Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2013, Article ID 978738, 7 pages http://dx.doi.org/10.1155/2013/978738 Research Article New Generalization of π-Best Simultaneous Approximation in Topological Vector Spaces Mahmoud Rawashdeh and Sarah Khalil Department of Mathematics and Statistics, Jordan University of Science and Technology, Irbid 22110, Jordan Correspondence should be addressed to Mahmoud Rawashdeh; msalrawashdeh@just.edu.jo Received 20 January 2013; Revised 23 April 2013; Accepted 23 April 2013 Academic Editor: Naseer Shahzad Copyright © 2013 M. Rawashdeh and S. Khalil. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. Let πΎ be a nonempty subset of a Hausdorff topological vector space π, and let π be a real-valued continuous function on π. If for π π each π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ , there exists π0 ∈ πΎ such that πΉπΎ (π₯) = ∑π=1 π(π₯π − π0 ) = inf{∑π=1 π(π₯π − π) : π ∈ πΎ}, then πΎ is called π-simultaneously proximal and π0 is called π-best simultaneous approximation for π₯ in πΎ. In this paper, we study the problem of π-simultaneous approximation for a vector subspace πΎ in π. Some other results regarding π-simultaneous approximation in quotient space are presented. 1. Introduction Let πΎ be a closed subset of a Hausdorff topological vector space π and π a real-valued continuous function on π. For π₯ ∈ π, set πΉπΎ (π₯) = inf π∈πΎ π(π₯ − π). A point π0 ∈ πΎ is called π-best approximation to π₯ in πΎ if πΉπΎ (π₯) = π(π₯ − π0 ). π The set ππΎ (π₯) = {π ∈ πΎ : πΉπΎ (π₯) = π(π₯ − π )} denotes the set of all π-best approximations to π₯ in πΎ. Note that this set may be empty. The set πΎ is said to be π-proπ ximal (π-Chebyshev) if for each π₯ ∈ π, ππΎ (π₯) is nonempty (singleton). The notion of π-best approximation in a vector space π was given by Breckner and Brosowski [1] and in a Hausdorff topological space π by Narang [2, 3]. For a Hausdorff locally convex topological vector space and a continuous sublinear functional π on π, certain results on best approximation relative to the functional π were proved in [1, 4]. By using the existence of elements of π-best approximation, certain results on fixed points were proved by Pai and Veermani in [5]. In addition, for a topological vector space π relative to upper semicontinuous functions, some results on best approximation were proved by Haddadi and Hamzenejad [6]. Moreover, Naidu [7] proved some results on best simultaneous approximation related to π-nearest point and topological vector space π. Analogous to the problem of simultaneous approximation [8], we introduce the concept of best π-simultaneous approximation as follows. Definition 1. Let πΎ be a non-empty subset of a Hausdorff topological vector space π, and let π be a real-valued continuous function on π. A point π0 ∈ πΎ is called πbest simultaneous approximation in πΎ if there exists π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ such that π π π=1 π=1 πΉπΎ (π₯) = inf {∑ π (π₯π − π) : π ∈ πΎ} =∑ π (π₯π − π0 ) . (1) The set of all π-best simultaneous approximations to π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ in πΎ is denoted by π π ππΎ (π₯) = {π ∈ πΎ : πΉπΎ (π₯) =∑ π (π₯π − π)} . (2) π=1 The set πΎ is called π-simultaneously proximal (π-simultaneously Chebyshev) if for each π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ , π ππΎ (π₯) =ΜΈ π (singleton). If π = 1, simultaneous π-proximal is precisely π-proximal. 2 Abstract and Applied Analysis We remark that if π(π₯) = βπ₯β, then the concept of π-best approximation is precisely the best approximation. A set πΎ is said to be inf-compact at a point π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ [5] if each minimizing sequence in πΎ (i.e., ∑ππ=1 π(π₯π −ππ ) → πΉπΎ (π₯)) has a convergent subsequence in πΎ. The set πΎ is called inf-compact if it is inf-compact at each π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ . It is easy to see that if πΎ is compact or inf-compact, then πΎ is π-simultaneously proximal. In this paper, we introduce the concept of π-simultaneous approximation and study the existence and uniqueness problem of π-simultaneous approximation of a subspace πΎ of a Hausdorff topological vector space π. Certain results regarding π-simultaneous approximation in quotient spaces are obtained by generalizing some of the results in [9]. Throughout this paper, π is a Hausdorff topological vector space and π is a real-valued continuous function on π. π (5) ππΌπΎ (πΌπ₯) = πΌππΎπΉ (π₯), for all π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ and πΌ ∈ R. (6) πΎ is π-simultaneously proximal (π-simultaneously Chebyshev) if and only if πΌπΎ is π-simultaneously proximal (π-simultaneously Chebyshev), πΌ ∈ R. π (7) If π is convex function and πΎ is a convex set, then ππΎ (π₯) is convex. Proof. (1) Let π₯ = (π₯1 , π₯2 , . . . , π₯π ) and π = (π¦, π¦, . . . , π¦) ∈ ππ . Then π πΉπΎ+π¦ (π₯ + π) = inf ∑ π ((π₯π + π¦) − (π + π¦)) = πΉπΎ (π₯) . π∈πΎ (3) (2) The equation π π ∑π (π₯π − π0 ) = inf ∑ π ((π₯π + π¦) − (π + π¦)) 2. π-Simultaneous Approximation π∈πΎ π=1 Definition 3. A subset πΎ of π is called π-closed if for all sequences {ππ } of πΎ and for all π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ , such that ∑ππ=1 π(π₯π − ππ ) → 0, we have π₯ ∈ πΎπ . Definition 4. A subset πΎ of π is called π-compact if for every sequence {ππ } in πΎ there exist a subsequence {πππ } of {ππ } and π0 ∈ πΎ such that π(πππ − π0 ) → 0. Definition 5. For π₯, π¦ ∈ π, where π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ and π¦ = (π¦1 , π¦2 , . . . , π¦π ) ∈ ππ , π₯ is said to be π-orthogonal to π¦ denoted by π₯⊥π π¦, if ∑ππ=1 π(π₯π ) ≤ ∑ππ=1 π(π₯π + πΌπ¦π ) for every scalar πΌ ∈ R. Also, π₯ is said to be π-orthogonal to a set πΎ if π₯⊥π π, for all π ∈ πΎ. Definition 6. We say that πΎ is π€-compact if every net {ππΌ } in πΎ has a convergent subnet. (2) π ππΎ+π¦ (π₯ + π) = π ππΎ (π₯) π∈πΎ Moreover, if π is absolutely homogeneous function, then one has the following. (4) πΉπΌπΎ (πΌπ₯) = |πΌ|πΉπΎ (π₯), for all π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ and πΌ ∈ R. π=1 π π implies that π0 + π¦ ∈ ππΎ+π¦ (π₯ + π) if and only if π0 ∈ ππΎ (π₯). Thus, π π ππΎ+π¦ (π₯ + π) = ππΎ (π₯) + π¦. (5) (3) The proof follows immediately from part (2) above. (4) Let π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ , πΌ ∈ R. Then, π πΉπΌπΎ (πΌπ₯) = inf ∑ π (πΌπ₯π − πΌπ) π∈πΎ π=1 (6) π = |πΌ| inf ∑ π (π₯π − π) = |πΌ| πΉπΎ (π₯) . π∈πΎ π=1 π (5) If πΌ = 0, then we are done. If πΌ =ΜΈ 0 and π0 ∈ ππΌπΎ (πΌπ₯), then π0 ∈ πΌπΎ and π π ∑ π (πΌπ₯π − π0 ) = inf ∑ π (πΌπ₯π − πΌπ) . π∈πΎ π=1 (7) π=1 This implies that π ∑ π (π₯π − + π¦, for all π₯ = (π₯1 , π₯2 , . . . , π₯π ). (3) πΎ is π-simultaneously proximal (π-simultaneously Chebyshev) if and only if πΎ + π¦ is π-simultaneously proximal (π-simultaneously Chebyshev) for every π¦ ∈ π. (4) = inf ∑ π (π₯π − π) Theorem 7. Let πΎ be a subset of π. Then, one has the following. (1) πΉπΎ+π¦ (π₯+π) = πΉπΎ (π₯), for all π₯ = (π₯1 , π₯2 , . . . , π₯π ), where π = (π¦, π¦, . . . , π¦) ∈ ππ . π=1 π In this section, we give some characterizations of π-proximal sets in π. We begin with the following definitions. Definition 2. A function π : π → R is called absolutely homogeneous if π(πΌπ₯) = |πΌ|π(π₯), for all π₯ ∈ π and all πΌ ∈ R. π=1 π=1 1 π ) = πΉπΎ (π₯) , πΌ 0 (8) π which implies that (1/πΌ)π0 ∈ ππΎ (π₯). (6) The proof follows immediately from part (5) above. π (7) Let π1 , π2 ∈ ππΎ (π₯). Since πΎ is convex, then ππ1 − (1 − π π)π2 ∈ πΎ. We must show that ππ1 − (1 − π)π2 ∈ ππΎ (π₯); that is, π π ∑ π (π₯π − (ππ1 − (1 − π) π2 )) = inf ∑ π (π₯π − π) . π=1 π∈πΎ π=1 (9) Abstract and Applied Analysis 3 π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ , such that ∑ππ=1 π(π₯π − ππ ) → 0. This implies that So, π ∑ π (π₯π − (ππ1 − (1 − π) π2 )) π∈πΎ π =∑ π (π (π₯π − π1 ) + (1 − π) (π₯π − π2 )) π π π π=1 Theorem 11. Let π be a topological vector space and πΎ a vector subspace of π. Suppose that π is continuous function and πΎ is π€-compact; then, πΎ is π-simultaneously proximal. is convex. Example 8. Let π = R2 and πΎ = {(π₯1 , π₯2 ) ∈ R2 : π₯12 +π₯22 ≤ 4}, and let π(π₯, π¦) = π₯2 − π¦2 . If π§ = ((0, 0), (0, 1)) ∈ π2 , then one can show that πΉπΎ (π§) = π(0, 1/2) = −1/4. Theorem 9. Let π be an absolutely homogeneous real-valued function on π and π a vector subspace of π. Then, Proof. Let π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ . Since π πΉπΎ (π₯) = inf ∑ π (π₯π − π) , Proof. (1) Let π₯ = (π₯1 , π₯2 , . . . , π₯π ). Then, π=1 π=1 1 . πΌ (17) But πΎ is π€-compact; then, there exists a subnet {ππΌπ½ } such that ππΌπ½ → π0 . Thus, ∀π = 1, 2, . . . , π. (18) Since π is continuous, then π=1 (11) π ∈π π=1 π π π=1 π=1 ∑ π (π₯π − ππΌπ½ ) ≤∑ π (π₯π − π) + = |πΌ| inf ∑ π (π₯π − πσΈ ) = |πΌ| πΉπ (π₯) . σΈ 1 . πΌ (19) Also, Then, π π π∈π π π π=1 π=1 ∑ π (π₯π − π0 ) = lim inf ∑ π (π₯π − ππΌπ½ ) ∑ π (πΌπ₯π − π0 ) = inf ∑ π (πΌπ₯π − π) π=1 π π₯π − ππΌπ½ σ³¨→ π₯π − π0 , π (2) Let π0 ∈ π ∑ π (π₯π − ππΌ ) ≤∑ π (π₯π − π) + π πΉπ (πΌπ₯) = inf ∑ π (πΌπ₯π − π) (16) then, for any constant πΌ, there exists {ππΌ } such that π (2) ππ(πΌπ₯) = πΌππ(π₯), for all π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ , πΌ ∈ R − {0}. where π ∈ πΎ, π=1 (1) πΉπ(πΌπ₯) = |πΌ|πΉπ(π₯), for all π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ , πΌ ∈ R − {0}; π ππ(πΌπ₯). (15) Hence, for all π = 1, 2, . . . , π, π(π₯π − π0 ) = 0. Using the assumption it follows that π₯π −π0 = 0, and, hence, π₯π = π0 ∈ πΎ. Consequently, π₯ ∈ πΎπ and πΎ is π-closed. = πΉπΎ (π₯) =∑ π (π₯π − π) , π∈π (14) π=1 = ππΉπΎ (π₯) + (1 − π) πΉπΎ (π₯) π π=1 πΉπΎ (π₯) =∑ π (π₯π − π0 ) = 0. π=1 which implies that π=1 π (10) = π ∑ π (π₯π − π1 ) + (1 − π) ∑ π (π₯π − π2 ) π ππΎ (π₯) π Since πΎ is π-simultaneously proximal, then there exists π0 ∈ πΎ such that π=1 π=1 π πΉπΎ (π₯) = inf ∑ π (π₯π − π) ≤∑ π (π₯π − ππ ) σ³¨→ 0. π=1 (12) (20) π π=1 ≤∑ π (π₯π − π) . π=1 if and only if π 1 π (π₯π − πσΈ ) = πΉπ (π₯) , (13) ∑ π (π₯π − π0 ) = inf ∑ σΈ ∈π πΌ π π=1 π π for all πΌ ∈ R − {0}, which implies that (1/πΌ)π0 ∈ ππ(π₯), so, π π0 ∈ πΌππ(π₯). Theorem 10. Let π be a positive real-valued function on π such that π₯ = 0 if and only if π(π₯) = 0. Then, if πΎ is πsimultaneously proximal, then πΎ is π-closed. Proof . Since π is a positive function, then ∑ππ=1 π(π₯π ) ≥ 0 for all π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ . Let {ππ } be a sequence of πΎ and π Hence, π0 ∈ ππΎ (π₯). ΜπΉ to be such that For a subset πΎ of π, let us define πΎ π ΜπΉ = {π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ : πΉπΎ (π₯) = ∑π (π₯π )} . πΎ π=1 (21) 2 Example 12. Consider π = (R2 ) and πΎ = {((π₯1 , π¦1 ), (π₯2 , π¦2 )) : π₯π = π¦π , for all π = 1, 2}. Let π(π₯, π¦) = π₯2 + π¦2 ; then, one can see that ΜπΉ = {((π₯1 , −π₯1 ) , (π₯2 , −π₯2 ))} . πΎ (22) 4 Abstract and Applied Analysis ΜπΉ , we prove the folUsing the previous definition of πΎ lowing theorem characterizing π-simultaneously proximal subspaces. Thus, π ∑ π (π₯π − π0 ) π=1 Theorem 13. Let πΎ be a vector subspace of π. Then, πΎ is πΜπΉ , simultaneously proximal in π if and only if ππ = π·π + πΎ where π·πΎ = {(π, π, . . . , π) : π ∈ πΎ}. ΜπΉ . Then, for π₯ = (π₯1 , π₯2 , Proof. Suppose that ππ = π·π + πΎ . . . , π₯π ) ∈ ππ , there exists π1 = (π0 , π0 , . . . , π0 ) ∈ π·πΎ and ΜπΉ such that π₯ = π¦+π1 . Hence, π₯−π1 = π¦ = (π¦1 , π¦2 , . . . , π¦π ) ∈ πΎ Μ π¦ ∈ πΎπΉ , and π πΉπΎ (π¦) = πΉπΎ (π₯ − π1 ) =∑ π (π₯π − π0 ) , (23) π=1 π = inf {∑ π (π₯π − π0 − πσΈ ) : πσΈ ∈ πΎ} , π=1 ΜπΉ . which implies that π₯ − π0 ∈ πΎ ΜπΉ . Since π is symmetric, (2) Let π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ πΎ then π π π=1 π=1 π π = inf {∑ π (π₯π − π) : π ∈ πΎ} ∑ π (π₯π − π0 ) = inf ∑ π (π₯π − π0 − π) π∈πΎ π=1 (27) π=1 ∑ π (−π₯π ) =∑ π (π₯π ) and so π π = inf {∑ π (π₯π − π0 + π0 − π) : π ∈ πΎ} π=1 π=1 (24) π (28) π = inf {∑ π (− (−π₯π + π)) : −π ∈ πΎ} = inf ∑ π (π₯π − πσΈ ) = πΉπΎ (π₯) . σΈ π=1 π ∈πΎ π=1 π So, πΎ is π-simultaneously proximal. Conversely, suppose that πΎ is π-simultaneously proximal and π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ . Then, there exists π0 ∈ πΎ such that π = inf {∑ π (−π₯π + π) : −π ∈ πΎ} . π=1 ∑ππ=1 π(−π₯π ) = inf{∑ππ=1 π(−π₯π + π) : −π ∈ πΎ}, Hence, which implies that ΜπΉ . −π₯ = (−π₯1 , −π₯2 , . . . , −π₯π ) ∈ πΎ π ∑ π (π₯π − π0 ) = inf ∑ π (π₯π − π) π∈πΎ π=1 π=1 π (25) = inf ∑ π (π₯π − (πσΈ + π0 )) , π∈πΎ (3) Let π₯ = (π₯1 , π₯2 , . . . , π₯π ). Since π₯⊥πΉ πΎ, then π π π=1 π=1 ∑ π (π₯π ) ≤ ∑π (π₯π + πΌπ) π=1 (29) ∀πΌ ∈ R, π ∈ πΎ. π where π = πσΈ + π0 . If π1 = (π0 , π0 , . . . , π0 ) ∈ π·πΎ , then = ∑π (π₯π − (−πΌπ)) ∀πΌ ∈ R, π ∈ πΎ. (30) π=1 π ∑ π (π₯π − π0 ) = πΉπΎ (π₯ − π1 ) , π (26) = ∑π (π₯π − πσΈ ) , π=1 πσΈ ∈ πΎ. π=1 ΜπΉ and ππ = π·π + πΎ ΜπΉ . which implies that π₯ − π1 = π2 ∈ πΎ So, Proposition 14. Let π be a topological vector space and πΎπsimultaneous proximal subset of π. Then, π ΜπΉ ; (1) π0 ∈ ππΎ (π₯) if and only if π₯ − π0 ∈ πΎ (2) if π is symmetric (i.e., π(−π₯) = π(π₯) for all π₯ ∈ π), ΜπΉ if and only if −π₯ ∈ πΎ ΜπΉ ; then π₯ ∈ πΎ ΜπΉ , where π₯ = (π₯1 , π₯2 , . . . , π₯π ); (3) if π₯⊥πΉ πΎ, then π₯ ∈ πΎ ΜπΉ and πΌπΎ = πΎ, then π₯⊥πΉ πΎ, where π₯ = (4) if π₯ ∈ πΎ (π₯1 , π₯2 , . . . , π₯π ). π Proof. (1) Let π0 ∈ ππΎ (π₯) if and only if ∑ππ=1 π(π₯π − π0 ) = inf{∑ππ=1 π(π₯π − π) : π ∈ πΎ}. π π π=1 π=1 ∑ π (π₯π ) ≤∑ π (π₯π − πσΈ ) , πσΈ ∈ πΎ. (31) ΜπΉ . Hence, π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ πΎ ΜπΉ and πΌπΎ = πΎ. Then, (4) Let π₯ ∈ πΎ π π ∑ π (π₯π ) = inf ∑ π (π₯π − π) π=1 π∈πΎ π=1 π = inf ∑ π (π₯π − πΌπ) , πΌπ∈πΎ since πΌπΎ = πΎ, π=1 π = inf ∑ π (π₯π + (−πΌπ)) , π=1 ∀π ∈ πΎ. (32) Abstract and Applied Analysis 5 Thus, for some π0 ∈ π, we have Thus, π π π=1 π=1 ∑ π (π₯π ) ≤∑ π (π₯π + πΌσΈ π) , ∀πΌσΈ ∈ R, ∀π ∈ πΎ. (33) Hence, π₯⊥πΉ πΎ. ΜπΉ ) = Theorem 15. Let πΎ be a vector subspace of π. If π(πΎ π π /π·πΎ , then πΎ is π-simultaneously proximal, where π is the canonical map π₯ → π₯ + π·π . ΜπΉ ) = ππ /π·πΎ and π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ . Proof. Let π(πΎ ΜπΉ . Hence, π₯−π¦ = π0 for Then, π₯+π·πΎ = π¦+π·πΎ for some π¦ ∈ πΎ Μ ΜπΉ + some π0 ∈ π·πΎ . Thus, π₯ = π¦ + π0 ∈ πΎπΉ + π·π . Therefore, πΎ π·π = ππ . By Theorem 15, πΎ is π-simultaneously proximal. Definition 16. Let πΎ and π be two vector subspaces of π such that π is closed and π ⊂ πΎ. Suppose that π is a positive real-valued function defined on π. Then, a function πΜ : (π/π)π → R can be defined as follows: πΜ (π₯1 + π, π₯2 + π, . . . , π₯π + π) π (34) π=1 for each (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ . Theorem 17. Let πΎ and π be two vector subspaces of π such that π ⊂ πΎ. If π0 is a point of π-best simultaneous Μ approximation to (π₯1 , π₯2 , . . . , π₯π ) in πΎ, then π0 +π is an π-best simultaneous approximation to (π₯1 , π₯2 , . . . , π₯π ) + π in πΎ/π. Μ Proof. Suppose that π0 + π is not π-best simultaneous approximation to (π₯1 +π, π₯2 +π, . . . , π₯π +π) in πΎ/π. Then, πΜ ((π₯π − π0 + π π)π=1 ) β° πΜ ((π₯π − π + π π)π=1 ) π=1 π=1 (39) so, π π π=1 π=1 ∑ π (π₯π − (π1 − π0 )) <∑ π (π₯π − π0 ) . (40) Since π ⊂ πΎ implies that π1 − π0 ∈ πΎ, therefore, π0 is not π-best simultaneous approximation to (π₯1 , π₯2 , . . . , π₯π ) in πΎ, which is a contradiction. Proof. If πΎ is π-simultaneously proximal in π, then there exists at least π0 ∈ πΎ such that π0 is π-best simultaneous approximation to (π₯1 , π₯2 , . . . , π₯π ) in πΎ. Thus by Μ Theorem 11, π0 + π is an π-best simultaneous approximation Μ to (π₯1 , π₯2 , . . . , π₯π ) + π in πΎ/π, so, πΎ/π is π-simultaneously proximal in π/π. Theorem 19. Let πΎ and π be two vector subspaces of π such that π ⊂ πΎ. If π is π-simultaneously proximal in π and Μ πΎ/π is π-simultaneously proximal in π/π, then πΎ is πsimultaneously proximal in π. Μ Proof. Since πΎ/π is π-simultaneously proximal in π/π, Μ then there exists π0 ∈ πΎ such that π0 + π is π-best simultaneous approximation to (π₯1 , π₯2 , . . . , π₯π ) + π from πΎ/π, so, π π πΜ ((π₯π − π0 + π)π=1 ) ≤ πΜ ((π₯π − π + π)π=1 ) , (35) for at least π ∈ πΎ, say π1 ∈ πΎ, such that π π πΜ ((π₯π − π1 + π)π=1 ) < πΜ ((π₯π − π0 + π)π=1 ) . π Corollary 18. Let πΎ and π be two vector subspaces of π such that π ⊂ πΎ. Then, if πΎ is π-simultaneously proximal in π, Μ then πΎ/π is π-simultaneously proximal in π/π. 3. π-Simultaneous Approximation in Quotient Space = inf {∑ π (π₯π + π¦) : π¦ ∈ π} π ∑ π (π₯π − π1 + π0 ) <∑ π (π₯π − π0 ) , ∀π ∈ πΎ, ⇓ π (36) π πΜ ((π₯π − π0 + π)π=1 ) = inf ∑ π (π₯π − π0 + π) π∈π π=1 π Since ≤ inf ∑ π (π₯π − π + π) , π∈π π π πΜ ((π₯π − π0 + π)π=1 ) = inf {∑ π (π₯π − π0 + π¦) : π¦ ∈ π} π=1 (41) π=1 for all π ∈ πΎ. Note that π ≤∑ π (π₯π − π0 ) , π=1 (37) π inf ∑ π (π₯π − π0 + π) π∈π we have πΜ ((π₯π − π1 + π π)π=1 ) = πΉπ (π₯1 − π0 , π₯2 − π0 , . . . , π₯π − π0 ) π < ∑ π (π₯π − π0 ) . π=1 π=1 (38) ≤ πΉπ (π₯1 − π, π₯2 − π, . . . , π₯π − π) . (42) 6 Abstract and Applied Analysis Since π is π-simultaneously proximal in π, then there exists π0 ∈ π such that πΉπ (π₯1 − π0 , π₯2 − π0 , . . . , π₯π − π0 ) π =∑ π (π₯π − π0 − π0 ) (43) π=1 π ≤∑ π (π₯π − π − π) , π-simultaneous Chebyshev in π. Then, there exists π₯ = (π₯1 , . . . , π₯π ) ∈ ππ which has two distinct π-best simultaneous approximations, say β0 and β1 ∈ πΎ + π. Thus, we have β0 and π β1 ∈ ππΎ+π(π₯). Since π ⊆ πΎ + π, we have that β0 + π and π π β1 + π ∈ π(πΎ+π)/π(π₯ + π) = ππΎ/π(π₯ + π). By hypothesis, Μ πΎ/π is π-simultaneous Chebyshev, and so β0 + π = β1 + π. Then, there exists π0 ∈ π \ {0} such that β1 = β0 + π0 . Thus, we conclude that π π=1 ∑ π ((π₯π − β0 ) − π0 ) for all π ∈ π and π ∈ πΎ. So, π π=1 π π ∑ π (π₯π − (π0 + π0 )) ≤∑ π (π₯π − (π + π)) , π=1 =∑ π (π₯π − β1 ) (44) π=1 π=1 for all π ∈ π and π ∈ πΎ. Hence, π = inf {∑ π (π₯π − (β0 + π))} π∈π π ∑ π (π₯π − (π0 + π0 )) π=1 π π=1 ≤ {∑ π ((π₯π − β0 ) − π)} , (45) π ∀π ∈ π π=1 = inf {∑ π (π₯π − (π + π)) : π ∈ π, π ∈ πΎ} . = πΉπ (π₯ − β0 ) . π=1 So, π0 + π0 is an π-best simultaneous approximation to (π₯1 , π₯2 , . . . , π₯π ) from πΎ and πΎ is π-simultaneously proximal in π. Theorem 20. Let πΎ and π be two vector subspaces of π such that π ⊂ πΎ. If π is π-simultaneously proximal in π Μ and πΎ is π-simultaneously Chebyshev in π, then πΎ/π is πsimultaneously Chebyshev in π/π. Proof. Suppose not, then there exists (π₯1 , π₯2 , . . . , π₯π ) + π ∈ πΜ π/π, and π1 + π, π2 + π ∈ ππΎ/π((π₯1 , π₯2 , . . . , π₯π ) + π) such that π1 + π =ΜΈ π2 + π. Thus, π1 − π2 ∉ π. Since π is πsimultaneously proximal in π, then π ππ (π₯1 − π1 , π₯2 − π1 , . . . , π₯π − π1 ) =ΜΈ π, (46) π ππ (π₯1 − π2 , π₯2 − π2 , . . . , π₯π − π2 ) =ΜΈ π. π (47) π Let π1 ∈ ππ(π₯1 − π1 , π₯2 − π1 , . . . , π₯π − π1 ) and π2 ∈ ππ(π₯1 − π2 , π₯2 − π2 , . . . , π₯π − π2 ). By Theorem 13, π1 + π1 and π2 + π2 are π-best simultaneous approximation to (π₯1 , π₯2 , . . . , π₯π ) from πΎ. Since πΎ is π-simultaneously Chebyshev in π, then π1 + π1 = π2 + π2 , and, hence, π1 − π2 = π1 − π2 ∈ π, which is a contradiction. Theorem 21. Let πΎ and π be two vector subspaces of a topological vector space π. If π is π-simultaneously Chebyshev in π, then the following assertions are equivalent: Μ (i) πΎ/π is π-simultaneously Chebyshev in π/π; (ii) πΎ + π is simultaneously Chebyshev in π. Proof. (i ⇒ ii) By hypothesis, (πΎ + π)/π = πΎ/π is Μ π-simultaneous Chebyshev. Assume that πΎ + π is not So, π0 and 0 are π-best simultaneous approximations to π₯−β0 from π. Hence, π is not π-simultaneously Chebyshev. This is a contradiction. (ii ⇒ i) Assume that (i) does not hold. Then, there exists Μ π₯ + π ∈ πΎ/π which has two distinct π-best simultaneous approximations, say π + π and πσΈ + π ∈ πΎ/π; thus, π − πσΈ ∉ π. Since π is π-simultaneously proximal, so there exist πbest simultaneous approximations π and πσΈ to π₯−π and π₯−πσΈ π from π, respectively. Therefore, we have π ∈ ππ(π₯ − π) and π πσΈ ∈ ππ(π₯ − πσΈ ). Since π ⊆ πΎ + π, π + π and πσΈ + π ∈ π π ππΎ/π(π₯ + π) = π(πΎ+π)/π(π₯ + π), so π + π and πσΈ + πσΈ ∈ π ππΎ+π(π₯). But πΎ + π is π-simultaneously Chebyshev. Thus we get π + π = πσΈ + πσΈ , and therefore π − πσΈ ∈ π. This is a contradiction. Definition 22. A subset πΎ of π is called π-quasisimultaneπ ously Chebyshev if ππΎ (π₯) is non-empty and π-compact set in π, for all π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ . Theorem 23. Let π be a positive function, π an π-simultaneously proximal vector subspace of π, and K π-quasisimultaneously Chebyshev of π such that π ⊂ πΎ. Then, πΎ/π is Μ π-quasi-simultaneously Chebyshev in ππ /π. Proof. Since πΎ is π-simultaneously proximal in π, then by Μ Corollary 12, πΎ/π is π-simultaneously proximal in π/π. Let π₯ = (π₯1 , π₯2 , . . . , π₯π ) ∈ ππ and (ππ + π) a sequence in πΜ ππΎ/π(π₯ + π). For every π, there exists ππ ∈ π such that π ππ + ππ = ππσΈ ∈ ππΎ (π₯). But since π is a vector subspace, we have ππσΈ + π = ππ + ππ + π = ππ + π. (48) Abstract and Applied Analysis 7 Since πΎ is π-quasi-simultaneously Chebyshev of π, the sequence {ππ } has a subsequence {πππ } which is π-convergent π to π0 ∈ ππΎ (π₯), meaning that π (πππ − π0 ) σ³¨→ 0. (49) πΜ (πππ − π0 + π) ≤ π (πππ − π0 ) σ³¨→ 0. (50) πΜ (πππ − π0 + π) σ³¨→ 0. (51) But Hence, πΜ Μ and πΎ/π Consequently, ππΎ/π(π₯ + π) is π-compact Μ is π-quasi-simultaneously Chebyshev. This completes the proof. 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