1 Acta Math. Univ. Comenianae Vol. LXXIX, 1(2010), pp. 1–8 SOME GEOMETRIC PROPERTIES OF A GENERALIZED CESÀRO SEQUENCE SPACE V. A. KHAN Abstract. In this paper we define the generalized Cesàro sequence space Cesp (q) and exhibit some geometrical properties of the space. The results herein proved are exhibit analogous to those by Y. A. Cui [Southeast Asian Bull. Math. 24 (2000), 201–210] for the Cesàro sequence space Cesp . 1. Introduction Let (X, k.k) be a real Banach space. By B(X) and S(X), we denote the closed unit ball and the unit sphere of X, respectively. For any subset A of X, χA represents a characteristics function of A. A norm k.k is called uniformly convex (UC) (cf. [2]) if, for each ε > 0, there exists δ > 0 such that, for x, y ∈ S(X), kx − yk > ε implies 1 (x + y) < 1 − δ. (1.0.1) 2 A Banach space X is said to have the Banach-Saks property if every bounded sequence (xn ) in X admits a subsequence {zn } such that the sequence {tk (z)} is convergent in norm in X (see [1]), where 1 (z1 + z2 + · · · + zk ). k Every Banach space X with the Banach-Saks property is reflexive, but the converse is not true (see [4, 5]). Kakutani [6] proved that any uniformly convex Banach space X has the Banach-Saks property. Moreover, he also proved that if X is a reflexive Banach space and θ ∈ (0, 2) such that for every sequence (xn ) in S(X) weakly convergent to zero, there exist n1 , n2 ∈ N satisfying the Banach-Saks property. For a sequence (xn ) ⊂ X, we define tk (z) = A(xn ) = lim inf{kxi + xj k : i, j ≥ n, i 6= j}. n→∞ Received August 10, 2005; revised November 02, 2009. 2000 Mathematics Subject Classification. Primary 46E30, 46E40, 46B20. Key words and phrases. Banach-Saks property; ε-separated sequence; property β; Generalized Cesàro sequence space. 2 V. A. KHAN In [6], the following new geometric constant connected with the packing constant (see [7]) and with the Banach-Saks property was defined C(X) = sup{A(xn ) : (xn ) is a weakly null sequence in S(X)}. Recall that a sequence (xn ) is said to be an ε-separated sequence if, for some ε > 0, sep(xn ) = inf{kxn − xm k : n 6= m} > ε. A Banach space X is said to satisfy property (β) if and only if, for every ε > 0, there exists δ > 0 such that, for each element x ∈ B(X) and each sequence (xn ) in B(X) with sep(xn ) ≥ ε, there is an index k such that x + xk for some k ∈ N. 2 | ≥ 1 − δ, In this paper, we define the generalized Cesàro sequence space as follows: let p ∈ [1, ∞) and q be a bounded sequence of positive real numbers such that Qn = n X qk , (n ∈ N), k=0 Cesp (q) = x = (x(i)) : kxk = ∞ X n=1 !p !1/p n X 1 |qi x(i)| <∞ . Qn i=1 If qi = 1 for all i ∈ N, then Cesp (q) is reduced to Cesp (cf. [3, 8, 9]). Lemma 1.1. Let x, y ∈ Cesp (q). Then for any ε > 0 and L > 0, ∃ δ > 0 such that | kx + ykp − kxkp | < ε whenever kxkp ≤ L and kykp ≤ δ. Proof. For any fix ε > 0 and L > 0, take β = 2−p L−1 ε and δ = 2−p β p−1 ε. Then for any x, y ∈ Cesp (q) with kxkp ≤ L and kykp ≤ δ, we have ∞ n X 1 X ( |qi x(i) + qi y(i)|)p Q n n=1 i=1 !p ∞ n X qi y(i) 1 X = (1 − β)qi x(i) + β(qi x(i) + ) Qn i=1 β n=1 kx + ykp = !p n n 1 X 1 X qi y(i) ≤ (1 − β) |qi x(i)| + β |qi x(i) + | Qn i=1 Qn i=1 β n=1 !p !p ∞ n ∞ n X X 1 X 1 X qi y(i) ≤ (1 − β) |qi x(i)| + β |qi x(i) + | Qn i=1 Qn i=1 β n=1 n=1 ∞ X 3 GENERALIZED CESÀRO SEQUENCE SPACE !p n ∞ βX 1 X ≤ |qi x(i)| + Qn i=1 2 n=1 n=1 !p ∞ n βX 1 X 2qi y(i) + | | 2 n=1 Qn i=1 β ∞ X p ≤ kxk + ε/2 + (2/β) p−1 ∞ X n=1 n 1 X |2qi x(i)| Qn i=1 !p !p n 1 X |qi y(i)| Qn i=1 ≤ kxkp + ε. 2. Main Results. Theorem 2.1. The space Cesp (q) satisfies the property (β). Proof. Let Cesp (q) not have property (β). Then there exists ε0 > 0 such that, for any δ ∈ (0, ε0 /(1+21+p )), there is a sequence (xn ) ⊂ S(Cesp (q)) with sep(xn ) > 1/p ε0 and an element x0 ∈ S(Cesp (q)) such that xn + x0 p >1−δ for any n ∈ N. 2 Fix δ ∈ (0, ε0 /(1 + 21+p )). We want to show that !p ∞ n X 1 X 21+p δ lim sup (2.1.1) |qi xk (i)| ≤ p . j→∞ k Qn i=1 2 −1 n=j+1 Otherwise, without loss of generality, we can assume that there exists a sequence (jk ) such that jk → ∞ as k → ∞ and !p ∞ n X 1 X 21+p δ (2.1.2) |qi xk (i)| > p for every k ∈ N. Qn i=1 2 −1 n=j +1 k Let δ > 0 be a real number corresponding to ε = δ and L = 1 in Lemma 1. By absolute continuity of the norm of x0 , there exists a positive integer n1 such that !p ∞ n X 1 X p |qi x0 (i)| kx0 χn1 ,n1 +1,n1 +2,... k = < δ1 . Qn i=1 n=n +1 1 Choose k so large that jk > n1 . By the Lemma 1 and (2.1.2), we have !p n ∞ X 1 X qi xk (i) + qi x0 (i) 1−δ < Qn i=1 2 n=1 !p !p n1 n ∞ n X X 1 X qi xk (i)+qi x0 (i) 1 X qi xk (i) + qi x0 (i) = + Qn i=1 2 Qn i=1 2 n=n +1 n=1 1 4 V. A. KHAN !p !p n1 n n 1 X 1 X 1X |qi x0 (i)| + |qi xk (i)| Qn i=1 2 n=1 Qn i=1 !p n ∞ X 1 X qi xk (i) +δ + Qn i=1 2 n=n1 +1 !p !p n1 ∞ n n 1 1X 1 X 1 X 1 X ≤ + |qi xk (i)| + p |qi xk (i)| + δ 2 2 n=1 Qn i=1 2 n=n +1 Qn i=1 1 !p !p ∞ ∞ n n p X X 1 1 1 1 X 2 −1 X ≤ + |qi xk (i)| − |qi xk (i)| + δ 2 2 n=1 Qn i=1 2p n=n +1 Qn i=1 n1 1X ≤ 2 n=1 1 < 1 − 2δ + δ = 1 − δ. That is a contradiction. Hence (2.1.1) must hold. Since !p !p n1 n1 n X 1 X 1 X |qi xk (i)| ≤ |qi xk (i)| ≤ 1, Qn1 i=1 Qn i=1 n=1 we have |qi xk (i)| ≤ Qn1 for k ∈ N and i = 1, 2, . . . , n1 . Hence there is a subsequence (zn ) of (xn ) and a sequence (an ) of real numbers such that lim qi zk (i) = ai , k→∞ for ı = 1, 2, . . . , n1 . Therefore, n1 X n 1 X |qi zk (i) − qi zm (i)| Q n i=1 n=1 !p < δ for n,m sufficiently large. Consequently, kzk − zm kp ∞ n X 1 X ( |qi zk (i) − qi zm (i)|)p Q n n=1 i=1 !p !p n1 n ∞ n X X 1 X 1 X = |qi zk (i) − qi zm (i)| + |qi zk (i) − qi zm (i)| Qn i=1 Qn i=1 n=1 n=n1 +1 !p n1 n X 1 X ≤ |qi zk (i) − qi zm (i)| Qn i=1 n=1 !p !p ! ∞ n ∞ n X X 1 X 1 X p +2 ( |qi zk (i)| + |qi zm (i)| Qn i=1 Qn i=1 n=n +1 n=n +1 = 1 ≤δ+2 p+1 1 δ < ε0 , 1/p i.e., sep(xn ) ≤ sep(zn ) < ε0 . This is a contradiction. Therefore Cesp (q) must satisfy the property (β). 5 GENERALIZED CESÀRO SEQUENCE SPACE Theorem 2.2. C(Cesp (q)) = 21/p . Proof. Let in X K = sup{A(un ) : un = un (i)ei ∈ S(Cesp (q)), i=in−1 +1 ω 0 = i0 < i1 < i2 < . . . , un →0, . Then C(Cesp (q)) ≥ K. Moreover, for any ε > 0, there is a sequence (xn ) ⊂ ω S(Cesp (q)) with xn →0 such that A(xn ) + ε > C(Cesp (q)). By the definition of A(xn ), there exists a subsequence (yn ) of (xn ) such that kyn + ym k + 2ε > C(Cesp (q)) (2.2.1) for any n, m ∈ N with m 6= n. Take v1 = y1 . Then, by the absolute continuity of the norm of y1 , there exists i1 ∈ N such that ∞ X v1 (i)ei < ε. i=i1 +1 Putting z1 = i1 P v1 (i)ei , we have i=1 kz1 + ym k = ky1 + ym − ∞ X v1 (i)ei k ≥ ky1 + ym k − ε for any m > 1. i=i1 +1 Hence by (2.2.1), we have kz1 + ym k + 3ε > C(Cesp (q)) for any m > 1. Since yn (i) → 0 for i = 1, 2, · · · , there exists n2 ∈ N with n2 > n1 such that i 1 X yn (i)ei < ε whenever n ≥ n2 . i=1 Define v2 = yn2 . Then there is i2 > i1 such that ∞ X v2 (i)ei < ε. i=i2 +1 Taking z2 = i2 P v2 (i)ei , we obtain i=i1 +1 kz1 + z2 k = ky1 − ∞ X v1 (i)ei + yn2 − i=i1 +1 ≥ ky1 + yn2 k − 3ε. i1 X i=1 v2 (i)ei − ∞ X i=i2 +1 v2 (i)ei 6 V. A. KHAN Hence and by (2.2.1), we immediately obtain kz1 + z2 k + 5ε > C(Cesp (q)). k−1 Suppose that increasing sequences (ij )k−1 j=1 , (nj )j=1 of natural numbers and a sek−1 quence (zj )j=1 of elements of Cesp (q) are already defined and kzn + zm k + 6ε > C(Cesp (q)) for m, n ∈ {1, 2, . . . , k − 1}, m 6= n. Since yn (i) → 0 for i = 1, 2, · · · , there exists a natural number nk > nk−1 such that i k−1 X yn (i)ei < ε i=1 provided n ≥ nk . Put v = ynk . Then there is ik > ik−1 such that ∞ X vk (i)ei < ε. i=ik +1 Defining zk = ik P vk (i)ei , we obtain i=ik−1 +1 ij−1 ik−1 ∞ ∞ X X X X kzj + zk k = ynj − vj (i)ei − vj (i)ei + ynk − vk (i)ei − vk (i)ei i=1 ij+1 i=1 ik+1 ≥ kynj + ynk k − 4ε for j = 1, 2, . . . , k − 1. Hence, by (2.2.1), we obtain kzj + zk k + 6ε > C(Cesp (q)) for j = 1, 2, · · · , k − 1. Using the induction principle, we can find a sequence (zn ) satisfying the following conditions: P (1) zn = vn (i)ei , where 0 = i0 < i1 < i2 < . . . ; i=in−1 +1 (2) kzn + zm k + 6ε > C(Cesp (q)) for m, n, ∈ N, m 6= n; (3) kzn k ≤ 1 for n = 1, 2, . . .; ω (4) zn →0 as n → ∞. Define un = zn /kzn k for each n ∈ N. Then every un ∈ S(Cesp (q)) and zn zm ≥ kzn + zm k ≥ C(Cesp (q)) − 6ε kun + um k = + kzn k kzm k for any m, n ∈ N, m 6= n. By the arbitrariness of ε, we have C(Cesp (q)) = K. Let ε > 0 be given. Take nε ∈ N such that p ∞ X a < ε, Qk k=inε +1 7 GENERALIZED CESÀRO SEQUENCE SPACE where inε X a= |qi unε (i)|. i=inε −1 +1 Hence for any m > nε , we have !p k ∞ X X 1 + um k p = |qi unε (i)| + Qk i=1 i=inε −1 +1 k=im−1 +1 !p im−1 k ∞ X X 1 X |qi unε (i)| + ≥ Qk i=1 i=inε −1 +1 k=im−1 +1 !p k ∞ X 1 X = |qi unε (i)| Qk i=1 i=i +1 im−1 kunε X !p k X 1 (a + |qi um (i)| Qk i=1 !p k 1 X ( |qi um (i)| Qk i=1 nε −1 p ∞ X a − + Qk k=im−1 ∞ X k=im−1 +1 !p k 1 X ( |qi um (i)| Qk i=1 > 1 − ε + 1 = 2 − ε, i. e. A(un ) ≥ (2 − ε)) ≥ (2 − ε)1/p . On the other hand, for ε mentioned above, by Lemma 1.1, there exists δ > 0 such that k|x + ykp − kxkp | < ε whenever kxkp ≤ 1 and kykp < δ. Take nδ ∈ N such that ∞ X k=inδ +1 a p ( ) < δ, Qk and inδ X a= |qi unδ (i)|. i=inδ −1 +1 Hence for any m > nδ , we have kunδ + um kp im−1 X = i=inδ −1 +1 ∞ X ≤ i=inδ −1 +1 k 1 X |qi unδ (i)| Qk i=1 1 Qk = kunδ (i)kp + k X − k1=im−1 +1 < 2 + ε, + |qi unδ (i)| i=1 ∞ X ∞ X k=im−1 +1 !p k=im−1 +1 ∞ X !p + ∞ X k=im−1 +1 k X 1 (a + |qi um (i)|) Qk i=1 !p k 1 X |qi um (i)| Qk i=1 + kum kp k X 1 (a + |qi um (i)|) Qk i=1 !p k X 1 (a + |qi um (i)|) Qk i=1 !p !p 8 V. A. KHAN i. e. A((un )) ≤ (2 + ε)1/p . Since ε was arbitrary, we obtain C(Cesp (q)) = 21/p . Corollary 2.1. The space Cesp (q)) satisfies the Banach-Saks property . Proof. The proof follows immediately from the above Theorem 1 of [3] and Theorem 2.2. Acknowledgment. The author is grateful to Prof. Mursaleen and to the referee for their valuable suggestions. References 1. Banach S.and Saks S.; Sur la convergence forte dans les champs Lp , Studia Math. 2 (1930), 51–57. 2. Clarkson J. A., Uniformly convex spaces, Trans. Amer. Math. 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