Research Article Dynamics Analysis of an HIV Infection Model including

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Hindawi Publishing Corporation
Journal of Applied Mathematics
Volume 2013, Article ID 419593, 12 pages
http://dx.doi.org/10.1155/2013/419593
Research Article
Dynamics Analysis of an HIV Infection Model including
Infected Cells in an Eclipse Stage
Shengyu Zhou, Zhixing Hu, Wanbiao Ma, and Fucheng Liao
Department of Applied Mathematics, University of Science and Technology Beijing, Beijing 100083, China
Correspondence should be addressed to Zhixing Hu; huzhixing@ustb.edu.cn
Received 28 January 2013; Accepted 31 March 2013
Academic Editor: Junjie Wei
Copyright © 2013 Shengyu Zhou et al. This is an open access article distributed under the Creative Commons Attribution License,
which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
In this paper, an HIV infection model including an eclipse stage of infected cells is considered. Some quicker cells in this stage
become productively infected cells, a portion of these cells are reverted to the uninfected class, and others will be latent down in
the body. We consider CTL-response delay in this model and analyze the effect of time delay on stability of equilibrium. It is shown
that the uninfected equilibrium and CTL-absent infection equilibrium are globally asymptotically stable for both ODE and DDE
model. And we get the global stability of the CTL-present equilibrium for ODE model. For DDE model, we have proved that the
CTL-present equilibrium is locally asymptotically stable in a range of delays and also have studied the existence of Hopf bifurcations
at the CTL-present equilibrium. Numerical simulations are carried out to support our main results.
1. Introduction
In recent years, mathematical models have been done on the
viral dynamics of HIV. In the basic mathematical modeling of
viral dynamics, the description of the virus infection process
has three populations: uninfected target cells, productively
infected cells, and free viral particles [1–7]. In this model,
infected cells are assumed to produce new virions immediately after target cells are infected by a free virus.
However, there are many biological steps between viral
infection of target cells and the production of HIV-1 virions.
In 2007, Rong and coworkers [8] studied an extension of the
basic model of HIV-1 infection. The main feature of their
model is that an eclipse stage for the infected cells is included
and a portion of these cells are reverted to the uninfected
class. Perelson et al. [9] presented this kind of cell early in
1993. Buonomo and Vergas-De-León [10] have performed the
global stability analysis of this model. Perelson et al. [1] put
forward another model in 1997. He divided infected cells into
two kinds: long-lived productively infected cells and latently
infected cells. Latently infected cells are also activated into
productively infected cells [11]. Motivated by their work and
now we concern the progression of infected cells from this
eclipse phase to the productive, and a portion of these cells are
reverted to the uninfected class or are latent down in the body.
In most virus infections, cytotoxic T lymphocytes (CTLs)
play a critical role in antiviral defense by attacking virusinfected cells. Therefore, the dynamics of HIV infection
with CTL response has received much attention in the
past decades, some include the immune response without
immune delay [12–15], and others contain immune delay
[16–19]. Some HIV infection models with CTL-response
describe only the interaction among uninfected target cells,
productively infected cells, CTLs [12, 14, 20]. The most basic
model can be written as
𝑑π‘₯
= 𝑠 − 𝑑π‘₯ − 𝛽π‘₯𝑦,
𝑑𝑑
𝑑𝑦
= 𝛽π‘₯𝑦 − 𝛼𝑦 − 𝑝𝑦𝑧,
𝑑𝑑
(1)
𝑑𝑧
= 𝑓 (π‘₯, 𝑦, 𝑧) − π‘Ÿπ‘§,
𝑑𝑑
where π‘₯, 𝑦, and 𝑧 represent the concentration of uninfected
target cells, productively infected cells, CTLs at time 𝑑,
respectively. Parameters 𝑠 and 𝑑 are the birth rate and death
rate of uninfected cells, respectively. The uninfected cells
become infected at rate of 𝛽π‘₯𝑦. Productively infected cells
are produced at rate 𝛽π‘₯𝑦, 𝛼 is the death rate of productively
2
Journal of Applied Mathematics
infected cells, 𝑝 is the strength of the lytic component, and π‘Ÿ is
the death rate of CTLs. Function 𝑓(π‘₯, 𝑦, 𝑧) describes the rate
of immune response activated by the infected cells. Wang et
al. [14] assumed that the production of CTLs depends only on
the population of infected cells and gave 𝑓(π‘₯, 𝑦, 𝑧) = 𝑐𝑦. Ji et
al. [12] assumed that the production of CTLs also depends on
the population of CTL cells and chose the former 𝑓(π‘₯, 𝑦, 𝑧) =
𝑐𝑦𝑧.
In this paper, we also consider the dynamics of HIV
infection with CTL response and give 𝑓(π‘₯, 𝑦, 𝑧) = 𝑐𝑦𝑧.
Meanwhile, our model also concludes an eclipse stage of
infected cells. After the eclipse stage, some quicker infected
cells which become productively infected cells are obviously
attacked by CTLs. Other infected cells which will be reverted
to the uninfected class or be latent down in the body do
not have the ability to express HIV and will not cause
CTL immune response. Therefore, we only take the immune
response to productively infected cells into account and
ignore the attack to latently infected cells by CTLs. So we get
the following ODE:
2. The Existence of the Equilibrium of System
In system (2) and (3), the basic reproduction numbers for
viral infection and for CTL response are given as follows:
𝑅0 =
π‘žπ‘ π›½
,
𝑑𝛼 (𝛿 + πœ‚ + π‘ž)
π‘π‘žπ‘ π›½
𝑅1 =
.
𝑐𝑑𝛼 (𝛿 + πœ‚ + π‘ž) + π›Όπ›½π‘Ÿ (πœ‚ + π‘ž)
It is clear that 𝑅0 > 𝑅1 always holds. For system (2) and
(3), there exists three equilibriums.
Theorem 1. For system (2) and (3), the uninfected equilibrium
𝐸0 (𝑠/𝑑, 0, 0, 0) always exists;
(1) if 𝑅0 > 1, a CTL-absent infection equilibrium
𝐸1 (π‘₯1 , 𝑀1 , 𝑦1 , 𝑧1 ) exists, where
𝑑π‘₯
= 𝑠 − 𝛽π‘₯𝑦 − 𝑑π‘₯ + 𝛿𝑀,
𝑑𝑑
𝑑𝑀
= 𝛽π‘₯𝑦 − (𝛿 + πœ‚ + π‘ž) 𝑀,
𝑑𝑑
𝑑𝑦
= π‘žπ‘€ − 𝑝𝑦𝑧 − 𝛼𝑦,
𝑑𝑑
(2)
where 𝑀 represents the concentration of infected cells in the
eclipse stage at time 𝑑. Infected cells in the eclipse phase revert
to the uninfected class at a constant rate 𝛿. In addition, they
may alternatively progress to the productively infected class
at the rate π‘ž or die at the rate πœ‚. But some authors believe that
time delay cannot be ignored in models for immune response
[16–19]. In this paper, 𝜏 represents CTL-response delay, that
is, the time between antigenic stimulation and generating
CTLs. We investigated the effect of a time delay on system
(2) to obtain the following DDE model:
𝑑π‘₯
= 𝑠 − 𝛽π‘₯𝑦 − 𝑑π‘₯ + 𝛿𝑀,
𝑑𝑑
𝑑𝑦
= π‘žπ‘€ − 𝑝𝑦𝑧 − 𝛼𝑦,
𝑑𝑑
π‘₯1 =
𝛼 (𝛿 + πœ‚ + π‘ž)
,
π›½π‘ž
𝑀1 =
𝑠
1
(1 − ) ,
𝑛+π‘ž
𝑅0
𝑦1 =
π‘ž
𝑀,
𝛼 1
(5)
𝑧1 = 0;
(2) if 𝑅1 > 1, there exists a CTL-present infection
equilibrium 𝐸2 (π‘₯2 , 𝑀2 , 𝑦2 , 𝑧2 ), where
𝑑𝑧
= 𝑐𝑦𝑧 − π‘Ÿπ‘§,
𝑑𝑑
𝑑𝑀
= 𝛽π‘₯𝑦 − (𝛿 + πœ‚ + π‘ž) 𝑀,
𝑑𝑑
(4)
π‘₯2 =
𝑐 (𝛿 + πœ‚ + π‘ž)
𝑀2 ,
π›½π‘Ÿ
𝑀2 =
π‘ π›½π‘Ÿ
,
𝑐𝑑 (𝛿 + πœ‚ + π‘ž) + π›½π‘Ÿ (πœ‚ + π‘ž)
π‘Ÿ
𝑦2 = ,
𝑐
𝑧2 =
(6)
𝛼
(𝑅 − 1) .
𝑝 1
3. The Global Stability of the ODE Model
The initial conditions for system (2) are given as follows:
π‘₯ (0) > 0,
(3)
𝑑𝑧
= 𝑐𝑦 (𝑑 − 𝜏) 𝑧 (𝑑 − 𝜏) − π‘Ÿπ‘§.
𝑑𝑑
Our paper is organized as follows: the three equilibriums
on system (2) and (3) are given in the next section. In
Section 3, the global stability of the ODE model is discussed.
The analysis of the stability for this DDE model is carried out
in Section 4. Finally, some numerical simulations are carried
out to support our analytical results, and some conclusions
are presented.
𝑀 (0) > 0,
𝑦 (0) > 0,
𝑧 (0) > 0.
(7)
It is clear that all solutions of system (2) are positive for 𝑑 > 0.
Before analyzing the stability of system (2), we now show that
the solutions of system (2) are bounded.
Theorem 2. Let (π‘₯(𝑑), 𝑀(𝑑), 𝑦(𝑑), and 𝑧(𝑑)) be the solution of
system (2) satisfying initial conditions (7), then there exists
𝑀 > 0 such that π‘₯(𝑑) < 𝑀, 𝑀(𝑑) < 𝑀, 𝑦(𝑑) < 𝑀, and
𝑧(𝑑) < 𝑀 hold after sufficiently large time 𝑑.
Proof. Let
𝐿 (𝑑) = π‘₯ (𝑑) + 𝑀 (𝑑) + 𝑦 (𝑑) +
𝑝
𝑧 (𝑑) ,
𝑐
(8)
Journal of Applied Mathematics
3
where π‘˜ = min{𝑑, πœ‚, 𝛼, π‘Ÿ}. It follows from (2) that
π‘π‘Ÿ
𝑑𝐿 (𝑑)
= 𝑠 − 𝑑π‘₯ (𝑑) − πœ‚π‘€ (𝑑) − 𝛼𝑦 (𝑑) − 𝑧 (𝑑)
𝑑𝑑
𝑐
𝑝
< 𝑠 − π‘˜ (π‘₯ (𝑑) + 𝑀 (𝑑) + 𝑦 (𝑑) + 𝑧 (𝑑))
𝑐
(9)
= 𝑠 − π‘˜πΏ (𝑑) .
If 𝑅0 < 1, then 𝑑𝑉1 /𝑑𝑑 ≤ 0 for all π‘₯ > 0, 𝑀 > 0, 𝑦 > 0 and 𝑧 >
0. So the uninfected equilibrium 𝐸0 is stable. Clearly, it follows
from (12) that 𝑑𝑉1 /𝑑𝑑 = 0 if and only if π‘₯ = π‘₯0 = 𝑠/𝑑, 𝑀 =
0, 𝑦 = 0, and 𝑧 = 0. Therefore, the largest invariant set in the
set {(π‘₯, 𝑀, 𝑦, 𝑧) ∈ 𝑅+4 | 𝑑𝑉1 /𝑑𝑑 = 0} is the singleton {𝐸0 }. By
LaSalle invariance principle, it follows that the equilibrium 𝐸0
is globally asymptotically stable.
Therefore, 𝐿(𝑑) < 𝑠/π‘˜+πœ€ for all large 𝑑, where πœ€ is an arbitrarily
small positive constant. Thus, π‘₯(𝑑) < 𝑀, 𝑀(𝑑) < 𝑀, 𝑦(𝑑) < 𝑀
and 𝑧(𝑑) < 𝑀 for some positive constant 𝑀.
Theorem 4. For system (2), if 𝑅1 < 1 and 1 < 𝑅0 ≤
1 + (πœ‚ + π‘ž)/𝛿, CTL-absent infection equilibrium 𝐸1 is globally
asymptotically stable.
Theorem 3. If 𝑅0 < 1, the uninfected equilibrium 𝐸0 of system
(2) is globally asymptotically stable.
Proof. Define a Lyapunov function
𝑉2 (π‘₯, 𝑀, 𝑦, 𝑧) = π‘₯ − π‘₯1 − π‘₯1 ln
Proof. Construct a Lyapunov function
𝑉1 (π‘₯, 𝑀, 𝑦, 𝑧) = π‘₯ − π‘₯0 − π‘₯0 ln
+
π‘₯
π‘₯0
+ 𝑀 − 𝑀1 − 𝑀1 ln
𝛿
2
[(π‘₯ − π‘₯0 ) + 𝑀]
2 (𝑑 + πœ‚ + π‘ž) π‘₯0
+𝑀+
(𝛿 + πœ‚ + π‘ž)
𝑝 (𝛿 + πœ‚ + π‘ž)
𝑦+
𝑧,
π‘ž
π‘π‘ž
(10)
where π‘₯0 = 𝑠/𝑑. The derivative of 𝑉1 along positive solutions
of system (2) is given as follows:
𝛿
(π‘₯ − π‘₯0 + 𝑀)
(𝑑 + πœ‚ + π‘ž) π‘₯0
(11)
(𝛿 + πœ‚ + π‘ž)
+
(π‘žπ‘€ − 𝛼𝑦 − 𝑝𝑦𝑧)
π‘ž
+
π‘π‘Ÿ (𝛿 + πœ‚ + π‘ž)
𝑝 (𝛿 + πœ‚ + π‘ž)
𝑦𝑧 −
𝑧.
π‘ž
π‘π‘ž
𝛼 (𝛿 + πœ‚ + π‘ž)
(𝑅0 − 1) 𝑦
π‘ž
−
π‘π‘Ÿ (𝛿 + πœ‚ + π‘ž)
𝑧.
π‘π‘ž
𝛽π‘₯1 𝑦1
𝑦
(𝑦 − 𝑦1 − 𝑦1 ln ) .
π‘žπ‘€1
𝑦1
(13)
π‘₯1
) (𝑠 − 𝑑π‘₯ − 𝛽π‘₯𝑦 + 𝛿𝑀)
π‘₯
+
𝑦
𝛽π‘₯1 𝑦1
(1 − 1 ) (π‘žπ‘€ − 𝛼𝑦 − 𝑝𝑦𝑧)
π‘žπ‘€1
𝑦
+
𝛿
[(π‘₯ − π‘₯1 ) + (𝑀 − 𝑀1 )]
(𝑑 + πœ‚ + π‘ž) π‘₯1
2
(π‘₯ − π‘₯0 )
𝑑𝑉1
𝑑𝛿π‘₯
= − (𝑑π‘₯0 + 𝛿𝑀 +
)
𝑑𝑑
𝑑+πœ‚+π‘ž
π‘₯π‘₯0
+
+
𝑀 𝑑𝑀 𝛽𝑝π‘₯1 𝑦1 𝑑𝑧
𝑑π‘₯ 𝑑𝑀
+
) + (1 − 1 )
+
𝑑𝑑
𝑑𝑑
𝑀 𝑑𝑑
π‘žπ‘π‘€1 𝑑𝑑
= (1 −
On substituting 𝑠 = 𝑑π‘₯0 and 𝛿𝑀(π‘₯ − π‘₯0 )/π‘₯ =
−𝛿𝑀((π‘₯ − π‘₯0 )2 /π‘₯π‘₯0 ) + 𝛿𝑀((π‘₯ − π‘₯0 )/π‘₯0 ) into (11), we derive
that
𝛿 (πœ‚ + π‘ž)
𝑀2
(𝑑 + πœ‚ + π‘ž) π‘₯0
𝛿
2
[(π‘₯ − π‘₯1 ) + (𝑀 − 𝑀1 )]
2 (𝑑 + πœ‚ + π‘ž) π‘₯1
𝛿
[(π‘₯ − π‘₯1 ) + (𝑀 − 𝑀1 )]
(𝑑 + πœ‚ + π‘ž) π‘₯1
×(
+ 𝛽π‘₯𝑦 − (𝛿 + πœ‚ + π‘ž) 𝑀
−
+
𝑦 𝑑𝑦
𝑑𝑉2
π‘₯ 𝑑π‘₯ 𝛽π‘₯1 𝑦1
(1 − 1 )
= (1 − 1 )
+
𝑑𝑑
π‘₯ 𝑑𝑑
π‘žπ‘€1
𝑦 𝑑𝑑
× [𝑠 − 𝑑π‘₯ − (πœ‚ + π‘ž) 𝑀]
+
𝑀 𝛽𝑝π‘₯1 𝑦1
+
𝑧
𝑀1
π‘π‘žπ‘€1
Calculating the derivative of 𝑉2 along positive solutions of
system (2), it follows that
𝑑𝑉1 (π‘₯ − π‘₯0 )
=
(𝑠 − 𝑑π‘₯ − 𝛽π‘₯𝑦 + 𝛿𝑀)
𝑑𝑑
π‘₯
+
π‘₯
π‘₯1
× [𝑠 − 𝑑π‘₯ − (πœ‚ + π‘ž) 𝑀]
(12)
+ (1 −
+
𝑀1
) [𝛽π‘₯𝑦 − (𝛿 + πœ‚ + π‘ž) 𝑀]
𝑀
π›½π‘π‘Ÿπ‘₯1 𝑦1
𝛽𝑝π‘₯1 𝑦1
𝑦𝑧 −
𝑧.
π‘žπ‘€1
π‘π‘žπ‘€1
(14)
4
Journal of Applied Mathematics
At CTL-absent infection equilibrium 𝐸1 , on substituting 𝑠 =
𝛽π‘₯1 𝑦1 + 𝑑π‘₯1 − 𝛿𝑀1 , 𝛼 = π‘ž(𝑀1 /𝑦1 ), and 𝛿 + πœ‚ + π‘ž = 𝛽π‘₯1 𝑦1 /𝑀1
into (14), we obtain that
𝑑𝑉2
𝑑𝑑
Theorem 5. For system (2), if 𝑅1 > 1 and 𝑐𝑑(𝛿 + πœ‚ + π‘ž) −
π‘Ÿπ›½π›Ώ ≥ 0, CTL-present infection equilibrium 𝐸2 is globally
asymptotically stable.
Proof. Define a Lyapunov function
= (1 −
+
+
π‘₯1
) [−𝑑 (π‘₯ − π‘₯1 ) − 𝛽π‘₯𝑦 + 𝛽π‘₯1 𝑦1 + 𝛿 (𝑀 − 𝑀1 )]
π‘₯
𝑉3 (π‘₯, 𝑀, 𝑦, 𝑧)
= π‘₯ − π‘₯2 − π‘₯2 ln
𝛽π‘₯1 𝑦1
𝑦
𝑦
(1 − 1 ) (π‘žπ‘€ − π‘žπ‘€1 − 𝑝𝑦𝑧)
π‘žπ‘€1
𝑦
𝑦1
𝛿
[(π‘₯ − π‘₯1 ) + (𝑀 − 𝑀1 )]
(𝑑 + πœ‚ + π‘ž)
+
𝛿
2
[(π‘₯ − π‘₯2 ) + (𝑀 − 𝑀2 )]
2 (𝑑 + πœ‚ + π‘ž) π‘₯2
+
𝛽π‘₯2 𝑦2
𝑦
(𝑦 − 𝑦2 − 𝑦2 ln )
π‘žπ‘€2
𝑦2
+
𝛽𝑝π‘₯2 𝑦2
𝑧
(𝑧 − 𝑧2 − 𝑧2 ln ) .
π‘π‘žπ‘€2
𝑧2
× [−𝑑 (π‘₯ − π‘₯1 ) − (πœ‚ + π‘ž) (𝑀 − 𝑀1 )]
𝑀
𝑀
+ (1 − 1 ) (𝛽π‘₯𝑦 − 𝛽π‘₯1 𝑦1 )
𝑀
𝑀1
(15)
Noting that
π‘₯
) (𝑀 − 𝑀1 )
π‘₯1
𝑑𝑉3
𝑑𝑑
= (1 −
2
(π‘₯ − π‘₯1 )
𝛿
= −𝛿 (𝑀 − 𝑀1 )
+
(π‘₯ − π‘₯1 ) (𝑀 − 𝑀1 ) ,
π‘₯π‘₯1
π‘₯1
(16)
+
𝑑𝑉2
𝑑𝑑
𝛿
𝑑π‘₯ 𝑑𝑀
[(π‘₯ − π‘₯2 ) + (𝑀 − 𝑀2 )] (
+
)
𝑑𝑑
𝑑𝑑
(𝑑 + πœ‚ + π‘ž) π‘₯2
= (1 −
2
−
(π‘₯ − π‘₯1 )
𝑑𝛿π‘₯
)
𝑑+πœ‚+π‘ž
π‘₯π‘₯1
𝛿 (πœ‚ + π‘ž)
2
(𝑀 − 𝑀1 )
(𝑑 + πœ‚ + π‘ž)
− 𝛽π‘₯1 𝑦1 (
+
𝑦 𝑑𝑦
π‘₯2 𝑑π‘₯ 𝛽π‘₯2 𝑦2
(1 − 2 )
)
+
π‘₯ 𝑑𝑑
π‘žπ‘€2
𝑦 𝑑𝑑
+ (1 −
therefore,
= − (𝑑π‘₯1 − 𝛿𝑀1 + 𝛿𝑀 +
(18)
Calculating the derivative of 𝑉3 along positive solutions of
system (2), we obtain that
𝛽𝑝π‘₯1 𝑦1
π›½π‘Ÿπ‘π‘₯1 𝑦1
+
𝑦𝑧 −
𝑧.
π‘žπ‘€1
π‘π‘žπ‘€1
𝛿 (1 −
π‘₯
𝑀
+ 𝑀 − 𝑀2 − 𝑀2 ln
π‘₯2
𝑀2
π‘₯𝑦𝑀1
π‘₯1 𝑦1 𝑀
+
+
− 3)
π‘₯ 𝑦𝑀1 π‘₯1 𝑦1 𝑀
𝛽𝑝π‘₯1 𝑦1 𝑑 (𝛿 + πœ‚ + π‘ž) + π‘Ÿπ›½ (πœ‚ + π‘ž)
[
] (𝑅1 − 1) 𝑧.
π‘π‘žπ‘€1
𝛽 (πœ‚ + π‘ž)
(17)
Since π‘₯1 /π‘₯ + 𝑦1 𝑀/𝑦𝑀1 + π‘₯𝑦𝑀1 /π‘₯1 𝑦1 𝑀 − 3 ≥ 0 and the equality
holds if and only if π‘₯ = π‘₯1 , 𝑀 = 𝑀1 and 𝑦 = 𝑦1 . If 𝑅0 ≤
1 + (πœ‚ + π‘ž)/𝛿, then 𝑑π‘₯1 − 𝛿𝑀1 ≥ 0. So, if 𝑅1 < 1 and 1 < 𝑅0 ≤
1 + (πœ‚ + π‘ž)/𝛿, then 𝑑𝑉2 /𝑑𝑑 ≤ 0 for all π‘₯ > 0, 𝑀 > 0, 𝑦 > 0
and 𝑧 > 0. Clearly, it follows from (17) that 𝑑𝑉2 /𝑑𝑑 = 0 if and
only if π‘₯ = π‘₯1 , 𝑀 = 𝑀1 , 𝑦 = 𝑦1 , and 𝑧 = 0, thus the largest
invariant set in the set {(π‘₯, 𝑀, 𝑦, 𝑧) ∈ 𝑅+4 | 𝑑𝑉2 /𝑑𝑑 = 0} is the
singleton {𝐸1 }. Therefore, the global asymptotic stability of 𝐸1
follows from the LaSalle’s invariance principle.
𝑧 𝑑𝑧
𝑀2 𝑑𝑀 𝛽𝑝π‘₯2 𝑦2
(1 − 2 )
)
+
𝑀 𝑑𝑑
π‘žπ‘π‘€2
𝑧 𝑑𝑑
π‘₯2
) (𝑠 − 𝑑π‘₯ − 𝛽π‘₯𝑦 + 𝛿𝑀)
π‘₯
+
𝑦
𝛽π‘₯2 𝑦2
(1 − 2 ) (π‘žπ‘€ − 𝛼𝑦 − 𝑝𝑦𝑧)
π‘žπ‘€2
𝑦
+
𝛿
[(π‘₯ − π‘₯2 ) + (𝑀 − 𝑀2 )]
(𝑒 + πœ‚ + π‘ž) π‘₯2
× [𝑠 − 𝑑π‘₯ − (πœ‚ + π‘ž) 𝑀]
+ (1 −
+
𝑀2
) [𝛽π‘₯𝑦 − (𝛿 + πœ‚ + π‘ž) 𝑀]
𝑀
𝛽𝑝π‘₯2 𝑦2
𝑧
(1 − 2 ) (𝑐𝑦𝑧 − π‘Ÿπ‘§) .
π‘žπ‘π‘€2
𝑧
(19)
At CTL- present infection equilibrium 𝐸2 , on substituting 𝑠 =
𝛽π‘₯2 𝑦2 +𝑑π‘₯2 −𝛿𝑀2 , 𝛼 = π‘ž(𝑀2 /𝑦2 )−𝑝𝑧2 , 𝑦2 = π‘Ÿ/𝑐, and 𝛿+πœ‚+π‘ž =
𝛽π‘₯2 𝑦2 /𝑀2 into (19), it follows that
𝑑𝑉3
π‘₯
= (1 − 2 )
𝑑𝑑
π‘₯
× [−𝑑 (π‘₯ − π‘₯2 ) − 𝛽π‘₯𝑦 + 𝛽π‘₯2 𝑦2 + 𝛿 (𝑀 − 𝑀2 )]
Journal of Applied Mathematics
5
+
𝑦
𝛽π‘₯2 𝑦2
𝑦
(1 − 2 ) (π‘žπ‘€ − π‘žπ‘€2 + 𝑝𝑦𝑧2 − 𝑝𝑦𝑧)
π‘žπ‘€1
𝑦
𝑦2
+
𝛿
[(π‘₯ − π‘₯2 ) + (𝑀 − 𝑀2 )]
(𝑑 + πœ‚ + π‘ž)
× [−𝑑 (π‘₯ − π‘₯2 ) − (πœ‚ + π‘ž) (𝑀 − 𝑀2 )]
+ (1 −
𝑀2
𝑀
) (𝛽π‘₯𝑦 − 𝛽π‘₯2 𝑦2 )
𝑀
𝑀2
𝛽𝑝π‘₯2 𝑦2
𝑧
(1 − 2 ) (𝑐𝑦𝑧 − π‘Ÿπ‘§) .
π‘žπ‘π‘€2
𝑧
+
(20)
4. The Stability Analysis of the DDE Model
In this section, we consider the stability of the delay model
(3).
4
) be the Banach space of continuLet 𝐢 = 𝐢 ([−𝜏, 0], 𝑅+0
4
ous functions mapping from the interval [−𝜏, 0] to 𝑅+0
with
the topology of uniform convergence, where
Noting that
2
𝛿 (1 −
Since π‘₯2 /π‘₯+𝑦2 𝑀/𝑦𝑀2 +π‘₯𝑀2 𝑦/π‘₯2 𝑦2 𝑀−3 ≥ 0 and the equality
holds if and only if π‘₯ = π‘₯2 , 𝑀 = 𝑀2 , and 𝑦 = 𝑦2 . If 𝑐𝑑 (𝛿 + πœ‚ +
π‘ž)−π‘Ÿπ›½π›Ώ ≥ 0, then 𝑑π‘₯2 −𝛿𝑀2 = ((𝑐𝑑(𝛿+πœ‚+π‘ž)−π‘Ÿπ›½π›Ώ)/π‘Ÿπ›½)𝑀2 ≥ 0.
Therefore, if 𝑅1 > 1 and 𝑐𝑑 (𝛿 + πœ‚ + π‘ž) − π‘Ÿπ›½π›Ώ ≥ 0, it follows
from (22) that 𝑑𝑉3 /𝑑𝑑 ≤ 0 for all π‘₯ > 0, 𝑀 > 0, 𝑦 > 0, and
𝑧 > 0. Clearly, it follows from (22) that 𝑑𝑉3 /𝑑𝑑 = 0 if and
only if π‘₯ = π‘₯2 , 𝑀 = 𝑀2 , 𝑦 = 𝑦2 , and 𝑧 = 𝑧2 . So the largest
invariant set in the set {(π‘₯, 𝑀, 𝑦, 𝑧) ∈ 𝑅+4 | 𝑑𝑉3 /𝑑𝑑 = 0} is the
singleton {𝐸2 }. By LaSalle invariance principle, we conclude
that the equilibrium 𝐸2 is globally asymptotically stable.
(π‘₯ − π‘₯2 )
π‘₯
) (𝑀 − 𝑀2 ) = − 𝛿 (𝑀 − 𝑀2 )
π‘₯2
π‘₯π‘₯2
(21)
𝛿
+
(π‘₯ − π‘₯2 ) (𝑀 − 𝑀2 ) ,
π‘₯2
4
𝑅+0
= {(π‘₯1 , π‘₯2 , π‘₯3 , π‘₯4 ) | π‘₯𝑖 ≥ 0, 𝑖 = 1, 2, 3, 4} .
it follows from (20) and (21) that
(23)
The initial conditions for system (3) are given as follows:
2
(π‘₯ − π‘₯2 )
𝑑𝑉3
= − (𝑑π‘₯2 + 𝛿 (𝑀 − 𝑀2 ))
𝑑𝑑
π‘₯π‘₯2
+
π‘₯ = πœ‘1 (πœƒ) ,
𝑧 = πœ‘4 (πœƒ) ,
𝛿
(π‘₯ − π‘₯2 ) (𝑀 − 𝑀2 )
π‘₯2
+ 𝛽π‘₯2 𝑦2 (1 −
+ 𝛽π‘₯2 𝑦2 (
−
𝑑
𝛿
2
[
(π‘₯ − π‘₯2 ) + (π‘₯ − π‘₯2 )
π‘₯2 𝑑 + πœ‚ + π‘ž
× (𝑀 − 𝑀2 ) +
(22)
2
(π‘₯ − π‘₯2 )
𝑑𝛿π‘₯
)
𝑑+πœ‚+π‘ž
π‘₯π‘₯2
π‘₯2 𝑦2 𝑀 π‘₯𝑀2 𝑦
+
+
− 3) .
π‘₯ 𝑦𝑀2 π‘₯2 𝑦2 𝑀
𝑧 (0) > 0,
Theorem 7. If 𝑅0 < 1, the uninfected equilibrium 𝐸0 of system
(3) is globally asymptotically stable.
π‘Š1 (π‘₯, 𝑀, 𝑦, 𝑧) = π‘₯ − π‘₯0 − π‘₯0 ln
𝛽𝑝π‘₯2 𝑦2
+
(𝑧 − 𝑧2 ) (𝑦 − 𝑦2 )
π‘žπ‘€2
− 𝛽π‘₯2 𝑦2 (
𝑦 (0) > 0,
(24)
Proof. If 𝑅0 < 1, construct a Lyapunov functional
π‘₯𝑦
π‘₯𝑀2 𝑦
𝑀
−
−
+ 1)
π‘₯2 𝑦2 𝑀2 π‘₯2 𝑀𝑦2
𝛿 (πœ‚ + π‘ž)
2
−
(𝑀 − 𝑀2 )
(𝑑 + πœ‚ + π‘ž)
πœƒ ∈ [−𝜏, 0] ,
Theorem 6. Let π‘₯(𝑑), 𝑀(𝑑), 𝑦(𝑑), and 𝑧(𝑑) be the solution of
system (3) satisfying the initial conditions (24), then there exists
𝑀 > 0 such that π‘₯(𝑑) < 𝑀, 𝑀(𝑑) < 𝑀, 𝑦(𝑑) < 𝑀, and 𝑧(𝑑) <
𝑀 hold after sufficiently large time 𝑑.
πœ‚+π‘ž
2
(𝑀 − 𝑀2 ) ]
𝑑+πœ‚+π‘ž
= − (𝑑π‘₯2 − 𝛿𝑀2 + 𝛿𝑀 +
𝑀 (0) > 0,
𝑦 = πœ‘3 (πœƒ) ,
4
where (πœ‘1 (πœƒ), πœ‘2 (πœƒ), πœ‘3 (πœƒ), πœ‘4 (πœƒ)) ∈ 𝐢([−𝜏, 0], 𝑅+0
). It is clear
to see that all solutions of system (3) satisfying the initial
conditions (24) are positive for all 𝑑 ≥ 0. By the similar
method to Theorem 2, we can get the following theorem.
𝑦 𝑦2 𝑀
𝑀
−
−
+ 1)
𝑀2 𝑦2 𝑦𝑀2
𝛽𝑝π‘₯2 𝑦2
(𝑦 − 𝑦2 ) (𝑧 − 𝑧2 )
π‘žπ‘€2
+ 𝛽π‘₯2 𝑦2 (
π‘₯ (0) > 0,
π‘₯𝑦
𝑦
π‘₯
− 2+ )
π‘₯2 𝑦2
π‘₯ 𝑦2
−
𝑀 = πœ‘2 (πœƒ) ,
π‘₯
π‘₯0
+
𝛿
2
[(π‘₯ − π‘₯0 ) + 𝑀] + 𝑀
2 (𝑑 + πœ‚ + π‘ž) π‘₯0
+
(𝛿 + πœ‚ + π‘ž)
𝑝 (𝛿 + πœ‚ + π‘ž)
𝑦+
𝑧
π‘ž
π‘π‘ž
+
𝑝 (𝛿 + πœ‚ + π‘ž) 𝑑
∫ 𝑦 (πœƒ) 𝑧 (πœƒ) π‘‘πœƒ,
π‘ž
𝑑−𝜏
(25)
6
Journal of Applied Mathematics
where π‘₯0 = 𝑠/𝑑. Calculating the derivative of π‘Š1 along
positive solutions of system (3), it follows that
+
+ 𝑀 − 𝑀1 − 𝑀1 ln
π‘‘π‘Š1 (π‘₯ − π‘₯0 )
=
(𝑠 − 𝑑π‘₯ − 𝛽π‘₯𝑦 + 𝛿𝑀)
𝑑𝑑
π‘₯
𝛿
(π‘₯ − π‘₯0 + 𝑀)
+
(𝑑 + πœ‚ + π‘ž) π‘₯0
+
× [𝑠 − 𝑑π‘₯ − (πœ‚ + π‘ž) 𝑀]
+
(𝛿 + πœ‚ + π‘ž)
(π‘žπ‘€ − 𝛼𝑦 − 𝑝𝑦𝑧) + 𝛽π‘₯𝑦
π‘ž
− (𝛿 + πœ‚ + π‘ž) 𝑀 +
−
(26)
𝑝 (𝛿 + πœ‚ + π‘ž)
𝑦𝑧
π‘ž
+
If 𝑅0 < 1, we have π‘‘π‘Š1 /𝑑𝑑 ≤ 0 for all π‘₯ > 0, 𝑀 > 0, 𝑦 > 0,
and 𝑧 > 0. It follows that the uninfected equilibrium 𝐸0 is
stable. Clearly, it follows from (27) that π‘‘π‘Š1 /𝑑𝑑 = 0 if and
only if π‘₯ = 𝑠/𝑑, 𝑀 = 0, 𝑦 = 0, and 𝑧 = 0. Therefore the largest
invariant set in the set {(π‘₯, 𝑀, 𝑦, 𝑧) ∈ 𝑅+4 | π‘‘π‘Š1 /𝑑𝑑 = 0} is the
singleton {𝐸0 }. By LaSalle invariance principle [21], we can
conclude that the equilibrium 𝐸0 is globally asymptotically
stable.
From the above analysis, we can obtain that the time delay
has no effect on the stability of the uninfected equilibrium 𝐸0
for the DDE model.
Theorem 8. For system (3), if 𝑅1 < 1 and 1 < 𝑅0 ≤ 1 +
(πœ‚ + π‘ž)/𝛿, then CTL-absent infection equilibrium 𝐸1 is globally
asymptotically stable.
+
π‘₯
π‘₯1
𝛽π‘₯1 𝑦1
𝑦
(𝑦 − 𝑦1 − 𝑦1 ln )
π‘žπ‘€1
𝑦1
+
𝛿
[(π‘₯ − π‘₯1 ) + (𝑀 − 𝑀1 )]
(𝑑 + πœ‚ + π‘ž) π‘₯1
(27)
𝛼 (𝛿 + πœ‚ + π‘ž)
π‘π‘Ÿ (𝛿 + πœ‚ + π‘ž)
(𝑅0 − 1) 𝑦 −
𝑧.
π‘ž
π‘π‘ž
π‘Š2 (π‘₯, 𝑀, 𝑦, 𝑧) = π‘₯ − π‘₯1 − π‘₯1 ln
𝛽π‘₯1 𝑦1
𝑦
(1 − 1 ) (π‘žπ‘€ − 𝛼𝑦 − 𝑝𝑦𝑧)
π‘žπ‘€1
𝑦
+ (1 −
2
Proof. Define a lyapunov functional
+
(29)
× [𝑠 − 𝑑π‘₯ − (πœ‚ + π‘ž) 𝑀]
π‘‘π‘Š1
𝑑𝛿π‘₯
= − (𝑑π‘₯0 + 𝛿𝑀 +
)
𝑑𝑑
𝑑+πœ‚+π‘ž
𝛿𝑀 (πœ‚ + π‘ž)
(π‘₯ − π‘₯0 )
−
π‘₯π‘₯0
(𝑑 + πœ‚ + π‘ž) π‘₯0
𝛽𝑝π‘₯1 𝑦1
𝛽𝑝π‘₯1 𝑦1 𝑑
𝑧+
∫ 𝑦 (πœƒ) 𝑧 (πœƒ) π‘‘πœƒ.
π‘π‘žπ‘€1
π‘žπ‘€1
𝑑−𝜏
(28)
Calculating the derivative of π‘Š2 along positive solutions of
system (3), it follows that
On substituting 𝑠 = 𝑑π‘₯0 and 𝛿𝑀(π‘₯ − π‘₯0 )/π‘₯ =
−𝛿𝑀((π‘₯ − π‘₯0 )2 /π‘₯π‘₯0 ) + 𝛿𝑀((π‘₯ − π‘₯0 )/π‘₯0 ) into (26), we derive
that
×
𝑀
𝑀1
π‘₯
π‘‘π‘Š2
= (1 − 1 ) (𝑠 − 𝑑π‘₯ − 𝛽π‘₯𝑦 + 𝛿𝑀)
𝑑𝑑
π‘₯
π‘π‘Ÿ (𝛿 + πœ‚ + π‘ž)
𝑧.
π‘π‘ž
2
𝛿
2
[(π‘₯ − π‘₯1 ) + (𝑀 − 𝑀1 )]
2 (𝑑 + πœ‚ + π‘ž) π‘₯1
−
𝑀1
) [𝛽π‘₯𝑦 − (𝛿 + πœ‚ + π‘ž) 𝑀]
𝑀
π›½π‘π‘Ÿπ‘₯1 𝑦1
𝛽𝑝π‘₯1 𝑦1
𝑧+
𝑦𝑧.
π‘π‘žπ‘€1
π‘žπ‘€1
At CTL-absent infection equilibrium 𝐸1 , on substituting 𝑠 =
𝛽π‘₯1 𝑦1 + 𝑑π‘₯1 − 𝛿𝑀1 , 𝛼 = π‘ž(𝑀1 /𝑦1 ), and 𝛿 + πœ‚ + π‘ž = 𝛽π‘₯1 𝑦1 /𝑀1
into (29), we obtain that
π‘‘π‘Š2
𝑑𝑑
= (1 −
π‘₯1
) [−𝑑 (π‘₯ − π‘₯1 ) − 𝛽π‘₯𝑦 + 𝛽π‘₯1 𝑦1 + 𝛿 (𝑀 − 𝑀1 )]
π‘₯
+
𝛽π‘₯1 𝑦1
𝑦
𝑦
(1 − 1 ) (π‘žπ‘€ − π‘žπ‘€1 − 𝑝𝑦𝑧)
π‘žπ‘€1
𝑦
𝑦1
+
𝛿
[(π‘₯ − π‘₯1 ) + (𝑀 − 𝑀1 )]
(𝑑 + πœ‚ + π‘ž)
× [−𝑑 (π‘₯ − π‘₯1 ) − (πœ‚ + π‘ž) (𝑀 − 𝑀1 )]
+ (1 −
−
𝑀1
𝑀
) (𝛽π‘₯𝑦 − 𝛽π‘₯1 𝑦1 )
𝑀
𝑀1
π›½π‘Ÿπ‘π‘₯1 𝑦1
𝛽𝑝π‘₯1 𝑦1
𝑧+
𝑦𝑧.
π‘π‘žπ‘€1
π‘žπ‘€1
(30)
Journal of Applied Mathematics
7
It follows from (16) and (30) that
Firstly, the linearized equations of system (3) at 𝐸2 are
given as follows:
2
(π‘₯ − π‘₯1 )
π‘‘π‘Š2
= − (𝑑π‘₯1 + 𝛿 (𝑀 − 𝑀1 ))
𝑑𝑑
π‘₯π‘₯1
+
𝑑π‘₯
= − (𝛽𝑦2 + 𝑑) π‘₯ (𝑑) − 𝛽π‘₯2 𝑦 (𝑑) + 𝛿𝑀 (𝑑) ,
𝑑𝑑
𝛿
(π‘₯ − π‘₯1 ) (𝑀 − 𝑀1 )
π‘₯1
𝑑𝑀
= 𝛽𝑦2 π‘₯ (𝑑) + 𝛽π‘₯2 𝑦 (𝑑) − (𝛿 + πœ‚ + π‘ž) 𝑀 (𝑑) ,
𝑑𝑑
𝑑𝑦
= π‘žπ‘€ (𝑑) − (𝛼 + 𝑝𝑧2 ) 𝑦 (𝑑) − 𝑝𝑦2 𝑧 (𝑑) ,
𝑑𝑑
π‘₯𝑦
𝑦
π‘₯
+ 𝛽π‘₯1 𝑦1 (1 −
− 1+ )
π‘₯1 𝑦1
π‘₯ 𝑦1
𝑦 𝑦1 𝑀
𝑀
−
−
+ 1)
+ 𝛽π‘₯1 𝑦1 (
𝑀1 𝑦1 𝑦𝑀1
𝛽π‘₯ 𝑦
𝑦
− 1 1 (1 − 1 ) 𝑝𝑦𝑧
π‘žπ‘€1
𝑦
+ 𝛽π‘₯1 𝑦1 (
−
π‘₯𝑦
π‘₯𝑀1 𝑦
𝑀
−
−
+ 1)
π‘₯1 𝑦1 𝑀1 π‘₯1 𝑀𝑦1
𝑑
𝛿
2
[
(π‘₯ − π‘₯1 ) + (π‘₯ − π‘₯1 )
π‘₯1 𝑑 + πœ‚ + π‘ž
× (𝑀 − 𝑀1 ) +
πœ‚+π‘ž
2
(𝑀 − 𝑀1 ) ]
𝑑+πœ‚+π‘ž
π›½π‘Ÿπ‘π‘₯1 𝑦1
𝛽𝑝π‘₯1 𝑦1
−
𝑧+
𝑦𝑧
π‘π‘žπ‘€1
π‘žπ‘€1
= − (𝑑π‘₯1 − 𝛿𝑀1 + 𝛿𝑀 +
𝑑𝛿π‘₯
)
𝑑+πœ‚+π‘ž
2
×
𝛿 (πœ‚ + π‘ž)
(π‘₯ − π‘₯1 )
2
−
(𝑀 − 𝑀1 )
π‘₯π‘₯1
(𝑑 + πœ‚ + π‘ž)
π‘₯𝑦𝑀1
𝑦𝑀
π‘₯
− 𝛽π‘₯1 𝑦1 ( 1 + 1 +
− 3)
π‘₯ 𝑦𝑀1 π‘₯1 𝑦1 𝑀
𝛽𝑝π‘₯1 𝑦1 𝑑 (𝛿 + πœ‚ + π‘ž) + π‘Ÿπ›½ (πœ‚ + π‘ž)
+
[
] (𝑅1 − 1) 𝑧.
π‘π‘žπ‘€1
𝛽 (πœ‚ + π‘ž)
(31)
Since π‘₯1 /π‘₯ + 𝑦1 𝑀/𝑦𝑀1 + π‘₯𝑦𝑀1 /π‘₯1 𝑦1 𝑀 − 3 ≥ 0 and the equality
holds if and only if π‘₯ = π‘₯1 , 𝑀 = 𝑀1 , and 𝑦 = 𝑦1 . If 𝑅0 ≤
1 + (πœ‚ + π‘ž)/𝛿, then 𝑑π‘₯1 − 𝛿𝑀1 ≥ 0. Therefore, if 𝑅1 < 1 and 1 <
𝑅0 ≤ 1 + (πœ‚ + π‘ž)/𝛿, it follows from (31) that π‘‘π‘Š2 /𝑑𝑑 ≤ 0 for all
π‘₯ > 0, 𝑀 > 0, 𝑦 > 0, and 𝑧 > 0. It is readily seen from (31) that
π‘‘π‘Š2 /𝑑𝑑 = 0 if and only if π‘₯ = π‘₯1 , 𝑀 = 𝑀1 , 𝑦 = 𝑦1 , and 𝑧 = 0.
Thus the largest invariant set in the set {(π‘₯, 𝑀, 𝑦, 𝑧) ∈ 𝑅+4 |
π‘‘π‘Š2 /𝑑𝑑 = 0} is the singleton {𝐸1 }. Then the global asymptotic
stability of 𝐸1 follows from the LaSalle’s invariance principle
[21].
From the above analysis, we obtain that the time delay
has no effect on the stability of the CTL-absent infection
equilibrium 𝐸1 for the DDE model. Next, we analyze stability
and Hopf bifurcation at the CTL-present equilibrium 𝐸2 .
(32)
𝑑𝑧
= 𝑐𝑧2 𝑦 (𝑑 − 𝜏) + 𝑐𝑦2 𝑧 (𝑑 − 𝜏) − π‘Ÿπ‘§ (𝑑) .
𝑑𝑑
The characteristic equation of system (32) at 𝑂 (0, 0, 0, 0)
takes the form
𝐺 (πœ†) = πœ†4 + 𝑀1 πœ†3 + 𝑀2 πœ†2 + 𝑀3 πœ† + 𝑀4
− (𝑁1 πœ†3 + 𝑁2 πœ†2 + 𝑁3 πœ† + 𝑁4 ) e−πœ†πœ = 0,
(33)
where
𝑀1 = 𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž + 𝛼 + 𝑝𝑧2 + π‘Ÿ,
𝑀2 = 𝛽𝑦2 (πœ‚ + π‘ž) + 𝑑 (𝛿 + πœ‚ + π‘ž)
+ (𝛽𝑦2 + 𝑑) (𝛼 + 𝑝𝑧2 )
+ π‘Ÿ (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž + 𝛼 + 𝑝𝑧2 ) ,
𝑀3 = π‘Ÿ [𝛽𝑦2 (πœ‚ + π‘ž) + 𝑑 (𝛿 + πœ‚ + π‘ž)
+ (𝛽𝑦2 + 𝑑) (𝛼 + 𝑝𝑧2 )]
+ 𝛽𝑦2 (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 ) ,
𝑀4 = π‘Ÿπ›½π‘¦2 (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 ) ,
𝑁1 = π‘Ÿ,
(34)
𝑁2 = π‘Ÿ (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž + 𝛼 + 𝑝𝑧2 )
− 𝑐𝑝𝑦2 𝑧2 ,
𝑁3 = π‘Ÿ [𝛽𝑦2 (πœ‚ + π‘ž) + 𝑑 (𝛿 + πœ‚ + π‘ž)
+ (𝛽𝑦2 + 𝑑) (𝛼 + 𝑝𝑧2 )]
− 𝑐𝑝𝑦2 𝑧2 (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž) ,
𝑁4 = π‘Ÿπ›½π‘¦2 (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 )
− 𝑐𝑝𝑦2 𝑧2 [𝛽𝑦2 (πœ‚ + π‘ž) + 𝑑 (𝛿 + πœ‚ + π‘ž)] .
Theorem 9. Suppose 𝜏 = 0, if 𝑅1 > 1, then the CTL-present
equilibrium 𝐸2 of system (3) is locally asymptotically stable.
Proof. If 𝜏 = 0, (33) becomes
πœ†4 + (𝑀1 − 𝑁1 ) πœ†3 + (𝑀2 − 𝑁2 ) πœ†2
+ (𝑀3 − 𝑁3 ) πœ† + 𝑀4 − 𝑁4 = 0.
(35)
8
Journal of Applied Mathematics
Since 𝑅1 > 1, π‘₯2 > 0, 𝑀2 > 0, 𝑦2 > 0, and 𝑧2 > 0, by the
Routh-Hurwitz criteria, it follows that
𝐢 = 𝛽𝑦2 (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 ) (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž)
× [𝛽𝑦2 (πœ‚ + π‘ž) + 𝑑 (𝛿 + πœ‚ + π‘ž) (𝛽𝑦2 + 𝑑) (𝛼 + 𝑝𝑧2 )]
𝐻1 = 𝑀1 − 𝑁1 = 𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž + 𝛼 + 𝑝𝑧2 > 0,
2
+ 𝛽𝑦2 (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 )
𝐻2 = (𝑀1 − 𝑁1 ) (𝑀2 − 𝑁2 ) − (𝑀3 − 𝑁3 )
× [𝑑 (𝛿 + πœ‚ + π‘ž) + (𝛽𝑦2 + 𝑑) (𝛼 + 𝑝𝑧2 )] > 0.
(37)
= [𝛽𝑦2 (πœ‚ + π‘ž) + 𝑑 (𝛿 + πœ‚ + π‘ž)
+ (𝛽𝑦2 + 𝑑) (𝛼 + 𝑝𝑧2 ) + 𝑐𝑝𝑦2 𝑧2 ]
Let
2
× (𝛽𝑦2 𝑑 + 𝛿 + πœ‚ + π‘ž + 𝛼 + 𝑝𝑧2 )
𝐷 = 𝛽𝑦2 (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 ) ,
β„Ž = 𝑐𝑝𝑦2 𝑧2 > 0,
− 𝛽𝑦2 (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 )
𝑓 (β„Ž) = π΄β„Ž2 + π΅β„Ž + 𝐢,
− 𝑐𝑝𝑦2 𝑧2 (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž)
𝑔 (β„Ž) = π΄β„Ž2 − π·β„Ž + 𝐢.
= [𝑑 (𝛿 + πœ‚ + π‘ž) + (𝛽𝑦2 + 𝑑) (𝛼 + 𝑝𝑧2 )]
(38)
If 𝑔(β„Ž) > 0 for all β„Ž > 0, then 𝑓(β„Ž) > 0. Since
× [𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž + 𝛼 + 𝑝𝑧2 ]
Δ 1 = 𝐷2 − 4𝐴𝐢
+ 𝛽𝑦2 (πœ‚ + π‘ž) (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž)
3
= − 4(𝛼 + 𝑝𝑧2 ) (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž) 𝛽𝑦2 (πœ‚ + π‘ž)
+ 𝑐𝑝𝑦2 𝑧2 (𝛼 + 𝑝𝑧2 ) > 0,
× [𝑑 (𝛿 + πœ‚ + π‘ž) + (𝛽𝑦2 + 𝑑) (𝛼 + 𝑝𝑧2 )]
𝐻3 = (𝑀1 − 𝑁1 ) [(𝑀2 − 𝑁2 ) (𝑀3 − 𝑁3 )
2
2
− (𝑀1 − 𝑁1 ) (𝑀4 − 𝑁4 )] − (𝑀3 − 𝑁3 )
= [𝛽𝑦2 (πœ‚ + π‘ž) + 𝑑 (𝛿 + πœ‚ + π‘ž)
− 4(𝛼 + 𝑝𝑧2 ) (𝛽𝑦2 + 𝑑 + 𝛿) 𝛽𝑦2 (πœ‚ + π‘ž)
× (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž)
× [𝛽𝑦2 (πœ‚ + π‘ž)
+ (𝛽𝑦2 + 𝑑) (𝛼 + 𝑝𝑧2 ) + 𝑐𝑝𝑦2 𝑧2 ]
(39)
+ 𝑑 (𝛿 + πœ‚ + π‘ž) (𝛽𝑦2 + 𝑑) (𝛼 + 𝑝𝑧2 )]
× (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž + 𝛼 + 𝑝𝑧2 )
3
2
− 4(𝛼 + 𝑝𝑧2 ) (πœ‚ + π‘ž) 𝛽𝑦2 (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž)
× [𝛽𝑦2 (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 )
× π‘‘ (𝛿 + πœ‚ + π‘ž) (𝛽𝑦2 + 𝑑)
+𝑐𝑝𝑦2 𝑧2 (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž)]
2
2
2
2
− 3[𝛽𝑦2 (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 )] < 0,
× π‘π‘π‘¦2 𝑧2 [𝛽𝑦2 (πœ‚ + π‘ž) + 𝑑 (𝛿 + πœ‚ + π‘ž)]
and 𝑔(0) = 𝐢 > 0, it follows that 𝑔(β„Ž) > 0 for all β„Ž > 0, thus
𝑓(β„Ž) > 0, that is, 𝐻3 > 0.
− [𝛽𝑦2 (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 )
+ 𝑐𝑝𝑦2 𝑧2 (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž)]
3
− 4(𝛼 + 𝑝𝑧2 ) (πœ‚ + π‘ž) (𝛽𝑦2 ) (𝛽𝑦2 + 𝑑 + 𝛿)
2
− (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž + 𝛼 + 𝑝𝑧2 )
2
2
= 𝐴(𝑐𝑝𝑦2 𝑧2 ) + 𝐡𝑐𝑝𝑦2 𝑧2 + 𝐢,
(36)
󡄨󡄨𝑀 − 𝑁 𝑀 − 𝑁
󡄨󡄨
0
0
1
3
3
󡄨󡄨 1
󡄨󡄨
󡄨󡄨
󡄨󡄨
−
𝑁
𝑀
−
𝑁
0
1
𝑀
󡄨
󡄨󡄨
2
2
4
4
𝐻4 = 󡄨󡄨󡄨
󡄨󡄨
0
0
𝑀1 − 𝑁1 𝑀3 − 𝑁3
󡄨󡄨
󡄨󡄨󡄨
󡄨󡄨
0
1
𝑀2 − 𝑁2 𝑀4 − 𝑁4 󡄨󡄨󡄨
(40)
= (𝑀4 − 𝑁4 ) 𝐻3 .
where
𝐴 = (𝛼 + 𝑝𝑧2 ) (𝛽𝑦2 + 𝑑 + 𝛿 + πœ‚ + π‘ž) > 0,
2
𝐡 = [(𝛽𝑦2 + 𝑑) + 𝛽𝑦2 𝛿] (𝛼 + 𝑝𝑧2 )
2
× (𝛽𝑦2 + 𝑑 + 𝛼 + 𝑝𝑧2 ) + [(𝛽𝑦2 + 𝑑) + 𝛽𝑦2 𝛿]
× π›Ώ (𝛼 + 𝑝𝑧2 ) + (𝛽𝑑𝑦2 + 𝑑2 ) (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 )
2
− 𝛽𝑦2 (πœ‚ + π‘ž) (𝛼 + 𝑝𝑧2 ) ,
Noting that
𝑀4 − 𝑁4 = 𝑐𝑝𝑦2 𝑧2 [𝛽𝑦2 (πœ‚ + π‘ž) + 𝑑 (𝛿 + πœ‚ + π‘ž)] > 0, (41)
it follows that 𝐻4 > 0. Therefore, all the roots of (35) have
negative real parts. This completes the proof of Theorem 9.
For 𝜏 = 0, the all roots of 𝐺(πœ†) = 0 have negative real
roots in Theorem 9. By the continuous dependence of roots
Journal of Applied Mathematics
9
of 𝐺(πœ†) = 0 on the parameters, it follows that there exists
𝜏 > 0 such that for 𝜏 ∈ [0, 𝜏), all roots of (33) satisfy
𝐺 (πœ†) = 0,
Re (πœ†) < 0,
for 𝜏 ∈ [0, 𝜏) ,
Denote 𝐺(𝑒) = 𝑒4 + π‘ž1 𝑒3 + π‘ž2 𝑒2 + π‘ž3 𝑒 + π‘ž4 . Then we have
𝐺󸀠 (𝑒) = 4𝑒3 + 3π‘ž1 𝑒2 + 2π‘ž2 𝑒 + π‘ž3 .
(42)
and when 𝜏 = 𝜏, Re (πœ†) = 0. To determine 𝜏 and the
associated purely imaginary roots πœ”π‘– (πœ” > 0).
Suppose that πœ† = πœ”π‘– (πœ” > 0) is a solution of (33), it follows
that
Suppose that (49) has positive real roots. Without loss of
generality, we assume that it has 𝑛 (1 ≤ 𝑛 ≤ 4) positive real
roots, defined by 𝑒1 < 𝑒2 < ⋅ ⋅ ⋅ < 𝑒𝑛 , respectively. Then (47)
has 𝑛 positive real roots
πœ”1 = √𝑒1 , πœ”2 = √𝑒2 , . . . , πœ”π‘› = √𝑒𝑛 .
πœ”4 − 𝑀1 πœ”3 𝑖 − 𝑀2 πœ”2 𝑖 + 𝑀3 πœ”π‘–
− (−𝑁1 πœ”3 𝑖 − 𝑁2 πœ”2 + 𝐡3 πœ”π‘– + 𝐡4 ) (cos πœ”πœ − 𝑖 sin πœ”πœ) = 0.
(43)
Separating the real and imaginary parts, it follows that
(𝑁4 − 𝑁2 πœ”2 ) cos πœ”πœ + (𝑁3 πœ” − 𝑁1 πœ”3 ) sin πœ”πœ
= πœ”4 − 𝑀2 πœ”2 + 𝑀4 ,
(𝑁1 πœ”3 − 𝑁3 πœ”) cos πœ”πœ + (𝑁4 − 𝑁2 πœ”2 ) sin πœ”πœ
(44)
= 𝑀1 πœ” − 𝑀3 πœ”.
𝑗
πœπ‘™ =
𝐴 πœ”6 + 𝐴 2 πœ”π‘™4 + 𝐴 3 πœ”π‘™2 + 𝐴 4
1
(arccos 1 𝑙
+2π‘—πœ‹) , (52)
2
2
πœ”π‘™
(𝑁4 −𝑁2 πœ”π‘™2 ) +(𝑁3 πœ”π‘™ −𝑁1 πœ”π‘™3 )
where 𝑙 = 1, 2, . . . , 𝑛, 𝑗 = 0, 1, 2, 3, . . ., then ± πœ”π‘™ i are a pair of
𝑗
purely imaginary roots of (33) with πœπ‘™ .
Differentiating (33) implicitly with respect to 𝜏, we obtain
that
From (44), we obtain that
1
(𝐴 1 πœ”6 + 𝐴 2 πœ”4 + 𝐴 3 πœ”2 + 𝐴 4 ) ,
Δ
πœ”
sin πœ”πœ = − (𝐡1 πœ”6 + 𝐡2 πœ”4 + 𝐡3 πœ”2 + 𝐡4 ) ,
Δ
3𝑁1 πœ†2 + 2𝑁2 πœ† + 𝑁3
𝜏
+
− .
πœ† (𝑁1 πœ†3 + 𝑁2 πœ†2 + 𝑁3 πœ† + 𝑁4 ) πœ†
cos πœ”πœ =
(45)
π‘‘πœ† −1
1
=
]
{(3𝑀1 πœ”π‘™2 − 𝑀3 )
𝑗
π‘‘πœ 𝜏=πœπ‘™
πœ”π‘™ Δ
𝐴 1 = 𝑀1 𝑁1 − 𝑁2 ,
× [(𝑁1 πœ”π‘™3 − 𝑁3 πœ”π‘™ ) cos πœ”π‘™ 𝜏
𝐴 2 = 𝑁4 + 𝑀2 𝑁2 − 𝑀1 𝑁3 − 𝑀3 𝑁1 ,
𝐴 3 = 𝑀3 𝑁3 − 𝑀2 𝑁4 − 𝑀4 𝑁2 ,
𝐡1 = 𝑁1 ,
+ (𝑁4 − 𝑁4 πœ”π‘™2 ) sin πœ”π‘™ 𝜏]
𝐴 4 = 𝑀4 𝑁4 ,
𝐡2 = 𝑀1 𝑁2 − 𝑁3 − 𝑀2 𝑁1 ,
+ (4πœ”π‘™3 − 2𝑀2 πœ”π‘™ )
(46)
− (𝑁1 πœ”π‘™3 − 𝑁3 πœ”π‘™ ) sin πœ”π‘™ 𝜏]
𝐡4 = 𝑀3 𝑁4 − 𝑀4 𝑁3 ,
2
+ (𝑁3 − 3𝑁1 πœ”π‘™2 ) (𝑁1 πœ”π‘™3 − 𝑁3 πœ”π‘™ )
Δ = (𝑁4 − 𝑁2 πœ”2 ) + (𝑁3 πœ” − 𝑁1 πœ”3 ) > 0.
+ 2𝑁2 πœ”π‘™ (𝑁4 − 𝑁2 πœ”π‘™2 )} .
It follows from (44) that
πœ”8 + π‘ž1 πœ”6 + π‘ž2 πœ”4 + π‘ž3 πœ”2 + π‘ž4 = 0,
(47)
On substituting (45) into (54), we obtain
where
π‘ž1 =
(54)
× [(𝑁4 − 𝑁2 πœ”π‘™2 ) cos πœ”π‘™ 𝜏
𝐡3 = 𝑀2 𝑁3 + 𝑀4 𝑁1 − 𝑀3 𝑁2 − 𝑀1 𝑁4 ,
2
(53)
Thus,
Re [
where
(51)
From (45), we have
3
2
πœ†πœ
π‘‘πœ† −1 − (4πœ† + 3𝑀1 πœ† + 2𝑀2 πœ† + 𝑀3 ) e
[ ] =
π‘‘πœ
πœ† (𝑁1 πœ†3 + 𝑁2 πœ†2 + 𝑁3 πœ† + 𝑁4 )
3
(50)
𝑀12
− 2𝑀2 −
Re [
𝑁12 ,
π‘ž2 = 𝑀22 + 2𝑀4 − 2𝑀1 𝑀3 + 2𝑁1 𝑁3 − 𝑀22 ,
π‘ž3 = 𝑀32 − 2𝑀2 𝑀4 + 2𝑁2 𝑁4 − 𝑀32 ,
=
π‘ž4 = 𝑀42 − 𝑁42 .
(48)
Letting 𝑒 = πœ”2 , (47) becomes
𝑒4 + π‘ž1 𝑒3 + π‘ž2 𝑒2 + π‘ž3 𝑒 + π‘ž4 = 0.
π‘‘πœ† −1
]
π‘‘πœ 𝜏=πœπ‘™π‘—
1
[4πœ”π‘™6 + 3 (𝑀12 − 2𝑀2 − 𝑁12 ) πœ”π‘™4
Δ
+ 2 (𝑀22 − 𝑁22 + 2𝑀4 + 2𝑁1 𝑁3 − 2𝑀1 𝑀3 ) πœ”π‘™2
+𝑀32 − 𝑁32 + 2𝑁2 𝑁4 − 2𝑀2 𝑀4 ] =
(49)
𝐺󸀠 (𝑒𝑙 )
,
Δ
(55)
10
Journal of Applied Mathematics
2
2
where Δ = (𝑁4 − 𝑁2 πœ”2 ) +(𝑁3 πœ” − 𝑁1 πœ”3 ) > 0. If we suppose
that 𝐺󸀠 (𝑒) =ΜΈ 0, then
12
10
π‘‘πœ†
π‘‘πœ† −1
sign {Re [ ] } = sign {Re [ ] }
π‘‘πœ 𝜏=πœπ‘™π‘—
π‘‘πœ 𝜏=πœπ‘™π‘—
𝐺󸀠 (𝑒𝑙 )
} = sign {𝐺󸀠 (𝑒𝑙 )} .
Δ
(56)
𝑧(𝑑)
= sign {
8
4
Applying Theorem 9 and the Hopf bifurcation theorem for
functional differential equation [22] from (56), we derive the
existence of a Hopf bifurcation as follows.
2
7
2
𝑦(
𝑑)
6
1.5
)
π‘₯(𝑑
5
4 1
Figure 1: The CTL-present infection equilibrium 𝐸2 of system (3) is
locally asymptotically stable when 𝑅1 = 1.33 > 1 and 𝜏 = 1.5.
Remark 11. If 𝑒 is the last simple positive root of (49), then
we have 𝐺󸀠 (𝑒) > 0. From (56), we obtain Re [π‘‘πœ†/π‘‘πœ]𝜏=𝜏 > 0.
0.8
0.75
0.7
𝑧(𝑑)
Remark 12. In this paper, we construct a few Lyapunov functions (functionals) to prove the global stability of steady states
of ODE model (DDE model). This function (functional)
can also prove the global stability of steady states of other
viral infections models with cure rate [7, 10]. Moreover, the
method studying the existence of Hopf bifurcations applies to
other viral infections models with immune delay [2, 18, 19].
𝐸2
0
8
Theorem 10. Suppose that (49) has at least one simple positive
root and 𝑒 is the last such root, then there is a Hopf bifurcation
for the system (3) as 𝜏 passes upwards through 𝜏 leading to a
periodic solution that bifurcates from 𝐸2 , where
𝐴 1 πœ”6𝑙 + 𝐴 2 πœ”4𝑙 + 𝐴 3 πœ”2𝑙 + 𝐴 4
1
𝜏 = (arccos
+ 2π‘—πœ‹) .
2
2
πœ”
(𝑁4 − 𝑁2 πœ”2𝑙 ) + (𝑁3 πœ”π‘™ − 𝑁1 πœ”3𝑙 )
(57)
6
0.65
0.6
0.55
0.5
5. Numerical Simulations
In this section, we perform numerical calculation to support
our theoretical analysis of this paper.
4
3
2
𝑒 + 10.5385𝑒 + 3.9615𝑒 + 0.0729𝑒 + 0.0151 = 0.
(58)
Equation (58) has no positive roots, and all roots have
negative real parts. Therefore, the equilibrium is locally
asymptotically stable for all 𝜏 ≥ 0 (e.g., 𝜏 = 1.5, see Figure 1).
Example 14. If we select parameters 𝑠 = 10, 𝛽 = 0.1, 𝛼 =
0.4, 𝑝 = 0.3, 𝑐 = 0.5, π‘Ÿ = 0.9, 𝑑 = 1, 𝛿 = 1, πœ‚ = 1, and
π‘ž = 4, then 𝑅1 = 1.45 > 1 and the CTL-present equilibrium
𝐸2 (8.8107, 0.2642, 1.7997, 0.6244). It follows from (49) that
𝑒4 + 40.7439𝑒3 + 41.9038𝑒2 − 1.9589𝑒 − 2.0726 = 0.
(59)
Equation (59) has only one positive real root 𝑒 =
0.2217 and any other roots have negative real parts. Thus,
2.2
𝑑)
𝑦(
Example 13. If we choose parameters 𝑠 = 1.5, 𝛽 = 0.3, 𝛼 =
0.1, 𝑝 = 0.015, 𝑐 = 0.12, π‘Ÿ = 0.8, 𝑑 = 0.1, 𝛿 = 0.6, πœ‚ = 0.4, and
π‘ž = 0.7, then 𝑅1 = 1.33 > 1 and the CTL-present equilibrium
𝐸2 (1.1751, 1.3825, 6.6667, 1.6283). From (49), we obtain that
0.45
2.4
2
1.8
1.6 8.5
8.6
8.7
8.8
8.9
𝑑)
π‘₯(
Figure 2: The CTL-present infection equilibrium 𝐸2 of system (3) is
locally asymptotically stable when 𝑅1 = 1.45 > 1 and 𝜏 = 0.2 < 𝜏.
πœ” = √𝑒 = 0.4709. In addition, it is easy to show that
𝜏 = 0.948. Therefore, Theorem 10 is satisfied.
If 𝜏 = 0.2 < 𝜏, the CTL-present infection equilibrium 𝐸2
of system (3) is locally asymptotically stable (see Figure 2). If
𝜏 = 5 > 𝜏, then the CTL-present infection equilibrium 𝐸2 of
system (3) becomes unstable, and the Hopf bifurcation occurs
(see Figure 3).
6. Conclusion
In this paper, we have studied an HIV infection model
including infected cells in an eclipse stage and CTL immune
Journal of Applied Mathematics
11
Foundation for Engineering Research Institute of USTB
(YJ2012-001).
2
References
𝑧(𝑑)
1.5
1
0.5
0
1
10
9
𝑦(
0.5
𝑑)
8
7
0
𝑑)
π‘₯(
6
Figure 3: The bifurcating periodic solution from the equilibrium 𝐸2
of system (3) occurs when 𝜏 = 5.
response. The global stability of the uninfected equilibrium
𝐸0 for system (2) and (3) has been given by the LaSalle’s
invariance principle when the basic reproductive ratio 𝑅0 < 1;
it shows that the disease will be controlled. Compared with
the earlier modeling studies on the immune response of HIV
infection [14, 18, 20], our analysis reveals the existence of
a CTL-absent infection equilibrium 𝐸1 (π‘₯1 , 𝑀1 , 𝑦1 , 0) when
𝑅0 > 1. We also obtained the global asymptotic stability of
a CTL-absent infection equilibrium 𝐸1 for system (2) and (3)
when 𝑅1 < 1 and 1 < 𝑅0 < 1 + (πœ‚ + π‘ž)/𝛿. This indicates
that there is a persistent HIV infection with no humeral and
cellular immune responses. Furthermore, we can see that the
time delay has no effect on the stability of the uninfected
equilibrium 𝐸0 and CTL-absent infection equilibrium 𝐸1 for
the DDE model.
When 𝑅1 > 1, we show that the CTL-present infection
equilibrium 𝐸2 is locally asymptotically stable when the delay
𝜏 is small, and with the increase of the delay 𝜏 the stability of
𝐸2 may destabilize and lead to Hopf bifurcation. This suggests
that, with the HIV infection developing, the proviral load
and CTL frequency can either stabilize at a constant level
or show oscillations. Similar phenomenon was also observed
in [17–19]. The HIV dynamics model without immune delay
is globally stable [14, 15]. In this paper, we show that the
HIV infection model including infected cells in an eclipse
stage and CTL immune response without immune delay is
globally stable; and for the model with immune delay, Hopf
bifurcation appears under some conditions.
Acknowledgments
This work was supported by National Natural Science
Foundation of China (61174209, 11071013), the Basic Scientific Research Foundation of Central University (FRF-BR11-048B, FRF-BR-12-004), and the Basic Theory Research
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