Notes on QSS Reduction 1 Overview The purpose of these notes is to describe the qss reduction in a systematic way, and then show several examples of how this works. We suppose that we have a differential equation of the form du 1 = Au + B(u), (1) dt ǫ where ǫ << 1. We assume that the eigenvalues of A are non-positive. In order for there to be a separation of time scales, it must be that A has a null-space. So we assume that the nullspace of A is spanned by {φi }, i = 1, · · · , k, and that there are corresponding vectors {ψi }, i = 1, · · · , k, that span the nullspace of AT , and form a biorthogonal set, < ψi , φj >= δij . To see the separation of time scales directly, we introduce a change of variables, X u = P u + Qu = ai φi + χ (2) i P where P u = i αi φi , αi = hψi , ui, Qu = u − P u. Notice that P is a projection, with P u in the nullspace of A, and Qu is orthogonal to the nullspace of AT We project the equation (1) to find (multiply by ψi ) dai = ψiT B(u). dt This is the slow-manifold equation. Next we note that (3) Qu dt = du dt − Pu , dt so that X 1 dχ = Aχ + B(u) − ψiT B(u)φi . dt ǫ i (4) Now we are essentially done. The leading order qss approximation is χ = 0 with slow dynamics given by X dai = ψiT B( ai φi ). (5) dt i However, it is easy to get a better approximation by taking X X X 1 Aχ + B( ai φi ) − ψiT B( aj φj )φi ǫ i i j (6) in which case the slow equation becomes dai = ψiT B dt X i ai φi − ǫA† B( X i ai φi ) − X i ψiT B( X j aj φj )φi !! . (7) Notice that this analysis assumes that φi are independent of time. If they are not independent of time, a similar argument still applies, but with some extra terms. 1 Figure 1: Model of the RyR. R and RI are closed states, O is the open state, and I is the inactivated state. 2 2.1 Examples RyR Kinetics Consider the 4-state chemical reaction network shown in Fig.1 We assume that k1 >> k2 and k−1 >> k−2 . To simplify the notation, we set c = 1. The master equation for this network can be written in the form of (1) by first rescaling k±1 → ǫk±1 for some fixed small number ǫ. We don’t specify it completely, because we want to allow k1 , k2 , k−1 and k−2 to be time varying. −k2 0 k−2 0 −k1 k−1 0 0 P00 k1 −k−1 0 P10 0 −k2 0 k−2 0 , B= A= u= k2 0 P01 , 0 −k−2 0 0 −k1 k−1 0 k2 0 −k−2 0 0 k1 −k−1 P11 (8) where the identification of states is R = {00}, RI = {01}, O = {10}, I = {11}. The decomposition of the equations uses the vectors 0 1 0 κ−1 0 −1 0 κ1 , , (9) φ = φ = φ = φ1 = 4 3 2 1 0 κ−1 0 −1 0 κ1 0 where κ±1 = k±1 , k1 +k−1 1 1 ψ1 = 0 , 0 and 0 0 ψ2 = 1 , 1 κ1 −κ−1 ψ3 = 0 , 0 0 0 ψ4 = κ1 −κ−1 (10) Notice that φ1 , φ2 span the nullspace of A, φ3 , φ4 span the non-zero eigenspace of A, ψ1 , ψ2 span the nullspace of AT , and ψ3 , ψ4 span the nonzero eigenspace of AT . We define y1 = P00 + P10 , y2 = P01 + P11 , and and learn that (multiply by ψ1 and ψ2 ) dy1 = −k2 y1 + k−2 y2 , dt dy2 = k2 y1 − k−2 y2 , dt 2 (11) which describes the slow kinetics. The fast kinetics follow (from multiplication by ψ3 , and ψ4 ) dP00 1 z1 −k2 k−2 z1 κ1 dt − κ−1 dPdt10 = − (k1 + k−1 ) + (12) z2 k2 −k−2 z2 κ1 dPdt01 − κ−1 dPdt11 ǫ where z1 = κ1 P00 − κ−1 P10 , and z2 = κ1 P00 − κ−1 P10 . Thus, the leading order qss approximation has z1 = z2 = 0, or κ1 P00 − κ−1 P10 = 0, and κ1 P00 − κ−1 P10 = 0, That is, P00 = y1 2.2 κ−1 , κ1 + κ−1 P10 = y1 κ1 , κ1 + κ−1 P01 = y2 κ−1 , κ1 + κ−1 P11 = y2 κ−1 . κ1 + κ−1 (13) Adiabatic Reduction for Master Equations This same technology can be used to find the slow evolution of drift-jump stochastic processes. We suppose that the transitions between xk states are fast. If this is the case, then we can write the master equation system as ∂p ∂ 1 = − (Fp) + Ap. ∂t ∂y ǫ (14) Now, it must be that the matrix A has a zero eigenvalue with eigenvector φ. The corresponding left eigenvector is ψ with entries (ψj ) = 1. We assume that hφ, ψi = 1. Using these, we split p into two parts p = vφ + w (15) where hp, ψi = v, and hw, ψi = 0. It follows that and ∂v ∂ = −ψ T (F(vφ + w)), ∂t ∂y (16) 1 ∂ ∂ ∂w = Aw − (Fp) + ψ T (Fp)φ. ∂t ǫ ∂y ∂y (17) Here, the fast behavior of w is evident, so we take w to be in quasi-steady state. Thus, we take ∂ ∂ (18) Aw = ǫ (vFφ) − ǫψ T (vFφ)φ + O(ǫ2 ). ∂y ∂y This equation can be solved uniquely for w subject to the constraint ψ T w = 0; we denote this as ∂ ∂ w = ǫA⊥ (vFφ) − ǫA⊥ ψ T (vFφ)φ + O(ǫ2 ), (19) ∂y ∂y where A⊥ is the inverse of the properly constrained A. Consequently, ∂ ∂ T ∂ ∂v T ⊥ T ∂ ǫψ FA = − (ψ Fvφ) − (vFφ) − ψ (vFφ)φ , ∂t ∂y ∂y ∂y ∂y 3 (20) 2.3 Jump Velocity Processes Consider the simple example of a stochastic differential equation dy = kx, dt (21) where x is either 0 or 1, with transition rates α and β. The F-P equation is ∂kp ∂p = αq − βp − ∂t ∂y ∂q = βp − αq ∂t We can reduce this to a single pde by observing that ∂q ∂t = − ∂p − ∂t ptt = −(α + β)pt − αkpy − kpty . (22) (23) ∂ap ∂y so that (24) Suppose that α and β are large compared to k. Then the exchange between states is fast relative to the rate of change of y, and we should be able to do a qss reduction. To do so, 1 α we introduce dimensionless time (set k = 1) and let ǫ = α+β , and introduce a = α+β and β b = α+β , so that a + b = 1. In terms of these variables, the F-P equations are 1 ∂p ∂p = (aq − bp) − , ∂t ǫ ∂y 1 ∂q = (bp − aq). ∂t ǫ (25) (26) We introduce the change of variables v = p + q, w = bp − aq, (27) q = bv − w. (28) so that p = av + w, In terms of these variables the F-P equations are ∂v ∂av ∂w = − − ∂t ∂y ∂y 1 ∂av ∂w ∂w = − w−b −b ∂t ǫ ∂y ∂y (29) (30) Now we see the obvious fast-slow separation and take w to be in quasi-steady state, so that w = −ǫb ∂av + O(ǫ2 ), ∂y (31) from which it follows that ∂v ∂av ∂ ∂av =− + (ǫb ) + O(ǫ2 ), ∂t ∂y ∂y ∂y which is the standard F-P equation we seek. 4 (32) 2.3.1 More generally For the more general problem dy = xf (y) − g(y), dt (33) the F-P equations are 1 ∂p = (aq − bp) − ∂t ǫ ∂q 1 = (bp − aq) + ∂t ǫ ∂ ((f − g)p), ∂y ∂ (gq). ∂y (34) (35) We now introduce the change of variables (27) and find ∂v ∂ = − ((af − g)v + f w), ∂t ∂y ∂w 1 ∂ ∂ = − w − a (gq) − b ((f − g)p). ∂t ǫ ∂y ∂y (36) (37) Again, the fast-slow separation is apparent and we take w to be in quasi-steady state, so that ∂ ∂ (38) w = ǫ(−a (gbv) − b ((f − g)av)) + O(ǫ2 ), ∂y ∂y from which it follows that ∂v ∂ ∂ = − ((af − g)v) + ∂t ∂y ∂y ∂ ∂b ǫf b (f av) + ǫf gv + O(ǫ2 ), ∂y ∂y which is the F-P equation we seek. 5 (39)