Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2013, Article ID 701087, 10 pages http://dx.doi.org/10.1155/2013/701087 Research Article Periodic Solution for Impulsive Cellar Neural Networks with Time-Varying Delays in the Leakage Terms Bingwen Liu1 and Shuhua Gong2 1 2 College of Mathematics and Computer Science, Hunan University of Arts and Science, Changde, Hunan 415000, China College of Mathematics, Physics and Information Engineering, Jiaxing University, Jiaxing, Zhejiang 314001, China Correspondence should be addressed to Shuhua Gong; shuhuagong@yahoo.cn Received 29 January 2013; Accepted 12 March 2013 Academic Editor: Chuangxia Huang Copyright © 2013 B. Liu and S. Gong. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. This paper is concerned with impulsive cellular neural networks with time-varying delays in leakage terms. Without assuming bounded and monotone conditions on activation functions, we establish sufficient conditions on existence and exponential stability of periodic solutions by using Lyapunov functional method and differential inequality techniques. Our results are complement to some recent ones. 1. Introduction It is well known that impulsive differential equations are mathematical apparatus for simulation of process and phenomena observed in control theory, physics, chemistry, population dynamics, biotechnologies, industrial robotics, economics, and so forth [1–3]. Thus, many neural networks with impulses have been studied extensively, and a great deal of literature is focused on the existence and stability of an equilibrium point [4–7]. In [8–10], the authors discussed the existence and global exponential stability of periodic solution of a class of cellular neural networks (CNNs) with impulse. Recently, Wang et al. [11] considered the following CNNs with impulses and leakage delays: π π₯πσΈ (π‘) = −ππ π₯π (π‘ − ππ ) + ∑ πΌππ (π‘) ππ (π₯π (π‘)) π=1 π + ∑π½ππ (π‘) ππ (π₯π (π‘ − πππ )) + πΌπ (π‘) , π=1 π‘ ≥ 0, (1) π‘ =ΜΈ π‘π , Δπ₯π (π‘π ) = π₯π (π‘π+ ) − π₯π (π‘π− ) = πππ π₯π (π‘π ) , where Δπ₯π (π‘π ) are the impulses at moments π‘π and π‘1 < π‘2 < ⋅ ⋅ ⋅ is a strictly increasing sequence such that limπ → ∞ π‘π = +∞; ππ > 0 and ππ > 0 are constants, and πΌππ (π‘), πΌπ (π‘), and π½ππ (π‘) are continuous periodic functions with period π. Suppose that the following conditions are satisfied. π (π΄ 1 ) There exist constants πΏ π , π = 1, 2, . . . π, such that, for any πΌ, π½ ∈ π , 0< ππ (πΌ) − ππ (π½) πΌ−π½ π < πΏπ , πΌ =ΜΈ π½, π = 1, 2, . . . π. (2) (π΄ 2 ) ππ (0) = 0 and for π = 1, 2, . . . , π, there exists a constant 0 < ππ < +∞, such that σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ππ (πΌ)σ΅¨σ΅¨σ΅¨ ≤ ππ , πΌ ∈ π . (3) By using the continuation theorem of coincidence degree theory and a suitable degenerate Lyapunov-Krasovskii functional together with model transformation technique, some results were obtained in [11] to guarantee that all solutions of system (1) converge exponentially to a periodic function. However, to the best of our knowledge, few authors have considered the existence and stability of periodic solutions of system (1) without the assumptions (π΄ 1 ) and (π΄ 2 ). Thus, it is worthwhile to continue to investigate the convergence behavior of system (1) in this case. In view of the fact that the coefficients and delays in neural networks are usually time varying in the real world, motivated by the above discussions, 2 Abstract and Applied Analysis in this paper, we will consider the problem on periodic solution of the following impulsive CNNs with time-varying delays in the leakage terms: π=1 π‘ ≥ 0, (4) π‘ =ΜΈ π‘π , in which π corresponds to the number of units in a neural network, π₯π (π‘) corresponds to the state vector of the πth unit at the time π‘, and ππ (π‘) represents the rate with which the πth unit will reset its potential to the resting state in isolation when disconnected from the network and external inputs at the time π‘. πππ (π‘) and πππ (π‘) are the connection weights at the time π‘, ππ (π‘) and πππ (π‘) denote the transmission delays, πΌπ (π‘) denotes the external bias on the πth unit at the time π‘, ππ and ππ are activation functions of signal transmission, Δπ₯π (π‘π ) are the impulses at moments π‘π , and 0 ≤ π‘1 < π‘2 < ⋅ ⋅ ⋅ is a strictly increasing sequence such that limπ → ∞ π‘π = +∞, and π, π = 1, 2, . . . , π. It is obvious that when π = π and ππ (π‘) is a constant function, (1) is a special case of (4). The main purpose of this paper is to give the conditions for the existence and exponential stability of the periodic solutions for system (4). By applying Lyapunov functional method and differential inequality techniques, without assuming (π΄ 1 ) and (π΄ 2 ), we derive some new sufficient conditions ensuring the existence, uniqueness, and exponential stability of the periodic solution for system (4), which are new and complement previously known results. Moreover, an example is also provided to illustrate the effectiveness of our results. Throughout this paper, we assume that the following conditions hold. (π»1 ) For π, π = 1, 2, . . . , π, πΌπ , πππ , πππ : π → π and ππ , ππ , πππ : π → π + are continuous periodic functions with period π > 0, and π‘ − ππ (π‘) ≥ 0 for all π‘ ≥ 0. In addition, there exist constants ππ+ , ππ+ , πΌπ+ , ππ , πππ+ , πππ+ , and πππ+ such that π‘∈π πΌπ+ σ΅¨ σ΅¨ = sup σ΅¨σ΅¨σ΅¨πΌπ (π‘)σ΅¨σ΅¨σ΅¨ , π‘∈π σ΅¨ σ΅¨ πππ+ = sup σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ , π‘∈π ππ+ = supππ (π‘) , π‘∈π πππ+ σ΅¨ σ΅¨ = sup σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ , π‘∈π πππ+ = supπππ (π‘) , (π ∈ π+ ) . (6) σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ππ (π’) − ππ (V)σ΅¨σ΅¨σ΅¨ ≤ πΏππ |π’ − V| , σ΅¨ σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ππ (π’) − ππ (V)σ΅¨σ΅¨σ΅¨ ≤ πΏππ |π’ − V| . σ΅¨ σ΅¨ (7) (π»5 ) For all π‘ > 0 and π ∈ {1, 2, . . . , π}, there exist constants ππ > 0 and π > 0 such that Δπ₯π (π‘π ) = π₯π (π‘π+ ) − π₯π (π‘π− ) = πππ π₯π (π‘π ) , ππ+ = supππ (π‘) , π‘π+π = π‘π + π, ππ (0) = ππ (0) = 0, π π=1 ππ(π+π) = πππ , (π»4 ) For each π ∈ {1, 2, . . . , π}, there exist nonnegative π π constants πΏ π and πΏ π such that, for all π’, V ∈ π , π π₯πσΈ (π‘) = −ππ (π‘) π₯π (π‘ − ππ (π‘)) + ∑πππ (π‘) ππ (π₯π (π‘)) + ∑ πππ (π‘) ππ (π₯π (π‘ − πππ (π‘))) + πΌπ (π‘) , (π»3 ) There exists a π ∈ π+ such that (5) π‘∈π ππ = max {ππ+ , max πππ+ } . π=1,2,...,π (π»2 ) The sequence of times π‘π (π ∈ π) satisfies π‘π < π‘π+1 and limπ → +∞ π‘π = +∞, and πππ satisfies −2 ≤ πππ ≤ 0 for π ∈ {1, 2, . . . , π} and π ∈ π+ , where π+ denotes the set of all positive integers. −π > − [ππ (π‘) − ππ (π‘) ππ (π‘) ππ+ ] ππ π σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ + ππ (π‘) ππ (π‘) πππ+ ) πΏ π ππ π=1 (8) π σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ + ππ (π‘) ππ (π‘) πππ+ ) πΏ π ππ . π=1 For convenience, let π₯ = (π₯1 , π₯2 , . . . , π₯π )π ∈ π π , in which “π” denotes the transposition. We define |π₯| = (|π₯1 |, |π₯2 |, . . . , |π₯π |)π and βπ₯β = max1≤π≤π {|π₯π |}. As usual in the theory of impulsive differential equations, at the points of discontinuity π‘π of the solution π‘ σ³¨→ (π₯1 (π‘), π₯2 (π‘), . . . , π₯π (π‘))π , we assume that (π₯1 (π‘), π₯2 (π‘), . . . , π₯π (π‘))π ≡ (π₯1 (π‘ − 0), π₯2 (π‘ − 0), . . . , π₯π (π‘ − 0))π . It is clearly that, in general, the derivative π₯πσΈ (π‘π ) does not exist. On the other hand, according to system (4), there exists the limit π₯πσΈ (π‘π β 0). In view of the above convention, we assume that π₯πσΈ (π‘π ) ≡ π₯πσΈ (π‘π − 0). The initial conditions associated with (4) are assumed to be of the form π₯π (π ) = ππ (π ) , π ∈ [−ππ , 0] , π = 1, 2, . . . , π, (9) where ππ (⋅) denotes a real-valued continuous function defined on [−ππ , 0]. 2. Preliminary Results The following lemmas will be used to prove our main results in Section 3. Lemma 1. Let (H1 )–(H5 ) hold. Suppose that π₯(π‘) = (π₯1 (π‘), π₯2 (π‘), . . . , π₯π (π‘))π is a solution of system (1) with the initial conditions πΎ σ΅¨ σ΅¨ π₯π (π ) = ππ (π ) , σ΅¨σ΅¨σ΅¨ππ (π )σ΅¨σ΅¨σ΅¨ < ππ , π ∈ [−ππ , 0] , (10) π where πΎ = 1 + maxπ=1,2,...,π {[ππ+ ππ+ + 1]πΌπ+ }, π = 1, 2, . . . , π. Then πΎ σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨π₯π (π‘)σ΅¨σ΅¨σ΅¨ < ππ , π ∀π‘ ≥ 0, π = 1, 2, . . . , π. (11) Proof. Assume that (11) does not hold. From (π»2 ), we have σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ + σ΅¨ (12) σ΅¨σ΅¨π₯π (π‘π )σ΅¨σ΅¨σ΅¨ = σ΅¨σ΅¨σ΅¨(1 + πππ )σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨π₯π (π‘π )σ΅¨σ΅¨σ΅¨ ≤ σ΅¨σ΅¨σ΅¨π₯π (π‘π )σ΅¨σ΅¨σ΅¨ . Abstract and Applied Analysis 3 So, if |π₯π (π‘π+ )| > πΎ, then |π₯π (π‘π )| > πΎ. Thus, we may assume that there exist π ∈ {1, 2, . . . , π} and π‘∗ ∈ (π‘π , π‘π+1 ) such that πΎ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨π₯π (π‘∗ )σ΅¨σ΅¨σ΅¨ = ππ , π ∀π‘ ∈ [−ππ , π‘∗ ) , πΎ σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨π₯π (π‘)σ΅¨σ΅¨σ΅¨ < ππ σ΅¨ σ΅¨ π σ΅¨ σ΅¨ = −ππ (π‘∗ ) σ΅¨σ΅¨σ΅¨π₯π (π‘∗ )σ΅¨σ΅¨σ΅¨ + ππ (π‘∗ ) σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ − π (π ) π₯ (π − π (π )) π π σ΅¨σ΅¨ π π‘∗ −ππ (π‘∗ ) σ΅¨σ΅¨ σ΅¨ π‘∗ ×∫ π (13) + ∑πππ (π ) ππ (π₯π (π )) π = 1, 2, . . . , π. π=1 π + ∑πππ (π ) ππ (π₯π (π − πππ (π ))) According to (4), we get π=1 σ΅¨σ΅¨ σ΅¨σ΅¨ +πΌπ (π ) σ΅¨σ΅¨σ΅¨σ΅¨ ππ σ΅¨σ΅¨ σ΅¨ π σ΅¨σ΅¨ σ΅¨ + ∑ σ΅¨σ΅¨σ΅¨πππ (π‘∗ ) ππ (π₯π (π‘∗ ))σ΅¨σ΅¨σ΅¨σ΅¨ π π₯πσΈ (π‘) = −ππ (π‘) π₯π (π‘ − ππ (π‘)) + ∑πππ (π‘) ππ (π₯π (π‘)) π=1 π π=1 + ∑ πππ (π‘) ππ (π₯π (π‘ − πππ (π‘))) + πΌπ (π‘) π σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ + ∑ σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘∗ )σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨σ΅¨ππ (π₯π (π‘∗ − πππ (π‘∗ )))σ΅¨σ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨πΌπ (π‘∗ )σ΅¨σ΅¨σ΅¨ π=1 π=1 = −ππ (π‘) π₯π (π‘) + ππ (π‘) [π₯π (π‘) − π₯π (π‘ − ππ (π‘))] σ΅¨ σ΅¨ ≤ − [ππ (π‘∗ ) − ππ (π‘∗ ) ππ (π‘∗ ) ππ+ ] σ΅¨σ΅¨σ΅¨π₯π (π‘∗ )σ΅¨σ΅¨σ΅¨ π + ∑ πππ (π‘) ππ (π₯π (π‘)) π=1 π + ∑ πππ (π‘) ππ (π₯π (π‘ − πππ (π‘))) + πΌπ (π‘) (14) π=1 = −ππ (π‘) π₯π (π‘) + ππ (π‘) ∫ π‘ π‘−ππ (π‘) π₯πσΈ (π ) ππ π { = { − [ππ (π‘∗ ) − ππ (π‘∗ ) ππ (π‘∗ ) ππ+ ] ππ { π σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘∗ )σ΅¨σ΅¨σ΅¨σ΅¨ + ππ (π‘∗ ) ππ (π‘∗ ) πππ+ ) πΏ π ππ π=1 π + ∑ πππ (π‘) ππ (π₯π (π‘ − πππ (π‘))) + πΌπ (π‘) , π=1 π‘ =ΜΈ π‘π , π=1 π = 1, 2, . . . , π. Calculating the upper left derivative of |π₯π (π‘)|, together with (13), (14), (π»5 ), and πΎ> [ππ+ ππ+ + π σ΅¨ σ΅¨ π πΎ + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘∗ )σ΅¨σ΅¨σ΅¨σ΅¨ + ππ (π‘∗ ) ππ (π‘∗ ) πππ+ ) πΏ π ππ π π=1 + [ππ+ ππ+ + 1] πΌπ+ + ∑ πππ (π‘) ππ (π₯π (π‘)) π‘ > 0, π σ΅¨ σ΅¨ π πΎ + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘∗ )σ΅¨σ΅¨σ΅¨σ΅¨ + ππ (π‘∗ ) ππ (π‘∗ ) πππ+ ) πΏ π ππ π π=1 1] πΌπ+ , (15) π σ΅¨ σ΅¨ π } πΎ + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘∗ )σ΅¨σ΅¨σ΅¨σ΅¨ + ππ (π‘∗ ) ππ (π‘∗ ) πππ+ ) πΏ π ππ } π π=1 } + [ππ+ ππ+ + 1] πΌπ+ πΎ < −π + [ππ+ ππ+ + 1] πΌπ+ π < 0. we obtain (16) σ΅¨ σ΅¨ 0 ≤ π·− σ΅¨σ΅¨σ΅¨π₯π (π‘∗ )σ΅¨σ΅¨σ΅¨ π‘ σ΅¨σ΅¨ σΈ σ΅¨σ΅¨ σ΅¨σ΅¨π₯π (π )σ΅¨σ΅¨ ππ σ΅¨ σ΅¨ π‘∗ −ππ (π‘∗ ) ∗ σ΅¨ σ΅¨ ≤ −ππ (π‘∗ ) σ΅¨σ΅¨σ΅¨π₯π (π‘∗ )σ΅¨σ΅¨σ΅¨ + ππ (π‘∗ ) ∫ π σ΅¨ σ΅¨ + ∑ σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘∗ ) ππ (π₯π (π‘∗ ))σ΅¨σ΅¨σ΅¨σ΅¨ π=1 π σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ + ∑ σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘∗ )σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨σ΅¨ππ (π₯π (π‘∗ − πππ (π‘∗ )))σ΅¨σ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨πΌπ (π‘∗ )σ΅¨σ΅¨σ΅¨ π=1 It is a contradiction and shows that (11) holds. The proof is now completed. Remark 2. After the conditions (π»1 )–(π»5 ), the solution of system (4) always exists (see [1, 2]). In view of the boundedness of this solution, from the theory of impulsive differential equations in [1], it follows that the solution of system (4) with initial conditions (10) can be defined on [0, +∞). Lemma 3. Suppose that (H1 )–(H5 ) are true. Let π₯∗ (π‘) = (π₯1∗ (π‘), π₯2∗ (π‘), . . . , π₯π∗ (π‘))π be the solution of system (4) with 4 Abstract and Applied Analysis initial value π∗ = (π1∗ (π‘), π2∗ (π‘), . . . , ππ∗ (π‘))π , and let π₯(π‘) = (π₯1 (π‘), π₯2 (π‘), . . . , π₯π (π‘))π be the solution of system (4) with initial value π = (π1 (π‘), π2 (π‘), . . . , ππ (π‘))π . Then, there exists a positive constant π such that π₯π (π‘) − π₯π∗ (π‘) = π (π−ππ‘ ) , π = 1, 2, . . . , π. which, together with the continuity of Γπ (π), implies that we can choose two positive constants π and π such that −π > Γπ (π) = − [ππ (π‘) ππππ (π‘) − π (17) + −ππ (π‘) ππππ (π‘) ππ (π‘) (π + ππ+ ππππ )] ππ ∗ Proof. Let π¦(π‘) = π₯(π‘) − π₯ (π‘). Then, for π ∈ {1, 2, . . . , π}, it is followed by π σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ + πππ+ ππ (π‘) ππππ (π‘) ππ (π‘)) πΏ π ππ π=1 π¦πσΈ (π‘) = −ππ (π‘) (π₯π (π‘ − ππ (π‘)) − π₯π∗ (π‘ − ππ (π‘))) π + ∑πππ (π‘) [ππ (π₯π (π‘)) − π=1 ππ (π₯π∗ π σ΅¨ σ΅¨ + ∑ ( σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ πππππ (π‘) + πππ+ ππ (π‘) ππππ (π‘) (π‘))] π=1 π + + ∑πππ (π‘) [ππ (π₯π (π‘ − πππ (π‘))) (18) π=1 −ππ (π₯π∗ (π‘ − πππ (π‘)))] , π‘ ≥ 0, π¦π (π‘π+ ) = (1 + πππ ) π¦π (π‘π ) , π × ππ (π‘) πππππ ) πΏ π ππ , π‘ ≥ 0, π = 1, 2, . . . , π. (21) Let π‘ =ΜΈ π‘π , ππ (π‘) = π¦π (π‘) πππ‘ , π = 1, 2, . . . . π = 1, 2, . . . , π. (22) Then Define continuous functions Γπ (π) by setting ππσΈ (π‘) = πππ (π‘) − ππ (π‘) πππ‘ π¦π (π‘ − ππ (π‘)) Γπ (π) = − [ππ (π‘) ππππ (π‘) − π {π + πππ‘ { ∑πππ (π‘) [ππ (π₯π (π‘)) − ππ (π₯π∗ (π‘))] {π=1 + −ππ (π‘) ππππ (π‘) ππ (π‘) (π + ππ+ ππππ )] ππ π π σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ + πππ+ ππ (π‘) ππππ (π‘) ππ (π‘)) πΏ π ππ π=1 + ∑πππ (π‘) [ππ (π₯π (π‘ − πππ (π‘))) (19) π σ΅¨ σ΅¨ + ∑ ( σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ πππππ (π‘) π=1 } −ππ (π₯π∗ (π‘ − πππ (π‘)))] } } π=1 + π +πππ+ ππ (π‘) ππππ (π‘) ππ (π‘) πππππ ) πΏ π ππ , π ≥ 0, π‘ ≥ 0, = πππ (π‘) − ππ (π‘) ππππ (π‘) ππ (π‘) π = 1, 2, . . . , π. + ππ (π‘) ππππ (π‘) [ππ (π‘) − ππ (π‘ − ππ (π‘))] Then Γπ (0) = − [ππ (π‘) − {π + πππ‘ { ∑πππ (π‘) [ππ (π₯π (π‘)) − ππ (π₯π∗ (π‘))] {π=1 ππ (π‘) ππ (π‘) ππ+ ] ππ π σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ + πππ+ ππ (π‘) ππ (π‘)) πΏ π ππ π=1 π σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ + πππ+ ππ (π‘) ππ (π‘)) πΏ π ππ π=1 < −π, π‘ ≥ 0, π = 1, 2, . . . , π, π (20) + ∑πππ (π‘) [ππ (π₯π (π‘ − πππ (π‘))) π=1 } −ππ (π₯π∗ (π‘ − πππ (π‘)))] } } Abstract and Applied Analysis 5 = πππ (π‘) − ππ (π‘) ππππ (π‘) ππ (π‘) + ππ (π‘) ππππ (π‘) ∫ π‘ π‘−ππ (π‘) Let πΎ be a positive number such that ππσΈ (π ) ππ σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ππ (π‘)σ΅¨σ΅¨σ΅¨ ≤ π < πΎππ π { + πππ‘ { ∑πππ (π‘) [ππ (π₯π (π‘)) − ππ (π₯π∗ (π‘))] {π=1 ∀π‘ ∈ [−ππ , 0] , π = 1, 2, . . . , π. (26) We claim that π + ∑πππ (π‘) [ππ (π₯π (π‘ − πππ (π‘))) π=1 −ππ (π₯π∗ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ππ (π‘)σ΅¨σ΅¨σ΅¨ < πΎππ , } (π‘ − πππ (π‘)))] } } = πππ (π‘) − ππ (π‘) ππππ (π‘) ππ (π‘) + ππ (π‘) ππππ (π‘) (27) Obviously, (27) holds for π‘ = 0. We first prove that (27) is true for 0 < π‘ ≤ π‘1 . Otherwise, there exist π ∈ {1, 2, . . . , π} and π ∈ (0, π‘1 ] such that one of the following two cases must occur; { πππ (π ) − ππ (π ) πππ π¦π (π − ππ (π )) { π‘−ππ (π‘) { ×∫ ∀π‘ > 0, π = 1, 2, . . . , π. π‘ π + πππ ∑ πππ (π ) [ππ (π₯π (π )) − ππ (π₯π∗ (π ))] (1) ππ (π) = πΎππ , π=1 ∀π‘ ∈ [0, π) , π + πππ ∑ πππ (π ) [ππ (π₯π (π − πππ (π ))) π=1 (2) ππ (π) = −πΎππ , } −ππ (π₯π∗ (π − πππ (π )))]}ππ } {π + πππ‘ { ∑πππ (π‘) [ππ (π₯π (π‘)) − ππ (π₯π∗ (π‘))] {π=1 ∀π‘ ∈ [0, π) , σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ππ (π‘)σ΅¨σ΅¨σ΅¨ < πΎππ σ΅¨ σ΅¨ π = 1, 2, . . . , π, σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ππ (π‘)σ΅¨σ΅¨σ΅¨ < πΎππ σ΅¨ σ΅¨ (28) (29) π = 1, 2, . . . , π. Now, we distinguish two cases to finish the proof. Case (i). If (28) holds. Then, from (21), (23), and (π»1 )– (π»5 ), we have π + ∑πππ (π‘) [ππ (π₯π (π‘ − πππ (π‘))) π=1 } −ππ (π₯π∗ (π‘ − πππ (π‘)))] } , } π‘ =ΜΈ π‘π , σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ + σ΅¨ σ΅¨σ΅¨ππ (π‘π )σ΅¨σ΅¨σ΅¨ = σ΅¨σ΅¨σ΅¨1 + πππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨ππ (π‘π )σ΅¨σ΅¨σ΅¨ , 0 ≤ ππσΈ (π) = πππ (π) − ππ (π) ππππ (π) ππ (π) + ππ (π) ππππ (π) π = 1, 2, . . . , π, (23) π = 1, 2, . . . , π. (24) { ππ {πππ (π ) − ππ (π ) π π¦π (π − ππ (π )) π−ππ (π) { ×∫ π π + πππ ∑πππ (π ) [ππ (π₯π (π )) − ππ (π₯π∗ (π ))] π=1 We define a positive constant π as follows: π + πππ ∑πππ (π ) [ππ (π₯π (π − πππ (π ))) π=1 { σ΅¨ σ΅¨} π = max { sup σ΅¨σ΅¨σ΅¨ππ (π )σ΅¨σ΅¨σ΅¨} . 1≤π≤π } {π ∈[−ππ , 0] (25) } −ππ (π₯π∗ (π − πππ (π )))] } ππ } 6 Abstract and Applied Analysis Case (ii). If (29) holds. Then, from (21), (23), and (π»1 )– (π»5 ), we get {π + πππ { ∑πππ (π) [ππ (π₯π (π)) − ππ (π₯π∗ (π))] {π=1 π 0 ≥ ππσΈ (π) + ∑ πππ (π) [ππ (π₯π (π − πππ (π))) π=1 = πππ (π) − ππ (π) ππππ (π) ππ (π) + ππ (π) ππππ (π) } −ππ (π₯π∗ (π − πππ (π)))] } } { πππ (π ) − ππ (π ) πππ π¦π (π − ππ (π )) { π−ππ (π) { ×∫ ≤ πππ (π) − ππ (π) ππππ (π) ππ (π) + ππ (π) ππππ (π) π π + πππ ∑πππ (π ) [ππ (π₯π (π )) − ππ (π₯π∗ (π ))] { σ΅¨ + πππ (π ) σ΅¨σ΅¨ σ΅¨σ΅¨ππ (π − ππ (π ))σ΅¨σ΅¨σ΅¨ {πππ (π ) + ππ π π−ππ (π) { π σ΅¨ πσ΅¨ + ∑ πππ+ πΏ π σ΅¨σ΅¨σ΅¨σ΅¨ππ (π )σ΅¨σ΅¨σ΅¨σ΅¨ ×∫ π π=1 π + πππ ∑πππ (π ) [ππ (π₯π (π − πππ (π ))) π=1 } −ππ (π₯π∗ (π − πππ (π )))] } ππ } π=1 π σ΅¨ σ΅¨} π + ∑πππ+ πΏ π πππππ (π ) σ΅¨σ΅¨σ΅¨σ΅¨ππ (π − πππ (π ))σ΅¨σ΅¨σ΅¨σ΅¨} ππ π=1 } π σ΅¨σ΅¨ σ΅¨σ΅¨ π σ΅¨σ΅¨ σ΅¨σ΅¨ + ∑ σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨ πΏ π σ΅¨σ΅¨σ΅¨ππ (π)σ΅¨σ΅¨σ΅¨ {π + πππ { ∑πππ (π) [ππ (π₯π (π)) − ππ (π₯π∗ (π))] {π=1 π π=1 + ∑ πππ (π) [ππ (π₯π (π − πππ (π))) π σ΅¨ σ΅¨ σ΅¨ π σ΅¨ + ∑ σ΅¨σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨σ΅¨ πΏ π πππππ (π) σ΅¨σ΅¨σ΅¨σ΅¨ππ (π − πππ (π))σ΅¨σ΅¨σ΅¨σ΅¨ π=1 } −ππ (π₯π∗ (π − πππ (π)))] } } π=1 ≤ − [ππ (π) ππππ (π) − π − ππ (π) ππππ (π) ππ (π) × (π + ≥ πππ (π) − ππ (π) ππππ (π) ππ (π) + ππ (π) ππππ (π) + ππ+ ππππ )] πΎππ { σ΅¨ + πππ (π ) σ΅¨σ΅¨ σ΅¨σ΅¨ππ (π − ππ (π ))σ΅¨σ΅¨σ΅¨ {πππ (π ) − ππ π π−ππ (π) { π σ΅¨ πσ΅¨ − ∑ πππ+ πΏ π σ΅¨σ΅¨σ΅¨σ΅¨ππ (π )σ΅¨σ΅¨σ΅¨σ΅¨ ×∫ π σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨σ΅¨ + πππ+ ππ (π) ππππ (π) ππ (π)) πΏ π πΎππ π=1 π σ΅¨ σ΅¨ + ∑ ( σ΅¨σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨σ΅¨ πππππ (π) + πππ+ ππ (π) ππππ (π) π=1 π=1 ππππ+ π σ΅¨} σ΅¨ π − ∑πππ+ πΏ π πππππ (π ) σ΅¨σ΅¨σ΅¨σ΅¨ππ (π − πππ (π ))σ΅¨σ΅¨σ΅¨σ΅¨} ππ π=1 } π σ΅¨σ΅¨ σ΅¨σ΅¨ π σ΅¨σ΅¨ σ΅¨σ΅¨ − ∑ σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨ πΏ π σ΅¨σ΅¨σ΅¨ππ (π)σ΅¨σ΅¨σ΅¨ π ) πΏ π πΎππ × ππ (π) π π { = { − [ππ (π) ππππ (π) − π − ππ (π) ππππ (π) ππ (π) { π=1 π σ΅¨ σ΅¨ σ΅¨ π σ΅¨ − ∑ σ΅¨σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨σ΅¨ πΏ π πππππ (π) σ΅¨σ΅¨σ΅¨σ΅¨ππ (π − πππ (π))σ΅¨σ΅¨σ΅¨σ΅¨ + × (π + ππ+ ππππ )] ππ π=1 ≥ − [ππ (π) ππππ (π) − π − ππ (π) ππππ (π) ππ (π) π σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨σ΅¨ + πππ+ ππ (π) ππππ (π) ππ (π)) πΏ π ππ π=1 + × (π + ππ+ ππππ )] (−πΎππ ) π σ΅¨ σ΅¨ + ∑ ( σ΅¨σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨σ΅¨ πππππ (π) + πππ+ ππ (π) ππππ (π) π σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨σ΅¨ + πππ+ ππ (π) ππππ (π) ππ (π)) πΏ π (−πΎππ ) π=1 ππππ+ × ππ (π) π < −ππΎ < 0. π=1 π } ) πΏ π ππ } πΎ π σ΅¨ σ΅¨ + ∑ ( σ΅¨σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨σ΅¨ πππππ (π) + πππ+ ππ (π) ππππ (π) } π=1 + (30) π × ππ (π) πππππ ) πΏ π (−πΎππ ) Abstract and Applied Analysis 7 solution π₯(π‘) can be defined for all π‘ ∈ [0, +∞). By hypothesis (π»1 ), we have, for any natural number β, { = { − [ππ (π) ππππ (π) − π − ππ (π) ππππ (π) { + × ππ (π) (π + ππ+ ππππ ) ] ππ [π₯π (π‘ + (β + 1) π)] π σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨σ΅¨ + πππ+ ππ (π) ππππ (π) ππ (π)) πΏ π ππ = −ππ (π‘) π₯π (π‘ + (β + 1) π − ππ (π‘)) π π=1 + ∑ πππ (π‘) ππ (π₯π (π‘ + (β + 1) π)) π σ΅¨ σ΅¨ + ∑ ( σ΅¨σ΅¨σ΅¨σ΅¨πππ (π)σ΅¨σ΅¨σ΅¨σ΅¨ πππππ (π) + πππ+ ππ (π) ππππ (π) π=1 + ∑ πππ (π‘) ππ (π₯π (π‘ + (β + 1) π − πππ (π‘))) π=1 + π } × ππ (π) πππππ ) πΏ π ππ } (−πΎ) } + πΌπ (π‘) , > ππΎ > 0. (31) Therefore, (27) holds for π‘ ∈ [0, π‘1 ]. From (24) and (27), we know that (32) ∀π‘ ∈ [π‘1 , π‘2 ] , π = 1, 2, . . . , π. (33) + π₯π ((π‘π + (β + 1) π) ) (37) = (1 + ππ(π+(β+1)π) ) π₯π (π‘π+(β+1)π ) ∀π‘ > 0, π = 1, 2, . . . , π. (34) ∀π‘ > 0, π = 1, 2, . . . , π. (35) That is, Remark 4. If π₯∗ (π‘) = (π₯1∗ (π‘), π₯2∗ (π‘), . . . , π₯π∗ (π‘))π is the π-periodic solution of system (4), it follows from Lemma 3 that π₯∗ (π‘) is globally exponentially stable. 3. Main Results In this section, we will study existence and exponential stability for periodic solutions of system (4). Theorem 5. Suppose that all conditions in Lemma 3 are satisfied. Then system (4) has exactly one π-periodic solution π₯∗ (π‘). Moreover, π₯∗ (π‘) is globally exponentially stable. Proof. Let π₯(π‘) = (π₯1 (π‘), π₯2 (π‘), . . . , π₯π (π‘))π be a solution of system (4) with initial conditions (10). By Remark 2, the π = 1, 2, . . . . Thus, for any natural number β, we obtain that π₯(π‘ + (β + 1)π) is a solution of system (4) for all π‘ + (β + 1)π ≥ 0. Hence, π₯(π‘ + π) is also a solution of (4) with initial values π ∈ [−ππ , 0] , π = 1, 2, . . . , π. π₯π (π + π) , Further, we have σ΅¨ σ΅¨σ΅¨ ∗ −ππ‘ σ΅¨σ΅¨π₯π (π‘) − π₯π (π‘)σ΅¨σ΅¨σ΅¨ ≤ πΎππ π , Further, by hypothesis of (π»3 ), we obtain = (1 + πππ ) π₯π (π‘π + (β + 1) π) , Thus, for π‘ ∈ [π‘1 , π‘2 ], we may repeat the above procedure and obtain σ΅¨ σ΅¨ σ΅¨ ππ‘ σ΅¨σ΅¨ σ΅¨σ΅¨ππ (π‘)σ΅¨σ΅¨σ΅¨ = σ΅¨σ΅¨σ΅¨π¦π (π‘)σ΅¨σ΅¨σ΅¨ π < πΎππ , π‘ =ΜΈ π‘π , π = 1, 2, . . . , π. + ) = π₯π (π‘π+(β+1)π π = 1, 2, . . . , π. σ΅¨ σ΅¨ σ΅¨ ππ‘ σ΅¨σ΅¨ σ΅¨σ΅¨ππ (π‘)σ΅¨σ΅¨σ΅¨ = σ΅¨σ΅¨σ΅¨π¦π (π‘)σ΅¨σ΅¨σ΅¨ π < πΎππ , (36) π π=1 σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ ππ‘ σ΅¨σ΅¨ππ (π‘1 )σ΅¨σ΅¨σ΅¨ = σ΅¨σ΅¨σ΅¨π¦π (π‘1 )σ΅¨σ΅¨σ΅¨ π 1 < πΎππ , π = 1, 2, . . . , π, σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨σ΅¨ + σ΅¨ σ΅¨σ΅¨ππ (π‘1 )σ΅¨σ΅¨σ΅¨ = σ΅¨σ΅¨σ΅¨1 + ππ1 σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨ππ (π‘1 )σ΅¨σ΅¨σ΅¨ ≤ σ΅¨σ΅¨σ΅¨ππ (π‘1 )σ΅¨σ΅¨σ΅¨ < πΎππ , σΈ (38) Then, by the proof of Lemma 3, there exists a constant πΎ > 0 such that for any natural number β, σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨π₯π (π‘ + (β + 1) π) − π₯π (π‘ + βπ)σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ = σ΅¨σ΅¨σ΅¨π₯π (π‘ + βπ + π) − π₯π (π‘ + βπ)σ΅¨σ΅¨σ΅¨ ≤ πΎππ π−π(π‘+βπ) = πΎππ π−ππ‘ ( 1 πππ π‘ =ΜΈ π‘π , β ) , π‘ + βπ ≥ 0, π = 1, 2, . . . , π, σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨π₯π ((π‘π + (β + 1) π)+ ) − π₯π ((π‘π + βπ)+ )σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨σ΅¨ σ΅¨ = (1 + πππ ) σ΅¨σ΅¨π₯π (π‘π + (β + 1) π) − π₯π (π‘π + βπ)σ΅¨σ΅¨σ΅¨ ≤ πΎππ π−π(π‘π +βπ) = πΎππ π−ππ‘π ( 1 β ) , πππ ∀π ∈ π+ , π = 1, 2, . . . , π. (39) 8 Abstract and Applied Analysis Moreover, for any natural number π, we can obtain 4. An Example π₯π (π‘ + (π + 1) π) In this section, we give an example to demonstrate the results obtained in the previous sections. π = π₯π (π‘) + ∑ [π₯π (π‘ + (β + 1) π) − π₯π (π‘ + βπ)] , Example 6. Consider the following impulsive cellar neural network consisting of two neurons with time-varying delays in the leakage terms, which is described by β=0 π‘ + βπ ≥ 0, π‘ =ΜΈ π‘π , π = 1, 2, . . . , π, + (π₯π ((π‘π + (π + 1) π) )) (40) π + = π₯π (π‘) + ∑ [π₯π ((π‘π + (β + 1) π) ) π₯1σΈ (π‘) = −3 (|sin ππ‘| + 1) π₯1 (π‘ − β=0 + − (π₯π ((π‘π + βπ) ))] , ∀π ∈ π+ , π = 1, 2, . . . , π. Combining (39) with (40), we know that π₯(π‘ + ππ) will converge uniformly to a piecewise continuous function π₯∗ (π‘) = (π₯1∗ (π‘), π₯2∗ (π‘), . . . , π₯π∗ (π‘))π on any compact set of π . Now we are in the position of proving that π₯∗ (π‘) is a π-periodic solution of system (4). It is easily known that π₯∗ (π‘) is π-periodic since π₯π∗ (π‘ + π) = lim π₯π (π‘ + π + ππ) π+1 → +∞ = π₯π∗ (π‘) , π‘ =ΜΈ π‘π , + + 1 sin2 ππ‘π2 (π₯2 (π‘)) 16 + 1 sin2 ππ‘π1 (π₯1 (π‘ − cos2 ππ‘)) 16 + 1 sin2 ππ‘π2 (π₯2 (π‘ − 2sin2 ππ‘)) 16 π‘ =ΜΈ 2π − 1, (41) + π → +∞ π = 1, 2, . . . , where π = 1, 2, . . . , π. Noting that the right side of (4) is piecewise continuous, together with (36) and (37), we know that {π₯πσΈ (π‘ + (π + 1)π)} converges uniformly to a piecewise continuous function on any compact set of π \ {π‘1 , π‘2 , . . .}. Therefore, letting π → +∞ on both sides of (36) and (37), we get + 1 sin3 ππ‘π2 (π₯2 (π‘)) 16 + 1 sin3 ππ‘π1 (π₯1 (π‘ − cos2 ππ‘)) 16 + 1 sin3 ππ‘π2 (π₯2 (π‘ − 2sin2 ππ‘)) 16 + 100 sin ππ‘ σΈ ππ(2π ) = −2, π (43) π‘ =ΜΈ 2π − 1, π₯π (π‘π+ ) = (1 + πππ ) π₯π (π‘π ) , π₯π∗ (π‘) = −ππ (π‘) π₯π∗ (π‘ − ππ (π‘)) π‘π = π, + ∑πππ (π‘) ππ (π₯π∗ (π‘)) sin4 ππ‘ ) 1000 1 + cos3 ππ‘π1 (π₯1 (π‘)) 16 π₯π∗ ((π‘π + π) ) = lim π₯π ((π‘π + π + ππ) ) = π₯π∗ (π‘π+ ) , 1 cos2 ππ‘π1 (π₯1 (π‘)) 16 + 100 cos ππ‘ π₯π (π‘ + (π + 1) π) lim + π₯2σΈ (π‘) = −3 (|cos ππ‘| + 1) π₯1 (π‘ − π → +∞ = sin2 ππ‘ ) 1000 π = 1, 2, ππ(2π −1) = −1, π, π = 1, 2, . . . . π=1 + π Here, it is assumed that the activation functions are ∑πππ (π‘) ππ (π₯π∗ π=1 + πΌπ (π‘) , (π‘ − πππ (π‘))) (42) π1 (π₯) = π2 (π₯) = π₯ + 2 sin π₯, π‘ =ΜΈ π‘π , π = 1, 2, . . . , π, π1 (π₯) = π2 (π₯) = π₯ + 3 sin π₯. π₯π∗ (π‘π+ ) = (1 + πππ ) π₯π∗ (π‘π ) , π = 1, 2, . . . , π = 1, 2, . . . , π. Thus, π₯∗ (π‘) = (π₯1∗ (π‘), π₯2∗ (π‘), . . . , π₯π∗ (π‘))π is a π-periodic solution of system (4). Finally, by Lemma 3, we can prove that π₯∗ (π‘) is globally exponentially stable. This completes the proof. Noting that π1 (π‘) = sin2 ππ‘ , 1000 π1 (π‘) = 3 (|sin ππ‘| + 1) , π2 (π‘) = sin4 ππ‘ , 1000 π2 (π‘) = 3 (|cos ππ‘| + 1) , (44) Abstract and Applied Analysis 9 π11 (π‘) = 1 cos2 ππ‘, 16 π12 (π‘) = 1 sin2 ππ‘, 16 π11 (π‘) = 1 sin2 ππ‘, 16 π12 (π‘) = 1 sin2 ππ‘, 16 π21 (π‘) = 1 cos3 ππ‘, 16 π22 (π‘) = 1 sin3 ππ‘, 16 1 π21 (π‘) = sin3 ππ‘, 16 of China (Grants nos. 11C0916 and 11C0915), the Natural Scientific Research Fund of Zhejiang Provincial of China (Grant no. LY12A01018), and the Natural Scientific Research Fund of Zhejiang Provincial Education Department of China (Grant no. Z201122436). References 1 π22 (π‘) = sin3 ππ‘, 16 π11 (π‘) = π21 (π‘) = cos2 ππ‘, π12 (π‘) = π22 (π‘) = 2sin2 ππ‘, (45) then we obtain − [ππ (π‘) − ππ (π‘) ππ (π‘) ππ+ ] ππ 2 σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ + ππ (π‘) ππ (π‘) πππ+ ) πΏ π ππ π=1 2 σ΅¨ σ΅¨ π + ∑ (σ΅¨σ΅¨σ΅¨σ΅¨πππ (π‘)σ΅¨σ΅¨σ΅¨σ΅¨ + ππ (π‘) ππ (π‘) πππ+ ) πΏ π ππ π=1 < − (3 − 6 × 1 × 6) 1000 + 2( 1 1 1 +6× × )×3 16 1000 16 + 2( 1 1 1 +6× × )×4 16 1000 16 < −1, (46) ππ = 1, π = 1, 2. This yields that system (43) satisfies (π»1 )–(π»5 ). Hence, from Theorem 5, system (43) has exactly one 2-periodic solution. Moreover, the 2-periodic solution is globally exponentially stable. Remark 7. Since π1 (π₯) = π2 (π₯) = π₯ + 2 sin π₯, π1 (π₯) = π2 (π₯) = π₯ + 3 sin π₯ and CNNs (43) is a very simple form of CNNs with time-varying delays in the leakage terms, it is clear that the conditions (π΄ 1 ) and (π΄ 2 ) are not satisfied. Therefore, all the results in [11–19] and the references therein cannot be applicable to system (43) to obtain the existence and exponential stability of the 2-periodic solutions. Acknowledgments The authors would like to express their sincere appreciation to the reviewers for their helpful comments in improving the presentation and quality of the paper. This work was supported by the National Natural Science Foundation of China (Grant no. 11201184), the Natural Scientific Research Fund of Hunan Provincial of China (Grant no. 11JJ6006), the Construct Program of the Key Discipline in Hunan Province (Mechanical Design and Theory), the Natural Scientific Research Fund of Hunan Provincial Education Department [1] V. Lakshmikantham, D. D. BaΔ±Μnov, and P. S. Simeonov, Theory of Impulsive Differential Equations, World Scientific, Singapore, 1989. [2] A. M. SamoΔ±Μlenko and N. A. Perestyuk, Impulsive Differential Equations, World Scientific Publishing, Singapore, 1995. [3] M. U. 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