Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2013, Article ID 248740, 7 pages http://dx.doi.org/10.1155/2013/248740 Research Article Dissipative Sturm-Liouville Operators with Transmission Conditions Hüseyin Tuna1 and Aytekin EryJlmaz2 1 2 Department of Mathematics, Mehmet Akif Ersoy University, 15100 Burdur, Turkey Department of Mathematics, Nevsehir University, 50300 Nevsehir, Turkey Correspondence should be addressed to Aytekin EryΔ±lmaz; eryilmazaytekin@gmail.com Received 7 December 2012; Accepted 11 February 2013 Academic Editor: Lucas JoΜdar Copyright © 2013 H. Tuna and A. EryΔ±lmaz. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. In this paper we study dissipative Sturm-Liouville operators with transmission conditions. By using Pavlov’s method (Pavlov 1947, Pavlov 1981, Pavlov 1975, and Pavlov 1977), we proved a theorem on completeness of the system of eigenvectors and associated vectors of the dissipative Sturm-Liouville operators with transmission conditions. 1. Introduction Spectral theory is one of the main branches of modern functional analysis and it has many applications in mathematics and applied sciences. There has recently been great interest in spectral analysis of Sturm-Liouville boundary value problems with eigenparameter-dependent boundary conditions (see [1–14]). Furthermore, many researchers have studied some boundary value problems that may have discontinuities in the solution or its derivative at an interior point π [15–19]. Such conditions which include left and right limits of solutions and their derivatives at π are often called “transmission conditions” or “interface conditions.” These problems often arise in varied assortment of physical transfer problems [20]. The spectral analysis of non-self-adjoint (dissipative) operators is based on ideas of the functional model and dilation theory rather than the method of contour integration of resolvent which is studied by Naimark [21], but this method is not effective in studying the spectral analysis of boundary value problem. The functional model technique acts a part on the fundamental theorem of Nagy-FoiasΜ§. In 1960s independently from Nagy-FoiasΜ§ [22], Lax and Phillips [23] developed abstract scattering programme that is very important in scattering theory. Pavlov’s functional model [24–28] has been extended to dissipative operators which are finite dimensional extensions of a symmetric operator, and the corresponding dissipative and Lax-Phillips scattering matrix was investigated in some detail [5–14, 22–27, 29, 30]. This theory is based on the notion of incoming and outgoing subspaces to obtain information about analytical properties of scattering matrix by utilizing properties of original unitary group. By combining the results of Nagy-FoiasΜ§ and LaxPhillips, characteristic function is expressed with scattering matrix and the dilation of dissipative operator is set up. By means of different spectral representation of dilation, given operator can be written very simply and functional models are obtained. The eigenvalues, eigenvectors and spectral projection of model operator are expressed obviously by characteristic function. The problem of completeness of the system of eigenvectors is solved by writing characteristic function as factorization. The purpose of this paper is to study non-self-adjoint Sturm-Liouville operators with transmission conditions. To do this, we constructed a functional model of dissipative operator by means of the incoming and outgoing spectral representations and defined its characteristic function, because this makes it possible to determine the scattering matrix of dilation according to the Lax and Phillips scheme [23]. Finally, we proved a theorem on completeness of the system of eigenvectors and associated vectors of dissipative operators which is based on the method of Pavlov. While proving our results, we use the machinery of [5, 7–10]. 2 Abstract and Applied Analysis 2. Self-Adjoint Dilation of Dissipative Sturm-Liouville Operator and transmission conditions Consider the differential expression π (π¦) = −π¦σΈ σΈ + π (π₯) π¦, π₯ ∈ [π, π) ∪ (π, π) , (1) where πΌ1 := [π, π), πΌ2 := (π, π) and πΌ = πΌ1 ∪ πΌ2 , π(π₯) is realvalued function on πΌ, and π ∈ πΏ1loc (πΌ). The points π and π are regular and π is singular for the differential expression π(π¦). Moreover π(π±) := limπ₯ → π± π(π₯) one-sided limits exist and are finite. To pass from the differential expression π(π¦) to operators, we introduce the Hilbert space π» = πΏ2 (πΌ1 ) ⊕ πΏ2 (πΌ2 ) with the inner product π π π π β¨π, πβ©π» := πΎ1 πΎ2 ∫ π1 π1 ππ₯ + πΏ1 πΏ2 ∫ π2 π2 ππ₯, π1 (π₯) , π2 (π₯) , π₯ ∈ πΌ1 ∈ π», π₯ ∈ πΌ2 π (π₯) , π (π₯) = { 1 π2 (π₯) , π₯ ∈ πΌ1 ∈ π», π₯ ∈ πΌ2 πΎ1 π (π−, π) , πΏ1 1 π2σΈ (π+, π) = πΎ2 σΈ π (π−, π) , πΏ2 1 π2 (π+, π) = πΎ1 π (π−, π) , πΏ1 1 π2σΈ (π+, π) = πΎ2 σΈ π (π−, π) , πΏ2 1 (7) where πΌ, πΎ1 , πΎ2 , πΏ1 , and πΏ2 ∈ R with πΎ1 πΎ2 > 0 and πΏ1 πΏ2 > 0. The solutions π(π₯, π) and π(π₯, π) belong to π». Let π’ (π₯) = π1 (π₯, 0) , π₯ ∈ πΌ1 π’ (π₯) = { 1 π’2 (π₯) = π2 (π₯, 0) , π₯ ∈ πΌ2 , V (π₯) = π1 (π₯, 0) , π₯ ∈ πΌ1 , V (π₯) = { 1 V2 (π₯) = π2 (π₯, 0) , π₯ ∈ πΌ2 , (2) (3) π’1 (π) = cos πΌ, π’1σΈ (π) = sin πΌ, V1 (π) = − sin πΌ, V1σΈ (π) = cos πΌ π’2 (π+) = πΎ1 π’ (π−) , πΏ1 1 π’2σΈ (π+) = πΎ2 σΈ π’ (π−) , πΏ2 1 V2 (π+) = πΎ1 V (π−) , πΏ1 1 V2σΈ (π+) = πΎ2 σΈ V (π−) . πΏ2 1 π 1 (π¦) : πΎ1 π¦ (π−) − πΏ1 π¦ (π+) = 0, π π π 2 (π¦) : πΎ2 π¦σΈ (π−) − πΏ2 π¦σΈ (π+) = 0, π π π 3 (π¦) : π¦ (π) cos πΌ + π¦σΈ (π) sin πΌ = 0, + πΏ1 πΏ2 [π¦, π§]π − πΏ1 πΏ2 [π¦, π§]π+ , π 4 (π¦) : [π¦, V]π − πΊ[π¦, π’]π = 0, (4) where [π¦, π§]π₯ = π¦(π₯)π§σΈ (π₯) − π¦σΈ (π₯)π§(π₯) (π₯ ∈ πΌ), [π¦, π§]π = limπ₯ → π [π¦, π§]π₯ exists and is finite. Suppose that Weyl’s limit circle case holds for the differential expression π(π¦) on πΌ. There are several sufficient conditions in which Weyl’s limit circle case holds for a differential expression [21]. Denote by π (π₯) , π₯ ∈ πΌ1 π (π₯) = { 1 π2 (π₯) , π₯ ∈ πΌ2 , (5) the solutions of the equation π(π¦) = ππ¦, π₯ ∈ πΌ, satisfying the initial conditions π1 (π, π) = cos πΌ, π1 (π, π) = − sin πΌ, π1σΈ (π, π) = sin πΌ, π1σΈ (π, π) = cos πΌ (6) (10) All the maximal dissipative extensions LπΊ of the operator πΏ 0 are described by the following conditions (see [4, 15, 18]): ∫ π (π¦) π§ ππ₯ − ∫ π¦π (π§) ππ₯ = πΎ1 πΎ2 [π¦, π§]π− − πΎ1 πΎ2 [π¦, π§]π π₯ ∈ πΌ1 π₯ ∈ πΌ2 , (9) and transmission conditions and πΎ1 , πΎ2 , πΏ1 , and πΏ2 are some real numbers with πΎ1 πΎ2 > 0 and πΏ1 πΏ2 > 0. Let πΏ 0 denote the closure of the minimal operator generated by (1) and by π·0 its domain. Besides, we denote the set of all functions π(π₯) from π» such that π, πσΈ ∈ π΄πΆloc (πΌ), π(π±), πσΈ (π±) one-sided limits exist and are finite and π(π¦) ∈ π»; π· is the domain of the maximal operator πΏ. Furthermore, πΏ = πΏ∗0 [21]. For two arbitrary functions π¦(π₯), π§(π₯) ∈ π·, we have Green’s formula π (π₯) , π (π₯) = { 1 π2 (π₯) , (8) π’(π₯), and V(π₯) be solutions of the equation π(π¦) = 0, π₯ ∈ πΌ, satisfying the initial conditions where π (π₯) = { π2 (π+, π) = (11) Im πΊ > 0. Let us add the “incoming” and “outgoing” subspaces π·− = πΏ (−∞, 0) and π·+ = πΏ2 (0, ∞) to π». The orthogonal sum π» = π·− ⊕ π» ⊕ π·+ is called main Hilbert space of the dilation. In the space H, we consider the operator LπΊ on the set Μ π+ β©, π·(LπΊ), its elements consisting of vectors π€ = β¨π− , π¦, generated by the expression 2 Μ π+ β© = β¨π LπΊ β¨π− , π¦, ππ− ππ Μ ,π +β© , π (π¦) ππ ππ (12) satisfying the conditions π− ∈ π21 (−∞, 0), π+ ∈ π21 (0, ∞), Μ = 0, π 2 (π¦) Μ = 0, π 3 (π¦) Μ = 0, [π¦, Μ V]π − πΊ[π¦, Μ π’]π = π¦Μ ∈ π», π 1 (π¦) Μ V]π −πΊ[π¦, Μ π’]π = (πΆ/√πΏ1 πΏ2 )π+ (0), where (πΆ/√πΏ1 πΏ2 )π− (0), [π¦, π21 are Sobolev spaces and πΆ2 := 2 Im πΊ, πΆ > 0. Theorem 1. The operator LπΊ is self-adjoint in H and it is a Μ πΊ(= πΏ πΎ ). self-adjoint dilation of the operator πΏ Abstract and Applied Analysis 3 Proof. We first prove that LπΊ is symmetric in H. Namely, (LπΊπ, π)H − (π, LπΊπ)H = 0. Let π, π ∈ π·(LπΊ), π = Μ π+ β© and π = β¨π− , π§Μ, π+ β©. Then we have β¨π− , π¦, (LπΊπ, π)H − (π, LπΊπ)H Μ π+ β© , β¨π− , π§Μ, π+ β©) = (LπΊ β¨π− , π¦, Μ π+ β© , LπΊ β¨π− , π§Μ, π+ β©) − (β¨π− , π¦, =∫ 0 ∞ −∞ Μ , π§Μ)π» + ∫ ππ+σΈ π+ ππ ππ−σΈ π− ππ + (π (π¦) 0 0 −∫ −∞ =∫ 0 ∞ Μ π (Μπ§))π» − ∫ ππ+σΈ π+ ππ ππ−σΈ π− ππ − (π¦, (13) 0 ∞ −∞ Μ π§Μ]π + ∫ ππ+σΈ π+ ππ ππ−σΈ π− ππ + πΏ1 πΏ2 [π¦, 0 −∫ −∞ ∞ for π¦Μ and Im π < 0. By applying onto the mapping π, we obtain (17), and We obtain by direct computation (14) Thus, LπΊ is a symmetric operator. To prove that LπΊ is self-adjoint, we need to show that LπΊ ⊆ L∗πΊ. Take π = β¨π− , π§Μ, π+ β© ∈ π·(L∗πΊ). Let L∗πΊπ = π∗ = β¨π−∗ , π§Μ∗ , π+∗ β© ∈ H, so that (15) By choosing elements with suitable components as the π ∈ π·(LπΊ) in (15), it is not difficult to show that π− ∈ π21 (−∞, 0), π+ ∈ π21 (0, ∞), π ∈ π·(L), and π∗ = LπΊπ; the operator LπΊ is defined by (12). Therefore (15) is obtained from (LπΊπ, π)H = (π, LπΊπ)H for all π ∈ π·(L∗πΊ). Furthermore, π ∈ π·(L∗πΊ) satisfies the conditions Μ V]π + πΊ[π¦, Μ π’]π = [π¦, πΆ π+ (0) . √πΏ1 πΏ2 √πΏ1 πΏ2 Μ π’]π ) π−πππ β© Μ V]π + πΊ[π¦, ([π¦, πΆ (18) −1 Μ π§Μ]π . = ππ− (0) π− (0) − ππ+ (0) π+ (0) + πΏ1 πΏ2 [π¦, πΆ π− (0) , √πΏ1 πΏ2 For this purpose, we set (LπΊ − ππΌ)−1 π1 π¦Μ = π = β¨π− , π§Μ, π+ β© Μ and hence Μπ(Μπ§) − πΜπ§ = which implies that (LπΊ − ππΌ)π = π1 π¦, −πππ Μ π− (π) = π− (0)π and π+ (π) = π+ (0)π−πππ . Since π ∈ π¦, 1 π·(LπΊ), then π− ∈ π2 (−∞, 0); it follows that π− (0) = 0, Μ V]π − and consequently π§ satisfies the boundary condition [π¦, Μ πΊ), and since point π with Μ π’]π = 0. Therefore π§Μ ∈ π·(πΏ πΊ[π¦, Im π < 0 cannot be an eigenvalue of dissipative operator, Μ πΊ − ππΌ)−1 π¦. Μ Thus we have then π§Μ = (πΏ Μ πΊ − ππΌ) π¦, Μ = β¨0, (πΏ 0 Μ π’]π = Μ V]π + πΊ[π¦, [π¦, π¦Μ ∈ π», Im β < 0. (17) −1 ππ−σΈ π− ππ − ∫ ππ+σΈ π+ ππ (LπΊπ, π)H = (π, L∗πΊπ)H = (π, π∗ )H . −1 −1 Μ πΊ − ππΌ) π¦, Μ π(LπΊ − ππΌ) π1 π¦Μ = (πΏ (LπΊ − ππΌ) π1 π¦Μ 0 Μ π§Μ]π = 0. ππ− (0) π− (0) − ππ+ (0) π+ (0) + πΏ1 πΏ2 [π¦, is self-adjoint dilation of π΅πΊ. To show this, it is sufficient to verify the equality (16) Hence, π·(L∗πΊ) ⊆ π·(LπΊ); that is, LπΊ = L∗πΊ. The self-adjoint operator LπΊ generates on H a unitary group ππ‘ = exp (πLπΊπ‘) (π‘ ∈ R+ = (0, ∞)). Let us denote by π : H → π» and π1 : π» → H the mapping acting Μ π+ β© → π¦Μ and π1 : according to the formulae π : β¨π− , π¦, Μ 0β©. Let ππ‘ := πππ‘ π1 , π‘ ≥ 0, by using ππ‘ . The π¦Μ → β¨0, π¦, family {ππ‘ } (π‘ ≥ 0) of operators is a strongly continuous semigroup of completely nonunitary contraction on π». Let us denote by π΅πΊ the generator of this semigroup: π΅πΊπ¦Μ = Μ The domain of π΅πΊ consists of all limπ‘ → +0 (ππ‘)−1 (ππ‘ π¦Μ − π¦). the vectors for which the limit exists. The operator π΅πΊ is dissipative. The operator LπΊ is called the self-adjoint dilation Μ πΊ; hence LπΊ of π΅πΊ (see [10, 21, 30]). We show that π΅πΊ = πΏ Μ πΊ − ππΌ) (πΏ −1 ∞ −1 = π(LπΊ − ππΌ) π1 = −ππ ∫ ππ‘ π−πππ‘ ππ‘π1 0 ∞ −1 = − π ∫ ππ‘ π−πππ‘ ππ‘ = (π΅πΊ − ππΌ) , Im π < 0, 0 (19) Μ πΊ = π΅πΊ. so this clearly shows that πΏ 3. Functional Model of Dissipative Sturm-Liouville Operator The unitary group {ππ‘ } has an important property which makes it possible to apply it to the Lax-Phillips [23]. It has orthogonal incoming and outgoing subspaces π·− = β¨πΏ2 (−∞, 0), 0, 0β© and π·+ = β¨0, 0, πΏ2 (0, ∞)β© having the following properties: (1) ππ‘ π·− ⊂ π·− , π‘ ≤ 0 and ππ‘ π·+ ⊂ π·+ , π‘ ≥ 0, (2) ∩π‘≤0 ππ‘ π·− = ∩π‘≥0 ππ‘ π·+ = {0}, (3) ∪π‘≥0 ππ‘ π·− = ∪π‘≤0 ππ‘ π·+ = H, (4) π·− ⊥ π·+ . Property (4) is clear. To be able to prove property (1) for π·+ (the proof for π·− is similar), we set Rπ = (LπΊ − ππΌ)−1 . For all π, with Im π < 0 and for any π = β¨0, 0, π+ β© ∈ π·+ , we have π Rπ π = β¨0, 0, −ππ−πππ ∫ ππππ π+ (π ) ππ β© , 0 (20) as Rπ π ∈ π·+ . Therefore, if π ⊥ π·+ , then ∞ 0 = (Rπ π, π)H = −π ∫ π−πππ‘ (ππ‘ π, π)H ππ‘, 0 Im π < 0, (21) 4 Abstract and Applied Analysis which implies that (ππ‘ π, π)H = 0 for all π‘ ≥ 0. Hence, for π‘ ≥ 0, ππ‘ π·+ ⊂ π·+ , and property (1) has been proved. In order to prove property (2), we define the mappings + π : H → πΏ2 (0, ∞) and π1+ : πΏ2 (0, ∞) → π·+ as Μ π+ β© → π+ and π1+ : π → β¨0, 0, πβ©, follows: π+ : β¨π− , π¦, respectively. We take into consider that the semigroup of isometries ππ‘+ := π+ ππ‘ π1+ (π‘ ≥ 0) is a one-sided shift in πΏ2 (0, ∞). Indeed, the generator of the semigroup of the onesided shift ππ‘ in πΏ2 (0, ∞) is the differential operator π(π/ππ) with the boundary condition π(0) = 0. On the other hand, the generator π of the semigroup of isometries ππ‘+ (π‘ ≥ 0) is the operator ππ = π+ LπΊπ1+ π = π+ LπΊβ¨0, 0, πβ© = π+ β¨0, 0, π(π/ππ)πβ© = π(π/ππ)π, where π ∈ π21 (0, ∞) and π(0) = 0. Since a semigroup is uniquely determined by its generator, it follows that ππ‘+ = ππ‘ , and, hence, 2 β ππ‘ π·+ = β¨0, 0, β ππ‘ πΏ (0, ∞)β© = {0} , π‘≥0 (22) π‘≤0 Definition 2. The linear operator π΄ with domain π·(π΄) acting in the Hilbert space π» is called completely non-self-adjoint (or simple) if there is no invariant subspace π ⊆ π·(π΄)(π =ΜΈ {0}) of the operator π΄ on which the restriction π΄ to π is selfadjoint. To prove property (3) of the incoming and outgoing subspaces, let us prove following lemma. Μ πΊ is completely non-self-adjoint Lemma 3. The operator πΏ (simple). ΜπΊ Proof. Let π»σΈ ⊂ π» be a nontrivial subspace in which πΏ σΈ σΈ Μ with domain π·(πΏ Μ ) = induces a self-adjoint operator πΏ πΊ πΊ σΈ σΈ ∗ Μ Μ Μ Μ Μ π» ∩ π·(πΏ πΊ). If π ∈ π·(πΏ πΊ), then π ∈ π·(πΏ πΊ) and π σ΅©σ΅©σ΅© ππΏΜσΈ πΊπ‘ Μσ΅©σ΅©σ΅©2 π ππΏΜσΈ π‘ Μ ππΏΜσΈ πΊπ‘ Μ π π) σ΅©π πσ΅©σ΅© = (π πΊ π, σ΅©π» ππ‘ π» ππ‘ σ΅©σ΅© 2 Μ σΈ πΊ π‘ ππΏ = − πΆ ([π Assume that π (π₯, π) := { π1 (π₯, π) , π₯ ∈ πΌ1 π2 (π₯, π) , π₯ ∈ πΌ2 , 2 (24) π (π₯, π) , π₯ ∈ πΌ1 π (π₯, π) := { 1 π2 (π₯, π) , π₯ ∈ πΌ2 are solutions of π(π¦) = ππ¦ satisfying the conditions π1 (π, π) = cos πΌ, π1σΈ (π, π) = sin πΌ, π1σΈ (π, π) = cos πΌ, π1 (π, π) = − sin πΌ, so the proof is completed. 0= relative to the group {ππ‘ } and has the form HσΈ = β¨0, π»σΈ , 0β©, where π»σΈ is a subspace in π». Therefore, if the subspace HσΈ (and hence also π»σΈ ) was nontrivial, then the unitary group {ππ‘σΈ } restricted to this subspace would be a unitary part of the Μ σΈ of πΏ Μ πΊ to π»σΈ would be group {ππ‘ }, and hence, the restriction πΏ πΊ Μ πΊ is simple, a self-adjoint operator in π»σΈ . Since the operator πΏ σΈ it follows that π» = {0}. The lemma is proved. π2 (π+, π) = πΎ1 π (π−, π) , πΏ1 1 π2σΈ (π+, π) = πΎ2 σΈ π (π−, π) . πΏ2 1 (25) Let us adopt the following notations: πΎ (π) = [π, V]π [π, π’]π , π (π) = − [π, π’]π [π, π’]π , −1 ππΊ (π) = (π (π) πΎ (π) + πΊ) (π (π) πΎ (π) + πΊ) , (26) (27) where π(π) is a meromorphic function on the complex plane C with a countable number of poles on the real axis. Further, it is possible to show that the function π(π) possesses the following properties: Im π(π) ≤ 0 for all Im π =ΜΈ 0, and π(π) = π(π) for all π ∈ C, except the real poles π(π). We set ππ− (π₯, π, π) (23) Μ π’] ) . π, π π» Μ π’]π = 0. Using this result with Consequently, we have [π¦, Μ π’]π = 0, we have [π¦, Μ π’]π = Μ V]π + πΊ[π¦, boundary condition [π¦, Μ 0; that is, π¦(π) = 0. Since all solutions of π(π¦) = ππ¦ belong to πΏ2 (0, ∞), from this it can be concluded that the resolvent Μ πΊ) is a compact operator, and the spectrum of πΏ Μ πΊ is π π (πΏ purely discrete. Consequently, by the theorem on expansion Μ σΈ we obtain in the eigenvectors of the self-adjoint operator πΏ πΊ σΈ Μ π» = {0}. Hence the operator πΏ πΊ is simple. The proof is completed. Let us define π»− = ∪π‘≥0 ππ‘ π·− , π»+ = ∪π‘≤0 ππ‘ π·+ . Lemma 4. The equality π»− + π»+ = H holds. Proof. Considering property (1) of the subspace π·+ , it is easy to show that the subspace HσΈ = H β (π»− + π»+ ) is invariant = β¨π−πππ , πΆ −1 π (π) [(π (π) πΎ (π) + πΊ) [π, π’]π ] π (π₯, π) , √πΏ1 πΏ2 ππΊ (π) π−πππ β© . (28) We note that the vectors ππ− (π₯, π, π) for real π do not belong to the space H. However, ππ− (π₯, π, π) satisfies the equation Lπ = ππ and the corresponding boundary conditions for the operator Lβ . By means of vector ππ− (π₯, π, π), we define the transformaΜ (π) by tion πΉ− : π → π − Μ (π) := (πΉ− π) (π) := π − 1 (π, ππ)H √2π (29) Abstract and Applied Analysis 5 Μ π+ β© in which π− (π), π+ (π), π¦(π₯) on the vectors π = β¨π− , π¦, are smooth, compactly supported functions. Lemma 5. The transformation πΉ− isometrically maps π»− onto πΏ2 (R). For all vectors π, π ∈ π»− the Parseval equality and the inversion formulae hold: ∞ Μ , πΜ ) = ∫ (π, π)H = (π − − πΏ2 −∞ (30) Proof. For π, π ∈ π·− , π = β¨π− , 0, 0β©, π = β¨π− , 0, 0β©, with Paley-Wiener theorem, we have 0 1 1 (π, ππ )H = ∫ π− (π) π−πππ ππ ∈ π»−2 , √2π √2π −∞ (31) and by using usual Parseval equality for Fourier integrals, ∞ (π, π)H = ∫ −∞ ∞ = ∫ −∞ π− (π) π− (π)ππ (32) Μ (π) πΜ (π)ππ = (πΉ π, πΉ π) 2 . π − − − − πΏ Here, π»±2 denote the Hardy classes in πΏ2 (R) consisting of the functions analytically extendible to the upper and lower halfplanes, respectively. We now extend the Parseval equality to the whole of π»− . We consider in π»− the dense set of π»−σΈ of the vectors obtained as follows from the smooth, compactly supported functions in π·− : π ∈ π»−σΈ if π = ππ π0 , π0 = β¨π− , 0, 0β©, π− ∈ πΆ0∞ (−∞, 0), where π = ππ is a nonnegative number depending on π. If π, π ∈ π»−σΈ , then for π > ππ and π > ππ we have π−π π, π−π π ∈ π·− ; moreover, the first components of these vectors belong to πΆ0∞ (−∞, 0). Therefore, since the operators ππ‘ (π‘ ∈ R) are unitary, by the equality πΉ− ππ‘ π = (ππ‘ π, ππ− )H πππ‘ =π (π, ππ− )H = β¨ππΊ (π) π−πππ , π−πππ β© . (36) Μ (π) = (πΉ π)(π) and πΜ (π) = (πΉ π)(π). where π − − − − Μ (π) = π − (π₯, π, π) −1 πΆ π (π) [(π (π) πΎ (π) + πΊ) [π, π’]π ] π (π₯, π) , √πΏ1 πΏ2 Μ (π) πΜ (π) ππ, π − − ∞ 1 Μ (π) π ππ, π= ∫ π π √2π −∞ − We set ππ+ πππ‘ = π πΉ− π, (33) we have (π, π)H = (π−π π, π−π π)H = (πΉ− π−π π, πΉ− π−π π)πΏ2 , Μ π) Μ πΏ2 . (ππππ πΉ− π, ππππ πΉ− π)πΏ2 = (π, (34) (35) By taking the closure (35), we obtain the Parseval equality for the space π»− . The inversion formula is obtained from the Parseval equality if all integrals in it are considered as limits in the integrals over finite intervals. Finally πΉ− π»− = ∪π‘≥0 πΉ− ππ‘ π·− = ∪π‘≥0 ππππ‘ π»−2 = πΏ2 (R); that is, πΉ− maps π»− onto the whole of πΏ2 (R). The lemma is proved. vectors ππ+ (π₯, π, π) for real π do not belong However, ππ+ (π₯, π, π) satisfies the equation We note that the to the space H. Lπ = ππ and the corresponding boundary conditions for the operator Lβ . With the help of vector ππ+ (π₯, π, π), we define Μ (π) by (πΉ π)(π) := π Μ (π) := the transformation πΉ+ : π → π + + + + √ Μ (1/ 2π)(π, ππ )H on the vectors π = β¨π− , π¦, π+ β© in which π− (π), π+ (π), and π¦(π₯) are smooth, compactly supported functions. Lemma 6. The transformation πΉ+ isometrically maps π»+ onto πΏ2 (R). For all vectors π, π ∈ π»+ the Parseval equality and the inversion formula hold: Μ , πΜ ) = ∫ (π, π)H = (π + + πΏ2 ∞ −∞ Μ (π) πΜ (π)ππ, π + + ∞ 1 Μ (π) π+ ππ, π= ∫ π π √2π −∞ + (37) Μ (π) = (πΉ π)(π) and πΜ (π) = (πΉ π)(π). whereπ + + + + Proof. The proof is analogous to Lemma 6. It is obvious that the matrix-valued function ππΊ(π) is meromorphic in C and all poles are in the lower half-plane. From (27), |ππΊ(π)| ≤ 1 for Im π > 0, and ππΊ(π) is the unitary matrix for all π ∈ R. Therefore, it explicitly follows from the formulae for the vectors ππ− and ππ+ that ππ+ = ππΊ (π) ππ− . (38) It follows from Lemmas 6 and 5 that π»− = π»+ . Together with Lemma 5, this shows that π»− = π»+ = H; therefore property (3) has been proved for the incoming and outgoing subspaces. Thus, the transformation πΉ− isometrically maps π»− onto πΏ2 (R) with the subspace π·− mapped onto π»−2 and the operators ππ‘ are transformed into the operators of multiplication by ππππ‘ . This means that πΉ− is the incoming spectral representation for the group {ππ‘ }. Similarly, πΉ+ is the outgoing spectral representation for the group {ππ‘ }. It follows from (38) that the passage from the πΉ− representation of an element Μ (π) = π ∈ H to its πΉ+ representation is accomplished as π + −1 Μ (π). Consequently, according to [22], we have proved ππΊ (π)π − the following. Theorem 7. The function ππΊ(π) is the scattering matrix of the group {ππ‘ } (of the self-adjoint operator LπΊ). 6 Abstract and Applied Analysis Let π(π) be an arbitrary nonconstant inner function (see [19]) on the upper half-plane (the analytic function π(π) and the upper half-plane C+ is called inner function on C+ if |πβ (π)| ≤ 1 for all π ∈ C+ and |πβ (π)| = 1 for almost all π ∈ R). Define πΎ = π»+2 β ππ»+2 . Then πΎ =ΜΈ {0} is a subspace of the Hilbert space π»+2 . We consider the semigroup of operators ππ‘ (π‘ ≥ 0) acting in πΎ according to the formula ππ‘ π = π[ππππ‘ π], π = π(π) ∈ πΎ, where π is the orthogonal projection from π»+2 onto πΎ. The generator of the semigroup {ππ‘ } is denoted by −1 ππ = lim (ππ‘) (ππ‘ π − π) , π‘ → +0 (39) where π is a maximal dissipative operator acting in πΎ and with the domain π·(π) consisting of all functions π ∈ πΎ, such that the limit exists. The operator π is called a model dissipative operator. Recall that this model dissipative operator, which is associated with the names of Lax-Phillips [23], is a special case of a more general model dissipative operator constructed by Nagy and FoiasΜ§ [22]. The basic assertion is that π(π) is the characteristic function of the operator π. Let πΎ = β¨0, π», 0β©, so that H = π·− ⊕ πΎ ⊕ π·+ . It follows from the explicit form of the unitary transformation πΉ− under the mapping πΉ− that 2 H σ³¨→ πΏ (R) , π·− σ³¨→ π»−2 , Μ (π) = (πΉ π) (π) , π σ³¨→ π − − π·+ σ³¨→ ππΊπ»+2 , πΎ σ³¨→ π»+2 β ππΊπ»+2 , corresponding singular measure π must be contained in the set of poles ππΊ(π). But in this case the singular measure π is a simple step function. If we require ππΊ(π) to have no zeros of infinite multiplicity, then π = 0. So the singular factor vanishes. The characteristic function ππΊ(π) of the maximal Μ πΊ has the form dissipative operator πΏ ππΊ (π) := π (π) πΎ (π) + πΊ , π (π) πΎ (π) + πΊ (41) where Im πΊ > 0. Theorem 9. For all the values of πΊ with Im πΊ > 0, except possibly for a single value πΊ = πΊ0 , the characteristic function Μ πΊ is a Blaschke ππΊ(π) of the maximal dissipative operator πΏ Μ product. The spectrum of πΏ πΊ is purely discrete and belongs Μ πΊ(πΊ =ΜΈ πΊ0 ) has a to the open upper half-plane. The operator πΏ countable number of isolated eigenvalues with finite multiplicity and limit points at infinity. The system of all eigenvectors and Μ πΊ is complete in the space π». associated vectors of the operator πΏ Proof. From (35), it is clear that ππΊ(π) is an inner function in the upper half-plane, and it is meromorphic in the whole complex π-plane. Therefore, it can be factored in the form ππΊ (π) = ππππ π΅πΊ (π) , π = π (πΊ) ≥ 0, (42) where π΅πΊ(π) is a Blaschke product. It follows from (42) that (40) Μ ) (π) = ππππ‘ π Μ (π) . ππ‘ σ³¨→ (πΉ− ππ‘ πΉ−−1 π − − Μ πΊ is unitarily equivaThe formulas (40) show that operator πΏ lent to the model dissipative operator with the characteristic function ππΊ(π). We have thus proved the following theorem. Theorem 8. The characteristic function of the maximal dissiΜ πΊ coincides with the function ππΊ(π) defined pative operator πΏ by (27). 4. The Spectral Properties of Dissipative Sturm-Liouville Operators By using characteristic function, the spectral properties of the Μ πΊ(πΏ πΎ ) can be investigated. The maximal dissipative operator πΏ characteristic function of the maximal dissipative operator Μ πΊ is known to lead to information of completeness about the πΏ spectral properties of this operator. For instance, the absence of a singular factor π (π) of the characteristic function ππΊ(π) in the factorization det ππΊ(π) = π (π)π΅(π) (π΅(π) is a Blaschke product) ensures completeness of the system of eigenvectors Μ πΊ(πΏ πΎ ) in the space and associated vectors of the operator πΏ πΏ 2 (0, ∞) (see [10, 21, 30]). If the characteristic function ππΊ(π) has nontrivial singular factor, the system of eigenvectors Μ πΊ(πΏ πΎ ) can fail to and associated vectors of the operator πΏ be complete. Because ππΊ(π) is smooth, the support of the σ΅¨ σ΅¨ πππ σ΅¨ σ΅¨ σ΅¨ σ΅¨σ΅¨ −π(πΊ) Im π , σ΅¨σ΅¨ππΊ (π)σ΅¨σ΅¨σ΅¨ = σ΅¨σ΅¨σ΅¨σ΅¨π σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨π΅πΊ (π)σ΅¨σ΅¨σ΅¨ ≤ π Im π ≥ 0. (43) Further, expressing ππΊ(π) := π(π)πΎ(π) in terms of ππΊ(π), we find from (35) that ππΊ (π) = πΊππΊ (π) − πΊ . 1 − ππΊ (π) (44) For a given value πΊ (Im πΊ > 0), if π(πΊ) > 0, then (43) implies that limπ‘ → +∞ ππΊ(ππ‘) = 0, and then (44) gives us that limπ‘ → +∞ ππΊ(ππ‘) = πΊ0 . 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