DYNAMIC CRACK PROPAGATION BETWEEN TWO BONDED ORTHOTROPIC PLATES M. S. MATBULY Received 30 June 2003 and in revised form 30 August 2003 The problem of crack propagation along the interface of two bonded dissimilar orthotropic plates is considered. Using Galilean transformation, the problem is reduced to a quasistatic one. Then, using Fourier transforms and asymptotic analysis, the problem is reduced to a pair of singular integral equations with Cauchy-type singularity. These equations are solved using Gauss-Chebyshev quadrature formulae. The dynamic stress intensity factors are obtained in closed form expressions. Furthermore, a parametric study is introduced to investigate the effect of crack growth rate and geometric and elastic characteristics of the plates on values of dynamic stress intensity factors. 1. Introduction Composite materials have been extensively employed in many engineering fields such as mechanical and aerospace structures. When the material used as member of such structures contains a crack, it is seriously necessary to study the stress field distribution at the immediate vicinity of crack tips. The inertia action must be considered when the applied loads or crack length depend on time. Also, the most frequently observed phenomenon in the experiments shows that the crack growth rate is constant during the extending history except in the final unstable or arresting stage [11]. So, the elastodynamic analysis of a moving crack, with constant velocity, is one of the most important problems in fracture mechanics. The dynamic stress intensity factors (DSIF) play a key role in characterizing the fracture behaviour of such problems. Thus, analytical determination of DSIF in predicting the fracture cannot be overemphasized. In general, there are two approaches for analytical determination of DSIF. The first one employs the integral transforms and asymptotic analysis to reduce the problem to that of a system of singular integral equations [1, 3, 10, 15, 20, 22, 23]. The second approach employs complex analysis to reduce the problem to that of a system of Riemann-Hilbert problems [12, 13, 14, 19]. The present work is concerned with elastodynamic stress disturbance problem of a moving Griffith crack with constant velocity. The crack is located at the interface of two Copyright © 2004 Hindawi Publishing Corporation Journal of Applied Mathematics 2004:1 (2004) 55–68 2000 Mathematics Subject Classification: 42C20 URL: http://dx.doi.org/10.1155/S1110757X04306170 56 Dynamic crack propagation between two bonded plates X2 1 1 σ12 = σ22 =0 =1 Plate 1 1 σ22 = F1 (X1 ) H1 1 = F2 (X1 ) σ12 X1 Interfacial line 2 σ12 = F2 (X1 ) 2 = F1 (X1 ) σ22 H2 =2 a0 +ct a0 +ct Plate 2 2 2 σ12 = σ22 =0 Figure 1.1. Two bonded dissimilar plates containing moving interfacial crack. bonded dissimilar orthotropic plates, as shown in Figure 1.1. Each plate possesses a finite width and is subjected to a static stress distribution along crack surfaces. This is the main difference between the present work and previous ones [1, 3, 4, 6, 7, 8, 10, 12, 13, 14, 15, 19, 20, 22, 23], which were concerned only with plates of infinite widths. The governing equations of the problem are described. Then, Fourier transforms and asymptotic analysis are employed to reduce the solution of the problem to that of a system of first-kind singular integral equations with Cauchy-type singularity. These are solved numerically according to the algorithm in [17]. Then, closed-form expressions for the asymptotic stress field distribution at the immediate vicinity of crack tips are obtained. 2. Governing equations Assuming that the Cartesian coordinate axes are the axes of symmetry of the elastic materials, the displacement equations of motion for orthotropic plates are [3] 2 ∂2 U2 ∂2 U1 ∂2 U1 ∂ U1 = m , 2 + C66 2 + C12 + C66 ∂X1 ∂X2 ∂t 2 ∂X1 ∂X2 2 2 ∂2 U1 ∂2 U2 ∂ U2 ∂ U2 = m , C66 2 + C22 2 + C12 + C66 ∂X1 ∂X2 ∂t 2 ∂X1 ∂X2 C11 (2.1) where is a superscript ( = 1 for orthotropic material in X2 > 0, while = 2 for orthotropic material in X2 < 0), as shown in Figure 1.1; U j ( j = 1,2) are the displacement components in direction of X1 and X2 , respectively; Cij (i, j = 1,2) and C66 are the elastic constants of orthotropic plate materials; and m and t are the material mass density and time, respectively. The boundary conditions along the interface of plates are 1 2 X1 ,X2 ,t = lim− σ22 X1 ,X2 ,t = F1 X1 , lim+ σ22 X2 →0 1 lim σ12 X2 →0+ X1 ,X2 ,t X2 →0 2 = lim− σ12 X2 →0 X1 ,X2 ,t = F2 X1 , X1 < a0 + d, M. S. Matbuly 57 lim U11 X1 ,X2 ,t = lim− U12 X1 ,X2 ,t , X2 →0+ lim U21 X2 →0+ X1 ,X2 ,t X2 →0 = lim− U22 X2 →0 X1 > a0 + d X1 ,X2 ,t , 1 2 lim+ σ22 X1 ,X2 ,t = lim− σ22 X1 ,X2 ,t , X2 →0 1 lim σ12 X2 →0+ X1 ,X2 ,t X2 →0 2 = lim− σ12 X2 →0 X1 > a0 + d, X1 ,X2 ,t , (2.2) where a0 is the initial half crack length, and d = |c|t, where c is the magnitude of crack propagation velocity. Moreover, Fi (X1 ) (i = 1,2) are known functions. They represent the applied static stress along crack surfaces; F1 (−X1 ) = F1 (X1 ) and F2 (−X1 ) = − f2 (−X1 ). The boundary conditions along the external boundaries are 1 1 2 σ12 X1 ,H1 ,t = σ22 X1 ,H1 ,t = σ12 X1 , −H2 ,t 2 X1 , −H2 ,t = 0, = σ22 (2.3) X1 < ∞, where H1 and H2 are as shown in Figure 1.1. Using Galilean transformation: x = (X1 − ct)/a0 , y = X2 /a0 , and t = t, the governing equations (2.1), (2.2), and (2.3) can be reduced to a quasistatic form as follows: 2 2 ∂2 u ∂ ν ∂ u + a = 0, + a 1 2 ∂x2 ∂x∂y ∂y 2 ( = 1,2) 2 2 ∂2 ν ∂ u ∂ ν + b + b = 0, 1 2 ∂x2 ∂x∂y ∂y 2 (2.4) where u (x, y) = U1 X1 ,X2 ,t , a0 ν (x, y) = a1 = C12 + C66 2 , C11 1 − M1 a2 = b1 = C12 + C66 2 , C66 1 − M2 b2 = c M j = Vj ( j = 1,2), C11 C66 V1 = U2 X1 ,X2 ,t , a0 (2.5a) C66 2 , 1 − M1 (2.5b) C22 2 , 1 − M2 (2.5c) C11 , m V2 = C66 . m (2.5d) Furthermore, the values of Mach numbers M j (, j = 1,2) are assumed to be less than unity for subsonic crack propagation. 58 Dynamic crack propagation between two bonded plates The boundary conditions for the reduced quasistatic problem can be expressed as follows: lim σ y1y (x, y) = lim− σ y2y (x, y) = f1 (x), y →0 y →0+ |x| < 1, 1 2 lim+ σxy (x, y) = lim− σxy (x, y) = f2 (x), (2.6) y →0 y →0 lim u1 (x, y) = lim− u2 (x, y), y →0 y →0+ |x| > 1, lim+ ν (x, y) = lim− ν2 (x, y), 1 (2.7) y →0 y →0 lim+ σ y1y (x, y) = lim− σ y2y (x, y), y →0 y →0 1 2 lim σxy (x, y) = lim− σxy (x, y), y →0 y →0+ σxy = σ12 , Q σ y y = |x| > 1, (2.8) 1 2 σ y1y x,h1 = σxy x,h1 = σ y2y x, −h2 = σxy x, −h2 = 0, |x| < ∞, (2.9) where H h = a0 σ22 , Q 1 2 C66 , Q = C66 (2.10) ( = 1,2). 3. Solution of the problem Decoupling (2.4) then employing Fourier sine (cosine) transforms with respect to x, one can find that 4 ∞ 1 Aj (α)eαr j y sinαx dα , u (x, y) = π j =1 0 4 ∞ 1 ν (x, y) = kj Aj (α)eαr j y cosαx dα , π j =1 0 ( = 1,2) (3.1) where α is the transform variable, Aj (α) ( = 1,2 and j = 1,4) are unknown functions, and r j ( = 1,2 and j = 1,4) are the real distinct roots of f1 r 4 − 2 f2 r 2 + 1 = 0 ( = 1,2), (3.2) provided that f1 = a2 b2 , kj = 2 f2 = a2 + b2 − a1 b1 , 2 a2 r j − 1 a1 r j f2 > f1 , f1 > 0, ( = 1,2, j = 1,4). (3.3) (3.4) M. S. Matbuly 59 From the stress-displacement relationship of orthotropic materials [9], one can get (x, y) = σxy C66 ∂ν ∂u + Q ∂x ∂y 4 ∞ 1 αpj Aj (α)eαr j y sinαx dα = π j =1 0 σ y y (x, y) = = 1 ∂u ∂ν C12 + C22 Q ∂x ∂y ( = 1,2), 4 ∞ 1 αoj Aj (α)eαr j y cosαx dα π j =1 0 (3.5) ( = 1,2), where pj C66 r j − kj = , Q oj C12 + C22 rj kj = . Q (3.6) On suitable substitution from (2.9) into (3.5), one can find that Am (α) = 4 Ljm eαβ jm Aj (α) (m, = 1,2), (3.7) j =3 where h1 r − r for = 1 j m (m = 1,2, j = 3,4), = h2 r − r for = 2 j m 2 n n=1 (−1) 1 − δnm pn o j − p j on L jm = (,m = 1,2, j = 3,4), p1 o2 − p2 o1 βjm (3.8) (3.9) δnm is the Kronecker delta. Substituting (3.5) and (3.7) into (2.8), one can find that E2 D1 − D42 E41 1 E42 D31 − D42 E31 1 A3 (α) + 4 4 A4 (α), ∆ ∆ D2 E1 − E32 D41 1 D2 E1 − E32 D31 1 A3 (α) + 3 4 A4 (α), A24 (α) = 3 3 ∆ ∆ A23 (α) = (3.10) where ∆ = D32 E42 − D42 E32 , Dj = pj + 2 m=1 αβ jm pm L jm e , Ej = oj + 2 m=1 om Ljm eαβ jm ( = 1,2, j = 3,4). (3.11) 60 Dynamic crack propagation between two bonded plates The boundary conditions (2.6) and (2.7) in conjunction with (3.7), (3.8), (3.9), (3.10), and (3.11) lead to 1 ∞ 1 1 α E3 A3 (α) + E41 A14 (α) cosαx dα = f1 (x), π 0 |x| < 1, 1 ∞ 1 1 1 1 α D3 A3 (α) + D4 A4 (α) sinαx dα = f2 (x), π 0 ∞ 1 α τ1 (α)A13 (α) + τ2 (α)A14 (α) sinαx dα = 0, π 0 |x| > 1, 1 ∞ α ξ1 (α)A13 (α) + ξ2 (α)A14 (α) cosαx dα = 0, π 0 (3.12) (3.13) where 2 τ1 (α) = 1 + 2 τ2 (α) = 1 + ξ1 (α) = − 1+ m=1 k31 + 2 m=1 ξ2 (α) = k41 + 2 m=1 − k42 + 2 2 L23m eαβ3m 1 1 αβ13m km L3m e 2 k32 + − m=1 ∆3 − 1 + 2 2 αβ23m km L3m e 2 L24m eαβ4m ∆2 , ∆4 , m=1 ∆1 2 1 m=1 2 1 E4 D3 − D42 E31 2 2 2 αβ4m km L4m e ∆2 , 1 1 αβ4m km L4m e − k32 + 2 2 2 L24m eαβ4m m=1 2 L23m eαβ3m 2 ∆1 − 1 + m=1 m=1 2 m=1 1 L14m eαβ4m − k42 + ∆1 = − 1+ m=1 1 L13m eαβ3m 2 m=1 (3.14) 2 2 2 αβ3m km L3m e ∆3 2 2 2 αβ4m km L4m e ∆4 , , ∆ E42 D41 − D42 E41 , ∆3 = ∆ D32 E31 − E32 D31 , ∆ D2 E1 − E32 D41 ∆4 = 3 4 . ∆ ∆2 = The unknown functions A1j (α) ( j = 3,4) can be determined through solving the integral equations (3.12) and (3.13) as follows [21]. Let ∂ν1 (x, y) ∂ν2 (x, y) − lim− = φ1 (x) 1 − H(x − 1) , y →0 y →0 ∂x ∂x ∂u1 (x, y) ∂u2 (x, y) lim+ − lim− = φ2 (x) 1 − H(x − 1) , y →0 y →0 ∂x ∂x lim+ (3.15) where H(x − 1) is the unit step function [2], while φ j (x) ( j = 1,2) are unknown odd and even functions of x, respectively. M. S. Matbuly 61 From (3.13) and (3.15), one can deduce that τ2 Φ1 (α) + ξ2 Φ2 (α) , (αΨ) − τ1 Φ1 (α) + ξ1 Φ2 (α) A14 (α) = , (αΨ) A13 (α) = (3.16) where Φ1 (α) = 2 Φ2 (α) = 2 1 0 1 0 φ1 (x)sinαx dx, (3.17) φ2 (x)cosαx dx, Ψ = τ1 ξ2 − τ2 ξ1 . Substituting (3.16) into (3.12), the problem is reduced to the following system of integral equations: 2 1 j =1 −1 H̆i j (x,t)φ j (t)dt = fi (x), |x| < 1, i = 1,2, (3.18) where the kernels H̆i j (x,t) are 1 ∞ 1 1 E3 τ2 − E41 τ1 sinα(t − x)dα, π 0 Ψ 1 ∞ 1 1 H̆12 (x,t) = E3 ξ2 − E41 ξ1 cosα(t − x)dα, π 0 Ψ 1 ∞ 1 1 D3 τ2 − D41 τ1 cosα(t − x)dα, H̆21 (x,t) = π 0 Ψ 1 ∞ 1 1 H̆22 (x,t) = − D ξ2 − D41 ξ1 sinα(t − x)dα. π 0 Ψ 3 H̆11 (x,t) = (3.19) Since the integrands of (3.19) are continuous functions of α, then it is clear that any possible singularity of the kernels must result from the asymptotic analysis of the integrands as t → x and α → ∞ [16, 21]. Then, by adding and subtracting the asymptotic expressions of these integrands under the integral sign, the problem can be reduced to the following pair of singular integral equations with Cauchy-type singularity: 1 1 2 φ j (t) 1 δi j G i j Hi j (x,t)φ j (t)dt = fi (x), dt + π j =1 −1 t − x −1 |x| < 1, i = 1,2, (3.20) 62 Dynamic crack propagation between two bonded plates where H11 (x,t) = H12 (x,t) = H21 (x,t) = H22 (x,t) = ∞ 0 1 1 E3 τ2 − E41 τ1 − G11 sinα(t − x)dα, Ψ 0 1 1 E3 ξ2 − E41 ξ1 − G12 cosα(t − x)dα, Ψ 0 1 1 D τ2 − D41 τ1 − G21 cosα(t − x)dα, Ψ 3 ∞ ∞ ∞ 0 1 −1 Ψ D31 ξ2 − D41 ξ1 − G22 sinα(t − x)dα, o3 B − s2 /B − o14 B − s1 /B , Z G11 = 1 G12 = p1 B − s2 /B − p41 B − s1 /B G21 = 3 , Z o3 k41 B − s4 /B − o14 k31 B − s3 /B , Z p1 k1 B − s3 /B − p31 k41 B − s4 /B G22 = 4 3 , Z (3.21) 1 s − s + k1 s − k41 s1 s1 s4 − s2 s3 , + Z = k41 − k3 + 3 4 3 2 B B2 B = L231 L242 − L241 L232 p12 o22 − p22 o21 , s1 = B13 + B24 L231 L242 + B12 + B27 L241 L232 , s2 = B33 + B44 L231 L242 + B32 + B47 L241 L232 , s3 = k12 B13 + k22 B24 L231 L242 + k22 B12 + k12 B27 L241 L232 , s4 = k12 B33 + k22 B44 L231 L242 + k22 B32 + k12 B47 L241 L232 , B13 = p31 o22 − p22 o13 , B24 = p12 o13 − p31 o21 , B12 = p31 o21 − p12 o13 , B27 = p22 o13 − p31 o22 , B33 = p41 o22 − p22 o14 , B44 = p12 o14 − p41 o21 , B32 = p41 o21 − p12 o14 , B47 = p22 o14 − p41 o22 . From (3.15) and (2.5d), one can deduce the single-valuedness conditions ensuring the uniqueness of φi (α) (i = 1,2) as follows: 1 −1 φ1 (t)dt = 0, 1 2 φ2 (t)dt = c −1 2 C11 − m2 Equations (3.20) and (3.22) can be solved as follows [17]. 1 C11 . m1 (3.22) M. S. Matbuly 63 Assume that qi (t) φi (t) = √ 1 − t2 (i = 1,2), (3.23) where qi (t) (i = 1,2) are bounded continuous functions for all t ∈ [−1,1]. By substituting from (3.23) into (3.20) and (3.22) then employing Gauss-Chebyshev integration formulae, the solution of the problem can be reduced to the following system of linear algebraic equations [17]: n1 2 wk j =1 k=1 δi j G i j + Hi j xl ,tk q j tk = fi xl tk − xl n1 wk q2 tk k =1 wk q1 tk = 0, k =1 n1 (i = 1,2) xl = 1,n1 − 1 , 2 = πc (3.24) 2 C11 − m2 1 C11 , m1 where n1 is the number of collocation points in the interval [−1,1], w1 = wn1 = 1 , 2n1 − 2 tk = cos xl = cos wk = π(k − 1) n1 − 1 π(2l − 1) 2n1 − 2 1 n1 − 1 for k = 2,n1 − 1 , k = 1,n1 , (3.25) l = 1,n1 − 1 . For the concerned problem, one can deduce that the DSIF at the left and right crack tips are equal. Then, by making use of the following asymptotic relations, as α → ∞, [5]: Φ1 (α) = 1 −1 q (t) sinαt dt ≈ q1 (1) 1 − t2 1 q (t) √2 cosαt dt ≈ q2 (1) Φ2 (α) = 1 − t2 −1 ∞ 0 1 α √ e−bα √1 2π π 1 +ϑ , sin α − α 4 α 2π π 1 +ϑ , cos α − α 4 α √ sin h π dα = 0.5tan−1 , 0.25 b coshα cos b 2 + h2 sinhα b > 0, (3.26) 64 Dynamic crack propagation between two bonded plates the leading terms of the asymptotic stress field distribution (3.5) at the immediate vicinity of the right crack tip (x → 1 and y → 0± ) can be obtained as follows: ζ ζ θ θ σxy (x, y) ≈ q1 (1) 1 sin 1 − 2 sin 2 2ρ1 2 2ρ2 2 θ θ ζ ζ + q2 (1) 3 cos 1 − 4 cos 2 , 2ρ1 2 2ρ2 2 (3.27) γ1 γ2 θ θ σ y y (x, y) ≈ q1 (1) cos 1 − cos 2 2ρ1 2 2ρ2 2 γ3 γ4 θ θ + q2 (1) sin 1 − sin 2 , 2ρ1 2 2ρ2 2 where 2 ρ1 = (x − 1)2 + r31 y , θ1 = tan−1 r31 y , x−1 ξ1 = θ2 = tan−1 ξ2 = 2 r41 y , x−1 p41 1 − s1 /B , Z p1 k1 − s4 /B ξ3 = 3 4 , Z p31 1 − s2 /B , Z ρ2 = (x − 1)2 + r41 y , γ1 = o13 1 − s2 /B , Z γ2 = o14 1 − s1 /B , Z γ3 = o13 k41 − s4 /B , Z γ4 = o14 k31 − s3 /B . Z (3.28) p1 k1 − s3 /B ξ4 = 4 3 , Z Therefore, the DSIF, KI , and KII can be determined as follows [18]: KI + iKII = Q 2a0 lim x→1, √ y →0+ x − 1 σ y y (x, y) + iσxy (x, y) (3.29) such that by substituting from (3.27) and (3.28) into (3.29) then evaluating the limits, one can find that √ √ KI = Q a0 γ1 − γ2 q1 (1), KII = Q a0 ξ3 − ξ4 q2 (1). (3.30) M. S. Matbuly 65 3.4 a0 = 0.75 Normalized DSIF (KI ) 3.0 2.6 a0 = 0.5 2.2 a0 = 0.25 1.8 1.4 1.0 a0 = 0.10 0.6 0.2 −0.2 0.0 0.2 0.8 0.4 0.6 Crack growth rate (mm/h) Figure 4.1. Variation of the normalized KI with the crack growth rate and initial crack length. 4. Numerical results A parametric study is introduced to investigate the effects of crack growth rate, initial crack length, and the plate width on the values of DSIF. Consider that a structure of two bonded orthotropic plates as in Figure 1.1 possesses the following elastic characteristics: m1 = m2 = 1g/cm3 , 1 2 C66 = C66 = 1MPa, 1 = 2.5MPa, C22 2 C11 = 1 + r1 C66 − r1 r2 C22 = C12 2 r1 r2 (4.1) 2 C22 = 4MPa, 2 + 1 − r1 2 + r2 ( = 1,2), − 1 C66 ( = 1,2), where (4.1) are derived from (2.5), (3.2), and (3.3). Also, for the concerned numerical results, it is assumed that 1 > r1 > r2 > 0, r3 = −r1 , and r4 = −r2 . The initial crack length 2a0 ranges from 0.2 to 1.5 cm, while the width of plates ranges from 5 to 10 m. For simplicity, the numerical results are obtained for constant uniform stress distribution along the crack surfaces, |x| < 1 and y → ±0. !∞ !4 Furthermore, we have found that | 0 Ii j (α,x,t)dα − 0 Ii j (α,x,t)dα| < 10−16 , where Ii, j (α,x,t) (i, j = 1,2), are the integrands of (3.21). Therefore, the improper integrals of (3.21) are approximated and evaluated numerically from α = 0 → 4 by using the trapezoidal rule. Then, the values of DSIF are normalized such that NormalizedKI = KI 1 √ , σ22 a0 Normalized KII = KII 1 √ , σ12 a0 1 1 and σ12 represent the applied stress along the upper crack surface. where σ22 (4.2) Dynamic crack propagation between two bonded plates Normalized DSIF (KII ) 66 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 −1.0 −2.0 −3.0 −4.0 0.1 a0 = 0.5 a0 = 0.25 a0 = 0.1 a0 = 0.75 0.2 0.3 0.4 0.5 0.6 Crack growth rate (mm/h) 0.7 0.8 Figure 4.2. Variation of the normalized KII with the crack growth rate and initial crack length. Normalized DSIF (KI ) 2.2 H1 = 10, H2 = 5 1.8 1.4 H1 = 5, H2 = 5 1.0 H1 = 5, H2 = 10 0.6 0.1 0.2 0.3 0.4 0.5 0.6 Crack growth rate (mm/h) 0.7 0.8 Figure 4.3. Variation of the normalized KI with the crack growth rate for different plate widths. Figure 4.1 shows that the value of normalized KI continuously decreases with increasing the crack growth rate, where 0 < c < 0.32 and 0.5 < c < 0.6, while it increases elsewhere. Also, it shows increasing the pathological oscillatory behaviour [3] for the normalized KI with increasing the initial crack length. Figure 4.2 shows that the value of normalized KII continuously increases with increasing the crack growth rate except for 0.5 < c < 0.65. But this decreasing interval is shifted to 0.4 < c < 0.5 for the case of a relatively long initial crack length 2a0 = 1.5 cm. One can notice as well that the pathological oscillatory behaviour of the normalized KII increases with increasing a0 . For the prescribed elastic and geometric characteristics, Figure 4.3 shows that the value of normalized KI continuously increases with increasing the crack growth rate except when c < 0.5 and H1 > H2 , it is decreased. Also, Figure 4.4 shows that the value of normalized KII continuously decreases with increasing the crack growth rate, while it increases with increasing c when c > 0.62 and H1 < H2 . M. S. Matbuly 67 Normalized DSIF (KII ) 1.7 1.6 1.5 H1 = 10, H2 = 5 1.4 1.3 H1 = 5, H2 = 10 H1 = 5, H2 = 5 1.2 1.1 1.0 0.1 0.2 0.3 0.4 0.5 0.6 Crack growth rate (mm/h) 0.7 0.8 Figure 4.4. Variation of the normalized KII with the crack growth rate for different plate widths. 5. Conclusion The present work is concerned with elastodynamic analysis of crack propagation between two bonded dissimilar orthotropic plates. The width of each plate is assumed to be finite. This is the new trend and the main difference between this work and the previous ones [1, 3, 4, 6, 7, 8, 10, 12, 13, 14, 15, 19, 20, 22, 23]. So, the present work can be considered as an extension for the analysis of interfacial crack problems. References [1] [2] [3] [4] [5] [6] [7] [8] [9] [10] [11] R. Babaei and S. A. Lukasiewicz, Dynamic response of a crack in a functionally graded material between two dissimilar half planes under antiplane shear impact, Engrg. Fracture Mech. 60 (1998), 479–487. R. N. 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Matbuly: Department of Engineering Mathematics and Physics, Faculty of Engineering, Zagazig University, P.O. 44519, Zagazig, Egypt E-mail address: mohamedmatbuly@hotmail.com