Name _KEy Differential Equations and Linear Algebra 2250 Midterm Exam 2 Version 1, 21 Mar 2014 Instructions: This in-class exam is designed to be completed in 30 minutes. No calculators, notes, tables or books. No answer check is expected. Details count 3/4, answers count 1/4. 1. (The 3 Possibilities with Symbols) Let a, b and c denote constants and consider the system of equations ‘&: b—3 2b—4 i—b b—i a a 0 a 2 3 —i 1 = z b — 2 b 2 b —b +b 2 b Tk JJ tYtCk yOc ‘rlut D... SyS1Lr., ta±e (a) [40%] Determine a and b such that the system has a unique solution. (b) [30%] Explain why a = 0 and b = b 0 implies no solution. Ignore any other possible no solution cases. 4n: (c) [30%] Explain why a = 0 implies infinitely many solutions. Ignore any other possible infinitely many solution cases. 1 /-3 c..e — vc.e fr’ee v&ht -b b-3 2. 2 o I’ j—I, \ 0 (o(3,’,, — -I t) Ck 2 2 C.o4’( ‘ 1) ( i) ) —6 6—3 o19)2) -) —io 0 02 — Corr. 1)0(1)1)1) 0- — o a. ec%%&M. LLVeq4 1 € ci’tr 0 2 - 0 I (0 2. f— ‘- 0 O 0 Use this page to start your solution, Attach extra pages as needed. 6V i I :: vç 0 c et I \_\ c) 2 °N 2.. 2 -&’z, I 1 s2Ap 2250 Midterm Exam 2 S2014 [2lMar] Name. 2. (Vector Spaces) Do all parts. Details not required for (a-(d). ()( )() (a) [10%] or fhlse: The span of the vectors is a subspace of of , , 0 dimension 2. t , (b) [10%] True or A matrix equationA b has a solution if and only if the matrix A has an VM inverse. t+ (c) [10%] rue or false: Relation x + y = 2x + z defines a subspace in 7?. 1\ (d) [10%] rue or false: The span of er, e, sinh(x) is a subspace of the vector space of functions continuous on —oo <x < (e) [20%] State two linear algebra theorems that apply to conclude that the set S = span(1, x, x2) is a subspace of the vector space of all polynomials. Do not present details, but please state the theorems fully. (f) [40%] Find a basis of vectors for the subspace of 7? given by the system of restriction equations . 311 + + 2x + 211 ç ® ILL Is ‘\ ‘a 0 I 2. 0 0 13 2. (3 c’ o 2. 414 212 + 414 LL) 13 a = = = V .- c f’ LLSW7c I 02- t 0 ( I I \ ‘ 2 L) o’4o(3) A4)1) I CZ c20 RF — L) (‘ I C 22 - { I Q D2LU0\ 2. I L 0 2 c.ew(3)I)_I) I ft 2COC) — 1 x -)D 2 — 1 ) Use this page to start your solution. Attach exa pages as mieded. 1 H \ I Q(I))-i) ] tu..L+(I) ‘a 9C22.I 0 c,0 Il 2 a lo 00 0 pv-4 V IL Lç g’ c’ 0 0 4 V Lto !2. O\\ fri,fpL.C.. )V. 0 f2r V c$øv 3 j i 0 10x 4x 12x S.) Syc1ri i21) OILj 0, 0, 0, 0. = ‘1. flo\ -o’kio t 415 o) 4s-f c Io + + + + c... f4 ‘ 2x 4fafr* ,4 (t’ 214 + + 12 0 Ut: — ¼.) rLy,2.) —i) 2250 Midterm Exam 2 S2014 [2lMar] Name. / 3. (Independence and Dependence) Do all parts. (a) [10%] State an independence test for 3 vectors in R. . Write the hypothesis and conclusion, not just 5 the name of the test. (b) [10%] State fully an independence test for 3 functions, each is which is a linear combination of Euler solution atoms, e.g., e, cosh(x), sin(x) + x. No details are expected, but please state the test fully. (c) [40%] Let v , v 1 , v 2 , v 3 4 denote the rows of the matrix A— — 0 0 0 0 —2 1 2 1 —6 0 0 2 1 0 510 301 Decide if the four rows , v 2 i ,v 3 4 are independent and display the details of the chosen independence test. (d) [40%] Extract from the list below a largest set of independent vectors. , j= 0 0 0 0 0 0 2 2 —2 2 ,= 0 1 1 —1 1 ,= 0 1 1 1 3 0 3 3 —1 5 ,t= 0 0 0 2 2 sc )LvpJ c- ‘ ø-- rr%4 1() 7 - ck) c * ? P4 3c9 W ‘& i ci i, r\ f\Dj 8A DOO00 (io. 3 I II \o-1— \o2 fo2 0 (CL4L4t I i ç ° Lo O2,2 1 AT1 io2L 3\ C 1 r4\1,o 0 H Z C 2’ \ I /rl roL)3 &4 Sb.rLf I 00 LO Ioc’ I o i c Use this page to start your solution. Attach extra pages as needed. J o22\ C) D 4 00 0 j 2250 Midterm Exam 2 52014 [2lMar] Name. 4. (Determinants) Do all parts. (a) [10%] True o The toolkit operations of swap, combination and multiply apply to determinants 7 D4 and leave the value of the determinant unchanged. (b) [10%] True or For 3 x 3 matrices A and B, ]A+ B = 1A + B. (c) [20%] Assume given 3 x 3 matrices A, B. Suppose A , B 2 3 are elementary B =E 2 1 and E 2 3 , E 1 matrices representing respectively a combination, a multiply by —3 and a swap. Assume det(B) 9. Let C = 3A. Find all possible values of det(C). (d) [30%] Suppose matrix C is 8 x 8, nonzero but C 2 = 0. Let B = I C and A = I + C. Explain why B is the inverse of A. (e) [30%] Let symbols a, b, c denote constants. Define matrix r 8. —r X2 — A— — llOa 1 0 0 0 abOl 1 c12 0. Then the adjugate [adjoint] formula for the inverse is defined. Find the value of the entry in row 2, column 3 of A’. Assume ]A 4(3 C= (-XO=i ç Ag cCr-c c #, AL(’Nft&. -x’ £4CC X7/( — 1 &tAt UQ C - 3 - — b’.-N) 0 Cl 2 i.c. L2_ Use this page to start your solution. Attach extra pages as needed. ) 2250 Midterm Exam 2 S2014 [2lMar] Name. 5. (Linear Differential Equations) Do all parts. (a) [20%] Solve for the general solution of 12y” -I- hg’ + 2 y = 0. 5)2 (b) [40%] The characteristic equation is (4r 4 2 )(r 2r + r = 0. Find the general solution y of the linear homogeneous constant-coefficient differential equation. (c) [20%] A fourth order linear homogeneous differential equation with constant coefficients has a par ticular solution 2e + sin(x) + xe. Find the roots of the characteristic equation. (d) [20%] Mark with X the functions which can possibly be be a solution of a linear homogeneous differential equation with constant coefficients. Test your choices against this theorem: — — The general solution of a linear homogeneous nth order differential equation with constant coefficients is a linear combination of Euler solution atoms. r \2-I-iIr 4-2 — z) (‘j-’ )i IAIh /L ,½ = 0) = t-o1c °>k ) I ±2 ;)LA 1) Y ecos2 _—l ,((xI) iyot oii XTt O Use this page to start your solution. Attach extra pages as needed. %+i1 1f 4 LA3