Diodes-2 Engineering 43 Bruce Mayer, PE Registered Electrical & Mechanical Engineer

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Engineering 43

Diodes-2

Bruce Mayer, PE

Registered Electrical & Mechanical Engineer

[email protected]

Engineering-43: Engineering Circuit Analysis

1

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Learning Goals

Understand the Basic Physics of

Semiconductor PN Junctions which form most Diode Devices

Sketch the IV Characteristics of Typical

PN Junction Diodes

Use the Graphical LOAD-LINE method to determine the “Operating Point” of

Nonlinear (includes Diodes) Circuits

Engineering-43: Engineering Circuit Analysis

2

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Learning Goals

Analyze diode-containing Voltage-

Regulation Circuits

Use various math models for Diode operation to solve for Diode-containing

Circuit Voltages and/or Currents

Learn The difference between LARGE-signal and SMALL-Signal

Circuit Models

IDEAL and

PieceWise-Linear

Models

Engineering-43: Engineering Circuit Analysis

3

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Diode Models

LoadLine Analysis works well when the ckt connected to a

SINGLE Diode can be “Thevenized”

Engineering-43: Engineering Circuit Analysis

4

However, for

NONLinear ckts, such as those containing multiple diodes, construction of the LOAD-Curve

Eqn may be difficult, or even impossible.

Many such ckts can be analyzed by

Idealizing

the diode

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Diode Models

Consider an Electrical Diode →

We can MODEL the V-I

Behavior of this Device in

Several ways

I

V

REAL

Behavior

IDEAL

Model

Engineering-43: Engineering Circuit Analysis

5

OFFSET

Model

LINEAR

Model

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Ideal Model (Ideal Rectifier)

Diode OFF

Analyze Ckts containing Ideal Diodes

1. Assume

(or Guess) a “state” for each diode. Ideal Diodes have

Two

states

1.

2.

ON → a SHORT Ckt when Fwd Biased

OFF →an OPEN Ckt if Reverse Biased

2. Check

the Assumed Opens & Shorts

• Should have

Current

thru the SHORTS

• Should have ∆V across the OPENS

Engineering-43: Engineering Circuit Analysis

6

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Ideal Model (Ideal Rectifier)

Diode OFF

3. Check to see if

guesses

for i-flow,

∆V, and BIAS-State are

consistent

with the Ideal-Diode Model

4. If i-flow,

∆V, and bias-V are consistent with the ideal model, then We’re

DONE.

• If we arrive at even a SINGLE

Inconsistency, then START OVER at step-1

Engineering-43: Engineering Circuit Analysis

7

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example

Ideal Diode

Find For Ckt Below find:

I d

1

• Use the

Ideal

Diode

Model

&

V o

I d

1

I d

2

A

Engineering-43: Engineering Circuit Analysis

8

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example

Ideal Diode

A

I d

1

I d

2

Assume BOTH

Diodes are ON or

Conducting

Engineering-43: Engineering Circuit Analysis

9

In this Case

V

D1

= V

D2

= 0

Thus D2 Anode is connected to GND

I

Then Find by Ohm

d

2

10

0

10 k

V

1 mA

Next use KCL at

I d

1

Node-A (in = out)

I d

2

0

 

9 .

9 k

Bruce Mayer, PE

V

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example

Ideal Diode

A

I d

1

I d

2

I d

1

Using I

D2

0

 

9 .

9 k

= 1 mA

V

1 mA

Engineering-43: Engineering Circuit Analysis

10

Thus

I d

1

 

0 .

0101 mA

Now must Check that both Diodes are indeed conducting

I d

1

From the analysis

 

10 µA

I d

2

 

1 mA

Thus the current thru both Diodes is

positive

which is consistent with the assumption

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example

Ideal Diode

A

I d

1

I d

2

Another way to think about this is that since V

D2

V

D1

= 0 and

= 0 (by Short

Assumption) Find

Vo = GND+V

D2

+V

D1

= GND + 0 + 0 = 0

11

Since both Diodes conduct the Top of

Vo is connected to

GND thru D2 & D1

Engineering-43: Engineering Circuit Analysis

Thus the Answer

I d

1

 

10 µA

V o

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

0 V

Example

Ideal Diode

Find For Ckt Below find:

I d

1

• Use the

Ideal

Diode

Model

&

V o

I d

1

I d

2

• Note the

different

values on

R1

&

R2

– Swapped

B

Engineering-43: Engineering Circuit Analysis

12

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example

Ideal Diode

B

I d

1

I d

2

Again Assume

BOTH Diodes are

ON, or Conducting

Engineering-43: Engineering Circuit Analysis

13

As Before

V

D1

= V

D2

= 0

Again V

B shorted to

GND thru D1

I d

Then Find by Ohm

2

10

0

V

9 .

9 k

1 .

01 mA

Now use KCL at

Node-B (in = out)

I d

1

I d

2

0

 

1 0 k

Bruce Mayer, PE

V

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example

Ideal Diode

B

I d

1

I d

2

I d

1

Using I

D2

0

 

1 0 k

= 1.01 mA

V

1 .

01 mA

Engineering-43: Engineering Circuit Analysis

14

Thus

I d

1

 

0 .

01 mA

Now must Check that both Diodes are indeed conducting

I d

1

From the analysis

10 µA

I d

2

 

1 .

01 mA

We find and

INCONSISTENCY and our Assumption is WRONG

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example

Ideal Diode

B

I d

1

I d

2

In this Case D1 is an OPEN → I

D1

=0

Current I

D2 must flow thru BOTH

Resistors

I d

2

Then Find by Ohm

10

10

 

9 .

9

V k

1 .

005 mA

Must Iterate

Assume

• D1 →

OFF

D2 → ON

Engineering-43: Engineering Circuit Analysis

15

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example

Ideal Diode

B

I d

1

I d

2

Must Check that D1 is

REVERSE Biased as it is assumed OFF

V

B

By KVL & Ohm

 

10 V

10 kΩ

1 .

005 mA

V

B

 

0 .

05 V

 

50 mV

Thus D1 is INDEED

Reverse-Biased,

Thus the Ckt operation is

Consistent with our

Assumption

Engineering-43: Engineering Circuit Analysis

16

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example

Ideal Diode

B

I d

1

I d

2

Calculate Vo by noting that:

D2 is

ON

D1 is

OFF

→ V

D2

Current can only flow thru D2

= 0

In this case Vo = V

B

By the Previous

Calculation, Find

I d

1

0 A

V o

 

50 mV

Engineering-43: Engineering Circuit Analysis

17

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Offset & Linear Models

The Offset Model

The Linear Model

Better than Ideal, but no account of

Forward-Slope

Engineering-43: Engineering Circuit Analysis

18

The model eqn:

v

D

R b i

D

0 .

6 V

Yet more accurate, but also does not account for

Rev-Bias Brk-Down

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Point Slope Line Eqn

When constructing multipiece-wise linear models, the

Point-Slope

Equation is extremely Useful

y

y

1

m

x

x

1

• Where

m

y x

y x

2

2

– (x

1

, y

1

) & (x

2

y x

1

1

, y

2

) are

KNOWN Points

Engineering-43: Engineering Circuit Analysis

19

18

16

14

12

10

8

Example: Find Eqn for line-segment:

(3,17)

6

(19,5)

4

2 4

m

16 6

y

x

8

5

10 12

 x

17

19

3

14

 

12

16

18

m

 

3

4

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

20

Point Slope Line Eqn

18

16

14

12

Using the 2 nd

Point

(3,17)

Multiply by m, move

−5 to other side of =

y

5

 

3

4

x

19

10

8

y

5

 

3

4

x

57

4

20

6

4

2

(19,5)

4 6 8 10 12 14 16 18 x

y

5

 

3

x

19

4

Can easily convert to y = mx+b

20

Engineering-43: Engineering Circuit Analysis

y

 

3

4

x

57

4

5

y

 

3

4

x

57

4

20

4

y

 

3

x

77

4

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Slopes on vi Curve

With Reference to the Point-Slope eqn v takes over for x , and

If the curve is

NONlinear then the

local

conductance is the first Derivative i takes over for y

m vi

,

Op

di dv

Op

Amps

Volt

Siemens

The Slope on a vi

Curve is a

m vi

conductance

I

V

G

Amps

Volt

S iemens

m vi

Engineering-43: Engineering Circuit Analysis

21

m vi

,

Op

di dv

Op

g

Recall the Op-Pt is also the Q-Pt

m vi

,

Op

m vi

,

Q

di

dv

Q

Bruce Mayer, PE

g

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Slopes on vi Curve

18

Linear VI Curve

22

Finally recall that conductance & resistance are

Inverses

m vi

G

1

Example: Find the

R

RESISTANCE of the device associated with the VI curve that follows

Engineering-43: Engineering Circuit Analysis

16

14

12

10

8

6

4

2

m vi

4 6

I

V

8

10 12 14 16

V (volts)

17

19

5

3

Amps

Volts

18

20

m vi

12 A

16 V

G

3

Siemens

4

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Slopes on vi Curve

18

Linear VI Curve

Since R = 1/G Find the Device

R

Resistance as

V

I

19

17

3

5

Volts

Amps

16

14

12

10

1

m vi

R

1.333

8

4

3

Ohms

6

m vi

G

1

R

0.75

S

23

R

16 V

12 A

For a NONlinear vi

4

2 4 6 8 14 16 10 12

V (volts)

The General Reln

r

Op

1

g

di

1 or alternativ ely

dv

Op

curve the local slope then: r = 1/g

Engineering-43: Engineering Circuit Analysis

r

Op

dv di

Op

r

Q

dv di

Q

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

18 20

Example PieceWise Linear Model

Construct a

PieceWise

Linear

Model for the Zener vi curve shown at

Right

Engineering-43: Engineering Circuit Analysis

24

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

PieceWise Linear Zener

Us Pt-Slp eqn with

(0.6V,0mA) for Pt-1

i

D

OR

0

100 mS

v

D

:

i

D

100 mS

v

D

0 .

6 V

60 mA

Segment- B is easy

m

A

R

m for Segment A

1

A

I

V

100

1.6

0

0.6

mA

V

m

A

100 mS

1

10

Engineering-43: Engineering Circuit Analysis

25

i

D

0

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

PieceWise Linear Zener

i

D

Us Pt-Slp eqn with

(−6V,0mA) for Pt-1

0

OR :

i

D

83 .

3 mS

v

D

83 .

3 mS

v

D

6 V

500 mA

m

C

1

R

C

m for Segment C

I

V

0

6

100

7 .

2

 mA

V

m

C

100 mA

1.2V

83 .

33 mS

1

12

Thus the PieceWise

Model for the Zener

i

D

100 mS

8 3.3mS

v

D

0

v

D

60 mA

500 mA if if if

v

D

0 .

6 V

6 V

v

D

v

D

0

6 V

.

6 V

Engineering-43: Engineering Circuit Analysis

26

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example PieceWise Linear Model

Alternatively in terms of

i

D

v

D

10

Resistances

60 mA if

0 if

v

D

6 V

v

12

D

500 mA if

v

D v

D

0 .

6 V

6 V

0 .

6 V

ADVICE: remember the

Pt-Slope

27

Line-Eqn

Engineering-43: Engineering Circuit Analysis

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Half-Wave Rectifier Ckt

Consider an Sinusoidal V-Source, such as an AC socket in your house, supplying power to a Load thru a Diode

Engineering-43: Engineering Circuit Analysis

28

Power Input Load Voltage

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

HalfWave Rectifier

Note that the Doide is FWD-Biased during only the

POSITIVE half-cycle of the Source

Using this simple ckt provides to the load

ONLY positive-V; a good thing sometimes

However, the positive voltage comes in nasty

PULSES which are not well tolerated by positive-V needing loads

Engineering-43: Engineering Circuit Analysis

29

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Smoothed HalfWave Rectifier

Adding a Cap to the

Circuit creates a

Smoothing

effect

This produces v

L

(t) and i

L

(t) curves

In this case the

Diode Conducts

ONLY when v s

>v

C and v

C

=v

L

Engineering-43: Engineering Circuit Analysis

30

i

C i

D

C

dv

L

i

C

i

L dt

Note that i

L

(t) is approx. constant

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Smoothed HalfWave Rectifier

The change in

Voltage across the

Cap is called “Ripple”

Ripple

Often times the load has a Ripple “Limit” from which we determine Cap size

Engineering-43: Engineering Circuit Analysis

31

From the i

L

(t) curve on the previous slide note:

• Cap Discharges for

Almost the ENTIRE

Cycle time, T (diode Off)

• The Load Current is approx. constant, I

L

Recall from EARLY in the Class

Charge

Current

Time

Or, symbolical ly :

Q

I

T

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Smoothed HalfWave Rectifier

Also from Cap

Physics

(chp3)

Q cap

C

 

V cap

Note that both these equations are

Approximate, but they are still useful

Engineering-43: Engineering Circuit Analysis

32

In the Smoother Ckt the Cap charges during the “Ripple” portion of the curve

Equating the Charge

& Discharge “Q’s find

Q cap

Charge

C

V r

I

Discharge

T

L

for initial Ckt Design

Solving the equations for the

Cap Value needed for a given V r

T

C

I

L

V r

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Smoothed HalfWave Rectifier

V

L,lo

Find the Approximate Average Load

Voltage

V

L,hi

V

L

,

avg

33

V

L

,

avg

V m

V

L

,

hi

V

L

,

lo

2

Engineering-43: Engineering Circuit Analysis

V m

V r

2

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Capacitor-Size Effect

Any load will discharge the capacitor. In this case, the output will depend on how the RC time constant compares with the period of the input signal.

The plots at right consider the various cases for the simple circuit above with a

1kHz, 5V sinusoidal input

RC T

1 mS

Engineering-43: Engineering Circuit Analysis

34

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Full Wave Rectifier

The half-wave ckt will take an AC-

Voltage and convert it to DC, but the rectified signal has gaps in it.

The gaps can be eliminated thru the use of a Full-Wave rectifier ckt

Engineering-43: Engineering Circuit Analysis

35

The Diodes are

• Face-to-Face (right)

• Butt-to-Butt (left)

This rectified output has

NO Gaps

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Full Wave Rectifier Operation

D1 Supplies V to Load

D4 Supplies V to Load

Engineering-43: Engineering Circuit Analysis

36

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Full Wave Rectifier Smoothing

The Ripple on the

FULL wave Ckt is about 50% of that for the half-wave ckt

Since the Cap

DIScharges only a half-period compared to the half-wave ckt, the size of the

“smoothing” cap is then also halved:

C

I

L

T

2

V r

Engineering-43: Engineering Circuit Analysis

37

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Small Signal Models

Often we use NonLinear Circuits to

Amplify, or otherwise modify, non-steady

Signals such as ac-sinusoids that are small compared to the DC Operating

Point, or Q-Point of the Circuit.

Over a small v or i range even

Non

Linear devices

appear linear

.

This allows us to construct a so-called

38 small signal Linear Model

Engineering-43: Engineering Circuit Analysis

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Small Signal Analysis

Small signal Analysis is usually done in

Two Parts:

1. Large-Signal DC Operating Point (Q-Pt)

2. Linearize about the Q-Pt using calculus

Recall from

dy

Calculus

dx

y

x

This approximation become more accrate as

∆y & ∆x become smaller

Engineering-43: Engineering Circuit Analysis

39

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Small Signal Analsyis

Now let y→i

D

, and x→ v

D

Use a DC power Supply to set the operating point on the diode curve as shown at right

• This could be done using LoadLine methods

From Calculus

di

D dv

D

 

i

D

v

D

 units of A/V or Siemens

Next Take derivative about the Q-Pt

Engineering-43: Engineering Circuit Analysis

40

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Small Signal Analysis

About Q-Pt

di

D dv

D

Q

i

D

v

D

near Q

Now if we have a math model for the vi curve, and we inject ON TOP of

V

DQ

∆v

D a small signal, find

Engineering-43: Engineering Circuit Analysis

41

i

D

di

D dv

D

Q

 

D

g d

 

v

D

The derivative is the diode small-signal

Conductance at Q

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Small Signal Analysis

In the large signal

Case: R = 1/G

By analogy In the small signal case: r = 1/g

Also since small signal analysis is associated with small amounts that change with time…

Define the Diode’s

DYNAMIC, smallsignal Conductance and Resistance

r g d d

di

D dv

D

Q

1

g d

di

D dv

D

Q

1

dv

D di

D

Q

Engineering-43: Engineering Circuit Analysis

42

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Small Signal Analysis

r d

di

D dv

D

Note Units for r d

Q

1



Amp

Volt



1

Volt

Amp

Recall the

 

 approximation for i

i

D

di

D dv

D

Q

 

D

v r d

D

D

Change Notation for

Small

Signal conditions

i

D

v

D

i d v d

Engineering-43: Engineering Circuit Analysis

43

Find r d for a

“Shockley” Diode in majority FWD-Bias

Recall Shockley Eqn

i

D

I s e



v

D nV

T



1

Then the Largesignal Operating

I

DQ

Point at v

D

I s e



V

DQ nV

T



1

= V

DQ

I s e



V

DQ nV

T



Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Small Signal Analysis

Taking the derivative of the

di

D dv

D

Q

Shockely Eqn

I

S e



v

D nV

T

 1

nV

T

1

nV

T

I

S e



v

D nV

T



Recall from last sld

I s e



V

DQ nV

T



I

DQ

Sub this Reln into the Derivative Eqn

di

D dv

D

Q

1

nV

T

I

 

DQ

I

DQ nV

T

Recall

r d

di

D dv

D

Q

1

r d

Subbing for di

D

/dv

D

di

D dv

D

Q

1

I

DQ nV

T

1

nV

T

I

DQ

Engineering-43: Engineering Circuit Analysis

44

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Notation: Large, Small, Total

V

DQ and I

DQ are the LARGE Signal operating point (Q-Pt) DC quantities

• These are STEADY-STATE values

 v

D and i

D are the TOTAL and

INSTANTANEQOUS quantities

• These values are not necessarily steadystate. To emphasize this we can write v

D

(t) and i

D

(t)

Engineering-43: Engineering Circuit Analysis

45

Bruce Mayer, PE

[email protected]edu • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Notation: Large, Small, Total

 v d and i d are the SMALL, AC quantities

• These values are not necessarily steadystate. To emphasize this we can write v d

(t) and i d

(t)

An

Example for

Diode

Current notation

Engineering-43: Engineering Circuit Analysis

46

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Effect of Q-Pt Location

From

i d

Analysis

v d r d i d

2 ,

pp i d

1

pp

and

r d

nV

T

I

DQ v d

1

pp v d

2

pp

Engineering-43: Engineering Circuit Analysis

47

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

DC Srcs

SHORTS in Small-Signal

In the small-signal equivalent circuit

DC voltage-sources

are represented by

SHORT CIRUITS; since their voltage is

CONSTANT, they exhibit ZERO

INCREMENTAL, or SIGNAL, voltage

Alternative Statement: Since a DC

Voltage source has an ac component of current, but NO ac VOLTAGE, the DC

Voltage Source is equivalent to a

48

SHORT circuit for ac signals

Engineering-43: Engineering Circuit Analysis

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Setting Q, Injecting v

Consider this ckt with AC & DC V-srcs

Sets Q

Sets v d

Engineering-43: Engineering Circuit Analysis

49

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Large and Small Signal Ckts

Recall from Chps 3 and 5 for Caps:

• OPENS to DC

• SHORTS to fast AC

Z

C

1

j

C

Thus if C

1 is LARGE it COUPLES v in

(t) with the rest of the ckt

Similarly, Large C

2 couples to the Load

Engineering-43: Engineering Circuit Analysis

50

To Find the Q-point

DE

couple v in and v o to arrive at the

DC

circuit

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Large and Small Signal Ckts

Finding the Large signal Model was easy; the Caps acts as an OPENS

The Small Signal Ckt needs more work

• Any

DC V-Supply

is a SHORT to GND

• The Diode is replaced by r d

• The

Caps

are

(or g d

)

Shorts

Engineering-43: Engineering Circuit Analysis

51

Thus the Small Signal ckt for the above

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example: Small Signal Gain

Find the Small

Signal Amplification

(Gain), A v

, of the previous circuit

Using the Small

Signal Circuit

Engineering-43: Engineering Circuit Analysis

52

Note that R

C

, r d

, and

R

L are in Parallel

1

R p

1

R

C

1

R d

1

R

L

And v o

(t) appears across this parallel combination

The equivalent ckt

Bruce Mayer, PE

v o

 

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Example: Small Signal Gain

Thus for this Ckt the

Large, Small, and small-Equivalent ckts

1

R p

1

R

C

1

R d

1

R

L v o

 

Then the

Amplification (Gain) by Voltage Divider

A v

v v in o

R

R p

R p

Engineering-43: Engineering Circuit Analysis

53

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

All Done for Today

Small

Signal

BJT Amp

LARGE

Signal

Model

Common Collector

Amplifier

Engineering-43: Engineering Circuit Analysis

54

SMALL

Signal

Model

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Engineering 43

Appendix

Bruce Mayer, PE

Registered Electrical & Mechanical Engineer

[email protected]

Engineering-43: Engineering Circuit Analysis

55

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

v o

 

v o

 

Engineering-43: Engineering Circuit Analysis

56

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Small Signal Analysis

In the large signal

Case: R = 1/G

By analogy In the small signal case: r = 1/g

Also since small signal analysis is associated with small amounts that change with time…

Define the Diode’s

DYNAMIC

Conductance and

Resistance

r g d d

di

D dv

D

Q

1

g d

di

D dv

D

Q

1

dv

D di

D

Q

Engineering-43: Engineering Circuit Analysis

57

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

P10.67

Graph v o vs. v i for v i

: −5V to +5V

6

-6 -5 -4 -3 -2 -1

0

-1

0

-2

5

4

3

2

1

1

-3

-4

-5

-6

file =XY_Plot_0211.xls

2 3 4 5 6

Engineering-43: Engineering Circuit Analysis

58

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Engineering-43: Engineering Circuit Analysis

59

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Engineering-43: Engineering Circuit Analysis

60

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Engineering-43: Engineering Circuit Analysis

61

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

Engineering-43: Engineering Circuit Analysis

62

Bruce Mayer, PE

[email protected] • ENGR-43_Lec-10b_Diode-2_SmallSignalAnalysis.pptx

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