[SHIVOK SP212] February 8, 2016 CH 26 CurrentandResistance I. ElectricCurrent: A. Althoughanelectriccurrentisastreamofmovingcharges,notall movingchargesconstituteanelectriccurrent.Ifthereistobean electriccurrentthroughagivensurface,theremustbeanetflowof chargethroughthatsurface.Twoexamplesaregiven. 1. Thefreeelectrons(conductionelectrons)inanisolatedlengthof copperwireareinrandommotionatspeedsoftheorderof106m/s.Ifyou passahypotheticalplanethroughsuchawire,conductionelectronspass throughitinbothdirectionsattherateofmanybillionspersecond—but thereisnonettransportofchargeandthusnocurrentthroughthewire. However,ifyouconnecttheendsofthewiretoabattery,youslightlybiasthe flowinonedirection,withtheresultthattherenowisanettransportof chargeandthusanelectriccurrentthroughthewire. 2. Theflowofwaterthroughagardenhoserepresentsthedirectedflow ofpositivecharge(theprotonsinthewatermolecules)atarateofperhaps severalmillioncoulombspersecond.Thereisnonettransportofcharge, becausethereisaparallelflowofnegativecharge(theelectronsinthewater molecules)ofexactlythesameamountmovinginexactlythesamedirection. B. Diagram Page1 [SHIVOK SP212] February 8, 2016 C. Thefigurebelowshowsasectionofaconductor,partofa conductingloopinwhichcurrenthasbeenestablished.Ifchargedq passesthroughahypotheticalplane(suchasaa’)intimedt,thenthe currentithroughthatplaneisdefinedas: 1. Thechargethatpassesthroughtheplaneinatimeintervalextending from0totis: 2. Understeady‐stateconditions,thecurrentisthesameforplanesaa’, bb’,andcc’andforallplanesthatpasscompletelythroughtheconductor,no matterwhattheirlocationororientation. 3. TheSIunitforcurrentisthecoulombpersecond,ortheampere(A): D. SampleProblem: 1. Anisolatedconductingspherehasa10cmradius.Onewirecarriesa currentof1.0000020Aintoit.Anotherwirecarriesacurrentof 1.0000000Aoutofit.Howlongwouldittakeforthespheretoincreasein potentialby1000V? Page2 [SHIVOK SP212] February 8, 2016 II. ElectricCurrent,ConservationofCharge,andDirectionofCurrent A. Acurrentarrowisdrawninthedirectioninwhichpositivecharge carrierswouldmove,eveniftheactualchargecarriersarenegative andmoveintheoppositedirection. 1. Diagram III. CurrentDensity A. Themagnitudeofcurrentdensity,J,isequaltothecurrentperunit areathroughanyelementofcrosssection.Ithasthesamedirectionas thevelocityofthemovingchargesiftheyarepositiveandtheopposite directioniftheyarenegative. B. IfthecurrentisuniformacrossthesurfaceandparalleltodA,then JisalsouniformandparalleltodA. Here, A is the total area of the surface. Page3 [SHIVOK SP212] February 8, 2016 C. TheSIunitforcurrentdensityistheamperepersquaremeter 2 (A/m ). D. Diagram 1. Figure26‐4showshowcurrentdensitycanberepresentedwitha similarsetoflines,whichwecancallstreamlines. 2. Thecurrent,whichistowardtheright,makesatransitionfromthe widerconductoratthelefttothenarrowerconductorattheright.Since chargeisconservedduringthetransition,theamountofchargeandthusthe amountofcurrentcannotchange. 3. However,thecurrentdensitychanges—itisgreaterinthenarrower conductor. E. SampleProblem: 1. Afuseinanelectriccircuitisawirethatisdesignedtomelt,and therebyopenthecircuit,ifthecurrentexceedsapredeterminedvalue. Supposethatthematerialtobeusedinafusemeltswhenthecurrentdensity risesto440A/cm2.Whatdiameterofcylindricalwireshouldbeusedtomake afusethatwilllimitthecurrentto0.50A? Page4 [SHIVOK SP212] February 8, 2016 F. CurrentDensity,DriftSpeed 1. Whenaconductorhasacurrentpassingthroughit,theelectronsmove randomly,buttheytendtodriftwithadriftspeedvdinthedirectionopposite thatoftheappliedelectricfieldthatcausesthecurrent.Thedriftspeedistiny comparedwiththespeedsintherandommotion. 2. Inthefigurebelow,theequivalentdriftofpositivechargecarriersisin thedirectionoftheappliedelectricfield,E.Ifweassumethatthesecharge carriersallmovewiththesamedriftspeedvdandthatthecurrentdensityJis uniformacrossthewire’scross‐sectionalareaA,thenthenumberofcharge carriersinalengthLofthewireisnAL.Herenisthenumberofcarriersper unitvolume. 3. ThetotalchargeofthecarriersinthelengthL,eachwithchargee,is then 4. Thetotalchargemovesthroughanycrosssectionofthewireinthe timeinterval Page5 [SHIVOK SP212] February 8, 2016 IV. ResistanceandResistivity: A. Wedeterminetheresistancebetweenanytwopointsofa conductorbyapplyingapotentialdifferenceVbetweenthosepoints andmeasuringthecurrentithatresults.TheresistanceRisthen B. TheSIunitforresistancethatfollowsfromEq.26‐8isthevoltper ampere.Thishasaspecialname,theohm(symbol): C. Inacircuitdiagram,werepresentaresistorandaresistancewith thesymbol D. Picture 1. Remember,Isentthecolorcodesoutlastnight(email). Page6 [SHIVOK SP212] February 8, 2016 E. Resistivity 1. Theresistivity,,ofaresistorisdefinedas: a) 2. TheSIunitforis.m. 3. Theconductivityofamaterialisthereciprocalofitsresistivity: a) 4. ExampleTable Page7 [SHIVOK SP212] February 8, 2016 F. Note:Resistanceisapropertyofanobject.Resistivityisa propertyofamaterial. G. EquationforResistance 1. Proof: a) Ifthestreamlinesrepresentingthecurrentdensityareuniform throughoutthewire,theelectricfield,E,andthecurrentdensity,J,will beconstantforallpointswithinthewire. b) c) d) Thus Page8 [SHIVOK SP212] February 8, 2016 H. ResistanceandResistivity,VariationwithTemperature: 1. Therelationbetweentemperatureandresistivityforcopper—andfor metalsingeneral—isfairlylinearoveraratherbroadtemperaturerange.For suchlinearrelationswecanwriteanempiricalapproximationthatisgood enoughformostengineeringpurposes: 2. Graph I. Sampleproblem: 1. Acommonflashlightbulbisratedat0.30Aand2.9V(thevaluesofthe currentandvoltageunderoperatingconditions).Iftheresistanceofthe tungstenbulbfilamentatroomtemperature(20°C)is1.1Ω,whatisthe temperatureofthefilamentwhenthebulbison? Page9 [SHIVOK SP212] February 8, 2016 V. Ohm’sLaw: A. Ohm’sLawisanassertionthatthecurrentthroughadeviceis ALWAYSdirectlyproportionaltothepotentialdifferenceappliedto thedevice. B. AconductingdeviceobeysOhm’sLawwhentheresistanceofthe deviceisindependentofthemagnitudeandpolarityoftheapplied potentialdifference. C. AconductingmaterialobeysOhm’sLawwhentheresistivityofthe materialisindependentofthemagnitudeanddirectionoftheapplied electricfield. D. Diagrams/graphs Page 10 [SHIVOK SP212] February 8, 2016 E. AMacroscopicViewofOhm’sLaw: 1. Itisoftenassumedthattheconductionelectronsinametalmovewith asingleeffectivespeedv ,andthisspeedisessentiallyindependentofthe eff 6 temperature.Forcopper,v =1.6x10 m/s. eff 2. Whenweapplyanelectricfieldtoametalsample,theelectronsmodify theirrandommotionsslightlyanddriftveryslowly—inadirectionopposite thatofthefield—withanaveragedriftspeedv .Thedriftspeedinatypical d ‐7 6 metallicconductorisabout5x10 m/s,lessthantheeffectivespeed(1.6x10 m/s)bymanyordersofmagnitude. 3. Themotionofconductionelectronsinanelectricfieldisacombination ofthemotionduetorandomcollisionsandthatduetoE. 4. IfanelectronofmassmisplacedinanelectricfieldofmagnitudeE,the electronwillexperienceanacceleration: 5. Intheaveragetimebetweencollisions,theaverageelectronwill acquireadriftspeedofv =a. d 6. Thus Page 11 [SHIVOK SP212] February 8, 2016 VI. PowerinElectricCircuits: A. Inthefigurebelow,thereisanexternalconductingpathbetween thetwoterminalsofthebattery.Asteadycurrentiisproducedinthe circuit,directedfromterminalatoterminalb.Theamountofcharge dqthatmovesbetweenthoseterminalsintimeintervaldtisequaltoi dt. B. Thischargedqmovesthroughadecreaseinpotentialof magnitudeV,andthusitselectricpotentialenergydecreasesin magnitudebytheamount C. ThepowerPassociatedwiththattransferistherateoftransfer dU/dt,givenby Page 12 [SHIVOK SP212] February 8, 2016 D. Theunitofpoweristhevolt‐ampere(VA). E. Sampleproblem: 1. InFig.below(a),a20Ωresistorisconnectedtoabattery.Figurebelow (b)showstheincreaseofthermalenergyEthintheresistorasafunctionof timet.TheverticalscaleissetbyEth,s=2.50mJ,andthehorizontalscaleisset byts=4.0s.Whatistheelectricpotentialacrossthebattery? Page 13 [SHIVOK SP212] February 8, 2016 VII. Semiconductors: A. Puresiliconhasahighresistivityanditiseffectivelyaninsulator. However,itsresistivitycanbegreatlyreducedinacontrolledwayby addingminuteamountsofspecific“impurity”atomsinaprocess calleddoping. B. Asemiconductorislikeaninsulatorexceptthattheenergy requiredtofreesomeelectronsisnotquitesogreat.Theprocessof dopingcansupplyelectronsorpositivechargecarriersthatarevery looselyheldwithinthematerialandthusareeasytogetmoving.Also, bycontrollingthedopingofasemiconductor,onecancontrolthe densityofchargecarriersthatareresponsibleforacurrent. C. Theresistivityinaconductorisgivenby: D. Inasemiconductor,nissmallbutincreasesveryrapidlywith temperatureastheincreasedthermalagitationmakesmorecharge carriersavailable.Thiscausesadecreaseofresistivitywithincreasing temperature.Thesameincreaseincollisionratethatisnotedfor metalsalsooccursforsemiconductors,butitseffectisswampedby therapidincreaseinthenumberofchargecarriers. E. Table Page 14 [SHIVOK SP212] February 8, 2016 VIII. Superconductors: A. In1911,DutchphysicistKamerlinghOnnesdiscoveredthatthe resistivityofmercuryabsolutelydisappearsattemperaturesbelow about4K.Thisphenomenoniscalledsuperconductivity,anditmeans thatchargecanflowthroughasuperconductingconductorwithout losingitsenergytothermalenergy. B. Oneexplanationforsuperconductivityisthattheelectronsthat makeupthecurrentmoveincoordinatedpairs.Oneoftheelectrons inapairmayelectricallydistortthemolecularstructureofthe superconductingmaterialasitmovesthrough,creatingnearbya short‐livedconcentrationofpositivecharge.Theotherelectroninthe pairmaythenbeattractedtowardthispositivecharge.Such coordinationbetweenelectronswouldpreventthemfromcolliding withthemoleculesofthematerialandthuswouldeliminateelectrical resistance.Newtheoriesappeartobeneededforthenewer,higher temperaturesuperconductors. Page 15