Electronic Journal of Differential Equations, Vol. 2006(2006), No. 131, pp. 1–15. ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu ftp ejde.math.txstate.edu (login: ftp) A SEMILINEAR ELLIPTIC PROBLEM INVOLVING NONLINEAR BOUNDARY CONDITION AND SIGN-CHANGING POTENTIAL TSUNG-FANG WU Abstract. In this paper, we study the multiplicity of nontrivial nonnegative solutions for a semilinear elliptic equation involving nonlinear boundary condition and sign-changing potential. With the help of the Nehari manifold, we prove that the semilinear elliptic equation: −∆u + u = λf (x)|u|q−2 u in Ω, ∂u = g(x)|u|p−2 u on ∂Ω, ∂ν has at least two nontrivial nonnegative solutions for λ is sufficiently small. 1. Introduction In this paper, we consider the multiplicity of nontrivial nonnegative solutions for the following semilinear elliptic equation −∆u + u = λf (x)|u|q−2 u ∂u = g(x)|u|p−2 u ∂ν in Ω, (1.1) on ∂Ω, −1) N where 1 < q < 2 < p < 2(N with smooth N −2 , λ > 0, Ω is a bounded domain in R ∂ boundary, ∂ν is the outer normal derivative and f, g : Ω → R are continuous functions which change sign in Ω. Associated with (1.1), we consider the energy functional Jλ in H 1 (Ω), Z Z 1 λ 1 Jλ (u) = kuk2H 1 − f |u|q dx − g|u|p ds. 2 q Ω p ∂Ω R where ds is the measure on the boundary and kuk2H 1 = Ω |∇u|2 + u2 dx. It is well known that Jλ is of C 1 in H 1 (Ω) and the solutions of equation (1.1) are the critical points of the energy functional Jλ . The fact that the number of solutions of equation (1.1) is affected by the nonlinear boundary conditions has been the focus of a great deal of research in recent years. Garcia-Azorero, Peral and Rossi [10] have investigated (1.1) when f ≡ g ≡ 1. 2000 Mathematics Subject Classification. 35J65, 35J50, 35J55. Key words and phrases. Semilinear elliptic equations; Nehari manifold; Nonlinear boundary condition. c 2006 Texas State University - San Marcos. Submitted July 6, 2006. Published October 17, 2006. Partially supported by the National Science Council of Taiwan (R.O.C.). 1 2 T.-F. WU EJDE-2006/131 They found that there exist positive numbers Λ1 , Λ2 with Λ1 ≤ Λ2 such that equation (1.1) admits at least two positive solutions for λ ∈ (0, Λ1 ) and no positive solution exists for λ > Λ2 . Also see Chipot-Chlebik-Fila-Shafrir [4], Chipot-Shafrir-Fila [5], Flores-del Pino [8], Hu [11], Pierrotti-Terracini [14] and Terraccini [16] where problems similar to equation (1.1) have been studied. The purpose of this paper is to consider the multiplicity of nontrivial nonnegative solutions of equation (1.1) with sign-changing potential. We prove that equation (1.1) has at least two nontrivial nonnegative solutions for λ is sufficiently small. Theorem 1.1. There exists λ0 > 0 such that for λ ∈ (0, λ0 ), equation (1.1) has at least two nontrivial nonnegative solutions. Among the other interesting problems which are similar of equation (1.1), Ambrosetti-Brezis-Cerami [3] have investigated the equation −∆u = λ|u|q−2 u + |u|p−2 u in Ω, (1.2) u = 0 on ∂Ω, where 1 < q < 2 < p ≤ N2N −2 . They proved that there exists λ0 > 0 such that (1.2) admits at least two positive solutions for λ ∈ (0, λ0 ), has a positive solution for λ = λ0 , and no positive solution for λ > λ0 . Actually, Adimurthi-Pacella-Yadava [1], Damascelli-Grossi-Pacella [6], Ouyang-Shi [13] and Tang [17] proved that there exists λ0 > 0 such that equation (1.2) in the unit ball B N (0; 1) has exactly two positive solutions for λ ∈ (0, λ0 ), has exactly one positive solution for λ = λ0 and no positive solution exists for λ > λ0 . Generalizations of the result of equation (1.2) were done by Ambrosetti-Azorero-Peral [2], de Figueiredo-Gossez-Ubilla [9] and Wu [18]. This paper is organized as follows. In section 2, we give some notation and preliminaries. In section 3, we prove that (1.1) has at least two nontrivial nonnegative solutions for λ is sufficiently small. 2. Notation and Preliminaries Throughout this section, we denote by Sp , Cp the best Sobolev embedding and trace constant for the operators H 1 (Ω) ,→ Lp (Ω), H 1 (Ω) ,→ Lp (∂Ω), respectively. Now, we consider the Nehari minimization problem: For λ > 0, αλ = inf{Jλ (u) : u ∈ Mλ }, where Mλ = {u ∈ H (Ω)\{0} : hJλ0 (u), ui = 0}. Define Z Z ψλ (u) = hJλ0 (u), ui = kuk2H 1 − λ f |u|q dx − 1 Ω g|u|p ds. ∂Ω Then for u ∈ Mλ , hψλ0 (u), ui = 2kuk2H 1 − λq Z Ω f |u|q dx − p Z g|u|p ds. ∂Ω Similarly to the method used in Tarantello [15], we split Mλ into three parts: 0 M+ λ = {u ∈ Mλ : hψλ (u), ui > 0}, M0λ = {u ∈ Mλ : hψλ0 (u), ui = 0}, 0 M− λ = {u ∈ Mλ : hψλ (u), ui < 0}. Then, we have the following results. EJDE-2006/131 A SEMILINEAR ELLIPTIC PROBLEM 3 Lemma 2.1. There exists λ1 > 0 such that for each λ ∈ (0, λ1 ) we have M0λ = φ. Proof. We consider theR following two cases. Case (I): u ∈ Mλ and ∂Ω g|u|p ds ≤ 0. We have Z Z λ f |u|q dx = kuk2H 1 − Ω g|u|p ds. ∂Ω Thus, hψλ0 (u), ui = 2kuk2H 1 Z − λq Z q f |u| dx − p g|u|p ds ∂Ω Z + (q − p) g|u|p ds > 0 Ω = (2 − q)kuk2H 1 ∂Ω and so u ∈ M+ λ. R Case (II): u ∈ Mλ and ∂Ω g|u|p ds > 0. Suppose that M0λ 6= φ for all λ > 0. If u ∈ M0λ , then we have Z Z 0 = hψλ0 (u), ui = 2kuk2H 1 − λq f |u|q dx − p g|u|p ds ∂Ω Z Ω 2 p = (2 − q)kukH 1 − (p − q) g|u| ds. ∂Ω Thus, kuk2H 1 = p−q 2−q Z g|u|p ds (2.1) ∂Ω and Z λ f |u|q dx = kuk2H 1 − Ω Z g|u|p ds = ∂Ω p−2 2−q Z g|u|p ds. (2.2) ∂Ω Moreover, ( Z p−2 )kuk2H 1 = kuk2H 1 − g|u|p ds p−q ∂Ω Z =λ f |u|q dx Ω ≤ λkf kLp∗ kukqLp ≤ λkf kLp∗ Spq kukqH 1 , where p∗ = p p−q . This implies h p−q i1/(2−q) kukH 1 ≤ λ( )kf kLp∗ Spq . p−2 Let Iλ : Mλ → R be given by Z kuk2(p−1) 1/(p−2) 1 −λ f |u|q dx, Iλ (u) = K(p, q) R H p g|u| ds Ω ∂Ω (2.3) 4 T.-F. WU EJDE-2006/131 2−q (p−1)/(p−2) p−2 where K(p, q) = ( p−q ) ( 2−q ). Then Iλ (u) = 0 for all u ∈ M0λ . Indeed, from (2.1) and (2.2) it follows that for u ∈ M0λ we have Z kuk2(p−1) 1/(p−1) H1 R −λ Iλ (u) = K(p, q) f |u|q dx g|u|p ds Ω ∂Ω p−1 R p−q p−1 1 p−2 p g|u|p ds p − 2 ( 2−q ) 2 − q p−1 ∂Ω (2.4) R ( ) = p ds p−q 2−q g|u| ∂Ω Z p−2 p − g|u| ds = 0. 2 − q ∂Ω However, by (2.3), the Hölder and Sobolev trace inequality, for u ∈ M0λ kuk2(p−1) 1/(p−2) 1 Iλ (u) ≥ K(p, q) R H p − λSpq kf kLp∗ kukqH 1 g|u| ds ∂Ω 2(p−1) 1/(p−2) kukH 1 q ≥ kukqH 1 K(p, q) − λS kf k p∗ L p p+q(p−2) Cpp kgk∞ kukH 1 h p − q i 1−q p 1−q 2−q kf kLp∗ Spq − λSpq kf kLp∗ . ≥ kukqH 1 K(p, q)Cp2−p λ 2−q p−2 This implies that for λ sufficiently small we have Iλ (u) > 0 for all u ∈ M0λ , this contradicts (2.4). Thus, we can conclude that there exists λ1 > 0 such that for λ ∈ (0, λ1 ), we have M0λ = φ. − By Lemma 2.1, for λ ∈ (0, λ1 ) we write Mλ = M+ λ ∪ Mλ and define αλ− (Ω) = inf − Jλ (u). αλ+ = inf + Jλ (u); u∈Mλ u∈Mλ The following lemma shows that the minimizers on Mλ are “usually” critical points for Jλ . Lemma 2.2. For λ ∈ (0, λ1 ). If u0 is a local minimizer for Jλ on Mλ , then Jλ0 (u0 ) = 0 in H ∗ (Ω). Proof. If u0 is a local minimizer for Jλ on Mλ , then u0 is a solution of the optimization problem minimize Jλ (u) subject to ψλ (u) = 0. Hence, by the theory of Lagrange multipliers, there exists θ ∈ R such that Jλ0 (u0 ) = θψλ0 (u0 ) in H ∗ (Ω). Thus, hJλ0 (u0 ), u0 iH 1 = θhψλ0 (u0 ), u0 iH 1 . M+ λ ∪ M− λ, By Lemma 2.1, u0 ∈ This completes the proof. we have hψλ0 (u0 ), u0 iH 1 R q Lemma 2.3. (i) If u ∈ M+ λ , then Ω f |u| dx > 0; R − p (ii) If u ∈ Mλ , then ∂Ω g|u| ds > 0. (2.5) 6= 0 and so by (2.5) θ = 0. EJDE-2006/131 A SEMILINEAR ELLIPTIC PROBLEM Proof. (i) Case (I): R g|u|p ds ≤ 0. We have Z Z q 2 λ f |u| dx = kukH 1 − ∂Ω g|u|p ds > 0. ∂Ω Ω Case (II): g|u|p ds > 0. We have Z Z 2 q kukH 1 − λ f |u| dx − R ∂Ω 5 Ω and kuk2H 1 g|u|p ds = 0 ∂Ω p−q > 2−q Z g|u|p ds. ∂Ω Thus, Z q f |u| dx = λ kuk2H 1 Ω p−2 − g|u| ds > 2−q ∂Ω Z p Z g|u|p ds > 0. ∂Ω (ii) Since Z (2 − − (p − q) g|u|p ds = hψλ0 (u), ui < 0. ∂Ω R It follows that ∂Ω g|u|p ds > 0. This completes the proof. q)kuk2H 1 For each u ∈ M− λ, we write 1/(p−2) (2 − q)kuk2 H1 R < 1. tmax = p (p − q) ∂Ω g|u| ds Then we have the following lemma. 2−q p(2−q) p 2−q p−2 Cp 2−p Sp−q kf k−1 . Then for Lemma 2.4. Let p∗ = p−q and λ2 = ( p−2 p−q )( p−q ) Lp∗ − each u ∈ Mλ and λ ∈ (0, λ2 ), we have R (i) if RΩ f |u|q dx ≤ 0, then Jλ (u) = supt≥0 Jλ (tu) > 0; (ii) if Ω f |u|q dx > 0, then there is a unique 0 < t+ = t+ (u) < tmax such that t+ u ∈ M+ λ and Jλ (t+ u) = Proof. Fix u ∈ M− λ. inf 0≤t≤tmax Jλ (tu), Jλ (u) = sup Jλ (tu). t≥tmax Let h(t) = t2−q kuk2H 1 − tp−q Z g|u|p ds for t ≥ 0. ∂Ω We have h(0) = 0, h(t) → −∞ as t → ∞, h(t) achieves its maximum at tmax , increasing for t ∈ [0, tmax ) and decreasing for t ∈ (tmax , ∞). Moreover, h(tmax ) Z 2−q (2 − q)kuk2 p−2 (2 − q)kuk2 p−q p−2 1 1 2 H H R R = kukH 1 − g|u|p ds (p − q) ∂Ω g|u|p ds (p − q) ∂Ω g|u|p ds ∂Ω 2−q h 2 − q 2−q i kukp p−2 2 − q p−q H1 = kukqH 1 ( ) p−2 − ( ) p−2 R p−q p−q g|u|p ds ∂Ω p(2−q) 2−q p − 2 2 − q p−2 ≥ kukqH 1 ( )( ) Cp 2−p p−q p−q or h(tmax ) ≥ kukqH 1 ( p(2−q) 2−q p − 2 2 − q p−2 )( ) Cp 2−p . p−q p−q (2.6) 6 T.-F. WU EJDE-2006/131 R R (i): Ω f |u|q dx ≤ 0. There is a unique t− > tmax such that h(t− ) = λ Ω f |u|q dx and h0 (t− ) < 0. Now, Z |t− u|p ds (2 − q)kt− uk2H 1 − (p − q) ∂Ω Z h i − 1+q − 1−q = (t ) (2 − q)(t ) kuk2H 1 − (p − q)(t− )p−q−1 g|u|p ds ∂Ω = (t− )1+q h0 (t− ) < 0, and hJλ0 (t− u), t− ui − 2 kuk2H 1 − q Z − p q Z − (t ) λ f |u| dx − (t ) Ω Z h i = (t− )q h(t− ) − λ f |u|q dx = 0. = (t ) g|u|p ds ∂Ω Ω − Thus, t u ∈ M− λ − or t = 1. Since for t > tmax , we have Z (2 − q)ktuk2H 1 − (p − q) g|tu|p ds < 0, ∂Ω d Jλ (tu) = tkuk2H 1 dt d2 J (tu) < 0, 2 λ Z dt Z − λtq−1 f |u|q dx − tp−1 Ω g|u|p ds = 0 for t = t− . ∂Ω Thus, Jλ (u) = supt≥0 Jλ (tu). Moreover, tp t2 Jλ (u) ≥ Jλ (tu) ≥ kuk2H 1 − 2 p 2 Z p By routine computations, g(t) = t2 kuk2H 1 − tp R t0 = (kuk2H 1 / ∂Ω g|u|p ds)1/(p−2) . Thus, Jλ (u) ≥ (ii): R Ω g|u|p ds for all t ≥ 0. ∂Ω R ∂Ω g|u|p ds achieves its maximum at p 2 p − 2 kukH 1 p−2 R > 0. 2p g|u|p ds ∂Ω f |u|q dx > 0. By (2.6) and Z h(0) = 0 < λ f |u|q dx ≤ λkf kLp∗ Spq kukqH 1 Ω p(2−q) 2−q − 2 2 − q p−2 )( ) Cp 2−p −q p−q ≤ h(tmax ) for λ ∈ (0, λ2 ), < p kukqH 1 ( p there are unique t+ and t− such that 0 < t+ < tmax < t− , Z + h(t ) = λ f |u|q dx = h(t− ), Ω h0 (t+ ) > 0 > h0 (t− ). EJDE-2006/131 A SEMILINEAR ELLIPTIC PROBLEM 7 − − − + We have t+ u ∈ M+ λ , t u ∈ Mλ , and Jλ (t u) ≥ Jλ (tu) ≥ Jλ (t u) for each + − + + − t ∈ [t , t ] and Jλ (t u) ≤ Jλ (tu) for each t ∈ [0, t ]. Thus, t = 1 and Jλ (u) = sup Jλ (tu), Jλ (t+ u) = t≥0 inf 0≤t≤tmax Jλ (tu). This completes the proof. Next, we establish the existence of nontrivial nonnegative solutions for the equation −∆u + u = λf (x)|u|q−2 u in Ω, (2.7) u = 0 on ∂Ω, Associated with equation (2.7), we consider the energy functional Z 1 λ 2 f |u|q dx Kλ (u) = kukH 1 − 2 q Ω and the minimization problem βλ = inf{Kλ (u) : u ∈ Nλ }, where Nλ = {u ∈ H01 (Ω)\{0} : hKλ0 (u), ui = 0}. Then we have the following result. Theorem 2.5. Suppose that λ > 0. Then equation (2.7) has a nontrivial nonnegative solution vλ with Kλ (vλ ) = βλ < 0. Proof. First, we need to show that Kλ is bounded below on Nλ and βλ < 0. Then for u ∈ Nλ , Z −q kuk2H 1 = λ f |u|q dx ≤ λkf kLq∗ Sp 2 kukqH 1 . Ω where p∗ = p p−q . This implies −q 1 kukH 1 ≤ (λkf kLp∗ Sp 2 ) 2−q . (2.8) Hence, Z 1 λ kukH 1 − f |u|q dx 2 q Ω 1 1 − kuk2H 1 = 2 q 1 1 −q 1 ≤ − λkf kLp∗ Sp 2 2−q 2 q Kλ (u) = for all u ∈ Nλ and βλ < 0. Let {vn } be a minimizing sequence for Kλ on Nλ . Then by (2.8) and the compact imbedding theorem, there exist a subsequence {vn } and vλ in H01 (Ω) such that vn * vλ weakly in H01 (Ω) and vn → vλ q R strongly in Lq (Ω). f |vλ | dx > 0. If not, Z λ 1 1 2 f |vλ |q dx + o(1) ≥ kvλ k2H 1 + o(1), Kλ (vn ) ≥ kvλ kH 1 − 2 q Ω 2 First, we claim that Ω (2.9) 8 T.-F. WU EJDE-2006/131 R this contradicts Kλ (vn ) → βλ (Ω) < 0 as n → ∞. Thus, Ω f |vλ |q dx > 0. In particular, vλ 6≡ 0. Now, we prove that vn → vλ strongly in H01 (Ω). Suppose otherwise, then kvλ kH 1 < lim inf n→∞ kvn kH 1 and so Z Z 2 q 2 kvλ kH 1 − λ f |vλ | dx < lim inf kvn kH 1 − λ f |vn |q dx = 0. n→∞ Ω Since Ω q R Ω f |vλ | dx > 0, there is a unique t0 6= 1 such that t0 vλ ∈ Nλ . Thus, t0 vn * t0 vλ weakly in H01 (Ω). Moreover, Kλ (t0 vλ ) < Kλ (vλ ) < lim Kλ (vn ) = βλ , n→∞ which is a contradiction. Hence vn → vλ strongly in H01 (Ω). This implies vλ ∈ Nλ and Kλ (vn ) → Kλ (vλ ) = βλ as n → ∞. Since Kλ (vλ ) = Kλ (kvλ k) and kvλ k ∈ Nλ , without loss of generality, we may assume that vλ is a nontrivial nonnegative solution of equation (2.7). Then we have the following results. Lemma 2.6. (i) αλ ≤ αλ+ ≤ βλ < 0; (ii) Jλ is coercive and bounded below on Mλ for all λ ∈ (0, p−2 p−q ]. Proof. (i) Let vλ be a positive solution of equation (2.7) such that K(vλ ) = βλ . R Since vλ ∈ C 2 (Ω). Then we have ∂Ω g|vλ |p ds = 0 and vλ ∈ M+ λ . This implies Z λ 1 f |vλ |q dx = βλ < 0 Jλ (vλ ) = kvλ k2H 1 − 2 q Ω and so αλ ≤ αλ+ ≤ βλ < 0. R R (ii) For u ∈ Mλ , we have kuk2H 1 = λ Ω f |u|q dx + ∂Ω g|u|p ds. Then by the Hölder and Young inequalities, Z p−2 p − q Jλ (u) = kuk2H 1 − λ f |u|q dx 2p pq Ω p−2 p − q 2 ≥ kukH 1 − λ kf kLp∗ Spq kukqH 1 2p pq 2 p − 2 p − q (p − q)(2 − q) ≥ −λ kuk2H 1 − λ kf kLp∗ Spq 2−q 2p 2p 2pq 2 1 (p − q)(2 − q) (p − 2) − λ(p − q) kuk2H 1 − λ kf kLp∗ Spq 2−q . = 2p 2pq Thus, Jλ is coercive on Mλ and Jλ (u) ≥ −λ for all λ ∈ (0, p−2 p−q ]. 2 (p − q)(2 − q) kf kLp∗ Spq 2−q 2pq EJDE-2006/131 A SEMILINEAR ELLIPTIC PROBLEM 9 3. Proof of Theorem 1.1 First, we will use the idea of Ni-Takagi [12] to get the following results. Lemma 3.1. For each u ∈ Mλ , there exist > 0 and a differentiable function ξ : B(0; ) ⊂ H 1 (Ω) → R+ such that ξ(0) = 1, the function ξ(v)(u − v) ∈ Mλ and R R R 2 Ω ∇u∇vdx − λq Ω f |u|q−2 uvdx − p ∂Ω g|u|p−2 uvds R hξ 0 (0), vi = (3.1) (2 − q)kuk2H 1 − (p − q) ∂Ω g|u|p ds for all v ∈ H 1 (Ω). Proof. For u ∈ Mλ , define a function F : R × H 1 (Ω) → R by Fu (ξ, w) = hJλ0 (ξ(u − w)), ξ(u − w)i Z Z = ξ2 |∇(u − w)|2 + (u − w)2 dx − ξ q λ f |u − w|q dx Ω Ω Z p p −ξ g|u − w| ds. ∂Ω Then Fu (1, 0) = hJλ0 (u), ui = 0 and d Fu (1, 0) = 2kuk2H 1 − λq dξ = (2 − q)kuk2H 1 Z Z q f |u| dx − p g|u|p ds ∂Ω Z − (p − q) g|u|p ds 6= 0. ∂Ω ∂Ω According to the implicit function theorem, there exist > 0 and a differentiable function ξ : B(0; ) ⊂ H 1 (Ω) → R such that ξ(0) = 1, R R R 2 Ω ∇u∇vdx − λq Ω f |u|q−2 uvdx − p ∂Ω g|u|p−2 uvds R hξ 0 (0), vi = (2 − q)kuk2H 1 − (p − q) ∂Ω g|u|p ds and Fu (ξ(v), v) = 0 for all v ∈ B(0; ) which is equivalent to hJλ0 (ξ(v)(u − v)), ξ(v)(u − v)i = 0 for all v ∈ B(0; ), that is ξ(v)(u − v) ∈ Mλ . Lemma 3.2. For each u ∈ M− λ , there exist > 0 and a differentiable function ξ − : B(0; ) ⊂ H 1 (Ω) → R+ such that ξ − (0) = 1, the function ξ − (v)(u − v) ∈ M− λ and R R R 2 Ω ∇u∇vdx − λq Ω f |u|q−2 uvdx − p ∂Ω g|u|p−2 uvds − 0 R h(ξ ) (0), vi = (3.2) (2 − q)kuk2H 1 − (p − q) ∂Ω g|u|p ds for all v ∈ H 1 (Ω). Proof. Similar to the argument in Lemma 3.1, there exist > 0 and a differentiable function ξ − : B(0; ) ⊂ H 1 (Ω) → R such that ξ − (0) = 1 and ξ − (v)(u − v) ∈ Mλ for all v ∈ B(0; ). Since Z 0 2 hψλ (u), ui = (2 − q)kukH 1 − (p − q) g|u|p ds < 0. ∂Ω 10 T.-F. WU EJDE-2006/131 Thus, by the continuity of the function ξ − , we have hψλ0 (ξ − (v)(u − v)), ξ − (v)(u − v)i − = (2 − q)kξ (v)(u − v)k2H 1 Z g|ξ − (v)(u − v)|p ds < 0 − (p − q) ∂Ω if sufficiently small, this implies that ξ − (v)(u − v) ∈ M− λ. Proposition 3.3. Let λ0 = min{λ1 , λ2 , p−1 p−q }, Then for λ ∈ (0, λ0 ): (i) There exists a minimizing sequence {un } ⊂ Mλ such that Jλ (un ) = αλ + o(1), Jλ0 (un ) = o(1) in H ∗ (Ω); (ii) there exists a minimizing sequence {un } ⊂ M− λ such that Jλ (un ) = αλ− + o(1), Jλ0 (un ) = o(1) in H ∗ (Ω). Proof. (i) By Lemma 2.6 (ii) and the Ekeland variational principle [7], there exists a minimizing sequence {un } ⊂ Mλ such that Jλ (un ) < αλ + 1 , n 1 kw − un kH 1 for each w ∈ Mλ . n By taking n large, from Lemma 2.6 (i), we have Z 1 1 1 1 2 Jλ (un ) = ( − )kun kH 1 − ( − )λ f |un |q dx 2 p q p Ω 1 βλ < αλ + < . n 2 This implies Z −pq q q ∗ kf kLp Sp kun kH 1 ≥ βλ > 0. f |un |q dx > 2λ(p − q) Ω Jλ (un ) < Jλ (w) + (3.3) (3.4) (3.5) (3.6) Consequently, un 6= 0 and putting together (3.5), (3.6) and the Hölder inequality, we obtain h −pq i1/q kun kH 1 > βλ Sp−q kf k−1 (3.7) ∗ p L 2λ(p − q) h 2(p − q) i1/(2−q) kun kH 1 < kf kLp∗ Spq (3.8) (p − 2)q Now, we show that kJλ0 (un )kH −1 → 0 as n → ∞. Applying Lemma 3.1 with un to obtain the functions ξn : B(0; n ) → R+ for some n > 0, such that ξn (w)(un − w) ∈ Mλ . Choose 0 < ρ < n . Let u ∈ H 1 (Ω) with ρu u 6≡ 0 and let wρ = kuk . We set ηρ = ξn (wρ )(un − wρ ). Since ηρ ∈ Mλ , we H1 deduce from (3.4) that 1 Jλ (ηρ ) − Jλ (un ) ≥ − kηρ − un kH 1 n EJDE-2006/131 A SEMILINEAR ELLIPTIC PROBLEM 11 and by the mean value theorem, we have 1 hJλ0 (un ), ηρ − un i + o(kηρ − un kH 1 ) ≥ − kηρ − un kH 1 . n Thus, hJλ0 (un ), −wρ i + (ξn (wρ ) − 1)hJλ0 (un ), (un − wρ )i 1 ≥ − kηρ − un kH 1 + o(kηρ − un kH 1 ). n Since ξn (wρ )(un − wρ ) ∈ Mλ and (3.9) it follows that u − ρhJλ0 (un ), i + (ξn (wρ ) − 1)hJλ0 (un ) − Jλ0 (ηρ ), (un − wρ )i kukH 1 1 ≥ − kηρ − un kH 1 + o(kηρ − un kH 1 ). n Thus, hJλ0 (un ), u kηρ − un kH 1 o(kηρ − un kH 1 ) i≤ + kukH 1 nρ ρ (ξn (wρ ) − 1) 0 + hJλ (un ) − Jλ0 (ηρ ), (un − wρ )i. ρ (3.9) (3.10) Since kηρ − un kH 1 ≤ ρkξn (wρ )k + kξn (wρ ) − 1kkun kH 1 and lim ρ→0 kξn (wρ ) − 1k ≤ kξn0 (0)k, ρ if we let ρ → 0 in (3.10) for a fixed n, then by (3.8) we can find a constant C > 0, independent of ρ, such that hJλ0 (un ), u C i ≤ (1 + kξn0 (0)k). kukH 1 n The proof will be complete once we show that kξn0 (0)k is uniformly bounded in n. By (3.1), (3.8) and the Hölder inequality, we have hξn0 (0), vi ≤ bkvkH 1 R |(2 − q)kun kH 1 − (p − q) ∂Ω g|un |p ds| for some b > 0. We only need to show that Z |(2 − q)kun kH 1 − (p − q) g|un |p ds| > c (3.11) ∂Ω for some c > 0 and n large enough. We argue by contradiction. Assume that there exists a subsequence {un }, we have Z (2 − q)kun kH 1 − (p − q) g|un |p ds = o(1). (3.12) ∂Ω Combining (3.12) with (3.7), we can find a suitable constant d > 0 such that Z g|un |p ds ≥ d for n sufficiently large. (3.13) ∂Ω In addition (3.12), and the fact that un ∈ Mλ also give Z Z Z p−2 q 2 p λ f |un | dx = kun kH 1 − g|un | ds = g|un |p ds + o(1) 2 − q ∂Ω Ω ∂Ω 12 T.-F. WU EJDE-2006/131 and 1 h p−q i 2−q kun kH 1 ≤ λ( + o(1). )kf kLp∗ Spq p−2 (3.14) This implies Z ku k2(p−1) 1/(p−2) n H1 Iλ (un ) = K(p, q) R − λ f |un |q dx = o(1). p ds g|u | n Ω ∂Ω (3.15) However, by (3.13), (3.14) and λ ∈ (0, λ0 ), ku k2(p−1) 1/(p−2) n H1 Iλ (un ) ≥ K(p, q) R − λSpq kf kLp∗ kun kqH 1 p ds g|u | n ∂Ω ku k2(p−1) 1/(p−2) n H1 q q − λS kf k ≥ kun kH 1 K(p, q) p∗ L p p+q(p−2) Cpp kun kH 1 n o p 1−q 1−q p − q )kf kLp∗ Spq 2−q − λkf kLp∗ . ≥ kun kqH 1 K(p, q)Cp2−p λ 2−q ( p−2 this contradicts (3.15). We get hJλ0 (un ), u C i≤ . kukH 1 n This completes the proof of (i). (ii) Similarly, by using Lemma 3.2, we can prove (ii). We will omit detailed proof here. Now, we establish the existence of a local minimum for Jλ on M+ λ. Theorem 3.4. Let λ0 > 0 as in Proposition 3.3, then for λ ∈ (0, λ0 ) the functional + Jλ has a minimizer u+ 0 in Mλ and it satisfies + (i) Jλ (u+ 0 ) = αλ = αλ ; + (ii) u0 is a nontrivial nonnegative solution of equation (1.1); (iii) Jλ (u+ 0 ) → 0 as λ → 0. Proof. Let {un } ⊂ Mλ be a minimizing sequence for Jλ on Mλ such that and Jλ0 (un ) = o(1) Jλ (un ) = αλ + o(1) in H ∗ (Ω). Then by Lemma 2.6 and the compact imbedding theorem, there exist a subsequence 1 {un } and u+ 0 ∈ H (Ω) such that u n * u+ 0 weakly in H 1 (Ω), un → u+ 0 strongly in Lp (∂Ω) and un → u+ 0 First, we claim that conclude that Z R strongly in Lq (Ω). q f (x)ku+ 0 k dx Ω f |un |q dx → Ω Z 6= 0. Suppose otherwise, by (3.16) we can q f |u+ 0 | dx = 0 as n → ∞ Ω and so kun k2H 1 (3.16) Z = ∂Ω g|un |p ds + o(1). EJDE-2006/131 A SEMILINEAR ELLIPTIC PROBLEM 13 Thus, Z Z 1 λ 1 2 q Jλ (un ) = kun kH 1 − f |un | dx − g|un |p ds 2 q Ω p ∂Ω Z 1 1 g|un |p ds + o(1) =( − ) 2 p ∂Ω Z 1 1 p =( − ) g|u+ 0 | ds as n → ∞, 2 p ∂Ω this contradicts Jλ (un ) → αλ < 0 as n → ∞. Moreover, o(1) = hJλ0 (un ), φi = hJλ0 (u0 ), φi + o(1) for all φ ∈ H 1 (Ω). + Thus, u+ 0 ∈ Mλ is a nonzero solution of equation (1.1) and Jλ (u0 ) ≥ αλ . Now + we prove that un → u0 strongly in H 1 (Ω). Suppose otherwise, then ku+ 0 kH 1 < lim inf n→∞ kun kH 1 and so Z Z + q 2 p ku+ k − λ f |u | dx − g|u+ 1 0 H 0 0 | ds Ω ∂Ω Z Z 2 q < lim inf kun kH 1 − λ f |un | dx − g|un |p ds = 0, n→∞ this contradicts u+ 0 Ω ∈ Mλ . Hence un → ∂Ω u+ 0 strongly in H 1 (Ω) and Jλ (un ) → Jλ (u+ 0 ) = αλ as n → ∞. + + − Moreover, we have u+ 0 ∈ Mλ . If not, then u0 ∈ Mλ and by Lemma 2.4, there are + − + + + − + unique t0 and t0 such that t0 u0 ∈ Mλ and t0 u0 ∈ M− λ . In particular, we have − t+ < t = 1. Since 0 0 d + Jλ (t+ 0 u0 ) = 0 dt and d2 + Jλ (t+ 0 u0 ) > 0, dt2 − + + + there exists t+ 0 < t̄ ≤ t0 such that Jλ (t0 u0 ) < Jλ (t̄u0 ). By Lemma 2.4, + + − + + Jλ (t+ 0 u0 ) < Jλ (t̄u0 ) ≤ Jλ (t0 u0 ) = Jλ (u0 ), + + + which is a contradiction. Since Jλ (u+ 0 ) = Jλ (|u0 |) and |u0 | ∈ Mλ , by Lemma + 2.2 we may assume that u0 is a nontrivial nonnegative solution of equation (1.1). From Lemma 2.6 it follows that (p − q)(2 − q) 2 (kf kLp∗ Spq ) 2−q 0 > Jλ (u+ ) ≥ −λ 0 2pq and so Jλ (u+ 0 ) → 0 as λ → 0. Next, we establish the existence of a local minimum for Jλ on M− λ. Theorem 3.5. Let λ0 > 0 as in Proposition 3.3. Then for λ ∈ (0, λ0 ) the functional − Jλ has a minimizer u− 0 in Mλ and satisfies − (i) Jλ (u− 0 ) = αλ ; − (ii) u0 is a nontrivial nonnegative solution of equation (1.1). Proof. By Proposition 3.3 (ii), there exists a minimizing sequence {un } for Jλ on M− λ such that Jλ (un ) = αλ− + o(1) and Jλ0 (un ) = o(1) in H ∗ (Ω). 14 T.-F. WU EJDE-2006/131 By Lemma 2.6 and the compact imbedding theorem, there exist a subsequence {un } 1 and u− 0 ∈ H (Ω) such that u n * u− 0 un → u− 0 weakly in H 1 (Ω), strongly in Lp (∂Ω), un → u− strongly in Lq (Ω). 0 R p Since (2 − q)kun k2H 1 − (p − q) R ∂Ω g|upn | ds < 0, by the Sobolev trace inequality there exists C > 0 such that ∂Ω g|un | ds > C. Moreover, o(1) = hJλ0 (un ), φi = hJλ0 (u0 ), φi + o(1) for all φ ∈ H 1 (Ω) and (2 − q)ku0 k2H 1 − (p − q) Z g|u0 |p ds Z − (p − q) ∂Ω ≤ lim inf (2 − q)kun k2H 1 n→∞ u− 0 g|un |p ds ≤ 0. ∂Ω M− λ 1 Thus, ∈ is a nonzero solution of equation (1.1). Now we prove that un → u− 0 strongly in H (Ω). Suppose otherwise, then ku− 0 kH 1 < lim inf n→∞ kun kH 1 and so Z Z − q 2 p ku− k − λ f |u | dx − g|u− 1 0 H 0 0 | ds Ω ∂Ω Z Z 2 < lim inf kun kH 1 − λ f |un |q dx − g|un |p ds = 0, n→∞ this contradicts u− 0 ∈ Ω M− λ. Hence un → ∂Ω u− 0 strongly in H 1 (Ω). 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