F6 _77,IT: ROOM STRESSES IN A LAI D JOINT WITH ELASTIC ADHESIVE 14o. 1864 September 1957 R A 4,,t. FEB 171958 v.v *PATE Co This Report is One of a Series Issued in Cooperation with the ANC-23 PANEL ON SANDWICH. CONSTRUCTION MR AIRCRAFT of the Departments of the AIR FORCE, NAVY, AND COMMERCE H II111111111rIlm in.1[111[,' 1111111111111l FOREST PRODUCTS LABORATORY MADISON 5, WISCONSIN UNITED STATES DEPARTMENT OF AGRICULTURE FOREST SERVICE In Cooperation with the University of Wisconsin t TABLE OF CONTENTS Page I. SUMMARY 1 II. INTRODUCTION 1 III. NOTATION 2 IV. THEORETICAL ANALYSIS 4 V. NUMERICAL COMPUTATIONS 24 VI. CONCLUSIONS 27 VII. REFERENCES 28 VIII. ACKNOWLEDGEMENTS. 29 IX. APPENDICES 30 X. Appendix A -- Integration Formulas 30 Appendix B -- Euler Transformation for Divergent Series 32 FIGURES 33 — STRESSES IN A LAP JOINT WITH ELASTIC ADHESIVE ! By R. E. SHERRER, Engineer Forest Products Laboratory, ? Forest Service U. S. Department of Agriculture I. SUMMARY A theoretical solution for the displacements and stresses in the adhesive of a lap joint loaded in tension is presented. The solution is applicable for an anti-symmetrical jointwith arbitrary overlap, adhesive thickness and plate thickness and for adhesive and plates of any arbitrary combination of materials. Elementary theory of bending is used for the plates and theory of elasticity is used for the adhesive. The usual limitations of these theories apply to the solution. Numerical results and curves are included. II. INTRODUCTION The purpose of this report is to solve the following problem: Given two rectangular sheets of any isotropic material and of equal thickness t, of unit width, and of length (/ + 2c) (see figure 1), lap-jointed !This report is one of a series (ANC-23, Item 51-4) prepared and distributed by the U. S. Forest Products Laboratory under U. S. Navy Bureau of Aeronautics Order No. NAer 01628 and U. S. Air Force No. AF-18 (600)-102 and DO 33(616)-53-20. Results here reported are preliminary and may be revised as additional data become available. ?Maintained at Madison, 'Wis., in cooperation with the University of Wisconsin. Rept. No. 1864 2. over a length 2c, bonded by an adhesive layer of any isotropic material and of thickness 2b, and acted upon by tensile forces of magnitude T o per unit sheet width, find the displacements and stresses of all points within the adhesive. For the solution in this report, a free body of the joint section (see figure 2) acted upon by loads as computed in reference 1 will be used. Elementary theory of bending will be used on the rectangular sheets (henceforth called plates) and theory of elasticity, using the Saint-Venant principle on the free edges, will be used for the adhesive. Plane strain is assumed. III. NOTATION x, y rectangular coordinates (figure 1) 2c length of joint 2b thickness of adhesive t thickness of each plate G shear modulus of elasticity for adhesive Poisson' s ratio for adhesive E Young' s modulus for plates D flexural rigidity per unit width of plate G' 2Gc non-dimensional rigidity factor Et D' Dnon-dimensional rigidity factor 2 2Gtc T tension in plate per unit width 3. M moment in plate per unit width V transverse shear in plate per unit width To value of T at beginning of joint Mo estimated value of M at beginning of joint T' M' Vt To , non-dimensional tension factor 4Gc Mc 12 D , non-dimensional moment factor Vo • non-dimensional shear factor 4Gc2 Cro normal unit stress of adhesive on plate To tangential unit stress of adhesive on plate v odeflection of plate surface in contact with adhesive uohorizontal displacement of plate surface in contact with adhesive vp deflection of center plane of plate up horizontal displacement of center plane of plate u, v displacements of adhesive o , o-y , , T xy plane stresses in adhesive do cosh an b en s inh ftn b 4. fn anb sinh anb - (1 - 2p.) cosh anb gn f3n b cosh Pn b - (1 - 2p.) sinh f3nb h n anb sinh an b - (3 - 4p.) cosh anb in Pn b cosh (an b - (3 - 4p.) sinh Pnb in anb cosh an b - 2(1 - p.) sinh anb kn sinh an b fn an b cosh anb mn Pn b sinh 13n b nncosh On b grib sinh Pnb - 2(1 - IA) cosh Pnb on IV. THEORETICAL ANALYSIS To simplify the writing, the units of length will be taken such as to make c equal to unity. This will have the effect of making b, t, u, v, , vp and the coordinates x and y non-dimensional, since b u o , vo , up will be written for b/c, t for t/c, etc. From the free-body diagram shown in figure 3 0 a- o dV -dx .T.0 _ dT 0 dv dM 2 dx dx 0 5. where the moment M is given by M=D d 2 v, (4) Elimination of V and M gives dv. dr_ d4v Dd x4 P + Cr° = dx (T) (5) as the differential equation for the plates. It will be assumed that the displacements of the central plane of the upper plate are related to the displacements of the lower surface of the plate as follows: v " = vo t dvo • u — dx p = uoZ These assumptions are in accord with the elementary theory of bending used for the plates. The unit strain at the central plane of the plate is given by dup T dx Et (8) From equations (7) and (8) T Et duo t d2vo =0 dx 2 dx (9) Equations (5) and (9) are the two differential equations to be solved. It 6. is noted that the term on the right side of equation (5) is non-linear since both T and v pdepend on the applied load. The differential equations for the adhesive based upon plane strain are I 8 au av 1 - 2p. ax + -57 ) "2u = ° 1 8 ,8u , Ov% 1 1 - 2p. 8y 8x 8y (10) v-v = 0 The boundary conditions for the upper plate are (see figure 2) T = T o at x = 1 (12) T = 0 at x = -1 (13) M = Mo at x = 1 (14) M = 0 at x = -1 (15) V = -Vo at x = 1 (16) V = 0 at x = -1 (17) To simplify the analysis, the principle of Saint-Venant will be used for the free boundaries (x = ±1) of the adhesive. This imposes the following conditions: crxdy = x = ±1 0 (18) 7. 6x y dy = 0 (19) dy = 0 (20) x = ±1 -b T xy -b x = *1 The conditions at the boundary between the adhesive and the upper plate will be assumed to be Oro = Cry To = T x at y = b (21) at y = b (22) u 0 = u at y = b (23) vo = v at y = b (24) Similar conditions will apply for the lower plate, but these do not have to be expressed if the necessary conditions of symmetry and anti-symmetry are observed when writing the expressions for displacements. If any term in the expressions for u and v is even in x, it must be odd in y and vice versa. Expressions for u and v satisfying equations (10) and (11) and with sufficient arbitrary constants to satisfy all boundary conditions as well as equations (5) and (9) will now be written. The details of how the 8. various terms of these expressions were obtained is not important and will not be given. That each term does satisfy the differential equations (10) and (11) may be verified by substitution. Equations (12) . to (20) give nine conditions for which nine arbitrary constants (a 1 to a 9 ) have been provided. The first seven of these are used in the expressions for u and v, the eighth comes from the integration of equation (2) and the ninth from integration of equation (1). The plate differential equations (5) and (9) together with conditions at the boundary between the plate and adhesive make it necessary to add to the expressions for u and_v terms which become Fourier series for this boundary. The expressions follow: u = a y + a 2 (1 - µ)xx + a 1 5 5 a 7 + n=1 x 5 [3 3 3xy2 a x2y + 1 4 (3.3 1 - a6 —4x 4 y - — + (1 - 2p.)x 3y2 - (1 - p.)xy4 20 (1 - 2p.) x 4 y - (1 - p.)x2y 3 + (3 - 214 y5 4 Anorny cosh an y + A' Binh 20 a y n YE nf3ny sinh 13ny + Bn cosh 13n1 n=1 d cos ax an sin Pnx (25) 9. ›, V )4 I il I " / c cd in Is) )4 Io 1 . 1 I f NI 1 a) 5 + r= eN "1 ›.• )4 ‘t r—r--1 0 ta 0 t; t .5 al er....0.%■111 ›.• 1 1-711 1 0 cCL ti il ti 0 u 03 0 ir.'"..'''... 1 to 1-71 1 CCI I.. M ± i i u 14 N 14 cd •4 ......• + r.1 M)4 i i err= 0 1 ,.. iNI A1_2_1 r••1 I en v i a I (---1.---1 + 0 PI s 0 tl C1. tO t) .4tO o in m ...–. ± N ›•• >•■ 1 ± rd id I 1 + •••■• m 5 5-4 al cni N I m .--I 'Cr 0 0 t03 0 fil -4 SwEiNie.ao!" 0 [1 .-111 + ii . I 10 ti N k71 CCL il r4 N r___....._„i i N d ›, a .-j, ... >4 + d I 1 ...v.... ,..1 4 ul u 1---7-1 M en W A I I Tr "--"..=/ CCL ZS e N o U r7-4-1 •-• X N tn • cl d MI 1:q d MI e+.) + + 0 Lt' ••• -0 Lai • 11. '-. 3- 1 1 1.-4 ....- >4 0 ti NI . NI IN >4 3. M .44 r*T—I ›, 1 1 ,:‘,.. j ....... ›• X r—...-11 ev > I co -1- 6.-1 + + ›, COI cr3 ,...., N I >4 c.‘ii Li 0 M encd 1/4....2,„.._ 4 0 tN.1 r., ›. pri cli .0 + ›. c0. 0:1 ›^. 0 0 tl X I -0 4.2._ tfi 0 O •-• 3. '2 I ...4 • IN I ›, O ti .0 I I 171 4 PI • + •-1 ......0 NI r-al *-$1 X .-'447 + 0 u 1,;± j ren—i -0 LI) .t4 a I ,4 IN3 I v to ›, COI CE, b i.i f--..";:---.1 Cia,0 .5 rn 1 7.. I NI -0 en›, X . i ....... 1 N id td 41 ,------""---t I ' 0 Zs x 71 + r.3 CCL to 0 0 ca 0 _ '‹ .■---J 1d 0 N + + l 'I 0 f1:1 '.■-317 0 N I 12. I p .11 .11 M 1 m >4 ti U) ml N0 U >4 en 1 M 1 —I N N + 14 N. _I cd J. + il Lfl ni .41 1 --;'. Cd 1 I en° I co 11 O 1 .-1 ....- ›, M en . rd .0 s cr ,-IIp,_..1 mi a N I " o—I •••■••• r-4 ......0 o 1 7. 1 NI . ..-., en i NtIm 1 - .. 0 < g1:1 1....._1 + + mi x NI I i.—..0 ev ›, 7. fll " Nt+ > 0 Ca. to ..-1 0 to ti rr--___, il 0 >4 m 0 ti -0 + ± g ...4 co af---- ›--'.-----Th r----. -1 >4 ct) > I L-0 )4 o CO_ v14 .0 rd 1 o C t■P ,.0 so en ›, 0 tto <4 1-____Nr_a '[.•91 0 N + 0 0 c" ›, 0 C0. 0 CI:1 L.........Ne->- C 0 N + 1 0 13. From equations (2), (22), and (29) T = ZG 1 si x - w a4 x 3 a 5 li bx 4 + (1 - p.)b3x2 2 3(1 - p,) 3a 3 bx 2 - 2 [2 - 11 ) 3,-5 _ (1 20 (2 -µ)O] 4 +a µ) n=1 n=1 d a "Iµx 5 ' 20 A n fn + A n' d + ZG [3ngn + Bn e - 2G 13 4x + 4 2 8 b 2x 3 _ - 1 CO5 (1 - /1) b2x3 2 sin anx finx n (30) Pn From equations (4), (6) and (26) a 3 b + a4 2(2 - /1) x + M ( 1. - - 1- a7x ) 6(1 - ix) b 2 x 3 6a. 5 bx 2 D -9- a 6 (3 - 2µ) x3 [Anhn + An an sin anx n=1 + DBin +B'n el n gii cos Onx n=1 [n From equations (1), (21) and (28) (31) 14. V = - 2G a9 - + a (x 3 - 3b2x) 3 ) x5 p.b 2x 3 - a5 (1 - a p.) b 3x2 2 + a (1 b 4 (1 - p.) 2 x2 b4] + a bx4 4. (1 1-4 3x 2 7 4 a 6 ( 2 - /1) bx4 4 + 2G n=1 + An kd c 13 anx an + 2GZ E3n o n + Bn' n=1 n sin 13nx (32) Pn It is advantageous to select an and On such that siriai cos (33) =0 Sri 0 (34) These relations will be used wherever they apply. The boundary conditions, equations (12) to (20), will now be used to obtain nine equations between the constants a l to a9 inclusive. From equations (12), (13) and (30) - 3a b -a5 E 2 3 b+ (1 - p)bl + a 8 = T' (35) 15. 1a4 al 3(1 - p.) 2 + a 3 + a k-. + ( 1aa) b 2 _(2 - ii) b 4 4 2 20 7 From equations 5 1 -11 4 2 2 - a6 ( 2 20 (14), = = _ 4 114 (36) T' (15) and (31) - M' (37) b a4 2(2 - P. ) + a6 (3 - 2p.) - 6(1 - lob ] - a7 = - 6M' (1 - p.) (38) From equations (16), (17) and (32) a 9 + a.4 b 3a7 Eb + - (]L - a6 4 (1 - p.) 4 2 [Awl n + A'. 1(11 cos an - V' - - 11) b3 2 (39) an n=1 (1- 1.0d a 3 (1 - 3b 2 ) + a 5 (1 + /1) 2 10 Y + n=1 , n B n o n + 13 n n sin gn Pn =-V (40) 16. From equations (18) and (27) a2 + a 3 (3 - b 2 ) + a5 (1 - p.)b 2- IL:Lk) b4 10 + = 0 (41) From equations (19) and (27) a (1 - 11) 6 3 - 11 ) 3 (2 5 b]. 6 aE2 4 - (1 - 1.1.) b2 2 20 b (1 - p) b2 2 ( 2 P.)b] 20 µb 5 a _ (42) From equations (20) and (29) al _a4 2 1 - 11) a7 E 4 + )-F An j n n=i cos a + A n' k ri a n b n = 0 (43) Equations (5) and (9) provide the additional relations that are required. From equation (9) 17. 5 4 3 F0 +F1 x +F 2 x 2 + F3 x + F4 x + F5 x Y f - hat A n + kn n=1 n=1 En inP2 enG1 nt gn1 nn Pn 8} cos O nx n dncrnt drip' – + A ni } sin anx 2 enPnt 2 (44) =0 From equation (5) 4 Ho + H 1 x+ H 2 x 2 + H 3x 3+ H4x - 2 jn + a f thnon3 D ' n n] A n + d n cr 3 D' + --k n n =1 + an dd A ll sin ni3n3 D + 2 – o n - fin gd Bn a x n=1 + [e n i3 n D' + –2 n t n 1 d dvn e 13 n1 cos Pri x * _ --(T--'-.) nn (ix Gt clx +0 (45) 18. Where F0 = - a 2 (1 - F1 1 - al G + 3a 3b [b + a4 _ ( 1211 + E b4G F = 3 (2 - b ti)] +b a 5 3(1 =- 2p.)b 2 + 3bt + (1 - p.)b 3G G a + a6 b 4 3(1 - p,) +aE ±(3 - 2µ)t+ 1. (1 2 2 _ 2p.) b + + 7 2 Ob2G] aE + La be' 2 F5 = Ho = 6 (2 20 [32 3 t (46) a6 3(1 - p.)b2t [ 2(1 - 1.1.)b 3 + (2 - FL) b1/41 4 4 F2 = - + a 5 (1 - p.)b4 + a G ' 8 (47) (48) Ii)b 2 G ' (49) (50) G + a -L G' 7 20 + a 5 libD' (51) _ (1 - 14 0 - 2(1 - p.)b1 (52) t 19. Hi = - a + 3(1 - H H 2 (1 - 4b (1 - - a 7 6D' - }L)b 2 2 a _6a 3 t 5 3 = - a 6 2(2 t + a6 6(3 - zon 2 (1 b 3 - 11 ) + LL1.0.1,3 3(1 - YID 2 (53) (54) 61.1.1] t + (2 - 4) + a 7 -21 1D (55) + t (56) H 4 = a 5 (1 t Relations for the constants,n A A ''Bnand B , can be found by ——— applying integral transforms to equations (44) and (45). Using the sine transform (see Appendix A) on equation (44) gives 2 cos an F l an hnant 4 _ _a6 ) F3 InG ' An a 2 n + [cn _ 20 + 120 ) F5 an dnant 2 + cinG a— A n [n =0 (57) 20. The cosine transform on equation (44) gives 2 sin /3 n F0 , - 2 kl ) F2 On + Pn 12 - –2On + 24% F4 Pn –74/ en(3nt 2 n13nt gnGl Bn 2 13n - e mn (58) B' = 0 n /3n The sine transform on equation (45) gives 2 cos an an H1 + (1 - 3 4 + a3 D' + nn jn + anf] n An 2 k + a d A' = P n + dna3 n 13' + t n n n n (59) The cosine transform on equation (45) gives 2 sin I3n + H o + + 2 o in 2 (1 - pz ) H g 1 B n nn 13 + + 12 (1 - — p2 3 enfin D I + + 24 —) H4 p4 2 nn i- + + i n13n3 D nen B'n = Qn (60 ) where 1 P=1 2Gt v ) d (T dv ...1 dx dx sin anx dx (61) Qn 21. 1 1 f d (T dv ) cos Pnclx 2Gt dx clx -1 (62) Equations (35) to (43) and (57) to (60) form a matrix from which the constants may be solved. A simplification of the matrix may be made by multiplying equation (43) by b and adding the result to equation (39). The resulting equation, a 9 + al b a _Eb5 - a7 2 6 20 (2 - 114 5 20 = V (63) will replace equation (39). The nature of the matrix is such that it may be broken into two independent matrices. By using the aforementioned equations, together with equations (46) to (56), matrices (64) and (65) are formed. Solving these matrices (with a finite number of equations) for the constants and substituting the constants into equations (25) to (29) will give the displacements and stresses for the adhesive. 24. V. NUMERICAL COMPUTATIONS Mo and Vo are computed from a given force T o by means of the following equations: Mo =k 2 = k (t b) T 2 (66) 2b) (67) where the values of k and k' are taken from table 1 of reference 1. In order to simplify the computations, the non-linear terms, P n and Qn , of the matrices, were set equal to zero. Reference to equations (61) and (62) together with equations (26) and (30) will show that each term of P n and Qn involves the multiplication of two small constants thereby making the contribution of P n and Qn to the matrix significantly small. The fifth equation of matrix (64) and the fourth equation of matrix (65) each contain a divergent series. Both of these equations are used to satisfy the shear stresses on the boundaries of the adhesive and plates. Since they describe a physical condition of the problem, they must sum to a finite value. The problem then is to determine the values of the summations with a finite number of terms. There are several methods of summing divergent series, but the one best suited for this problem is the Euler transformation for divergent series (see 25. Appendix B). The reasons are that in both series the terms in general alternate in sign, remain fairly constant in magnitude (for large values 1 of c_) for matrix (64), and decrease nearly as — for matrix (65). These are conditions for which the Euler transformation works very well. Since one of the divergent series comes from equation (29) for shear stress, it will be necessary to treat both equations the same way in order to satisfy the boundary condition for shear. Hence, if the Euler transform is used in the matrix, it must be used on equation (29). For the other stresses and the displacements it is not so easy to determine whether to use the Euler transformation or not. If a series already converges iri a satisfactorily way, the application of the Euler transformation may slow the convergence or even cause the series to diverge. Since it is difficult to determine the need of the Euler transformation analytical, the following three cases were studied numerically. (a ) Transformation is not used on any equation (b ) Euler transformation used on matrix equations only (c Euler transformation used on matrices, displacement and stress equations. A typical comparison of u, v, cr x , o-„, and r xy is shown in figures (4) to (8). A study of these curves and other similar comparison curves led to the following conclusions: 2 6. (1) use the Euler transformation on the matrices (2) do not use the Euler transformation on u (3) the same results are obtained with or without the Euler trans formation on v (4) use the Euler transformation on cr x (5) the same results are obtained with or without the Euler transformation on cr (6) use the Euler transformation on T xy It is possible that different choices of material and different ranges of dimensions would lead to different conclusions. Also, some other transformation may work better than the Euler transformation. Having established the numerical procedure, it remains to determine how many Fourier terms are needed to give satisfactory answers. Figures (9) to (13) show the effects of adding these terms to the solution. From a study of these curves and other similar curves, the following conclusions may be drawn. (1) displacement u converges in a satisfactory way, but will require several Fourier terms (2) displacement v could not be made to converge by any method tried (3) stress Tx could not be made to converge by any method tried 27. (4) the maximum value of stress cr is obtained with very few Fourier terms, but the distribution will not be established with these terms (5) the shear stress T xy distribution could not be established with the number of terms taken. The most important stress in the design of lap joints is the normal stress cr y , as a study of the stress curves will verify. The maximum normal stress is well established with y = 4. Therefore, a study of this normal stress is made under varying parameters. Figure (14) shows the effect of varying the glue thickness while holding all other variables constant. Likewise, figure (15) shows the effect of varying the plate thickness and figure (16) shows the effect of varying the load. VI. CONCLUSIONS For the most important stress Ly , reliable computations can be made from the solution. This is also true for the displacement u. The shear stress .r xy requires further study and it appears that all that is required is to take many more Fourier terms. For the displacement v and the normal stress o- x to be found. some means of obtaining convergence has 28. VII. REFERENCES (1) Goland, M. and Reissner, E. 1944. Stresses in Cemented Joints. Journal of Applied Mechanics, Vol. II. (2) Kuenzi, E. W. 1956. Determination of Mechanical Properties of Adhesives for Use in the Design of Bonded Joints. Forest Products Laboratory Rept. No. 1851. 2 9. VIII. ACKNOWLEDGEMENTS The author is indebted to the Forest Products Laboratory and to the Engineering Experimental Station of the University of Wisconsin for providing financial support for this project. The author wishes to thank Prof. Gerald Pickett of the Mechanics Department of the University of Wisconsin and Mr. Charles Norris of the Forest Products Laboratory for their advice, guidance and encouragement throughout the course of this work. 30. IX. APPENDICES 1. Appendix A -- Integration Formulas Integration formulas used in this report include the following: (48) sin anx dx = 0 x sin a x S4 2 nx 2 cos a n dx = sin a x dx = n n 4 (70) 0 3 . x s in a x dx x (69) 2 cos a n an (71) (1 -) (72) sin anx dx = 0 5 s. x m ax dx n 2 cos a n an ki - 20 an 120 1 a4 n (73) 31. -1 cos gn 2 sin x dx = 13 n (74) n x cos Pnx dx '= 0 (75) 2 x cos gnx dx = 2 Bin (76) gn 1311 1 x 3 (77) cos gnx dx = 0 x4 cos gnx dx 2 x 5 cos Pax dx = 0 sin /3 n 12 24 on4 (78) (79) 32. 2. Appendix B -- Euler Transformation for Divergent Series The transformation is usually written as follows: al a + a l 2 a a + 2a + a 2 1 2 3 a 2+ a a + 3a + 3a + a 1 3 z 4 2 3 a + 2a + a 3a 2 3 4 a + a 3 4 a 4 (80) 1 where al , a2 , a 3 , etc. are terms of the original series. The new series is formed as follows: 1 1 1 1 1 (a + 3a —a + — (a 1 + aZ • ++ — (a + 2a 2 + a 3 ) + 2 1 1 4 21 8 16 + 3a 3 + a ) + . . 4 (81) In the series used in this report, the identity of the original terms has to be maintained since the terms are used in amatrix. In order to do this the series is rearranged in the following manner Kl a l + K 2a2 + K 3a 3 + . . . . + Knan + + Kta. k (83) where Kn (m - 1) ! ni=.n (rn - n) ! (n - 1)1 2m and k is the total number of terms used in the series. (83)