A.6 Complex
Numbers & Solving
Equations
It is our choices…who show who we really are, far more
than our abilities.
-Albus Dumbledore
Solving Equations
Let’s recall solving the following equation.
x2 4 0
If we extend our number system to include complex numbers,
we can solvethe previous equation. How cool is that!
If N is a positive real number, we define the principal square
root of –N, denoted by N , as
N Ni
x 1 i
x 4 2i
x 8 2 2i
N In Complex Number System
Evaluate the square root of the following negative numbers
in the complex number system.
1)
3
2)
18
Equations in Complex Number System
Solve the following equations in the complex number system.
x2 9 0
4 x 2 8 x 16 0
Equations in Complex Number System
Solve the following equations in the complex number system.
2x 3 3x 2 6x 9 0
x 6x 12x 0
3
2
x 3 27 0
10x 2 6x 1 0
Equations in Complex Number System
2x 3 3x 2 6x 9 0
x 3 , 3i
2
x 3 6x 2 12x 0
x 0, 3 3i
3
x 3, 3i
2
3 i
x
10
x 27 0
3
10x 2 6x 1 0
Now that we have extended our number system to include
as many solutions as the
complex numbers, we should get
trying to solve!
degree of the polynomial we are
Character of Solutions
For the equation ax 2 bx c 0
b 2 4ac 0 the equation has two unequal real solutions
2
b 4ac 0 the equation has a repeated real solution
the equation has two complex solutions that
b 4ac 0 are not real and are conjugates of each other
2
Now look at your worksheet for determining the character of
the equations!
Character of Solutions
Ex. x 6 x 13 0
2
b 2 4ac 0 the equation has two unequal real solutions
b 2 4ac 0 the equation has a repeated real solution
b 2 4ac 0
the equation has two complex solutions that
are not real and are conjugates of each other
A.6 Complex
Numbers & Solving
Equations
Homework #9:
p.1008
#55 – 71 EOO, 73
STUDY GUIDE DUE
MONDAY!!
Challenge Problem
Due Tuesday
It is our choices…who show who we really are, far more
than our abilities.
-Albus Dumbledore