Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2013, Article ID 507950, 11 pages http://dx.doi.org/10.1155/2013/507950 Research Article Some Spaces of Double Sequences Obtained through Invariant Mean and Related Concepts S. A. Mohiuddine and Abdullah Alotaibi Department of Mathematics, Faculty of Science, King Abdulaziz University, P.O. Box 80203, Jeddah 21589, Saudi Arabia Correspondence should be addressed to S. A. Mohiuddine; mohiuddine@gmail.com Received 29 November 2012; Accepted 11 March 2013 Academic Editor: Elena Braverman Copyright © 2013 S. A. Mohiuddine and A. Alotaibi. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. We introduce some double sequences spaces involving the notions of invariant mean (or π-mean) and π-convergence for double sequences while the idea of π-convergence for double sequences was introduced by CΜ§akan et al. 2006, by using the notion of invariant mean. We determine here some inclusion relations and topological results for these new double sequence spaces. 1. Preliminaries, Background, and Notation In 1900, Pringsheim [1] presented the following notion of convergence for double sequences. A double sequence π₯ = (π₯ππ ) is said to converge to the limit πΏ in Pringsheim’s sense (shortly, π-convergent to πΏ) if for every π > 0 there exists an integer π such that |π₯ππ − πΏ| < π whenever π, π > π. In this case, πΏ is called the π-limit of π₯. A double sequence π₯ = (π₯ππ ) of real or complex numbers is said to be bounded if βπ₯β∞ = supπ,π |π₯ππ | < ∞. The space of all bounded double sequences is denoted by Mπ’ . If π₯ ∈ Mπ’ and is π-convergent to πΏ, then π₯ is said to be boundedly π-convergent to πΏ (shortly, ππ-convergent to πΏ). In this case, πΏ is called the ππ-limit of π₯. The assumption of πconvergent was made because a double sequence on which π-convergent is not necessarily bounded. In general, for any notion of convergence ], the space of all ]-convergent double sequences will be denoted by C] , the space of all ]-convergent to 0 double sequences by C]0 and the limit of a ]-convergent double sequence π₯ by ]-limπ,π π₯ππ , where ] ∈ {π, ππ}. Let Ω denote the vector space of all double sequences with the vector space operations defined coordinatewise. Vector subspaces of Ω are called double sequence spaces. In addition to the above-mentioned double sequence spaces, we consider the double sequence space as } { σ΅¨ σ΅¨ Lπ’ := {π₯ ∈ Ω | βπ₯β1 := ∑ σ΅¨σ΅¨σ΅¨σ΅¨π₯ππ σ΅¨σ΅¨σ΅¨σ΅¨ < ∞} π,π } { (1) of all absolutely summable double sequences. All considered double sequence spaces are supposed to contain Φ := span {ejk | π, π ∈ N} , (2) where 1; jk eil = { 0; if (π, π) = (π, β) , otherwise. (3) We denote the pointwise sums ∑π,π ejk , ∑π ejk (π ∈ N), and ∑π ejk (π ∈ N) by e, ek , and ej , respectively. Let π be a one-to-one mapping from the set N of natural numbers into itself. A continuous linear functional π on the space β∞ of bounded single sequences is said to be an invariant mean or a π-mean if and only if (i) π(π₯) ≥ 0 when 2 Abstract and Applied Analysis the sequence π₯ = (π₯π ) has π₯π ≥ 0 for all π, (ii) π(π) = 1, where π = (1, 1, 1, . . .), and (iii) π(π₯) = π((π₯π(π) )) for all π₯ ∈ β∞ . Throughout this paper we consider the mapping π which has no finite orbits, that is, ππ (π) =ΜΈ π for all integer π ≥ 0 and π ≥ 1, where ππ (π) denotes the πth iterate of π at π. Note that a π-mean extends the limit functional on the space π of convergent single sequences in the sense that π(π₯) = lim π₯ for all π₯ ∈ π, (see [2]). Consequently, π ⊂ ππ the set of bounded sequences all of whose π-means are equal. We say that a sequence π₯ = (π₯π ) is π-convergent if and only if π₯ ∈ ππ . Using this concept, Schaefer [3] defined and characterized π-conservative, π-regular, and π-coercive matrices for single sequences. If π is translation then ππ is reduced to the set π of almost convergent sequences [4]. Recently, Mohiuddine [5] has obtained an application of almost convergence for single sequences in approximation theorems and proved some related results. In 2006, CΜ§akan et al. [6] presented the following definition of π-convergence for double sequences and further studied by Mursaleen and Mohiuddine [7–9]. A double sequence π₯ = (π₯ππ ) of real numbers is said to be π-convergent to a number πΏ if and only if π₯ ∈ Vπ , where For more details of spaces for single and double sequences and related concepts, we refer to [14–31] and references therein. In this paper, we define and study some new spaces involving the idea of invariant mean and π-convergence for double sequences and establish a relation between these spaces. Further, we extend above spaces to more general spaces by considering the double sequences πΌ = (πΌππ ) such that πΌππ > 0 for all π, π and supπ,π πΌππ = π» < ∞ and prove some topological results. 2. The Double Sequence Spaces We construct the following spaces involving the idea of invariant mean and π-convergence for double sequences: 1 (π + 1) (π + 1) Wπ = {π₯ = (π₯ππ ) : π π × ∑ ∑ ππππ π‘ (π₯ − βπΈ) σ³¨→ 0 as π, π σ³¨→ ∞, π=0 π=0 uniformly in π , π‘, for some β} , Vπ = {π₯ ∈ Mπ’ : lim ππππ π‘ (π₯) = πΏ uniformly in π , π‘; π,π → ∞ [Wπ ] = {π₯ = (π₯ππ ) : πΏ = π-limπ₯} , π π π σ΅¨ σ΅¨ × ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯ − βπΈ)σ΅¨σ΅¨σ΅¨σ΅¨ σ³¨→ 0 as π, π σ³¨→ ∞, π 1 ππππ π‘ (π₯) = ∑ ∑π₯ π π , (π + 1) (π + 1) π=0 π=0 π (π ),π (π‘) π=0 π=0 (4) while here the limit means ππ-limit. Let us denote by Vπ the space of π-convergent double sequences π₯ = (π₯ππ ). For π(π) = π + 1, the set Vπ is reduced to the set F of almost convergent double sequences [10]. Note that Cππ ⊂ Vπ ⊂ Mπ’ . Maddox [11] has defined the concepts of strong almost convergence and π-convergence for single sequences and established inclusion relation between strong almost convergence, π-convergence, and almost convergence for single sequence. BasΜ§arir [12] extended the notion of strong almost convergence from single sequences to double sequences and proved some interesting results involving this idea and the notion of almost convergence for double sequences. In the recent past, Mursaleen and Mohiuddine [13] presented the notions of absolute and strong π-convergence for double sequences. A bounded double sequence π₯ = (π₯ππ ) is said to be strongly π-convergent if there exists a number β such that π π 1 σ΅¨ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨π₯ππ (π ),ππ (π‘) − βσ΅¨σ΅¨σ΅¨σ΅¨ σ³¨→ 0 (π + 1) (π + 1) π=0 π=0 1 (π + 1) (π + 1) uniformly in π , π‘, for some β} , WσΈ π = {π₯ = (π₯ππ ) : ∞ ∞ σ΅¨ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ π=0 π=0 converges uniformly in π , π‘} , WσΈ σΈ π = {π₯ = (π₯ππ ) : ∞ ∞ σ΅¨ sup ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ π ,π‘ π=0 π=0 (5) as π, π σ³¨→ ∞ uniformly in π , π‘, while here the limit means ππ-limit. In this case, we write [Vπ ]-lim π₯ = β. Let us denote by [Vπ ] the set of all strongly π-convergent sequences π₯ = (π₯ππ ). If π is translation then [Vπ ] is reduced to the set [F] of strong almost convergence double sequences due to BasΜ§arir [12]. σ΅¨ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ < ∞} , (6) where πΈ = (πππ ) with πππ = 1 for all π, π; ππππ π‘ = ππππ π‘ (π₯) = π π 1 ∑ ∑ ππππ π‘ (π₯) , (π + 1) (π + 1) π=0 π=0 Abstract and Applied Analysis 3 (L2) (1/π’V) ∑π’π=1 ∑Vπ=1 |Ω†πππ π‘ − β| → 0 as π’, V → ∞ (uniformly in π , π‘); π0,0,π ,π‘ (π₯) = π0,0,π ,π‘ = π₯π ,π‘ , π−1,0,π ,π‘ (π₯) = π−1,0,π ,π‘ (π₯) = π₯π −1,π‘ , (L3) (1/π’V) ∑π’π=1 ∑Vπ=1 |Ω‡πππ π‘ − β| → 0 as π’, V → ∞ (uniformly in π , π‘); π0,−1,π ,π‘ (π₯) = π0,−1,π ,π‘ (π₯) = π₯π ,π‘−1 , π−1,−1,π ,π‘ (π₯) = π−1,−1,π ,π‘ (π₯) = π₯π −1,π‘−1 . (7) (L4) (1/π’V) ∑π’π=1 ∑Vπ=1 |ππππ π‘ + ππππ π‘ − Ω†πππ π‘ − Ω‡πππ π‘ | → 0 as π’, V → ∞ (uniformly in π , π‘), where Remark 1. If [Wπ ]-lim π₯ = β, that is, π π 1 σ΅¨ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − βσ΅¨σ΅¨σ΅¨σ΅¨ σ³¨→ 0 (π + 1) (π + 1) π=0 π=0 Ω†πππ π‘ = (8) Ω‡πππ π‘ as π, π → ∞, uniformly in π , π‘; then σ΅¨σ΅¨ π π π σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ 1 σ΅¨σ΅¨ 1 ∑ ∑ σ΅¨σ΅¨σ΅¨ ∑ππππ π‘ − βσ΅¨σ΅¨σ΅¨σ΅¨ σ³¨→ 0, (π + 1) (π + 1) π=0 π=0 σ΅¨σ΅¨ π + 1 π=0 σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨σ΅¨ π π π σ΅¨σ΅¨ σ΅¨σ΅¨ 1 σ΅¨σ΅¨ 1 ∑ ∑ σ΅¨σ΅¨ ∑ ππππ π‘ − βσ΅¨σ΅¨σ΅¨ σ³¨→ 0. σ΅¨ σ΅¨σ΅¨ + 1) + 1) π + 1 (π (π π=0 π=0 σ΅¨σ΅¨ π=0 σ΅¨ π π=1 π=1 ∑Vπ (π’π β π’π+1 ) = ∑π’π (Vπ β Vπ−1 ) β π’π+1 Vπ . (9) (10) (13) 1 π’ V σ΅¨σ΅¨ σ΅¨ + ππππ π‘ − Ω†πππ π‘ − Ω‡πππ π‘ σ΅¨σ΅¨σ΅¨σ΅¨ ∑ ∑ σ΅¨σ΅¨π π’V π=1 π=1 σ΅¨ πππ π‘ = 1 π’ V σ΅¨σ΅¨ σ΅¨ − β + ππππ π‘ − β − Ω†πππ π‘ + β − Ω‡πππ π‘ + βσ΅¨σ΅¨σ΅¨σ΅¨ ∑ ∑ σ΅¨σ΅¨π π’V π=1 π=1 σ΅¨ πππ π‘ ≤ π’ V 1 π’ V σ΅¨σ΅¨ σ΅¨ σ΅¨ 1 σ΅¨ ∑ ∑ σ΅¨σ΅¨ππππ π‘ − βσ΅¨σ΅¨σ΅¨ + ∑ ∑ σ΅¨σ΅¨σ΅¨ππππ π‘ − βσ΅¨σ΅¨σ΅¨ π’V π=1 π=1 π’V π=1 π=1 + We get Abel’s transformation for double series π π 1 = ∑ ππππ π‘ . (π + 1) π=0 Proof. Suppose that [Wπ ]-lim π₯ = β. Thus, we have Wπ lim π₯ = β, that is, (L1) holds. We see that conditions (L2) and (L3) follows from the Remark 1. Write We remark that by using Abel’s transformation for single series π π 1 ∑ ππππ π‘ , (π + 1) π=0 π ∑ ∑ Vππ (π’ππ − π’π+1,π − π’π,π+1 + π’π+1,π+1 ) 1 π’ V σ΅¨σ΅¨ † σ΅¨ 1 π’ V σ΅¨σ΅¨ ‡ σ΅¨ − βσ΅¨σ΅¨σ΅¨σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨Ωπππ π‘ − βσ΅¨σ΅¨σ΅¨σ΅¨ + ∑ ∑ σ΅¨σ΅¨Ω π’V π=1 π=1 π’V π=1 π=1 σ΅¨ πππ π‘ = Σ1 + Σ2 + Σ3 + Σ4 π=1 π=1 (say) . (14) π π π = ∑ ∑ π’ππ (Δ 11 Vππ ) − ∑ π’π,π+1 (Δ 10 Vππ ) π=1 π=1 (11) π=1 π − ∑ π’π+1,π (Δ 01 Vππ ) + π’π+1,π+1 Vππ , π=1 where Δ 10 Vππ = Vππ − Vπ−1,π , Δ 01 Vππ = Vππ − Vπ,π−1 Δ 11 Vππ = Vππ − Vπ−1,π − Vπ,π−1 + Vπ−1,π−1 . (12) In the recent past, Altay and BasΜ§ar [32] also presented another form of Abel’s transformation for double series. By our assumption, that is, [Wπ ]-lim π₯ = β, Σ1 → 0 as π’, V → ∞ uniformly in π , π‘. The condition (L1) implies that ππππ π‘ tends to zero as π, π tending to ∞ uniformly in π , π‘; therefore Σ2 → 0 as π’, V → ∞ uniformly in π , π‘ and Σ3 , Σ4 → 0 as π’, V → ∞ uniformly in π , π‘ by the conclusion (L2) and (L3), respectively. Thus, (14) tends to zero as π’, V → ∞ uniformly in π , π‘, that is, (L4) holds. Conversely, let (L1)–(L4) hold. Then, 1 π’ V σ΅¨σ΅¨ σ΅¨ − βσ΅¨σ΅¨σ΅¨ ∑ ∑ σ΅¨π π’V π=1 π=1 σ΅¨ πππ π‘ ≤ 1 π’ V σ΅¨σ΅¨ σ΅¨ + ππππ π‘ − Ω†πππ π‘ − Ω‡πππ π‘ σ΅¨σ΅¨σ΅¨σ΅¨ ∑ ∑ σ΅¨σ΅¨π π’V π=1 π=1 σ΅¨ πππ π‘ 3. Inclusion Relations + 1 π’ V σ΅¨σ΅¨ σ΅¨ − βσ΅¨σ΅¨σ΅¨ ∑ ∑ σ΅¨π π’V π=1 π=1 σ΅¨ πππ π‘ In the following theorem, we establish a relationship between spaces defined in Section 2. Before proceeding further, first we prove the following lemmas which will be used to prove our inclusion relations. + 1 π’ V σ΅¨σ΅¨ † σ΅¨ − βσ΅¨σ΅¨σ΅¨σ΅¨ ∑ ∑ σ΅¨σ΅¨Ω π’V π=1 π=1 σ΅¨ πππ π‘ + 1 π’ V σ΅¨σ΅¨ ‡ σ΅¨ − βσ΅¨σ΅¨σ΅¨σ΅¨ ∑ ∑ σ΅¨σ΅¨Ω π’V π=1 π=1 σ΅¨ πππ π‘ Lemma 2. Consider that [Wπ ]-lim π₯ = β if and only if (L1) Wπ -lim π₯ = β; → 0 (π’, V → ∞) uniformly in π , π‘. (15) 4 Abstract and Applied Analysis Lemma 3. One has ππππ π‘ + ππππ π‘ − Ω†πππ π‘ − Ω‡πππ π‘ = ππ [ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ ] . = π 1 1 π−1 {(π + 1) ππππ π‘ − ∑ ππππ π‘ }] ∑[ π π=0 π (π + 1) π=0 = π π−1 1 1 π−1 ∑ ππππ π‘ − ∑ ∑ ππππ π‘ ππ π=0 π (π + 1) π π=0 π=0 = 1 π−1 1 ∑ ππππ π‘ − ππ,π−1,π ,π‘ . ππ π=0 π (16) Proof. Since ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ =[ π π π−1 π 1 1 ∑ ∑ ππππ π‘ − ∑ ∑π ] π (π + 1) π=0 π=0 πππ π‘ (π + 1) (π + 1) π=0 π=0 (19) Substituting (18) and (19) in (17), we get π π−1 1 1 π−1 π−1 −[ ∑ ∑ ππππ π‘ − ∑ ∑π ] . ππ π=0 π=0 πππ π‘ (π + 1) π π=0 π=0 ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ (17) First, we solve the expression in the first bracket [ π 1 1 π−1 1 ∑ ππππ π‘ − ∑ ππππ π‘ − ππππ π‘ π (π + 1) π=0 ππ π=0 π = π π π−1 π 1 1 ∑ ∑ ππππ π‘ − ∑ ∑π ] π (π + 1) π=0 π=0 πππ π‘ (π + 1) (π + 1) π=0 π=0 + 1 = π (π + 1) (π + 1) = π π π−1 π=0 π=0 π=0 = π = π−1 1 ∑ [πππππ π‘ − ∑ ππππ π‘ ] π (π + 1) (π + 1) π=0 π=0 = π π 1 1 ∑ [ππππ π‘ − ∑ ππππ π‘ ] π (π + 1) π=0 (π + 1) π=0 π π π 1 1 ∑ ππππ π‘ − ∑ ∑ ππππ π‘ π (π + 1) π=0 π (π + 1) (π + 1) π=0 π=0 = π 1 1 ∑ ππππ π‘ − ππππ π‘ . π (π + 1) π=0 π = (18) π π−1 1 1 π−1 π−1 ∑ ∑ ππππ π‘ − ∑ ∑π ππ π=0 π=0 πππ π‘ (π + 1) π π=0 π=0 π π−1 1 π−1 1 = ∑[ {π ∑ ππππ π‘ − (π + 1) ∑ ππππ π‘ }] π π=0 π (π + 1) π=0 π=0 = π−1 1 π−1 1 {πππππ π‘ − ∑ ππππ π‘ }] ∑[ π π=0 π (π + 1) π=0 1 − ππ,π−1,π ,π‘ ) (π π πππ π‘ 1 − ππ,π−1,π ,π‘ ) (π π πππ π‘ π 1 1 [ππππ π‘ − ∑ ππππ π‘ ] ππ (π + 1) π=0 − Now, the expression in the second bracket (20) π 1 [(π + 1) ππππ π‘ − ∑ ππππ π‘ ] ππ (π + 1) π=0 − = 1 − ππ,π−1,π ,π‘ ) (π π πππ π‘ π−1 1 [πππππ π‘ − ∑ ππππ π‘ ] ππ (π + 1) π=0 − π π 1 = ∑ [(π + 1) ππππ π‘ − ∑ ππππ π‘ ] π (π + 1) (π + 1) π=0 π=0 = π π−1 1 [π ∑ ππππ π‘ − (π + 1) ∑ ππππ π‘ ] ππ (π + 1) π=0 π=0 − × [ ∑ (π ∑ ππππ π‘ − (π + 1) ∑ ππππ π‘ )] 1 π π π,π−1,π ,π‘ 1 − ππ,π−1,π ,π‘ ) . (π π πππ π‘ We know that ππππ π‘ = = ππ−1,π,π ,π‘ = π π 1 ∑ ∑ ππππ π‘ (π + 1) (π + 1) π=0 π=0 π−1 π π 1 [ ∑ ∑ ππππ π‘ + ∑ ππππ π‘ ] , (21) (π + 1) (π + 1) π=0 π=0 π=0 π−1 π 1 ∑ ∑π . π (π + 1) π=0 π=0 πππ π‘ Abstract and Applied Analysis 5 From (21), we have Also, we have (π + 1) ππππ π‘ − πππ−1,π,π ,π‘ = π 1 ∑π . (π + 1) π=0 πππ π‘ (22) Thus, (20) becomes σ΅¨σ΅¨ σ΅¨σ΅¨ π π σ΅¨σ΅¨ 1 σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ ∑ ∑ ππππ π‘ (π₯ − β)σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨ (π + 1) (π + 1) σ΅¨σ΅¨π=0 π=0 σ΅¨σ΅¨ σ΅¨ ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ = 1 − (π + 1) ππππ π‘ + πππ−1,π,π ,π‘ ] [π ππ πππ π‘ − = 1 − ππ,π−1,π ,π‘ ) (π π πππ π‘ ≤ π π 1 σ΅¨ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯ − β)σ΅¨σ΅¨σ΅¨σ΅¨ (π + 1) (π + 1) π=0 π=0 ≤ π π 1 ∑ ∑ ππππ π‘ (|π₯ − β|) . (π + 1) (π + 1) π=0 π=0 (23) Hence, [Vπ ] ⊂ [Wπ ] ⊂ Wπ and 1 − ππππ π‘ − π (ππππ π‘ − ππ−1,π,π ,π‘ ) [π ππ πππ π‘ [Wπ ]-lim π₯ = Wπ -lim π₯ = β. −π (ππππ π‘ − ππ,π−1,π ,π‘ )] . π 1 ∑ ππππ π‘ − ππππ π‘ . (π + 1) π=0 (24) Similarly, we can write π (ππππ π‘ − ππ,π−1,π ,π‘ ) = π 1 ∑ ππππ π‘ − ππππ π‘ . (π + 1) π=0 ∞ ∞ σ΅¨ σ΅¨ Iπππ π‘ = ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ π=π π=π (32) σ³¨→ 0 (25) as π, π → ∞, uniformly in π , π‘; and Using (24) and (25) in (23), we get ππππ π‘ σ³¨→ β ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ = (31) (ii) We have to show that WσΈ π ⊂ [Wπ ]. If π₯ ∈ WσΈ π , then we have Also (22) can be written as π (ππππ π‘ − ππ−1,π,π ,π‘ ) = (30) π π 1 1 1 [ππππ π‘ +ππππ π‘ − ∑ ππππ π‘ − ∑ ππππ π‘ ] . ππ (π + 1) π=0 (π + 1) π=0 (26) (say) as π, π σ³¨→ ∞, uniformly in π , π‘, (33) that is, Wπ -lim π₯ = β. In order to prove that π₯ ∈ [Wπ ], it is enough to show that condition (L4) of Lemma 2 holds. Now, Iπππ π‘ − Iπ,π+1,π ,π‘ − Iπ+1,π,π ,π‘ + Iπ+1,π+1,π ,π‘ This implies that ∞ ∞ σ΅¨ σ΅¨ = ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ π=π π=π ππππ π‘ + ππππ π‘ − Ω†πππ π‘ − Ω‡πππ π‘ = ππ [ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ ] . (27) Theorem 4. One has the following inclusions and the limit is preserved in each case: (i) [Vπ ] ⊂ [Wπ ] ⊂ Wπ , (ii) WσΈ π ⊂ [Wπ ] if the conditions (L2) and (L3) of Lemma 2 hold, (iii) WσΈ π ⊂ WσΈ σΈ π . Proof. (i) Let π₯ ∈ [Vπ ] with [Vπ ]-lim π₯ = β, say. Then, ππππ π‘ (|π₯ − β|) σ³¨→ 0 This implies that as π, π σ³¨→ ∞, uniformly in π , π‘. π=π+1 ∞ ∞ σ΅¨ σ΅¨ − ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ π=π π=π+1 ∞ + ∑ ∞ σ΅¨ σ΅¨ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ π=π+1 π=π+1 ∞ ∞ ∞ π=π π=π π=π+1 = ∑ [∑ − ∑ ] as π, π σ³¨→ ∞, uniformly in π , π‘. (28) π π 1 ∑ ∑ ππππ π‘ (|π₯ − β|) σ³¨→ 0 (π + 1) (π + 1) π=0 π=0 ∞ ∞ σ΅¨ σ΅¨ − ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ π=π (29) σ΅¨ σ΅¨ × σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ ∞ ∞ ∞ π=π+1 π=π π=π+1 − ∑ [∑ − ∑ ] σ΅¨ σ΅¨ × σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ 6 Abstract and Applied Analysis ∞ σ΅¨ σ΅¨ = ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ π=π Hence, it is left to show that for fixed π, π σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨ ≤ πΎ, σ΅¨ σ΅¨ ∞ σ΅¨ σ΅¨ − ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ From (40), we have π=π+1 ∞ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨ < 1, σ΅¨ σ΅¨ ∞ σ΅¨ σ΅¨ = [ ∑ − ∑ ] σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ π=π π=π+1 σ΅¨ σ΅¨ = σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨ . (34) σ΅¨ σ΅¨ = σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ . By Lemma 3, we have ππππ π‘ + ππππ π‘ − Ω†πππ π‘ − Ω‡πππ π‘ = ππ [ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ ] . (42) for every fixed π > π0 , π > π0 and for all π , π‘. Since π (π + 1) π (π + 1) (ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ ) π Replacing π and π by π and π, respectively, we have Iπππ π‘ − Iπ,π+1,π ,π‘ − Iπ+1,π,π ,π‘ + Iπ+1,π+1,π ,π‘ ∀π , π‘. (41) π = ∑ ∑ ππ (ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ ) . π=1 π=1 (43) (35) Accordingly, ππ [ (π + 1) (π + 1) (36) × (ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ ) − (π − 1) (π + 1) So that we have 1 π π σ΅¨σ΅¨ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨ππππ π‘ + ππππ π‘ − Ω†πππ π‘ − Ω‡πππ π‘ σ΅¨σ΅¨σ΅¨σ΅¨ ππ π=1 π=1 1 π π = ∑ ∑ ππ [Iπππ π‘ − Iπ,π+1,π ,π‘ ππ π=1 π=1 × (ππ−1,π,π ,π‘ − ππ−2,π,π ,π‘ − ππ−1,π−1,π ,π‘ + ππ−2,π−1,π ,π‘ ) − (π + 1) (π − 1) (37) + (π − 1) (π − 1) −Iπ+1,π,π ,π‘ + Iπ+1,π+1,π ,π‘ ] . By using Abel’s transformation for double series in the right hand side of above equation, we have 1 π π σ΅¨σ΅¨ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨ππππ π‘ + ππππ π‘ − Ω†πππ π‘ − Ω‡πππ π‘ σ΅¨σ΅¨σ΅¨σ΅¨ ππ π=1 π=1 π π π 1 = [ ∑ ∑ Iπππ π‘ − π ∑ Iπ+1,π,π ,π‘ ππ π=1 π=1 π=1 × (ππ,π−1,π ,π‘ − ππ−1,π−1,π ,π‘ − ππ,π−2,π ,π‘ + ππ−1,π−2,π ,π‘ ) × (ππ−1,π−1,π ,π‘ − ππ−2,π−1,π ,π‘ − ππ−1,π−2,π ,π‘ + ππ−2,π−2,π ,π‘ ) ] π π π=1 π=1 = ∑ π [ ∑ π (ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ ) π−1 − ∑ π (ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ )] (38) π π=1 π−1 π π=1 π=1 − ∑ π [ ∑ π (ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ ) −π ∑ Iπ,π+1,π ,π‘ + ππIπ+1,π+1,π ,π‘ ] π=1 π−1 → 0 as π, π → ∞, uniformly in π , π‘ (by (32)). Hence, by Lemma 2, π₯ ∈ [Wπ ]. (iii) Let π₯ ∈ WσΈ π , and we have to show that − ∑ π (ππππ π‘ − ππ−1,π,π ,π‘ π=1 ∞ ∞ σ΅¨ σ΅¨ sup ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ ≤ πΎ, π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ ) ] π=0 π=0 (39) where πΎ is an absolute constant. Since π₯ ∈ WσΈ π , there exist integers π0 , π0 such that σ΅¨ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ < 1, ∀π , π‘. π>π0 π>π0 (40) π = ∑ π [π (ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ )] π=1 π−1 − ∑ π [π (ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ )] . π=1 (44) Abstract and Applied Analysis 7 π−1 π π π−1 π−1 π−1 } {π π = { ∑ ∑ ππ − ∑ ∑ ππ − ∑ ∑ ππ + ∑ ∑ ππ} π=1 π=1 π=1 π=1 π=1 π=1 {π=1 π=1 } This implies that (π + 1) (π + 1) (ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ ) ππσΈ − (π − 1) (π + 1) × ( ∑ ∑ ππ’V ) π’=ππ V=βπ × (ππ−1,π,π ,π‘ − ππ−2,π,π ,π‘ − ππ−1,π−1,π ,π‘ + ππ−2,π−1,π ,π‘ ) π π−1 π−1 π π−1 } {π = { ∑ π [ ∑π − ∑ π] − ∑ π [∑π + ∑ π]} π=1 π=1 ] π=1 [π=1 ]} {π=1 [π=1 − (π + 1) (π − 1) × (ππ,π−1,π ,π‘ − ππ−1,π−1,π ,π‘ − ππ,π−2,π ,π‘ + ππ−1,π−2,π ,π‘ ) ππσΈ + (π − 1) (π − 1) βπσΈ × ( ∑ ∑ ππ’V ) × (ππ−1,π−1,π ,π‘ − ππ−2,π−1,π ,π‘ − ππ−1,π−2,π ,π‘ + ππ−2,π−2,π ,π‘ ) π’=ππ V=βπ = [ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ ] . (45) π π−1 π=1 π=1 σΈ ππ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨ ≤ πΎ (π, π) βπσΈ π’=ππ V=βπ (46) (50) Thus, we have σΈ ππ βπσΈ ∑ ∑ ππ’V = (π + 1) (π + 1) ππ,π,π ,π‘ π’=ππ V=βπ π, π = 1, 2, . . . + (π − 1) (π − 1) ππ−1,π−1,π ,π‘ . and π be monotonically increasing. For simplicity in notation, we denote ππππ π‘ = ππππ π‘ (π) − ππ−1,π,π ,π‘ (π) − ππ,π−1,π ,π‘ (π) + ππ−1,π−1,π ,π‘ (π) . (48) ππσΈ βσΈ π π−1 for all π, π ≥ 1 and π0,0,π ,π‘ (π) = ππ π‘ with ππ = π π (π ), βπ = π (π‘) + 1, π (π ) + 1, ππσΈ = π (π‘). Further, we calculate π (π + 1) π (π + 1) ππππ π‘ − π (π − 1) π (π + 1) ππ−1,π,π ,π‘ − π (π + 1) π (π − 1) ππ,π−1,π ,π‘ + π (π − 1) π (π − 1) ππ−1,π−1,π ,π‘ σ΅¨σ΅¨ πσΈ βσΈ σ΅¨σ΅¨ σ΅¨σ΅¨ π π σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ ∑ ∑ ππ’V σ΅¨σ΅¨σ΅¨ ≤ πΎ (π, π) , σ΅¨σ΅¨π’=π V=β σ΅¨ σ΅¨σ΅¨ π π σ΅¨σ΅¨σ΅¨ ∀π , π‘. (52) (53) where πΎ is independent of π’, V. By (49), we have π π π 1 = ∑ ∑ ππ ( ∑ ∑ ππ’V ) (49) π (π + 1) π (π + 1) π=1 π=1 π’=π V=β π Hence, it follows from (46) that for each fixed π > π0 , π > π0 , Hence, it follows from (52) that σ΅¨σ΅¨σ΅¨ππ’V σ΅¨σ΅¨σ΅¨ ≤ πΎ ∀π’, V, σ΅¨ σ΅¨ Again from the definition of ππππ π‘ , it is easy to obtain βπσΈ (51) − (π + 1) (π − 1) ππ,π−1,π ,π‘ (47) π =0 π‘=0 π−1 π’=ππ V=βπ − (π − 1) (π + 1) ππ−1,π,π ,π‘ π π₯ππ = ∑ ∑ππ π‘ , π βπσΈ = ππ ( ∑ ∑ ππ’V ) . for every fixed π > π0 , π > π0 and for all π , π‘, where πΎ(π, π) is a constant depending upon π, π. Now, for any given infinite double series ∑π ∑π‘ ππ π‘ denoted as “π”, let us write ππππ π‘ σΈ ππ = {π ∑ π − π ∑ π} ( ∑ ∑ ππ’V ) Using (42) and (45), we have π βπσΈ = σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨ ≤ πΎ, ∀π, π, π , π‘. Also from (43) and (54), we have σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨ ≤ πΎ, σ΅¨ σ΅¨ (54) ∀π, π, π , π‘. (55) 4. Topological Results Here, we extend the spaces [Wπ ], WσΈ π , WσΈ σΈ π to more general spaces, respectively, denoted by [Wπ (πΌ)], WσΈ π (πΌ), WσΈ σΈ π (πΌ), 8 Abstract and Applied Analysis where πΌ = (πΌππ ) is a double sequence of positive real numbers for all π, π and supπ,π πΌππ = π» < ∞. First, we recall the notion of paranorm as follows. A paranorm is a function π : π → R defined on a linear space π such that for all π₯, π¦, π§ ∈ π Theorem 5. Let πΌ = (πΌππ ) be a bounded double sequence of strictly positive real numbers. Then, [Wπ (πΌ)] is a complete linear topological space paranormed by π (π₯) = sup ( π,π,π ,π‘ (P1) π(π₯) = 0 if π₯ = π , where π = max(1, supπ,π πΌππ ). If πΌ ≥ 1 then [Wπ,πΌ ] is a Banach space and [Wπ,πΌ ] is a πΌ-normed space if 0 < πΌ < 1. (P3) π(π₯ + π¦) ≤ π(π₯) + π(π¦) (P4) If (πΌπ ) is a sequence of scalars with πΌπ → πΌ0 (π → ∞) and π₯π , π ∈ π with π₯π → π (π → ∞) in the sense that π(π₯π − π) → 0 (π → ∞), then πΌπ π₯π → πΌ0 π (π → ∞), in the sense that π(πΌπ π₯π − πΌ0 π) → 0 (π → ∞). A paranorm π for which π(π₯) = 0 implies π₯ = π is called a total paranorm on π, and the pair (π, π) is called a total paranormed space. Note that each seminorm (norm) π on π is a paranorm (total) but converse needs not be true. A paranormed space (π, π) is a topological linear space with the topology given by the paranorm π. Now, we define the following spaces: π 1/π (57) (P2) π(−π₯) = π(π₯) [Wπ (πΌ)] = {π₯ = (π₯ππ ) : π π 1 σ΅¨πΌππ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯)σ΅¨σ΅¨σ΅¨σ΅¨ ) (π + 1) (π + 1) π=0 π=0 Proof. Let (π₯ππ ) and (π¦ππ ) be two double sequences. Then, σ΅¨σ΅¨ σ΅¨πΌ σ΅¨ σ΅¨πΌ σ΅¨ σ΅¨πΌ σ΅¨σ΅¨π₯ππ + π¦ππ σ΅¨σ΅¨σ΅¨ ππ ≤ πΎ (σ΅¨σ΅¨σ΅¨π₯ππ σ΅¨σ΅¨σ΅¨ ππ + σ΅¨σ΅¨σ΅¨π¦ππ σ΅¨σ΅¨σ΅¨ ππ ) , σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨ where πΎ = max(1, 2π»−1 ) and π» = supπ,π πΌππ . Since |π|πΌππ ≤ max (1, |π|π») , (59) therefore π π 1 σ΅¨ σ΅¨πΌππ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (ππ₯ + ππ¦)σ΅¨σ΅¨σ΅¨σ΅¨ (π + 1) (π + 1) π=0 π=0 ≤ πΎπΎ1 1 (π + 1) (π + 1) π π 1 σ΅¨πΌππ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯)σ΅¨σ΅¨σ΅¨σ΅¨ (π + 1) (π + 1) π=0 π=0 + πΎπΎ2 π σ΅¨πΌππ σ΅¨ × ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯ − βπΈ)σ΅¨σ΅¨σ΅¨σ΅¨ σ³¨→ 0, π=0 π=0 (58) (60) π π 1 σ΅¨ σ΅¨πΌππ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π¦)σ΅¨σ΅¨σ΅¨σ΅¨ , (π + 1) (π + 1) π=0 π=0 where πΎ1 = max(1, |π|π») and πΎ2 = max(1, |π|π»). From (60), we have that if π₯, π¦ ∈ [Wπ (πΌ)], then ππ₯+ππ¦ ∈ [Wπ (πΌ)]. Thus, [Wπ (πΌ)] is a linear space. Without loss of generality, we can take as π, π σ³¨→ ∞, uniformly in π , π‘} , [Wπ (πΌ)] -lim π₯ = 0. WσΈ π (πΌ) = {π₯ = (π₯ππ ) : (61) Clearly, π(0) = 0, π(−π₯) = π(π₯). From (58) and Minkowski’s inequality, we have ∞ ∞ σ΅¨ σ΅¨πΌππ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ −ππ−1,π,π ,π‘ −ππ,π−1,π ,π‘ +ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ 1/π π=0 π=0 π π σ΅¨ σ΅¨πΌππ ( ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯ + π¦)σ΅¨σ΅¨σ΅¨σ΅¨ ) π=0 π=0 converges uniformly in π , π‘} , π π σ΅¨πΌππ /π σ΅¨σ΅¨ σ΅¨ σ΅¨πΌππ /π ≤ [ ∑ ∑ (σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯)σ΅¨σ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨ππππ π‘ (π¦)σ΅¨σ΅¨σ΅¨σ΅¨ )] WσΈ σΈ π (πΌ) = {π₯ = (π₯ππ ) : 1/π π=0 π=0 1/π ∞ π π σ΅¨πΌππ σ΅¨ ≤ ( ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯)σ΅¨σ΅¨σ΅¨σ΅¨ ) ∞ σ΅¨ σ΅¨πΌππ sup ∑ ∑σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ −ππ−1,π,π ,π‘ −ππ,π−1,π ,π‘ +ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨σ΅¨ π ,π‘ π=0 π=0 π=0 π=0 1/π π π σ΅¨ σ΅¨πΌππ + ( ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π¦)σ΅¨σ΅¨σ΅¨σ΅¨ ) < ∞} . . π=0 π=0 (62) (56) We remark that if πΌ = (πΌππ ) is a constant sequence, then we write [Wπ,πΌ ] in place of [Wπ (πΌ)]. Hence, π (π₯ + π¦) ≤ π (π₯) + π (π¦) . (63) Abstract and Applied Analysis 9 Since πΌ = (πΌππ ) is bounded away from zero, there exists a constant πΏ > 0 such that πΌππ ≥ πΏ for all π, π. Now for |π| ≤ 1, |π|πΌπ π‘ ≤ |π|πΏ and so π (ππ₯) ≤ |π|πΏ/ππ (π₯) , (64) that is, the scaler multiplication is continuous. Hence, π is a paranorm on [Wπ (πΌ)]. Let (π₯π ) be a Cauchy sequence in [Wπ (πΌ)], that is, π π π (π₯ − π₯ ) σ³¨→ 0 as π, π σ³¨→ ∞. which is proved in the next theorem (i.e., Theorem 7). Using the standard technique as in the previous theorem, we can prove that β is subadditive. Now, we have to prove the continuity of scalar multiplication. Suppose that π₯ = (π₯ππ ) ∈ WσΈ π (πΌ). Then, for π > 0 there exist integers π, π > 0 such that ∞ ∞ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯) − ππ−1,π,π ,π‘ (π₯) π=π π=π Since π π π 1 σ΅¨ σ΅¨πΌππ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯π − π₯π )σ΅¨σ΅¨σ΅¨σ΅¨ ≤ [π (π₯π − π₯π )] , (π + 1) (π + 1) π=0 π=0 (66) If |π| ≤ 1, then by (72) we have ∞ ∞ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (ππ₯) − ππ−1,π,π ,π‘ (ππ₯) π=π π=π σ΅¨πΌππ − ππ,π−1,π ,π‘ (ππ₯) + ππ−1,π−1,π ,π‘ (ππ₯ )σ΅¨σ΅¨σ΅¨σ΅¨ it follows that σ΅¨σ΅¨ σ΅¨πΌ σ΅¨σ΅¨ππππ π‘ (π₯π − π₯π )σ΅¨σ΅¨σ΅¨ ππ σ³¨→ 0 as π, π σ³¨→ ∞ ∀π, π, π , π‘. (67) σ΅¨ σ΅¨ (72) σ΅¨πΌππ − ππ,π−1,π ,π‘ (π₯) + ππ−1,π−1,π ,π‘ (π₯)σ΅¨σ΅¨σ΅¨σ΅¨ < π. (65) ∞ ∞ σ΅¨ ≤ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯) − ππ−1,π,π ,π‘ (π₯) π=π π=π In particular, σ΅¨σ΅¨ σ΅¨ σ΅¨ π π σ΅¨σ΅¨ σ΅¨σ΅¨π0,0,π ,π‘ (π₯π − π₯π )σ΅¨σ΅¨σ΅¨ = σ΅¨σ΅¨σ΅¨π₯π π‘ σ΅¨ σ΅¨ σ΅¨ σ΅¨ − π₯π π‘ σ΅¨σ΅¨ σ³¨→ 0 (68) as π, π σ³¨→ ∞ for fixed π , π‘. Hence, (π₯π ) is a Cauchy sequence in C. Since C is complete, there exists π₯ = (π₯ππ ) ∈ C such that π₯π → π₯ coordinatewise as π → ∞. It follows from (66) that given π > 0, there exists π0 such that 1/π π π 1 σ΅¨ σ΅¨πΌππ ( ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯π − π₯π )σ΅¨σ΅¨σ΅¨σ΅¨ ) (π + 1) (π + 1) π=0 π=0 < π, (69) for π, π > π0 . Now taking π → ∞ and supπ ,π‘,π,π in (69), we have π(π₯π − π₯) ≤ π for π > π0 . This proves that π₯π → π₯ and π₯ = (π₯ππ ) ∈ [Wπ (πΌ)]. Hence [Wπ (πΌ)] is complete. If πΌ is a constant then it is easy to prove the rest of the theorem. Theorem 6. One has the following: WσΈ π (πΌ) is a complete paranormed space, paranormed by ∞ ∞ σ΅¨ β (π₯) = sup ( ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ − ππ−1,π,π ,π‘ π ,π‘ π=0 π=0 σ΅¨σ΅¨πΌππ − ππ,π−1,π ,π‘ + ππ−1,π−1,π ,π‘ σ΅¨σ΅¨σ΅¨ 1/π (70) ) which is defined on WσΈ π (πΌ). If πΌ ≥ 1 then WσΈ π,πΌ is a Banach space and if 0 < πΌ < 1, Wπ,πΌ is πΌ-normed space. Proof. In order for the paranorm in (70) be defined, we require that WσΈ π (πΌ) ⊂ WσΈ σΈ π (πΌ) σ΅¨πΌππ − ππ,π−1,π ,π‘ (π₯) + ππ−1,π−1,π ,π‘ (π₯)σ΅¨σ΅¨σ΅¨σ΅¨ < π. (73) (71) Since for fixed π, π π−1 π−1 σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (ππ₯) − ππ−1,π,π ,π‘ (ππ₯) − ππ,π−1,π ,π‘ (ππ₯) π=0 π=0 σ΅¨σ΅¨πΌππ +ππ−1,π−1,π ,π‘ (ππ₯)σ΅¨σ΅¨σ΅¨ (74) σ³¨→ 0 as π → 0, it follows from (73) and (74) that for fixed π₯ = (π₯ππ ), β(ππ₯) → 0 as π → 0. Also, since |π|πΌππ ≤ max(1, |π|π») implies that 1/π β (ππ₯) ≤ (sup |π|πΌππ ) β (π₯) . (75) It follows that for fixed π, β(ππ₯) → 0 as π₯ → 0. This proves the continuity of scalar multiplication. Hence, β is a paranorm. The proof of the completeness of WσΈ π (πΌ) can be achieved by using the same technique as in Theorem 5. Theorem 7. Suppose that πΌ = (πΌππ ) is bounded double sequence of strictly positive real numbers. Then, (i) WσΈ σΈ π (πΌ) is a complete linear space paranormed by the function β defined in (70). In particular, if πΌ is a constant, WσΈ σΈ π,πΌ is a Banach space for πΌ ≥ 1 and πΌnormed space for 0 < πΌ < 1, (ii) WσΈ π (πΌ) is a closed subspace of WσΈ σΈ π (πΌ). Proof. (i) Proceeding along the same lines as in Theorem 6, except for the proof of continuity of scalar multiplication. If π₯ = (π₯ππ ) ∈ WσΈ σΈ π (πΌ), we cannot assert (72) as in the case when π₯ = (π₯ππ ) ∈ WσΈ π (πΌ). Since πΌ is bounded away from zero, there 10 Abstract and Applied Analysis exists πΏ > 0 such that πΌππ ≥ πΏ for all π, π. Hence, |π| ≤ 1 implies |π|πΌππ ≤ |π|πΏ . Since β (ππ₯) ≤ |π|πΌππ β (π₯) , (76) continuity of scalar multiplication follows. (ii) For this, first we have to show that WσΈ π (πΌ) ⊂ WσΈ σΈ π (πΌ) . (77) Let π₯ = (π₯ππ ) ∈ WσΈ π (πΌ). Then, there exist integers π, π such that ∞ ∞ σ΅¨ ∑ ∑ σ΅¨σ΅¨σ΅¨σ΅¨ππππ π‘ (π₯) − ππ−1,π,π ,π‘ (π₯) − ππ,π−1,π ,π‘ (π₯) π=π π=π (78) σ΅¨πΌππ + ππ−1,π−1,π ,π‘ (π₯)σ΅¨σ΅¨σ΅¨σ΅¨ < 1. By an argument similar to Theorem 4(iii), we obtain (77). Since WσΈ π (πΌ) and WσΈ σΈ π (πΌ) are complete with the same metric, we have (ii). 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