The Schrodinger Equation, Stationary States and Physical Conditions Ch 2: When things go fast, use Special Relativity. Ch 3: Light is a particle (photon) Ch 4: Matter is a wave Test 2 22OCT15 on Chapter 3 and 4. (Note NOT Chapter 2). Light homework this week. Memorize the follow equations: (3-3) p. 80 (first eqn) (3-8) (4-4) and (4-5) {notice similarity to (3-2) and (3-7)} (4-8) (4-9) (4-10) (4-14) and (4-15) (4-20) (not the middle part) For each equation be sure you know the meaning of each variable and when the equation is applicable. So far, we’ve applied Schrodinger’s equation to a free particle. Now we apply Schrodinger’s equation to bound states A bound particle is in a system with a welldefined potential energy U (x) ℏ2 𝜕𝜕2 Ψ(𝑥𝑥,𝑡𝑡) − 2𝑚𝑚 𝜕𝜕𝜕𝜕 2 + 𝑈𝑈(𝑥𝑥)Ψ(𝑥𝑥, 𝑡𝑡) = 𝜕𝜕Ψ(𝑥𝑥,𝑡𝑡) 𝑖𝑖ℏ 𝜕𝜕𝜕𝜕 Compare to free particle version: ℏ2 𝜕𝜕 2 Ψ(𝑥𝑥, 𝑡𝑡) 𝜕𝜕Ψ(𝑥𝑥, 𝑡𝑡) − = 𝑖𝑖ℏ 2 2𝑚𝑚 𝜕𝜕𝜕𝜕 𝜕𝜕𝜕𝜕 Separation of variables: Ψ 𝑥𝑥, 𝑡𝑡 = 𝜓𝜓(𝑥𝑥)𝜙𝜙(𝑡𝑡) Insert ℏ2 𝜕𝜕2 Ψ(𝑥𝑥,𝑡𝑡) :− + 2𝑚𝑚 𝜕𝜕𝜕𝜕 2 𝑈𝑈(𝑥𝑥)Ψ(𝑥𝑥, 𝑡𝑡) = 𝜕𝜕Ψ(𝑥𝑥,𝑡𝑡) 𝑖𝑖ℏ 𝜕𝜕𝜕𝜕 ℏ2 𝜕𝜕 2 𝜓𝜓(𝑥𝑥) 𝜕𝜕𝜕𝜕(𝑡𝑡) − 𝜙𝜙(𝑡𝑡) + 𝑈𝑈(𝑥𝑥)𝜙𝜙(𝑡𝑡)𝜓𝜓(𝑥𝑥) = 𝑖𝑖ℏ𝜓𝜓(𝑥𝑥) 2 2𝑚𝑚 𝜕𝜕𝜕𝜕 𝜕𝜕𝜕𝜕 ℏ2 𝜕𝜕 2 𝜓𝜓(𝑥𝑥) 𝜕𝜕𝜕𝜕(𝑡𝑡) − 𝜙𝜙(𝑡𝑡) + 𝑈𝑈(𝑥𝑥)𝜙𝜙(𝑡𝑡)𝜓𝜓(𝑥𝑥) = 𝑖𝑖ℏ𝜓𝜓(𝑥𝑥) 2 𝜕𝜕𝜕𝜕 2𝑚𝑚 𝜕𝜕𝜕𝜕 Divide by 𝜓𝜓(𝑥𝑥)𝜙𝜙(𝑡𝑡), ℏ2 1 𝜕𝜕 2 𝜓𝜓(𝑥𝑥) 1 𝜕𝜕𝜕𝜕(𝑡𝑡) − + 𝑈𝑈(𝑥𝑥) = 𝑖𝑖ℏ 2 𝜙𝜙(𝑡𝑡) 𝜕𝜕𝜕𝜕 2𝑚𝑚 𝜓𝜓(𝑥𝑥) 𝜕𝜕𝜕𝜕 Left is depends only on space (x), the right only on time (t) Only possible if both sides equal the same constant C Solution is 1 𝜕𝜕𝜕𝜕(𝑡𝑡) 𝑖𝑖ℏ 𝜙𝜙(𝑡𝑡) 𝜕𝜕𝜕𝜕 =C 𝜙𝜙 𝑡𝑡 = 𝑒𝑒 −𝑖𝑖𝜔𝜔𝑡𝑡 where 𝐶𝐶 = 𝐸𝐸 = ℏ𝜔𝜔 (memorize the solution) Ψ 𝑥𝑥, 𝑡𝑡 = 𝜓𝜓 𝑥𝑥 𝜙𝜙 𝑡𝑡 = 𝜓𝜓 𝑥𝑥 𝑒𝑒 −𝑖𝑖𝜔𝜔𝑡𝑡 So Ψ 𝑥𝑥, 𝑡𝑡 2 = 𝜓𝜓 ∗ 𝑥𝑥 𝑒𝑒 +𝑖𝑖𝜔𝜔𝑡𝑡 𝜓𝜓 𝑥𝑥 𝑒𝑒 −𝑖𝑖𝜔𝜔𝑡𝑡 = 𝜓𝜓 𝑥𝑥 2 Does not depend on time! Probability density (not the wave function) is what we measure. Particle’s probability density does not change in time; called stationary state. 𝑀𝑀𝑀𝑀𝑀𝑀𝑀𝑀𝑀𝑀𝑀𝑀𝑀𝑀𝑀𝑀 ℏ2 𝜕𝜕2 𝜓𝜓 𝑥𝑥 − 2𝑚𝑚 𝜕𝜕𝜕𝜕 2 + 𝑈𝑈 𝑥𝑥 𝜓𝜓 𝑥𝑥 = 𝐸𝐸𝜓𝜓 𝑥𝑥 ( I set C = E, and multiplied by 𝜓𝜓 𝑥𝑥 .) Total probability of finding particle must be 1. Ensuring this is called “normalization”. Given by ∫𝑎𝑎𝑙𝑙𝑙𝑙 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠 Ψ 𝑥𝑥, 𝑡𝑡 2 𝑑𝑑𝑑𝑑 = 1 Also save function must also be smooth so we can take two derivatives Ch 5: 2, 3, 5, 6 and 19. Work 19 on the board.