Name: _______________________________________________________
BASEBALL PROBLEM
Suppose you throw a baseball into the air with an initial upward velocity of 29 ft/s and an initial height of
6ft. The formula h  16t 2  29t  6 gives the ball’s height h in feet at time t seconds.
a. How high is the ball when you first throw it?
b. How fast is the ball going when you first throw it
c. Graph the equation h  16t 2  29t  6 on your graphing calculator.
Hint: You’re going to have to change your ‘WINDOW’ settings on your calculator
before you hit ‘GRAPH’. They should look like this:
WINDOW
Xmin = 0
Xmax = 4
Xscl = 1
Ymin = 0
Ymax = 25
Yscl = 5
Xres = 1
d. Sketch a copy of the graph you got in part (c).
i. On your graph: label which axis represents ‘time’ and which axis represents ‘height’.
ii. Label the y – intercept, show the ordered pair
e. Use the equation and algebra to find out how high the ball is after 0.5 seconds. How high is the
ball after 1.5 seconds? (Show your work!!) Label both of these ordered pairs on your graph in
part (d)
f. The ball’s height is 0 when it is on the ground. Find the number of seconds it takes for the ball to
hit the ground by solving 0  16t 2  29t  6 . Label this ordered pair on your graph in part (d)