Acta Mathematica Academiae Paedagogicae Ny´ıregyh´aziensis 22 (2006), 41–61 www.emis.de/journals ISSN 1786-0091

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Acta Mathematica Academiae Paedagogicae Nyı́regyháziensis
22 (2006), 41–61
www.emis.de/journals
ISSN 1786-0091
UNIFORM (C, α) (−1 < α < 0) SUMMABILITY OF FOURIER
SERIES WITH RESPECT TO THE WALSH–PALEY SYSTEM
V. TEVZADZE
Abstract. In the present paper we prove a number of statements dealing with
the uniform convergence of Cesàro means of negative order of the Fourier–
Walsh series.
1. Definitions and Notation
Let r0 (x) be the function defined by

£
¢
1
if x ∈ 0, 12 ,
r0 (x) =
−1 if x ∈ £ 1 , 1¢ ,
r0 (x + 1) = r0 (x).
2
The Rademacher system is defined by
rn (x) = r0 (2n x), n ≥ 1,
and x ∈ [0, 1).
Let ψ0 (x), ψ1 (x), ψ2 (x), . . . represent the Walsh functions, i.e. ψ0 (x) = 1, and if
k = 2n1 + 2n2 + · · · + 2ns is a positive integer with n1 > n2 > · · · > ns , then
ψk (x) = rn1 (x) · rn2 (x) · · · rns (x).
Denote by Knα (t) the kernel of the method (C, α) and call it the Cesàro kernel:
Knα (t) =
Aα
k =
n
1 X α
An−ν ψν (t),
Aα
n ν=0
(α + 1)(α + 2) · · · (α + k)
k!
(α 6= −k).
It is well-known ([19, Ch. 3]), that
n
X
Aα−1
(I)
Aα
=
n
n−k ;
k=0
(II)
(III)
α
α−1
Aα
;
n − An−1 = An
α
α
An ∼ n .
2000 Mathematics Subject Classification. 42C19.
Key words and phrases. Walsh system, Cesàro summability, negative order, uniform convergence, modulus of continuity, modulus of variation.
41
42
V. TEVZADZE
By C(0, 1) we denote the space of the continuous periodic functions with period
1 and norm
kf kC = max |f (x)|.
0≤x≤1
Let f ∈ C(0, 1); the modulus of continuity of function f is called the function
ω(δ, f ) = max |f (x) − f (y)|,
|x−y|≤δ
x,y∈[0,1]
0 ≤ δ ≤ 1.
A modulus of continuity is called the nonnegative function ω of the nonnegative
argument possessing the following properties:
(1)
(2)
(3)
(4)
ω(0) = 0;
ω(δ) is nondecreasing;
ω(δ) is continuous on [0, 1];
ω(δ1 + δ2 ) ≤ ω(δ1 ) + ω(δ2 ) for 0 ≤ δ1 ≤ δ2 ≤ δ1 + δ2 ≤ 1.
Given the modulus of continuity ω(δ), by H ω we denote a set of all those functions f ∈ C(0, 1) for each of which ω(δ, f ) = O(ω(δ)) as δ → 0. If, however,
α
ω(δ) = δ α (0 < α ≤ 1), then by Lip α we denote a class H δ .
Let φ be an increasing continuous function on [0, ∞), and φ(0) = 0.
By Vφ it is denoted the class of bounded on [0, 1] functions f for which
Vφ (f ) = sup
Π
n
X
φ (|f (xk ) − f (xk−1 )|) < ∞,
k=1
where Π = {0 ≤ x0 < x1 < x1 , · · · < xn ≤ 1} is an arbitrary partitioning of the
segment [0, 1].
Let M (0, 1) denote a class of bounded functions on [0, 1]. The modulus of variation of the function f ∈ M (0, 1) is called the function of an entire argument υ(n, f )
defined as follows: υ(0, f ) = 0, and for n ≥ 1
υ(n, f ) = sup
Πn
n−1
X
|f (t2k+1 ) − f (t2k )| ,
k=0
where Πn is an arbitrary system of n nonintersecting intervals (t2k , t2k+1 ) (k =
0, 1, 2, . . . , n − 1) of the segment [0, 1].
The notion of modulus of variation has been introduced by Z. Chanturia [3].
If υ(n) is nondecreasing convex upwards function and υ(0) = 0, then υ(n) is
called the modulus of variation. Given the modulus of variation υ(n), by V [υ] we
denote the class of those functions which satisfy the relation υ(n, f ) = O(υ(n)) as
n → ∞.
Next, let f ∈ C(0, 1), and σ(f ) be the Fourier–Walsh–Paley series of that function, i.e.
σ(f ) ∼
∞
X
k=0
Z1
ck ψk (x), where ck =
f (t)ψk (t) dt, k = 0, 1, 2, . . . .
0
UNIFORM (C, α) (−1 < α < 0) SUMMABILITY OF FOURIER SERIES
43
By σnα (f, x) we denote Cesàro means, or (C, α) means of the Fourier–Walsh–
Paley series of the function f , i.e.
σnα (f, x) =
n
1 X α
An−ν cν ψν (t).
Aα
n ν=0
2. Introduction
N. Fine [5] has proved that for any summable function f the means σnα (x, f )
converge almost everywhere for all α > 0, and for any continuous function σ(f ) is
uniformly (C, 1) summable to f .
In [18], S. Yano has studied the points (C, α) convergence of the summable
function f , namely: if lim f (x) = A, then σ(f ) is (C, α) summable to A at the
x→x0
point x0 (α > 0). Moreover, Yano has shown that if f (x) satisfies the Lipschitz
condition of order α (0 < α < 1), then for every β > α
|σnβ (f, x) − f (x)| = O(n−α ).
This result has been somewhat amplified by V. Kokilashvili [12], who found that
n
β
kσn−1
(f, x) − f (x)kC ≤
1X
Eν (f ),
n ν=1
β ≥ 1,
En (f ) is the best approximation of f (x) in the metric C(0, 1) with the help of
polynomials by the Walsh system.
The problems of summability of Cesàro means of positive order for Walsh–Fourier
series were studied in [8]–[7].
The questions dealing with the uniform convergence of Cesàro means of negative
order were first studied by the author, and the obtained results without proof were
published in [17].
Important results in this direction have been obtained by Goginava in [9], [10].
3. Main Results
The main results of the paper are presented in the form of the following propositions.
Theorem 1. Let ω(δ, f ) be the modulus of continuity, and let υ(n, f ) be the modulus
of variation of the function f ∈ C(0, 1).
If
)
( µ
¶X
n
m
X
1
υ(k, f )
1
,f
+
= 0, 0 < α < 1,
lim min
ω
n→∞ 1≤m≤n
n
k 1−α
k 2−α
k=1
k=m+1
then σ(f ) is uniformly (C, −α) summable to f .
Theorem 1 can be rewritten in the following equivalent form.
Theorem 2. Let ω(δ, f ) be the modulus of continuity, and let υ(n, f ) be the modulus
of variation of the function f . Then
44
V. TEVZADZE
( µ
¶ mX
0 (n)
1
1
−α
|σn (f, x) − f (x)| ≤ c(α) ω
,f
n
k 1−α
k=1
n
X
+
k=m0 (n)+1
υ(k, f ) − υ(k − 1, f )
k 1−α
)
+ o(1),
where m0 (n) = m0 is defined by the inequality
µ
¶
υ(m0 , f )
υ(m0 + 1, f )
1
0
≤ω
,f ≤
.
(1 )
m0 + 1
n
m0
If ω( n1 , f ) <
υ(n,f )
n ,
then we take m0 = n.
Let ω(δ) be an arbitrary modulus of continuity and υ(n) be an arbitrary modulus
of variation. Furthermore, let
(20 )
τ (n) = ω
µ ¶ mX
0 (n)
1
1
+
1−α
n
k
k=1
n
X
k=m0 (n)+1
υ(k) − υ(k − 1)
.
k 1−α
where m0 (n) is defined by the relation (10 ) and omitting in it the function f .
Suppose lim τ (n) = lim τ (ni ) = τ0 > 0. Then the following theorem is valid.
n→∞
i→∞
Theorem 3. In the class H ω ∩ V (υ) there exists a function f0 , such that
(30 )
lim
|f0 (0) − σ2−α
ni (f0 , 0)|
> 0.
τ (2ni )
4. Auxiliary Results
We shall need the following
Lemma 1 ([16]). Let
Knα (t) =
n
1 X α
An−ν ψν (t).
Aα
n ν=0
Then the estimate
|Kn−α (t)| ≤ c(α)
1
1
,
1−α
t
A−α
n
t ∈ (0, 1), 0 < α < 1,
holds.
Lemma 2 ([16]). For any α ∈ (0, 1) and p ≥ 2m the equality
Ã2m −1
!
X
−α
Sgn
An−ν ψν (t) = Sgn(ψ2m −1 (t)), t ∈ [0, 1),
ν=0
is valid.
Lemma 3 ([3]). If f ∈ C ∩ Vφ , where φ(u) is strictly increasing for u ∈ [0, ∞) and
φ(0) = 0, then
µ ¶
1
−1
, n ≥ 1.
υ(n, f ) ≤ c(f )nφ
n
UNIFORM (C, α) (−1 < α < 0) SUMMABILITY OF FOURIER SERIES
45
Lemma 4. If f ∈ C ∩ Vφ , where φ satisfies the conditions of Lemma 3, then the
following two conditions
µ ¶
∞
X
1
1
−1
(1)
< ∞ (0 < α < 1)
φ
−α
k
k
k=1
and
Z1
(2)
0
1
dτ < ∞
φα (τ )
(0 < α < 1)
are equivalent.
Proof. We have
(3)
m
X
k=2
1
k 1−α
φ
−1
µ ¶ Zm
µ ¶
µ ¶
m−1
X 1
1
1
1
1
−1
−1
≤
φ
dt ≤
φ
.
k
t1−α
t
k 1−α
k
k=1
1
Since
Zm
1
1
t1−α
φ
µ ¶
Z1
1
1
dt = u1−α φ−1 (u) 2 du
t
u
1
m
Z1
=
−1
φ−1
Z (1)
1
u1+α
φ−1 (u) du =
1
m
1
φ−1 ( m
)
¯φ−1 (1)
1 τ ¯¯
1
=−
+
α φα (τ ) ¯φ−1 ( 1 ) α
(4)
τ
φ0 (τ ) dτ
φ1+α (τ )
m
¯φ−1 (1)
1 τ ¯¯
1
=−
+
α φα (τ ) ¯φ−1 ( 1 ) α
m
1
= φ−1
α
µ
1
m
¶
φ−1
Z (1)
τ
φ0 (τ ) dτ
φ1+α (τ )
1
)
φ−1 ( m
φ−1
Z (1)
τ
dτ
φα (τ )
1
)
φ−1 ( m
1
1
mα − φ−1 (1) +
α
α
φ−1
Z (1)
1
dτ,
φα (τ )
1
φ−1 ( m
)
therefore if the condition (1) is fulfilled, then the condition (2) is likewise fulfilled;
and if the condition (2) is fulfilled, then
Z1
0
1
dτ ≥
α
φ (τ )
1
φ−1 ( m
)
Z
0
dτ
≥ φ−1
α
φ (τ )
µ
1
m
¶
mα
and by virtue of (3) and (4) the condition (1) is fulfilled.
¤
Lemma 5. ([15]) Let f ∈ C(0, 1), then for every α ∈ (0, 1) the estimation
¯ Z1 2k−1 −1
¯
X
¯
1 ¯¯
−α
An−ν ψν (u)[f (x+̇t) − f (x)]dt¯¯
−α ¯
An
ν=0
0
where 2k ≤ n < 2k+1 , holds.
≤
c(α)
k−1
X
r=0
µ
2
r−k
ω
1
,f
2r
¶
,
46
V. TEVZADZE
5. Proof of Main Results
Proof of Theorem 1. Represent n ≥ 1 in the form n = 2m + p, 0 ≤ p < 2m . As is
known (see [4, p. 393]),1
Z1
σn−α (f, x)
Kn−α (t)[f (x+̇t) − f (x)] dt
− f (x) =
0
=
1
A−α
n
Z1 2m−1
X−1
1
+ −α
An
(5)
=
1
A−α
n
+
ν=0
0
1
+ −α
An
A−α
n−ν ψν (t)[f (x+̇t) − f (x)] dt
Z1
m
2X
−1
m−1
0 ν=2
m
Z1 2X
+p
0
A−α
n−ν ψν (t)[f (x+̇t) − f (x)] dt
ν=2m
Z1 2m−1
X−1
1
+ −α
An
A−α
n−ν ψν (t)[f (x+̇t) − f (x)] dt
ν=0
0
1
A−α
n
A−α
n−ν ψν (t)[f (x+̇t) − f (x)] dt
Z1 2m−1
X−1
A−α
n−2m−1 −ν ψν (t)[f (x+̇t) − f (x)] dt
ν=0
0
Z1 X
p
A−α
n−2m −ν ψ2m (t)ψν (t)[f (x+̇t) − f (x)] dt
0 ν=0
= A1 + A2 + A3 .
Estimate A1 . By Lemma 5, we have
¯
¯
Z1 2m−1
X−1
¯ 1
¯
−α
¯
|A1 | = ¯ −α
An−ν ψν (t)[f (x+̇t) − f (x)] dt¯¯ ≤
A
n
≤ c(α)
ν=0
0
m−1
X
µ
2ν−m ω
ν=0
1
,f
2ν
¶
,
whence
(6)
A1 = o(1)
as
n → ∞.
1 x+̇y means that x, y is written as dyadic fractions which are combined pairwise with respect
to [mod 2].
UNIFORM (C, α) (−1 < α < 0) SUMMABILITY OF FOURIER SERIES
47
Now we proceed to estimation A2 ; first we estimate the sum
2m−1
X−1
A−α
n−2m−1 −ν ψν (t).
ν=0
We have
¯ m−1
¯
¯2 X−1
¯
¯
¯
−α
¯
An−2m−1 −ν ψν (t)¯¯
¯
¯ ν=0
¯
¯
¯
m−1
m−1
¯n−2
¯
n−2
X
¯ X
¯
−α
−α
¯
=¯
An−2m−1 −ν ψν (t) −
An−2m−1 −ν ψν (t)¯¯
¯ ν=0
¯
ν=2m−1
¯ p
¯ ¯ q
¯
¯X
¯ ¯X
¯
¯
¯ ¯
¯
≤¯
A−α
A−α
p−ν ψν (t)¯ + ¯
q−ν ψν (t)¯ ,
¯
¯ ¯
¯
ν=0
ν=0
where p = n − 2m−1 , q = n − 2m . This by virtue of Lemma 1 implies that
¯ m−1
¯
¯2
¯
¯ X−1 −α
¯
1
¯
An−2m−1 −ν ψν (t)¯¯ ≤ c(α) 1−α .
¯
t
¯ ν=0
¯
(7)
For A2 we have
1
|A2 | = −α
An
¯ 1 m−1
¯
¯Z 2
¯
X−1
¯
¯
¡
¢
−α
¯
An−2m−1 −ν ψ2m−1 (t)ψν (t) f (x+̇t) − f (x) dt¯¯
¯
¯
¯
ν=0
0
2j+1
¯ 2m−1 −1 µ Z2m
1 ¯¯ X
= −α ¯
An
j=0
2j
2m
2j+2
2m 2m−1 −1
Z
−
2j+1
2m
X
2m−1
X−1
¡
¢
A−α
n−2m−1 −ν ψν (t) f (x+̇t) − f (x) dt
ν=0
¶¯
¯
¡
¢
¯.
A−α
ψ
(t)
f
(x
+̇t)
−
f
(x)
dt
m−1
n−2
−ν ν
¯
ν=0
Taking into account the fact that the functions ψν (t) (ν = 0, 1, . . . , 2m−1 − 1)
¢
£ j
m−1
, 2j+1
− 1, we find that if
are constant in the intervals 2m−1
m−1 , j = 0, 1, . . . , 2
£ 2j 2j+1 ¢
¢
¡
¡ 2j ¢
1
t ∈ 2m , 2m , then ψν t + 2m = ψν (t) = ψν 2m , and hence
48
V. TEVZADZE
2j+1
¯ 2m−1 −1 Z2m
1 ¯¯ X
|A2 | = −α ¯
A
n
−
j=0
2m−1
X−1
2m−1
X−1
ν=0
2j
2m
A−α
n−2m−1 −ν ψν
j=0
2j+1
¯ 2m−1 −1 Z2m
1 ¯¯ X
= −α ¯
An
j=0
¡
¢
A−α
n−2m−1 −ν ψν (t) f (x+̇t) − f (x)
µ
¶µ µ
µ
¶¶
¶ ¯
¯
1
1
t+ m
f x+̇ t + m
− f (x) dt¯¯
2
2
2m−1
X−1
µ
A−α
n−2m−1 −ν ψν
¶
2m−1
ν=0
2j
2m
j
µ
µ
µ
¶¶¶ ¯
¯
1
× f (x+̇t) − f x+̇ t + m
dt¯¯
2
1
(8)
¯ 2m−1 −1 Z2m 2m−1
µ
¶
X−1
1 ¯¯ X
j
−α
= −α ¯
An−2m−1 −ν ψν
2m−1
An
ν=0
j=0
0
µ µ
µ
¶¶
µ
µ
¶¶¶ ¯
¯
2j
2j + 1
× f x+̇ t + m
− f x+̇ t +
dt¯¯
m
2
2
1
m−1
¯ 2m−1 −1
¶
µ
Z 2 X−1
1 ¯ X −m
j
= −α ¯¯
2
A−α
ψ
m−1
ν
n−2
−ν
2m−1
An
ν=0
j=0
0
µ µ
¶
µ
¶¶ ¯
¯
t + 2j
t + 2j + 1
× f x+̇ m
− f x+̇
dt¯¯
m
2
2
1 2m−1 −1
¯ 2m−1 −1
¶
µ
Z
X
1 ¯¯ X −m
j
−α
≤ −α ¯
An−2m−1 −ν ψν
2
2m−1
An
ν=0
j=1
0
µ µ
¶
µ
¶¶ ¯
¯
t + 2j
t + 2j + 1
× f x+̇ m
− f x+̇
dt¯¯
m
2
2
1
m−1
¯ Z 2 X−1
¶
µ
¶¶ ¯
µ µ
¯
¯
1
t
t+1
−f
x
+̇
dt¯¯
+ −α 2−m ¯¯
A−α
f
x
+̇
m−1
n−2
−ν
m
m
2
2
An
ν=0
0
=
(1)
A2
+
(2)
A2 .
It can be seen easily that
µ
(2)
A2
α
−m
≤ c(α)n 2
(9)
µ
≤ c(α)ω
ω
1
,f
2m
1
,f
2m
¶ 2m−1
X−1
A−α
n−2m−1 −ν
ν=0
¶
α −m m(1−α)
n 2
2
µ
≤ c(α)ω
1
,f
2m
(1)
Estimate now A2 . Applying (7), we have
(1)
A2
¶1−α
2m−1
j
j=1
0
¯µ µ
¶
µ
¶¶¯
¯
¯
t + 2j
t + 2j + 1
¯
¯ dt
× ¯ f x+̇ m
− f x+̇
¯
m
2
2
α −m
≤ c(α)n 2
Z1 2m−1
X−1 µ
¶
.
UNIFORM (C, α) (−1 < α < 0) SUMMABILITY OF FOURIER SERIES
Z1

2m−1
X−1
j 1−α
j=1
0

¯ µ
µ
¶
¶¯
¯
¯
t
+
2j
+
1
t
+
2j
¯f x+̇
¯ dt.
− f x+̇
¯
¯
2m
2m
1

≤ c(α)
49
Estimate the sum
A=
2m−1
X−1
1
j 1−α
j=1
¯ µ
¶
µ
¶¯
¯
¯
¯f x+̇ t + 2j − f x+̇ t + 2j + 1 ¯ .
¯
¯
m
m
2
2
It is evident that for every t ∈ [0, 1) there exists a y(t) ∈ [0, 1), such that
q
m
x+̇ t+q
2m = y +̇ 2m , q = 1, 2, . . . , 2 − 1.
Thus
¯
¶
µ
¶¯
2m−1
X−1 1 ¯ µ
¯
¯f y +̇ 2j − f y +̇ 2j + 1 ¯ .
A=
¯
¯
1−α
m
m
j
2
2
j=1
Using the Abelian transformation and taking into account (see [19, p. 378]) that
|(x + h) − x| ≤ h, x, h ∈ [0, 1) and (see [3, p. 536]) υ(n, f ) ≤ c(f )nω( n1 , f ), we
obtain
¯ µ
¶
µ
¶¯
s
X
1 ¯¯
2j + 1 ¯¯
2j
A=
−
f
y
+̇
+
f
y
+̇
+
¯
j 1−α ¯
2m
2m
j=1
+
2m−1
X−1
j=s+1
µ
≤ω
+
1
,f
2m
−
j 1−α
¶X
s
j=1
2m−1
X−2 µ
j=s+1
+
1
j 1−α
2
1
(s + 1)1−α
1
,f
2m
µ
ω
1
2m−1
,f
¶X
s
1
(j + 1)1−α
¶X
¶
µ
¶¯
j ¯ µ
¯
¯
¯f y +̇ 2k − f y +̇ 2k + 1 ¯
¯
¯
m
m
2
2
k=1
¯
¶
µ
¶¯
X−1 ¯ µ
¯
¯f y +̇ 2j − f y +̇ 2j + 1 ¯
¯
¯
m
m
2
2
j=1
¶
µ
¶¯
s ¯ µ
X
¯
¯
¯f y +̇ 2j − f y +̇ + 2j + 1 ¯
¯
¯
m
m
2
2
j=1
¶X
s
j=1
Since υ(n, f ) ≤ cnω
therefore
−
m−1
(2m−1 )1−α
µ
1
j 1−α
1
1
≤ω
¯ µ
¶
µ
¶¯
¯
¯
¯f y +̇ + 2j − f y +̇ + 2j + 1 ¯
¯
¯
m
m
2
2
1
j 1−α
¡1
n, f
¢
+
m−1
2X
υ(j, f ) υ(2m−1 , f )
+ m−1 1−α .
j 2−α
(2
)
j=s+1
and
υ(n,f )
n
↓ 0 due to the convexity of υ(n, f ) [3],
m−1
2X
υ(j, f )
+
1−α
j
j 2−α
j=s+1
j=1


m−1
s
2X
m−1
m−1
X
υ(2
,
f
)
υ(2
,
f
)
1
1

≥ c
2m−1
j 1−α 2m−1
j 1−α
j=1
j=s+1
1
s
≥c
υ(2m−1 , f ) X 1
υ(2m−1 , f )
≥
c
2m−1
j 1−α
(2m−1 )1−α
j=1
50
V. TEVZADZE
and hence

µ
(1)
A2 ≤ c(α) ω
1
,f
2m
¶X
s
j=1
1
+
j 1−α
2m−1
X−1
j=s+1

υ(j, f ) 
.
j 2−α
It can be easily seen that the last relation is valid for all s, 1 ≤ s ≤ n. Thus
(1)
finally, for A2 we obtain the estimate
!
à µ
¶X
s
n
X
1
1
υ(k, f )
(1)
,f
.
(10)
A2 ≤ c(α) ω
+
n
k 1−α
k 2−α
k=1
k=s+1
Analogous estimate is obtained for A3 ,
à µ
!
¶X
s
n
X
1
1
υ(k, f )
(11)
|A3 | ≤ c(α) ω
,f
+
.
n
k 1−α
k 2−α
k=1
k=s+1
Taking into account (6), (8), (9), (10) and (11), from (5) we get
(12)
|σn−α (x, f ) − f (x)|
à µ
≤ c(α) min
1≤m≤n
ω
1
,f
n
¶X
m
k=1
1
k 1−α
n
X
υ(k, f )
+
k 2−α
!
+ o(1),
k=m+1
where o(1) is the value tending to zero as n → ∞.
This implies that Theorem 1 is valid.
¤
From Theorem 1 we can obtain a number of corollaries.
Corollary 1. If ω(δ, f ) = O(δ α ) (0 < α < 1), then σ(f ) is uniformly (C, −α)
summable to f .
Corollary 2. If f ∈ C ∩ V [υ], and
∞
X
υ(k)
< ∞,
k 2−α
0 < α < 1,
k=1
then σ(f ) is uniformly (C, −α) summable to f .
Corollary 3. If f ∈ C ∩Vφ , where φ(u) is strictly increasing convex for u ∈ [0, ∞),
φ(0) = 0, and
µ ¶
∞
X
1
1
−1
φ
< ∞, 0 < α < 1,
k 1−α
k
k=1
then σ(f ) is uniformly (C, −α) summable to f .
Indeed, in the conditions of Corollary 3, by Lemma 3, the relation
µ ¶
1
−1
u(n, f ) ≤ c(f ) nφ
, n ≥ 1,
n
is valid, and hence
nφ−1 ( n1 )
υ(n, f )
1
≤
c(f
)
= c(f ) 1−α φ−1
n2−α
n2−α
n
from which, by virtue of Corollary 2, follows Corollary 3.
µ ¶
1
n
UNIFORM (C, α) (−1 < α < 0) SUMMABILITY OF FOURIER SERIES
51
Corollary 4. If f ∈ C ∩ Vφ , where φ satisfies the conditions of Corollary 3, and
Z1
(13)
0
1
φα (τ )
dτ < ∞,
0 < α < 1,
then σ(f ) is uniformly (C, −α) summable to f .
Corollary 4 follows directly from Corollary 3 by using Lemma 4.
Corollary 5. If f ∈ C(0, 1), m = min f (t), M = max f (t), and the Banach
0≤t≤1
0≤t≤1
indicatrix2 N (y, f ) satisfies the condition
ZM
N α (y, f ) dy < ∞,
0 < α < 1,
m
then σ(f ) is uniformly (C, −α) summable to f .
This corollary follows from Theorem 1 by virtue of the results of [1].
Corollary 6. Let f ∈ C ∩Vφ , where φ(u) is a strictly increasing on [0, ∞) function,
φ(0) = 0, and (13) is fulfilled, then
1
ω( n
,f )
Z
|σn−α (f, x)
− f (x)| ≤ c(α)
0
Vφ (f )
dτ + o(1),
φα (τ )
where Vφ (f ) is a full φ variation of the function f on [0, 1].
Corollary 6 follows from Theorem 1 by virtue of the results obtained in [3].
Proof of Theorem 2. Let m0 < n such that
!
à µ
¶X
m
n
X
1
1
υ(k, f )
min
ω
,f
+
1≤m≤n
n
k 1−α
k 2−α
k=1
k=m+1
(14)
µ
¶X
m0
n
X
1
1
υ(k, f )
=ω
,f
+
,
n
k 1−α
k 2−α
k=1
Then
¶X
µ
m0
1
1
,f
+
ω
1−α
n
k
k=1
n
X
k=m0 +1
k=m0 +1
υ(k, f )
≤ω
k 2−α
µ
1
,f
n
¶ mX
0 −1
k=1
1
k 1−α
+
n
X
υ(k, f )
k 2−α
k=m0
and
µ
ω
1
,f
n
¶X
m0
k=1
1
k 1−α
+
n
X
k=m0 +1
υ(k, f )
≤ω
k 2−α
µ
1
,f
n
¶ mX
0 +2
k=1
1
k 1−α
+
n
X
k=m0 +1
υ(k, f )
.
k 2−α
The above inequalities imply that
µ
¶
µ
¶
υ(m0 , f )
υ(m0 + 1, f )
1
1
1
1
≤
,
ω
,f
≤
ω
,
f
,
2−α
2−α
n
(m
+
1)
n
(m
+
1)1−α
m1−α
m
0
0
0
0
2The Banach indicatrix N (y, f ) is a number (finite or infinite) of solutions of the equation
f (x) = y.
52
V. TEVZADZE
whence
υ(m0 + 1, f )
≤ω
m0 + 1
(15)
µ
1
,f
n
¶
≤
υ(m0 , f )
.
m0
)
Because of the fact that υ(n,f
is strictly decreasing (see [3, p. 544]) starting
n
from some n0 , then for n ≥ n0 the m0 (n) from the relation (15) is defined uniquely.
If, however, the minimum in the left-hand side of (14) is attained for m0 = n, we
have one relation
µ
¶
1
υ(m0 , f )
ω
,f ≤
.
n
m0
Using now the Abelian transformation, we get
n
X
k=m0 +1
υ(k, f ) − υ(k − 1, f )
=
k 1−α
+
(16)
k=m0 +1
k=m0 +1
1
k 1−α
υ(n, f )
υ(m0 , f )
−
≥ c(α)
1−α
n
(m0 + 1)1−α
whence
n
X
µ
n−1
X
υ(k, f )
≤ c(α)
k 2−α
−
1
(k + 1)1−α
n−1
X
k=m0 +1
¶
υ(k, f )
υ(k, f )
υ(m0 , f )
−
,
2−α
k
(m0 + 1)1−α
Ã
n
X
υ(k, f ) − υ(k − 1, f )
υ(m0 , f )
+
1−α
1−α
k
(m
0 + 1)
n=m +1
!
,
0
and since
υ(m0 , f )
υ(m0 + 1, f )
≤
(m0 + 1)α ≤ 2ω
1−α
(m0 + 1)
m0 + 1
µ
1
,f
n
¶
mα
0,
taking into account (12) and (16), we obtain
kσn−α (f )
¶X
½ µ
m
1
1
,f
− f kC ≤ c(α) ω
1−α
n
k
k=1
+
n
X
k=m0 +1
υ(k, f ) − υ(k − 1, f )
k 1−α
Thus Theorem 2 is proved.
¾
+ o(1),
¤
To prove Theorem 3 we will need some lemmas.
Lemma 6. If υ(n) = o(n1−α ), υ(n) → ∞, as n → ∞, and υ(n) is convex,
then there exists the sequence of natural numbers {ϕ(n)} possessing the following
properties:
(a) ϕ(n) = o(n) as n → ∞;
n
X
υ(k) − υ(k − 1)
= o(1) as n → ∞.
(b)
k 1−α
k=ϕ(n)+1
Proof. Suppose
µ
¶
υ(m) − υ(m − 1)
1
ϕ(n) = max m :
≥
m1−α
n
Because υ(n) is convex, υ(k) − υ(k − 1) ↓, and since
ϕ(n) ↑ ∞.
υ(k)−υ(k−1)
k1−α
↓ 0, therefore
UNIFORM (C, α) (−1 < α < 0) SUMMABILITY OF FOURIER SERIES
53
From the definition of ϕ(n) it follows that
υ(ϕ(n)) − υ(ϕ(n) − 1)
1
υ(ϕ(n) + 1) − υ(ϕ(n))
1
≥
and
< .
ϕ1−α (n)
n
(ϕ(n) + 1)1−α
n
(17)
Therefore
ϕ1−α (n)
υ(ϕ(n))
≤ υ(ϕ(n)) − υ(ϕ(n) − 1) ≤
,
n
ϕ(n)
whence
υ(ϕ(n))
ϕ(n)
≤ 1−α
= o(1).
n
ϕ
(n)
By virtue of (17) we have
n
X
υ(k) − υ(k − 1)
≤ (υ(ϕ(n) + 1) − υ(ϕ(n)))
k 1−α
k=ϕ(n)+1
≤ c(α)
(ϕ(n) + 1)
n
1−α
n
X
1
k 1−α
k=ϕ(n)+1
nα ≤ c(α)
ϕ1−α (n)
= o(1).
n1−α
Thus the lemma is proved.
¤
Lemma 7. Let
m
K2−α
m (t)
2
1 X −α
= −α
A m ψν (t),
A2m ν=0 2 −ν
0 < α < 1.
There exists a natural number N such that for i < m − N the estimate
2i
Z2m
iα
|K2−α
m (t)| dt ≥ c(α)2
2i−1
2m
is valid for sufficiently large m.
Proof. We have
2i
2i
Z2m
|K2−α
m (t)|dt ≥
2i−1
2m
1
A−α
2m
m
¯
Z2m ¯ 2X
¯ −1 −α
¯
¯
A2m −ν (t)ψν (t)¯¯dt
¯
2i−1
2m
ν=0
2i
−
(18)
1
A−α
2m
Z2m
|A−α
0 (t)ψ2m (t)|dt
2i−1
2m
2i
=
1
A2−α
m
m
¯
Z2m ¯ 2X
¯ −1 −α
¯
1 2i−1
¯
¯
= A1 − A2 .
A
m −ν (t)ψν (t) dt −
2
¯
¯
m
A−α
2m 2
ν=0
2i−1
2m
Here we present lower bound of A1 . By Lemma 2, we have
2i
1
A1 = −α
A2 m
m
¯
Z2m ¯ 2X
¯ −1 −α
¯
¯
A2m −ν (t)ψν (t)¯¯dt
¯
2i−1
2m
ν=0
54
V. TEVZADZE
2i
=
1
A−α
2m
m
Z2m µ 2X
−1
¶
m
(t)ψ
(t)ψ
(t)
dt
A−α
ν
2 −1
2m −ν
ν=0
2i−1
2m
k+1
m
i
m
¶
2X
−1 Z2 µ 2X
−1
1
−α
= −α
A2m −ν (t)ψν (t)ψ2m −1 (t) dt
A2m k=2i−1
ν=0
k
2m
=
1
A−α
2m
m
2X
−1
k+1
A−α
2m −ν
m
i
µ 2X
−1 Z2
ν=0
k=2i−1
k
2m
µ 2X
2 −1
−1
³ k ´
³ k ´¶
1
1 X −α
m
A
ψ
ψ
,
m
ν
2 −1
2 −ν
m
2m
2m
A−α
2m 2
ν=0
k=2i−1
m
=
¶
ψν (t)ψ2m −1 (t)dt
i
from which it follows that since (see [2, p. 17])
µ ¶
³ ν ´
k
, ν, k = 0, 1, 2, . . . ,
ψk m = ψν
2
2m
and ([4, p. 379])
µ
¶
³ ν ´ µ 2m − 1 ¶
ν 2m − 1
+̇
ψk
=
ψ
ψk
,
k
2m
2m
2m
2m
ν, k = 1, 2, . . . , 2m − 1,
we get

 i
2m −1
2 −1
³ ν ´ µ 2m − 1 ¶
1
1 X −α  X

A1 = −α m
Am
ψk m ψk
2
2m
A2m 2 ν=0 2 −ν k=2i−1
 i

µ
¶
2m −1
2 −1
1
1 X −α  X
ν 2m − 1 
= −α m
Am
+̇ m
ψk
2m
2
A2m 2 ν=0 2 −ν
i−1
k=2
=
1
A−α
2m
¶
µ
¶¸
·
µ
2 −1
ν 2m − 1
1 X −α
ν 2m − 1
Am
+̇ m
− D2i−1
+̇ m
.
D 2i
2m ν=0 2 −ν
2m
2
2m
2
m
Since (see [4])

2m ,
D2m (t) =
0,
(19)
0 ≤ t < 2−m ,
2−m ≤ t < 1,
where Dn (t) =
n−1
X
ψk (t),
k=0
therefore for ν < 2m−1 + · · · + 2m−i+1 we will have
µ
¶
µ
¶
ν 2m − 1
ν 2m − 1
D2i
+̇ m
= 0, D2i−1
+̇ m
=0
2m
2
2m
2
and hence
A1 =
µ
µ
¶
ν 2m − 1
i
D
+̇
A−α
2
2m −ν
2m
2m
ν=pi +qi +1
µ
¶¶
ν 2m − 1
− D2i−1
+̇ m
2m
2
µ
µ
¶
µ
¶¶ ¾
pX
i +qi
ν 2m − 1
ν 2m − 1
−α
+
A2m −ν D2i
+̇ m
− D2i−1
+̇ m
,
2m
2
2m
2
ν=p
1
1
m
2
A−α
m
2
½
m
2X
−1
i
UNIFORM (C, α) (−1 < α < 0) SUMMABILITY OF FOURIER SERIES
55
where pi = 2m−1 + 2m−2 + · · · + 2m−i+1 = 2m − 2m−i+1 , qi = 2m−i+1 + 2m−i+2 +
· · · + 21 + 20 = 2m−i − 1.
α−1
α
Taking again into account (19) and equalities Aα
, we obtain
k − Ak−1 = Ak


m
2m X
−2m−i
2X
−1
1 2i−1 
−α

A−α
A1 = −α m
A2m −ν −
2m −ν
A2m 2
ν=2m −2m−i+1
ν=2m −2m−i
 m−i

m−i
2 X−1
2X
i−1
1 2

= −α m 
A−α
A−α
2m−i −ν −
2m−i+1 −ν
A2m 2
ν=0
ν=0
(20)
−1 2i−1
= −α m
A2m 2
¾
+
A−α
2m−i
½ 2m−i
X−1
−α−1
−α−1
(A−α−1
2m−i −ν A2m−i +1−ν + · · · + A2m−i+1 −ν )
ν=0
1 2i−1
= − −α m
A2m 2
m−i
2m−i
X−1 2X
ν=0
A−α−1
2m−i +k−ν
k=0
i−1
1 2
− −α m A−α
2m−i = B1 + B2 .
A2m 2
Estimate now B1 . By virtue of (III) we have
(21)
mα
≥ c(α)2
2m−i
X−1
2i−1
2m
|B1 | ≥ c(α)(2m )α
ν=0
m−i 1−α
(2
(2m−i − ν)−α
)
≥ c0 (α)2iα .
For B2 we have
|B2 | ≤ c(α)2mα
(22)
2i
2i−1
≤
c(α)
.
2m
2m(1−α)
Similar estimate is obtained for A2 . That is,
(23)
A2 ≤ c(α)
2i
2m(1−α)
.
Taking into account (20), (21), (22) and (23), from (18) we obtain
2i
Z2m
iα
|K2−α
− c1 (α)
m (t)| dt ≥ c0 (α)2
2i
2m(1−α)
.
2i−1
2m
Since 2−(m−i)(1−α) → 0 as (m − i) → ∞, there exists a natural number N such
that
2i
c0 (α) iα
c1 (α) m(1−α) <
2 for i < m − N,
2
2
and therefore
2i
Z2m
|K2−α
m (t)| dt ≥
c0 (α) iα
2 ,
2
i < m − N.
2i−1
2m
Thus the lemma is proved.
¤
56
V. TEVZADZE
Proof of Theorem 3. Let τ (n) be defined by the relation (20 ), where m0 (n) for
n > n0 is defined uniquely by inequality (15) by omitting the function f .
Next, let {ni } ⊂ N such that lim τ (2ni ) = τ0 > 0.
i→∞
Without restriction of generality we can assume (see [3, p. 1545]) that υ(n) is
convex, and υ(n) ≤ cnω( n1 ). There can take place two cases: (1) υ(n) = o(n1−α );
(2) υ(n) 6= o(n1−α ).
Let us consider the case υ(n) = o(n1−α ). Suppose that υ(n) → ∞ because
τ (n) → 0 as n → ∞, otherwise. By Lemma 6, there exists the sequence of natural
numbers {ϕ(n)} with the properties indicated in the lemma. Note that if υ(n) =
o(n1−α ) as n → ∞, then
(24)
ω
µ ¶ mX
0 (n)
1
1
→ 0,
1−α
n
k
n → ∞.
k=1
Indeed,
ω
µ ¶ mX
0 (n)
1
υ(m0 (n)) α
1
≤ c(α)
m0 (n)
1−α
n
k
m0 (n)
k=1
= c(α)
υ(m0 (n))
= o(1),
m1−α
(n)
0
n → ∞.
Therefore by virtue of the fact that lim τ (2ni ) = τ0 > 0, starting from some i0
ϕ(2ni ) > m0 (2ni ).
Taking into account (24) and also the properties of the sequence {ϕ(n)}, we find
that


(2ni )
2n i
 µ 1 ¶ m0X
X
1
υ(k) − υ(k − 1) 
+
lim ω
i→∞ 

2ni
k 1−α
k 1−α
n
k=1
µ
= lim ω
i→∞
1
2ni
¶ m0X
(2
ni
)
+ lim
i→∞
ni
2
X
+ lim
i→∞
k=ϕ(2ni )+1
ϕ(2ni )
X
= lim
i→∞
i )+1
ϕ(2ni )
1
k 1−α
k=1
(25)
k=m0 (2
k=m0 (2ni )+1
X
k=m0 (2ni )+1
υ(k) − υ(k − 1)
k 1−α
υ(k) − υ(k − 1)
k 1−α
υ(k) − υ(k − 1)
= τ0 .
k 1−α
Suppose
ξ(n) =
2q(n)+4
X
k=2r(n)+3
υ(k) − υ(k − 1)
,
k 1−α
where r(n) = [log2 m0 (n)], q(n) = [log2 ϕ(n)].
Now we construct the sequence of natural numbers {`k } and the sequence of
functions {fk }.
Let `1 ∈ {ni } such that `1 > ni0 , and `1 > n0 (see the definition of n0 and i0 ),
`1
)
≤ 1.
2`1 − ϕ(2`1 ) > N (N appears in Lemma 7) and 4ϕ(2
2` 1
UNIFORM (C, α) (−1 < α < 0) SUMMABILITY OF FOURIER SERIES
57
The function ϕ1 (x) is defined as follows:


`1

υ(r + 1) − υ(r) for x = 22r+1
), . . . , 4ϕ(2`1 ) − 1,
`1 +2 , r = m0 (2




0
for x = 2`1r+1 , r = m0 (2`1 ), . . . , 4ϕ(2`1 ),
ϕ1 (x) =
£
¤
£
`1 ¤
`1
)
)


0
for x ∈ 0, m02(2
,1
∪ 4ϕ(2
`1
`1

2



is linear and continuous for the rest x from [0, 1].
Assume
f1 (x) = ϕ1 (x) Sgn K2−α
`1 (x).
Let the numbers `1 , `2 , . . . , `k−1 and periodic with period 1 functions f1 , f2 , . . . , fk−1
be already constructed. Then `k and fk can be constructed as follows: we choose
`k in such a way that the following conditions be fulfilled:
(1) `k > `k−1 ;
(2) `k ∈ {ni };
`k
`k −1
)
)
(3) 4ϕ(2
< m02(2
(ϕ(n) = o(n));
`
`k −1
¡2 k1 ¢
(4) ω 2`k ≤ υ(4ϕ(2`k −1 )) − υ(4ϕ(2`k −1 ) − 1);
(5) m0 (2`k ) > ϕ(2`k −1 );
¡ ¢
`k−1
) ≤ c1 (α)ξ(`k−1 );
(6) ω 21`k mα
0 (2
(7)
k−1
P
ω
i=1
¡
1
2`i
¢
1
ω(
`i
ϕ(2 )
R2`k
0
)
1
τα
dτ < c2 (α)ξ(2`k )
(the constants c1 (α) and c2 (α) will be chosen below).
Let

2r+1

`
`

υ(r + 1) − υ(r) for x = 2`k +2 , r = m0 (2 k ), . . . , 4ϕ(2 k ) − 1,



0 for x = r , r = m (2`k ), . . . , 4ϕ(2`k ),
0
2`k +1
ϕk (x) =
£ m0 (2`k ) ¤ £ 4ϕ(2`k ) ¤


0 for x ∈ 0, 2`k
∪
,1

2` k



is linear and continuous for the rest x from [0, 1].
Assume
fk (x) = ϕk (x) Sgn K2−α
`k (x).
Let now
f0 (x) =
∞
X
fk (x)
k=1
Reasoning just as in [3, p. 548], we can show that f0 ∈ H ω ∩ V [υ]. It remains to
prove the relation (30 ).
Suppose
∞
X
fi (x).
Fk (x) =
i=k+1
Taking into account the definition of the function fk (x) and Lemma 1, we obtain
¯ 1
¯
¯Z
¯
¯
¯
−α
¯
¯
|σ2−α
(F
,
0)
−
F
(0)|
=
F
(t)K
(t)dt
k
k
k
`k
¯
¯
2`k
¯
¯
0
58
V. TEVZADZE
≤ kFk kC
1
A−α
2` k
m0 (2`k )
2`k
Z
µ
1
dt ≤ c(α) ω
t1−α
0
¶
¶α
m0 (2`k )
2`k +1
2`k
¶
µ
1
`k
≤ c0 (α)ω
mα
0 (2 ).
2`k +1
1
µ
2`k α
By virtue of the property (6) of the sequence {`k }, we get
`k
|σ2−α
),
`k (Fk , 0)| ≤ c0 (α)c1 (α)ξ(2
(26)
Further, using Lemma 7 and the definition of fk (x), we can write
¯
¯
¯
−α
|σ2`k (fk , 0) − fk (0)| = ¯
¯
4ϕ(2`k )
2`k
¯
¯
Z
¯
fk (t)K2−α
`k (t)dt¯
m0 (2`k )
2` k
`k )+2
2q(2
2` k
4ϕ(2`k )
2`k
Z
Z
ϕk (t)|K2−α
`k (t)|dt ≥
=
m0 (2`k )
2`k
(27)
`
2r(2 k )+1
2`k
q(2`k )+1
≥
ϕk (t)|K2−α
`k (t)|dt
X
2i+1
2`k
Z
ϕk (t)|K2−α
`k (t)|dt
i=r(2`k )+1
2i
2`k
q(2`k )+1
X
≥ c(α)
[υ(2i+2 + 1) − υ(2i+2 )]2iα
i=r(2`k )+1
`k
)+4
2q(2
X
≥ c3 (α)
i=2r(2
`k )+3
υ(i) − υ(i − 1)
= c3 (α)ξ(2`k )
i1−α
+1
since
`k
)+4
2q(2
X
`k )+3
i=2r(2
υ(i) − υ(i − 1)
≤ c(α)
i1−α
+1
`k
)+4
2q(2
X
q(2`k )+1
= c(α)
`k )+3
i=2r(2
X
i+3
2X
i=r(2`k )+1 j=2i+2
υ(i + 1) − υ(i)
i1−α
υ(j + 1) − υ(j)
j 1−α
q(2`k )+1
X
≤ c(α)
[υ(2i+2 + 1) − υ(2i+2 )]2iα .
i=r(2`k )+1
Estimate now σ2−α
`k (gk , 0), where gk (t) =
k
P
i=1
fi (t).
Since gk (t) ∈ H ω ∩ V , using Corollary 6, we find that
ω(
1
Z2`k
|σ2−α
`k (gk , 0)| ≤ c(α)
0
)
V (gk )
dτ + o(1).
τα
UNIFORM (C, α) (−1 < α < 0) SUMMABILITY OF FOURIER SERIES
It is easy to see that
V (gk ) ≤ 2
k−1
X
µ
1
2`i
ω
i=1
59
¶
ϕ(2`i ),
and therefore
|σ2−α
`k (gk , 0)| ≤ c1 (α)
k−1
X
i=1
µ
ω
1
2`i
ω(
¶
1
Z2`k
ϕ(2`i )
0
)
1
dτ + o(1).
τα
Taking into account the property (7) of the sequence {ϕ(n)}, we have
(28)
`k
|σ2−α
) + o(1).
`k (gk , 0)| ≤ c4 (α)c2 (α)ξ(2
It follows from (26), (27) and (28) that
−α
−α
−α
|σ2−α
`k (f0 , 0) − f0 (0)| = |σ `k (fk , 0) + σ `k (gk , 0) + σ `k (Fk , 0)|
2
2
2
−α
−α
≥ |σ2−α
`k (fk , 0)| − |σ2`k (Fk , 0)| − |σ2`k (gk , 0)|
≥ c3 (α)ξ(2`k ) − x0 (α)c1 (α)ξ(2`k ) − c4 (α)c2 (α)ξ(2`k ) − o(1).
Choosing now c1 (α) =
c3 (α)
3c0 (α) ,
c2 (α) =
c3 (α)
3c4 (α) ,
|σ2−α
`k (f0 , 0) − f0 (0)| ≥
whence
we get
c3 (α)ξ(2`k )
− o(1),
3
|σ2−α
c3 (α)
o(1)
`k (f0 , 0) − f0 (0)|
≥
−
`
k
ξ(2 )
3
ξ(2`k )
and since ξ(2`k ) ∼ τ (2`k ) by virtue of (25), from the last relation we obtain (30 ).
Consider now case 2), i.e. υ(n) 6= o(n1−α ). We define the function υ1 (x) as
follows:



υ(n) for x = n, n ∈ N,


υ1 (x) = 0 for x = 0,



is linear and continuous for the rest x from [0, ∞).
Let
ω1 (δ) = δυ1
µ ¶
1
.
δ
It is easily seen that ω1 (δ) is the modulus of continuity, and since υ(n) ≤ cnω( n1 ),
therefore ω1 (δ) ≤ cω(δ). By S. Stechkin’s lemma, there exists the convex modulus
of continuity ω0 (δ) satisfying the condition
c1 ω0 (δ) < ω1 (δ) < c2 ω0 (δ),
and since υ1 (n) = υ(n), we have H ω0 ⊂ H ω ∩ V [υ].
By virtue of the fact that υ(n) 6= o(n1−α ), it follows that ω0 (δ) 6= o(δ α ) (0 <
α < 1). Let us now show that in the class H ω0 there exists the function f0 whose
Fourier–Walsh–Paley series fails to be summable by the method (C, −α) to f0 at
the point x = 0.
60
V. TEVZADZE
By the condition ω0 (δ) 6= o(δ α ), there exists the sequence {ni } ⊂ N, such that
µ
¶
1
ω
2ni α ≥ c > 0, i = 1, 2, . . . .
2ni
We choose from {ni } the sequence with the following properties:
∞
¡ ¢
¡ ¢
P
ω 21`i ≤ 2ω 21`k ;
1)
i=k+1 ³
´
¡ ¢
¡ ¢
1
2) 2`k+1 ω 2`k+1
> 2 · 2`k ω 21`k since 2`k ω 21`k → ∞;
³ k−1
¡ ¢
P ¡ 1 ¢ `i ´α ¡ 1 ¢
3)
ω 2`i 2
ω 2`k ≤ c0 (α)ω 21`k 2`k α (c0 (α) depends on our choice).
Let
i=1
 ¡ ¢

`k +1

for x = 22r+1
− 1,
ω 1
`k +2 , r = 0, 1, , . . . , 2

 2`k
r
`
+1
ϕk (t) = 0 for x = `k +1 , r = 0, 1, , . . . , 2 k ,
2



is linear and continuous for the rest x from [0, 1].
Suppose
f0 (x) =
∞
X
ϕk (t) Sgn K2−α
`k (t).
k=1
Reasoning analogously as in case 1), we can show that f0 is the unknown function.
Thus Theorem 3 is proved.
¤
From Theorems 1 and 3 follows
Theorem 4. For the Fourier–Walsh–Paley series of all functions of the class
H ω ∩ V [υ] to be (C, −α) uniformly summable, it is necessary and sufficient that
the condition
½ µ ¶X
¾
m
n
X
1
1
υ(k)
lim min
ω
+
=0
n→∞ 1≤m≤n
n
k 1−α
k 2−α
k=1
k=m+1
be fulfilled.
Theorem 5. For the Fourier–Walsh–Paley series of all functions of the class
C ∩ V [υ] to be uniformly (C, −α) summable, it is necessary and sufficient that
the condition
∞
X
υ(k)
(29)
< ∞. 0 < α < 1,
k 2−α
k=1
be fulfilled.
Proof. The sufficiency of the condition (29) is contained in Theorem 4, and the
necessity can be proved by using [3] (see [3, p. 552]).
¤
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Received September 26, 2005.
Department of Mechanics and Mathematics,
Tbilisi State University,
Chavchavadze str. 1, Tbilisi 0128,
Georgia
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