6­3 Day 2 Dividing Polynomials January 21, 2010 6.3 Dividing Polynomials Day 2 Objective: Divide polynomials using synthetic division. Jan 8­9:41 AM 1 6­3 Day 2 Dividing Polynomials January 21, 2010 Check Skills You'll Need Simplify and write in standard form. 1. 5x - 2x2 + 9 + 4x3 2. 10 + 5x3 - 9x2 - 8x3 3. 3x + x2 - x + 7 - 2x2 4. -4x4 - 7x2 + x3 + x4 Jan 8­9:46 AM 2 6­3 Day 2 Dividing Polynomials January 21, 2010 Review: Use long division to divide 2x2 - 19x + 24 by x - 8. Is x - 8 a factor of 2x2 - 19x + 24? Jan 8­9:46 AM 3 6­3 Day 2 Dividing Polynomials January 21, 2010 Synthetic Division If you are dividing a polynomial by a linear polynomial you can use a shortcut called synthetic division. Yea we love shortcuts!! Jan 8­10:31 AM 4 6­3 Day 2 Dividing Polynomials January 21, 2010 Example #1: Divide 2x3 - x2 + 3 by x - 3. dividend divisor Step 1: Write the dividend in descending powers of x. Then copy the coefficients, remembering to insert a zero for any missing powers of x. 2 -1 0 3 Row 1 Step 2: Insert the usual division symbol. In synthetic division the divisor is of the form x - c, and c is the number placed to the left of the division symbol. Here we insert 3. 3 2 -1 0 3 Row 1 Nov 18­2:14 PM 5 6­3 Day 2 Dividing Polynomials January 21, 2010 Example #1: Divide 2x3 - x2 + 3 by x - 3. Step 3: Bring the 2 down two rows, and enter it in row 3. 3 2 -1 0 3 Row 1 Row 2 2 Row 3 Step 4: Multiply the latest entry in row 3 by the divisor (3 in this case), and place the result in row 2, one column over to the right. 3 2 2 -1 6 x3 0 3 Row 1 Row 2 Row 3 Nov 18­2:14 PM 6 6­3 Day 2 Dividing Polynomials January 21, 2010 Example #1: Divide 2x3 - x2 + 3 by x - 3. Step 5: Add the entry in row 2 to the entry above it in row 1, and enter the sum in row 3. 3 2 2 x3 -1 6 5 0 3 Row 1 Row 2 Row 3 Step 6: Repeat Steps 4 and 5 until no more entries are available in row 1. 3 2 2x 3 -1 0 3 Row 1 6 15 45 Row 2 3 3 5x 15x 48 Row 3 Nov 18­2:14 PM 7 6­3 Day 2 Dividing Polynomials January 21, 2010 Example #1: Divide 2x3 - x2 + 3 by x - 3. Step 7: The final entry in row 3 is the remainder, the other entries are the coefficients in descending order of a polynomial whose degree is one less than that of the dividend. 3 2 2x 3 -1 0 3 Row 1 6 15 45 5x 3 15x 3 48 Row 2 Row 3 Quotient = 2x2 + 5x + 15 Remainder = 48 ***The Quotient is a factor of the Dividend if the Remainder is ZERO!! Nov 18­2:14 PM 8 6­3 Day 2 Dividing Polynomials January 21, 2010 Example #2: Use synthetic division to divide 3x3 - 4x2 + 2x - 1 by x + 1. Is x + 1 a factor of 3x3 - 4x2 + 2x - 1? Jan 8­9:49 AM 9 6­3 Day 2 Dividing Polynomials January 21, 2010 Example #3: Use synthetic division to divide x3 + 4x2 + x - 6 by x + 1. Is x + 1 a factor of x3 + 4x2 + x - 6? Jan 8­9:49 AM 10 6­3 Day 2 Dividing Polynomials January 21, 2010 Example #4: Use synthetic division to divide x3 - 2x2 - 5x + 6 by x + 2. Is x + 2 a factor of x3 - 2x2 - 5x + 6? Jan 8­9:49 AM 11 6­3 Day 2 Dividing Polynomials January 21, 2010 Homework: page 324 (13 - 22, 48 - 51) Homework is Jan 8­2:01 PM 12