Chabot Mathematics §7.6 Radical Equations Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege.edu Chabot College Mathematics 1 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Review § 7.5 MTH 55 Any QUESTIONS About • §7.5 → Rational Exponents Any QUESTIONS About HomeWork • §7.5 → HW-28 Chabot College Mathematics 2 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Radical Equations A Radical Equation is an equation in which at least one variable appears in a radicand. Some Examples: 4 5 x 1 4 1 and m 2 4 1 and m 2 m 9. Chabot College Mathematics 3 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Power Rule vs Radical Eqns Power Rule for Solving Radical Equations: If BOTH SIDES of an equation are RAISED TO THE SAME POWER, ALL solutions of the original equation are ALSO solutions of the NEW equation Chabot College Mathematics 4 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Caveat PowerRule → Check CAUTION Read the power rule carefully; it does not say that all solutions of the new equation are solutions of the original equation. They may or may not be… Solutions that do not satisfy the original equation are called extraneous solutions; they must be discarded. Thus the CHECK is CRITICAL Chabot College Mathematics 5 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt ReCall Exponent Power Rule The Power Rule Provides a Crucial Tool for solving Radical Equations. Recall the Exponent Power Rule n a n b If a = b, then = for any natural-number exponent n Chabot College Mathematics 6 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Example Solve by PwrRule Solve Radical Equations: a) y 12 b) SOLUTION a) y 2 12 2 b) 3 x 4 x 3 y 144 Check Chabot College Mathematics 7 4 3 x 64 Check 144 12 12 12 3 3 True 64 4 4 4 True Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Example Solve 4 x x 60 SOLUTION Check 4 x x 60 4 x 2 42 x 2 x 60 x 60 16x x 60 15x 60 x4 Chabot College Mathematics 8 4 x x 60 2 4 4 4 60 4 2 64 88 4 Satisfies the original Eqn, so 4 is verified as a Solution Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Solving Radical Equations 1. Isolate the radical. If there is more than one radical term, then isolate one of the radical terms. 2. Raise both sides of the equation to the same power as the root index. 3. If all radicals have been eliminated, then solve. If a radical term remains, then isolate that radical term and raise both sides to the same power as its root index. 4. Check each solution. Any apparent solution that does not check is an extraneous solution Chabot College Mathematics 9 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Example Solve x 5 x 7 SOLUTION x 5 x 7 x 5 2 x7 2 x 2 10 x 25 x 7 x 2 11x 25 7 x 2 11x 18 0 ( x 2)( x 9) 0 x2 0 or x 9 0 x2 x 9 Chabot College Mathematics 10 Square both sides. Use FOIL or Formula. Subtract x from both sides. Subtract 7 from both sides. Factor. Use the zero-products theorem. The TENTATIVE Solutions Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Example Solve x 5 x 7 Check BOTH Tentative Solutions x2 25 27 95 97 4 16 3 9 3 3 x 9 False. 44 True. Because 2 does not check, it is an extraneous solution. The only soln is 9 Chabot College Mathematics 11 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Example Solve x 5 x 7 What Produced the Extraneous Solution? At this step we Squared a NEGATIVE Number withOUT Knowing it… x 5 2 x7 2 Square both sides. If x = 2, then (x−5) = −3 • So Squaring (x−5) is the SAME as Squaring −3; we just didn’t know it – Thus 2 is a solution to x 2 11x 18 0 – But NOT a solution to Chabot College Mathematics 12 x x 7 5 0 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Example Solve SOLUTION x 4 6 Check x 4 6 x 4 6 x 2 4 4 6 x 2 2 x4 2 2 4 6 2 6 This tentative solution x=4 does not check, so it is an extraneous solution. The equation has no solution; the solution set is {Ø} Chabot College Mathematics 13 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Example Solve SOLUTION 4 4 x3 2 x3 4 24 x 3 3 5. Check x3 3 5 4 4 4 4 x3 3 5 13 3 3 5 4 16 3 5 x 3 16 23 5 x 13 55 So 13 checks. The solution set is {13} Chabot College Mathematics 14 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Example Solve SOLN m 39 m 6 m 2 6 m 36 2 m 39 Isolate the variable radical Using the Power Rule Check m 39 36 3 9 639 Chabot College Mathematics 15 So 36 checks. The solution set is {36} Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Example Solve x x 5 1 x x 5 1 SOLN x 1 x 5 Isolate the variable radical x1 x5 2 x 2x 1 x 5 2 2 Sq Both Sides to Remove Radical (x−1)2 ≠ x2 −12 x 3x 4 0 2 ( x 4)( x 1) 0 x 4 0 or x 1 0 x 4 or x 1 Chabot College Mathematics 16 Apply Zero-Products Tentative Solutions Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Example Solve x x 5 1 Check BOTH Tentative Solutions x x 5 1 4 4 4 5 1 9 1 3+1 x x 5 1 −1 −1 15 1 4 1 2+1 In this Case 4 checks while −1 does NOT. The solution set is {4} Chabot College Mathematics 17 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Example Solve 3 3x 4 2 0. SOLUTION CHECK 3 3x 4 2 3 3 x 4 3 23 3x 4 8 3x 4 x 4/3 Chabot College Mathematics 18 3x 4 2 0 3 3 3x 4 2 0 3 ? 4 3 4 2 0 3 3 ? 4 4 20 3 ? 8 20 22 0 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt WhiteBoard Work Problems From §7.6 Exercise Set • 20, 26, 30, 46, 56 Remember, Raising Both Sides of Eqn to an EVEN Power can introduce EXTRANEOUS Solutions Chabot College Mathematics 19 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt All Done for Today Life Expectancy Chabot College Mathematics 20 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Chabot Mathematics Appendix r s r s r s 2 2 Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege.edu – Chabot College Mathematics 21 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt Graph y = |x| 6 Make T-table x -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Chabot College Mathematics 22 5 y = |x | 6 5 4 3 2 1 0 1 2 3 4 5 6 y 4 3 2 1 x 0 -6 -5 -4 -3 -2 -1 0 1 2 3 -1 -2 -3 -4 -5 file =XY_Plot_0211.xls -6 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt 4 5 6 5 5 y 4 4 3 3 2 2 1 1 0 -10 -8 -6 -4 -2 -2 -1 0 2 4 6 -1 0 -3 x 0 1 2 3 4 5 -2 -1 -3 -2 M55_§JBerland_Graphs_0806.xls -3 Chabot College Mathematics 23 -4 M55_§JBerland_Graphs_0806.xls -5 Bruce Mayer, PE BMayer@ChabotCollege.edu • MTH55_Lec-45_7-6a_Radical_Equations.ppt 8 10