﺎد ﻧﺴ ﺒﺔ.ﺿﻤﻦ اﻟﻤﻮاﺻﻔﺎت اﻟﻘﻴﺎﺳ ﻴﺔ ﻟﻄﺒﻘ ﺔ اﻟﺘﺒﻠ ﻴﻂ اﻟﻤﻄﻠﻮﺑ ﺔ :اﻻﺳﻔﻠﺖ اﻟﻤﻘﺎﺑﻠﺔ ﻟﻤﺎ ﻳﺄﺗﻲ Flow (mm) (Max. Stability) أآﺒﺮ ﻗﻴﻤﺔ ﻟﻠﺜﺒﺎت.2 (( )ﻣﻌﺪل اﻟﻘﻴﻤﺔ5%) ﻋﻨﺪ ﻧﺴﺒﺔ ﻓﺠﻮات.3 5 1 (( )ﻣﻌﺪل اﻟﻘﻴﻤﺔ75%) ﻧﺴﺒﺔ اﻟﻔﺠﻮات ﻣﻤﻠﻮءة ﺑﺎﻻﺳﻔﻠﺖ.4 Voids in mix (%) 8 Voids filled with asphalt (%) 85 ﻳﺴ ﻘﻂ اﻟﻤﻌ ﺪل ﻋﻠ ﻰ اﻟﻤﻨﺤﻨﻴ ﺎت،وﺑﺄﻳﺠ ﺎد ﻣﻌ ﺪل ﻟﻨﺴ ﺒﺔ اﻻﺳ ﻔﻠﺖ أﻋ ﻼﻩ . وﻳﺪﻗﻖ ﻣﻊ اﻟﻤﻮاﺻﻔﺔ،ﻻﻳﺠﺎد ﻗﻴﻤﺔ آﻞ ﻋﺎﻣﻞ ﻣﻦ اﻟﻌﻮاﻣﻞ .وﺧﻮاص اﻟﺮآﺎم أو اﻻﺳﻔﻠﺖ 1000 600 (Max. Density) أآﺒﺮ ﻗﻴﻤﺔ ﻟﻠﻜﺜﺎﻓﺔ.1 إذا ﻟ ﻢ ﺗﻨﻄﺒ ﻖ أﺣ ﺪ اﻟﻤﻮاﺻ ﻔﺎت ﻓﻬﻨ ﺎك ﺧﻠ ﻞ ﻓ ﻲ ﻣﻮاﺻ ﻔﺎت وﺗﺤﻠﻴ ﻞ 2.4 2 65 4 5 6 Asphalt content by wt. of total mix (%) For surface course (wearing): • % of asphalt (usually effective asphalt) = 4.5 – 6.5 % by wt. of total mix • Stability at 60oC & 75 blows/end ≥ 800 kg • Flow = 2 – 4 mm • % air voids in total mix = 3 – 5 % • % voids filled with asphalt = 70 – 85 % • % voids in mineral aggregate V. M. A.% (min. =15%) • Filler / Asphalt (max. = 1.4) • Index of retained strength = • Relative compaction = comp. st. (Im mersion) *100% ≥ 70% comp. st. (Dry) Field density *100% ≥ 96% Lab. density Compaction of Pavement: a) Rolling edges & joints: immediately after spreading (Tandem steel roller). b) Break down rolling: as soon as the mix can bear roller (3-wheel roller). c) Intermediate roller: while the mix is still plastic (kinematics roller). d) Finish rolling: mix still warm to eliminate tire marks (steel roller). Note: Smoothness: (Irregularities) ≤ 3mm/3m 3m 05-4 Asphalt Paving Mixture Nov-2009 Lectures of Highway Engineering – Forth Stage Analysis of Mixture (Mass-Volume Relationship): ﻓﺮاﻏﺎت هﻮاﺋﻴﺔ اﻻﺳﻔﻠﺖ اﻟﻔﻌﺎل ()اﻟﻤﺤﻴﻂ ﺑﺎﻟﺮآﺎم Aggregate particle coated with asphalt, showing absorbed asphalt, permeable and impermeable porous Zero Air voids (air space) Va WS1 Binder (Asphalt) Effective asphalt Gb VS1 WS2 Absorbed Asphalt VS2 WS اﻻﺳﻔﻠﺖ اﻟﻤﻤﺘﺺ داﺧﻞ اﻟﻤﺴﺎﻣﺎت اﻟﻨﻔﺎذة ﻟﻠﺮآﺎم اﻟﻔﺠﻮات اﻟﻤﺤﺼﻮرة ﺑﻴﻦ اﻟﺮآﺎم واﻻﺳﻔﻠﺖ اﻟﺠﺰء اﻟﺼﻠﺐ ﻣﻦ اﻟﺮآﺎم + اﻟﻔﺠﻮات اﻟﺪاﺧﻠﻴﺔ اﻟﺼﻤﺎء W Vv V Permeable Porous Wagg. Solid Aggregate + Impermeable Porous V3 V2 V1 Aggregate coated with asphalt, showing air voids Va = volume of air voids in total mix Vs1 = volume of effective asphalt Vs2 = volume of absorbed asphalt V1 = apparent volume of aggregate V2 = effective volume of aggregate V3 = bulk volume of aggregate V = total volume of mixture Vv = voids of aggregate (Voids in mineral aggregate) - Bulk GA = bulk specific gravity of combined aggregate = = WAgg. V3 100 %course %fine %filler + + Gs(course) Gs(file) Gs(filler) Ex.: 50% (1"-No.4) Gs=2.6, 45%, 45% (No.4-No.200) Gs=2.65, 5% (No.200) Gs=3.15 Bulk GAgg. = 100 50 45 5 + + 2.6 2.65 3.15 05-5 Asphalt Paving Mixture Nov-2009 Lectures of Highway Engineering – Forth Stage - PS = total % of asphalt (by wt. of total mix) - PA = % of aggregate (by wt. of total mix) PS + PA = 100% Æ PA = 100 - PS - In void less mix Æ max. theoretical sp. gr. of mix (max. Gm by testing in the lab (ASTM-2041) max . Gm = - Effective GA = = W V − Va WA V2 100 − PS (as sp. gr. of asphalt), where V2 = V-(Va+Vs1+Vs2), 100 PS − Gm Gs Effective GA constant property (independent of asphalt content) وﻻﻳﺠ ﺎد،( ﻟﻨﺴ ﺒﺔ ﻣ ﻦ اﻻﺳ ﻔﻠﺖ ﻟﻨﻮﻋﻴ ﺔ رآ ﺎم واﺳ ﻔﻠﺖTheoretical) (max. Gm) ﻣ ﻦ ﺗﺠﺮﺑ ﺔ ﻣﺨﺘﺒﺮﻳ ﺔ ﻳﻤﻜ ﻦ أﻳﺠ ﺎد (max. Gm) ( وﻧﻄﺒ ﻖ اﻟﻘ ﻮاﻧﻴﻦ اﻵﺗﻴ ﺔ ﻻﺳ ﺘﺨﺮاج ﻗ ﻴﻢeffective GA) ( ﻟﻨﺴ ﺐ أﺧ ﺮى ﻣ ﻦ اﻻﺳ ﻔﻠﺖ ﻳﻤﻜ ﻦ أﻳﺠ ﺎدmax. Gm) .( دون إﺟﺮاء ﺗﺠﺎرب أﺧﺮىCalculated) - Actual Gm = W Wair = Wair − Wwater V Found by: Core from pavement, or compacted sp. gr. in lab - Calculated max. Gm = 100 W = P 100 − PS V − Va S + Gs effective G A - % air voids (in total mix) = Va max . Gm − actual Gm *100% = *100% V max . Gm - % voids in mineral aggregate (V.M.A.%) = Vv actual Gm * PA *100% = 100 − bulk G A V Vv = V – V3, WS1 + WS2 = WS, WS + WA = W - Absorbed asphalt (% by wt. of agg.) = P'S2 = ⎡ 1 1 WS 2 *100% WA ⎤ − =⎢ ⎥ * Gs *100% ⎣ bulk G A effective G A ⎦ V3 – V2 = VS2, VS2Gs , WA ⎛ WA WA ⎞ ⎟⎟ ⎜⎜ , ⎝ V3 V2 ⎠ 05-6 Asphalt Paving Mixture Nov-2009 Lectures of Highway Engineering – Forth Stage - Effective asphalt (% by wt. of total mix) = PS1 = PS − P'S2 *PA = PS – PS2 100 Where: PS2 = absorbed asphalt (% by wt. of total mix) - % voids filled with asphalt = = VS1 *100% Vv actual Gm * PS1 *100% actual Gm * PS1 + Gs * % air voids Vv = Va + VS Ex.: To prepare asphalt mixture as surface course, it is found the following: a) For aggregate: Sieve size: % passing: For course agg. Gs = 2.64 For fine agg. Gs = 2.67 For filler Gs = 3.10 1" 100 No. 4 45 No. 200 5 b) For asphalt (40-50) Æ Gs = 1.04 c) For asphalt concrete contains 5% asphalt Æ max. Gm = 2.49 If the same above materials used to construct asphalt concrete layer with 5.7% asphalt. The core from layer has Wair = 1200gm, & Wwater = 692gm. Check this layer? Sol.: Check: % air voids (3-5), V.M.A. = min. 15, asphalt voids (70-85), effective asphalt (4.5-6.5)%, اﻟﺘﻘﺮﻳﺐ ﻟﺜﻼث ﻣﺮاﺗﺐ Bulk GA = 100 = 2.672 55 40 5 + + 2.64 2.67 3.1 Effective GA = 100 − 5 = 2.687 ()ﻣﻘﺪرا ﺛﺎﺑﺖ ﺑﺘﻐﻴﺮ ﻧﺴﺒﺔ اﻻﺳﻔﻠﺖ 100 5 − 2.49 1.04 For the layer with asphalt = 5.7% Actual Gm = 1200 = 2.362 1200 − 692 05-7 Asphalt Paving Mixture Nov-2009 Lectures of Highway Engineering – Forth Stage Calculated max Gm = 100 = 2.464 5.7 100 − 5.7 + 1.04 2.687 Check: 1) % V. M. A. = 100 − 2) % air voids = 2.362 * 94.3 = 16.6% ≥ 15% ∴OK 2.672 2.464 − 2.362 *100% = 4.1% (3 – 5)% ∴OK 2.464 3) absorbed asphalt (by wt. of agg.) 1 1 ⎤ − = ⎡⎢ *1.04 *100% = 0.23% ⎣ 2.672 2.687 ⎥⎦ ∴ effective asphalt concrete = PS1 = 5.7 − 0.23 * 94.3 = 5.48% (4.5-6.5)% ∴OK 100 4) % voids filled with asphalt = 2.362 * 5.48 *100% = 75.2% (70 – 85)% ∴OK 2.362 * 5.48 + 1.04 * 4.1 05-8 Asphalt Paving Mixture Nov-2009 Lectures of Highway Engineering – Forth Stage 06-Drainage: Proper drainage is important to ensure high quality pavement. Moisture in the subgrade and subbase layer can weaken these materials by: 1) Increasing pore water pressure. 2) Reducing the materials resistance to shear. - Some soils expand when moist causing differential heaving. - Moisture can cause stripping of aggregate. Moisture Sources: Rain water, runoff, and high ground water, which prevented by: A) Surface Drainage: By removing all water that is present on surface and shoulder, by these primary means, to prevent water infiltration and accumulation: 1) Impermeable Mix: Air voids in total mix <7%, by proper compaction and minor cracks in the mix should be sealed. 2) Slop: Cross slop =2% and using curb with gutter (in urban and suburban highways) or road side ditches (in rural highway cut). 3) Grade: Use grade ≥ 0.5% for curb with gutter or side ditches to allow flow to central collection point. B) Subsurface Drainage: Is concerned with removing water, typically the result of high water table or wet weather which can accumulate under the pavement structure by two chief means: - Gravity flow: (in mix with air voids above 7%) and through cracks. - Capillary rise: (in the fine grained soil). 06-1 Drainage Nov-2009 Lectures of Highway Engineering – Forth Stage 1) Minimize water infiltration into the pavement structure: by providing proper road side drainage and minimizing air voids in the mix. 2) Provide surface drainage: consist of three base elements: - A permeable subbase to provide for rapid removal of water which enters the pavement structure. - A method of conveying the removed water, by using a base sloped towards a drainage ditch. - A filter layer (such as geotextile, graded aggregate) to prevent the migration of fines into the permeable base from subgrade. Asphalt or PCC Shoulder Base and/or subbase Permeable base (subbsae) grotextile or graded agg. Outlet Collector pipe 06-2 Drainage Nov-2009 Lectures of Highway Engineering – Forth Stage 07-Evaluation of Strength for Subgrade: * C. B. R.: California Bearing Ratio, for subgrade in "Flexible Pavement". C.B.R.0.1" = C.B.R.0.2" P0.1" (psi) 1000(psi) Whichever is grater P (psi) = 0.2" 1500(psi) * K: Modulus of subgrade reaction, for subgrade in "Rigid Pavement" By Westagard: R = K * δ Where: R = reaction (applied stress), δ = deflection P Pressure (P) 10psi 18" ϕ P0.05" 24" ϕ 26" ϕ 28" ϕ K 1 0.05" 30" ϕ δ10psi Subgrade Deflection (δ) وﻳﻘ ﺮأ اﻟﺘﺸ ﻮﻩ وﻳﺮﺳ ﻢ،(ﺗﺠﺮى اﻟﺘﺠﺮﺑﺔ ﻣﻮﻗﻌﻴًﺎ ﻣﻦ ﺧﻼل ﺗﺤﻤﻴﻞ ﺻﻔﺎﺋﺢ ذات أﻗﻄﺎر ﻣﺨﺘﻠﻔﺔ )اﻟﻤﺒﻴﻨﺔ أﻋ ﻼﻩ : وهﻨﺎك ﻃﺮﻳﻘﺘﻴﻦ،(K) ﻣﻨﺤﻨﻲ وﻣﻨﻪ ﻧﺴﺘﺨﺮج ﻗﻴﻤﺔ As: K (pci) = P0.05" 0.05" Or sometime: K = 10(psi) δ10 psi وﻳﻤﻜ ﻦ اﺳ ﺘﺨﺪام أﻗﻄ ﺎر،ﻓﻲ ﺣﺎﻟﺔ ﻋﺪم اﻣﻜﺎﻧﻴﺔ اﺳﺘﺨﺪام ﺑﻌﺾ اﻟﺼﻔﺎﺋﺢ ﻓﻲ اﻟﺘﺠﺮﺑﺔ ﺑﺴ ﺒﺐ ﺿ ﻴﻖ اﻟﻤﺴ ﺎﺣﺔ :أﺧﺮى وﺗﺼﺤﺢ اﻟﻨﺘﺎﺋﺞ For the sheets & deflection: Depend on K with 30" ϕ base plate For K40"ϕ = 0.8 K30"ϕ K20"ϕ = 1.5 K30"ϕ 07-1 Evaluation of Strength for Subgrade Nov-2009 Lectures of Highway Engineering – Forth Stage By AASHTO class.: Clayey sand A-7 Æ K = 50 – 150 psi Gravel A-1 Æ K = 400 – 500 psi For soft subgrade: (( ﻗﻠﻴﻠﺔ ﺟﺪًا )ﺗﺮﺑﺔ ﺿﻌﻴﻔﺔK) إذا آﺎﻧﺖ Partial or full replacement with better soil, as granular material, with cohesive soil (more frictional resistance), or by soil stabilization. . أو اﺳﺘﺨﺪام ﺗﻘﻨﻴﺎت ﺗﺜﺒﻴﺖ اﻟﺘﺮﺑﺔ،(اﺳﺘﺒﺪال ﺟﺰﺋﻲ او آﻠﻲ ﺑﺘﺮﺑﺔ أﻓﻀﻞ )ﺧﻠﻂ اﻟﺘﺮﺑﺔ اﻟﻀﻌﻴﻔﺔ ﺑﺘﺮﺑﺔ ﻗﻮﻳﺔ 07-2 Evaluation of Strength for Subgrade Nov-2009 Lectures of Highway Engineering – Forth Stage 08-Thickness Design of Flexible Pavement: By different methods [due to: methods pf traffic analysis, failure definition (structural & users), evaluation of properties, & environmental effects]. 1) AASHO (AASHTO) Guide method. 2) T. A. I. method (The asphalt institute method). 3) N. C. S. A. (National Crushed Stone Association). AASHTO method: D1 D2 D3 D4 D or h = f (Wt18, ρt, S, & R) SN = f (S, R) Note: h (for each layer) > max. size of agg. * 2 Surface Leveling Base Subbase (C.B.R.) Subgrade (C.B.R.) Where: a) Wt18 = Equivalent (18kips) (≈8.2ton) single axle applications. Wt18 = f (axle type, axle load magnitude, ρt, design life, & SN) Wt18 = Σ T*A*F Where: T = Future trucks / Day / Direction = (Future ADT * %Truck * D.D) A = Axle / Truck F = Damage factor b) ρt = Terminal Serviceability: Lowest serviceability allowed at the end of design period before resurfacing or reconstruction. By: Arbitrary scale (named present serviceability index: 5 for best riding quality, and 0 for worst) ρt = 2.5 for main highway ρt = 2.0 for secondary highway 08-1 Thickness Design of Flexible Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage c) S = Road bed support value d) R = Regional factor e) SN = Structural number: Index number derived from analysis of traffic (Wt18), road bed support number (S), regional factor (R) [from monograph], which may be converted to thickness of various layers by using suitable layer coefficient. SN4 = a1 D1+a1' D2+a2 D3+a3 D4 SN3 = a1 D1+a1' D2+a2 D3 SN2 = a1 D1+a1' D2 SN1 = a1 D1 Surface Leveling Base Subbase Subgrade Subgrade SN3 = a1 D1+a2 D2+a3 D3 SN2 = a1 D1+a2 D2 SN1 = a1 D1 D1 Æ a1 D2 Æ a1' D3 Æ a2 D4 Æ a3 Surface Base Subbase D1 Æ a1 D2 Æ a2 D3 Æ a3 Subgrade Case (1) General Case (2) Ideal Arrangement (D1) ( ﻧﺠ ﺪP.514) ( ﻣ ﻦ اﻟﻤﺨﻄ ﻂa1)( وP.509) ( ﻣ ﻦ اﻟﻤﺨﻄﻄ ﺎتSN1) ( ﻧﺴﺘﺨﺮجD1) ( اﻟﻤﻄﻠﻮبSN1 = a1 D1) :ﻣﻼﺣﻈﺔ .(0.5") ﺑﺎﻻﻧﺞ وﻳﻘﺮب ﻷﻗﺮب ﻧﺼﻒ For case (1) General: a1 = Layer coefficient for Surface D1 = Thickness of Surface (inch) a2 = Layer coefficient for Base D2 = Thickness of Base (inch) a3 = Layer coefficient for Subbase D3 = Thickness of Subbase (inch) Design monographs and tables: Yoder (Table 4.9 P.164, 165), (Fig. 15.1 P.509), (Table 15.1 P.510), (Fig. 15.3 P.514, 515), (Fig. 15.5 P.516) 08-2 Thickness Design of Flexible Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage Ex.: A main rural highway has been built or designed for (200) daily 18-kips single axle load repetition. Regional factor (R) = 1.2 & the characteristics of pavement materials as following: Subgrade Æ C. B. R. = 5% (Plastic clay) Subbase Æ C. B. R. = 20% (Sand-gravel) Base Æ C. B. R. = 80% (Crushed stone) Surface Æ E = 4.3*105psi (Asphalt concrete) Sol.: From graph (P.514, 515) Surface a1 = 0.42 (Modulus E = 4.3) Base a2 = 0.13 (C. B. R. = 80%) Subbase a3 = 0.095 (C. B. R. = 20%) SN1 = a1 D1 Wt18 = 200 From graph (P.516) ( ﻟﻠﻄﺒﻘﺔ اﻟﺘﻲ ﻗﺒﻠﻬﺎC. B. R.) ﻗﻴﻢ S1 (@ 80% C.B.R.) = 8.5 Æ SN1 = 1.95 S2 (@ 20% C.B.R.) = 6.2 Æ SN2 = 2.82 S3 (@ 5% C.B.R.) = 4 Æ SN3 = 3.78 SN1 = a1 D1 1.95 = 0.42*D1 Æ D1 = 4.64" use D1 = 5" Æ D2 = 5.54" use D2 = 6" Æ D3 = 9.47" use D3 = 9.5" SN2 = a1 D1 + a2 D2 2.82 = 0.42*5 + 0.13*D2 SN3 = a1 D1 + a2 D2 + a3 D3 3.78 = 0.42*5 + 0.13*6 + 0.045*D3 08-3 Thickness Design of Flexible Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage H.W.: Secondary highway, ADT (1994) = 400vph, truck = 40%, D. D. = 50%, annual rate of traffic growth = 6%, design life = 20 years, wet (saturated road bed). Truck type: 40Kips 13Kips Materials Properties Asphalt concrete wearing course M. S. ≥ 800 kg Asphalt concrete leveling course M. S. ≥ 700 kg Crushed stone base C. B. R. 80 % Subbase C. B. R. 30 % Subgrade C. B. R. 2% Determine thickness of layers in (cm) Note: let D1 = 8 cm Ans.: D1 = 8cm (3"), D2 = 11cm (4.5"), D3 = 12cm (5"), D4 = 57cm (22.5") 1kg = 2.20462 lb 08-4 Thickness Design of Flexible Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage (Yoder, Fig. 15.3, P.515) 08-5 Thickness Design of Flexible Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage (Yoder, Fig. 15.3, P.515) 08-6 Thickness Design of Flexible Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage Regional Factor (Yoder, Table 15.1, P.510) Condition Roadbed materials frozen to depth of 5in or more Roadbed materials dry, summer and fall Roadbed materials wet, spring thaw R value 0.2 – 1.0 0.3 – 1.5 4.0 – 5.0 (Yoder, Fig. 15.5, P.516) 08-7 Thickness Design of Flexible Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage (Yoder, Fig. 15.5, P.517) 08-8 Thickness Design of Flexible Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage (Yoder, Fig. 15.1, P.509) 08-9 Thickness Design of Flexible Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage Table 4.9 AASHO Equivalence Factors – Flexible Pavement (Yoder, P.164) Single Axle, ρt = 2.0 Axle Load (kips) 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 1 0.0002 0.002 0.01 0.03 0.08 0.16 0.32 0.59 1.00 1.61 2.49 3.71 5.36 7.54 10.38 14.00 18.55 24.20 31.14 39.57 2 0.0002 0.003 0.01 0.04 0.08 0.18 0.34 0.60 1.00 1.59 2.44 3.62 5.21 7.31 10.03 13.51 17.87 23.30 29.95 38.02 Structural Number, SN 3 4 0.0002 0.0002 0.002 0.002 0.01 0.01 0.04 0.03 0.09 0.08 0.19 0.18 0.35 0.35 0.61 0.61 1.00 1.00 1.56 1.55 2.35 2.31 3.43 3.33 4.88 4.68 6.78 6.42 9.24 8.65 12.37 11.46 16.30 14.97 21.16 19.28 27.12 24.55 34.34 30.92 5 0.0002 0.002 0.01 0.03 0.08 0.17 0.34 0.60 1.00 1.57 2.35 3.40 4.77 6.52 8.73 11.48 14.87 19.02 24.03 30.04 6 0.0002 0.002 0.01 0.03 0.08 0.17 0.33 0.60 1.00 1.60 2.41 3.51 4.96 6.83 9.17 12.17 15.63 19.93 25.10 31.25 Tandem Axle, ρt = 2.0 Axle Load (kips) 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 1 0.01 0.01 0.02 0.04 0.07 0.10 0.16 0.23 0.32 0.45 0.61 0.81 1.06 1.38 1.76 2.22 2.77 3.42 4.20 5.10 2 0.01 0.02 0.03 0.05 0.08 0.12 0.17 0.24 0.34 0.46 0.62 0.82 1.07 1.38 1.75 2.19 2.73 3.36 4.11 4.98 Structural Number, SN 3 4 0.01 0.01 0.02 0.01 0.03 0.03 0.05 0.05 0.08 0.08 0.12 0.12 0.18 0.17 0.26 0.25 0.36 0.35 0.49 0.48 0.65 0.64 0.84 0.84 1.08 1.08 1.38 1.38 1.73 1.72 2.15 2.13 2.64 2.62 3.23 3.18 3.92 3.83 4.72 4.58 08-10 5 0.01 0.01 0.02 0.04 0.07 0.11 0.16 0.24 0.34 0.47 0.63 0.83 1.08 1.38 1.73 2.16 2.66 3.24 3.91 4.68 6 0.01 0.01 0.02 0.04 0.07 0.10 0.16 0.23 0.33 0.46 0.62 0.82 1.07 1.38 1.74 2.18 2.70 3.31 4.02 4.83 Thickness Design of Flexible Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage Table 4.9 (Continued) (Yoder, P.165) Single Axle, ρt = 2.5 Axle Load (kips) 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 1 0.0004 0.003 0.01 0.03 0.08 0.17 0.33 0.59 1.00 2.61 2.48 3.69 5.33 7.49 10.31 13.90 18.41 24.02 30.90 39.26 2 0.0004 0.004 0.02 0.05 0.10 0.20 0.36 0.61 1.00 1.57 2.38 3.49 4.99 6.98 9.55 12.82 16.94 22.04 28.30 35.89 Structural Number, SN 3 4 0.0003 0.0002 0.004 0.004 0.02 0.01 0.05 0.04 0.12 0.10 0.23 0.21 0.40 0.39 0.65 0.65 1.00 1.00 1.49 1.47 2.17 2.09 3.09 2.89 4.31 3.91 5.90 5.21 7.94 6.83 10.52 8.85 13.74 11.34 17.73 14.38 22.61 18.06 28.51 22.50 5 0.0002 0.003 0.01 0.03 0.09 0.19 0.36 0.62 1.00 1.51 2.18 3.03 4.09 5.39 6.97 8.88 11.18 13.93 17.20 21.08 6 0.0002 0.002 0.01 0.03 0.08 0.18 0.34 0.61 1.00 1.55 2.30 3.27 4.48 5.98 7.79 9.95 12.51 15.50 18.98 23.04 Tandem Axle, ρt = 2.5 Axle Load (kips) 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 1 0.01 0.02 0.03 0.04 0.07 0.11 0.16 0.23 0.33 0.45 0.61 0.81 1.06 1.38 1.75 2.21 2.76 3.41 4.18 5.08 2 0.01 0.02 0.04 0.07 0.10 0.14 0.20 0.27 0.37 0.49 0.65 0.84 1.08 1.38 1.73 2.16 2.67 3.27 3.98 4.80 Structural Number, SN 3 4 0.01 0.01 0.02 0.02 0.04 0.03 0.07 0.06 0.11 0.09 0.16 0.14 0.23 0.21 0.31 0.29 0.42 0.40 0.55 0.53 0.70 0.70 0.89 0.89 1.11 1.11 1.38 1.38 1.69 1.68 2.06 2.03 2.49 2.43 2.99 2.88 3.58 3.40 4.25 3.98 08-11 5 0.01 0.01 0.03 0.05 0.08 0.12 0.18 0.26 0.36 0.50 0.66 0.86 1.09 1.38 1.70 2.08 2.51 3.00 3.55 4.17 6 0.01 0.01 0.02 0.04 0.07 0.11 0.17 0.24 0.34 0.47 0.63 0.83 1.08 1.38 1.73 2.14 2.61 3.16 3.79 4.49 Thickness Design of Flexible Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage 09-Rigid Pavement: Joints Concrete slab Concrete slab Base (or Subbase) Function of Base (or Subbase): 1) Drainage purpose Subgrade 2) Reduce the effect of subgrade volume change on concrete layer 3) Prevent pumping of fines through joints & edges 4) Increase "K" modulus of subgrade reaction Rigid Pavement Characteristics: - Can resist unlimited loading - Minor defects are not reflected. - More skid resistance, safe. - More economical for same projects at certain location. - Concrete layer is less thickness than other layers. Rigid Pavement Types: a) Plain concrete pavement: 1. No reinforcement except of using tie bars (for longitudinal joints) 2. Closer spacing between contractions joint (as transverse joints) Longitudinal Joints Transverse Joints Inclined Joints 3. Inclined joints may be used (for better load transfer) 4. Very limited use b) Simply reinforced concrete pavement: 1. Temperature (wire-mesh, B. R. C.) reinforcement between joints to control cracking (close to the upper surface) 2. Dowel bars across transverse joints 09-1 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage 3. Tie bars across longitudinal joints to control warping 4. Wider spacing between joints (from 3-6m to 12-14m) Longitudinal Joints Transverse Joints 5. Widely used Section c) Continuously reinforced concrete pavement: 1. No joints except some expansion joints & may be some contraction joints 2. Heavy reinforcement (≈ > 0.6% of cross sectional area) 3. High cost 4. Used in very-weak subgrade & high traffic load d) Pre-stressed concrete pavement: 1. Fewer joints 2. More expensive Type of Joints in Rigid Pavement: 1) Contraction joints: to relieve excessive tensile stress due to drop in temperature. واﻟﻨﺎﺗﺠﺔ ﻣﻦ اﻻﺣﺘﻜﺎك ﺑ ﻴﻦ اﻟﺒﻼﻃ ﺔ، ﻟﻠﺘﺨﻠﺺ ﻣﻦ اﺟﻬﺎدات اﻟﺸﺪ اﻟﻨﺎﺗﺠﺔ ﻣﻦ اﻧﺨﻔﺎض درﺟﺔ اﻟﺤﺮارة:ﻣﻔﺎﺻﻞ اﻟﺸﺪ . واﻟﺘﻲ ﺗﺴﺒﺐ ﻓﺸﻞ اﻟﻄﺒﻘﺔ،(Subgrade) واﻟﺘﺮﺑﺔ ﺗﺤﺘﻬﺎ ﺗﻘﻠﺺ ﻗﻮى اﺣﺘﻜﺎك واﻷﺧ ﺪود، ﻟﻤﻨﻊ ﺗﺄآﺴﺪ ﺣﺪﻳﺪ اﻟﺘﺴﻠﻴﺢ وﺗﺄﺛﺮ ﻃﺒﻘﺔ اﻟﺘﺮﺑﺔ،وﺗﻌﺎﻟﺞ ﺑﻌﻤﻞ أﺧﺪود ﻳﻤﻸ ﺑﺎﻟﻤﺎﺳﺘﻚ ﻟﻤﻨﻊ اﻟﻤﻴﺎﻩ ﻣﻦ اﻟﻤﺮور .ﻳﺼﻨﻊ ﻣﻨﻄﻘﺔ ﺿﻌﻴﻔﺔ ﻟﺘﺤﺪﻳﺪ ﻣﺴﺎر اﻟﻔﺸﻞ 3/8" B.R.C. d/4 d d/2 Fixed Dowel bars 1/2"-3/4" ϕ, 12-24" length, & 12-18" spacing (For load transfer) Free 09-2 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage B. R. C. Design: ( ﻓ ﻲ اﻟﺠ ﺰء اﻷﻋﻠ ﻰ ﻣ ﻦ ﻃﺒﻘ ﺔ اﻟﺘﺒﻠ ﻴﻂ ﻟﻤﻘﺎوﻣ ﺔ اﺟﻬ ﺎدات اﻟﺸ ﺪB.R.C.) ﺗﻮﺿ ﻊ ﻃﺒﻘ ﺔ ﻣ ﻦ اﻟﺘﺴ ﻠﻴﺢ وﺗﻜ ﻮن ﻟﻄﺒﻘ ﺔ اﻟﺘﺒﻠ ﻴﻂ ﺑ ﻴﻦ اﻟﻤﻔﺎﺻ ﻞ )ﻋﻠ ﻰ ﺟ ﺎﻧﺒﻲ،( اﻟﻤﺘﻮﻟﺪة ﺑﺴﺒﺐ ﺗﻐﻴﺮ ﺗﺪرﺟﺎت اﻟﺤ ﺮارةTensile stresses) : وأﺳﻠﻮب ﺣﺴﺎب آﻤﻴﺔ اﻟﺘﺴﻠﻴﺢ آﻤﺎ ﻳﺄﺗﻲ،(اﻷﺧﺪود L Edge b d joint joint Edge 1ft C L = Allowable spacing for contraction joint (for longitudinal reinforcement), (ft) b = Slab width, (ft) C = Coefficient of friction (1 – 2 use 1.5) γ = Unit wt. of concrete (pcf) d = Slab thickness (ft) Friction resistance = Allowable tensile strength Friction resistance = Concrete tensile strength + Steel tensile strength (L/2 * b * d)* γ * C = b * d * ftc + As * fs For one unit of width use b =1ft For safety assume concrete tensile strength (b * d * ftc) = 0 ftc = Allowable tensile strength of concrete ≈ 400 psi fs = Allowable tensile strength of steel ≈ 25000 psi As = Area of steel (in2/ft) W=d*γ where: W = Weight of 1ft2 of slab L/2 * 1 * W * C = As * fs As = L*W *C 2FS ( ﺗﻜ ﻮن اﻟﻤﺴ ﺎﻓﺔ ﺑ ﻴﻦL) أﻣ ﺎ ﻟﻠﺘﺴ ﻠﻴﺢ ﺑﺎﻻﺗﺠ ﺎﻩ اﻟﻌﺮﺿ ﻲ،( ﺗﻜﻮن اﻟﻤﺴﺎﻓﺔ ﺑﻴﻦ ﻣﻔﺼ ﻠﻴﻦL) ﻟﻠﺘﺴﻠﻴﺢ ﺑﺎﻻﺗﺠﺎﻩ اﻟﻄﻮﻟﻲ .(b) ( أيedge to edge) ﺣﺎﻓﺘﻲ اﻟﻄﺮﻳﻖ 09-3 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage 2) Expansion Joints: provide a clear spacing along the depth to relieve excessive compressive stresses due to rise in temperature. ﻓﺎﻟﻤﻌﺎﻟﺠﺔ ﺑﻌﻤﻞ أﺧﺪود أو ﻓﺮاغ ﻋﻠﻰ ﻋﻤﻖ ﻃﺒﻘ ﺔ اﻟﺘﺒﻠ ﻴﻂ ﻟﻤﻨ ﻊ، ارﺗﻔﺎع درﺟﺔ اﻟﺤﺮارة ﺗﺴﺒﺐ اﻟﺘﻤﺪد:ﻣﻔﺎﺻﻞ اﻟﺘﻤﺪد .إﺟﻬﺎدات اﻻﻧﻀﻐﺎط 3/4" d/4 d d/2 Fixed Free Dowel bar - Difficult in construction & maintenance - Needed when casting in cold season, near structure, & for materials with high coefficient of thermal expansion - Contraction joints used as expansion joints 3) Warping joints: to relieve tensile stresses due to warping because of difference in temperature between top and bottom of the slab (in night & day). 3/8" T Keyed C d/4 d d/2 Fixed Tie bar 1/2"ϕ, 30-36" length, & 24-30" spacing Fixed Night C T Day 4) Construction joints: in some conditions. .( وﻳﺴﺘﺨﺪم ﻓﻲ ﺑﻌﺾ اﻟﺤﺎﻻت )ﻣﺜﻞ ﻧﻬﺎﻳﺔ وﺟﺒﺔ ﻋﻤﻞ وﺑﺪاﻳﺔ وﺟﺒﺔ أﺧﺮى:ﻣﻔﺼﻞ إﻧﺸﺎﺋﻲ Fixed Free 09-4 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage Thickness Design of Rigid Pavement: Design methods: 1) PCA method (Portland Cement Association) 2) AASHO (AASHTO) guide method 1) PCA method: depends on fatigue analysis under repeated loading. h = f (axle type, axle load magnitude, No. of repetitions, M. R. (fr), & K) where: h = thickness of concrete layer Design steps: a) Analysis of traffic: Nact.: Actual No. of repetitions in 40-years period for each axle load. Axles ≥ 16 kips – Single ( وﻣﻔﺮدة ﺗﻬﻤﻞ16 )اﻟﻤﺤﺎور أﻗﻞ ﻣﻦ Axles ≥ 30 kips – Tandem ( وﻣﺰدوﺟﺔ ﺗﻬﻤﻞ30 )اﻟﻤﺤﺎور أﻗﻞ ﻣﻦ Nact. = T * A * 40 * 365 Where: T = Future truck per day per direction A = No. of axles per truck for certain axle load b) Correction for impact: Static axle load * 1.2 = corrected (dynamic) axle load c) M. R. (fr): Modulus of rupture (for third-point loading) (psi) σ= M.C I P Where: M= b d b.d 3 P.L d , C= , I= 6 2 12 P.L ∴ M.R. = 2 b.d L/3 09-5 L/3 L/3 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage M.R. = 8 − 10 f c = 600 – 750 psi Where: fc = Compression strength of concrete (psi) d) K: Modulus of subgrade reaction e) S: Actual load stress in pavement Determine form design charts from either single or tandem axle, depend on: - Corrected axle load - K – value - Suggested thickness of concrete layer "d" f) SR: Stress ratio SR = S , for each axle load M.R. g) Nall.: Allowable No. of repetitions of each axle load to account for fatigue in concrete pavement (depend on stress ratio SR) Note: Unlimited repetitions for SR = 0.5 or less Æ ∞ vehicles h) F: Fatigue percentage F= N act. *100% , for each axle load N all. i) Σ F < 100%, for correct assumption of "d" value ." وإﻋﺎدة اﻟﺘﺼﻤﻴﻢd" ( ﻓﻴﺠﺐ ﺗﻜﺒﻴﺮΣF ≥ 100%) إذا آﺎﻧﺖ ،"d" ( ﻓﺘﺒﻘﻰΣF ≤ 85%) إذا آﺎﻧﺖ .( وإﻋﺎدة اﻟﺘﺼﻤﻴﻢ1-0.5") " ﺑﻤﻘﺪارd" ( ﻓﺎﻟﺘﺼﻤﻴﻢ ﻏﻴﺮ اﻗﺘﺼﺎدي أي ﻧﻘﻠﻞ85%) أﻣﺎ إذا آﺎﻧﺖ أﻗﻞ ﻣﻦ Design monographs and tables: Yoder (Fig. 17.2, 17.3, P.604, 605), (Table 17.1, P.603) 09-6 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage Ex.: T = 60 trucks/day/dir, K = 150 psi, & M. R. = 650 psi Axle type Axle load A' (kips) (No. of axles/100 trucks) Tandem 45 0.1 43 0.1 41 0.1 39 1.0 37 0.9 35 1.4 33 1.8 31 9.4 Single 21 3.2 19 5.4 17 6.1 Find concrete layer thickness "d" using P.C.A. method? Sol.: Nact. = 60*(A'/100)*40*365 …(1) Corrected axle load = 1.2*axle load …(2) …(3) S 650 N act. F= *100% N all. SR = …(4) Assume d = 7" (1) Axle type (2) Axle load Tandem 45 43 41 39 37 35 33 31 21 19 17 Single (3) A' (No. of axles/ 100 trucks) 0.1 0.1 0.1 1.0 0.9 1.4 1.8 9.4 3.2 5.4 6.1 (4) Nact. (3)+eq.(1) 876 876 876 8760 7884 12250 15800 82400 28100 47400 53500 (5) Corrected axle load (2)+eq.(2) 54 51.6 49.2 46.8 44.4 42.8 39.6 37.6 25.2 22.8 20.1 (6) S (7) SR (8) Nall. (9) F (%) Graph+(5)+K+d 435 415 410 390 375 350 325 310 350 325 290 (6)+eq.(3) 0.67 0.64 0.63 0.60 0.58 0.54 0.50 0.48 0.54 0.50 0.45 (7)+table 4500 11000 14000 32000 57000 180000 ∞ ∞ 180000 ∞ ∞ ΣF (4)+(8)+eq.(4) 19 8 6 27 14 7 0 0 15 0 0 96% ΣF(%) = 96% < 100% ∴ d = 7" OK 09-7 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage 2) AASHTO method: d (slab thickness) = f (ρt, No. of Wt18, K, & working stresses in concrete) a) ρt: Terminal level of serviceability 2.5 for main highway 2.0 for secondary highway b) No. of Wt18: No. repetitions of 18-kips single axle load as: Wt18 = f (axle type, effective axle load, ρt, design life, assumed "d") c) K: Modulus of subgrade reaction (pci) d) Working stress in concrete = M. R. * 0.75 ( ﻣﻦ اﻟﻤﻔﺮوض ﺗﻌﺎد ﻋﻤﻠﻴﺔ اﻟﺘﺼﻤﻴﻢ0.5") اﻟﻤﺴﺘﺨﺮﺟﺔ ﺑﻤﻘﺪار أﻗﻞ أو أآﺒﺮ ﻣﻦd إذا آﺎﻧﺖ Design monographs and tables: Yoder (Fig. 17.4, 17.5, P.608), (Table 4.10, P.166, 167) Ex.: T = 60 trucks/day/dir, K = 150 psi, & M. R. = 650 psi Axle type Axle load A' (kips) (No. of axles/100 trucks) Tandem 45 0.1 43 0.1 41 0.1 39 1.0 37 0.9 35 1.4 33 1.8 31 9.4 Single 21 3.2 19 5.4 17 6.1 Find concrete layer thickness "d" using AASHTO method? (assume ρt = 2.5) 09-8 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage Sol.: Nact. = 60*(A'/100)*40*365 …(1) Corrected axle load = 1.2*axle load …(2) Assume d = 7" (1) Axle type (2) Axle load Tandem 45 43 41 39 37 35 33 31 21 19 17 Single (3) A' (No. of axles/ 100 trucks) 0.1 0.1 0.1 1.0 0.9 1.4 1.8 9.4 3.2 5.4 6.1 (4) Nact. (3)+eq.(1) (5) Corrected axle load (2)+eq.(2) (6) Equivalent factor (5)+Table (7) No. of Wt18 (4)*(6) 876 876 876 8760 7884 12250 15800 82400 28100 47400 53500 54 51.6 49.2 46.8 44.4 42.8 39.6 37.6 25.2 22.8 20.1 10.61 9.23 7.85 6.47 5.21 4.16 3.296 2.588 3.796 2.56 1.65 ΣWt18 9294.4 8085.5 6876.6 56677.2 41075.6 50960 52076.8 213251.2 10666.6 12134.0 88596 559694 psi ΣWt18 ≈ 560 ksi Working stress = 0.75 * 650 = 487.5 psi & K = 150 psi From monograph: d = 6.25" < dassumed (with more than 0.5") Not OK check (redesign) with d = 6.5" 09-9 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage Table 17.1. Stress Ratios Allowable Load Repetitions Yoder, P.603 Stress Allowable Ratio Repetition SR Nall (Veh.) 0.51 400,000 0.52 300,000 0.53 240,000 0.54 180,000 0.55 130,000 0.56 100,000 0.57 75,000 0.58 57,000 0.59 42,000 0.60 32,000 0.61 24,000 0.62 18,000 0.63 14,000 0.64 11,000 0.65 8,000 0.66 6,000 0.67 4,500 0.68 3,500 0.69 2,500 0.70 2,000 0.71 1,500 0.72 1,100 0.73 850 0.74 650 0.75 490 0.76 360 0.77 270 0.78 210 0.79 160 0.80 120 0.81 90 0.82 70 0.83 50 0.84 40 0.85 30 NOTE: Unlimited Repetition for SR = 0.5 or less Figure 17.2, Yoder, P.604 d = (7 – 9) in Charts and Tables for Rigid Pavement Thickness Design by PCA Method Figure 17.3, Yoder, P.605 09-10 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage Table 4.10 AASHO Equivalence Factors – Rigid Pavement (Yoder, P.166) Single Axle, ρt = 2.0 Axle Load (kips) 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 6 0.0002 0.002 0.01 0.03 0.09 0.19 0.35 0.61 1.00 1.55 2.32 3.37 4.76 6.59 8.92 11.87 15.55 20.07 25.56 32.18 7 0.0002 0.002 0.01 0.03 0.08 0.18 0.35 0.61 1.00 1.56 2.32 3.34 4.69 6.44 8.68 11.49 15.00 19.30 24.54 30.85 D – Slab Thickness (in) 8 9 0.0002 0.0002 0.002 0.002 0.01 0.01 0.03 0.03 0.08 0.08 0.18 0.18 0.34 0.34 0.60 0.60 1.00 1.00 1.57 1.58 2.35 2.38 3.40 3.47 4.77 4.88 6.52 6.70 8.74 8.98 11.51 11.82 14.95 15.30 19.16 19.53 24.26 24.63 30.41 30.75 10 0.0002 0.002 0.01 0.03 0.08 0.17 0.34 0.60 1.00 1.58 2.40 3.51 4.97 6.85 9.23 12.17 15.78 20.14 25.36 31.58 11 0.0002 0.002 0.01 0.03 0.08 0.17 0.34 0.60 1.00 1.59 2.41 3.53 5.02 6.94 9.39 12.44 16.18 20.71 26.14 32.57 10 0.01 0.03 0.05 0.08 0.13 0.20 0.30 0.44 0.62 0.85 1.14 1.51 1.96 2.51 3.17 3.95 4.87 5.95 7.20 8.63 11 0.01 0.03 0.05 0.08 0.13 0.20 0.30 0.44 0.62 0.85 1.14 1.51 1.97 2.52 3.19 3.98 4.93 6.03 7.31 8.79 Tandem Axle, ρt = 2.0 Axle Load (kips) 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 6 0.01 0.03 0.05 0.09 0.14 0.22 0.32 0.45 0.63 0.85 1.13 1.48 1.91 2.42 3.04 3.79 4.67 5.72 6.94 8.36 7 0.01 0.03 0.05 0.08 0.14 0.21 0.31 0.45 0.64 0.85 1.13 1.45 1.90 2.41 3.02 3.74 4.59 5.59 6.76 8.12 D – Slab Thickness (in) 8 9 0.01 0.01 0.03 0.03 0.05 0.05 0.08 0.08 0.13 0.13 0.21 0.20 0.31 0.30 0.44 0.44 0.62 0.62 0.85 0.85 1.14 1.14 1.49 1.50 1.93 1.95 2.45 2.49 3.07 3.13 3.80 3.89 4.66 4.78 5.67 5.82 6.83 7.02 8.17 8.40 09-11 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage Table 4.10 (Continued) (Yoder, P.167) Single Axle, ρt = 2.5 Axle Load (kips) 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 6 0.0002 0.003 0.01 0.04 0.10 0.20 0.38 0.63 1.00 1.51 2.21 3.16 4.41 6.05 8.16 10.81 14.12 18.20 23.15 29.11 7 0.0002 0.002 0.01 0.04 0.09 0.19 0.36 0.62 1.00 1.52 2.20 3.10 4.26 5.76 7.67 10.06 13.04 16.69 21.14 26.49 D – Slab Thickness (in) 8 9 0.0002 0.0002 0.002 0.002 0.01 0.01 0.03 0.03 0.08 0.08 0.18 0.18 0.35 0.34 0.61 0.60 1.00 1.00 1.55 1.57 2.28 2.34 3.23 3.36 4.42 4.67 5.92 6.29 7.79 8.28 10.10 10.70 12.94 13.62 16.41 17.12 20.61 21.31 25.65 26.29 10 0.0002 0.002 0.01 0.03 0.08 0.18 0.34 0.60 1.00 1.58 2.38 3.45 4.85 6.61 8.79 11.43 14.59 18.33 22.74 27.91 11 0.0002 0.002 0.01 0.03 0.08 0.17 0.34 0.60 1.00 1.58 2.40 3.50 4.95 6.81 9.14 11.99 15.43 19.52 24.31 29.90 10 0.01 0.03 0.05 0.08 0.13 0.20 0.30 0.44 0.62 0.85 1.14 1.50 1.95 2.48 3.12 3.87 4.74 5.75 6.90 8.21 11 0.01 0.03 0.05 0.08 0.13 0.20 0.30 0.44 0.62 0.85 1.14 1.51 1.96 2.51 3.16 3.94 4.86 5.92 7.14 8.55 Tandem Axle, ρt = 2.5 Axle Load (kips) 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 6 0.01 0.03 0.06 0.10 0.16 0.23 0.34 0.48 0.64 0.85 1.11 1.43 1.82 2.29 2.85 3.52 4.32 5.26 6.36 7.64 7 0.01 0.03 0.05 0.09 0.14 0.22 0.32 0.46 0.64 0.85 1.12 1.44 1.82 2.27 2.80 3.42 4.16 5.01 6.01 7.16 D – Slab Thickness (in) 8 9 0.01 0.01 0.03 0.03 0.05 0.05 0.08 0.08 0.14 0.13 0.21 0.21 0.31 0.31 0.45 0.44 0.63 0.62 0.85 0.85 1.13 1.14 1.47 1.49 1.87 1.92 2.35 2.43 2.91 3.04 3.55 3.74 4.30 4.55 5.16 5.48 6.14 6.53 7.27 7.73 09-12 Rigid Pavement Nov-2009 Lectures of Highway Engineering – Forth Stage 09-13 Rigid Pavement Apr-10 Lectures of Highway Engineering – Forth Stage 10-The Effect of type and amount of Filler on Asphalt Paving Mix First: The role of the filler in the mix is very complex: 1. Serves as an inertic materials in the mix. 2. Serves as an active materials in the mix. (due to its fineness and surface characteristics). a. Specific Surface (S.S.) (m2/kg). b. Surface Activity (S.A.) (Shape Factor). c. Absorption. * F/A (filler/Asphalt) ratio should be decreased as S.S. increases. * S.A.: Capacity of filler particles to absorb AC. And it increases as the irregularity increases (roughness and angularity) * More absorption è decrease in free AC. Second: 1. Behavior of filler/AC (mastic) and asphalt paving mixture can be explained by physical-chemical properties of filler at the filler-AC interface. 2. H.L. (Hydrated Lime) have the highest geometric irregularity and high surface activity è higher consistency (low penetration, high softening point, low ductility) for mastics and higher strength in mix. 3. Rapid deterioration of mix occurred with non-active filler (after 4 days of immersion at 60oC water) and H.L. Exhibits a superior durability potential with mix sensitivity to the immersion periods (as an active filler). [by E. Marshall St. Loss%, H.L. 5%, LSD (Limestone Dust) (15%)] 4. The use of Portland cement as filler increase the fatigue life of the mix. 10-1 The Effect of type and amount of Filler on Asphalt Paving Mix Apr-10 Lectures of Highway Engineering – Forth Stage Third: 1. The type and amount of filler used in asphalt paving mix is are of the most important factor that influence distress. (permanent deformation, low temp. cracking, fatigue cracking, and moisture damage). 2. Limestone dust (L.D.) (3, 5, 7)%, Hydrated Lime (H.L.) (5%), Cement (C.I.) (5%). - Marshall Stiffness = Stability / Flow (kg/mm) (Sp. 4"x2.5") - Compressive Strength = Max load / Cross-Section Area (kg/cm2) (Sp. 4"x4") - Indirect tensile strength = 2. Pu (kg/cm2) π.t.D 3. There is an optimum filler content for every type, satisfying most of asphalt paving mixture requirements for (strength, durability, workability). Shape Factor = 2.30 à H.L. (sp=2.30) à S.S. = 750m2/kg Shape Factor = 1.30 à L.D. (sp=2.88) à S.S. = 260m2/kg C.I. (sp=3.10) 10-2 The Effect of type and amount of Filler on Asphalt Paving Mix Lectures of Highway Engineering – Forth Stage 10-3 Apr-10 The Effect of type and amount of Filler on Asphalt Paving Mix