NAME: Chemistry 232 Analytical Chemistry Show all calculations for partial credit 1. (10 points) What is the difference between a 0.25 M solution of BaCl2 and a 0.25m solution? Would I use different glassware in making up 1L of each of these solutions? 2. (10 points) Concentrated Nitric Acid is 15.9 M, how much concentrated Nitric Acid do I need to make 2L of a 2.0 M Nitric Acid solution. 3. (10 points) I titrated a 25.00±.05 mL solution of NaOH with 21.34±.02 mL of .1007M HCl. What is the molarity of my NaOH solution, and what is the uncertainty in this molarity? 2 4. (10 points) I do 5 experiments and get a mean and standard deviation. I then do 45 additional experiments and find that neither my mean nor my standard deviation change significantly. The extra experiments seem like a waste of time, yet my text book tells me that I should have more confidence in my mean value. Why is this? Can you show numbers of equations to back this up? 5. (10 points) I do 5 experiments to determine the %Mn in a sample of steel. In these experiments I have a mean value of 0.678% Mn with a standard deviation of .001%. If I want to be right 95% of the time, what is the confidence interval I should establish from this data. 6. (10 points) The energy difference between a folded protein (native) and an unfolded protein (denatured) may be only 2 kJ (i.e. the )G of the reaction native6unfolded = +2 kJ). What is the K associated with this reaction? 3 7. (10 points) The ‘lime’ deposit you get from hard water is CaCO3. The Ksp of CaCO3 is 4.5x10-9. What is the solubility of Ca2+ in hard water? 8. (10 points) The carbonate in lime actually comes from CO2 in the air. CO2 in the air dissolves in water for form H2CO3. H2CO3 then undergoes two simple acid reactions: H2CO3 W HCO3- + H+ Ka1 = 4.45x10-7 HCO3- W CO32- + H+ Ka2 = 4.69x10-11 (A.) Based on the above equilibria how you expect the solubility of Ca2+ to change if you heated the water to drive off the CO2? Why? (B.) Based on the above equilibria how would you expect the solubility of Ca2+ to change if you increased the pH of the water? Why? (C.) Based on the above equilibria how would you expect the solubility of Ca2+ to change if you decreased the pH of the water? Why? 4 9A (5 points) In class I mentioned that the K for the dissociation of water is Kw = 1x10-14 = [H+][OH-]. Calculate the pOH of a solution if the pH is 7.37 9B (5 points) One easy way to convert from pH to pOH is to remember that pOH = 14pH. Why is this equation true? 10 (10 points - Hard question) A. In class we talked about how Mg(OH)2 is used as an antacid. Yet I showed that it has a very low solubility (Ksp = 7.1x10-12). I said the reason it is used as an antacid is that the OH- reacts with the H+ to form water. The K for this reaction is 1x10+14. So what is the K for the net reaction of Mg(OH)2 dissolving in water and then reacting with H+ ? I.e. The reaction : Mg(OH)2 (s)+ 2 H+(aq) W Mg2+ (aq) + 2H2O(l) B. If I swallow enough Mg(OH)2 so I have some solid laying undissolved in my stomach, and the stomach acid has been completely neutralized to the pH of the stomach juice is pH 7, what is the concentration of Mg2+ in the stomach juice? (Warning- You may get a funny looking answer.)