Math 1210 Practice for Midterm 3 February 28th, 2014 The following is a list of questions covering sections 3.6 through 4.1. The questions in the midterm will be a subset of these, with different functions. I will use this as a base for next Wednesday’s review session (April 2nd): please try to think about as many exercises as possible so that you can ask me questions on Wednesday. Name: UID: Section 3.6: The intermediate value theorem for derivatives 1. Let f be a function which is differentiable over the open interval (a, b) and continuous over the closed interval [a, b]. What does the intermediate value theorem for derivatives say? If moreover f (a) = f (b), what does the theorem say? 2. Consider the function f (x) = x2/3 . Show that the conclusion of the mean value theorem fails and explain why. 3. Consider the function f (x) = 2x3 − 9x2 + 1. (i) Show that the equation f (x) = 0 has exactly one solution on the interval (−1, 0). (ii) Show that the equation f (x) = 0 has exactly one solution on the interval (0, 1). (iii) Show that the equation f (x) = 0 has exactly one solution on the interval (4, 5). Section 3.7: Solving equations numerically I won’t be asking anything about this section in the midterm. Section 3.6: Antiderivatives R 2 2 4. Compute the integral (z √+1) dz. Hint: Expand the numerator first. z R 5. Compute the integral (t2 − 2 cos t) dt. √ R 6. Compute the integral (5x2 + 1) 5x3 + 3x − 2 dx. R 7. Compute the integral √ 3y2 dy. 2y +5 R sin x(1 + cos x)4 dx. √ R 9. Compute the integral sin x cos x 1 + sin2 x dx. 8. Compute the integral Section 3.7: Introduction to differential equations 10. Solve the differential equation dy x + 3x2 = dx y2 and find the solution y(x) that satisfies y(0) = 6. 11. Solve the differential equation dy = −y 2 x(x2 + 2)4 dx and find the solution y(x) that satisfies y(0) = 1. Section 4.1: Introduction to area P 12. Find a formula for nj=1 (j + 2)(j − 5). 13. Find the value of the following sums: P7 (−1)k 2k (i) k=3 k+1 P6 kπ (ii) k=−1 k sin 2 14. Follow the steps below to show that if r is any real number different from 1, then n X rk = r0 + r1 + . . . + rn = k=0 (i) If S = Pn k=0 1 − rn+1 1−r rk , what is rS. (ii) Compute rS − S and solve for S. P k (iii) Calculate the sum 10 k=1 2 . 15. Find the area of the region under the curve y = 2x + 2 over the interval [−1, 1] (i) First sketch a graph of the function and find the area using the classical formula for the area of a trapezoid. (ii) Subdivide the interval [-1,1] into n equal subintervals, calculate the sum of the areas of the corresponding n inscribed rectangles and let n → ∞. 16. Find the area of the region under the curve y = x2 over the interval [−2, 2]. To do this, subdivide the interval [-2,2] into n equal subintervals, calculate the sum of the areas of the corresponding n inscribed rectangles and let n → ∞. 17. Find the area of the region under the curve y = x3 + x over the interval [0, 1]. To do this, subdivide the interval [0,1] into n equal subintervals, calculate the sum of the areas of the corresponding n inscribed rectangles and let n → ∞. Section 4.3: The first fundamental theorem of Calculus For the following questions, remember that if f is a continuous function on the closed interval [a, b], then for any x inside of (a, b) we have Z x d f (t) dt = f (x) dx a Page 2 If in addition g(x) is a differentiable function, by the chain rule we have d dx Z g(x) f (t) dt = f (g(x))g 0 (x) a 18. Find the following derivatives: Rx 2 √ d (2t + t) dt (i) dx 0 R 1 d (ii) dx xt dt 0 R x+x2 √ d (iii) dx 2z + sin z dz 1 R 2 x t2 d (iv) dx dt −x2 1+t2 R sin x 5 d (v) dx t dt cos x Rb Rc Rb R4 19. Recall that for any c, we have a f (x) dx = a f (x) dx + c f (x) dx. Find 0 f (x) dx in each of the following cases: 0≤x<1 1 x 1≤x<2 (i) f (x) = 4−x 2≤x≤4 (ii) f (x) = |x − 2| (iii) f (x) = 3 + |x − 3| 20. For each of the following functions f (x), find the intervals on which the graph of y = f (x) is increasing and concave up. Rx u (i) f (x) = 0 √1+u 2 du Rx (ii) 0 cos u du Rx 21. Let F (x) = 0 sin t dt (i) Find F (0). (ii) Let y = G(x). Apply the first fundamental theorem of Calculus to obtain F 0 (x) = sin x. (iii) Solve the differential equation dy dx dy dx = = sin x. (iv) Find the solution of this equation that satisfies y(0) = F (0). Rπ (v) Compute F (π) = 0 sin t dt Rπ (vi) Use the second fundamental theorem of calculus to find 0 sin t dt and check that you obtain the same answer as before. Section 4.4: The second fundamental theorem of calculus and the method of substitution Page 3 22. Compute the following definite integrals: R4 4 (i) 1 x x−8 dx 2 R π/2 (ii) π/6 2 sin t dt √ R0 (iii) −1 x2 x3 + 1 dx R3 2 dx (iv) 1 √xx3+1 +3x R π/6 (v) 0 sin3 θ cos θ dθ R π/6 sin θ (vi) 0 cos 3 θ dθ R π/2 (vii) 0 sin x sin(cos x) dx R1 (viii) 0 x cos3 (x2 ) sin(x2 ) dx 23. Compute the following indefinite integrals: R√ 3 2x − 4 dx (i) R 2 3 (ii) x (x + 5) dx √ R 2 √ x +4 dx (iii) x sin x2 +4 R (iv) x2 (x3 + 5)8 cos [(x3 + 5)9 ] dx p R (v) x6 sin(3x7 + 9) 3 cos(3x7 + 9) dx p R (vi) x−4 sec2 (x−3 + 1) 5 tan(x−3 + 1) dx Section 4.5: The mean value theorem for integrals and the use of symmetry 24. Find all values of c which satisfy the mean value theorem for integrals on the given interval in each of the following cases: √ (i) f (x) = x + 1 over [0, 3]. (ii) f (x) = sin x over [−π, π]. (iii) f (x) = |x| over [0, 2] and [−2, 2]. 25. Use symmetry to help you evaluate the following integrals: Rπ (i) −π (sin x + cos x) dx R π/2 sin x (ii) −π/2 1+cos dx x R π/2 (iii) −π/2 z sin2 (z 3 ) cos(z 3 ) dz R π/4 (iv) −π/4 |x| sin5 x + |x|2 tan x dx 26. Use the substitution theorem to prove the following statements: Page 4 (i) If f (x) is an even function (namely f (−x) = f (x) for every x), then for every a Z a Z a f (x) dx = 2 f (x) dx −a 0 (ii) If f (x) is an odd function (namely f (−x) = −f (x) for every x), then for every a Z a f (x) dx = 0 −a (iii) If f (x) is a periodic function with period p (namely f (x + p) = f (x) for every x), then Z b+p Z b f (x) dx = f (x) dx a+p a Section 4.1: The area of a plane region 27. In each of the following questions, sketch the region bounded by the graphs of the given functions and calculate the area of the region. (i) y 2 = 4x, 4x − 3y = 4. √ (ii) y = x, y = −x + 6, y = 0. √ (iii) y = x, y = −x + 6, x = 0. (iv) x = 3 − y 2 , y = x − 1. (v) x = 3 − y 2 , y = x − 1, x = 0. Page 5