13-56 13-76 Two mass streams of two different ideal gases are mixed in a steady-flow chamber while receiving energy by heat transfer from the surroundings. Expressions for the final temperature and the exit volume flow rate are to be obtained and two special cases are to be evaluated. Assumptions Kinetic and potential energy changes are negligible. Analysis (a) Mass and Energy Balances for the mixing process: m 1 m 2 m 3 m 1h1 m 2 h2 Q in m 3h3 1 Steady-flow chamber h C PT 2 m 1CP , 1T1 m 2CP , 2T2 Q in m 3CP , mT3 CP , m T3 Q in m 1 m CP , 1 2 CP , 2 m 3 m 3 m 1CP , 1 m 3CP , m T1 m 2CP , 2 m 3CP , m 3 Surroundings T2 Q in m 3CP , m (b) The expression for the exit volume flow rate is obtained as follows: RT V3 m 3v3 m 3 3 3 P3 m 1CP , 1 m 2CP , 2 Q in T1 T2 m 3CP , m m 3CP , m m 3CP , m CP , 1 R3 m 1 R1T1 CP , 2 R3 m 2 R2T2 R3Q in V3 CP , m R1 P3 CP , m R2 P3 P3CP , m m R V3 3 3 P3 P3 P1 P2 CP , 1 R3 CP , 2 R3 R Q V3 V1 V2 3 in CP , m R1 CP , m R2 P3CP , m R3 Ru M 1 M 1 R3 M 2 , R1 M 3 Ru M 3 R2 M 3 CP , 1M 1 CP , 2 M 2 Ru Q in V3 V1 V2 CP , m M 3 CP , m M 3 P3 M 3CP , m R Ru , M The mixture molar mass M3 is found as follows: M 3 yi M i , (c) For adiabatic mixing V3 CP , 1M 1 CP , m M 3 yi m fi / M i m fi / Mi , m fi m i m i Q in is zero, and the mixture volume flow rate becomes V1 CP , 2 M 2 CP , m M 3 V2 (d) When adiabatically mixing the same two ideal gases, the mixture volume flow rate becomes M 3 M1 M 2 CP ,3 CP ,1 CP , 2 V3 V1 V2 PROPRIETARY MATERIAL. © 2011 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission.