Football Problem
Shelby Hampton and
Katie Petersen
The height of a punted football can be
modeled with the quadratic function:
h=-0.01x²+1.18x+2


The y-intercept of this equation is 2.
This represents the ball starting 2 feet off the
ground.
Vertex

Vertex: x=-b/2a

x=-1.18/2(-.01)

x=59 – Plug this into equation and solve for y

Vertex=(59,36.81)
Vertex equation

y=-.01(x-59)²+36.81
The nearest defensive player is 5ft horizontally form
the point of impact. How high must the player reach
to block the punt?


y=-.01(5-59)²+36.81
y=7.65 feet
What is the ball’s height when it has
traveled 20 yards downfield? 1yd=3ft



20yds(3)=60ft
y=-.01(60-59)²+36.81
y=36.8 feet
How far downfield has the ball traveled
when it reaches a height of 6 ft.?


6=-.01(x-59)²+36.81
3.5 ft.=x
When does the ball hit the ground?



0=-.01(x-59)²+36.81
119.6 ft=x
approx. 40 yards downfield