Electronic Journal of Differential Equations, Vol. 2012 (2012), No. 82, pp. 1–12. ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu ftp ejde.math.txstate.edu SOLITARY WAVES FOR THE COUPLED NONLINEAR KLEIN-GORDON AND BORN-INFELD TYPE EQUATIONS FEIZHI WANG Abstract. In this article we study the existence of solutions for a nonlinear Klein-Gordon-Maxwell equation coupled with a Born-Infeld equation. 1. Introduction It is well known that the gauge potential (φ, A) can be coupled to a complex order parameter ψ through the minimal coupling rule; that is the formal substitution ∂ ∂ 7→ + ieφ, ∂t ∂t ∇ 7→ ∇ − ieA, where e is the electric charge, A : R3 × R → R3 is a magnetic vector potential and φ : R3 ×R → R is an electric potential. Therefore, in a flat Minkowskian space-time with metric (gµν ) = diag[1, −1, −1, −1], we can define the Klein-Gordon-Maxwell Lagrangian density 1 1 ∂ψ LKGM = | + ieφψ|2 − |∇ψ − ieA|2 − m2 |ψ|2 + |ψ|q , 2 ∂t q where m ≥ 0 represents the mass of the charged field. The total action of the system is thus given by ZZ S= (LKGM + Lemf ) dx dt, (1.1) where Lemf is the Lagrangian density of the electro-magnetic field. In the BornInfeld theory (see [8]), with a suitable choice of constants, Lemf can be written as r b2 1 1 − 1 − 2 (|E|2 − |B|2 ) , Lemf = LBI := 4π b where b is the so-called Born-Infeld parameter, b 1. By the Maxwell equations, ∂A E = −∇φ − ∂t 2000 Mathematics Subject Classification. 35J15. Key words and phrases. Nonlinear Klein-Gordon; Born-Infeld type equation; electrostatic solitary wave; critical points. c 2012 Texas State University - San Marcos. Submitted December 22, 2011. Published May 23, 2012. Supported by grant ZR2011AL009 from the Shandong Province Natural Science Foundation. 1 2 F. WANG EJDE-2012/82 is the electric field, and B=∇×A is the magnetic induction field. If, as in [4], we consider the electrostatic solitary wave: ψ(x, t) = u(x)e−iωt , A = 0, φ = φ(x), where u : R3 → R and ω ∈ R, then the total action in (1.1) takes the form Z Z 1 1 2 |Du| dx + m2 − (eφ − ω)2 u2 dx FBI (u, φ) = 2 R3 2 R3 r Z Z 1 1 b2 q − |u| dx − 1 − 1 − 2 |∇φ|2 dx. q R3 4π R3 b (1.2) The critical point (u, φ) of FBI satisfies the Euler-Lagrange equations associted to (1.2). By standard calculations, we obtain: −∆u + [m2 − (φ − ω)2 ]u = |u|q−2 u, ∇φ ∇· q 1− = 4π(φ − ω)u2 , 1 2 b2 |∇φ| in R3 , in R3 , (1.3) where we have taken e = 1. We can see that the sign ω is not relevant for the existence of solutions for problem (1.3). In fact, if (u, φ) is a solution of (1.3) with ω, then (u, −φ) is also a solution corresponding to −ω. So, without loss of generality, we can assume ω > 0. As we know, a large number of works have been devoted to the problem like (1.3). In the following we review some assumptions and the corresponding results. In [2, 3, 4, 5, 6, 7, 9, 10, 15], the authors consider the first-order expansion of the second formula of (1.3) for b → +∞. Therefore (1.3) becomes −∆u + [m2 − (φ − ω)2 ]u = |u|q−2 u, ∆φ = 4π(φ − ω)u2 , in R3 , in R3 . (1.4) About the problem (1.4), the pioneering work is given by Benci and Fortunato [4]. They showed that (1.4) has infinitely many solutions when q ∈ (4, 6) and 0 < ω < m. In [10] d’Aprile and Mugnai proved the existence of nontrivial solutions of (1.4) whenever q ∈ (2, 4] and q−2 2 m > ω2 . 2 d’Aprile and Mugnai [9] also showed that (1.4) has no nontrivial solutions when q ≥ 6 and 0 < ω ≤ m or q ≤ 2. Recently, in [2], under the following conditions: (q − 2)(4 − q)m2 > ω 2 , m > ω > 0, p ∈ (2, 3), p ∈ [3, 6), Azzollini, Pisani and Pomponio showed that (1.4) admits a nontrivial solution. It is easy to see that (p − 2)(4 − p) > (p − 2)/2 for p ∈ (2, 3]. In [11, 12, 14], the authors consider the second-order expansion of the second formula of (1.3) for b → +∞. Therefore (1.3) becomes −∆u + [m2 − (φ − ω)2 ]u = |u|q−2 u, ∆φ + β2 ∆4 φ = 4π(φ − ω)u2 , in R3 , in R3 , (1.5) EJDE-2012/82 SOLITARY WAVES 3 where β2 = 1/(2b2 ) → 0 and ∆4 φ = D(|Dφ|2 Dφ). In [12], Fortunato, Orsina and Pisani showed the existence of electrostatic solutions with finite energy, while in [11] d’Avenia and Pisani proved that (1.5) has infinitely many solutions, provided that 4 < q < 6 and 0 < ω < m. In [14] Mugnai established the same results under the following assumptions: 4 ≤ q < 6 and 0 < ω < m or 2 < q < 4 and q−2 2 m > ω2 . 2 Recently, Yu [18] studied the original Born-Infeld equations, i.e. (1.3). He proved the existence of the least-action solitary waves in both bounded smooth domain case and R3 case whenever q ∈ (2, 6) and q−2 2 m > ω2 . q In the present paper we consider the nonlinear Klein-Gordon equations coupled with the N -th order expansion of the second formula of (1.3) for b → +∞: −∆u + [m2 − (φ − ω)2 ]u = |u|q−2 u, N X (βk ∆2k φ) = 4π(φ − ω)u2 , in R3 , in R3 , (1.6) k=1 1 and ∆2k φ = D(|Dφ|2k−2 Dφ), for k = where β1 = 1, βk = 1·3·5...(2k−3) 2k−1 (k−1)! b2(k−1) 2, 3, . . . , N . It is well-known that H 1 (R3 ) is the usual Sobolev space endowed with the norm Z 1/2 kukH 1 (R3 ) = [|Du|2 + u2 ] dx R3 (see [1], [17, Theorem 1.8]). D (R ) denotes the completion of C0∞ (R3 , R) with respect to the norm 1/(2N ) 1/2 Z Z 2 |Dφ|2N dx . |Dφ| dx + kφkDN (R3 ) = N R3 3 R3 By a solution (u, φ) of (1.6), we understand (u, φ) ∈ H 1 (R3 ) × DN (R3 ) satisfying (1.6) in the weak sense. Obviously, (u, φ) = (0, 0) is a trivial solution of (1.6). We define a functional FN : H 1 (R3 ) × DN (R3 ) → R by Z N 1 1 1 X 1 1 FN (u, φ) = |Du|2 − βk |Dφ|2k + (m2 − (φ − ω)2 )u2 − |u|q dx . 4π 2k 2 q R3 2 k=1 It is easy to see that FN ∈ C 1 (H 1 (R3 ) × DN (R3 ), R). Therefore solutions of (1.6) correspond to critical points of the functional FN . Next we give our main result. Theorem 1.1. Problem (1.6) has at least a nontrivial solution (u, φ) ∈ H 1 (R3 ) × DN (R3 ), provided one of the following conditions is satisfied (i) q ∈ (3, 6) and m > ω > 0. (ii) q ∈ (2, 3] and (q − 2)(4 − q)m2 > ω 2 > 0. R 1 3 Set |u|q := { R3 |u|q dx}1/q for 1 < q < ∞. We say that {un } ⊂ H (R ) is a 1 1 3 Palais-Smale sequence for Φ ∈ C H (R ), R at level c ∈ R (the (P S)c -sequence for short), if and only if {un } satisfies Φ(un ) → c and Φ0 (un ) → 0 as n → ∞. To find the critical points of the functional FN (u, φ) we will overcome two difficulties. The first difficulty is that FN (u, φ) is strongly indefinite (unbounded both 4 F. WANG EJDE-2012/82 from below and from above on infinite dimensional subspaces). To avoid this difficulty, we use the reduction method just like in [12, 11, 14]. The reduction method consists in reducing the study of FN (u, φ) to the study of a functional J(u) in the only variable u. The second difficulty is that the embedding of H 1 (R3 ) into Lq (R3 ) is not compact, where 2 < q < 2∗ (= 6). So J(u) does not in general satisfy the Palais-Smale condition. We will study J(u) in Hr1 (R3 ), where Hr1 (R3 ) = {u ∈ H 1 (R3 ) : u(x) = u(|x|)}. By the Principle of symmetric criticality (see [16] or [17, Theorem 1.28]), a critical point u ∈ Hr1 (R3 ) for J(u) is also a critical point in H 1 (R3 ). We construct a bounded (P S)c -sequence following the methods of Jeanjean [13]. Then there exists a subsequence of {un } which converges strongly in Hr1 (R3 ). This paper is organized as follows: in Section 2, we make some preliminaries; in Section 3, we obtain that the solutions of (1.6) must verify some suitable Pohožaev identity; in Section 4, we give the proof of Theorem 1.1. 2. Preliminaries In the following we give some lemmas, whose similar proofs can be founded in [9, 11, 14]. Lemma 2.1. For every u ∈ H 1 (R3 ) there is a unique φ = Φ(u) ∈ DN (R3 ) which solves N X (βk ∆2k φ) = 4π(φ − ω)u2 . (2.1) k=1 Lemma 2.2. For any u ∈ H 1 (R3 ), on the set {x ∈ R3 : u(x) 6= 0}, 0 ≤ Φ(u) ≤ ω. Proof. Set Φ− = min{Φ, 0}. Multiplying (2.1) by Φ− , we have Z Z N Z 1 X − βk |DΦ− |2k dx = (Φ− )2 u2 dx − ω Φ− u2 dx ≥ 0. 4π 3 3 3 R R R k=1 So we obtain DΦ− ≡ 0. Hence, Φ ≥ 0. When we multiply (2.1) by (Φ(u) − ω)+ = max{Φ(u) − ω, 0}, we obtain Z Z N 1 X (Φ(u) − ω)2 u2 dx = − βk |DΦ(u)|2k dx ≥ 0, 4π Φ(u)≥ω Φ(u)≥ω k=1 + so that (Φ(u) − ω) = 0 for u 6= 0. Hence Φ(u) ≤ ω. Lemma 2.3. The pair (u, φ) ∈ H 1 (R3 ) × DN (R3 ) is a solution of (1.6) if and only if u is a critical point of Z h N 1 1 X 1 2 JN (u) := FN (u, Φ(u)) = |Du| − βk |DΦ(u)|2k 2 4π 2k 3 R k=1 Z i 1 2 1 + (m − (Φ(u) − ω)2 )u2 − |u|q dx 2 q R3 and φ = Φ(u). EJDE-2012/82 SOLITARY WAVES 5 The functional of (1.6) is N 1 X 1 βk |Dφ|2k 4π 2k R3 2 k=1 Z i 1 1 + (m2 − (φ − ω)2 )u2 − |u|q dx. 2 q R3 Z FN (u, φ) = h1 |Du|2 − From Lemma 2.1, for fixed u ∈ H 1 (R3 ), we have − Z Z N Z 1 X βk |DΦ(u)|2k dx = Φ2 (u)u2 dx − ω Φ(u)u2 dx, 4π R3 R3 R3 k=1 where Φ(u) appears in Lemma 2.1. Then JN (u) = FN (u, Φ(u)) Z Z Z 1 ω 1 |Du|2 dx + (m2 − ω 2 ) Φ(u)u2 dx u2 dx + = 2 R3 2 2 R3 R3 Z N 1Z 1 X k − 1 2k + βk |DΦ(u)| dx − |u|q dx. 4π 2k q R3 R3 k=2 By the definition of JN (u), we have Z Z Z 0 hJN (u), ui = |Du|2 dx + (m2 − ω 2 ) u2 dx − Φ2 (u)u2 dx 3 3 3 R R R Z Z 2 q + 2ω Φ(u)u dx − |u| dx. R3 R3 From Lemmas 2.1 and 2.3, to obtain a solution of (1.6), we need only to find a critical point of JN in H 1 (R3 ). Note that the functional JN depends only on u. Set Hr1 (R3 ) = {u ∈ H 1 (R3 ) : u(x) = u(|x|)}. By standard arguments (Principle of symmetric criticality) one sees that a critical point u ∈ Hr1 (R3 ) for the functional JN in Hr1 (R3 ) is also a critical point for JN in H 1 (R3 ). 3. The Pohožaev identity In this section we obtain that the solutions of (1.6) must verify some suitable Pohožaev identity, as was proved in [9], which provides necessary conditions to prove the existence of nontrivial solutions. 2 2k Lemma 3.1. Let u ∈ Hloc (Rn ), φ ∈ Hloc (Rn ) and a, b ≥ 0. Then, for any ball n BR = {x ∈ R : |x| ≤ R > 0}, the following equalities hold: Z −∆uhx, Dui dx BR Z Z Z (3.1) 2−n 1 R = |Du|2 dx − hx, Dui2 dσ + |Du|2 dσ; 2 R ∂BR 2 ∂BR BR 6 F. WANG EJDE-2012/82 Z (a + bφ)φuhx, Dui dx Z a + bφ u2 hx, Dφi dx =− BR 2 Z Z n R 2 − (a + bφ)φu dx + (a + bφ)φu2 dσ; 2 BR 2 ∂BR Z Z Z g(u)hx, Dui dx = −n G(u) dx + R G(u)dσ; BR BR ∂BR Z Z ∆2k φ hx, Dφi dx = D(|Dφ|2k−2 Dφ)hx, Dφi dx BR BR Z Z R n − 2k |Dφ|2k dx − |Dφ|2k dσ = 2k 2k BR ∂BR Z 1 2k−2 2 |Dφ| hx, Dφi dσ, + R ∂BR BR (3.2) (3.3) (3.4) where ∆2k φ = D(|Dφ|R2k−2 |Dφ|) and g : R → R is a continuous function such that s g(0) = 0 and G(s) = 0 g(t) dt. Proof. The proofs of (3.1), (3.2) and (3.3) can be found in [9, Lemma 3.1]. In the following we show (3.4). For fix i1 , . . . , ik−1 , j, l = 1, 2, . . . , n, we see from the integration by parts formula that Z φ2xi1 . . . φ2xi φxj xj xl φxl dx k−1 BR Z Z xj =− (φ2xi1 . . . φ2xi xl φxl )xj φxj dx + φ2xi1 . . . φ2xi xl φxl φxj dσ k−1 k−1 |x| B ∂B Z R Z R (φ2xi1 . . . φ2xi )xj xl φxl φxj dx − φ2xi1 . . . φ2xi φxl φxj δlj dx =− k−1 k−1 BR BR Z Z xj − φ2xi1 . . . φ2xi xl φxl xj φxj dx + φ2xi1 . . . φ2xi xl φxl φxj dσ, k−1 k−1 |x| BR ∂BR where dσ indicates the (n − 1)-dimensional area element in ∂BR and δlj are the Kroneker symbols. Summing up for i1 , . . . , ik−1 , j, l = 1, 2, . . . , n, we have Z |Dφ|2k−2 ∆φhx, Dφi dx BR Z Z =− hD|Dφ|2k−2 , Dφihx, Dφi dx − |Dφ|2k dx (3.5) B B Z R Z R 1 |Dφ|2k−2 hx, D2 φDφi dx + |Dφ|2k−2 hx, Dφi2 dσ. − R BR ∂BR Similarly, for fix i1 , . . . , ik−1 , j, l = 1, 2, . . . , n, we see from the integration by parts formula that Z Z 2 φ2xi1 . . . φ2xi xl φxl xj φxj dx = φ2xi1 . . . φ2xi xl (φ2xj )xl dx k−1 BR Z =− BR BR (φ2xi1 . . . φ2xi k−1 xl )xl φ2xj dx + Z ∂BR k−1 φ2xi1 . . . φ2xi k−1 φ2xj x2l dσ |x| EJDE-2012/82 SOLITARY WAVES Z =− BR (φ2xi1 . . . φ2xi Z + ∂BR k−1 φ2xi1 . . . φ2xi )xl xl φ2xj dx − k−1 φ2xj Z BR 7 (φ2xi1 . . . φ2xi k−1 )xl φ2xj dx x2l dσ. |x| Summing up for i1 , . . . , ik−1 , j, l = 1, 2, . . . , n, we have Z |Dφ|2k−2 hx, D2 φDφidx BR Z Z Z =− hx, D(|Dφ|2k−2 )i|Dφ|2 dx − n |Dφ|2k dx + R |Dφ|2k dσ BR BR ∂BR Z Z Z 2k−2 2 2k = −2(k − 1) |Dφ| hx, D φDφidx − n |Dφ| dx + R |Dφ|2k dσ. 2 BR BR ∂BR Then Z |Dφ|2k−2 hx, D2 φDφidx = − BR n 2k Z BR |Dφ|2k dx + R 2k Z |Dφ|2k dσ. (3.6) ∂BR Using (3.5) and (3.6), we obtain Z ∆2k φ hx, Dφi dx BR Z D(|Dφ|2k−2 Dφ)hx, Dφi dx B Z R Z = |Dφ|2k−2 ∆φ hx, Dφi dx + hD|Dφ|2k−2 , Dφihx, Dφi dx BR BR Z Z Z 1 2k 2k−2 =− |Dφ| dx − |Dφ| hx, D2 φDφi dx + |Dφ|2k−2 hx, Dφi2 dσ R BR BR ∂BR Z Z Z n − 2k R 1 2k 2k = |Dφ| dx − |Dφ| dσ + |Dφ|2k−2 hx, Dφi2 dσ. 2k 2k ∂BR R ∂BR BR = Set Ω = m2 − w2 . From the above Lemma we have the following result. Lemma 3.2. If (u, φ) is a solution of the system (1.6), then (u, φ) satisfies the Pohožaev type identity: Z N 1 X 3(k − 1) βk |Dφ|2k dx 4π k R3 R3 R3 k=2 Z Z Z 6 −2 φ2 u2 dx + 5 ωφu2 dx − |u|q dx = 0. q R3 3 3 R R Z |Du|2 dx + 3 Z u2 dx + (3.7) 8 F. WANG EJDE-2012/82 Proof. Multiplying the first formula of (1.6) by hx, Dui, integrating on BR and using the above Lemma, we conclude that Z Z 1 3 − |Du|2 dx − Ω u2 dx 2 BR 2 BR Z Z Z 3 3 (φ − 2ω)φu2 dx + |u|q dx + (φ − ω)u2 hx, Dφi dx + 2 BR q BR BR Z Z (3.8) R 1 hx, Dui2 dσ − |Du|2 dσ = R ∂BR 2 ∂BR Z Z Z ΩR R R 2 2 − u dσ + (φ − 2ω)φu dσ + |u|q dx. 2 ∂BR 2 BR q ∂BR Multiplying the second formula of (1.6) by hx, Dφi, integrating on BR and using the above Lemma, we obtain Z (φ − ω)u2 hx, Dφi dx 4π BR N X Z = (βk ∆2k φ)hx, Dφi dx BR k=1 = N X Z βk = N X (3.9) ∆2k φhx, Dφi dx BR k=1 3 − 2k Z βk R 2k 2k BR |Dφ|2k−2 hx, Dφi2 dσ . k=1 1 + R Z |Dφ|2k dx − Z |Dφ|2k dσ ∂BR ∂BR By (3.8), (3.9) and the proof of [9, Theorem 1.1, pp. 316-317], we deduce the equality Z Z N 3 1 X 3 − 2k 2 |Du| dx − Ω u dx + |Dφ|2k dx βk 2 4π 2k R3 R3 R3 k=1 Z Z 3 3 + (φ − 2ω)φu2 dx + |u|q dx = 0. 2 R3 q R3 1 − 2 Z 2 Then, noting (1.6), we have Z N 1 X 3(k − 1) |Dφ|2k dx βk 2π 2k R3 R3 R3 k=2 Z Z Z 6 φ2 u2 dx + 5ω φu2 dx − −2 |u|q dx = 0. q R3 3 3 R R Z |Du|2 dx + 3Ω Z u2 dx + 4. Proof of the main theorem First, we give a abstract result which is due to Jeanjean [13]. EJDE-2012/82 SOLITARY WAVES 9 Proposition 4.1. Let (X, k · k) be a Banach space and let I ⊂ R+ be an interval. Consider the family of C 1 functionals on X Ψλ (u) = A(u) − λB(u), ∀λ ∈ I, with B(u) nonnegative and either A(u) → +∞ or B(u) → +∞, as kuk → ∞ and such that Ψλ (0) = 0. For any λ ∈ I we set Γλ = {γ ∈ C([0, 1], X) : γ(0) = 0, Ψλ (γ(1)) ≤ 0}. If for every λ ∈ I the set Γλ is nonempty and cλ := inf max Ψλ (γ(t)) > 0, γ∈Γλ t∈[0,1] then for almost every λ ∈ I there is a sequence {(uλ )n } ⊂ X such that (i) {(uλ )n } is bounded in X; (ii) Ψλ ((uλ )n ) → cλ ; (iii) Ψ0λ ((uλ )n ) → 0 in the dual X ∗ of X. Proof Theorem 1.1. Denote M (φ) := Z N 1 X k −1 |Dφ|2k dx. βk 4π k R3 k=2 Then, noting the definition of Φ(u) we can write (3.7) and J(u) by: Z Z Z |Du|2 dx + 3Ω u2 dx + 3M (Φ(u)) − 2 Φ2 (u)u2 dx 3 3 3 R R R Z Z 6 2 q + 5ω Φ(u)u dx − |u| dx = 0 q R3 R3 and JN (u) = Z Z 1 ω |Du|2 dx + Ω u2 dx + Φ(u)u2 dx 2 2 3 3 3 R R Z R 1 1 q + M (Φ(u)) − |u| dx, 2 q R3 1 2 Z respectively. For λ ∈ [ 21 , 1], we define the family of functionals JN,λ : Hr1 (R3 ) → R by Z Z Z 1 ω 1 |Du|2 dx + Ω u2 dx + Φ(u)u2 dx JN,λ (u) = 2 R3 2 2 R3 R3 Z 1 λ + M (Φ(u)) − |u|q dx 2 q R3 Using a slightly modified version of [2, Lemmas 2.3 and 2.4], it can be proved that: for every λ ∈ [ 21 , 1], there exist αλ , ρλ > 0 and νλ ∈ Hr1 (R3 ) such that (i) inf kuk=ρλ JN,λ (u) > αλ . (ii) kνλ k > ρλ and JN,λ (νλ ) < 0. Thus JN,λ has the mountain pass geometry. So we can define the Mountain Pass level cλ by cλ := inf max JN,λ (γ(t)), γ∈Γλ 0≤t≤1 where Γλ = {γ ∈ C([0, 1], Hr1 (R3 )) : γ(0) = 0, γ(1) = νλ }. 10 F. WANG EJDE-2012/82 Set X = Hr1 (R3 ), I = [ 12 , 1], Ψλ = JN,λ , Z Z Z 1 1 ω 1 2 2 A(u) = |Du| dx + Ω u dx + Φ(u)u2 dx + M (Φ(u)) 2 R3 2 2 2 3 3 R R and Z 1 B(u) = |u|q dx. q R3 It is easy to see that B(u) ≥ 0 for all u ∈ Hr1 (R3 ) and A(u) → +∞ as kuk → ∞. Thus, by Proposition 4.1, for almost every λ ∈ I there is a sequence {(uλ )n } ⊂ X such that (i) {(uλ )n } is bounded in Hr1 (R3 ); (ii) JN,λ ((uλ )n ) → cλ ; 0 (iii) JN,λ ((uλ )n ) → 0 in the dual (Hr1 (R3 ))∗ of Hr1 (R3 ). There exists uλ ∈ Hr1 (R3 ) such that Jλ0 (uλ ) = 0, Jλ (uλ ) = cλ , for almost every λ ∈ I. Now we can choose a suitable λn → 1 and uλn such that Jλ0 n (uλn ) = 0, Jλn (uλn ) = cλn → c1 , For simplicity we denoted uλn by un . Since Jλ0 n (un ) = 0, un satisfies the Pohožaev equality Z Z Z |Dun |2 dx + 3Ω u2n dx + 3M (Φ(un )) − 2 Φ2 (un )u2n dx R3 R3 R3 Z Z (4.1) 6λn 2 + 5ω Φ(un )un dx − |un |q dx = 0. q R3 R3 By Jλ0 n (un ) = 0 and Jλn (un ) = cλn → c1 , we have Z Z Z |∇un |2 dx + Ω u2n dx + 2ω Φ(un )u2n dx R3 R3 R3 Z Z 2 2 − Φ (un )un dx − λn |un |q dx = 0 R3 (4.2) R3 and, for n large enough, Z Z 1 1 1 |∇un |2 dx + Ω u2n dx + M (Φ(un )) 2 R3 2 2 3 R Z Z ω λn 2 + Φ(un )un dx − |un |q dx ≤ c1 + 1. 2 R3 q R3 Set α and β two real number (which we will estimate later). Then from α × (4.1) + β × (4.2), we obtain Z λn |un |q dx q R3 Z Z n 1 2 = (α + β) |∇un | dx + (3α + β)Ω u2n dx + 3αM (Φ(un )) 6α + qβ R3 R3 Z Z o + (5α + 2β) ωΦun u2n dx − (2α + β) Φ2un u2n dx . R3 Thus c1 + 1 ≥ Jλn (un ) R3 EJDE-2012/82 SOLITARY WAVES 11 Z Z 1 |∇un |2 dx + Ω u2n dx 2 R3 R3 Z Z 1 1 λn 2 + M (Φ(un )) + ωφun un dx − |un |q dx 2 2 R3 q R3 Z Z 1 1 α+β 3α + β = |∇un |2 dx + − − Ω u2n dx 2 6α + qβ R3 2 6α + qβ 3 R 1 5α + 2β Z 1 3α 2 M (Φ(un )) + − ωφun un dx + − 2 6α + qβ 2 6α + qβ R3 Z 2α + β Φ2 (un )u2n dx + 6α + qβ R3 Z 1 τ +1 = − |∇un |2 dx 2 6τ + q R3 Z 1 2τ + 1 3τ + M (Φ(un )) + − Φ2 (un )u2n dx 2 6τ + q 6τ + q R3 1 5τ + 2 Z 1 3τ + 1 Z 2 − Ω un dx + − ωΦ(un )u2n dx, + 2 6τ + q 2 6τ + q R3 R3 where τ = α . Under one of the following conditions: β (i) q ∈ (4, 6), τ ∈ ((2 − q)/4, −1/2) and m > ω > 0; (ii) q ∈ (3, 4], τ ∈ ((2 − q)/4, (q − 4)/4) and p m > ω > 0; (iii) q ∈ (2, 3], τ ∈ ((2 − q)/4, +∞) and m (q − 2)(4 − q) > ω > 0, = 1 2 we conclude that 1 τ +1 − > 0, 2 6τ + q 1 3τ − >0 2 6τ + q and 1 3τ + 1 2τ + 1 2 1 5τ + 2 t + − ωt + − Ω ≥ 0, for t ∈ [0, ω]. 6τ + q 2 6τ + q 2 6τ + q R So we obtain that R3 |∇un |2 dx is bounded for all n. 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