Hindawi Publishing Corporation Journal of Applied Mathematics Volume 2013, Article ID 896050, 10 pages http://dx.doi.org/10.1155/2013/896050 Research Article Minimum-Energy Bivariate Wavelet Frame with Arbitrary Dilation Matrix Fengjuan Zhu, Qiufu Li, and Yongdong Huang School of Mathematics and Information Science, Beifang University of Nationalities, Yinchuan 750021, China Correspondence should be addressed to Yongdong Huang; nxhyd74@126.com Received 31 January 2013; Revised 10 June 2013; Accepted 18 June 2013 Academic Editor: Li Weili Copyright © 2013 Fengjuan Zhu et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. In order to characterize the bivariate signals, minimum-energy bivariate wavelet frames with arbitrary dilation matrix are studied, which are based on superiority of the minimum-energy frame and the significant properties of bivariate wavelet. Firstly, the concept of minimum-energy bivariate wavelet frame is defined, and its equivalent characterizations and a necessary condition are presented. Secondly, based on polyphase form of symbol functions of scaling function and wavelet function, two sufficient conditions and an explicit constructed method are given. Finally, the decomposition algorithm, reconstruction algorithm, and numerical examples are designed. 1. Introduction Frames theory is one of the efficient tools in the signal processing. It was introduced by Duffin and Schaeffer [1] and was used to deal with problems in nonharmonic Fourier series. However, people did not pay enough attention to frames theory for a long time. When wavelets theory was booming, Daubechies et al. [2] defined the affine frame (wavelet frame) by combining the theory of continuous wavelet transform with frame. After that, people started to research frames and its application again. Benedetto and Li [3] gave the definition of frame multiresolution analysis (FMRA), and their work laid the foundation for other people to do further research. Frames not only can overcome the disadvantages of wavelets and multivariate wavelets but also increase redundancy, and the numerical computation becomes much more stable using frames to reconstruct signal. With well timefrequency localization and shift invariance, frames can be designed more easily than wavelets or multivariate wavelets. At present, frames theory has been widely used in theoretical and applicable domains [4–18], such as signal analysis, image processing, numerical calculation, Banach space theory, and Besov space theory. In 2000, Chui and He [5] proposed the concept of minimum-energy wavelet frames. The minimum-energy wavelet frames reduce the computational, and maintain the numerical stability, and do not need to search dual frames in the decomposition and reconstruction of functions (or signals). Therefore, many people paid more attention to the study of minimum-energy wavelet frames. Petukhov [6] studied the (minimum-energy) wavelet frames with symmetry. Huang and Cheng [7] studied the construction and characterizations of the minimum-energy wavelet frames with arbitrary integer dilation factor. Gao and Cao [8] researched the structure of the minimum-energy wavelet frames on the interval [0,1] and its application on signal denoising. Liang and Zhao [9] studied the minimum-energy multiwavelet frames with dilation factor 2 and multiplicity 2 and gave a characterization and a necessary condition of minimum-energy multiwavelets frames. Huang et al. [10, 11] studied minimum-energy multiwavelet frames and wavelet frames on the interval [0,1] with arbitrary dilation factor. It was well known that a majority of real-world signals are multidimensional, such as graphic and video signal. For this reason, many people studied multivariate wavelets and multivariate wavelet frames [12–18]. In this paper, in order to deal with multidimensional signals and combine organically the minimum-energy wavelet frames with the significant properties of multivariate wavelets, minimum-energy bivariate wavelet frames with arbitrary dilation matrix are studied. 2 Journal of Applied Mathematics The organization of this paper is as follows. In Section 2, we give preliminaries and basic definitions. Then, in Section 3, the main results are described. In Section 4, we present the decomposition and reconstruction formulas of minimum-energy bivariate wavelet frames. Finally, numerical examples are given in Section 5. 2. Preliminaries and Basic Definitions 2.1. Basic Concept and Notation. Let us recall the concept of dilation matrix and give some notations. Definition 1 (see [18]). Let π΄ be the 2 × 2 integer matrix. Suppose that its eigenvalues have a modulus strictly greater than 1, then π΄ is called a dilation matrix. (1) Throughout this paper, let Z, R denote the set of integers and real numbers, respectively. Z2 , R2 denote the set of 2-tuple integers and two-dimensional Euclidean space, respectively. For a given dilation matrix π΄, let {ππ , π = 0, 1, . . . , π − 1} be a complete set of representatives of Z2 /π΄Z2 , where π = | det(π΄)|. (2) Let πΏ2 (R2 ) = {π : ∫R2 |π(π₯)|2 ππ₯ < ∞} and π2 (Z2 ) = {π : ∑π∈Z2 |π π |2 ππ₯ < ∞}. For any π, π ∈ πΏ2 (R2 ), the inner product, norm, and the Fourier transform are defined, respectively, by σ΅©σ΅©2 σ΅©σ΅© σ΅©σ΅©πσ΅©σ΅© = β¨π, πβ© , β¨π (π₯) , π (π₯)β© = ∫ π (π₯) π (π₯)ππ₯, R2 πΜ (π) = 1 ∫ π (π₯) π−ππ₯⋅π ππ₯. √2π R2 (1) Definition 2 (see [18]). Let H be a complex and separable Hilbert space. A sequence {ππ : π ∈ Z} is a frame for H if there exist constants 0 < π΄, π΅ < ∞, such that, for any π ∈ H, σ΅© σ΅©2 σ΅¨ σ΅¨2 σ΅© σ΅©2 π΄σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅© ≤ ∑ σ΅¨σ΅¨σ΅¨β¨π, ππ β©σ΅¨σ΅¨σ΅¨ ≤ π΅σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅© . π∈Z The numbers π΄, π΅ are called frame bounds. A frame is tight if we can choose π΄ = π΅ as frame bounds in the Definition 2. If a frame ceases to be a frame when an arbitrary element is removed, it is called an exact frame. When π΄ = π΅ = 1, then π = ∑ β¨π, ππ β© ππ , π ∈ Z, π ∈ Z2 . Definition 3 (see [18]). A bivariate frame multiresolution analysis (FMRA) for πΏ2 (R2 ) consists of a sequence of closed subspaces {ππ }π∈Z and a function π ∈ π0 such that (1) ππ ⊂ ππ+1 , π ∈ Z; (2) βπ∈Z ππ = {0}, βπ∈Z ππ = πΏ2 (R2 ); (3) π(π₯) ∈ ππ ⇔ π(π΄π₯) ∈ ππ+1 , π ∈ Z, π₯ ∈ R2 ; (4) {π(π₯ − π)}π∈Z2 is a frame for π0 , where function π(π₯) is called scaling function of FMRA. Since π0 ⊂ π1 , π(π₯) satisfies two-scale equation (refinable equation) π∈Z2 (2) (5) For any π§ = (π§1 , π§2 )π , π§1 =ΜΈ 0, π§2 =ΜΈ 0, π = (π1 , π2 )π ∈ R2 , π§−1 , π§π are defined, respectively, by π π§−1 = (π§1−1 , π§2−1 ) , 2 π π§π = ∏π§π π . (4) π=1 (6) For any π΄ ∈ R2×2 , π§π΄ is defined by π π§π΄ = (π§π΄ 1 , π§π΄ 2 ) , where π΄ π is the π-th column of π΄. Now, we give the definition of frame. (5) (8) where {ππ }π∈Z2 ∈ π2 (Z2 ). The Fourier transform of (8) is πΜ (π) = π0 (π΄−π π) πΜ (π΄−π π) , π ∈ R2 , (9) where π0 (π) = (3) then π = π denotes that every component of π is zero, π > π denotes that the first nonzero component of π is positive, and π < π denotes that the first nonzero component of π is negative. (7) 2.2. Minimum-Energy Bivariate Wavelet Frame π (π₯) = ∑ ππ π (π΄π₯ − π) , (4) We sort the elements of Z2 by lexicographical order. That is, for any π = (π1 , π2 )π , π = (π1 , π2 )π , π, π ∈ Z2 , and let π = (π1 − π1 , π2 − π2 ) ; ∀π ∈ H. π∈Z (3) For any function π ∈ πΏ2 (R2 ), ππ,π (π₯) is defined by ππ,π (π₯) = π π/2 π (π΄π π₯ − π) , (6) π 1 1 ∑ ππ π−ππ π = ∑ ππ π§π , π π∈Z2 |det (π΄)| π∈Z2 (10) where π0 (π) is the symbol function of scaling function π(π₯), π π§ = π−ππ . For simplicity, in this paper, we suppose that any symbol function is trigonometric polynomial, and scaling function and wavelet function are compactly supported. Definition 4. Let π ∈ πΏ2 (R2 ) satisfies πΜ ∈ πΏ∞ and πΜ Μ continuous at 0 and π(0) = 1. Suppose that π generates a sequence of nested closed subspaces {ππ }π∈Z , then Ψ = {π1 , π2 , . . . , ππ} ⊂ π1 is called a minimum-energy bivariate wavelet frame associated with π if for all π ∈ πΏ2 (R2 ): π σ΅¨ σ΅¨2 σ΅¨ σ΅¨ σ΅¨2 σ΅¨2 π β©σ΅¨σ΅¨σ΅¨σ΅¨ . ∑ σ΅¨σ΅¨σ΅¨β¨π, π1,π β©σ΅¨σ΅¨σ΅¨ = ∑ σ΅¨σ΅¨σ΅¨β¨π, π0,π β©σ΅¨σ΅¨σ΅¨ + ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨β¨π, π0,π 2 2 2 π∈Z π∈Z π=1 π∈Z (11) Journal of Applied Mathematics 3 By the Parseval identity, minimum-energy bivariate wavelet frame Ψ must be a tight frame for πΏ2 (R2 ) with frame bound being equal to 1. At the same time, the formula (11) is equivalent to ∑ β¨π, π1,π β© π1,π = ∑ β¨π, π0,π β© π0,π π∈Z2 π∈Z2 π +∑ ∑ π=1 π∈Z2 π π β¨π, π0,π β© π0,π , 2 Theorem 6. Suppose that the symbols ππ (π), π = 0, 1, . . . , π in (10) and (14) are Laurent polynomial, and generate the refinable function π(π₯) and Ψ = {π1 , π2 , . . . , ππ}. If πΜ is Μ = 1 and π(π₯) generates a nested closed continuous at 0 and π(0) subspaces sequence {ππ }π∈Z , then the following statements are equivalent. (1) Ψ is a minimum-energy bivariate wavelet frame with arbitrary dilation matrix π΄ associated with π(π₯). (2) 2 ∀π ∈ πΏ (R ) . (12) π (π) π∗ (π) = πΌπ , The interpretation of minimum-energy bivariate wavelet frame will be clarified later. Consider Ψ = {π1 , π2 , . . . , ππ} ⊂ π1 , with π π (π₯) = ∑ π∈Z2 πππ π (π΄π₯ − π) , π = 1, 2, . . . , π. π 1 1 ππ (π) = ∑ πππ π−ππ π = ∑ πππ π§π , π π∈Z2 π π∈Z2 π = 1, 2, . . . , π, (14) π π=1 π∈Z2 where π§ = π . With π0 (π), π1 (π), . . . , ππ(π), we formulate the π ×(π+1) matrix π(π): ∀π, π ∈ Z2 . − π πΏππ = 0, Proof. By using the two-scale relations (8) and (13) and notation πΌππ , then formula (12) is equivalent to ∑ πΌππ β¨π, π (π΄π₯ − π)β© π (π΄π₯ − π) = 0, ∀π ∈ πΏ2 (R2 ) . π,π∈Z2 On the other hand, formula (17) can be reformulated as π σ΅¨2 σ΅¨ ∑σ΅¨σ΅¨σ΅¨ππ (π)σ΅¨σ΅¨σ΅¨ = 1, π=0 π (π) π0 (π) π1 (π) ⋅⋅⋅ ππ (π) π0 (π + 2π΄−π π1 π) π1 (π + 2π΄−π π1 π) ⋅ ⋅ ⋅ ππ (π + 2π΄−π π1 π) . . . ( ), . . . . . . −π −π −π π0 (π + 2π΄ ππ −1 π) π1 (π + 2π΄ ππ −1 π) ⋅ ⋅ ⋅ ππ (π + 2π΄ ππ −1 π) ∑ππ (π) ππ∗ (π + 2π΄−1 ππ π) = 0, π = 1, . . . , π − 1 π=0 which is equivalent to π π −1 π=0 π=0 ∑ππ (π) ∑ ππ∗ (π + 2π΄−1 ππ π) = 1, and π∗ (π) denotes the complex conjugate of the transpose of π(π). π π −1 π=0 π=1 ∑ππ (π) (π0∗ (π) − ∑ ππ∗ (π + 2π΄−1 ππ π)) = 1, 3. Main Result In this section, we give a complete characterization of minimum-energy bivariate wavelet frames with arbitrary dilation matrix and two sufficient conditions and a necessary condition of minimum-energy bivariate wavelet frame associated with the given scaling function. Proposition 5. Suppose that π΄ is a dilation matrix; let −1 ππ2ππ1 π΄ π1 π −1 ππ2ππ2 π΄ π1 A=( .. . π (20) π (15) π (18) (19) −πππ = (17) ∗ π∗ π ππ−π΄π + ∑ππ−π΄π ππ−π΄π ) πΌππ = ∑ (ππ−π΄π (3) (13) Using Fourier transform on the previous equation, we can get their symbols as follows: ∀π ∈ R2 . −1 ππ2πππ −1 π΄ π1 π −1 π π π −1 π=0 π=0 ∑ππ (π) ( ∑ ππ∗ (π+2π΄−1 ππ π) − 2ππ (π + 2π΄−1 ππ π)) = 1, π = 1, . . . , π − 1; π ∈ R2 , (21) or −1 ππ2ππ1 π΄ π2 ⋅ ⋅ ⋅ ππ2ππ1 π΄ ππ −1 π −1 π −1 ππ2ππ2 π΄ π2 ⋅ ⋅ ⋅ ππ2ππ2 π΄ ππ −1 ); .. .. . . π −1 ππ2πππ −1 π΄ π2 π −1 ⋅ ⋅ ⋅ ππ2πππ −1 π΄ π π∗ π§π΄π = 1, ∑ππ (π) ∑ π−π΄π π=0 ππ −1 The following theorem presents the equivalent characterizations of the minimum-energy bivariate wavelet frames with arbitrary dilation matrix. π π −1 π=0 π=1π∈Z2 ∑ππ (π) ( ∑ ∑ πππ∗π −π΄π π§π΄π−ππ ) = π − 1, (16) then, A is invertible matrix. π∈Z2 π π −1 π=0 π=1 π −1 ∑ππ (π) ( ∑ ππ2ππ π΄ ππ π ∑ πππ∗π −π΄π π§π΄π−ππ ) = −1, π∈Z2 π = 1, . . . , π − 1; π ∈ R2 , (22) 4 Journal of Applied Mathematics where ππ0 = ππ , π ∈ Z2 . Since A is an invertible matrix, the previous equation is equivalent to π ∑ππ (π) ∑ πππ∗π −π΄π π§π΄π−ππ = 1, π=0 π = 0, 1, . . . , π − 1. (23) Theorem 7. A compactly supported refinable function π ∈ Μ = 1, and π0 (π) is πΏ2 (R2 ), with πΜ continuous at 0 and π(0) the symbol function of π. Let Ψ = {π1 , π2 , . . . , ππ} be the minimum-energy multiwavelet frames associated with π; then π −1 π∈Z2 Μ −π π), π = We multiply the identities in (23) by π§ π(π΄ −πππ π΄−1 0, 1, . . . , π − 1, respectively, where π§ = π , and we get σ΅¨ σ΅¨2 ∑ σ΅¨σ΅¨σ΅¨σ΅¨π0 (π + 2π΄−1 ππ π)σ΅¨σ΅¨σ΅¨σ΅¨ ≤ 1, ππ π πΜ (π΄−π π) π§ππ = ∑ ∑ πππ∗π −π΄π π§π΄π πΜπ (π) , Proof. Let π·(π) be the first column of π(π) and π(π) = (π·(π), π(π)). Then, π· (π) π·∗ (π) + π (π) π∗ (π) = πΌπ . (30) ∗ (24) let π0 = π. Take the Fourier transform on the two sides of the previous formula, (23) is equivalent to π π π (π΄π₯ − ππ ) = ∑ ∑ πππ∗π −π΄π ππ (π₯ − π) , Since π(π)π (π) is a Hermitian matrix, the matrix πΌπ − π·(π)π·∗ (π) is positive semidefinite. We have π· (π) −π· (π) πΌ πΌ ( ∗π ) ( ∗π ) π· (π) 1 −π· (π) 1 πΌ − π· (π) π·∗ (π) =( π π = 0, 1, . . . , π − 1. π=0 π∈Z2 ) 1 − π·∗ (π) π· (π) (25) π· (π) π· (π) πΌ πΌ ) = det ( π ), det ( ∗ π π· (π) 1 1 − π·∗ (π) π· (π) Thus, π π∗ π π (π΄π₯ − π) = ∑ ∑ ππ−π΄π ππ (π₯ − π) , π=0 ∀π ∈ Z2 . (26) π∈Z2 By using the two-scale relations (8) and (13), we can rewrite formula (26) as ∑ πΌππ π (π΄π₯ − π) = 0, (29) π=0 π = 0, 1, . . . , π − 1; π=0 π∈Z2 ∀π ∈ R2 . 2 ∀π ∈ Z . π∈Z2 π ∈ Z2 . −π· (π) −π· (π) πΌπ πΌ ). ) = det ( π −π·∗ (π) 1 − π·∗ (π) π· (π) 1 Therefore, det (πΌπ − π· (π) π·∗ (π)) (1 − π·∗ (π) π· (π)) (27) In other words, the proof of Theorem 6 reduces to the proof of the equivalences of (18), (19), and (27). It is clear that (18) ⇒ (27) ⇒ (19). In order to prove (19) ⇒ (18), let π ∈ πΏ2 (R2 ) be any compactly supported function. Let π½π (π) = β¨π, ∑ πΌππ π (π΄π₯ − π)β© , det ( (28) π∈Z2 Then by using the properties that, for every fixed π, πΌππ = 0 except for finitely many π, and both π and π have compact support, it is clear that only finitely many of the values π½π (π) Μ is a nontrivial function, by taking is nonzero. Now, since π(π) the Fourier transform of (19), it follows that the trigonometric π −π polynomial ∑π∈Z2 π½π (π)π−ππ π΄ π ≡ 0. Obviously, π½π (π) = 0, π ∈ Z2 . By choosing π = ∑π∈Z2 πΌππ π(π΄π₯ − π), we get formula (27). By taking the Fourier transform of (27), we get πΌππ = 0, π, π ∈ Z2 . The proof of Theorem 6 is completed. Theorem 6 characterizes the necessary and sufficient condition for the existence of the minimum-energy bivariate wavelet frames associated with π. But it is not a good choice to use this theorem to construct the minimum-energy bivariate wavelet frames with arbitrary dilation matrix. For convenience, we need to present some sufficient conditions in terms of the symbol functions. (31) = (1 − π·∗ (π) π· (π)) (1 − π·∗ (π) π· (π)) , (32) that is, 1 − π·∗ (π) π· (π) ≥ 0. (33) The proof of Theorem 7 is completed. According to the Theorem 7, there may not exist minimum-energy bivariate wavelet frame associated with a given scaling function. If there exists a minimum-energy bivariate wavelet frame, then the symbol function of scaling function must satisfy (29). Based on the polyphase forms of π0 (π§), π1 (π§), . . . , ππ(π§), we give two sufficient conditions. π Let π§ = π−ππ ; then π0 (π) = π π 1 π −1 1 ∑ ππ π−ππ π = ∑ ∑ πππ +π΄π π−ππ (ππ +π΄π) π π∈Z2 π π=0 π∈Z2 = π 1 π −1 −πππ ππ ∑π ∑ πππ +π΄π π−ππ π΄π π π=0 π∈Z2 = 1 π −1 ππ 1 π −1 ππ 0 π΄ ∑π§ ∑ πππ +π΄π π§π΄π = ∑π§ ππ (π§ ) , √π π=0 π π=0 π∈Z2 (34) where ππ0 (π₯) = (1/√π ) ∑π∈Z2 πππ +π΄π π₯π , π₯ ∈ R2 . Similarly, ππ (π) = 1 π −1 ππ π π΄ ∑π§ ππ (π§ ) , √π π=0 π = 1, 2, . . . , π, (35) Journal of Applied Mathematics 5 where πππ (π₯) = (1/√π ) ∑π∈Z2 πππ π +π΄π π₯π , π₯ ∈ R2 . Let πΆ (π§) = Proof. Under the assumption, we know that the vector 1 √π 0 f := [π00 (π’) , π10 (π’) , . . . , ππ −1 (π’) , ππ 0 (π’)] π −1 π −1 π −1 π§π0 π−π2ππ0 π΄ π0 π§π1 π−π2ππ0 π΄ π1 ⋅ ⋅ ⋅ π§ππ −1 π−π2ππ0 π΄ ππ −1 π −1 π −1 π −1 π§π0 π−π2ππ1 π΄ π0 π§π1 π−π2ππ1 π΄ π1 ⋅ ⋅ ⋅ π§ππ −1 π−π2ππ1 π΄ ππ −1 ); ×( .. .. .. . . . π −1 π −1 π −1 π§π0 π−π2πππ −1 π΄ π0 π§π1 π−π2πππ −1 π΄ π1 ⋅ ⋅ ⋅ π§π3 π−π2πππ −1 π΄ ππ −1 f1 = π·0 f = [π’π‘0 π00 (π’) , π’π‘1 π10 (π’) , . . . , π’π‘π ππ 0 (π’)] πΎ = ∑ aπ π’ π , thus, π00 (π§π΄) π01 (π§π΄) ⋅ ⋅ ⋅ π0π (π§π΄ ) π10 (π§π΄) π11 (π§π΄) ⋅ ⋅ ⋅ π1π (π§π΄ ) ( ) .. .. .. . . . 0 1 π ππ −1 (π§π΄) ππ −1 (π§π΄) ⋅ ⋅ ⋅ ππ −1 (π§π΄) ∗ For convenience, let π’ = π§π΄ , condition (29) can be 0 2 rewritten as ∑π −1 π=0 |ππ (π’)| ≤ 1. 0 If there exists ππ (π’) such that π σ΅¨2 σ΅¨ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππ0 (π’)σ΅¨σ΅¨σ΅¨σ΅¨ = 1, (39) π=0 then, we have the following Theorem 8. Theorem 8. Let π(π₯) ∈ πΏ2 (R2 ) be a compactly supported Μ refinable function, with πΜ continuous at 0 and π(0) = 1, and its symbol function satisfies π −1 σ΅¨2 σ΅¨ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππ0 (π’)σ΅¨σ΅¨σ΅¨σ΅¨ ≤ 1. (40) π=0 If there exists ππ 0 (π’) such that π σ΅¨2 σ΅¨ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππ0 (π’)σ΅¨σ΅¨σ΅¨σ΅¨ = 1, (41) π=0 then there exists a minimum-energy bivariate wavelet frame associated with π(π₯). (43) where aπ ∈ Rπ +1 with a0 =ΜΈ 0 and aπΎ =ΜΈ 0. It is clear that f1 is a unit vector: f1∗ f1 ∗ πΎ πΎ π = ( ∑ aπ π’ ) ( ∑ aπ π’π ) = 1, π=(0,0) ∀ |π’| = 1, (44) π=(0,0) and consequently aπ0 aπΎ = 0. We next consider the (π + 1) × (π + 1) Householder matrix: π»1 = πΌπ +1 − π00 (π§π΄ ) π01 (π§π΄ ) ⋅ ⋅ ⋅ π0π (π§π΄) π10 (π§π΄ ) π11 (π§π΄ ) ⋅ ⋅ ⋅ π1π (π§π΄) ×( ) = πΌπ . .. .. .. . . . 0 1 π ππ −1 (π§π΄ ) ππ −1 (π§π΄ ) ⋅ ⋅ ⋅ ππ −1 (π§π΄ ) (38) π π‘0 , π‘1 , . . . , π‘π ∈ Z2 , π=(0,0) Since πΆ(π§) is a unitary matrix, condition (17) is equivalent to (42) is a unit vector. Construct diagonal matrix π·0 = diag(π’π‘0 , π’π‘1 , . . . , π’π‘π ) such that (36) π00 (π§π΄ ) π01 (π§π΄ ) ⋅ ⋅ ⋅ π0π (π§π΄) π10 (π§π΄ ) π11 (π§π΄ ) ⋅ ⋅ ⋅ π1π (π§π΄) π (π) = πΆ (π§) ( ). .. .. .. . . . 0 1 π ππ −1 (π§π΄ ) ππ −1 (π§π΄ ) ⋅ ⋅ ⋅ ππ −1 (π§π΄) (37) π 2 kkπ, βkβ2 (45) where k = aπΎ ± βaπΎ βe1 , with e1 = (1, 0, . . . , 0)ππ +1 , and the + or − signs are so chosen that k =ΜΈ 0. Then σ΅© σ΅© π»1 aπΎ = ± σ΅©σ΅©σ΅©aπΎ σ΅©σ΅©σ΅© e1 . (46) Since Householder matrix is orthogonal matrix, we have π (π»1 a0 ) (π»1 aπΎ ) = aπ0 π»1π π»1 aπΎ = aπ0 aπΎ = 0. (47) By the previous equation, the first component of π»1 a0 is 0. π Now π»1 f1 = ∑πΎ π=(0,0) (π»1 aπ )π’ , we construct diagonal matrix π‘(1) π·1 = diag(π’ , 1, . . . , 1), π‘(1) ∈ Z2 such that πΎ πΎ π=(0,0) π=(0,0) π f2 = π·1 π»1 f1 = π·1 ∑ (π»1 aπ ) π’π = ∑ a(1) π π’ (48) (1) is also a unit vector and πΎ1 < πΎ, a(1) 0 =ΜΈ 0, aπΎ1 =ΜΈ 0. Similarly, we define the Householder matrix: π»2 = πΌπ +1 − 2 k kπ , βkβ2 (49) where k = aπΎ1 ± βaπΎ1 βe1 =ΜΈ 0, and π·2 = diag(π’π‘(2) , 1, . . . , 1) such that πΎ1 πΎ1 π=(0,0) π=(0,0) π (2) π f3 = π·2 π»2 f2 = π·2 ∑ (π»2 a(1) π ) π’ = ∑ aπ π’ (50) (2) is also a unit vector and πΎ2 < πΎ1 , a(2) 0 =ΜΈ 0, aπΎ2 =ΜΈ 0. Since every component of f is a finite sum, we repeat this procedure finite times to get some unitary matrices π·πΏ , π»πΏ , π·πΏ−1 , π»πΏ−1 , . . . , π»2 , π·1 , π»1 , π·πΏ π»πΏ π·πΏ−1 π»πΏ−1 ⋅ ⋅ ⋅ π»2 π·1 π»1 π·0 f = e1 . (51) 6 Journal of Applied Mathematics That is, f is the first column of the unitary matrix ∗ ∗ π» := π·0∗ π»0∗ π·1∗ π»2∗ ⋅ ⋅ ⋅ π»πΏ−1 π·πΏ−1 π»πΏ∗ π·πΏ∗ . π½π = 1 ( − π0 (π + 2π΄−π π0 π) π0∗ (π + 2π΄−π ππ π) , Ωπ (52) − π0 (π + 2π΄−π π1 π) π0∗ (π + 2π΄−π ππ π) , . . . , − π0 (π + 2π΄−π ππ−1 π) π0∗ (π + 2π΄−π ππ π) , Let π−1 π00 (π’) π01 (π’) ⋅ ⋅ ⋅ π0π (π’) 0 1 π π» = (π1 (π’) π1 (π’) ⋅ ⋅ ⋅ π1 (π’)) ; .. .. .. . . . 0 1 π ππ (π’) ππ (π’) ⋅ ⋅ ⋅ ππ (π’) σ΅¨ σ΅¨2 ∑ σ΅¨σ΅¨σ΅¨σ΅¨π0 (π + 2π΄−π ππ π)σ΅¨σ΅¨σ΅¨σ΅¨ , 0, . . . , 0) π=0 (53) π = 2, 3, . . . , π − 1, π½π = 1 (π0 (π + 2π΄−π π0 π) , Ωπ then, π» satisfies (38). In the formula (15), we let 1 π −1 ππ π π΄ ππ (π) = ∑π§ ππ (π§ ) , √π π=0 π π0 (π + 2π΄−π π1 π) , . . . , π0 (π + 2π΄−π ππ −1 π)) (58) π = 1, . . . , π . (54) Then,we can obtain the formula (17). The proof of Theorem 8 is completed. Corollary 9. Let π(π₯) ∈ πΏ2 (R2 ) be a compactly supported Μ refinable function, with πΜ continuous at 0 and π(0) = 1, and its symbol function satisfies π −1 σ΅¨ σ΅¨2 ∑ σ΅¨σ΅¨σ΅¨σ΅¨π0 (π + 2π΄−1 ππ π)σ΅¨σ΅¨σ΅¨σ΅¨ ≤ 1, ∀π ∈ R2 . (55) π=0 Λ (π) = diag (1, . . . , 1, π π ) , (59) then, πΌπ − π· (π) π·∗ (π) = π (π) Λ (π) π∗ (π) . 2 (56) then there exists a minimum-energy bivariate wavelet frame associated with π(π₯). Next, we present an explicit formula of constructing minimum-energy bivariate wavelet frame. Suppose that π0 satisfies (29); let (57) Then Theorem 10. Let π(π₯) ∈ πΏ (R ) be a compactly supported Μ refinable function, with πΜ continuous at 0 and π(0) = 1, and its symbol function satisfies π −1 ∀π ∈ R2 . (61) π σ΅¨2 σ΅¨ ∑σ΅¨σ΅¨σ΅¨σ΅¨ππ0 (π’)σ΅¨σ΅¨σ΅¨σ΅¨ = 1, (62) π=0 then the symbol function of minimum-energy bivariate wavelet frame associated with π(π₯) is the first row of the matrix: π (π) = π (π) √Λ (π)π (π) , (63) where π(π) is any π × π unitary matrix, and π(π), Λ(π) are defined in (59). Proof. By Theorem 8, there exists a minimum-energy bivariate wavelet frame associated with the given scaling function, and the existence of ππ 0 (π’) guarantees that the elements of √Λ(π) are trigonometric polynomial, and we have π (π) π∗ (π) = π (π) √Λ (π)π (π) (π (π) √Λ (π)π (π)) π 1 = ⋅ ⋅ ⋅ = π π −1 = 1, (60) 2 If there exists ππ 0 (π’) satisfies π=0 D (π) = πΌπ − π· (π) π·∗ (π) . π (π) = (π½1 π½2 ⋅ ⋅ ⋅ π½π ) , π=0 π σ΅¨2 σ΅¨ ∑σ΅¨σ΅¨σ΅¨σ΅¨ππ0 (π’)σ΅¨σ΅¨σ΅¨σ΅¨ = 1, are the eigenvalues and eigenvectors of D(π), respectively, where Ω1 , Ω2 , . . . , Ωπ ensure that π½1 , π½2 , . . . , π½π are unit vector. Let σ΅¨ σ΅¨2 ∑ σ΅¨σ΅¨σ΅¨σ΅¨π0 (π + 2π΄−1 ππ π)σ΅¨σ΅¨σ΅¨σ΅¨ ≤ 1, If there exists ππ 0 (π’), . . . , ππ0 (π’), π ≥ π , such that π½1 = π π −1 σ΅¨ σ΅¨2 π π = 1 − ∑ σ΅¨σ΅¨σ΅¨σ΅¨π0 (π + 2π΄−π ππ π)σ΅¨σ΅¨σ΅¨σ΅¨ . π=0 π 1 (π∗ (π + 2π΄−π π1 π), −π0∗ (π + 2π΄−π π0 π), 0, . . . , 0) Ω1 0 ∗ ∗ (64) ∗ = π (π) Λ (π) π (π) = πΌπ − π· (π) π· (π) ; thus, symbol functions satisfy (17). Theorems 8 and 10 give different methods to construct minimum-energy bivariate wavelet frame. Journal of Applied Mathematics 7 4. Decomposition and Reconstruction Formulas of Minimum-Energy Bivariate Wavelet Frames Then we can derive the decomposition and reconstruction formulas that are similar to those of orthonormal wavelets. Suppose that the bivariate scaling function π(π₯) has an associated minimum-energy bivariate wavelet frame {π1 , . . . , ππ}. Let the projection operators Pπ of πΏ2 (R2 ) onto the nested subspace ππ be defined by (1) Decomposition Algorithm. Suppose that coefficients {ππ+1,π : π ∈ Z2 } are known. By the two-scale relations (8) and (13), we have 1 ππ,π (π₯) = π ∑π (π₯) , √π π∈Z2 π−π΄π π+1,π (72) 1 π π π ππ,π (π₯) = π ∑π (π₯) , π = 1, . . . , π. √π π∈Z2 π−π΄π π+1,π Pπ π := ∑ β¨π, ππ,π β© ππ,π . π∈Z2 (65) Then the formula (12) can be rewritten as Then, decomposition algorithm is given as π Pπ+1 π − Pπ π := ∑ ∑ π=1 π∈Z2 π π β¨π, ππ,π β© ππ,π . (66) ππ,π = In other words, the error term ππ = Pπ+1 π − Pπ π between consecutive projections is given by the frame expansion: π ππ,π = π π π β© ππ,π . ππ = ∑ ∑ β¨π, ππ,π (67) π=1 π∈Z2 Suppose that the error term ππ has another expansion in terms of the frames {π1 , . . . , ππ}, that is, (68) π=1 π∈Z2 ππ+1,π (π₯) = π=1 π∈Z2 π 1 ∗ π∗ π ππ,π (π₯) + ∑ππ−π΄π ππ,π ∑ {ππ−π΄π (π₯)} . √π π∈Z2 π=1 (74) ππ+1,π = π=1 π∈Z2 (73) π = 1, . . . , π. Take the inner products on both sides of (74) with π, we get Then by using both (67) and (68), we have π σ΅¨ σ΅¨2 π π π β©σ΅¨σ΅¨σ΅¨σ΅¨ = ∑ ∑ ππ,π β¨π, ππ,π β© , (69) β¨ππ , πβ© = ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨β¨π, ππ,π 1 ∑ ππ ππ , √π π∈Z2 π−π΄π π+1,π (2) Reconstruction Algorithm. From (26), it follows that π π . ππ = ∑ ∑ ππ,π ππ,π 1 π , ∑π √π π∈Z2 π−π΄π π+1,π π 1 ∗ π∗ π ππ,π + ∑ππ−π΄π ππ,π }. ∑ {ππ−π΄π √π π∈Z2 π=1 (75) 5. Numerical Examples In this section, we present some numerical examples to show the effectiveness of the proposed methods. and this derives π σ΅¨ σ΅¨2 π 0 ≤ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππ,π − β¨π, ππ,π β©σ΅¨σ΅¨σ΅¨σ΅¨ 2 Example 1. Let π΄ = 2πΌ2 ; then π = 4 and π=1 π∈Z π π σ΅¨ σ΅¨2 π = ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππ,π σ΅¨σ΅¨σ΅¨σ΅¨ − 2∑ ∑ ππ,π β¨π, ππ,π β© 2 2 π=1 π∈Z π=1 π∈Z (70) π σ΅¨ σ΅¨2 π + ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨β¨π, ππ,π β©σ΅¨σ΅¨σ΅¨σ΅¨ 2 π=1 π∈Z This inequality means that the coefficients of the error term ππ in (67) have minimal π2 -norm among all sequences {ππ,π } which satisfy (68). We next discuss minimum-energy bivariate wavelet frames decomposition and reconstruction. For any π ∈ πΏ2 (R2 ), we define the coefficients ππ,π := β¨π, ππ,π β© , π ππ,π := β¨π, ππ,π β© π = 1, . . . , π. (71) π2 = (0, 1)π , π3 = (1, 1)π . 1 − π−ππ1 1 − π−ππ2 1 − π−π(π1 +π2 ) πΜ (π) = ⋅ ⋅ . ππ1 ππ2 π (π1 + π2 ) π π=1 π∈Z π1 = (1, 0)π , (76) Μ of scaling funcSuppose that the Fourier transform π(π) tion π(π) is π=1 π∈Z σ΅¨ σ΅¨2 π σ΅¨ σ΅¨2 π = ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππ,π σ΅¨σ΅¨σ΅¨σ΅¨ − ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨β¨π, ππ,π β©σ΅¨σ΅¨σ΅¨σ΅¨ . 2 2 π0 = (0, 0)π , (77) Then its symbol function π0 (π) satisfies π0 (π) = 1 (1 + π−ππ1 ) (1 + π−ππ2 ) (1 + π−π(π1 +π2 ) ) . 8 (78) Thus, π00 (π’) = π 1 (1 + π’(1,1) ) , 4 π20 (π’) = π10 (π’) = π 1 (1 + π’(1,0) ) , 4 π 1 (1 + π’(0,1) ) , 4 2 π30 (π’) = . 4 (79) 8 Journal of Applied Mathematics 1 Let π40 π 1 (π’) = (1 − π’(1,0) ) , 4 π50 π 1 (π’) = (1 − π’(0,1) ) , 4 π 1 (1 − π’(1,1) ) . 4 π60 (π’) = (80) Then we have ∑6π=0 |ππ0 (π’)|2 = 1. By Corollary 9, there exists a minimum-energy bivariate wavelet frame associated with π(π). Using Theorem 8, let √2 2 ( ( ( π»1 = ( ( ( 1 √2 − 2 1 1 1 √2 ( 2 1 1 ( ( ( π»2 = ( ( ( 1 ( ( ( π»3 = ( ( ( ) ) ) ), ) ) √2 2 ) ( √2 2 √2 2 − 1 1 1 √2 2 √2 2 ) ) ) ), ) ) 1) π»4 √2 √2 √2 √2 √2 2 0 0 2 −2√2 2 0 √ √ 2 2 −2 2 0 0 0 0 1( ( = ( 0 0 0 0 0 −2√2 4( 0 0 2√2 0 −2√2 0 2 2 0 0 0 −2 ( √2 √2 −√2 −2 −√2 √2 √2 0 0 ) ) 2√2) , ) 0 −2 √2 ) π·1 = diag (π’(−1,−1) , 1, 1, 1, 1, 1, 1) , π·2 = diag (1, 1, π’(−1,0) , 1, 1, 1, 1) , √2 2 √2 2 − 1 √2 2 √2 2 ( π·3 = diag (1, π’(0,−1) , 1, 1, 1, 1, 1) . ) ) ) ), ) ) 1 1) 0 1 + π’(1,1) (0,1) 1+π’ 0 1 + π’(1,0) √2+ √2π’(1,0) ( 1( π»1∗ π·1∗ π»2∗ π·2∗ π»3∗ π·3∗ π»4∗ = ( 2 −2√2 4( (1,0) √ 2 − √2π’(1,0) 1−π’ (0,1) 1−π’ 0 (1,1) 1 − π’ 0 ( Consequently, we obtain symbol functions π1 (π) = 1 −ππ2 √ (π ( 2 + √2π−π2π1 ) − 2√2π−π(π1 +π2 ) ) , 8 π2 (π) = 1 (2π−π2(π1 +π2 ) − 2π−ππ1 π−π2π1 ) , 8 π3 (π) = 1 (2 − 2π−ππ1 ) , 8 1 π4 (π) = π−ππ2 (−2 + 2π−π2π1 ) , 8 π5 (π) = 1 √ (− 2 + √2π−π(2π1 +2π2 ) + π−ππ1 (−√2 + √2π−π2π2 )) , 8 π6 (π) = 1 (1 + π−π(2π1 +2π2 ) + π−ππ1 (1 + π−π2π2 ) 8 (81) Thus, we have 2π’(1,1) −2π’(0,1) 0 0 0 2π’(0,1) −2π’(1,1) 2 0 −2 0 0 −2+2π’(1,0) 0 0 0 −2 − 2π’(1,0) −2 0 2 0 −√2 + √2π’(1,1) −√2 + √2π’(0,1) 0 0 0 −√2 − √2π’(0,1) −√2 − √2π’(1,1) 1 + π’(1,1) 1 + π’(0,1) −1 − π’(1,0) ) ) −2 ) . ) −1 + π’(1,0) 1 − π’(0,1) 1 − π’(1,1) ) (82) −π−ππ2 (1 + π−π2π1 ) − 2π−π(π1 +π2 ) ) . (83) The functions generated by the previous symbol functions are minimum-energy bivariate wavelet frame functions associated with π(π₯). Example 2. Let π΄ = 3πΌ2 ; then π = 9 and π0 = (0, 0)π , π1 = (1, 0)π , π2 = (2, 0)π , π3 = (0, 1)π , π4 = (0, 2)π , π5 = (1, 1)π , π6 = (2, 1)π , π7 = (1, 2)π , π8 = (2, 2)π . (84) Journal of Applied Mathematics 9 Μ of scaling function Suppose that the Fourier transform π(π) π(π) is 1 − π−ππ1 1 − π−ππ2 1 − π−π(π1 +π2 ) ⋅ ⋅ . πΜ (π) = ππ1 ππ2 π (π1 + π2 ) (85) π π Let π§ = π−ππ = (π−ππ1 π−ππ2 ) , and we have π§π0 = 1, π§π1 = π−ππ1 , π’ = π§π΄ = (π−π(π1 +π2 ) , π−π(π1 −π2 ) ). Therefore, π 1 (1+π’(1,0) ) , 2√2 π10 (π’) = π 1 (1 − π’(1,0) ) , 2√2 π30 (π’) = π00 (π’) = Then its symbol function π0 (π) satisfies π0 (π) = 1 (1 + π−ππ1 + π−π2π1 ) (1 + π−ππ2 + π−π2π2 ) 27 Let (86) × (1 + π−π(π1 +π2 ) + π−π2(π1 +π2 ) ) . Thus, π π 1 (1 + π’(0,1) + π’(1,1) ) , 9 π20 (π’) = 1 (1 + 2π’(0,1) ) , 9 π30 (π’) = π π 1 (1 + π’(1,0) + π’(1,1) ) , 9 π40 (π’) = π 1 (1 + 2π’(1,0) ) , 9 π60 (π’) = π 1 (2 + π’(0,1) ) , 9 π50 (π’) = π 1 (2 + π’(1,1) ) , 9 π 1 (2 + π’(1,0) ) , 9 In this paper, we define the concept of minimum-energy bivariate wavelet frame with arbitrary dilation matrix and present its equivalent characterizations. We give a necessary condition and two sufficient conditions for minimum-energy bivariate wavelets frame and deduce the decomposition and reconstruction formulas of minimum-energy bivariate wavelets frame. Finally, we give several numerical examples to show the effectiveness of the proposed methods. Acknowledgments 3 π80 (π’) = . 9 (87) Let π90 (π’) = π 1 (1 − π’(0,−1) ) , 2√2 (93) 6. Conclusions π π70 (π’) = π20 (π’) = and we have ∑3π=0 |ππ0 (π’)|2 = 1. By Corollary 9, there exists a minimum-energy bivariate wavelet frame associated with π(π). π 1 π00 (π’) = (1 + π’(1,1) ) , 9 π10 (π’) = π 1 (1+π’(0,−1) ) . 2√2 (92) π √6 (1 − π’(1,0) ) , 9 0 π11 (π’) = 0 π10 (π’) = π √6 (1 − π’(0,1) ) , 9 π √6 (1 − π’(1,1) ) . 9 (88) 0 2 Then we have ∑11 π=0 |ππ (π’)| = 1. By Corollary 9, there exists a minimum-energy bivariate wavelet frame associated with π(π). 1 ); then π = 2 and Example 3. Let π΄ = ( 11 −1 π0 = (0, 0)π , π1 = (1, 0)π . (89) Μ of scaling funcSuppose that the Fourier transform π(π) tion π(π) satisfies 1 − π−ππ1 1 − π−ππ2 1 − π−π(π1 +π2 ) 1 − π−π(π1 −π2 ) ⋅ ⋅ ⋅ . πΜ (π) = ππ1 ππ2 π (π1 + π2 ) π (π1 − π2 ) (90) Then its symbol function π0 (π) satisfies π0 (π) = 1 (1 + π−ππ1 ) (1 + π−ππ2 ) . 4 The authors would like to thank Professor Weili Li and the anonymous reviewers for suggesting many helpful improvements to this paper. 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