8-5 Exponential & Logarithmic Equations Objectives: Solve exponential equations.

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

8-5 Exponential & Logarithmic

Equations

Objectives:

• Solve exponential equations.

Solve logarithmic equations.

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

Check Skills You'll Need

Evaluate each logarithm.

1. log

9

81 log

9

3 2. log 10 log

3

9

3. log

2

16

÷

log

2

8 4. Simplify 125

­ 2

3

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

Solving Exponential Equations

An equation of the form b cx =a, where the exponent includes a variable, is an exponential equation .

If m and n are positive and m = n, then log m = log n.

Therefore, you can solve an exponential equation by taking the logarithm of each side of the equation.

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

Example #1: Solving an Exponential Equation

Solve 7 3x = 20.

7 3x = 20 log 7 3x = log 20

3x log 7 = log 20 x = log 20

3log 7 x ≈ 0.5132

Take the common logarithm of each side.

Use the power property of logarithms.

Divide each side by 3 log 7.

Use a calculator.

Check: 7 3x = 20

7 3(0.5132) = 20

20.00382 ≈ 20

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

Example #2: Solve each equation. Round to the nearest ten-thousandth. Check your answers.

a. 3 x = 4 b. 6 2x = 21 c. 3 x+4 = 101

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

Solving Logarithmic Equations

To evaluate a logarithm with any base, you can use the

Change of Base Formula.

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

Example #3: Using the Change of Base Formula

Use the Change of Base Formula to evaluate log

3

15.

log

3

15 = log 15 log 3

≈ 2.4650

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

Example #4: Evaluate log

5

400.

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

An equation that includes a logarithmic expression, such as log

3

15 = log

2 x is called a logarithmic equation.

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

Example #5: Solving a Logarithmic Equation

Solve log (3x + 1) = 5.

log (3x + 1) = 5

3x + 1 = 10 5

3x + 1 = 100,000

3x = 99,999

x = 33,333

Check: log (3x + 1) = 5 log (3(33,333) + 1) = 5 log (100,000) = 5

log 10 5 = 5

5 = 5

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

Example #6: Solve log (7 ­ 2x) = ­ 1.

Check your answer.

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

Example #7: Using Logarithmic Properties to Solve an Eqauation

Solve 2 log x

­

log 3 = 2.

2 log x

­

log 3 = 2

(  )

3

2

log = 2

Write as a single logarithm.

x 2

= 10 2

Write in exponential form.

3

x 2 = 3(100) x =

±

10

3 ≈

±

17.32

Log x is defined only for x>0, so the solution is 10 √ 3 or about 17.32.

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8­5 Exponential and Logarithmic Equations 2011

Example #8: Solve log 6 ­ log 3x = ­ 2.

April 29, 2011

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8­5 Exponential and Logarithmic Equations 2011 April 29, 2011

Homework: page 464

(1 - 12, 23, 25 - 32 evaluate, 33 - 45)

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