. (k.) () 4i?s.’/

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Math 1050—4 Midterm Exam #3
April 17, 2015
.
No notes, books, etc. are allowed.
• Answer the questions
in
the spaces provided.
• You have 50 minutes to complete this exam.
• Good luck!
Name:
4i?s.’/
uNID:
For #1—7, are the statements true or false?
1. (1 point) aXaY
2. (1 point)
log,(zw)
3.
log(,(zW)
(1 point)
log(z) + 1
log
(
w)
=
=
log(z)lV
4.
(1 point)
5.
(ipoint) (a =a
6.
(1 point) 1og
7.
(1 point)
A
[Ct
1.
/z
()
2.
O
a
—
()
F1 P
.
Fcd
5.
logo (z)
\
(k.)
1og(w)
Ue
linear equation in two variables (ax +
i
by
=
()
r)
—
has a two solutions.
7.
For #8—10, write the expression as a rational
number in standard form.
8.
(1 point)
4SOO43O4_27
—
.
=
-
Li
12
9. (1
point)
(3)
9.
10. (1
point)
10,
000
I,
c
10.
1
/
oDD
Points earned:
out of a possible
10
points
ber in standard form.
For #11—12, write the expression as a rational num
11. (1
point)
, 000)
g
10
1o
(10
/c
(ice)
11.
1
3 ()
12. (1 point) log
/y
(/3)
/
4/3
12
13. (1 point) Solve for x if log(,(x)
form.)
=
standard
—2. (Write your answer as a rational number in
x: (c
I’
13.
Page 2
Points earned:
out of a possible 3 points
C
U
C
A
p..
(.AJ
A
p.,
..:I
c_I
r’
I
—13
J9
-4.-
p.
A
-
-
‘l•
0
—
—.
(.11
-
c__
—
I,
—
-.
—
—
—t
L
(1
N
‘
H
H
Ui
.)
L
17. (5 poiiils) Graph p(x)
I
1
=
—
4
(x
—
+
2)
())(2)(2)(2)<
0
1) (x
+
2) (x
+
2) (x
2
-
J
€ir&ph
lb
2
1
—5
18. (5points) Graphr(x)
—3(x
—
2
2)(x
+
5
4
3
4)
5(x+1)(x+1)
0
=
LcicLltJE
_3L)
C
&)
—
5
I
I
—5
I
—4
—3
—2
—1
0
I Page 4
1
2
I
I
3
4
5
Points earned:
out of a possible 10 points
For #22—25, graph the function, label its x- and y-intercepts (if there are any), and draw its
vertical and horizontal asymptotes (if any).
/
19. (3 points) e + 1
21. (3 points) Graph g :
where
ifx
ifx
I
I
I
(—oo,0)
E
—
I
—
oo)
I
I
20. (3 points) log(x
[0,
/
1)
Page 5
I
I
‘V
Points earned:
out of a possible 9 points
22.
(a) (1
point)
What
the slope of the line 30x
is
2?
—
j
3c
—
/
(a)
(b) (2 poiuts) Is there a unique solution to the following system?
/0
30x—3y=2
—3x
+
=
by
?
7
—
5/oo
D J re
i
.
—
/
(‘1 .i’
(b)
Find the solu
23. (2 points) The following system of two linear equations has a unique solution.
tion.
x
2x
2
=
—
+
3y
1
5
/
Ci
•
i
cJ
(f
j
3
L
23
3
Page 6
a
Points earned:
out of a possible 5 points
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