Available at http://pvamu.edu/aam Appl. Appl. Math. ISSN: 1932-9466 Applications and Applied Mathematics: An International Journal (AAM) Vol. 6, Issue 1 (June 2011) pp. 353 - 368 (Previously, Vol. 6, Issue 11, pp. 1543 – 1553) Multidimensional Inverse Boundary Value Problem for a System of Hyperbolic Equations M. A. Guliev and A.M. El-Hadidi Baku State University Baku, Azerbaijan mahsoup79@yahoo.com Received: February 10, 2011; Accepted: April 1, 2011 Abstract In the paper we investigate the solvability of the inverse multidimensional boundary value problem for the system of hyperbolic type equations. A method is proposed to reduce the considered problem to some non infinite system of differential equations. The proposed method allows one to prove the existence and uniqueness theorems for the multidimensional inverse boundary value problems in the class of the functions with bounded smoothness. Keywords: Boundary Value Problem; Multidimensional System; Hyperbolic Equations; existence and uniqueness theorems MSC (2010) No.: 35A05; 31A25; 35L20 1. Introduction The solution of various problems of physics is often necessary for restoration of the basic characteristics of a studied phenomenon or process, if you know the mathematical formulation of the problem. These characteristics are coefficients or unknowns in the right side of the 353 354 M.A. Guliev and A.M. El-Hadidi differential equation, which can determine under some additional information, are called inverse problems. In the last twenty - thirty years, the theory of inverse problems has been enriched by considering the problem of determining the coefficients of partial differential equations as a function of one or several variables. The study of one-dimensional and multi-dimensional inverse problems associated with the restoration of the coefficients of partial differential equations involved in Lavrentev et al. (1980), Romanov (1984), Anikonov et al. (1988), Namazov (1984), Guliev (2004), Isakov (2006) and others. The book of Lavrentev et al. (1980) is described widely recent results on the uniqueness of integral geometry and inverse problems for differential equations in partial derivatives. In the book of Romanov (1984), the inverse problem for second-order equation and hyperbolic systems of first order equations, including kinematic problem of static, dynamic, Lamb problem for the equations of the theory of elasticity and the problem of electrodynamics. In the paper of Anikonov et al. (1988), the example of a parabolic equation given way to explore the problem of solvability for some nonlinear inverse problems for differential equations. Considered here the inverse problem using the technique of Fourier transform can be reduced to quite acceptable for the study of boundary value problem for nonlinear integro-differential equation. In a study Bubnov (1987), author considered some inverse problems for hyperbolic equations. The method which used based on the reduction of the inverse problem of nonlinear infinite systems of differential equations, allows us to prove theorem existence and uniqueness for solutions of multidimensional inverse boundary value problems in classes of functions of finite smoothness. In the book of Namazov (1984), author studied one-dimensional inverse problem for the parabolic and hyperbolic type. He was assumed that the unknown coefficients of the equation depend only on the argument t. There are theorems proved the existence and uniqueness of the problems. In paper of Guliev (2004) using the idea of work Bubnov (1987), author investigate the multidimensional inverse boundary value problem for integro-differential equation of hyperbolic type in a bounded domain. In the book of Isakov (2006) using the tool of Carleman estimates the author investigate the inverse problems for hyperbolic, parabolic and elliptic equations and then proved the existence and uniqueness theorems for the solutions of the considered problem. In this paper, using the idea of work Bubnov (1987) discusses solvability of inverse boundary value problems for hyperbolic systems of equations and then proved the existence and uniqueness theorems for the solutions of the problem. Note that the considered equation in this paper is called the Klein-Gordon equation. This relative invariant quantum equation describing spineless scalar or pseudo scalar particle, which plays one of the roles of the fundamental equation of quantum field theory. This system of equations cannot be written as a single equation. AAM: Intern. J., Vol. 6, Issue 1 (June 2011) [Previously, Vol. 6, Issue 11, pp. 1543– 1553] 355 2. Problem Statement and Preliminary Results In the domain DT 0, T consider the following problem 2U ( x, t ) AU ( x, t ) a ( x)U ( x, t ) b( x)V ( x, t ) f ( x, t ) , t 2 (1) 2V ( x, t ) AV ( x, t ) a1 ( x)U ( x, t ) b1 ( x)V ( x, t ) g ( x, t ) ( x, t ) DT , t 2 (2) U ( x,0) ( x), U ( x, t ) 0, t t 0 x , (3) V ( x,0) ( x), V ( x, t ) 0, t t 0 x , (4) U ( x, t ) F ( x, t ), V ( x, t ) G ( x, t ), ( x, t ) S 0, T , (5) U ( x, T ) h( x), V ( x, T ) q( x), x , (6) U ( x, t ) 0, t t T (7) V ( x, t ) 0, t t T where is bounded domain in AU ( x, t ) n (a ( x)U i , j 1 n a i , j 1 ij i ij xi Rn , x , S C 2, n 3, ( x, t )) x j , aij ( x) a ji ( x) C 4 (), 2 j , 0 , ( x), ( x), f ( x, t ), g ( x, t ), F ( x, t ), G ( x, t ), h( x), q( x) are given functions, and a ( x), b( x), a1 ( x), b1 ( x), U ( x, t ), V ( x, t ) are unknown functions. Definition: The system U ( x, t ), V ( x, t ), a ( x), b( x), a1 ( x), b1 ( x) is called the solution of the problem (1) (7), if it satisfies to following conditions 2 1. a ( x ), b( x ), a1 ( x ), b1 ( x ) W2 () . 2. Functions U ( x, t ), and V ( x, t ) are continuous in closed domain DT together with all 356 M.A. Guliev and A.M. El-Hadidi derivatives in the equations (1) and (2), respectively. 3. Conditions (1) - (7) are satisfied in usual sense. Let's designate through Z l , gl ( x) eigenvalues and eigenfunctions of the problem Ag l ( x) Z l2 g l ( x), g l ( x) S 0 . (8) Then, from the general theory of elliptic equations it follows that Z l , l and gl (x) form a complete set in W21 () W22 (). Condition I. Let for T Z 2 l where the domain 2n2 T 2 and for any integers n and l the following inequality be satisfied C ( ) 1 , Td = diam , Zl - eigenvalues of a problem (8) [see Bubnov (1987)]. Note. [See Bubnov (1987)]. Suppose that, for an operator Au u xx , {0 x R0 } , the eigenfunction g l ( x) sin 2 g l of the problem Ag l( x ) zl2 g l ( x), g l ( x) s 0 will be the function l lx , zl . Then, the condition I can be written in the form R0 R0 l 2 k 2 2l 2 T 2 k 2 2l 2 T k T k 2l 2 T T k C ( ) 2 0 2 2 2 2 2 2 R0 T T R0 l T R0 l R0 l T R0 R0 l TR0 The last inequality is written on the basis of Liouville's theorem, provided that the quadratic irrationality. Lemma 1: Let the condition I be satisfied and k ( x) L2 (), k k , (k 1,2,...) . T Then, for k there exists a solution of the Dirichlet problem T is R0 AAM: Intern. J., Vol. 6, Issue 1 (June 2011) [Previously, Vol. 6, Issue 11, pp. 1543– 1553] 357 Abk ( x) 2k bk ( x) k ( x), bk ( x) S 0, for which the estimation 1 b ( x)dx 2 k 2 1 2 k ( x)dx is true. 3. Reduction of the Inverse Problems to the Nonlinear Infinite System of Differential Equations Let us assume that operator A and functions G ( x, t ), h( x), q( x) satisfy the following conditions ( x), ( x), f ( x, t ), g ( x, t ), F ( x, t ), 1. U W21 () W22 () n 2 AU ( x, t ) dx 1 U x21x j ( x, t ) U 2 ( x, t ) dx, i , j 1 1 0; 2. f ( x, t ), g ( x, t ), Dt6 f ( x, t ), Dt6 g ( x, t ) L2 (0, T ); W22 () , f ( x, T ), g ( x, T ), W22 (), Dtk f ( x, t ) Dtk g ( x, t ) t 0 Dtk g ( x, t ) t T 0, t 0 Dtk f ( x, t ) t T 0, (k 1,3,5); 3. F ( x, t ), G ( x, t ), Dt8 F ( x, t ), Dt8G ( x, t ) L2 (0, T ); W2 2 ( S ) , Dtk F ( x, t ) t 0 Dtk F ( x, t ) t T 0, Dtk G ( x, t ) 7 t 0 Dtk G ( x, t ) t T 0 (k 1,3,5,7); 4. ( x), ( x) W24 (), A( Ah( x)), A( Ag ( x)) L2 (), x ( x) ( x), h( x) q( x); F ( x , t ) t o ( x ) S , G ( x , t ) t o ( x ) S , F ( x , t ) t T h ( x ) S , G ( x , t ) t T q ( x ) S ; 5. ( x) ( x)q( x) ( x)h( x) 0 . The following assertion holds: 358 M.A. Guliev and A.M. El-Hadidi Lemma 2: Let U ( x, t ),V ( x, t ), a ( x), b( x), a1 ( x), b1 ( x) be a solution of the inverse problem (1) - (7). Then, following relations are satisfied: 1 a ( x) q( x)U tt ( x, t ) t 0 ( x)U tt ( x, t ) t T 0 ( x) , ( x) 1 b( x ) ( x)U tt ( x, t ) t T h( x)U tt ( x, t ) t 0 1 ( x) , ( x) 1 a1 ( x) q( x)Vtt ( x, t ) t 0 ( x)Vtt ( x, t ) t T 2 ( x) , ( x) 1 b1 ( x) ( x)Vtt ( x, t ) t T h( x)Vtt ( x, t ) t 0 3 ( x) , ( x) where 0 ( x) A ( x) f ( x, o) q( x) Ah( x) f ( x, T ) ( x), 1 ( x) A ( x) f ( x, o) h( x) ( x) Ah( x) f ( x, T ) , 2 ( x) Aq( x) g ( x, T ) ( x) q ( x) A ( x) g ( x,0) , 3 ( x) h( x) A ( x) g ( x, o) ( x) Aq( x) g ( x, T ) . The proof of a Lemma 2 follows from (1) - (7). Lemma 3: If the functions U k ( x), Vk ( x), k 0,1, 2, , are solutions of the following problem in the domain U ( x) 2 m 2 k2U k ( x) AU k ( x) k q ( x) mU m ( x) ( x) (1) mU m ( x) 0 ( x) ( x) m 0 m 0 ~ V ( x) 2 ~ m 2 ~ k ( x) (1) mU m ( x) h( x) mU m ( x) 1 ( x) f k ( x), ( x) m0 m 0 U ( x) 2 k2Vk ( x) AVk ( x) k q ( x ) V ( x ) ( x ) (1) m m2Vm ( x) 2 ( x) m m ( x) m 0 m 0 ~ V ( x) ~ 2 ~ m k ( x) (1) mVm ( x) h( x) mVm ( x) 3 ( x) g k ( x) (9) ( x) m 0 m 0 ~ ~ U k ( x) Fk ( x), Vk ( x) Gk ( x), S from the class S k 0,1,2,... (10) AAM: Intern. J., Vol. 6, Issue 1 (June 2011) [Previously, Vol. 6, Issue 11, pp. 1543– 1553] 359 m8 AU m ( x) dx m12 U m ( x) dx m6 AU m ( x) m0 2 2 m0 m0 2 W21 ( ) m2 A AU m ( x) m0 m12 Vm ( x) dx m8 AVm ( x) dx m6 AVm ( x) m0 2 2 m 0 m0 Then, the functions ~ ~ V ( x, t ) Vk ( x) cos k t , k o a ( x) 1 ~ 2 ~ q ( x ) U ( x ) ( x ) (1) k 2kU k ( x) 0 ( x), k k ( x) k 0 k 0 b( x ) 1 ~ k 2 ~ ( x ) ( 1 ) U ( x ) h ( x ) 2kU k ( x) 1 ( x), k k ( x) k 0 k 0 a1 ( x) 1 k 2~ 2~ q ( x) kVk ( x) ( x) (1) kVk ( x) 2 ( x), and ( x) k 0 k 0 b1 ( x) 1 ~ k 2~ ( x ) ( 1 ) V ( x ) h ( x ) 2kVk ( x) 3 ( x) k k ( x) k 0 k 0 are the solution of an inverse problem (1) - (7), where k k , T T 2 f k ( x) f ( x, t ) cos k tdt , T 0 T T 2 F ( x, t ) cos k tdt , T 0 g k ( x) 2 g ( x, t ) cos k tdt , T 0 Gk ( x) 2 G ( x, t ) cos k tdt , (k 0,1,2,....) . T 0 Fk ( x) T Proof: From (9) - (11) we obtain, (1), (2), (5) and , W21 ( ) m 0 k o L2 ( ) 2 ~ 2m A AVm ( x) ~ ~ U ( x, t ) U k ( x) cos k t , 2 2 L2 ( ) , (11) 360 M.A. Guliev and A.M. El-Hadidi ~ U t ( x, t ) t 0 ~ 0, U t ( x, t ) t T ~ 0, Vt ( x, t ) t 0 ~ 0 Vt ( x, t ) t T 0. Therefore, to prove Lemma 3, it is required to establish that ~ U ( x, t ) t 0 ~ ( x ) U ( x, t ) t T ~ h( x), V ( x, t ) t 0 ~ ( x ) V ( x, t ) t T q( x). Let ~ U ( x, t ) t 0 ~ ~ ( x), V ( x, t ) t 0 ~ ( x) . ~ Then, for the function ~ ( x) ( x) Z ( x), ~ ( x) ( x) Z ( x) from (8), (9) we have AZ ( x) Z ( x) ( x) U tt ( x, t ) q ( x)U tt ( x, t ) 0 ( x) t T t 0 ( x) ~ Z ( x) ~ ~ h( x)U tt ( x, t ) ( x)U tt ( x, t ) 1 ( x) , t 0 t T ( x) (12) Z ( x) AZ ( x) ( x) Vtt ( x, t ) q( x)Vtt ( x, t ) 2 ( x) t T t 0 ( x) ~ Z ( x) ~ ~ h( x)Vtt ( x, t ) ( x)Vtt ( x, t ) 3 ( x) , t t T 0 ( x) Z ( x) S 0, ~ Z ( x) 0. (13) S The uniqueness of the solution of the problem (12), (13) will be established below. Then, we prove the solvability of (9), (10). It will be similarly shown that U ( x, t ) t T h( x), V ( x, t ) t T q ( x). We investigate the solvability of (9), (10). æ k ( x) (k 0,1, 2,....) the solutions of the following problems Let us define by rk (x) and A rk ( x) 0, 2 rk ( x) S Fk ( x) (k 0,1, 2,...), 2 rk ( x) C ( ) C1 Fk ( x) W 7 2 ( S ) , (14) 2 A æ k ( x) 0, æ k ( x) S Gk ( x) (k 0,1, 2,...), AAM: Intern. J., Vol. 6, Issue 1 (June 2011) [Previously, Vol. 6, Issue 11, pp. 1543– 1553] 361 2 2 æ k ( x) C ( ) C1 Gk ( x) W 7 2 ( S ) . (15) 2 ~ Let us designate U k ( x) U k ( x) rk ( x), ~ Vk ( x) Vk ( x) æ k ( x) . Then, from (9) and (10), we have U k ( x) rk ( x) 2 m 2 U k ( x) AU k ( x) q ( x) mU m ( x) ( x) (1) mU m ( x) ( x) m0 m 0 2 k 0 ( x) q( x) r ( x) ( x) (1) m m2 rm ( x) m0 m 0 2 m m Vk ( x) æ k ( x) m 2 2 ( ) ( 1) ( ) ( ) ( ) ( ) ( ) (1) m m2 rm ( x) x U x h x U x x x 1 m m m m ( x) m0 m0 m 0 h( x) 2m rm ( x) f k ( x) 2k rk ( x), m0 k2Vk ( x) AVk ( x) U k ( x) rk ( x) 2 q ( x ) V ( x ) ( x ) (1) m m2Vm ( x) m m ( x) m 0 m 0 2 ( x) q ( x) m2 æ m ( x) ( x) (1) m m2 æ m ( x) m0 m0 Vk ( x) æ k ( x) m 2 2 m 2 ( x) (1) mVm ( x) h( x) mVm ( x) 3 ( x) ( x) (1) m æ m ( x) ( x) m0 m 0 m 0 h( x) 2mæ m ( x) g k ( x) 2k æ k ( x), (16) m0 U k ( x) S 0, Vk ( x) S 0 (k 0,1,2,...) . (17) 4. Existence and Uniqueness for the Problem (1) - (7) Now we investigate problem (16), (17). We consider the following set of functions B U 0 ( x),U 1 ( x),...,U k ( x),...,, V0 ( x), V1 ( x),...,Vk ( x),..., U k ( x) S 0, Vk ( x) S 0 k 0,1,2,..., 12k U k ( x) 2L () U 0 ( x) 2L ( ) R , 12k Vk ( x) 2L () V0 ( x) 2L () R , 4 4 k 1 2 2 k 1 2 2 362 M.A. Guliev and A.M. El-Hadidi 8 k k 1 AU k ( x) 2 L2 AU 0 ( x) () 2 L2 ( ) R, 8 k k 1 AVk ( x) 2 L2 ( ) AV0 ( x) 2 L2 ( ) R . Let us show that at suitable choice R , the problem (16), (17) is solvable in B . Let 0 ( x),1 ( x),...,k ( x),..., ~0 ( x),~1 ( x),...,~k ( x),... be an arbitrary elements from B and substitute it in a right hand side of (16). Then, we will obtain a function, which belongs to the space L2 () . Then, from Lemma 1, we have 2 2 22 2 2 2 2 2 2 mm ( x) 2 N 0 k ( x) m rm ( x) U ( x)dx 12 2 N0 k ( x) m 1 m 1 2 k 2 2 ( x) 2 2 2 2 N r ( x) mm ( x) 2rk ( x) N 0 m2 rm ( x) k2 ( x) 0 m 1 m 1 ( x) 2 2 2 0 k 2 2 ( x) 2 2 2 2 2 2 2 ( ) ( ) 2 ( ) N x x N x r ( x) 0 m rm ( x) m m 0 k 0 k m 1 m 1 ( x) 2 2 k 2 2 2 N æ ( x) m2m ( x) 2 N 02 æ k2 ( x) m2 rm ( x) f k2 ( x) k4 rk2 ( x) s m 1 m 1 2 2 ( x) ( x) (18) ~k2 ( x) 1 æ 2k ( x) 1 dx , ( x) ( x) 2 0 2 k 2 2 2 2 2 V x dx N x x N x k æ m ( x) ( ) 2 ( ) ( ) 2 ( ) 0 k k m 2 1 m 1 m 1 2 k 22 2 0 2 2 k 2 2 ( x) 2 N r ( x) m2 m ( x) 2 N 02 rk2 ( x) m2 æ m ( x) k2 ( x) 2 m 1 m 1 ( x) 2 2 2 0 k 2 2 ( x) 2 2 2 2 2 2 N x x N x 2 ( ) ( ) 2 ( ) r ( x) 2 m æ m ( x) m m 0 k 0 k m 1 m 1 ( x) 2 2 k 2 2 2 ( x) 2 N æ ( x) m2 æ m ( x) 2 N 02 æ k2 ( x) m2 m ( x) k2 ( x) 3 m 1 m 1 ( x) 2 3 ( x) 2 g k2 ( x) 4k æ 2k ( x) dx, (k 0,1,2,...) , (19) æ k ( x) ( x) 2 0 2 k where q ( x) N 0 max ( x) , c() ( x) ( x) , c() ( x) ( x) , c() h( x ) ( x) . c() Now, multiplying the relation (18) by 12 k and summing over k from 0 to , we obtain AAM: Intern. J., Vol. 6, Issue 1 (June 2011) [Previously, Vol. 6, Issue 11, pp. 1543– 1553] 363 2 k U k ( x)dx 12 k 0 N 02C1C2 2 1 44 2 k k ( x)dx k Ak ( x) dx 12 k 0 2 8 k 0 k k2 ( x)dx k Fk ( x) W 7 2 k k2 ( x)dx k Fk ( x) W 7 2 12 k 0 8 2 (S ) k 0 12 k 0 12 2 (S ) k 0 k Fk ( x) W 7 2 k rk2 ( x)dx k k2 ( x)dx k Ak ( x) dx 8 2 (S ) k 0 k 0 12 12 k 0 8 k 0 2 k k2 ( x)dx k Fk ( x) W 7 2 k k2 ( x)dx k Gk ( x) W 7 2 12 k 0 8 2 (S ) k 0 12 k 0 12 2 (S ) k 0 2 22 ( x) 12 2 æ ( x)dx Fk ( x) W 2 2 0 k k ( x)dx (S ) k 0 k 0 1 ( x ) C k 0 12 k 2 k 8 k 2 7 2 22 ( x) 12 2 12 2 r ( x)dx 2 1 x dx ( ) k æ k ( x ) dx k k k 0 k 0 1 ( x ) C k 0 16 12 22 22 2 k f k2 ( x)dx 2 k rk2 ( x)dx , (20) 1 12 2 k k 1 k 0 k 0 where 1, k k , k 0, k 1, 2,. Similarly from (19) we obtain 2 k Vk ( x)dx k 0 12 2 8 44 N 02C1C2 12 2 ( x ) dx k A k ( x) dx k k 2 1 k 0 k 0 k k2 ( x)dx k Gk ( x) W 7 2 k k2 ( x)dx k Fk ( x) W 7 2 k 0 12 8 2 (S ) k 0 k 0 12 12 2 (S ) k 0 k rk2 ( x)dx k Gk ( x) W 7 2 k k2 ( x)dx k A k ( x) dx k 0 12 8 2 (S ) k 0 k 0 12 k 0 8 2 k k2 ( x)dx k Gk ( x) W 7 2 k æ 2k ( x)dx k Gk ( x) W 7 2 12 k 0 8 2 (S ) k 0 12 k 0 22 ( x) 12 2 k2 ( x)dx k Gk ( x) W 7 2 2 2 (S ) k 0 k 0 1 ( x ) 12 k 2 k 0 8 2 (S ) 2 12 2 k k ( x)dx C k 0 22 ( x) 12 2 12 k æ 2k ( x)dx r ( x)dx 2 3 ( x ) dx k k k 0 k 0 1 ( x ) C k 0 12 2 k k 364 M.A. Guliev and A.M. El-Hadidi 22 2 k g k ( x)dx 12 2 1 k 0 22 2 1 k 0 16 k æ 2k ( x)dx . (21) From estimations (20), (21) and (16) we obtain 2 k U k ( x)dx 12 k 0 2 k Vk ( x)dx 12 k 0 11 44 N 02C1C2 R 2 44 44 L0 R 2 L20 2 KR 2 KL0 2 L0 , 2 1 1 1 2 1 (22) 11 44 N 02 C1C 2 R 2 44 44 L0 R 2 L20 2 KR 2 KL0 2 L0 , 2 1 1 1 2 1 (23) R2 L0 R 2 L20 2 2 2 k AU k ( x) dx 2 k U k ( x)dx 44 N0 C1C2 2 8 k 0 12 k 0 11KR 44 KL0 44 L0 , (24) R2 L0 R 2 L20 2 2 2 k AVk ( x) dx 2 k Vk ( x)dx 44 N0 C1C2 2 8 k 0 12 k 0 11KR 44 KL0 44 L0 , (25) where ( x) K max 0 ( x) T , c() 1 ( x) ( x) , c() 2 ( x) ( x) , c() 3 ( x) ( x) T Dt6 f ( x, t ) 2 , c() 2 2 2 2 2 L0 F ( x, t ) W 7 2 ( S ) Dt8 F ( x, t ) 7 2 dt G ( x, t ) W 7 2 ( S ) W S ( ) 2 2 2 T 0 T 0 Dt8G ( x, t ) 2 7 W2 2 ( S ) f ( x, t ) 2 L2 ( ) L2 ( ) Lemma 4: Let conditions 1-5, I and 1 2 1 22 be satisfied. Then, 35 R R 44 N 02C1C2 L0 11KR , 8 2 g ( x, t ) 2 L2 ( ) Dt6 g ( x, t ) 2 L2 ( ) dt . AAM: Intern. J., Vol. 6, Issue 1 (June 2011) [Previously, Vol. 6, Issue 11, pp. 1543– 1553] 365 88 N 02 C1C 2 L20 44 KL0 44 L0 3 , and 11 1 3R 2 1 204 N 02C1C2 2 L0 204 K (C1 1) 1 . 2 1 Then, there exists a solution of the problem (16), (17) in B and 12 k k 0 2 U k ( x) L2 ( ) 8 k 0 AU k ( x) 2 L2 ( ) R , 4 12 k k 0 2 Vk ( x ) L2 ( ) R, , AVk ( x) k 0 8 2 L2 ( ) R , 4 R. Proof: System (16) has the form ~ EZ k L ( Z k ), where L is determined by the right-hand sides of the system (16), and E an elliptic operator of the left hand sides of (16), Z k ( x) U k ( x),Vk ( x), ( k 0,1,2,... ). But since E has a bounded inverse, the system (16) can be written as: Z k L( Z k ), (26) where ~ L E 1 L , L( Z k ) L1 U k ( x), Vk ( x) , L2 U k ( x), Vk ( x) k 0,1,2,... . Take an arbitrary vector function 0 ( x),..., k ( x),..., ~0 ( x),..., ~k ( x),... B and substitute into the right hand side of (16). Then, for the solutions U k ( x) L1 (k ( x), k ( x)), Vk ( x) L2 (k ( x), k ( x)) we obtain estimations (22) - (25). Hence, under the conditions of Lemma 4, we get that (U k ( x),...,U k ( x)...), (V0 ( x),...,Vk ( x)...) B . This proves that, operator L is contracting. Let 1, k ( x), ~1, k ( x) and solutions will be 2, k ( x), ( 2,k ( x) (k 0,1, 2,) B . Then, the corresponding 366 M.A. Guliev and A.M. El-Hadidi U1, k ( x) L1 (1, k ( x), ~1, k ( x)) , V1, k ( x) L2 (1, k ( x), ~1, k ( x)) , U 2,k ( x) L1 ( 2,k ( x), ~2,k ( x)) , V2,k ( x) L2 ( 2,k ( x), ~2,k ( x)) . Let us denote that U k ( x) U1, k ( x) U 2, k ( x), Vk ( x) V1, k ( x) V2, k ( x), k ( x) 1,k ( x) 2,k ( x), ~k ( x) ~1,k ( x) ~2,k ( x). Let's rewrite the relation (16) for U1, k ( x), V1, k ( x), 1, k ( x), ~1, k ( x) and U 2,k ( x), V2,k ( x), 2,k ( x), 2,k ( x) . Further, subtracting the first relation to the second, under conditions of Lemma 4, we obtain the following estimation 2 2 k U k ( x)dx k Vk ( x)dx k AU k ( x) dx k AVk ( x) dx 12 k 0 12 k 0 2 8 k 0 2 8 k 0 12 8 12 8 2 2 k k2 ( x)dx k ~k2 ( x)dx k Ak ( x) dx k A~k ( x) dx , (27) k 0 k 0 k 0 k 0 where 1 3R 2 L0 204 KC1 . 2 1 204 N 02C1C2 2 1 From this we obtain the Lemma 4. Theorem: Let conditions of Lemma 4 be satisfied. Then, there exists unique solution of problem (16), (17) (an inverse problem (1) - (7)) for which the following estimations are true k 0 12 k U k ( x) 2 L2 ( ) R , 4 k 0 12 k Vk ( x) 2 L2 ( ) R , 4 AAM: Intern. J., Vol. 6, Issue 1 (June 2011) [Previously, Vol. 6, Issue 11, pp. 1543– 1553] 367 8 k k 0 AU k ( x) L2 ( ) k AU k ( x) W 6 2 k 0 k AVk ( x) W 6 2 8 k 0 k A AU k ( x) L 1 () 2 2 k 0 2 2 L2 ( ) 2 k A AVk ( x) L 1 () 2 k 0 R, , k AVk ( x) 2 2 () 2 k 0 2 () R, RC , and RC. Proof: Lemma 4 implies the solvability of the problem (16), (17) in B . Thus, the first estimate of the 10 10 Theorem holds. Multiplying (16), by k U k ( x) and k Vk ( x), accordingly, and take the sum over k from 0 to , then, integrating in and using the first estimation, we obtain 10 k U k ( x) W 1 ( ) constR, 10 k Vk ( x) W 1 ( ) constR. k 0 k 0 2 2 2 2 Then, from (10) and this estimation, we get 6 k AU k ( x) W 1 ( ) constR, 6 k AVk ( x) W 1 ( ) constR. k 0 k 0 2 2 2 2 Similarly, we can prove the following estimations A AU 2 k k 0 ( x) L 2 k 2 () constR, and A AV ( x) k 0 2 k k 2 L2 ( ) constR. To complete the proof of the theorem, it remains to prove that the solution of (12), (13) is equal to zero. Indeed, under the conditions of the Theorem we have 368 M.A. Guliev and A.M. El-Hadidi 2 R ~ 2 2 2 AZ ( x) dx AZ ( x) dx 12 N 02C1C2 KC1 AZ ( x) dx AZ ( x) dx . 2 ~ ~ Then, AZ ( x) 0, Z ( x) S 0 and AZ ( x) 0, Z ( x) S 0, hence, Z ( x) 0, Z ( x) 0 . 4. Conclusion In the paper we investigate the solvability for the inverse boundary value problems for the system of hyperbolic equations. The method based on the reducing of inverse boundary value problem to some nonlinear infinite systems of differential equations is proposed. Given method allows one to prove existence and uniqueness theorems of multidimensional inverse boundary value problems in the class of finite smoothness functions. REFERENCES Anikonov, J.E. and Bubnov, B.A. (1988). Existence and uniqueness of the inverse problem for parabolic equation, Dan USSR, 298, №4, pp. 277-279. Bubnov, B.А. (1987). On the solvability of multidimensional inverse problems for hyperbolic equations, Novosibirsk, the Preprint № 713. Guliev, M. A. (2004). Multidimensional inverse boundary value problem for the integrodifferential equation of hyperbolic type in a bounded domain, Transactions of Inc. Applied Math. and fur. NASU, v.9, Donetsk, pp.131-140. Lavrentev, M. M., Romanov, V. 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