Math 237-101 Summer 2013 Quiz 7, June 18 Carter Name Express the matrix " M= 4 7 7 9 # as a linear combination of the matrices A, B, and C where " A= # 1 1 1 1 " , B= 1 2 3 4 # " , and C = Solution. This is tantamount to solving the system of below: 1 1 1 x 1 2 1 · y = 1 3 4 z 1 4 5 1 1 4 5 # . equations (written in matrix form) 4 7 7 9 1 0 0 0 . We row reduce the augmented matrix 1 1 1 1 1 2 3 4 1 1 4 5 R2 − R1 7→ R20 R3 − R1 7→ R30 4 0 7 R4 − R1 7→ R4 −→ 7 9 R1 − R2 7→ R10 R3 − 2R2 7→ R30 R4 − 2R2 7→ R40 −→ 1 0 0 0 0 1 0 0 1 1 2 3 1 1 0 3 3 −3 4 −4 1 0 3 4 4 3 3 5 Thus z = −1, y = 3, and consequently x = 2. We have " M= 4 7 7 9 # " =2 1 1 1 1 # " +3 1 2 3 4 # " − 1 1 4 5 # = 2A + 3B + (−1)C.