Hindawi Publishing Corporation Journal of Applied Mathematics Volume 2013, Article ID 395628, 14 pages http://dx.doi.org/10.1155/2013/395628 Research Article Exact Traveling Wave Solutions for a Nonlinear Evolution Equation of Generalized Tzitzéica-Dodd-Bullough-Mikhailov Type Weiguo Rui College of Mathematics of Honghe University, Mengzi Yunnan 661100, China Correspondence should be addressed to Weiguo Rui; weiguorhhu@yahoo.com.cn Received 18 March 2013; Accepted 9 May 2013 Academic Editor: Shiping Lu Copyright © 2013 Weiguo Rui. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. By using the integral bifurcation method, a generalized TzitzeΜica-Dodd-Bullough-Mikhailov (TDBM) equation is studied. Under different parameters, we investigated different kinds of exact traveling wave solutions of this generalized TDBM equation. Many singular traveling wave solutions with blow-up form and broken form, such as periodic blow-up wave solutions, solitary wave solutions of blow-up form, broken solitary wave solutions, broken kink wave solutions, and some unboundary wave solutions, are obtained. In order to visually show dynamical behaviors of these exact solutions, we plot graphs of profiles for some exact solutions and discuss their dynamical properties. 1. Introduction In this paper, we consider the following nonlinear evolution equation: ππ’ π’π₯π‘ = πΌπ ππ’ + π½π , (1) where πΌ, π½ are two non-zero real numbers and π, π are two integers. We call (1) generalized TzitzeΜica-Dodd-BulloughMikhailov equation because it contains TzitzeΜica equation, Dodd-Bullough-Mikhailov equation, and TzitzeΜica-DoddBullough equation. When πΌ = 1, π½ = −1, π = 1, π = −2 or πΌ = −1, π½ = 1, π = −2, π = 1, especially (1) becomes classical TzitzeΜica equation [1–3] as follows: π’π₯π‘ = ππ’ − π−2π’ , (2) which was originally found in the field of geometry in 1907 by G. TzitzeΜica and appeared in the fields of mathematics and physics alike. Equation (2) usually called the “Dodd-Bullough equation,” which was initiated by Bullough and Dodd [4] and ZΜiber and SΜabat [5]. Indeed, (2) has another form π’π₯π₯ − π’π‘π‘ = ππ’ − π−2π’ ; see [6, 7] and the references cited therein. (3) When πΌ = −1, π½ = −1 and π = 1, π = −2, (1) becomes Dodd-Bullough-Mikhailov equation π’π₯π‘ + ππ’ + π−2π’ = 0. (4) When πΌ = 1, π½ = 1 and π = 1, π = −2, (1) becomes TzitzeΜicaDodd-Bullough equation π’π₯π‘ − ππ’ − π−2π’ = 0. (5) The Dodd-Bullough-Mikhailov equation and TzitzeΜicaDodd-Bullough equation appeared in many problems varying from fluid flow to quantum field theory. Moreover, when π = 1, π = −1, πΌ = 1/2, π½ = −1/2 or π = −1, π = 1, πΌ = −1/2, π½ = 1/2, (1) becomes the sinhGordon equation π’π₯π‘ = sinh π’, (6) which was shown in [7–10] and the references cited therein. When π = 1, π = −1, πΌ = π½ = 1/2 or π = −1, π = 1, πΌ = π½ = 1/2, (1) becomes the cosh-Gordon equation π’π₯π‘ = cosh π’, (7) 2 Journal of Applied Mathematics which was shown in [11, 12] and the references cited therein. When π = 1, π = 0, especially (1) becomes the Liouville equation π’π₯π‘ = πΌππ’ . 2. Two-Dimensional Planar Dynamical System of (1) and Its First Integral Applying the transformations π’(π₯, π‘) = ln |V(π₯, π‘)|, we change (1) into the following form: (9) Let V(π₯, π‘) = π(π₯ − ππ‘) = π(π), substituting π(π₯ − ππ‘) into (9), respectively, we obtain 2 π(πσΈ ) − πππσΈ σΈ = πΌππ+2 + π½ππ+2 , ππ = ππππ, (8) All the equations mentioned above play very significant roles in many scientific applications. And some of them were studied by many authors in recent years; see the following brief statements. In [13], by using the tanh method, Wazwaz considered some solitary wave and periodic wave solutions for the Dodd-Bullough-Mikhailov and Dodd-Bullough equations. In [14], Andreev studied the BaΜcklund transformation for Bullough-Dodd-Jiber-Shabat equation. In [15], Cherdantzev and Sharipov obtained finite-gap solutions of the Bullough-Dodd-Jiber-Shabat equation. In [16], Cherdantzev and Sharipov investigated solitons on the finite-gap background in the Bullough-Dodd-Jiber-Shabat model. In addition, the Darboux transformation, self-dual Einstein spaces and consistency and general solution of TzitzeΜica equation were studied in [17–19]. In this paper, by using integral bifurcation method [20], we will study (1). Indeed, the integral bifurcation method has successfully been combined with the computer method [21] and some transformations [22, 23] for investigating exact traveling wave solutions of some nonlinear PDEs. Therefore, using this method, we will obtain some new results which are different from those in the above references. The rest of this paper is organized as follows: in Section 2, we will derive two-dimensional planar system which is equivalent to (1) and give its first integral equation. In Sections 3 and 4, by using the integral bifurcation method, we will obtain some new traveling wave solutions of (1) and discuss their dynamic properties. VVπ₯π‘ − Vπ₯ Vπ‘ = πΌVπ+2 + π½Vπ+2 . and call (11) singular system. In order to obtain an equivalent system of (10), making a scalar transformation (12) equation (11) can be changed into a regular two-dimensional system as follows: ππ = πππ¦, ππ ππ¦ = ππ¦2 − πΌππ+2 − π½ππ+2 . ππ (13) Systems (11) and (13) are two integrable systems, and they have the same first integral as follows: π¦2 = βπ2 − 2πΌ π+2 2π½ π+2 − π π , ππ ππ (14) where β is integral constant. Systems (11) and (13) are planar dynamical systems defined by the 5-parameter (πΌ, π½, π, π, π). Usually their first integral (14) can be rewritten as π» (π, π¦) ≡ 2πΌ π 2π½ π π¦2 π + π + 2 = β. ππ ππ π (15) When π − π = 2π − 1, (π ∈ π), system (13) has two equilibrium points π(0, 0) and π΄((−πΌ/π½)1/(π−π) , 0) in the πaxes. When π − π = 2π, (π ∈ π) and πΌπ½ < 0, system (13) has three equilibrium point π(0, 0) and π΅1,2 (±(−πΌ/π½)1/(π−π) , 0) in the π-axes. When π−π = 2π, (π ∈ π) and πΌπ½ > 0, system (13) has only one equilibrium points π(0, 0). When π = π = π, (π ∈ π), system (13) has only one equilibrium point π(0, 0). Respectively, substituting every equilibrium point (the point π(0, 0) is exception) into (15), we have πΌ 1/(π−π) 2πΌ (π − π) πΌ π/(π−π) , 0) = , (− ) βπ΄ = π» ((− ) π½ πππ π½ πΌ 1/(π−π) βπ΅1 = π» (π΅1 ) = π» ((− ) , 0) π½ = 2πΌ (π − π) πΌ π/(π−π) , (− ) πππ π½ πΌ 1/(π−π) , 0) = (−1)π βπ΅1 . βπ΅2 = π» (π΅2 ) = π» (−(− ) π½ (10) (16) where “σΈ ” is the derivative with respect to π and π is wave speed. Clearly, (10) is equivalent to the following twodimensional systems: From the transformation π’(π₯, π‘) = ln |π(π₯ − ππ‘)|, we know that ln |π(π₯ − ππ‘)| approaches to −∞ if a solution π(π) approaches to 0 in (14). In other words, this solution determines an unboundary wave solution or blow-up wave solution of (1). It is easy to see that the second equation of system (11) is not continuous when π = 0. In other words, on such straight line π = 0 in the phase plane (π, π¦), the function πσΈ σΈ is not defined, and this implies that the smooth wave solutions of (1) sometimes become nonsmooth wave solutions. ππ = π¦, ππ ππ¦ ππ¦2 − πΌππ+2 − π½π2+π = . ππ ππ (11) However, when π = 0, (11) is not equivalent to (10) and the ππ¦/ππ cannot be defined, so we call the π = 0 singular line Journal of Applied Mathematics 3 3. Exact Solutions of (1) and Their Properties under the Conditions π = ± π, ±2π, π ∈ Z+ , and π = 2, π = −1 In this section, we investigate exact solutions of (1) under different kinds of parametric conditions and their properties. 3.1. Different Kinds of Solitary Wave Solutions and Unboundary Wave Solutions in the Special Cases π = 2π ∈ Z+ or π = π ∈ Z+ . (i) When β > 0, π½π < 0, π = 2π and π is even, then (14) can be reduced to π¦ = ±π√ β − π½ π 2 2πΌ π π − (π ) . ππ ππ (17) Taking π0 = 0 and π(0) = π1 as initial values, substituting (17) into the ππ/ππ = π¦ of (11), and then integrating it yield 1/π V (π₯, π‘) = ±( πΎ1 ) Ω1 cosh (π1 (π₯ − ππ‘)) + πΏ1 , (18) where π1 = (−πΌ/π½ + √(πΌ2 + π½ππβ)/π½2 )1/π , Ω1 = π1π (πΌ2 + π½ππβ), π1 = −π√β, πΎ1 = ππβ(ππβ − πΌπ1π ), πΏ1 = πΌ(ππβ − πΌπ1π ). By using program of Maple, it is easy to validate that (18) is the solution equation (9) when π is given. Substituting (18) into the transformation π’(π₯, π‘) = ln |V(π₯, π‘)|, we obtain a solitary wave solutions of (1) as follows: σ΅¨ σ΅¨σ΅¨ πΎ1 1 σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ π σ΅¨σ΅¨ Ω1 cosh (π1 (π₯ − ππ‘)) + πΏ1 σ΅¨σ΅¨σ΅¨ (iii) When π = 2π, β = 0, π½π > 0, πΌπ < 0 and π is even, (14) can be reduced to π¦ = ±π√ − V (π₯, π‘) = ±( Taking π0 = 0 and π(0) = (πβπ/2(πΌ + π½))1/π as initial values, substituting (20) into the ππ/ππ = π¦ of (11), and then integrating it yield 1/π V (π₯, π‘) = ±( πβπ sech2 π2 (π₯ − ππ‘) ) 2 (πΌ + π½) , (21) where π2 = (1/2)π√β. Substituting (21) into the transformation π’(π₯, π‘) = ln |V(π₯, π‘)|, we obtain a solution without boundary of (1) as follows: σ΅¨ σ΅¨ 1 σ΅¨σ΅¨ πβπ sech2 π2 (π₯ − ππ‘) σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ π σ΅¨σ΅¨ 2 (πΌ + π½) σ΅¨ (22) Equation (21) is smooth solitary wave solution of (9) but (22) is an exact solution without boundary of (1) because π’ → −∞ as V → 0. In order to visually show dynamical behaviors of solutions V and π’ of (21) and (22), we plot graphs of their profiles which are shown in Figures 1(a) and 1(b), respectively. 2 (−πΌπ) ) π½π + ππΌ2 (π₯ − ππ‘)2 1/π . (24) Substituting (24) into the transformation π’(π₯, π‘) = ln |V(π₯, π‘)|, we obtain an exact solutions of rational function type of (1) as follows: σ΅¨σ΅¨ σ΅¨ 2πΌπ 1 σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ (25) 2 2 π σ΅¨σ΅¨ π½π + ππΌ (π₯ − ππ‘) σ΅¨σ΅¨σ΅¨ (iv) When π = 2π, β > 0, πΌπ½ > 0, π½π > 0 (or πΌπ½ < 0, π½π > 0), and π is odd, (14) can be reduced to π¦ = ±√ π½ ππβ 2πΌ π 2 − π − (ππ ) . π√ ππ π½ π½ (26) Respectively, taking π0 = 0, π(0) = π1 , and π0 = 0, π(0) = π2 as initial values, substituting (26) into the ππ/ππ = π¦ of (11), and then integrating them yield πΎ1 ) Ω1 cosh (π1 (π₯ − ππ‘)) + πΏ1 1/π πΎ2 V (π₯, π‘) = ( ) Ω2 cosh (π2 (π₯ − ππ‘)) + πΏ2 1/π V (π₯, π‘) = ( (19) (20) (23) Taking π0 = 0 and π(0) = 0 as initial values, substituting (23) into the ππ/ππ = π¦ of (11), and then integrating it yield (ii) When π = π, β > 0, π/(πΌ + π½) > 0 and π is even, (14) can be reduced to 2 (πΌ + π½) π π¦ = ±π√ β − π . ππ π½ π 2 2πΌ π π − (π ) . ππ ππ π1 where (−πΌ/π½ − √(πΌ2 is + given above 1/π π½ππβ)/π½2 ) , Ω2 πΌπ2π ), and = π2 π2π (πΌ2 , (27) , (28) = + π½ππβ), π2 = π√β, πΎ2 = ππβ(ππβ − πΏ2 = πΌ(ππβ − πΌπ2π ). Respectively, substituting (27) and (28) into the transformation π’(π₯, π‘) = ln |V(π₯, π‘)|, we obtain two smooth unboundary wave solutions of (1) as follows: σ΅¨σ΅¨ σ΅¨ πΎ1 1 σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ , ln σ΅¨σ΅¨σ΅¨ π σ΅¨σ΅¨ Ω1 cosh (π1 (π₯ − ππ‘)) + πΏ1 σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨ πΎ2 1 σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ π σ΅¨σ΅¨ Ω2 cosh (π2 (π₯ − ππ‘)) + πΏ2 σ΅¨σ΅¨σ΅¨ π’ (π₯, π‘) = (29) (30) (v) When π = 2π, 0 < β < βπ΄ , πΌπ½ < 0, π½π < 0 (or πΌπ½ > 0, π½π < 0) and π is odd, (14) can be reduced to π¦ = ±√ − π½ ππβ 2πΌ π 2 + π + (ππ ) . π√− ππ π½ π½ (31) Similarly, by using (31), we obtain two smooth solitary wave solutions of (1) which are the same as the solutions (29) and (30). 4 Journal of Applied Mathematics 2 0.6 1.5 0.4 1 u 0.2 0.5 −2 −1 0 1 2 3 −0.2 0.1 −0.1 0.2 0.3 0.4 0.5 0.6 x x (a) Smooth solitary wave (b) Unboundary wave Figure 1: The phase portraits of solutions (21) and (22) for π = 4, πΌ = 3, π½ = −1, π = 2, β = 9, π‘ = 0.1. (vi) When π = π, β > 0 and π is odd, (14) can be reduced to (20), so the obtained solution is as the same as the solution (22). (vii) When π = 2π, β = 0, π½π > 0 and π is odd, (14) can be reduced to π¦ = ±√ π½ 2πΌ 2 π√− ππ − (ππ ) . ππ π½ V (π₯, π‘) = ( ) . (33) Substituting (33) into the transformation π’(π₯, π‘) = ln |V(π₯, π‘)|, we obtain a smooth unboundary wave solution of rational function type of (1) as follows: σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ 2πΌ 1 σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨ (34) σ΅¨ 2 2 π σ΅¨σ΅¨ π½ [1 + (ππΌ /π½π) (π₯ − ππ‘) ] σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ 3.2. Periodic Blow-Up Wave Solutions, Broken Kink Wave, and Antikink Wave Solutions in the Special Case π = 2π ∈ Z+ . (1) When π = 2π, πΌπ½ < 0, π½π > 0, βπ΅1 < β < 0 (or βπ΅2 < β < 0) and π is even, (14) can be reduced to π¦ = ±√ π½ ππβ 2πΌ π 2 π√ − π − (ππ ) . ππ π½ π½ Taking π0 = 0, π(0) = (−πΌ/π½ + √πΌ2 /π½2 + πβπ/π½) π0 = 0, π(0) = (−πΌ/π½ − √πΌ2 /π½2 + πβπ/π½) ππβ ) πΌ − π½Ω3 sin (arcsin π·1 − π3 (π₯ − ππ‘)) 1/π ππβ V (π₯, π‘) = −( ) πΌ + π½Ω3 sin (arcsin π·2 + π3 (π₯ − ππ‘)) = √(πΌ2 + ππβπ½)/π½2 , π3 where Ω3 1/π π½ [1 + (ππΌ2 /π½π) (π₯ − ππ‘)2 ] 1/π V (π₯, π‘) = ( (32) Taking π0 = 0 and π(0) = (−2πΌ/π½)1/π as initial values, substituting (32) into the ππ/ππ = π¦ of (11), and then integrating it yield −2πΌ values, substituting (35) into the ππ/ππ = π¦ of (11), and then integrating them yield 2 as the initial 1/π , (37) = π√−β, π·1 = 2 π’ (π₯, π‘) = σ΅¨σ΅¨ σ΅¨ ππβ 1 σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ , ln σ΅¨σ΅¨σ΅¨ π σ΅¨σ΅¨ πΌ − π½Ω3 sin (arcsin π·1 − π3 (π₯ − ππ‘)) σ΅¨σ΅¨σ΅¨ (38) π’ (π₯, π‘) = σ΅¨σ΅¨ σ΅¨ 1 σ΅¨σ΅¨σ΅¨ ππβ σ΅¨σ΅¨ σ΅¨σ΅¨ . ln σ΅¨σ΅¨σ΅¨ π σ΅¨σ΅¨ πΌ + π½Ω3 sin (arcsin π·2 + π3 (π₯ − ππ‘)) σ΅¨σ΅¨σ΅¨ (39) (2) When π = 2π, πΌπ½ < 0, π½π > 0, βπ΅2 < β < 0 and π is odd, (14) can be reduced to π¦ = ±√ and (36) (πΌ + πΌπ½Ω3 + π½ππβ)/π½Ω3 (πΌ + π½Ω3 ), π·2 = (πΌ − πΌπ½Ω3 + π½ππβ)/π½Ω3 (−πΌ + π½Ω3 ). Respectively, substituting (36) and (37) into the transformation π’(π₯, π‘) = ln |V(π₯, π‘)|, we obtain two periodic blow-up wave solutions of (1) as follows: (35) 1/π , π½ ππβ 2πΌ π 2 π√ − π − (ππ ) , ππ π½ π½ (40) which is the same as (35), so the obtained solution is the same as solution (39). Similarly, when π = 2π, πΌπ½ < 0, π½π > 0, Journal of Applied Mathematics 5 βπ΅1 < β < 0 and π is odd, the obtained solution is also the same as solution (38). (3) when π = 2π, πΌπ½ < 0, π½π < 0, β = βπ΅1 = βπ΅2 = 2 −πΌ /π½ππ and π is even, (14) can be reduced to π¦ = ±√− 1 π (π½ππ + πΌ) . πππ½ (41) Substituting (41) into the ππ/ππ = π¦ of (11) and then integrating it and setting the integral constants as zero yield V (π₯, π‘) = (− 1/π Ω πΌ (1 ± tanh 4 (π₯ − ππ‘))) , 2π½ 2 (42) where Ω4 = πΌ√−π/ππ½. Substituting (42) into the transformation π’(π₯, π‘) = ln |V(π₯, π‘)|, we obtain an unboundary wave solution of (1) as follows: π’ (π₯, π‘) = σ΅¨σ΅¨ Ω 1 σ΅¨σ΅¨σ΅¨σ΅¨ πΌ σ΅¨ ln σ΅¨σ΅¨ [1 ± tanh 4 (π₯ − ππ‘)]σ΅¨σ΅¨σ΅¨ . σ΅¨σ΅¨ π σ΅¨σ΅¨ 2π½ 2 (43) Equation (42) is smooth kink wave solution of (9), but (43) is a broken kink wave solution without boundary of (1) because π’ → −∞ as V → 0. In order to visually show dynamical behaviors of solutions V and π’ of (42) and (43), we plot graphs of their profiles which are shown in Figures 2(a) and 2(b), respectively. (4) When π = 2π, πΌπ½ > 0, π½π < 0, β = βπ΄ or πΌπ½ < 0, π½π < 0, β = βπ΄ and π is odd, (14) can be reduced to (41). So the obtained solution is also the same as the solution (43). 3.3. Periodic Blow-Up Wave Solutions and Solitary Wave Solutions of Blow-Up Form in the Special Case π = 2, π = −1. When π = −1, (14) can be reduced to π¦ = ±√ βπ2 − 2πΌ π+2 2π½ + π π. ππ π (44) (a) Under the conditions πΌπ½ > 0, πΌπ > 0, β ∈ (−∞, +∞) and π = 2, (44) becomes πΌ π¦ = ±√ √(π1 − π) (π − 0) (π − πΎ1 ) (π − πΏ1 ), π π ∈ (0, π1 ] , (45) where π1 , πΎ1 , πΏ1 are three roots of equation 2π½/πΌ + (πβ/πΌ)π − π3 and π1 > 0 > πΎ1 > πΏ1 . These three roots π1 , πΎ1 , πΏ1 can be obtained by Cardano formula as long as the parameters πΌ, π½, π, β are fixed (or given) concretely. For example, taking πΌ = 4.0, π½ = 2.0, π = 4.0, β = 9.0, the π1 β 3.054084215, πΎ1 β −0.1112641576, πΏ1 β −2.942820058. Taking (0, π1 ) as the initial values of the variables (π, π), substituting (45) into the ππ/ππ = π¦ of (11), and then integrating it yield π (−πΏ1 ) cn2 (Ω1 (π) , π1 ) , V (π₯, π‘) = π (π) = 1 (−πΏ1 ) + π1 sn2 (Ω1 π, π1 ) = (1/2)√−πΌπΏ1 (π1 − πΏ1 )/π, π1 = where Ω1 √π1 (πΎ1 − πΏ1 )/ − πΏ1 (π1 − πΎ1 ), π1 = (1/Ω1 )sn−1 (1, π1 ). By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (46), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨σ΅¨ π (−πΏ ) cn2 (Ω (π₯−ππ‘) , π ) σ΅¨σ΅¨ σ΅¨ 1 1 1 σ΅¨σ΅¨ σ΅¨σ΅¨ , π₯ − ππ‘=π ΜΈ 1. π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ 1 2 σ΅¨σ΅¨ (−πΏ1 )+π1 sn (Ω1 (π₯−ππ‘) , π1 ) σ΅¨σ΅¨σ΅¨ (47) (b) Under the conditions πΌπ½ > 0, πΌπ > 0, β ∈ (βπ΄ , +∞) and π = 2, (44) becomes πΌ π¦ = ±√ √(π1 − π) (0 − π) (πΎ1 − π) (π − πΏ1 ), π π ∈ [πΏ1 , πΎ1 ] . (48) Similarly, taking (0, πΏ1 ) as the initial values of the variables (π, π), substituting (48) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = πΎ1 πΏ1 . πΏ1 + (πΎ1 − πΏ1 ) sn2 (Ω1 π, π1 ) (49) By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (49), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨σ΅¨ σ΅¨σ΅¨ πΎ1 πΏ1 σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ 2 σ΅¨σ΅¨ πΏ1 + (πΎ1 − πΏ1 ) sn (Ω1 (π₯ − ππ‘) , π1 ) σ΅¨σ΅¨σ΅¨ (50) (c) Under the conditions πΌπ½ < 0, πΌπ > 0, β ∈ (−∞, +∞) and π = 2, (44) becomes πΌ π¦ = ±√ √(π2 − π) (π2 − π) (0 − π) (π − πΏ2 ), π π ∈ [πΏ2 , 0) , (51) where π2 , π2 , 0, πΏ2 are roots of equation π(2π½/πΌ + (πβ/πΌ)π − π3 ) = 0 and π2 > π2 > 0 > πΏ2 . As in the above cases, these three roots can be obtained by Cardano formula as long as the parameters πΌ, π½, π, β are given concretely, so the similar cases will be not commentated anymore in the following discussions. Similarly, taking (0, πΏ2 ) as the initial values of the variables (π, π), substituting (51) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = π2 πΏ2 sn2 (Ω2 (π₯ − ππ‘) , π2 ) , (π2 − πΏ2 ) + πΏ2 sn2 (Ω2 π, π2 ) π =ΜΈ π2 , (52) = (1/2)√πΌπ2 (π2 − πΏ2 )/π, π2 = where Ω2 √−πΏ2 (π2 − π2 )/π2 (π2 − πΏ2 ), π2 = (1/Ω2 )sn−1 (0, π2 ). By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (52), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨σ΅¨σ΅¨ π πΏ sn2 (Ω2 (π₯ − ππ‘) , π2 ) σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ , π₯ − ππ‘ =ΜΈ π . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ 2 2 σ΅¨ 2 σ΅¨σ΅¨ (π2 − πΏ2 ) + πΏ2 sn2 (Ω2 π, π2 ) σ΅¨σ΅¨σ΅¨ (53) (d) Under the conditions πΌπ½ < 0, πΌπ > 0, β ∈ (βπ΄ , +∞) and π = 2, (44) becomes π =ΜΈ π1 , (46) πΌ π¦ = ±√ √(π2 − π) (π − π2 ) (π − 0) (π − πΏ2 ). π (54) 6 Journal of Applied Mathematics −30 x −10 −20 x 0 10 −4 −2 0 2 4 6 8 −0.1 −0.2 −0.2 −0.3 u −0.4 −0.4 −0.6 −0.5 −0.8 −0.6 (a) Smooth kink wave (b) Unboundary wave Figure 2: The phase portraits of solutions (42) and (43) for π = 4, πΌ = 0.3, π½ = −0.3, π = 2, π‘ = 0.1. Taking the (0, π2 ) as the initial values of the variables (π, π), substituting (54) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = 2 π2 (π2 − πΏ2 ) dn (Ω2 (π₯ − ππ‘) , π2 ) . (55) (π2 − πΏ2 ) + (π2 − π2 ) sn2 (Ω2 π, π2 ) By using the transformations π’(π₯, π‘) = ln |V(π₯, π‘)| and (55), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨σ΅¨ σ΅¨σ΅¨ π2 (π2 − πΏ2 ) dn2 (Ω2 (π₯ − ππ‘) , π2 ) σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ 2 σ΅¨σ΅¨ (π2 − πΏ2 ) + (π2 − π2 ) sn (Ω2 (π₯ − ππ‘) , π2 ) σ΅¨σ΅¨σ΅¨ (56) (e) Under the conditions πΌπ½ < 0, πΌπ < 0, β ∈ (−∞, βπ΄ ) and π = 2, (44) becomes πΌ π¦ = ±√− √(π3 − π) (π3 − π) (π − 0) (π − πΏ3 ), π π ∈ (0, π3 ] , (57) where π3 , π3 , 0, πΏ3 are roots of equation π(−2π½/πΌ − (πβ/πΌ)π + π3 ) = 0 and π3 > π3 > 0 > πΏ3 . Taking the (0, π3 ) as the initial values of the variables (π, π), substituting (57) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = 2 π3 π3 cn (Ω3 π, π3 ) , πΏ3 − π3 sn2 (Ω3 π, π3 ) π =ΜΈ π3 , (58) = (1/2)√−πΌπ3 (π3 − πΏ3 )/π, π3 = where Ω3 √π3 (π3 − πΏ3 )/π3 (π3 − πΏ3 ), π3 = (1/Ω3 )sn−1 (1, π3 ). By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (58), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨σ΅¨ π π cn2 (Ω (π₯ − ππ‘) , π ) σ΅¨σ΅¨ σ΅¨ 3 3 σ΅¨σ΅¨ σ΅¨σ΅¨ , π₯ − ππ‘ =ΜΈ π3 . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ 3 3 2 σ΅¨σ΅¨ πΏ3 − π3 sn (Ω3 (π₯ − ππ‘) , π3 ) σ΅¨σ΅¨σ΅¨ (59) (f) Under the conditions πΌπ½ < 0, πΌπ < 0, β ∈ (−∞, βπ΄ ) and π = 2, (44) becomes πΌ π¦ = ±√− √(π4 − π) (0 − π) (π − πΎ4 ) (π − πΏ4 ), π π ∈ [πΎ4 , 0) , (60) where π4 , 0, πΎ4 , πΏ4 are roots of equation π(−2π½/πΌ − (πβ/πΌ)π + π3 ) = 0 and π4 > 0 > πΎ4 > πΏ4 . Taking the (0, πΎ4 ) as the initial values of the variables (π, π), substituting (60) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = πΏ4 πΎ4 cn2 (Ω4 π, π4 ) , πΏ4 − πΎ4 cn2 (Ω4 π, π4 ) π =ΜΈ π4 , (61) = (1/2)√πΌπΏ4 (π4 − πΎ4 )/π, π4 = where Ω4 √πΎ4 (π4 − πΏ4 )/π4 (π4 − πΎ4 ), π4 = (1/Ω4 )sn−1 (1, π4 ). By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (61), we obtain a periodic below-up wave solutions of (1) as follows: σ΅¨σ΅¨ πΏ πΎ cn2 (Ω (π₯ − ππ‘) , π ) σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨ 4 4 σ΅¨σ΅¨ , π₯ − ππ‘ =ΜΈ π4 . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ 4 4 2 σ΅¨σ΅¨ πΏ4 − πΎ4 cn (Ω4 (π₯ − ππ‘) , π4 ) σ΅¨σ΅¨σ΅¨ (62) (g) Under the conditions π = 2, πΌπ < 0, β = βπ΄ = −πΌ2 /2ππ½, (44) becomes πΌσ΅¨ σ΅¨ π¦ = ±√− σ΅¨σ΅¨σ΅¨π1 − πσ΅¨σ΅¨σ΅¨ √π (π + 2π1 ), π π =ΜΈ 0, (63) where π1 = (−π½/πΌ)1/3 . Taking (0, (1/2)π1 ) as the initial values of the variables (π, π), substituting (63) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = π1 [1 − 3 ], cosh (Ω5 π) + 2 π =ΜΈ π5 , (64) Journal of Applied Mathematics 7 where Ω5 = π1 √−3πΌ/π, π5 = (1/Ω5 )cosh−1 (1). Clearly, we have π(π5 ) = 0, π(±∞) = π1 . By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (64), we obtain a solitary wave solution of blow-up form of (1) as follows: σ΅¨σ΅¨ σ΅¨σ΅¨ 3 σ΅¨ σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨π1 [1 − ]σ΅¨σ΅¨σ΅¨σ΅¨ , π₯ − ππ‘ =ΜΈ π5 . cosh (Ω5 (π₯ − ππ‘)) + 2 σ΅¨σ΅¨ σ΅¨σ΅¨ (65) Equation (64) is smooth solitary wave solution of (9), but (65) is a solitary wave solution of blow-up form for (1) because π’ → −∞ as V → 0. In order to visually show dynamical behaviors of solutions V and π’ of (64) and (65), we plot graphs of their profiles which are shown in Figures 3(a) and 3(b), respectively. 3.4. Different Kinds of Periodic Wave, Broken Solitary Wave Solutions in the Special Case π = 1, π = −1. (1) Under the conditions β ∈ (βπ΄ , +∞), πΌπ½ > 0, π½π > 0 (or πΌπ½ < 0, π½π > 0), πΌπ > 0 and π = 1, (44) becomes 2πΌ π¦ = ±√ √(ππ − π) (π − ππ ) (π − 0), π where Ω7 = √−πΌππ/2π, π7 = √ππ/ππ , π7 = (1/Ω7 )sn−1 (0, π7 ). By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (70), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨ σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ππsn2 (Ω7 (π₯ − ππ‘) , π7 )σ΅¨σ΅¨σ΅¨σ΅¨ , π₯ − ππ‘ =ΜΈ π7 . (71) (3) Under the conditions β ∈ (βπ΄ , +∞), πΌπ½ < 0, π½π > 0 (or πΌπ½ > 0, π½π > 0) and π = 1, (44) becomes π¦ = ±√ − 2πΌ √(0 − π) (ππ − π) (π − ππ ), π where ππ,π = (βπ ± √β2 π2 + 16πΌπ½)/4πΌ and 0 are three roots of equation βπ2 − (2πΌ/π)π3 + (2π½/π)π = 0 and ππ > ππ > 0. Taking (0, ππ ) as the initial values of the variables (π, π), substituting (66) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = ππ − (ππ − ππ ) sn2 (Ω6 π, π6 ) , V (π₯, π‘) = π (π) = Equation (67) is smooth periodic wave solution of (9), but (68) is a double periodic wave solution of blow-up form of (1) because π’ → −∞ as V → 0. In order to visually show dynamical behaviors of solutions V and π’ of (67) and (68), we plot graphs of their profiles which are shown in Figures 4(a) and 4(b), respectively. (2) Under the condition β ∈ (−∞, βπ΄ ), πΌπ½ < 0, π½π > 0 (or πΌπ½ < 0, π½π < 0),πΌπ > 0 and π = 1, (44) becomes π¦ = ±√ 2πΌ √(0 − π) (π − ππ) (π − ππ ), π π ∈ [ππ, 0) , (69) where ππ, ππ , 0 are roots of equation βπ2 − (2πΌ/π)π3 + (2π½/π)π = 0 and ππ < ππ < 0. Taking (0, ππ) as the initial values of the variables (π, π), substituting (69) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = ππsn2 (Ω7 π, π7 ) , π =ΜΈ π7 , (70) dn2 ππ , (Ω8 π, π8 ) (73) where Ω8 = √πΌππ /2π, π8 = √(ππ − ππ )/ − ππ . By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (73), we obtain a periodic blow-up wave solutions of (1) as follows: σ΅¨σ΅¨ σ΅¨σ΅¨ ππ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ 2 σ΅¨σ΅¨ dn (Ω8 (π₯ − ππ‘) , π8 ) σ΅¨σ΅¨σ΅¨ (74) (4) Under the conditions β ∈ (−∞, βπ΄ ), πΌπ½ < 0, π½π > 0 (or πΌπ½ < 0, π½π < 0) and π = 1, (44) becomes (67) where Ω6 = √πΌππ/2π, π6 = √(ππ − ππ )/ππ. By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (67), we obtain a double periodic wave solution of (1) as follows: σ΅¨ σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ππ − (ππ − ππ ) sn2 (Ω6 (π₯ − ππ‘) , π6 )σ΅¨σ΅¨σ΅¨σ΅¨ . (68) (72) where ππ, ππ , 0 are roots of equation βπ2 − (2πΌ/π)π3 + (2π½/π)π = 0 and 0 > ππ > ππ . Taking (0, ππ) as the initial values of the variables (π, π), substituting (72) into the ππ/ππ = π¦ of (11), and then integrating it yield π ∈ [ππ , ππ] , (66) π ∈ [ππ , ππ] , π¦ = ±√ − 2πΌ √(ππ − π) (ππ − π) (π − 0), π π ∈ (0, ππ ] , (75) where ππ, ππ , 0 are roots of equation βπ2 − (2πΌ/π)π3 + (2π½/π)π = 0 and ππ > ππ > 0. Taking (0, ππ ) as the initial values of the variables (π, π), substituting (75) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = ππ cn2 (Ω9 π, π9 ) , dn2 (Ω9 π, π9 ) π =ΜΈ π9 , (76) where Ω9 = √−πΌππ/2π, π9 = √ππ /ππ, π9 = (1/Ω9 )sn−1 (0, π9 ). By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (76), we obtain periodic blow-up wave solutions of (1) as follows: σ΅¨σ΅¨ π cn2 (Ω (π₯ − ππ‘) , π ) σ΅¨σ΅¨ σ΅¨ 9 9 σ΅¨σ΅¨ σ΅¨σ΅¨ , π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ π 2 σ΅¨σ΅¨ dn (Ω9 (π₯ − ππ‘) , π9 ) σ΅¨σ΅¨σ΅¨ π₯ − ππ‘ =ΜΈ π9 . (77) (5) Under the conditions β = βπ΄ = −4πΌπ1 /π, πΌπ½ < 0, π½π > 0 and π = 1, (44) becomes π¦ = ±√ 2πΌ σ΅¨σ΅¨ σ΅¨ σ΅¨π + πσ΅¨σ΅¨σ΅¨ √−π, π σ΅¨ 1 π ∈ [−π1 , 0) , (78) 8 Journal of Applied Mathematics x 1 −15 −10 −5 5 0 0.5 10 −0.5 −1 −20 −15 −10 5 −5 10 u 15 x −1.5 −0.5 −2 −2.5 −1 (a) Smooth solitary wave (b) Solitary wave of blow-up form Figure 3: The phase portraits of solutions (64) and (65) for π = 2, πΌ = 0.3, π½ = −0.3, π = −2, π‘ = 0.1. 1 x −8 −6 −4 −2 0 2 4 0.5 −6 −4 x 2 −2 4 6 8 −0.5 −1 u −0.5 −1 −1.5 −1.5 −2 −2 (a) Smooth periodic wave (b) Double periodic wave of blow-up type Figure 4: The phase portraits of solutions (67) and (68) for β = 8, πΌ = 2.5, π½ = −2.5, π = 2, π‘ = 0.1. where π1 = (−π½/πΌ)1/2 . Taking (0, −π1 ) as the initial values of the variables (π, π), substituting (78) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = −π1 tanh2 (0.5Ω10 π) , π =ΜΈ 0, (79) where Ω10 = √2πΌπ1 /π. By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (79), we obtain a solitary wave solution of blow-up form of (1) as follows: σ΅¨ σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨π1 tanh2 (0.5Ω10 (π₯ − ππ‘))σ΅¨σ΅¨σ΅¨σ΅¨ , π₯ − ππ‘ =ΜΈ 0. (80) (6) Under the conditions β = βπ΄ = 4πΌπ1 /π, πΌπ½ < 0, π½π > 0 and π = 1, (44) becomes π¦ = ±√ − 2πΌ σ΅¨σ΅¨ σ΅¨ σ΅¨π − π1 σ΅¨σ΅¨σ΅¨ √π, π σ΅¨ π ∈ (0, π1 ] , (81) where π1 = (−π½/πΌ)1/2 . Taking (0, π1 ) as the initial values of the variables (π, π), substituting (81) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = π1 tanh2 (0.5Ω11 π) , π =ΜΈ 0, (82) Journal of Applied Mathematics 9 where Ω11 = √−2πΌπ1 /π. By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (82), we obtain a broken solitary wave solution of (1) as follows: σ΅¨ σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨π1 tanh2 (0.5Ω11 (π₯ − ππ‘))σ΅¨σ΅¨σ΅¨σ΅¨ , π₯ − ππ‘ =ΜΈ 0. (83) (7) Under the conditions β ∈ (−∞, 0], πΌπ½ > 0, π½π < 0 and π = 1, (44) becomes π¦ = ±√ − 2πΌ √(ππ − π) (0 − π) (π − ππ ), π π ∈ [ππ , 0) , (84) where ππ, ππ , 0 are roots of equation π2 β − (2πΌ/π)π3 + (2π½/π)π = 0 and ππ > 0 > ππ . Taking (0, ππ) as the initial values of the variables (π, π), substituting (84) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = 2 sn2 (Ω12 π, π12 ) −πππ12 , dn2 (Ω12 π, π12 ) π =ΜΈ π12 , (85) where Ω12 = √−πΌ(ππ − ππ )/2π, π12 = √−ππ /(ππ − ππ ), π12 = (1/Ω12 )sn−1 (0, π12 ). By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (85), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨σ΅¨ −π π2 sn2 (Ω (π₯ − ππ‘) , π ) σ΅¨σ΅¨ σ΅¨ 12 12 σ΅¨σ΅¨ σ΅¨σ΅¨ , π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ π 12 σ΅¨σ΅¨ dn2 (Ω12 (π₯ − ππ‘) , π12 ) σ΅¨σ΅¨ σ΅¨ π₯ − ππ‘ =ΜΈ π12 . (86) (8) Under the conditions β ∈ (−∞, 0], πΌπ½ > 0, π½π > 0 and π = 1, (44) becomes π¦ = ±√ 2πΌ √(ππ − π) (π − 0) (π − ππ ), π π ∈ (0, ππ] , (87) 2 3 where ππ, ππ , 0 are roots of equation βπ − (2πΌ/π)π + (2π½/π)π = 0 and ππ > 0 > ππ . Taking (0, ππ) as the initial values of the variables (π, π), substituting (87) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = ππcn2 (Ω13 π, π13 ) , π =ΜΈ π13 , (88) where Ω13 = √πΌ(ππ − ππ )/2π, π13 = √ππ/(ππ − ππ ), π13 = (1/Ω13 )sn−1 (0, π13 ). By using the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (88), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨ σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ππcn2 (Ω13 (π₯ − ππ‘) , π13 )σ΅¨σ΅¨σ΅¨σ΅¨ , π₯ − ππ‘ =ΜΈ π13 . (89) 3.5. Periodic Blow-Up Wave, Broken Solitary Wave, Broken Kink, and Antikink Wave Solutions in the Special Cases π = 2 or π = 1 and π = −2. When π = 2 is even and π = −2, (14) can be reduced to π¦ = ±√ βπ2 − 2πΌ π+2 π½ + . π ππ π (90) Because the singular straight line π = 0, this implies that (1) has broken kink and antikink wave solutions: see the following discussions. (i) Under the conditions π = 2, π = −2, β = √−4πΌπ½/π2 , πΌπ½ < 0, πΌπ < 0, (90) becomes π¦ = ±√− πΌ σ΅¨σ΅¨ 2 σ΅¨ σ΅¨σ΅¨π − π12 σ΅¨σ΅¨σ΅¨ , σ΅¨ πσ΅¨ (π =ΜΈ 0) , (91) where π1 = √−π½/πΌ. Taking (0, π1 ) as the initial values of the variables (π, π), substituting (91) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = ±π1 tanh [Ω14 π] , (92) where Ω14 = π1 √−πΌ/π. By using the transformations π’(π₯, π‘) = ln |V(π₯, π‘)| and (92), we obtain a broken kink wave solutions of (1) as follows: σ΅¨ σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨π1 tanh [Ω14 (π₯ − ππ‘)]σ΅¨σ΅¨σ΅¨ , (93) where (π₯ − ππ‘) ∈ (−∞, 0) and (π₯ − ππ‘) ∈ (0, +∞). (ii) Under the conditions β ∈ (βπ΅1 , +∞), πΌπ½ > 0, πΌπ > 0 and π = 2, π = −2, (90) becomes πΌ π¦ = ±√ √(π2 − π2 ) (π2 − π2 ), π (94) where π2 = (1/2πΌ)(πβ + √π2 β2 + 4πΌπ½), π2 = (1/2πΌ)(πβ − √π2 β2 + 4πΌπ½). Taking (0, π) as the initial values of the variables (π, π), substituting (94) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = ±√π2 − (π2 − π2 ) sn2 (Ω15 π, π15 ), (95) where π2 = (1/2πΌ)(πβ + √π2 β2 + 4πΌπ½), π2 = (1/2πΌ)(πβ − √π2 β2 + 4πΌπ½), Ω15 = π√πΌ/π, π15 = √(π2 − π2 )/π2 . By using the transformations π’(π₯, π‘) = ln |V(π₯, π‘)| and (95), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨ σ΅¨ π’ (π₯, π‘) = 0.5 ln σ΅¨σ΅¨σ΅¨σ΅¨π2 − (π2 − π2 ) sn2 (Ω15 π, π15 )σ΅¨σ΅¨σ΅¨σ΅¨ . (96) (iii) Under the conditions π = 1, π = −2, β = βπ΅1 = 3πΌπ2 /π, πΌπ½ > 0, πΌπ > 0, (90) becomes π¦ = ±√ πΌ σ΅¨σ΅¨ σ΅¨ σ΅¨−π + πσ΅¨σ΅¨σ΅¨ √−π2 − 2π, πσ΅¨ 2 (π =ΜΈ 0) , (97) where π2 = (−π½/πΌ)1/3 . Taking (0, −0.5π2 ) as the initial values of the variables (π, π), substituting (97) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = −π2 [ 3 − 1] , cosh (Ω16 π) + 1 π =ΜΈ π16 , (98) where Ω16 = √−3πΌπ2 /π, π16 = (1/Ω16 )cosh−1 (2). By using the transformations π’(π₯, π‘) = ln |V(π₯, π‘)| and (98), when 10 Journal of Applied Mathematics (π₯ − ππ‘) ∈ (−∞, π16 ) β (π16 , +∞), we obtain a broken solitary wave solution of (1) as follows: σ΅¨σ΅¨ σ΅¨σ΅¨ 3π2 σ΅¨ σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨ − π2 σ΅¨σ΅¨σ΅¨σ΅¨ . (99) σ΅¨σ΅¨ σ΅¨σ΅¨ cosh (Ω16 (π₯ − ππ‘)) + 1 (iv) Under the conditions β = βπ΅1 = 3πΌπ2 /π, πΌπ½ < 0, πΌπ < 0 and π = 1, π = −2, (90) becomes πΌσ΅¨ σ΅¨ π¦ = ±√− σ΅¨σ΅¨σ΅¨π2 − πσ΅¨σ΅¨σ΅¨ √π2 + 2π, π (π =ΜΈ 0) , π =ΜΈ π17 , (101) where Ω17 = √3πΌπ1 /π, π17 = (1/Ω17 )cosh−1 (2). By using the transformations π’(π₯, π‘) = ln |V(π₯, π‘)| and (101), when (π₯−ππ‘) ∈ (−∞, π17 ) β (π17 , +∞), we obtain a broken solitary wave solution of (1) as follows: σ΅¨σ΅¨ σ΅¨σ΅¨ 3π2 σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨π2 − (102) cosh (Ω17 (π₯ − ππ‘)) + 1 σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ (v) Under the conditions β ∈ (βπ΅1 , +∞), πΌπ½ < 0, π½π < 0 and π = 1, π = −2, (90) becomes 2πΌ π¦ = ±√ √(π5 − π) (π − π5 ) (π − πΎ5 ), π π ∈ [π5 , π5 ] , V (π₯, π‘) = π (π) = π5 − (π5 − π5 ) sn2 (Ω18 π, π18 ) , (104) where Ω18 = √πΌ(π5 − πΎ5 )/2π, π18 = √(π5 − π5 )/(π5 − πΎ5 ). By using the transformations π’(π₯, π‘) = ln |V(π₯, π‘)| and (104), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨ σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨π5 − (π5 − π5 ) sn2 (Ω18 (π₯ − ππ‘) , π18 )σ΅¨σ΅¨σ΅¨σ΅¨ . (105) (vi) Under the conditions β ∈ (βπ΅1 , +∞), πΌπ½ > 0, π½π < 0 and π = 1, π = −2, (90) becomes 2πΌ √(π5 − π) (π5 − π) (π − πΎ5 ), π √(2π½/ππ) ππ + β(ππ )2 − (2πΌ/ππ) (ππ )3 ππ−1 =± √2πΌ/ππ√(πππ − ππ ) (ππ (109) − πππ ) (ππ ππ−1 − 0) , where ππ,π = [(1/4πΌ)(ππβ ± √π2 π2 β2 + 16πΌπ½)]1/π . Taking (0, ππ ) as the initial values of the variables (π, π), substituting (109) into the ππ/ππ = π¦ of (11), and then integrating it yields V (π₯, π‘) = π (π) = ±[ππ − (ππ − ππ ) sn2 (Ω19 π, π19 )] 1/π , (110) where Ω19 = π√πΌππ /2ππ, π19 = √(ππ − ππ )/ππ . By using the transformations π’(π₯, π‘) = ln |V(π₯, π‘)| and (110), we obtain a periodic wave solution of (1) as follows: π’ (π₯, π‘) = 1 σ΅¨σ΅¨ σ΅¨ ln σ΅¨σ΅¨σ΅¨[ππ − (ππ − ππ ) sn2 (Ω19 (π₯ − ππ‘) , π19 )]σ΅¨σ΅¨σ΅¨σ΅¨ . π (111) (103) where π5 , π5 , πΎ5 are roots of equation π½/2πΌ + (πβ/2πΌ)π2 − π3 and πΎ5 < 0 < π5 < π5 . Taking (0, π5 ) as the initial values of the variables (π, π), substituting (103) into the ππ/ππ = π¦ of (11), and then integrating it yield π¦ = ±√ π¦=± (100) where π2 = (−π½/πΌ)1/3 . Taking (0, −0.5π2 ) as the initial values of the variables (π, π), substituting (100) into the ππ/ππ = π¦ of (11), and then integrating it yield 3 V (π₯, π‘) = π (π) = π2 [1 − ], cosh (Ω17 π) + 1 3.6. Periodic Wave, Broken Solitary Wave, Broken Kink, and Antikink Wave Solutions in the Special Cases π = −π or π = −2π and π ∈ Z+ . (a) When π = −π, π ∈ Z+ and πΌπ½ < 0, π½π < 0, πΌπ > 0, β > 4√−πΌπ½/ππ, (14) can be reduced to π ∈ [πΎ5 , π5 ] , (106) where πΎ5 < π5 < 0 < π5 . Taking (0, π5 ) as the initial values of the variables (π, π), substituting (106) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = πΎ5 + (π5 − πΎ5 ) sn2 (Ω19 π, π19 ) , (107) where πΎ5 < π5 < 0 < π5 , Ω19 = √−πΌ(π5 − πΎ5 )/2π, π19 = √(π5 − π5 )/(π5 − πΎ5 ). By using the transformations π’(π₯, π‘) = ln |V(π₯, π‘)| and (113), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨ σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨πΎ5 + (π5 − πΎ5 ) sn2 (Ω19 (π₯ − ππ‘) , π19 )σ΅¨σ΅¨σ΅¨σ΅¨ . (108) (b) When π = −2π, π ∈ Z+ and πΌπ½ < 0, π½π < 0, πΌπ > 0, β > βπ΅1 , (14) can be reduced to π¦=± =± √π½/ππ + β(ππ )2 − (2πΌ/ππ) (ππ )3 ππ−1 √2πΌ/ππ√(ππ − ππ ) (ππ − ππ ) (ππ − πΎπ ) ππ−1 (112) , where ππ , ππ , πΎπ are roots of equation π½/ππ + β(ππ )2 − (2πΌ/ππ)(ππ )3 = 0 and ππ > ππ > 0 > πΎπ . Taking (0, π) as the initial values of the variables (π, π), substituting (112) into the ππ/ππ = π¦ of (11), and then integrating it yield V (π₯, π‘) = π (π) = [ππ − (ππ − ππ ) sn2 (Ω20 π, π20 )] 1/π , (113) where Ω20 = π√πΌ(ππ − πΎπ )/2ππ, π20 = π π π π √(π − π )/(π − πΎ ). By using the transformations π’(π₯, π‘) = ln |V(π₯, π‘)| and (113), we obtain periodic wave solutions of (1) as follows: π’ (π₯, π‘) = 1 σ΅¨σ΅¨ π σ΅¨ ln σ΅¨σ΅¨σ΅¨π − (ππ − ππ ) sn2 (Ω20 (π₯ − ππ‘) , π20 )σ΅¨σ΅¨σ΅¨σ΅¨ . π (114) Journal of Applied Mathematics 11 (c) When π = −2π, π ∈ Z+ and πΌπ½ > 0, π½π < 0, πΌπ > 0, β > βπ΅2 , (14) can be reduced to π¦=± =± √π½/ππ + β(ππ )2 − (2πΌ/ππ) (ππ )3 ππ−1 (115) √−2πΌ/ππ√(ππ − ππ ) (ππ − ππ ) (ππ − πΎπ ) ππ−1 we only discuss the front case here. When π = 2, π = 1, under the transformation ππ = ππππ, system (118) can be reduced to the following regular system: V (π₯, π‘) = [ π − 1/π 2 ππ π21 sn2 (Ω21 π, π21 ) ] , dn2 (Ω21 π, π21 ) σ΅¨ σ΅¨ π π 2 2 1 σ΅¨σ΅¨σ΅¨ π − π π21 sn (Ω21 π, π21 ) σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ . ln σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ π σ΅¨σ΅¨ dn2 (Ω21 π, π21 ) σ΅¨ (116) (117) 4. Exact Traveling Wave Solutions of (1) and Their Properties under the Conditions π ∈ Z− , π ∈ Z− In this sections, we consider the case π ∈ Z− , π ∈ Z− of (1); that is, we will investigate different kinds of exact traveling wave solutions of (1) under the conditions π ∈ Z− , π ∈ Z− . Letting π = −π, π = −π, π ∈ Z+ , π ∈ Z+ , (11) becomes ππ¦ ππ¦2 − πΌπ2−π − π½π2−π = . ππ ππ ππ = π¦, ππ π» (π, π¦) = (119) which is an integrable system and it has the following first integral: (120) π¦2 2 (πΌ + π½) Μ − = β. π2 ππ (126) π¦2 2πΌ −π 2π½ −π Μ − π − π = β. π2 ππ ππ (127) Obviously, when π = π, system (125) has not any equilibrium point in the π-axis. When π − π is even number and πΌπ½ < 0, system (125) has two equilibrium points π΅1,2 (±π+ , 0) in the πaxis, where π+ = (−π½/πΌ)1/(π−π) . When π − π is odd number, system (125) has only one equilibrium point at π΅1 (π+ , 0) in the π-axis. Respectively substituting the above equilibrium points into (121), (124), and (127), we have 2 where Μβ is integral constant. When π =ΜΈ 0, we define π» (π, π¦) = (125) 2πΌ 2−π 2π½ 2−π π + π . ππ ππ π¦2 = π2 Μβ + π» (π, π¦) = 2 (πΌ + π½) π, π (124) which is an integrable system and it has the following first integral: First, we consider a special case π = π = 1. When π = π = 1, under the transformation ππ = ππππ, system (118) can be reduced to the following regular system: π¦2 = π2 Μβ + π½ π¦2 2πΌ − = Μβ. − π2 ππ ππ2 ππ¦ = πππ−2 π¦2 − πΌππ−π − π½ ππ ππ = πππ−1 π¦, ππ When π =ΜΈ 0, we define ππ¦ = ππ¦2 − (πΌ + π½) π, ππ (123) Μ 0 , 0) Indeed, system (122) has only one equilibrium point π΄(π in the π-axis, where π0 = −π½/πΌ. When ππ½ > 0, system (122) has two equilibrium points π± (0, π± ) in the singular line π = 0, where π± = ±√π½/π. Finally, we consider the general case π > 2. When π > 2, under the transformation ππ = πππ−1 ππ, system (118) can be reduced to the following regular system: (118) ππ = πππ¦, ππ π½ 2πΌ π+ , π π π¦2 = Μβπ2 + also we define = π√−πΌ(ππ − πΎπ )/2ππ, π21 = where Ω21 π π π π √(π − π )/(π − πΎ ). By using the transformations π’(π₯, π‘) = ln |V(π₯, π‘)| and (116), we obtain a periodic wave solution of (1) as follows: π’ (π₯, π‘) = (122) which is an integrable system and it has the following first integral: , where ππ > 0 > ππ > πΎπ . Taking (0, π) as the initial values of the variables (π, π), substituting (115) into the ππ/ππ = π¦ of (11), and then integrating it yield π ππ¦ = ππ¦2 − πΌπ − π½, ππ ππ = πππ¦, ππ (121) Obviously, when πΌ =ΜΈ − π½, system (119) has only one equilibrium point π(0, 0) in the π-axis. Second, we consider the special case π = 2, π = 1, and another case π = 1, π = 2 is very similar to the front case, so Μβ Μ = π» (π , 0) = − πΌ , 0 π΄ ππ½ (128) Μβ = π» (π , 0) = − 2πΌ π−π − 2π½ π−π , 1 + ππ + ππ + (129) Μβ = π» (−π , 0) = (−1)π+1 2πΌ π−π + (−1)π+1 2π½ π−π . 2 + ππ + ππ + (130) 12 Journal of Applied Mathematics 4.1. Nonsmooth Peakon Solutions and Periodic Blow-Up Wave Solutions under Two Special Cases π = π = 1 and π = 2, π = 1. (1) When π = π = 1 and πΌπ > 0, Μβ < 0, (120) can be reduced to 2 (πΌ + π½) π¦ = ±√Μβπ2 − π. π (131) Substituting (131) into the first equation of (118), taking (0, πΜβ/(2(πΌ + π½))) as initial value conditions, and integrating it, we obtain V (π₯, π‘) = π (π) = πΌ+π½ (cos √−Μβπ − 1) . πβ (132) where π1 = (1/√−Μβ)arccos((ππ + ππ )/(ππ − ππ )). From the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (138), we obtain a periodic blow-up wave solution of (1) as follows: π’ (π₯, π‘) σ΅¨σ΅¨ 1 σ΅¨σ΅¨σ΅¨ σ΅¨ = ln σ΅¨σ΅¨σ΅¨ [(ππ + ππ ) − (ππ − ππ ) cos (√−Μβ (π₯ − ππ‘))]σ΅¨σ΅¨σ΅¨ , σ΅¨σ΅¨ 2 σ΅¨σ΅¨ (139) where π₯ − ππ‘ =ΜΈ π1 + πΎπ, πΎ ∈ Z. (4) When π = 2, π = 1 and πΌπ½ > 0, π½π < 0 (or πΌπ½ < 0, π½π < 0), Μβ > −πΌ2 /ππ½, (123) can be reduced to From the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (132), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨σ΅¨ σ΅¨σ΅¨ πΌ + π½ σ΅¨ σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨ [cos (√−Μβ (π₯ − ππ‘)) − 1]σ΅¨σ΅¨σ΅¨ , σ΅¨σ΅¨ σ΅¨σ΅¨ πβ (133) where (π₯ − ππ‘) =ΜΈ 2πΎπ/√−Μβ, πΎ ∈ Z. (2) When π = 2, π = 1 and πΌπ½ > 0, π½π > 0 (or πΌπ½ < 0, π½π > 0), Μβ = Μβπ΄Μ = πΌ2 /π½π, (123) can be reduced to π¦=± π½ σ΅¨σ΅¨σ΅¨ πΌ σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨π + σ΅¨σ΅¨σ΅¨ . πΌ σ΅¨σ΅¨ √π½π σ΅¨σ΅¨ (134) Similarly, substituting (134) into the first equation of (118) and then integrating it, and setting the integral constant as zero, we have σ΅¨σ΅¨ σ΅¨σ΅¨ π½ σ΅¨πΌπσ΅¨ V (π₯, π‘) = π (π) = − [1 − exp (− σ΅¨ σ΅¨ )] . (135) πΌ √π½π From the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (135), we obtain a broken solitary cusp wave solution of (1) as follows: σ΅¨ σ΅¨σ΅¨σ΅¨ π½ |πΌ (π₯ − ππ‘)| σ΅¨σ΅¨σ΅¨ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨σ΅¨− [1 − exp (− )]σ΅¨σ΅¨σ΅¨ , (π₯ − ππ‘) =ΜΈ 0. σ΅¨σ΅¨ πΌ σ΅¨σ΅¨ √π½π (136) (3) When π = 2, π = 1 and πΌπ½ > 0, π½π > 0 (or πΌπ½ < 0, π½π > 0), Μβ < 0, (123) can be reduced to (140) Similarly, we have V (π₯, π‘) = π (π) = − 2 πΌ √πΌ − π½πΜβ − cos (√−Μβπ) . πΜβ πΜβ (141) From the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (141), we obtain a periodic blow-up wave solution of (1) as follows: σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ 2 σ΅¨ σ΅¨σ΅¨ πΌ √πΌ − π½πΜβ cos √−Μβ (π₯ − ππ‘)σ΅¨σ΅¨σ΅¨σ΅¨ . π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨ + Μ Μ σ΅¨σ΅¨ σ΅¨σ΅¨ πβ πβ σ΅¨σ΅¨ σ΅¨σ΅¨ (142) 4.2. Periodic Blow-Up Wave Solutions in the Special Case π = 2π > 1. When π = 2π > 2 and πΌπ½ < 0, πΌπ > 0 (or πΌπ½ > 0, πΌπ < 0), Μβ ∈ (Μβ1 , 0), (118) becomes 2πΌ −π π½ −2π π¦ = ±√ π2 (Μβ + π + π ) ππ ππ =± √−Μβ√−π½/ππΜβ − (2πΌ/ππΜβ) ππ − (ππ )2 ππ−1 (143) . Substituting (143) into the first equation of (118) and then integrating it, we have π½ 2πΌ π¦ = ±√−Μβ√ − − π − π2 πΜβ πΜβ (137) = ±√−Μβ√(ππ − π) (π − ππ ), where ππ = (−πΌ+ √πΌ2 − πΜβπ½)/πΜβ, ππ = (−πΌ− √πΌ2 − πΜβπ½)/πΜβ are roots of equation −π½/πΜβ − (2πΌ/πΜβ)π − π2 = 0. Substituting (137) into the first equation of (118), taking (0, ππ) as initial value conditions, and then integrating it, we have V (π₯, π‘) = π (π) = 2πΌ πΌ π¦ = ±√Μβπ2 + π+ . π π 1 [ (ππ + ππ ) − (ππ − ππ ) cos (√−βπ)] , 2 π ∈ (−π1 , π1 ) , (138) 1/π πΌ2 − ππΜβπ½ πΌ cos (π√−Μβπ)] . +√ V (π₯, π‘) = π (π) = [− ππΜβ π2 π2 Μβ2 ] [ (144) From the transformation π’(π₯, π‘) = ln |V(π₯, π‘)| and (144), we obtain periodic blow-up wave solutions of (1) as follows: σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨ πΌ2 − ππΜβπ½ 1 σ΅¨σ΅¨σ΅¨ πΌ σ΅¨ cos (π√−Μβ (π₯ − ππ‘))σ΅¨σ΅¨σ΅¨σ΅¨ . +√ π’ (π₯, π‘) = ln σ΅¨σ΅¨σ΅¨− 2 2 2 Μ π σ΅¨σ΅¨ ππΜβ σ΅¨σ΅¨ ππβ σ΅¨σ΅¨ σ΅¨σ΅¨ (145) Journal of Applied Mathematics 5. Conclusion In this work, by using the integral bifurcation method, a generalized TzitzeΜica-Dodd-Bullough-Mikhailov (TDBM) equation is studied. In some special cases, we obtained many exact traveling wave solutions of TDBM equation. These exact solutions include smooth solitary wave solutions, singular periodic wave solutions of blow-up form, singular solitary wave solutions of blow-up form, broken solitary wave solutions, broken kink wave solutions, and some unboundary wave solutions. Comparing with the results in many references (such as [24–27]), these types of solutions in this paper are very different than those types of solutions which are obtained by Exp-function method. Though the types of solutions derived from two methods are different, they are all useful in nonlinear science. The smooth solitary wave solutions and singular solitary wave solutions obtained in this paper especially can be explained phenomenon of soliton surface that the total curvature at each point is proportional to the fourth power of the distance from a fixed point to the tangent plane. Acknowledgments The authors would like to thank the reviewers very much for their useful comments and helpful suggestions. This work is supported by the Natural Science Foundation of Yunnan Province (no. 2011FZ193) and the National Natural Science Foundation of China (no. 11161020). The e-mail address “weiguorhhu@aliyun.com” in the author’s former publications (published articles) has been replaced by new e-mail address “weiguorhhu@aliyun.com” because Yahoo Company in China will be closed on August 19, 2013. Please use the new E-mail address “weiguorhhu@aliyun.com” if the readers contact him. References [1] G. TzitzeΜica, “Geometric infinitesimale-sur une nouvelle classes de surfaces,” Comptes Rendus de l’AcadeΜmie des Sciences, vol. 144, pp. 1257–1259, 1907. [2] G. TzitzeΜica, “Geometric infinitesimale-sur une nouvelle classes de surfaces,” Comptes Rendus de l’AcadeΜmie des Sciences, vol. 150, pp. 955–956, 1910. [3] G. TzitzeΜica, “Sur certaines courbes gauches,” Annales Scientifiques de l’EΜcole Normale SupeΜrieure. TroisieΜme SeΜrie, vol. 28, pp. 9–32, 1911. [4] R. K. Bullough and R. K. 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