Math 273 HW 2 Name: Due: 22 February 2016 Show Appropriate Work Scaled to 10 points 1. 2 Sketch the level curves corresponding to c = −2, −0, and 2 for f (x, y) = ex + y. p 2. Consider the function f (x, y) = x2 + (y/2)2 − 1. (a) 2 Find and sketch the domain of f . Express your solution in set notation. √ √ √ (b) 2 Sketch the level curves corresponding to c = 0, 3, 8, and 15. (c) 2 Sketch the surface. 3. Find the limit, if it exists, or show that the limit does not exist. Justify your solutions. (a) 2 lim (x,y)→(2,π) x cos y [Hint: Is f continuous?] x2 + sin2 y sin(x2 + y 2 ) [Hint: Polar and see Theorem 2 in §2.6.] x2 + y 2 (x,y)→(0,0) x arcsin y lim (c) 2 [Hint: Consider the paths x = 0 and y = sin x.] (x,y)→(0,0) x2 + y 2 3 3 x y − xy if (x, y) 6= (0, 0) 4. Consider the function f (x, y) = x2 + y 2 0 if (x, y) = (0, 0) (b) 2 lim (a) In class we showed that f was continuous. (b) A routine use of the quotient rule shows that for (x, y) 6= (0, 0), fx (x, y) = y(x4 + 4x2 y 2 − y 4 ) . (x2 + y 2 )2 (c) 2 For (x, y) 6= (0, 0) compute fy . Simplify. It should look similar to the above. (d) We can use the definition of a partial derivative at a point to compute fx (0, 0) as follows. f (h, 0) − f (0, 0) =0 h→0 h fx (0, 0) = lim (e) 2 Use the definition of a partial derivative at a point to compute and fy (0, 0). Specifically, f (0, h) − f (0, 0) . h→0 h fy (0, 0) = lim (f) 2 Use the definition of a partial derivative at a point to compute fxy (0, 0) and fyx (0, 0). fy (h, 0) − fy (0, 0) fx (0, h) − fx (0, 0) Specifically, fxy (0, 0) = lim and fyx (0, 0) = lim . h→0 h→0 h h (g) 1 What can be said about fxy and fyx in light of Clairaut’s Theorem (Theorm 1 in §14.3). p 5. Let f (x, y) = 36 − 9x2 − 4y 2 (a) 2 Sketch the surface. (b) 2 Find the differential df . (c) 2 If (x, y) changes from (1, 2) to (1.01, 1.97) compare the values of ∆f and df . √ (d) 2 Find an equation for the tangent plane to the surface at the point (1, 2, 11). (e) 1 Find an equation for the tangent plane to the surface at the point (0, 0, 6)