# Pre-Calculus: Algebra I and Algebra II Review Name: Day 1

```Pre-Calculus: Algebra I and Algebra II Review
Day 1
(Don’t forget to show work where necessary)
Answers without work = no credit
Write the expression using exponents:
1. (-7)(-7)(-7)(-7)
2. (2x  2x  2x) + 5
3. 2 to the nth power
Evaluate the expression:
4. (-4) 2
5. - 2 4
6. 24  (1  1) 4  4
7. 1  (5 2  10)  5
Evaluate the expression for the given value of x:
8. 3 x 2  2 x when x = -2
9. 2 x 2  (4  2 x)  2 when x = 4
 1 
10. 7  x 3   when x = -2
 2x 
Evaluate the expression for the given values of x and y
11. x 2  2y 2 when x=3, y=2
Solve the equation and check your solution
12. 3 – x = 2
13. -14 + 2x = 6
14. &frac12; x + 1 = 13
15. x + 6 = 3(3 – x)
16.
1
(14 x  2)  3(2  3 x)
2
Name:
Substitute the given value of x into the equation. Then solve the equation
for y:
17. 7x – 3y = 6 when x = 3
Solve the formula for the indicated variable:
18. Solve for c: P = a + b + c
19. Solve for h: S = 2πrh
20. Solve for b1 : A = &frac12; (b1 + b2)h
Graph the solution of the inequality on a number line
21. 0 &lt; x &lt; 3
22. x &lt; -2 or x &gt; 1
Solve the inequality and graph the solution on a number line
23. x – 5 &gt; 9
24. -3x + 7 &lt; -8
25. 2 &lt; x + 3 &lt; 5
Solve the absolute value equation or inequality and check the solutions
(remember you need to consider both positive and negative values):
26. |x – 3| = 5
27. |2x + 6| = 12
28. |3x – 3| = 8
29. |x – 3| &lt; 8
30. |2x – 3| &gt; 5
```