Physical Chemistry Lecture 15 Mathematics of State Functions, with an Emphasis on Entropy State functions State functions have exact differentials dU dH dS ∂U = dT ∂T V ∂H = dT ∂T V ∂S = dT ∂T V ∂U + dV ∂V T ∂H + dV ∂V T ∂S + dV ∂V T Must evaluate derivatives to allow calculation of changes Partial derivatives of state functions Internal energy ∂U ∂T V = CV ∂H ∂T P = CP Enthalpy Temperature derivatives of entropy General form dS Constant volume CV dU = dS = dT T T Constant pressure dH CP = dS = dT T T = dqrev T CV ∂S = ∂T V T CP ∂S = ∂T P T Volume derivative of entropy Use definitions of energy changes dU dU = TdS = CV dT − PdV ∂P + T − P dV ∂T V Setting these equal and rearranging dS = CV dT T ∂P P P + − + dV ∂T V T T Identification gives = ∂S ∂V T CV dT T ∂P + dV ∂T V ∂P = ∂T V Pressure derivative of entropy Use definitions of enthalpy change dH dH = TdS = C P dT + VdP ∂V + V − T dP ∂T P Setting these equal and rearranging dS = CP dT T V ∂V V + − − dP = T ∂T P T Identification gives ∂S ∂P T CP dT T ∂V − dP ∂T V ∂V = − ∂T P State functions Any state function can be a function of any two other state variables S = S (T , V ) S S S = S (T , P) = S ( P, V ) = S (U , V ) Each state function is a natural function of two specific variables Calculation of entropy changes Just like calculations of other statefunction changes Integrate appropriate derivatives over the range to find the change in entropy ∂P ∫V ∂T V dV 1 V2 ∆S = ∆S ∂V = − ∫ dP ∂T P P1 P2 Example calculation: entropy of mixing of ideals gases Process: two separated gases are allowed to intermingle Entropy is calculated as a sum of entropy of each component ∆S = ∆S A + ∆S B Entropy of mixing of ideal gases Temperature is constant Consider volume change of a gas V final ∆Si ∂Si = ∫ dV ∂V Vinitial T V final R dV = ∫ V Vinitial T V final ∂P = ∫ dV ∂T V Vinitial V final = R ln Vinitial Entropy of mixing of ideal gases The entropy change for the system is the sum of the entropy changes for the two gases ∆S = ∆S A + ∆S B VA + VB VA + VB + R ln = R ln VB VA This is a positive quantity: mixing is a spontaneous process Entropy change upon a phase change Phase changes occur at a specific temperature, Tφ Phase change is accompanied by a change in the enthalpy, ∆Hφ, called the latent enthalpy of transition Entropy change ∆Sφ = ∆H φ Tφ Examples of entropy of transition Melting of water Tf = 273.15 K; ∆Hf =6.01 kJ/mole ∆Sf = 22.0 J/K-mole Vaporization of water Tf = 373.15 K; ∆Hf =40.66 kJ/mole ∆Sf = 109 J/K-mole Summary Evaluate derivatives to determine statefunction changes Some derivatives are measured quantities CP, CV, α, κT etc. Others determined from equation of state Entropy derivatives are determined from definitions of reversible heat Calculate changes by integration of derivatives Entropy changes at phase transitions evaluated by the definition of entropy