Inequalities and Absolute Value Equations and Inequations - §2.4 - 2.5 Fall 2013 - Math 1010 A no TIE fighter and squinting cat zone. (Math 1010) M 1010 §2.4 - 2.4 1 / 12 Roadmap I Notes for solving inequalities. I Examples of solving inequalities. I Notes for solving absolute value equations and inequalites. I Examples of solving absolute value equations and inequalities. Today’s lecture will procede with slide notes and then chalkboard examples. (Math 1010) M 1010 §2.4 - 2.4 2 / 12 §2.4 - The Symbols for Inequalities I ’less than’ Example x < 7 I ’less than or equal’ Example x ≤ 4 I ’greater than’ Example x > −3 I ’greater than or equal’ Example x ≥ 2.8 - ’or equal’ means the values for the unknown can include that number. - Inequalties without ’or equal’, that is < and >, are called strict inequalities. (Math 1010) M 1010 §2.4 - 2.4 3 / 12 §2.4 - Notations Styles in this section include intervals, inequalty signs, graphs, and set (or set builder) notation. The samples below are equivalent. Example x + 6 < 9 ↔x <3 Interval: (−∞, 3) Inequality signs: x < 3 Set builder notation: {x|x < 3} (I like to use : in place of |.) (Math 1010) M 1010 §2.4 - 2.4 4 / 12 §2.4 - Operations Operations on all sides of an inequality with expressions are the same for equalities with one exception: Multiplication and division by a negative quantity produces an equivalent inequality with a reversed inequality symbol. Summary: I Add/Subtract: a < b ↔ a + c < b + c ↔ a − c < b − c I Multiply/Divide: positive quantities a < b ↔ ac < bc ↔ a ÷ c < b ÷ c, c > 0 I Multiply/Divide: negative quantities a < b ↔ ac > bc ↔ a ÷ c > b ÷ c, c < 0 I Transitivity: When a < b and b < c, then it follows that a < c. (Math 1010) M 1010 §2.4 - 2.4 5 / 12 §2.4 - Compound Inequalties - Conjunctive ’And’ Conjunctive (and) is used for compound inequalties that have two conditions. Both conditions must be met. Example −1 ≤ 5 − 2x and 5 − 2x < 7 Write this as a double inequalty and solve. (Math 1010) M 1010 §2.4 - 2.4 6 / 12 §2.4 - Compound Inequalties - Conjunctive ’And’ Conjunctive (and) is used for compound inequalties that have two conditions. Both conditions must be met. Example −1 ≤ 5 − 2x and 5 − 2x < 7 Write this as a double inequalty and solve. −1 ≤ 5 − 2x < 7 (Math 1010) M 1010 §2.4 - 2.4 6 / 12 §2.4 - Compound Inequalties - Conjunctive ’And’ Conjunctive (and) is used for compound inequalties that have two conditions. Both conditions must be met. Example −1 ≤ 5 − 2x and 5 − 2x < 7 Write this as a double inequalty and solve. −1 ≤ 5 − 2x < 7 −6 ≤ −2x < 2 (Math 1010) M 1010 §2.4 - 2.4 6 / 12 §2.4 - Compound Inequalties - Conjunctive ’And’ Conjunctive (and) is used for compound inequalties that have two conditions. Both conditions must be met. Example −1 ≤ 5 − 2x and 5 − 2x < 7 Write this as a double inequalty and solve. −1 ≤ 5 − 2x < 7 −6 ≤ −2x < 2 −6 2 ≥x > −2 −2 (Math 1010) M 1010 §2.4 - 2.4 6 / 12 §2.4 - Compound Inequalties - Conjunctive ’And’ Conjunctive (and) is used for compound inequalties that have two conditions. Both conditions must be met. Example −1 ≤ 5 − 2x and 5 − 2x < 7 Write this as a double inequalty and solve. −1 ≤ 5 − 2x < 7 −6 ≤ −2x < 2 −6 2 ≥x > −2 −2 3 ≥ x > −1 ↔ −1 < x ≤ 3 (Math 1010) M 1010 §2.4 - 2.4 6 / 12 Just Say No (Math 1010) M 1010 §2.4 - 2.4 7 / 12 §2.4 - Compound Inequalties - Disjunctive ’Or’ Disjuctive (or) is used for compound inequalties that have two conditions. Either condition may be met. These inequalities cannot be written as a compound inequality. Example x + 3 < −7 or x + 3 > 14 Solve. (Math 1010) M 1010 §2.4 - 2.4 8 / 12 §2.4 - Compound Inequalties - Disjunctive ’Or’ Disjuctive (or) is used for compound inequalties that have two conditions. Either condition may be met. These inequalities cannot be written as a compound inequality. Example x + 3 < −7 or x + 3 > 14 Solve. One at a time: x + 3 < −7 → x < −10 (Math 1010) M 1010 §2.4 - 2.4 8 / 12 §2.4 - Compound Inequalties - Disjunctive ’Or’ Disjuctive (or) is used for compound inequalties that have two conditions. Either condition may be met. These inequalities cannot be written as a compound inequality. Example x + 3 < −7 or x + 3 > 14 Solve. One at a time: x + 3 < −7 → x < −10 Next one: x + 3 > 14 → x > 11 (Math 1010) M 1010 §2.4 - 2.4 8 / 12 §2.4 - Compound Inequalties - Disjunctive ’Or’ Disjuctive (or) is used for compound inequalties that have two conditions. Either condition may be met. These inequalities cannot be written as a compound inequality. Example x + 3 < −7 or x + 3 > 14 Solve. One at a time: x + 3 < −7 → x < −10 Next one: x + 3 > 14 → x > 11 Solution: x < −10 or x > 11. (Math 1010) M 1010 §2.4 - 2.4 8 / 12 §2.5 - Absolute Value Equations and Inequalties An absolute value equation contains a term with an absolute value expression. It may have no solution, or it may have one or more solutions. Example |x| = 3.6 → x = −3.6 or x = 3.6 Example |x| = −12 → No solution; an absolute value cannot be negative. To solve |x| = a, a ≥ 0 the algebraic expression inside the absolute value symbols x may be −a or a. (Math 1010) M 1010 §2.4 - 2.4 9 / 12 §2.5 - Solving Equations I Simplify each side to have at most one absolute value expression. I Write two linear equations - write one side equal to the other side, and then write one side equal to the opposite of the other side. I Solve each linear equation one after the other. I Check the solutions! It is possible for no solution or one solution. (Math 1010) M 1010 §2.4 - 2.4 10 / 12 §2.5 - Solving Inequalities Absolute value inequalties match a conjunctive pair of statements (also, a compound inequality) or a disjunctive pair of statements. (Math 1010) M 1010 §2.4 - 2.4 11 / 12 §2.5 - Solving Inequalities Absolute value inequalties match a conjunctive pair of statements (also, a compound inequality) or a disjunctive pair of statements. Example Solutions to |x| < 2 lie between -2 and 2. That is, −2 < x < 2. (Math 1010) M 1010 §2.4 - 2.4 11 / 12 §2.5 - Solving Inequalities Absolute value inequalties match a conjunctive pair of statements (also, a compound inequality) or a disjunctive pair of statements. Example Solutions to |x| < 2 lie between -2 and 2. That is, −2 < x < 2. Example Solutions to |x| > 2 lie outside -2 and 2. That is, x < −2 or x > 2. (Math 1010) M 1010 §2.4 - 2.4 11 / 12 Assignment Assignment: For Monday: 1. Read sections 3.1 and 3.2. 2. Exercises from §2.4, 2.5 due Monday, September 16. 3. Pre-Exam 1 Wednesday, September 18. (Math 1010) M 1010 §2.4 - 2.4 12 / 12